I made a Javascript page to generate a JSON object for read it then from Android device.
I read it with the following code
StringBuilder stringBuilder = new StringBuilder();
HttpClient client = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
try {
HttpResponse response = client.execute(httpGet);
StatusLine statusLine = response.getStatusLine();
int statusCode = statusLine.getStatusCode();
if (statusCode == 200){
HttpEntity entity = response.getEntity();
InputStream content = entity.getContent();
BufferedReader reader = new BufferedReader(new InputStreamReader(content));
String line;
while ((line = reader.readLine()) != null){
stringBuilder.append(line);
}
} else {
Log.e("JSON", "Failed to donwload file");
}
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
The problem is that this code returns the source code of the webpage, and the source code is the script in Javascript, not the JSON string generated after execute it.
I need the JSON string and I need use Javascript to generate the JSON string because I access to an external service.
I haven't find any solution for this. I don't care if the possible solution involves the server or the Android terminal.
Thanks.
String myresponse=Html.escapeHtml(YourStringHere);
Try this.
private class MyJavaScriptInterface {
private MyJavaScriptInterface () {
}
public void setHtml(String contentHtml) {
//here you get the content html
}
}
private WebViewClient webViewClient = new WebViewClient() {
#Override
public void onPageFinished(WebView view, String url) {
view.loadUrl("javascript:window.ResponseChecker.setHtml"
+ "(document.body.innerHTML);");
}
}
Related
I using WebViewClient's shouldInterceptRequest function to filter photos in my android webView.
The problem
I'm trying to block google's base64 URL photos (like:data:image/jpeg;base64,+) using this regex data:image/(jpg|png|jpeg);base64, but without success.
I done my research and found that:
these base64 background images are injected with JS.
but I don't know to continue.
my code:
#Override
public WebResourceResponse shouldInterceptRequest(WebView view, WebResourceRequest request) {
String url = request.getUrl().toString();
if (imgCheck(url,res))
{
return new WebResourceResponse(
BrowserUnit.MIME_TYPE_TEXT_PLAIN,
BrowserUnit.URL_ENCODING,
new ByteArrayInputStream("".getBytes())
);
}
return super.shouldInterceptRequest(view, request);
}
private static boolean isImage(String url, Resources res) {
BufferedReader imageUrlRegex = openRawFile(res, R.raw.image_regex);
try {
String line = imageUrlRegex.readLine();
while (line != null) {
Pattern pattern = Pattern.compile(line);
if (pattern.matcher(url).find())
return true;
line = imageUrlRegex.readLine();
}
} catch (IOException e) {
e.printStackTrace();
return true;
}
return false;
}
data:image/(jpg|png|jpeg|svg|ico|webp|tif|tiff|bmp|eps|apng|avif|jfif|pjpeg|pjp|cur);base64,
**note : I tried block like this return url.contains("data:image"); still nothing
this question is how to apply java script by link to webview https://dl.dropboxusercontent.com/s/lmibwymtkebspij/background.js after the page is fully loaded the background should turn green here is a sample code for loading the page
webView = findViewById(R.id.Web);
webView.getSettings().setJavaScriptEnabled(true);
webView.setWebChromeClient(new MyWebChromeClient());
thank you in advance
maybe someone will come in handy load the text of the script into the script variable using get request to link the address of the script like this:
#SuppressLint("StaticFieldLeak")
class ProgressTask extends AsyncTask<String, Void, String> {
#Override
public String doInBackground(String... path) {
try {
content = getContent(path[0]);
} catch (IOException ex) {
content = ex.getMessage();
}
return content;
}
#Override
public void onPostExecute(String content) {
scriptbg = content;
Log.d("debug", scriptbg);
}
public String getContent(String path) throws IOException {
BufferedReader reader = null;
try {
URL url = new URL(path);
HttpsURLConnection c = (HttpsURLConnection) url.openConnection();
c.setRequestMethod("GET");
c.setReadTimeout(10000);
c.connect();
reader = new BufferedReader(new InputStreamReader(c.getInputStream()));
StringBuilder buf = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
buf.append(line + "\n");
}
return (buf.toString());
} finally {
if (reader != null) {
reader.close();
}
}
}
then we apply the script to our webView when the page is fully loaded like this:
public void onPageFinished(WebView view, String url) {
webView.loadUrl("javascript:" + Script);
Log.d("debug", "finish");
}
I am building an android app. I have build a request using OKHTTP and I get the response as a string composed of html css and js content. This response is actualy a form that the user must use to allow the app to communicate with a given website.
Now I want the user to be able to see that response as an html page and clicks on a button to allow the communictaion. Only problem I don't know how to display that response as an html in webview or in the web browser.
From the MainActivity:
Authenticate myAouth = new Authenticate("myCostumerKey","mySecretKey");
try {
myResponse=myAouth.run("myUrlHere");
//System.out.println( myResponse);
} catch (Exception e) {
e.printStackTrace();
}
the Autheticate class
public class Authenticate {
private final OkHttpClient client;
String[] myResponse =new String[2];
public Authenticate( final String consumerKey, final String consumerSecret) {
client = new OkHttpClient.Builder()
.authenticator(new Authenticator() {
#Override public Request authenticate(Route route, Response response) throws IOException {
if (response.request().header("Authorization") != null) {
return null; // Give up, we've already attempted to authenticate.
}
System.out.println("Authenticating for response: " + response);
System.out.println("Challenges: " + response.challenges());
String credential = Credentials.basic(consumerKey, consumerSecret);
Request myRequest =response.request().newBuilder()
.header("Authorization", credential)
.build();
HttpUrl myURL = myRequest.url();
myResponse[0]= String.valueOf(myURL);
return myRequest;
}
})
.build();
}
#RequiresApi(api = Build.VERSION_CODES.KITKAT)
public String[] run(String url) throws Exception {
Request request = new Request.Builder()
.url(url)
.build();
try (Response response = client.newCall(request).execute()) {
if (!response.isSuccessful()) throw new IOException("Unexpected code " + response);
myResponse[1]=response.body().string();
System.out.println(" URL is "+myResponse[0]+" my response body is "+myResponse[1]);
}
return myResponse;
}}
Any help would be apriciated.
Kind Regards
You can use the following code to convert the String to HTML and then display it in a WebView
try {
String html = new String(response, "UTF-8");
String mime = "text/html";
String encoding = "utf-8";
myWebView.getSettings().setJavaScriptEnabled(true);
myWebView.loadDataWithBaseURL(null, html, mime, encoding, null);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
}
I'm new to Java and Android development and try to create a simple app which should contact a web server A and send,add some data to text using a http get.
I have simple HTML code with some javascript (server A)
<html>
<head>
<title>This is my Webpage</title>`enter code here`
<h1>My Example</h1>
<script>
function myFunction(){
document.getElementById("myid").value=$ab;
}
</script
</head>
<body onload="myFunction()">
<input id="myid" type="text" />
</body>
</html>
and i have Android code to send http request to a local (server A)
public class MainActivity extends Activity {
private Button button;
#Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
button=(Button) findViewById(R.id.click);
button.setOnClickListener(new View.OnClickListener() {
#Override
public void onClick(View v) {
String url = "http://www.localhost/tuan/example.html";
MyCommandTask task = new MyCommandTask();
task.execute(url);
}
});
}
public class MyCommandTask extends AsyncTask<String,Void,Document>
{
#Override
protected Document doInBackground(String... params) {
String url=params[0];
try {
HttpGet httpGet = new HttpGet(url);
}
catch (Exception ex)
{
ex.printStackTrace();
}
return null;
}
#Override
protected void onPostExecute(Document document) {
super.onPostExecute(document);
}
}
}``
Now i want send text data and show result in text on (server A).
Please anyone help me.
Check this out dude. http://developer.android.com/training/basics/network-ops/connecting.html#download . Since you already got url string in doInBackground() method , use below code
InputStream is = null;
// Only display the first 500 characters of the retrieved
// web page content.
int len = 500;
try {
URL url = new URL(myurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(10000 /* milliseconds */);
conn.setConnectTimeout(15000 /* milliseconds */);
conn.setRequestMethod("GET");
conn.setDoInput(true);
// Starts the query
conn.connect();
int response = conn.getResponseCode();
Log.d(DEBUG_TAG, "The response is: " + response);
is = conn.getInputStream();
// Convert the InputStream into a string
String contentAsString = readIt(is, len);
return contentAsString;
// Makes sure that the InputStream is closed after the app is
// finished using it.
} finally {
if (is != null) {
is.close();
}
}
Don't forget to change return type of doInBackground() to String as well. If you wanna go further , try grab volley which is one of the awesome network library https://developer.android.com/training/volley/index.html
Here is how you can post data to server. Put these line inside doInBackground()
private static final String POST_PARAMS = "userName=Pankaj";
URL obj = new URL(POST_URL);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("POST");
con.setRequestProperty("User-Agent", USER_AGENT);
// For POST only - START
con.setDoOutput(true);
OutputStream os = con.getOutputStream();
os.write(POST_PARAMS.getBytes());
os.flush();
os.close();
// For POST only - END
int responseCode = con.getResponseCode();
System.out.println("POST Response Code :: " + responseCode);
if (responseCode == HttpURLConnection.HTTP_OK) { //success
BufferedReader in = new BufferedReader(new InputStreamReader(
con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
// print result
System.out.println(response.toString());
} else {
System.out.println("POST request not worked");
}
Here is the source
In my app, I have created web server which is hosting a web app. All the files of web app are placed in assets folder.
Now, i start the web server by running my application and then from crome brower, I try to run my web app by calling index.html file. The html, css part of the page is getting loaded properly but the images are not getting loaded in the page:
Here is my HttpRequestHandlerCode:
public class HomePageHandler implements HttpRequestHandler {
private Context context = null;
private static final Map<String, String> mimeTypes = new HashMap<String, String>() {
{
put("css", "text/css");
put("htm", "text/html");
put("html", "text/html");
put("xhtml", "text/xhtml");
put("xml", "text/xml");
put("java", "text/x-java-source, text/java");
put("md", "text/plain");
put("txt", "text/plain");
put("asc", "text/plain");
put("gif", "image/gif");
put("jpg", "image/jpeg");
put("jpeg", "image/jpeg");
put("png", "image/png");
put("svg", "image/svg+xml");
put("mp3", "audio/mpeg");
put("m3u", "audio/mpeg-url");
put("mp4", "video/mp4");
put("ogv", "video/ogg");
put("flv", "video/x-flv");
put("mov", "video/quicktime");
put("swf", "application/x-shockwave-flash");
put("js", "application/javascript");
put("pdf", "application/pdf");
put("doc", "application/msword");
put("ogg", "application/x-ogg");
put("zip", "application/octet-stream");
put("exe", "application/octet-stream");
put("class", "application/octet-stream");
put("m3u8", "application/vnd.apple.mpegurl");
put("ts", " video/mp2t");
}
};
public HomePageHandler(Context context){
this.context = context;
}
#Override
public void handle(HttpRequest request, HttpResponse response, HttpContext httpContext) throws HttpException, IOException {
//String contentType = "text/html";
//Log.i("Sushill", "..request : " + request.getRequestLine().getUri().toString());
final String requestUri = request.getRequestLine().getUri().toString();
final String contentType = contentType(requestUri);
String resp = Utility.openHTMLStringFromAssets(context, "html" + requestUri);
writer.write(resp);
writer.flush();
// }
}
});
((EntityTemplate) entity).setContentType(contentType);
response.setEntity(entity);
}
}
/**
* Get content type
*
* #param fileName
* The file
* #return Content type
*/
private String contentType(String fileName) {
String ext = "";
int idx = fileName.lastIndexOf(".");
if (idx >= 0) {
ext = fileName.substring(idx + 1);
}
if (mimeTypes.containsKey(ext)) {
//Log.i("Sushill", "...ext : " + ext);
return mimeTypes.get(ext);
}
else
return "application/octet-stream";
}
To handle image, I tried this but it did not work :
if(contentType.contains("image")) {
InputStream is = Utility.openImageFromAssets(context, "html" + requestUri);
char[] buffer = new char[1024];
try {
Reader reader = new BufferedReader(new InputStreamReader(is, "UTF-8"));
int n;
while ((n = reader.read(buffer)) != -1) {
writer.write(buffer, 0, n);
}
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
Can someone please help me in figuring out how to load the images also in my browser.
Thanks for any help
Do away with BufferedReader(new InputStreamReader' so you do away with UTF-8 too. Use only InputStream 'is'. Do away with writer. You are not showing what 'writer' is but do away with it. Use the OutputStream of the http connection. Keep the buffer and the loop where you read in the buffer and write from the buffer.