Develop Reference

Display three divs by order absolute than fixed than relative

I have some problems when rendering on only app(iOS) NOT website:
I have to use pure Javascript without any other libraries.
<div class="header" style="position:fixed; z-index: 99;"></div>
<div class="content" style="position:relative">
<div class="cover" style="position:absolute; z-index:999;"></div>
//some text content
</div>
The Cover div didn't display overlapping Header. What can I do to that?
I want that initially user will see Cover first, then scroll up then see fixed Header and eventually Content.
I dont want to change the HTML, because when I put header in content div, header usually jumps and take moment to back the correct position when scrolling content div.
Thanks for any help!

Give #content a z-index property, too. Say, 100.
The problem looks like z-index context. z-index is not a global value - it is relative to it's parent. You have #header with z-index:99, and it's sibling #content with z-index:auto(say 1 for argument's sake). #header always overlaps #content, and its children.

You are using absolute property to cover class, relative to content className that means, it position will change according to content class. Remove relative property to content class, add wrapeer to all header and content className.
<div style="position:relative">
<div class="header" style="position:fixed; z-index: 99;"></div>
<div class="content" >
<div class="cover" style="position:absolute; z-index:999;"></div>
//some text content
</div>
</div>

How to hide the rest of unused image

more you ask, more knowledge you get. Right ? I don't know this question is basic or not but a little make me think hard.
Look pic 1 what do i have.
pic 1: http://imgur.com/YFpfo69
When i upload an image, it will show up to the container called <img id="image"/> and the image is horizontally draggable. My problem is, how do i hide the rest of unused image ? When i dragging the image, the rest will not showing up

To fix this you can place overflow: hidden in the CSS of the parent element of the #image element.

Add the style overflow: hidden; to the parent element, like this:
<div style="overflow: hidden;">
<img src="img.png" id="image" />
</div>

Single page website with jQuery - Content in JS or HTML

I'm just picking up JS & jQuery and consider myself quite capable with HTML/CSS. I'm in the middle of building a single page front-end only website. I've got the layout nailed down with Bootstrap and now I'm just trying to figure out some of the functionality. My scenario is as follows:
There are 4 <div>s with text and an image in each of the 4 <div>s; and there is a <div> with class #content below it. There is a .on('click') listener for each of the #c1-4 divs and when the user clicks on a particular div, the #content div will change accordingly.
<div id="#c1" class="active-div">
<p>Text Here</p>
<img src="image.jpg">
</div>
<div id="#c2">
<p>Text 2 Here</p>
<img src="image2.jpg">
</div>
<div id="#c3">
<p>Text 3 Here</p>
<img src="image3.jpg">
</div>
<div id="#c4">
<p>Text 4 Here</p>
<img src="image4.jpg">
</div>
<div id="#content">
<!-- Content of the selected div goes here -->
</div>
By default, #c1 <div> is selected. The content that goes in to #content is mostly text but some icons and images too, with appropriate styling.
The Question: What is the best way to store & load content into the #content div? Based on my knowledge so far I believe the options are:
Hard-coding it into the JS and using .html() to set the content; although this would add quite a bit of HTML to the JS.
Hard-coding 4 different divs related to each of the 4 #c IDs and using .show() and .hide() accordingly.
Using .load() to load the content from another HTML document. However, I'm not sure how styling would be handled and how this will affect the display of the #content div.
I would also like to know the pros and cons of each of the above approaches and which one would be more suitable for future maintenance (e.g. adding a fifth, sixth #c numbered div to select & load content for).

In real world developers consider backend data to replace / append content based on user's clicks and it is just second thing how exactly you append / prepend / html or load your content to your div element. Not sure how you are going to hardcode different content according to the clicked button, I think in your case #2 & #3 should do the trick.
There is append / prepend actions you can use (they are self-explanatory I guess, but might be useful in some cases).
As I mentioned initially in ideal work you will do queries to your backend endpoints (databases, API etc..) and fetch content from there. Once done, you just style it accordingly using those divs and css (either inline or CSS table) things. Focus on overall construction!

There are a lot of ways to do this and a lot of JS frameworks out there that do it differently, but all of your options are appropriate in my opinion, especially given that you're using jQuery. I'll just talk a bit about your three options:
You can hard-code it into your JS, but you can also place the content in your HTML in a <script> tag and load it as a JavaScript string in jQuery, like they do for Underscore templates.
<script type="text/template" id="div-1">
<span>Hey, this is some content</span>
</script>
Then later in your JavaScript, just do $('#div-1').html() to get the contents of it, and you can stick that in your content div.
This option is also perfectly acceptable.
As long as you have all your css already applied to the document, dynamically changing the DOM won't affect its ability to apply styles. Just make sure you have all the rules in a stylesheet that is already loaded.

Expanding on my comment, here is how you could do it with hidden content divs and replacing html using .html()
$(function() {
var content = $('.active-div .content').html();
$('#content').html(content);
$('.item').click(function() {
$('.item').removeClass('active-div');
$(this).addClass('active-div');
content = $('.active-div .content').html();
$('#content').html(content);
});
});
.item {
cursor: pointer;
display:inline-block;
padding-right:10px;
}
.content {
display: none;
}
#content {
background: #000;
color: #fff;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="item active-div" id="#c1">
<p>Text Here</p>
<img src="image.jpg">
<div class="content">Sample content 1</div>
</div>
<div class="item" id="#c2">
<p>Text 2 Here</p>
<img src="image2.jpg">
<div class="content">Sample content 2</div>
</div>
<div class="item" id="#c3">
<p>Text 3 Here</p>
<img src="image3.jpg">
<div class="content">Sample content 3</div>
</div>
<div class="item" id="#c4">
<p>Text 4 Here</p>
<img src="image4.jpg">
<div class="content">Sample content 4</div>
</div>
<div id="content">
<!-- Content of the selected div goes here -->
</div>

django-cms div tags with cmsplugin class interfering with slider

I am using Django CMS 3.0.3. I've written a cms plugin with 2 CMSPluginBase derived classes, one adds a slider to a placeholder and another one is for adding slides as children to the slider.
In live mode everything works fine, but when I am editing content, I can't use the slider. The reason is that django-cms is decorating the html code with additional elements like this:
<div class="slider">
<div class="cms_plugin cms_plugin-2" style="width: 0px; overflow: hidden; position: absolute; left: 0px; display: block;">
<!-- Slider Item -->
<div class="slider-item"> [MY SLIDER CONTENT] </div>
<!-- /Slider Item -->
</div>
</div>
I got the HTML/CSS/JS from somebody else and I would preferable not use another slider. What options do I have to work around this problem?
Is there a way in django-cms to switch off the wrapping of plugins in "content mode" only, but to have the placeholder <div> included in "structure mode"? That would not be super convenient, but a workaround that I can live with.
Is there something else, I could do? I don't want to touch the slider itself. It might get an update and then I'd have to adjust it to adjust the slider to my needs again.

django-cms is need to wrap your plugin with <div class="cms_plugin cms_plugin-2"> for relation with "structure mode". There are no other variants.

JQuery: How to switch image back and forth?

I have the following HTML:
<div class="listing ref_1">
...
<div><img src="toggleON.png" /></div>
...
</div>
<div class="listing ref_2">
...
<div><img src="toggleON.png" /></div>
...
</div>
<div class="listing ref_3">
...
<div><img src="toggleON.png" /></div>
...
</div>
What I want to do is programmatically change the toggleON.png image to toggleOFF.png.
I'm trying to use the following code to do so but it's not working:
$('.ref_2').src("toggleOFF.png");
Anyone know what I'm doing wrong because the code above doesn't work.
Also, is there a better way to handle this?

'.ref_2' points to the div, you'll have to get to the image within the div
$('.ref_2 img').attr("src","toggleOFF.png");
would probably do it for you.

You need to select the img tag in side .ref_2
$('.ref_2 img').attr("src","toggleOFF.png");
It might be better though to put the image definition in css and swap classes.
<style>
.toggleOn div{
background: url('toggleOn.png') no-repeat;
}
.toggleOff div{
background: url('toggleOff.png') no-repeat;
}
</script>
<div class="listing ref_1 toggleOn">
...
<div></div>
...
</div>
<div class="listing ref_2 toggleOn">
...
<div></div>
...
</div>
<div class="listing ref_3 toggleOn">
...
<div></div>
...
</div>
<script>
$('.ref_2').removeClass('toggleOn').addClass('toggleOff');
</script>
This makes it really easy to change the image and lets you use the class as a state toggle if you need to check on it later.
Also it looks like you are using ref_# as a unique identifier, if so then it would be better to make it the ID of the div, will speed up jQuery's ability to find the element.

What I like to do is put both images in my main document in a hidden div, like:
<div style="position: absolute; visibility: hidden">
<img id="toggleON" src="/whatever/toggleON.png" .../>
<img id="toggleOFF" src="/whatever/toggleOff.png" .../>
</div>
That way they're both in the browser's cache. Then, to toggle an image from one to the other, you can do something like:
$(".whatever img").replaceWith($("#toggleON").clone());

Another solution is to put both image on absolute position, with the default one is set to the front (Using z-index property).
On mouse hover, you can hide the one in the front and the toggled-off image will showed up. The advantage of using this method is you could actually use animation technique to make it even smoother. It's what I did here. (It would be better if you have an additional wrapper div and set the mouse hover event on it)