On clicking a radio button in radiogroup2, the selected radio should swap positions with the radio with the id='selectedradio'. fiddle http://jsfiddle.net/DCC66/6/ --- updated --- clear view of radio rows and code is swapping but cancelling out http://jsfiddle.net/DCC66/14/
tried this to sort the id issue: http://jsfiddle.net/DCC66/18/
$(".radiogroup2 input[type='radio']").on('click', function () {
$('#radioselected').closest('label').before($(this).closest('label'));
$(this).closest('label').after($('#radioselected').closest('label'));
$(this).attr('domaintype', 'radioselected');
$('radioselected').attr('radioselected', 'domaintype');
});
and now this:// swaps once then stops and then just makes the clicked radio disapear. think it needs to add the id="radioselected" to the newly swapped radio. also still not swapping though only replacing radio.
$(".radiogroup2 input[type='radio']").on('click', function ()
{
$('#radioselected').closest('label').replaceWith($(this).closest('label'));
});
trying using clone still no luck:
$("div.radiogroup2 input[name='domain_ext']").click(function ()
{
$(this).clone('#radioselected').after(this);
});
Original
$("div.radiogroup2 input[name='domain_ext']").click(function()
{
//only if a the radio in radiogroup to are clicked take radio and swap with id='radioselected'
if ($(this).prop('checked'))
{
$(this).after('#radioselected').add(this);
$('#radioselected').after(this);
}
});
so any radio clicked in the "swap" row should switch positions with the radio in the first row with the id 'selectedradio'
Use a delegate instead of binding the event on the radio buttons directly. That way the radio buttons that are swapped into the div will also work.
Use the closest method to get the label around the radio buttons.
Remove the id from the radio button that you swap with, and add it to the selected radio button.
Use the after method to move the label into the second list next to the selected one, then use prependTo to move the label with the selected radio button into the first list.
You have some invalid HTML code that makes the rows swap place. Change <td><tr> to <tr><td>.
$("div.radiogroup2").on("click", ":radio", function () {
var l = $(this).closest('label');
var r = $('#radioselected');
r.removeAttr('id');
l.after(r.closest('label'));
$(this).attr('id', 'radioselected');
l.prependTo('.radiogroup1');
});
Demo: http://jsfiddle.net/DCC66/16/
Related
I have a table where all line have a input(type:radio) as an rowid.
In this way, I want mark the input as checked when the user click at line from the respective radio and so on in all lines.
$('tr').on('click' ,function(){
$(this).find('input[type=radio]').prop('checked':true);
});
When you click any TR find the radio's inside it and check them manually
$('#rowId').on('click', function() {
$('#radioIdForRow').prop('checked', true);
}.bind(this));
This is the same as #joyBlanks's answer, but gives you the flexibility to have the radio button not be within the DOM tree of the row.
I want to hide and show list items based on their attributed class.
The problem is that certain list items have multiple classes. So if I toggle one class then toggle another, any items with both selected classes will be removed.
I created a demo of my problem: http://jsfiddle.net/a4NkN/2/
Here's the JS CODE:
$('#easy').click(function(){
$(this).toggleClass( "checked" );
$('.easy').toggle();
});
$('#fun').click(function(){
$(this).toggleClass( "checked" );
$('.fun').toggle();
});
$('#silly').click(function(){
$(this).toggleClass( "checked" );
$('.silly').toggle();
});
If you select the "Easy" and "Fun" buttons, Boating will disappear.
How can I get Boating to stay?
This might be a good point to start from. Although you can do this cheaper and cleaner, that gives the idea:
Use an array to save the status of your selection buttons and one corresponding to hold the class names. Whenever your select buttons get clicked, you set all your elements invisible and reset those visible again, that are already selected by other buttons or the currently clicked, which is all saved in the switcher array.
//saves whether button is active
var switcher = [false, false, false];
//holds your classes selectable
var classes = ['easy', 'fun', 'silly'];
$('.toggler').click(function () {
// toogle the select button and save status
var x = $(this).hasClass('checked');
switcher[$(this).data('switch')] = !x;
$(this).toggleClass("checked", !x);
// iterate through your elements to set them active if needed
$('li').each(function () {
var cur = $(this);
cur.addClass('hidden');
$.each(switcher, function (index, data) {
if (data && cur.hasClass(classes[index])) {
cur.removeClass('hidden');
}
});
});
});
Whole solution in this fiddle: http://jsfiddle.net/BMT4x/
You cannot unconditionally toggle elements based on a click on one of the button filters if it is possible for an element to satisfy multiple filters at once. The correct approach is a little more involved.
Since your checked class means that only items corresponding to that button should be shown, do exactly this: toggle them based on the current status of the button. The items should be shown if and only if the corresponding button is checked as a result of clicking it.
$('#easy').click(function(){
$(this).toggleClass( "checked" );
$('.easy').toggle($(this).is(".checked"));
});
This code uses the last version of .toggle, the one accepting a boolean argument.
It can also be done more succintly:
$('.easy').toggle($(this).toggleClass( "checked" ).is(".checked"));
Example on JS FIddle.
The question is:
If the first click is on the radio button, it behaves normally; But if the first click is on span text (i.e. aaaa), it can not get the checked radio.
Please tell me why and how I can make it the same.
This code, which happens when the radio button is clicked:
var obj = $(e.target||e.srcElement).parent();
score = obj.find('input:checked').val();
Puts the parent in the obj variable, which is the containing DIV. This contains both of the radio buttons. It then finds the FIRST checked input element in that DIV, which is always the one with the 'first' value after it is checked.
You should just get the value of the item which was clicked:
score = $(e.target||e.srcElement).val();
This can be rewritten as
score = $(this).val();
Here's a working example: http://jsfiddle.net/RPSwD/10/
See new fiddle.
The problem is this line:
score = obj.find('input:checked').val();
Change it to:
score = $(this).val();
The reason for this is that you're looking for the selected item in the div but on the first click, the item has yet to become selected. Given that the event is targeted at the radio button, you can assume that radio is the selected one.
Note also that you don't need to use e.target||e.srcElement. jQuery takes care of this for you. Use $(this) instead.
Additionally, you need to set a name on the radio buttons to stop both from becoming selected. Alternatively, if having both selected is desired behaviour, use check boxes instead.
You don't need to use any of the event properties:
var score = $(this).val(); // in your '.x' click handler
$('.y').click(function(e) {
$(this).prev('.x').click();
});
just wrap your radio button inside label tag like this
<label for="radio1">
<input type=radio class="x" id="radio1" value="First"/>
<span class="y">aaaa</span>
</label>
No need for extra jquery or javascript
check the demo here
I need to collect the values of the checked radio buttons on page load (they are checked on page load) and add them and not only when the user clicks a radio button.
Here's the javascript:
$(function ()
{
updateDivResult();
$('input:radio').live('click',updateDivResult);
$('#1').click();
})
function updateDivResult(){
if ($("input:radio:checked"))
{
price = parseFloat($(this).val());
$('#price').html(roundNumber(price,2));
}
};
roundNumber() is a function defined by me.
Now it only updates the #price div when the user clicks a radio button.
Also, there are a few groups of radio buttons - how do I only add the value of one radio button from the group to the total price?
Thank you for assistance.
I think you need to loop through the checked values rather than just getting the val() of that selector because it seems like there could be more than one checked.
function updateDivResult(){
var price = 0;
$(":radio:checked").each(function(){
price += parseFloat($(this).val());
});
$('#price').html(roundNumber(price,2));
};
Can you provide more details?
I can see you are using jQuery.
You could use
$(document).ready(function() {...});
to run some methods when the document is read.
Moreover you could put a specific class to your html elements and use the "each" function to traverse them.
e.g.
$('.your_el').each(function() {...});
In that case the handler will be executed on each object with the class "your_el".
Hope this help, even if the problem is not so clear to me.
Che
The problem is mostly summed up in the title.
I am using the custom radio/checkbox code from accessible_custom_designed_checkbox_radio_button_inputs_styled_css_jquery/
This is the jist of their code (I modified it to allow defining different style depending on the label's title)
$(this).each(function(i){
if($(this).is('[type=radio]')){
var input = $(this);
// get the associated label using the input's id
var label = $('label[for='+input.attr('id')+']');
var labelTitle = label.attr('title');
// wrap the input + label in a div that has class "custom-radio-LabelTitle"
$('<div class="custom-radio-' + labelTitle + '"></div>').insertBefore(input).append(input, label);
// find all inputs in this set using the shared name attribute
var allInputs = $('input[name='+input.attr('name')+']');
//bind custom event, trigger it, bind click,focus,blur events
input.bind('updateState', function(){
if (input.is(':checked')) {
if (input.is(':radio')) {
allInputs.each(function(){
$('label[for='+$(this).attr('id')+']').removeClass('checked');
});
};
label.addClass('checked');
}
else { label.removeClass('checked checkedHover checkedFocus'); }
})
.trigger('updateState')
.click(function(){
$(this).trigger('updateState');
})
}
});
From my understanding, their code basically finds all the radio inputs and then defines a special trigger called updateState. Then they trigger it inside the input's click function.
So every time the input radiobutton is clicked, updateState is trigger, which in turn sets a class for that radiobutton's label. The changing of the class changes the CSS of the label.
When the label is clicked, The input that the label is for is also clicked (JQuery's .click() function is ran).
What I did was set all my input radiobuttons to display:none. That way the user only clicks the label, and secretly they clicked a radio button.
The .click() function won't run for the input if the input is hidden.
I assume there are two ways pass this:
instead of have the radio's .click() function trigger the handlestate, have the label's .click() function handle it instead. This may not work right though, because then the radio button may not actually be clicked (which messes up my form)
when the label is clicked, trigger the radio's click function manually. However, this may cause it to be triggered twice in every browser but IE. I don't know how to reference the label's radio nor to stop it from triggering twice.
a) instead of have the radio's
.click() function trigger the
handlestate, have the label's .click()
function handle it instead. This may
not work right though, because then
the radio button may not actually be
clicked (which messes up my form)
This may work right, on you label's .click() trigger also force the radio button to be checked like this,
$('#radiobutton').attr('checked', 'checked');
I got what I wanted with:
$("label[title='Plan']").click(function() {
var id = $(this).attr('for')
$("input[id='"+id+"']").trigger("click");
$("input[id='"+id+"']").trigger("updateState");
PlanChange();
});
Then removed all the onClicks.