I have the following:
<div id="container">
<img src="pic.png">
</div>
This is styled as follows:
#container {
height: 50px;
width: 50px;
}
In addition to this, I have some javascript hackery to cause the image to appear dead center in the containing div by setting margin-top and margin-left.
When I look at this in the Chrome web inspector, it's clear that the containing div does not start at the top of its parent. I suspect the image is being positioned relative to the container div's parent.
The trouble with this is that I want the container div to be a target for click events, such as dragging. The div only starts at the top of the image, when I want it to start above the image, and include the margin space as a part of the container. Any advice?
#plalx is right your using the wrong selector you should just do this:
#container{
width: 50px;
height: 50px;
padding: 5px;
}
padding is what your looking for with making the div bigger then the image for click. margin determines place on the page, padding determines space on the page beyond your height and width attributes.
See http://jsfiddle.net/VRJUc/. If you open the element inspector (chrome) and look at the actual size of the div you will see that it is actually 60x60 because I have added 5px of padding to each side.
Related
I am trying to create a responsive design for my app.
I have a big background image and it will show the full size when user has large screen and only show partial if user uses small screen.
I want to place few elements on my app with absolute position but the problem is I can't lock their top and left value because the screen size changes.
I have something like
css
#background{
background: url('BG.jpg') no-repeat top center fixed;
width: 1900px;
height: 1200px;
}
#element{
position: fixed;
z-index: 5;
top: 50%; //looks fine in 1900 x 1200 screen but position is off on 1200 x 1000
left:70%; //looks fine in 1900 x 1200 screen but position is off on 1200 x 1000
}
html
<div id='background'></div>
<img id='element' src='test.jpg' />
How do I keep the position of the element on the same spot when user has small screen? Thanks for the help!
When using position: absolute, you need to make sure that it has a parent with a position attribute other than the default (which is static). If there is no such parent, the document is the effective parent. For your example, I would advise making the img#element a child of div#background like so
<div id='background'>
<img id='element' src='test.jpg' />
</div>
and then adding position:relative; to the #background css style
#background{
background: url('BG.jpg') no-repeat top center fixed;
width: 1900px;
height: 1200px;
position: relative;
}
The reason relative is used, is because it doesn't take the element out of the document flow (like fixed or absolute would) and as long as you don't specify a top, left, 'bottom', or right attribute to the parent (#background in the case), it will stay in the same location as it would with default positioning.
Edit:
I don't think this will work out of the box for you. You need to figure out how to make the image's width dynamic as well. You can either give it a % based width or use media queries.
Edit 2:
Ia also just noticed you have position:fixed for img#element. Change that to position:absolute. that will make it so that it is positioned relative to the position:relative parent rather than the window.
Consider making a javascript function that calculates the screen width. After that add margin-left to #background equal to ( screen width / -2 ). Make #background width & height - 100%
I'm using the Snap.js plugin - (it allows you to create scrolling side drawers/panels).
It works by creating 3 absolutely positioned divs, one of which contains main content.
Is there a way to position a div fixed to the top of the window when it is itself inside the absolutely positioned div.
At the moment i'm just getting the fixed div to pin to the top of the absolutely positioned div, rather than to the top of the browser. When I scroll, the div remains fixed to the top of the main content, but not the window.
For example:
<div style="position:absolute;">
<div style="position:fixed;top:0">
<!-- some content which needs to be pinned to top of window -->
</div>
</div>
At the moment i'm using javascript to track the scroll offset and manually adjust the top position of the child div, which is not ideal for performance.
Any help appreciated!
I've made a fiddle showing my javascript workaround - it jitters when scrolling in internet explorer, any ideas.
<div id="displayed-content" class="snap-content scrollable">
<div><!-- regular content --></div>
<div><!-- fixed content --></div>
<div><!-- footer content --></div>
</div>
http://jsfiddle.net/bxRVT/
I am guessing a bit about what you are trying to do, but you might be looking for something like this:
<div class="local-wrap">
<div class="fixed">
Some content which needs to be pinned to top of window
</div>
<div class="port">
Regular content...
</div>
</div>
and apply the following CSS:
.local-wrap {
position: relative;
}
.local-wrap .fixed {
position: absolute;
top: 0;
left: 0;
background-color: lightgray;
width: 100%;
height: 5.00em;
}
.local-wrap .port {
position: relative;
top: 5.00em;
min-height: 10em;
height: 15em;
overflow: auto;
border: 1px solid gray;
border-width: 0 1px 1px 1px;
}
Demo fiddle: http://jsfiddle.net/audetwebdesign/pTJbW/
Essentially, to get a fixed block with respect to a block element, you need to use absolute positioning. Fixed positioning is always with respect to the root element or view port, so position: fixed won't help you.
What I have done is define a .local-wrap container, with two child blocks, one which is
positioned absolutely to the top of .local-wrap and the other in regular flow. I used position: relative to position it below .fixed, but a top margin would have also worked.
I fixed some heights to demonstrate scrolling content within the local window/port, but that can be changed depending on your design and application.
Disclaimer
I am not familiar with snap.js so there may be other considerations to consider.
Comment on CSS3 Transform and Fixed Elements
According to the CSS3 specs, if you apply a transform to an element, call it div.transformed, then div.transformed creates a new stacking context and serves as a containing block for any fixed position child elements that it contains, which is why in your scenario, the fixed position context does not stay at top of the window.
For reference, see Mozilla Developer Network -> CSS Reference -> Transform
In my intro page I have a really big image in height and width to fit all the resolutions (more than 4000px in width) and I set it as below:
#source-image {
width: 100%;
position: absolute;
top: 0;
left: 0;
}
Then, I added some text over that image with these style properties:
.description {
position:absolute;
top:510px;
left:23px;
width:340px
}
And it looks properly (and as I want it to be shown) on my 15.6 inch laptop with 1366x768 resolution.
However when my roommate saw it on his high resolution monitor the description was not on the “right” position. Of course, I understand why this is happening.
My question is how can I keep dynamically the proper position of the description text in all resolutions?
Thank you very much.
Set the distance from the bottom, not from the top. Or set it in %.
EDIT: I've adapted one of my experiments into an example: http://dabblet.com/gist/2787061
The position of the description is set relative to the bottom and the left of the image container (the image is filling its entire container).
In the first case, the distances to the left and the bottom of the image container are fixed, in px.
In the second case, they are in % and change on resizing the browser window.
Basically, the rules that do the trick are
figcaption {
bottom: 5px;
left: 23px;
/* more rules here */
}
in the fist case (fixed distances, in px) and
figcaption.perc {
left: 10%;
bottom: 17%;
}
in the second case (percentage).
Also, please note that you don't need position: absolute or to set the top and the left properties for the image.
However, you do need to set position:relative on the parent of the description box.
For the image to fill the screen horizontally, you need to have margin:0; and padding:0; on the body element and width: 100%; and margin: 0; on the figure element. I've edited my example to reflect these changes http://dabblet.com/gist/2787061
For the image to fill the screen both horizontally and vertically, the easiest way is to not even use an img tag, but simply set the image as a background image for the body and set the height for both the html and the body elements to 100% - example http://dabblet.com/gist/2792929
Be careful for two reasons: one, this will really distort the image and can make it look ugly when resizing the browser window and two, if you need some content below the image you will need to give the the outer element position: absolute and set its top: 100%. Both these two aspects can be seen in the example I've linked to. You can simply remove the content below the image if you don't need it.
use position:relative; for the div that wraps the image, and position:absolute; for the text div
please set percentage
check the example- description box set in horizontal center,
first set position relative into wraper div
.description {
position:absolute;
top:510px;
left:50%;
width:340px;
margin:0 0 0 -170px
}
I am wondering if it is possible to have a scrollbar inside and on top of the DIV as oppose to next to it? I am developing a chrome extension where I have a DIV that contains information on the far right side of the page. When the DIV exceeds the height of the page, a scrollbar appears next to this DIV as oppose to inside and on top of the DIV. In addition, I am wondering if it is possible to get the scrollbar to fade when the user does not hover over it?
I have modified the appearance of the scrollbar by using -webkit in the css. Here is a snippet of what I have done:
#sidebar::-webkit-scrollbar {
width: 8px;
height: 8px;
}
#sidebar::-webkit-scrollbar-track-piece {
background-color: #f3f3f3;
-webkit-border-radius: 0px;
}
#sidebar::-webkit-scrollbar-thumb:vertical {
height: 50px;
background-color: #ccc;
-webkit-border-radius: 0px;
}
As far as having the "inner" scrollbar, you can make the illusion of this by wrapping the DIV with another DIV of equal height and with the desired permanent width. Then set the inner DIV to 100% width, and it will adjust as the scrollbar appears. As far as the fade, I don't believe the scrollbar is part of the DOM, so Javascript is out, but you may be able to use the animate property in CSS http://fvsch.com/code/transition-fade/test1.html
Is it possible to place 1 DIV inside another DIV and have the DIV inside have a larger width and height than the DIV it is contained within?
Sounds like a riddle....
Basically I want to have a container that the user can set the width and height of. They will have also selected and image, cropped it and resized it using jQuery. The image will be the background of the container, however due to the fact that the background image could be made bigger than the container I want it to be possible for the background to be a DIV that can expand beyond the height and width of its container - To crop the image if you like.
Do able?
Yes, if I'm understanding you correctly
the container would be relatively positioned, the div "inside" would be absolutely positioned inside it -
the absolute positioning co-ordinates and getting the image centered would be done something like this, at default,
#inner {
position: absolute;
top: 0 ;
left: 0;
right: 0;
bottom: 0;
background: url(theimage.jpg) no-repeat 50% 50%;
}
this should center the image in the user sized container
then the "cropping tool" would be able to manipulate the co-ordinates (in an equal measure I presume) either + or - those 0 values, -, negative, ones will allow it to expand outside the "outer" container
$('<div>').attr('id', 'innerdiv').appendTo($('#div'));
CSS
#div{
height: 100px;
width: 100px;
background: green;
}
#innerdiv{
height: 200px;
width: 200px;
background: red;
}
HTML
<div id="div"></div>
http://jsfiddle.net/bKetM/
A background image will be 'cropped' by default. For example, if I have a 500px by 500px div and then I put a 1000px by 1000px image as its background then it will show the top left 500px by 500px of that image as a background. I could set the background image to be centered like so:
background:transparent url(image.png) no-repeat center;