I need to parse a json that contains a long number (that was produces in a java servlet). The problem is the long number gets rounded.
When this code is executed:
var s = '{"x":6855337641038665531}';
var obj = JSON.parse(s);
alert (obj.x);
the output is:
6855337641038666000
see an example here: http://jsfiddle.net/huqUh/
why is that, and how can I solve it?
As others have stated, this is because the number is too big. However, you can work around this limitation by sending the number as a string like so:
var s = '{"x":"6855337641038665531"}';
Then instead of using JSON.parse(), you can use a library such as javascript-bignum to work with the number.
It's too big of a number. JavaScript uses double-precision floats for numbers, and they have about 15 digits of precision (in base 10). The highest integer that JavaScript can reliably save is something like 251.
The solution is to use reasonable numbers. There is no real way to handle such large numbers.
The largest number JavaScript can handle without loss of precision is 9007199254740992.
I faced this issue some time ago, I was able to solve using this lib: https://github.com/josdejong/lossless-json
You can check this example:
let text = '{"normal":2.3,"long":123456789012345678901,"big":2.3e+500}';
// JSON.parse will lose some digits and a whole number:
console.log(JSON.stringify(JSON.parse(text)));
// '{"normal":2.3,"long":123456789012345680000,"big":null}' WHOOPS!!!
// LosslessJSON.parse will preserve big numbers:
console.log(LosslessJSON.stringify(LosslessJSON.parse(text)));
// '{"normal":2.3,"long":123456789012345678901,"big":2.3e+500}'
Related
I have a scenario where I need to parsefloat 19 digit string to number.
e.g. parseFloat("1000000000100000043") gives me 1000000000100000000
but the expected output required is 1000000000100000043
This is likely a precision overflow error.
The Number data type (but also int and float in other languages) have a finite number of bits available to represent a number. Typically around 15-16 decimal digits worth.
When length of original number in the string exceeds available precision, such number can no longer be represented by the target data type.
In this case the parseFloat function fails silently. If you want to catch this situation you need to add code to check incoming data or use another function, possibly a custom one.
Alternatively, you can convert the numeric value back to string and compare it with original to detect a discrepancy.
See also a question regarding double.Parse
You are running into how Javascript numbers are stored. See, e.g., here: https://www.w3schools.com/js/js_numbers.asp
You can use a library like decimal.js to work with large, exact numbers. These libraries store the number as string, but allow you to do mathematical operations.
We all know that +, Number() and parseInt() can convert string to integer.
But in my case I have very weird result.
I need to convert string '6145390195186705543' to number.
let str = '6145390195186705543';
let number = +str; // 6145390195186705000, but should be: 6145390195186705543
Could someone explain why and how to solve it?
Your number is above the Number.MAX_SAFE_INTEGER (9,007,199,254,740,991), meaning js might have a problem to represent it well.
More information
You are outside the maximum range. Check in your console by typing Number.MAX_SAFE_INTEGER
If you want a number outside this range, take a look into BigInt that allows to define numbers beyond the safe range
https://developers.google.com/web/updates/2018/05/bigint
Read the documentation well before using it since the usage is different than usual
I am guessing this is to solve the plusOne problem in leetcode. As others have answered, you cannot store value higher than the max safe integer. However you can write logic to add values manually.
If you want to add one to the number represented in the array, you can use the below function. If you need to add a different value, you need to tweak the solution a bit.
var plusOne = function(digits) {
let n = digits.length, carry=0;
if(digits[n-1]<9){
digits[n-1] +=1;
} else{
digits[n-1] = 0;
carry=1;
for(let i=n-2;i>=0;i--){
if(digits[i]<9){
digits[i]+=1;
carry=0;
break;
}else{
digits[i]=0;
}
}
if(carry>0){
digits.unshift(carry);
}
}
return digits;
};
Short answer: Your string represents a number to large to fit into the JavaScript number container.
According to the javascript documentation the maximum safe number is 2^53 which is 9007199254740992 source: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Number
When you try and convert your number you're creating an overflow exception so you get weird results.
In my case, i am converting a string value of '9999999999999999' to integer using parseFloat(). But it converts to next number of it i.e. 10000000000000000. But i need to convert it to before of that number i.e. 999999999999999998. I have searched for a while in google. But could not get clear idea to implement this.
Try this
document.getElementById("demo").innerHTML=Math.round(9999999999999999-2);
OUTPUT
9999999999999998
This number is too big to represented precisely in JavaScript Number value. So no amount of conversion will give you values reliably/precisly as you want around such range.
I.e. (9999999999999999-1)===(9999999999999999) returns true, but (9999999999999998)===(9999999999999999) returns false.
If you need such high precision in JavaScript (similar to many other languages) you need to use specialized data types (unfortunately there is no "BigInteger" type built in in JavaScript).
You will need to use some external javascript library to work with big numbers like that, cause max number you cant represent without losing presicion in javascript integers is 9007199254740992 (Explanation : What is JavaScript's highest integer value that a Number can go to without losing precision?)
Here you have some link where people discuss about some libraries to use for javascript big numbers.
How to deal with big numbers in javascript
I am working on a calculator in javascript, where user can enter the values in textfield and operation will be performed.
Now if user enters a very large value
for example 5345345345353453453453535
it is converted to 5.345345345353453e+24
I am using parsrInt() to convert it to integers. and it gives me 5.
which is wrong .
Can anybody suggest how to solve it?
Integers in javascript are, like every numbers, stored as IEEE754 double precision floats.
So you can only exactly store integers up to 2^51 (the size of the mantissa).
This means you'll have to design another format for dealing with big integers, or to use an existing library like BigInteger.js (Google will suggest a few other ones).
Taken from Mozilla documentation:
Parses a string argument and returns an integer of the specified radix
or base.
Therefore parseInt() is taking your value as a string 5.345345345353453e+24
It is then ignoring any non-integer values and classing this as a decimal (5.345...) and then evaluating this to 5.
As #dystroy has pointed out, if you wish to carry out calculations with these large numbers you'll need to use a custom format, or use a pre-existing javascript library.
Try parseFloat instead of parseInt.
<script type="text/javascript">
var value = parseFloat(5345345345353453453453535);
alert(value);
</script>
As you all know since it is one of the most asked topic on SO, I am having problems with rounding errors (it isn't actually errors, I am well aware).
Instead of explaining my point, I'll give an example of what possible numbers I have and which input I want to be able to obtain:
Let's say
var a = 15 * 1e-9;
alert(a)
outputs
1.5000000000000002e-8
I want to be able to obtain 1.5e-8 instead, but I cannot just multiply by 10e8, round and divide by 10e8 because I don't know if it will be e-8 or e-45 or anything else.
So basically I want to be able to obtain the 1.5000002 part, apply toFixed(3) and put back the exponent part.
I could convert into a string and parse but it just doesn't seem right...
Any idea ?
(I apologize in advance if you feel this is one of many duplicates, but I could not find a similar question, only related ones)
Gael
You can use the toPrecision method:
var a = 15 * 1e-9;
a.toPrecision(2); // "1.5e-8"
If you're doing scientific work and need to round with significant figures in mind: Rounding to an arbitrary number of significant digits
var a = 15 * 1e-9;
console.log(Number.parseFloat(a).toExponential(2));
//the above formula will display the result in the console as: "1.50e-8"