I am trying to show one div at a time and scroll trough them over and over. I have modified a Fiddle I found and I got it working on fiddle, but for some reason I cant implement a simple test page with the fiddle. It simply does not scroll trough the divs.
Here is the fiddle: http://jsfiddle.net/Twistar/d6nZP/86/
And here is my implemented code:
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<link rel="stylesheet" type="text/css" href="styles/styles.css">
<script type="text/javascript" src="includes/headers/jquery.min.js"></script>
<script type="text/javascript">
function go() {
var visibleBox = $('#container .boxes:visible');
visibleBox.hide();
var nextToShow = $(visibleBox).next('.boxes:hidden');
if (nextToShow.length > 0) {
nextToShow.show();
} else {
$('#container .boxes:hidden:first').show();
}
return false;
}
setInterval(go, 1000);
</script>
</head>
<body>
<div id="container">
<div class="boxes" style="display:">first box</div>
<div class="boxes" style="display:none;">second box</div>
<div class="boxes" style="display:none;">third box</div>
<div class="boxes" style="display:none;">forth box</div>
</div>
</body>
Can anyone please tell me what i am doing wrong?
I am guessing that you have a working fiddle but on your local test page its not working
your fiddle works because you got selected the default handlers from left handside dropdowns and its not working on your test page because your jquery handler is missing.
the reason is you are missing the document ready handler here:
$(function(){
setInterval(go, 1000);
});
try replacing with this one and see if helps.
I would probably simplyfy and would go with something like this: http://jsbin.com/osepim/1/
$(function() {
// hide all and show first
$(".boxes").hide().first().show();
setInterval(function(){
moveNext();
}, 1000);
});
function moveNext() {
var box = $(".boxes:visible"),
nextBox = box.next();
if(nextBox.length === 0)
nextBox = $(".boxes:first");
//hide all
$(".boxes").hide();
// show next
nextBox.fadeIn();
}
you need to wrap your javascripts code with the ready event $(document).ready() or use the short version $() and that will only excecute your codes when the page is finished loading so your codes should looks something like that
$(function(){
function go() {
var visibleBox = $('#container .boxes:visible');
visibleBox.hide();
var nextToShow = $(visibleBox).next('.boxes:hidden');
if (nextToShow.length > 0) {
nextToShow.show();
} else {
$('#container .boxes:hidden:first').show();
}
return false;
}
setInterval(go, 1000);
});
<!DOCTYPE html>
<head>
<meta charset="UTF-8">
<link rel="stylesheet" type="text/css" href="styles/styles.css" />
<style type="text/css">.boxes{display:none}</style>
</head>
<body>
<div id="container">
<div class="boxes">first box</div>
<div class="boxes">second box</div>
<div class="boxes">third box</div>
<div class="boxes">forth box</div>
</div>
<script type="text/javascript" charset="utf-8" src="//ajax.googleapis.com/ajax/libs/jquery/1.6.2/jquery.min.js"></script>
<script type="text/javascript">
function go() {
var visibleBox = $('#container .boxes:visible'); // GET THE DIV
visibleBox.hide();
var nextToShow = $(visibleBox).next('.boxes:hidden');
if (nextToShow.length > 0) { // SHOW NEXT ITEM
nextToShow.show();
} else {
$('#container .boxes:hidden:first').show();
}
return false;
}
setInterval(go, 1000); // MS SECOND OF LOOP
</script>
</body>
</html>
Related
How to execute a javaScript url when a visitor clicks inside div
Like this example :
<html>
<head>
<meta charset="UTF-8">
<style>
.youtube .play,.youtube img{cursor:pointer;position:absolute}
.youtube{position:relative;padding-bottom:56.23%;height:0;overflow:hidden;max-width:100%;background:#000;margin:5px}
.youtube embed,.youtube iframe,.youtube object{position:absolute;top:0;left:0;width:100%;height:100%;z-index:100;background:0 0}
.youtube img{bottom:0;display:block;left:0;margin:auto;max-width:100%;width:100%;right:0;top:0;border:none;height:auto;-webkit-transition:.4s all;-moz-transition:.4s all;transition:.4s all}
.youtube img:hover{-webkit-filter:brightness(75%)}
.youtube .play{height:72px;width:72px;left:50%;top:50%;margin-left:-36px;margin-top:-36px;background:url(//i.imgur.com/TxzC70f.png) no-repeat}
</style>
</head>
<body>
<div class="youtube" data-id="YQHsXMglC9A"></div>
</body>
<script>
/* Light YouTube Embeds by #labnol */
/* Web: http://labnol.org/?p=27941 */
document.addEventListener("DOMContentLoaded",
function() {
var div, n,
v = document.getElementsByClassName("youtube");
for (n = 0; n < v.length; n++) {
div = document.createElement("div");
div.setAttribute("data-id", v[n].dataset.id);
div.innerHTML = labnolThumb(v[n].dataset.id);
div.onclick = labnolIframe;
v[n].appendChild(div);
}
});
function labnolThumb(id) {
var thumb = '<img src="https://i.ytimg.com/vi/ID/hqdefault.jpg">',
play = '<div class="play"></div>';
return thumb.replace("ID", id) + play;
}
function labnolIframe() {
var iframe = document.createElement("script");
iframe.setAttribute("src", "https://www.youtube.com/embed/" + this.dataset.id + "?autoplay=1");
iframe.setAttribute("frameborder", "0");
iframe.setAttribute("allowfullscreen", "1");
this.parentNode.replaceChild(iframe, this);
}
</script>
</html>
Like this picture
image
.
Html code + javascript :
<!doctype html>
<html>
<head>
<meta charset="utf-8">
</head>
<body>
<div id="a" style="background-color:#999; height:90px; width:250px;" >Click here</div>
</body>
</html>
Javascript :
<script type="text/javascript">
document.write("Hello World!");
</script>
Or :
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
How do I run javaScript url when a visitor clicks inside div ?
Something liked this would do it...
function clickMe() {
alert("You clicked me!")
}
<!doctype html>
<html>
<head>
<meta charset="utf-8">
</head>
<body>
<div id="a" style="background-color:#999; height:90px; width:250px;" onclick="clickMe()" >Click here</a></div>
</body>
</html>
First of all, instead of trying to run a script, you should try to run a function.
For example
function test(){
document.write("Hello World!")
}
function test2(){
document.getElementById("output").innerHTML = "Hello World!"
}
<div onclick="test()">
<p> Click me </p>
</div>
<div onclick="test2()">
<p> Click me (won't remove screen) </p>
</div>
<div id="output">
</div>
Clicking on the first div will call the test() function. This function will however overwrite everything on the screen, that's not what you want.
The second method doesn't do that, instead it sets the content of the third div to "Hello World!"
I believe you want to run a JavaScript function when your div gets clicked. You just need to add an onclick() event to your <div> tag and declare that function. So your div would be something like this:
<div id="a" style="background-color:#999; height:90px; width:250px;" onclick="writeFunction();">Click here</div>
And the function, with the same name as you declared on your onclick:
<script type="text/javascript">
function writeFunction(){
document.write("Hello World!");
}
</script>
As you have used document.write and i have kept that, it does not show the result that you have illustrated in your picture and your div is vanishing. In order to do as you have imagined, you have to add a <p> element which is initally blank:
<p id='text'></p>
and then ask your function to set its text, like this:
document.getElementById('text').innerHTML = "Hello World!";
You can learn more here: https://www.w3schools.com/jsref/event_onclick.asp
Just recently made this sticky navbar with a little bit of jquery and realised that it doesn't work . When i tried copying my code to jsfiddle everything worked fine
<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css\style.css">
<link rel="stylesheet" type="text/css" href="http://fonts.googleapis.com/css?family=Open Sans">
<script type="text/javascript" src="https://code.jquery.com/jquery-1.12.4.min.js"></script>
<script type="text/javascript" src="js\scripts.js"></script>
</head>
<body>
<header onmouseover="this.style.background='white'" onmouseout="this.style.background='#e6e6e6'">
<img src="Photos\logo.png" width="210px" height="150px">
</header>
<ul class="navbar">
<li>Model</li>
</ul>
<div class="main">lots of words......</div
</body>
</html>
And the scripts.js file :
var n=$(".navbar"),
ns="navbar-scrolled",
head=$('header').height();
$(window).scroll(function() {
if( $(this).scrollTop() > head) {
n.addClass(ns);
}
else {
n.removeClass(ns);
}
});
The css file is the same as in my JSFiddle
By default JSFiddle runs your script on window load, which means it runs after the DOM has been loaded. You need to do this yourself normally. Just a slight change will fix it...
$(function() {
var n=$(".navbar"),
ns="navbar-scrolled",
head=$('header').height();
$(window).scroll(function() {
if( $(this).scrollTop() > head) {
n.addClass(ns);
}
else {
n.removeClass(ns);
}
});
});
You just need to wrap your code like this...
$(function() {
// your code goes here
});
There are other ways to do the same, but that will fix your problem.
I am trying to add 2 simple click functions to 2 images and make them "active" when clicked, however for some reason the code is not working.
This is the link to the external file:
<head>
<link href="bootstrap.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="jquery-1.11.0.min.js"></script>
<script type="text/javascript" src="jquery.leanModal.min.js"></script>
<script type="text/javascript" src="likeandshare.js"></script>
<link type="text/css" rel="stylesheet" href="blogformat.css" />
<script type="text/javascript" src="likeandshare.js"></script>
</head>
This is the html:
<div class="blog-header">
<h1>This heading should be center aligned and colored</h1>
<p>Italised date and Author entered here</p>
<div id="facebook-like-button">
<img src="images/facebook_like_button_big.jpeg">
</div>
<div id="facebook-share-button">
<img src="images/facebook-share.png">
</div>
</div>
This is the js code:
$(document).ready(main);
var like = function() {
$("#facebook-like-button").click(function() {
$(this).toggleClass("active");
});
};
I'm not sure why the div is not becoming active when clicked but I would also like to attach the function ONLY to the image, rather than the entire div.
Help :D
thanks.
As far as I'm aware, your code should be working. You must be incorrectly calling the ready function.
working example http://jsfiddle.net/2j0s1j8v/3/
All of these events fire back:
share = document.getElementById("facebook-share-button");
share.onclick = function(){
console.log("ONCLICK");
}
share.addEventListener("click", function(){ console.log("CLICK LISTENER"); } );
$("#facebook-share-button").click(function() {
console.log("JQUERY CLICK");
});
Check the console and look at the messages. All of them fire properly. f12 on chrome.
You can simply do this :
$(document).ready(function(){
$("#facebook-like-button").find('img').click(function() {
$(this).toggleClass("active");
});
});
first include jquery
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script type="text/javascript" src="likeandshare.js"></script>
</head>
second you create a like function and use main function .. you have a main function also or bad typo or what anyway in your case it should be
$(document).ready(like);
if you want to select an image inside the div just use > a >img
var like = function() {
$("#facebook-like-button > a > img").click(function() {
$(this).toggleClass("active");
});
};
https://jsfiddle.net/2j0s1j8v/4/
Like button
$("#facebook-like-button img").click(function () {
$(this).toggleClass("active");
});
Share button
$("#facebook-share-button img").click(function () {
$(this).toggleClass("active");
});
Here is a working example if I understand correctly what you wanted.
adds active class to the image on click.
EDIT: added share as well
Hi by any chance anyone will know how to do the fade in fade out change page effect in JavaScript?
Like this..
http://soulwire.co.uk/hello
I have tried this..
But when fadeout is not linking together..I mean not smooth like the above website.
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.2/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
$('body').css('display', 'none');
$('body').fadeIn(1000);
$('.link').click(function() {
event.preventDefault();
newLocation = this.href;
$('body').fadeOut(2000, newpage);
});
function newpage() {
window.location = newLocation;
}
});
</script>
Sorry am just think of....does background slideshow will work??? But on top can I add php/html code?
Another example...http://www.louisebradley.co.uk/portfolio/
Hey try the below code
See its WORKING DEMO
<!DOCTYPE html>
<html>
<head>
<title></title>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<script src="jquery.js"></script>
<script type="text/javascript">
function Close()
{
$('#div1').animate({ height: 50 });
}
function Open()
{
$('#div1').animate({ height: 100 });
}
</script>
</head>
<body>
<div id="div1" style="width:100%; height: 50px; background-color: #C0C0C0;" onmouseover="Open()" onmouseout="Close()"></div>
</body>
</html>
Also take a look at these stuffs
Fade in div on page load
JavaScript Fade Tutorial – Fading Elements In/Out
How to: javascript fade in fade out text
.fadeIn() Tutorial
the goal here is onclick of 1.gif, everything with .panel1 class disappears(style.display.none), and everything with a .panel2 class becomes visable (style.display.inline)
I'm new at this..so I think its just a syntax issue with ' ' or maybe " "
<!DOCTYPE html>
<html>
<head>
<title>main</title>
<meta charset="utf-8">
<style type="text/css">
.panel1 {display:inline;}
.panel2 {display:none;}
</style>
<script type="text/javascript">
function panelTransition(panelOut,panelIn)
{
document.getElementByClass(panelIn).style.display="inline";
document.getElementByClass(panelOut).style.display="none";
}
</script>
</head>
<body>
<img class="panel1" src=1.gif onclick="panelTransition(panel1,panel2)" />
<img class="panel2" src=2.gif />
</body>
</html>
There is no getElementByClass. It's getElementsByClassName, and it returns an array of items, so you'll need to modify your code to loop through them.
function panelTransition(panelOut, panelIn) {
var inPanels = document.getElementsByClassName(panelIn);
for (var i = 0; i < inPanels.length; i++) {
inPanels[i].style.display = 'inline';
}
var outPanels = document.getElementsByClassName(panelOut);
for (var i = 0; i < outPanels.length; i++) {
outPanels[i].style.display = 'none';
}
}
If you were using a JavaScript library, like jQuery, this would be much easier to do. Also, as has been mentioned, you need quotes around your arguments to panelTransition.
<img class="panel1" src=1.gif onclick="panelTransition('panel1', 'panel2')" />
<img class="panel2" src=2.gif />
<img class="panel1" src=1.gif onclick="panelTransition('panel1','panel2')" />
I think you need quotes there
<html>
<head>
<title>main</title>
<meta charset="utf-8">
<style type="text/css">
.panel1 {display:inline;}
.panel2 {display:none;}
</style>
<script type="text/javascript">
function panelTransition(panelOut,panelIn)
{
// panelIn gets turned on
setDisplay(panelIn,"inline");
// panelOut gets turned off
setDisplay(panelOut,"none");
}
function setDisplay(className,displayState)
{
// retrieve a list of all the matching elements
var list = document.getElementsByClassName(className);
// step through the list
for(i=0; i<list.length; i++) {
// for each element, set the display property
list[i].style.display = displayState;
}
}
</script>
</head>
<body>
<img class="panel1" src="1.gif" onclick="panelTransition('panel1','panel2')" />
<img class="panel2" src="2.gif" onclick="panelTransition('panel2','panel1')" />
</body>
</html>
Or you can accomplish the same in jQuery
// fires when the page is up and running
$(document).ready(function(){
// find all the panel1 elements,
// attach an on click handler
$(".panel1").bind("click", function(){
// find all the panel1 elements
// set their css display property to inline
$(".panel1").css("display","inline");
// find all the panel2 elements
// set their css display property to none
$(".panel2").css("display","none");
});
$(".panel2").bind("click", function(){
$(".panel2").css("display","inline");
$(".panel1").css("display","none");
});
});
You can learn all about jQuery here : http://www.jquery.com/
You'll only be able to get your code to run once, as soon as you click a panel1 image all of the panel2 images will disappear, you won't be able to click them back on ever again.