I am working on something here, I have a button, when you click on this button I want another page to open in a new window and not a new tab.
How would I do this in codeigniter?
I have a function in my controller like so
function print_members(){
$this->load->model('common_model');
$data = $this->common_model->general();
$data['members'] = $this->common_model->all_members();
$this->load->view('print_members', $data);
}
and when the user clicks on my input button
<?php echo form_open('controller/print_members', array('id'=>'form', 'target' =>'_blank')); ?>
<input id="print" type="submit" name="print" value="Print"/>
<? echo form_close(); ?>
I am basically looking for away to open `controller/print_members' function in a new window. The following code aboves opens it in a new tab.
This can be done by javascript
Javascript
<script>
function popup(){
var xhr = "<?php echo base_url('print_members')?>" /***controller url****/
popup=window.open(xhr,'print members' 'width=500,height=500');
}
</script>
you can used input or href like this
<input id="print" type="button" name="print" value="Print" onclick="popup()"/>
Or
<a href="void:javascript" onclick="popup()"/>Print </a>
no change in controller file
Related
I have 2 page
the innerhtml onclick page (a.php)
the page that start session (b.php)
in a.php I write function onclick to change some text
and I add the session from b.php in this text, but nothing change in text
$(document).ready(function(){
$('.add-to-cart').on('click',function(){
document.getElementById('outside_cart_text').innerHTML =
"Qty type <?php echo $this->session->userdata('qty_type'); ?> amount <?php echo $this->session->userdata('qty_product');?>";
});
});
it change the original text to "Qty type amount". But session value not appear.
the question is how to make it appear instantly?
additional detail : My click is on the button sumbit to other page, but I have already use this trick. It work like ajax. so after click I still in the same page (and not reload)
<style>
.hide { position:absolute; top:-1px; left:-1px; width:1px; height:1px; }
</style>
<iframe name="hiddenFrame" class="hide"></iframe>
<form action="receiver.pl" method="post" target="hiddenFrame">
<input name="signed" type="checkbox">
<input value="Save" type="submit">
</form>
Maybe it would work if the variables are encoded in json format.
document.getElementById('outside_cart_text').innerHTML =
"Qty type
<?php echo json_encode($this->session->userdata('qty_type')); ?>
amount
<?php echo json_encode($this->session->userdata('qty_product'));?>";
});
$(document).ready(function(){
$('.add-to-cart').on('click',function(){
var qty_type = '<?php echo $this->session->userdata('qty_type'); ?>';
var amount = '<?php echo $this->session->userdata('qty_product'); ?>';
$("#outside_cart_text").html("Qty type "+qty_type+" amount "+amount);
});
});
I have a php page which gets $page and $user using post method, I also have a button that i want, to open a URL in the same window using $page and $user variables when clicked, to use them with $_GET[] function.
i want my URL be like:
http://www.test.com/test.php?page=$page&user=$user
my code is like this:
<?php
$page=$POST_['page'];
$user=$POST_['user'];
<?
<html>
<head>
function openurl() {
var user=<?php echo "$user";?>;
var page=<?php echo "$page";?>;
open('www.test.com/test.php?page='+page'&user='+user,'_self');
}
</head>
<body>
<button onclick="openurl()" type="button">open url</button>
</body>
</html>
There is no need for scripting at all
If you want GET:
<?php
$page=$GET_['page']; // should be sanitized and you can use REQUEST for either
$user=$GET_['user'];
$parm = "page=".$page."&user=".$user;
?>
Open URL
If you need to post:
<form action="test.php" method="post">
<input type="hidden" name="page" value="<?php echo $page; ?>"/>
<input type="hidden" name="user" value="<?php echo $user; ?>"/>
<input type="submit" value="Open URL" />
</form>
Change these lines:
<?php
$page=$POST_['page'];
$user=$POST_['user'];
<?
....
var user=<?php echo "$user";?>;
var page=<?php echo "$page";?>;
open('www.test.com/test.php?page='+page'&user='+user,'_self');
to this:
<?php
$page=$_POST['page']; //incorrect $_POST declaration
$user=$_POST['user']; //incorrect $_POST declaration
?> //php tag incorrectly closed
....
var user=<?php echo $user;?>; //echoing a variable not string (no need for quotes)
var page=<?php echo $page;?>; // echoing a variable not string (no need for quotes)
open('www.test.com/test.php?page='+page+'&user='+user,'_self'); // link was broken, forget to put '+' after page variable in link.
You can create a form and via Javascript just run YOURFORMNAME.submit();
Use href in javaScript to move to another location:
location.href="www.test.com/test.php?page='+page'&user='+user"
I have a page with 'favourite' button that when clicked runs an Ajax post and updates my db table 'favourite' accordingly user and book details.
The current process is as follows,
click button once > add book to favourite table > refresh page > display success div
click button again > delete book from favourite table > refresh page > display success div
What I would like to do now is on page load, check if the user has already added the book as a favourite, if so, set the class of this button to btn-success (green).
How do I achieve this? Do I need to give the button an attribute on page load and check this on page load?
I am quite new to php and js so any advice is appreciated. I have included my code for reference.
ajax
$(document).ready(function(){
$( "#fav" ).click(function(){
book_id = $(fav).val(); // set the value of the button as the book_id
$.ajax({
type: 'POST',
url: '<?php echo URL; ?>books/checkFav',
data: {book_id:book_id},
success: function () {
window.location.reload(true);
}//end success
});//end ajax
});
});
checkFav php
$bookid=$_REQUEST['book_id']; //get this from ajax
$userid=$_SESSION['user_id']; //get this from session
$sql = "SELECT * FROM favourite WHERE book_id = :book_id AND user_id = :user_id";
... //execute
if(empty($rows_found)) {
$sql = "INSERT INTO favourite (book_id, user_id) VALUES (:book_id, :user_id)";
... //execute
} else {
$sql = "DELETE FROM favourite WHERE book_id = :book_id AND user_id = :user_id";
... //execute
}
html
echo '<td>
<button id="fav" value="'.$book->id.'" type="button" class="btn btn-default"></button></td>';
echo '</tr>';
This is incorrect:
<button id="fav" value="'.$book->id.'" type="button" class="btn btn-default"></button>
You must specify that you want PHP code and you want to echo $book->id, like this:
<button id="fav" value="<?php echo $book->id; ?>" type="button" class="btn btn-default"></button>
Also, let's suppose you have a PHP function isFavorite, then
<button id="fav" value="<?php echo $book->id; ?>" type="button" class="btn btn-default<?php echo ((isFavorite()) ? (" btn-success") : ("")); ?>"></button>
There are two things you can do:
make a php function that checks if it is already a favorite or not and returns true or false and based on that add a class to the button like this:
$("#buttonId").addClass("btn-success");
if you already have this data when the page loads you can add a php code inline in the html like this:
if($favorite){
$class = "btn-success";
}
and then in the html
<button id="fav" value="<?php echo $book->id; ?>" type="button" class="btn <?php echo ($book->isFavorite()) ? 'favorite' : '';?>"></button>
I have a Ajax Submit button which shows up with a message Successfully Added. View Cart when clicked on Add to cart button. Right now Successfully Added. and View Cart message is show as a single button. Is there any way to separate out Successfully Added and View Cart button?
Add to cart button code:
<fieldset class="add-to-cart-box">
<legend><?php echo $this->__('Add to Cart') ?></legend>
<?php if(!$_product->isGrouped()): ?>
<input name="qty" type="hidden" class="input-text qty" id="qty" maxlength="12" value="1" /></span>
<?php endif; ?>
<button class="form-button" onclick="ajaxSubmit('<?php echo $this->getAddToCartUrl($_product) ?>', this)"><span><?php echo $this->__('Add to Cart') ?></span></button>
</fieldset>
Successfully Added. View Cart message and button code:
<script type="text/javascript">
function ajaxSubmit(url, button){
var pars = '';
var target = '';
var myAjax = new Ajax.Updater(target,url, {method: 'get', parameters: pars});
button.innerHTML = '<span>Successfully Added. View Cart</span>';
button.className = 'form-button-alt';
button.style.marginTop = '6px';
button.attributes["onclick"].value = 'setLocation(\'/checkout/cart/\')';
}
</script>
you are replacing the inner button html
button.innerHTML = '<span>Successfully Added. View Cart</span>';
instead replace the button with two button instances
I have a form with 2 buttons: Approve and Reject.
<input type="button" name="Approve" value="Approve" onClick="location.href='approve.php?user=<?php echo $row['icnum'];?>&states=1'">
<input type="button" name="Reject" value="Reject" onClick="location.href='approve.php?user=<?php echo $row ['icnum'];?>&states=2'">
I want to disable the "Reject" button once the "Approve" button is clicked. So, the user cannot reject the form again after it has been approved.
I have tried several attempts, like:
<input type="button" value="Send" onclick="javascript=this.disabled = true; form.submit();">
But this code does not work for me. Even if it's actually working, the button is just disabling itself, not the other button.
I'm using Chrome. Any idea on how to solve this?
EDIT: This is my process form in php.
<?php session_start();
include('../include/dbconnect.php');
$user = $_GET['user'];
$states = $_GET['states'];
if($user){
$approve = "UPDATE student SET status='$states' WHERE icnum='$user'";
$result = mysql_query($approve) or die(mysql_error());
if ($result) {
?>
<script type="text/javascript">
window.location = "index.php"
</script>
<?php }
}
?>
What can I edit into these codes if the action is ran in the server-side?
Remove the javascript= from OnClick. You only need javascript: (colon not =) for anchors' hrefs
<input type="button" value="Send" onclick="this.disabled=true; formName.submit();">
In jQuery:
$('input[name=Approve]').click(function () {
$('input[name=Reject]').prop({disabled: true});
});
Try below
<asp:Button ID="cmdSubmit" runat="server" Text="Submit" onclick="btnSumbit_Click" onclick="btnSumbit_Click" OnClientClick="this.style.display = 'none';"/>