Develop Reference

How to get next 3 characters after a substring if it exist inside a string?

I have this string that's. The &# substring is common but number after it changes in almost every object of my JSON data. So I want to detect if there is this substring, then get next three characters after it replace it with something else. How can I do it?

You can do it like this
var para = 'that's';
para = para.substr(para.indexOf('#')+1, 3);
syntax:
substr(start, length)
indexOf(searchvalue, [start])

Assuming you want to replace everything from &# until ; (if not, please update your question by specifying expected output):
You can use String.prototype.replace() with a regular expression:
var para = 'some string ' middle † end';
para = para.replace(/&#([\d]*);/g, 'replacement');
The g modifier is important to replace all occurences in the string.
With the RegEx used, you can include the found number (between &# and ;) in the replacement string by using $1.

you can define and use a utility function to replace HTML entities like that:
function decode(text, replaceWith = '') {
return text.replace(/&#(\d+);/g, replaceWith)
}

Regex Help for content between two strings (javascript)

Hoping someone might help. I have a string formatted like the example below:
Lipsum text as part of a paragraph here, yada. |EMBED|{"content":"foo"}|/EMBED|. Yada and the text continues...
What I am looking for is a Javascript RegEx to capture the content between the |EMBED||/EMBED| 'tags', run a function on that content, and then to replace the entire |EMBED|...|/EMBED| string with the return of that function.
The catch is that I may have multiple |EMBED| blocks within a larger string. For example:
Yabba...|EMBED|{"content":"foo"}|/EMBED|. Dabba-do...|EMBED|{"content":"yo"}|/EMBED|.
I need the RegEx to capture and process each |EMBED| block separately, since the content contained within will be similar, but unique.
My initial thought is that I could just have a RegEx that captures the first iteration of the |EMBED| block, and the function which replaces this |EMBED| block is either part of a loop or recursion to continuously find the next block and replace it, until no more blocks are found in the string.
...but this seems expensive. Is there a more eloquent way?

You can use String.prototype.replace to replace a substring found via a regular expression with a modified version of the match using a mapping function, e.g.:
var input = 'Yabba...|EMBED|{"content":"foo"}|/EMBED|. Dabba-do...|EMBED|{"content":"yo"}|/EMBED|.'
var output = input.replace(/\|EMBED\|(.*?)\|\/EMBED\|/g, function(match, p1) {
return p1.toUpperCase()
})
console.log(output) // "Yabba...{"CONTENT":"FOO"}. Dabba-do...{"CONTENT":"YO"}."
Make sure that you use a non-greedy selector .*? to select the content between the delimiters to allow multiple replacements per string.

This is the cod which iterate through the matches of the regex:
var str = 'Lipsum text as part of a paragraph here, yada. |EMBED|{"content":"foo"}|/EMBED|. Yada and the text continues...';
var rx = /\|EMBED\|(.*)\|\/EMBED\|/gi;
var match;
while (true)
{
match = rx.exec(str);
if (!match)
break;
console.log(match[1]); //match[1] is the content between "the tags"
}

Replace with value '$' does not work in javascript

i tried to replace a string, provided the string regex with a value that has $ in the end.
Can anyone tell me what is happening in
Looking into mdn string replace docs, i found it is expected.
But what should one do he want to ignore this.
Means i want the replacing value should get as it is replaced, with 4 $s here.

You need to double the dollars in the replacement pattern as $$ are actually $.
.replace(/{{one}}/g, '000$$$$$$$$')
See String#replace help:
Pattern Inserts
$$ Inserts a "$".
If a user types $ in the replacement (that is, in case it is user-defined) you can just double it:
var ptrn = "{{one}}"; // regex pattern from user input
var repl = "000$$$$"; // replacement from user input
var rx = RegExp(ptrn, "g"); // building a dynamic regex
document.write("pp{{one}}pp".replace(rx, repl.replace(/\$/g, '$$$$')));
// ^--- doubling $s-----^

Regular expression to match a string which is NOT matched by a given regexp

I've been hoving around by some answers here, and I can't find a solution to my problem:
I have this regexp which matches everyting inside an HTML span tag, including contents:
<span\b[^>]*>(.*?)</span>
and I want to find a way to make a search in all the text, except for what is matched with that regexp.
For example, if my text is:
var text = "...for there is a class of <span class="highlight">guinea</span> pigs which..."
... then the regexp would match:
<span class="highlight">guinea</span>
and I want to be able to make a regexp such that if I search for "class", regexp will match "...for there is a class of..."
and will not match inside the tag, like in
"... class="highlight"..."
The word to be matched ("class") might be anywhere within the text. I've tried
(?!<span\b[^>]*>(.*?)</span>)class
but it keeps searching inside tags as well.
I want to find a solution using only regexp, not dealing with DOM nor JQuery. Thanks in advance :).

Although I wouldn't recommend this, I would do something like below
(class)(?:(?=.*<span\b[^>]*>))|(?:(?<=<\/span>).*)(class)
You can see this in action here
Rubular Link for this regex
You can capture your matches from the groups and work with them as needed. If you can, use a HTML parser and then find matches from the text element.

It's not pretty, but if I get you right, this should do what you wan't. It's done with a single RegEx but js can't (to my knowledge) extract the result without joining the results in a loop.
The RegEx: /(?:<span\b[^>]*>.*?<\/span>)|(.)/g
Example js code:
var str = '...for there is a class of <span class="highlight">guinea</span> pigs which...',
pattern = /(?:<span\b[^>]*>.*?<\/span>)|(.)/g,
match,
res = '';
match = pattern.exec(str)
while( match != null )
{
res += match[1];
match = pattern.exec(str)
}
document.writeln('Result:' + res);
In English: Do a non capturing test against your tag-expression or capture any character. Do this globally to get the entire string. The result is a capture group for each character in your string, except the tag. As pointed out, this is ugly - can result in a serious number of capture groups - but gets the job done.
If you need to send it in and retrieve the result in one call, I'd have to agree with previous contributors - It can't be done!

Match a string if it comes after certain string

I need a regular expression for JavaScript to match John (case insensitive) after Name:
I know how to do it, but I don't know how to get string from a different line like so (from a textarea):
Name
John
This is what I tried to do :: var str = /\s[a-zA-Z0-9](?= Name)/;
The logic: get a string with letter/numbers on a linespace followed by Name.
Then, I would use the .test(); method.
EDIT:
I tried to make the question more simple than it should have been. The thing I don't quite understand is how do I isolate "John" (really anything) on a new line followed by a specific string (in this case Name).
E.g., IF John comes after Name {dosomething} else{dosomethingelse}

Unfortunately, JavaScript doesn't support look-behinds. For something this simple, you can just match both parts of the string like this:
var str = /Name\s+([a-zA-Z0-9]+)/;
You then just have to extract the first capture group if you want to get John. For example:
"Name\n John".match(/Name\s+([a-zA-Z0-9]+)/)[1]; // John
However if you're just using .test, the capture group isn't necessary. For example:
var input = "Name\n John";
if (/Name\s+[a-zA-Z0-9]+/.test(input)) {
// dosomething
} else{
// dosomethingelse
}
Also, if you need to ensure that Name and John appear on separate lines with nothing but whitespace in between, you can use this pattern with the multi-line (m) flag.
var str = /Name\s*^\s*([a-zA-Z0-9]+)/m;

You do not need a lookahead here, simply place Name before the characters you want to match. And to enable case-insensitive matching, place the i modifier on the end of your regular expression.
var str = 'Name\n John'
var re = /Name\s+[a-z0-9]+/i
if (re.test(str)) {
// do something
} else {
// do something else
}
Use the String.match method if you want to extract the name from the string.
'Name\n John'.match(/Name\s+([a-z0-9]+)/i)[1];
The [1] here refers back to what was matched/captured in capturing group #1