Is it possible to create a table with different number of cells in each and every row with the same width and height ..?? If so how it can be done in a simpler way ..???
Note:
Row width and height are same
Cell width differs in each and every row
<table>
<tr>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td colspan="2"> </td>
<td> </td>
</tr>
<tr>
<td colspan="3"> </td>
</tr>
This is what i have tried using coll span ..Here let's say first row cells width is 30px,30px,30px . if i use coll span , it will be like 60px,30px but i want it as 50px,40px with only 2 cells
I want like this
You can use colspan to create cells that span multiple columns.
jsFiddle
<table>
<tr>
<td> </td>
<td> </td>
<td> </td>
</tr>
<tr>
<td colspan="2"> </td>
<td> </td>
</tr>
<tr>
<td colspan="3"> </td>
</tr>
</table>
If you want all to be the same width and height but only have the number of cells differ you can just not style certain cells in the <table>.
jsFiddle
<table>
<tr>
<td class="content"> </td>
<td></td>
<td></td>
</tr>
<tr>
<td class="content"> </td>
<td class="content"> </td>
<td></td>
</tr>
<tr>
<td class="content"> </td>
<td class="content"> </td>
<td class="content"> </td>
</tr>
</table>
Update
Your update with the image, yes you can accomplish this using colspan:
jsFiddle
<table>
<tr>
<td> </td>
<td colspan="2"> </td>
<td> </td>
</tr>
<tr>
<td colspan="2"> </td>
<td colspan="2"> </td>
</tr>
</table>
This uses four columns, the middle two are smaller than the others, here is an image that illustrates how the columns are set up:
Update #2
Here is an example of more randomly sizes cells. The first row 10%, 90% and the second row 55%, 45%.
jsFiddle
HTML
<table>
<tr>
<td></td>
<td colspan="2"></td>
</tr>
<tr>
<td colspan="2"></td>
<td></td>
</tr>
</table>
CSS
table {
width:100px;
}
td {
border: 1px solid #000;
height:1em;
}
tr:first-child td:first-child {
width:10%;
}
tr:first-child td:last-child {
width:90%;
}
tr:last-child td:first-child {
width:55%;
}
tr:last-child td:last-child {
width:45%;
}
Yes you can, with the colspan attribute for table cells, like this:
<table>
<tr>
<td>1</td>
<td>2</td>
<td>3</td>
<td>4</td>
<td>5</td>
<td>6</td>
</tr>
<tr>
<td>1</td>
<td colspan="2">2</td>
<td>3</td>
<td>4</td>
<td>5</td>
</tr>
<tr>
<td>1</td>
<td colspan="5">2</td>
</tr>
<tr>
<td colspan="2">1</td>
<td>2</td>
<td colspan="2">3</td>
<td>4</td>
</tr>
</table>
Working example: http://jsfiddle.net/sk5cB/
Not positive that this is what you're looking for, but you could create a table with merged cells by using the colspan attribute in your <td> tags.
HTML colspan Attribute
You may also use and create a table in
<tr> </tr> tags
If you intend to insert content in those cells and prefer to maintain the same cell width then it is impossible using only tables. I've searched for solutions on this problem as well, it looks great when the cells are empty like Daniel Imms presented in his example, but if you add content to those cells their width starts getting bigger and the other cells on the row start getting smaller. Specifying table-layout:fixed doesn't help because then the first row becomes the rule for all following rows.
If you have the possibility to use divs with float left and width in percentage and a clear fix display:table div that wraps them all, just like Bootstrap 3 does in its grid system, then that'll be much more reliable.
Related
I have the following React JSX code for a table:
<table>
<tr>
<td>col1</td>
<td>col2</td>
<td>col3</td>
</tr>
</table>
And I want to add a footer with 2 columns filling up the entire width but I'm having trouble doing that. I tried colspan but its not working as expected. How can I do this?
You can do this with colspan, all you need to take into account is that colspan should be integers (1,2,3) and cannot have something like 1.5.
So the trick is to also use colspan in your first row and give them all a colspan of 2, such that the total is 6 which you can divide by two columns of 3.
<table border="1">
<tr>
<td colspan="2">col1</td>
<td colspan="2">col2</td>
<td colspan="2">col3</td>
</tr>
<tr>
<td colspan="3">footer1</td>
<td colspan="3" >footer2</td>
</tr>
</table>
Just colspan your footer cell on all the 3 cells. Then add a separate table within that footer table and make 2 columns. Don't forget to make that inner table as lean as possible (no border, no margin, .. as you need it)
<table border="1">
<tr>
<td>col1</td>
<td width="400">col2</td>
<td>col3</td>
</tr>
<tr>
<td colspan="3">
<table width="100%">
<tr>
<td width="50%">footer left</td>
<td width="50%">footer right</td>
</tr>
</table>
</td>
</tr>
</table>
I am trying to set width:13% of Date column. But it doesn't work in my way. Where is the problem? and can't reduce width of subject column. Thanks in advance.
Check FIDDLE
<div style="width:70%;float:left;">
<div>
<table style="width:100%;" class="TicketsDashboard">
<tbody>
<tr>
<td style="width:13%"><b>Date</b></td>
<td ><b>Type</b></td>
<td ><b>Subject</b></td>
<td ><b>Responsible</b></td>
<td ><b>Action</b></td>
</tr>
<tr style="cursor:pointer;" onclick="openDetailDiv('PROT-155',124)">
<td>2019-07-21 12:52:08</td>
<td>Recommendation</td>
<td>First Subject going on perfectly edited</td>
<td>perfect</td>
<td class="editButtonMain">Edit</td>
</tr>
<tr style="cursor:pointer;" onclick="openDetailDiv('PROT-155',125)">
<td>2019-07-21 12:53:26</td>
<td>Decision</td>
<td>lklk kdj djjdjdjdjdjdjdjdjdjdjdjdjdjdjjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdj</td>
<td>bangldesh</td>
<td class="editButtonMain">Edit</td>
</tr>
</tbody>
</table>
</div>
<br>
<div id="ticketButtons"><input type="button" class="Btn" onclick="openDiag({function: "item", id: 155, dialogTitle: this.value})" value="Add Protocol Item"></div>
</div>
<div style="width:30%;float:left">
<table style="width:100%;" class="lightborder" id="headTable">
<tbody>
<tr id="slaTr">
<td width="100" valign="top">SLA:</td>
<td>
<div id="effortDiv" style="width:50%;float:left;text-align:center;padding-bottom:10px;display:none"></div>
<div id="timeDiv" style="text-align:center;padding-bottom:10px;display:none"></div>
</td>
</tr>
<tr>
<td width="100">Status:</td>
<td id="statusTd">Suggestion</td>
</tr>
<tr>
<td>Protocol Number:</td>
<td id="breadCrumb">PROT-155</td>
</tr>
<tr>
<td>Subject:</td>
<td id="protsubject">Chonchol -- test</td>
</tr>
<tr>
<td>Start Date:</td>
<td id="protstartdate">0000-00-00 00:00:00</td>
</tr>
<tr>
<td>End Date:</td>
<td id="protenddate">0000-00-00 00:00:00</td>
</tr>
<tr>
<td>Keeper:</td>
<td id="protkeeper">ewrwer</td>
</tr>
</tbody>
</table>
</div>
your subject column is going out because u didn't used space in this code <td>lklk kdj djjdjdjdjdjdjdjdjdjdjdjdjdjdjjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdjdj</td> if you want to be stop exceeding you can give space like this <td>lklk kdj djjdjdjdjdjd jdjdjdjdjdjdjdj djjdjdjdjdjdjdj djdjdjdjdjdjdjdjdjdjdjdj djdjdjdjdjdjdjdjdjdjdjdjdjdjdj</td>
What actually you wanted to get let us know clearly.
To increase the width of td
instead of <td style="width:13%"> give <td style="padding-left:13%">
To avoid the overflow
add
<style>
table { table-layout:fixed; }
table td {word-wrap:break-word;}
</style>
Thanks,
the reason of it, you should set the same style for the given column in every rows, or add a thead section in which you set it once of the column.
$(".rowIWanTtoReplace").replaceWith("<tr><td rowspan='11' class='n'>n</td><td rowspan='8'>n</td><td>t</td><td>n</td></tr><tr><td>u</td><td>n</td></tr><tr><td>v</td><td>n</td></tr><tr><td>w</td><td>n</td></tr><tr><td>x</td><td>n</td></tr><tr><td>y</td><td>n</td></tr><tr><td>z</td><td>n</td></tr>");
td {
border: 1px solid black
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>
<table class="station-device-table4">
<tr>
<td>x</td>
<td>y</td>
<td>z</td>
</tr>
<tr class="rowIWanTtoReplace">
<td rowspan="11" class="s">foobar</td>
<td rowspan="7">foobar</td>
<td>n</td>
</tr>
</table>
I just wanted to check whether or not this should be the result of a replaceWith() in this situation:
If I have a table and on one row I apply replaceWith(), And What I replace it with is multiple table rows.
Shouldn't that just affect the HTML so when displayed multiple should show in that section?
i.e ------ TR 1 -----------
.replaceWith("<tr>x</tr><tr>y</tr>")
shouldn't the first row replace the other row. And the second row append after?
Or is there an alternative method?
Thanks.
Example code for situation:
<table class="station-device-table4">
<tr>
<td>x</td>
<td>y</td>
<td>z</td>
</tr>
<tr class="rowIWanTtoReplace">
<td rowspan="11" class="s">foobar</td>
<td rowspan="7">foobar</td>
<td>n</td>
</tr>
</table>
JQuery example:
$(".rowIWanTtoReplace").replaceWith("<tr>
<td rowspan="11" class="n">n</td>
<td rowspan="8">n</td>
<td>t</td>
<td>n</td>
</tr>
<tr><td>u</td><td>n</td></tr>
<tr><td>v</td><td>n</td></tr>
<tr><td>w</td><td>n</td></tr>
<tr><td>x</td><td>n</td></tr>
<tr><td>y</td><td>n</td></tr>
<tr><td>z</td><td>n</td></tr>")
Note: This is made from backbone collections and stuff. I have outputted to the screen the html that it using to update. And put the code together as if it was normal jquery.
You cannot have linefeeds in strings unless you use template literals - also you had nested double quotes which also does not work.
In the original code you replaced a header cell with a table row which also did not compute.
This might be what you want:
$(".rowIWanTtoReplace").replaceWith(`<tr>
<td rowspan="11" class="tvmStatus">TVM Status</td>
<td rowspan="8">Component Events</td>
<td>t</td>
<td>n</td>
</tr>
<tr><td>u</td><td>n</td></tr>
<tr><td>v</td><td>n</td></tr>
<tr><td>w</td><td>n</td></tr>
<tr><td>x</td><td>n</td></tr>
<tr><td>y</td><td>n</td></tr>
<tr><td>z</td><td>n</td></tr>`)
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table class="station-device-table4">
<tr>
<td>x</td>
<td>y</td>
<td>z</td>
</tr>
<tr class="rowIWanTtoReplace">
<td rowspan="11" class="s">foobar</td>
<td rowspan="7">foobar</td>
<td>n</td>
</tr>
</table>
I'm working with the following HTML:
<tr class="oddrow">
<td>row1</td>
<td style="text-align:center;">
<table>
<tbody>
<tr>
<td width="50%">-1<br>+1</td>
<td width="50%">WSH: -110<br>SAC: -110</td>
</tr>
</tbody>
</table>
</td>
<td style="text-align:center;">
<table>
<tbody>
<tr>
<td width="50%">202.5</td>
<td width="50%">o: -110<br>u: -110</td>
</tr>
</tbody>
</table>
</td>
<td style="text-align:center;">WSH: 0<br>SAC: 0</td>
</tr>
<tr class="evenrow">
<td>row2</td>
<td style="text-align:center;">
<table>
<tbody>
<tr>
<td width="50%">-1<br>+1</td>
<td width="50%">WSH: -110<br>SAC: -110</td>
</tr>
</tbody>
</table>
</td>
<td style="text-align:center;">
<table>
<tbody>
<tr>
<td width="50%">202.5</td>
<td width="50%">o: -110<br>u: -110</td>
</tr>
</tbody>
</table>
</td>
<td style="text-align:center;">WSH: 0<br>SAC: 0</td>
<!-- The above line is the one I need. --!>
</tr>
There are 2 such rows (row1 and row2), alternating as an oddrow then evenrow. I have the entire HTML as a string in my JavaScript/jQuery code. I also have the information of the two three-letter abbreviations: in this example, WSH and SAC. What I need is the third <td style="text-align:center;"> of the row2 row. I should point out that there are several tables of row1 and row2 on the page, so I need a general selector. What I have been doing is just grabbing all the data in all the rows then parsing it from there, but the inconsistency of the data is making that more difficult. Is there a quick and dirty jQuery that will point me to the data I need?
I was thinking something like $("tr td:contains(" + abbrev + ") td:contains('row2')").text();, but that doesn't get it.
Can anyone help?
Your hierarchy in your selector is wrong, tds with the abbreviation are not an ancestor to the tds with the text of "row2"
You also need to ensure you have apostrophes around your abbrev variable.
Can you try:
$("tr td:contains('row2') td:contains('" + abbrev + "')").text()
Any chance you can add semantic classes instead? These sorts of selectors are gnarly to maintain.
<table class="tbl">
<tr>td class= "colorcode" colspan ="5"/><tr>
<tr class="ms.alternative>
<td></td>
<td class="bkcolor"></td>
<td class="bkcolor"></td>
<td class="bkcolor"></td>
<td> </td>
</tr>
<tr><td colspan="5"/></tr>
<tr>td class= "colorcode" colspan ="5"/><tr>
<tr class="ms.alternative>
<td></td>
<td class="bkcolor"></td>
<td class="bkcolor"></td>
<td class="bkcolor"></td>
<td></td>
</tr>
<tr><td colspan="5"/></tr>
<tr>td class= "colorcode" colspan ="5"/><tr>
<tr class="ms.alternative>
<td></td>
<td class="bkcolor"></td>
<td class="bkcolor"></td>
<td class="bkcolor"></td>
<td></td>
</tr>
<tr><td colspan=""/></tr>
</table>
I am new to jquery.. please help me to figure it out.
In the scenario above:
Now my question is: how would you select all tr with
class ms.alternative than find(td.bkcolor)
get the color of <td.bkcolor>
Now, if:
(number of majority of background color of '`tr.ms.alternative`' '`td.bkcolor`'
is red)
{
change td.colorcode.css(background-color:'red')
}
$('tr[class="ms.alternative"]').find('td[class="bkcolor"]').css("background-color");
will provide you the backgound color
$('tr[class="ms.alternative"]').find('td[class="bkcolor"]').css("background-color","new color");
will change the background-color in your case