Develop Reference

How to render an element on top of every other element on page without depending on the structure/styles used in the page?

I wish to display a button at a fixed position(sticky) on the page and it should always be on top of other elements on the page, assuming I have no knowledge of the structure and styles used on that page. The solution can only use Javascript(no jQuery), CSS3 and HTML5.
The solution has to be dynamic/adaptive i.e not directly dependent on the z-index values used on the page.

Demo: http://jsfiddle.net/lotusgodkk/sf1fukm5/
CSS:
.a {
position:fixed;
right:10px; //optional
top:10px; //optional
z-index:1;
background:grey; //optional
color:#000; //optional
padding:20px; //optional
}
HTML:
<div>--Content--</div>
<div class="a">Fixed</div> //Fixed div
<div>--Content--</div>....
For dynamic z-index using jQuery:
var highest = -999;
$("*").each(function () {
var current = parseInt($(this).css("z-index"), 10);
if (current && highest < current) highest = current;
});
$('your-element-selector').css('z-index',highest);
Using javascript:
How can you figure out the highest z-index in your document?
Refer: How to find the highest z-index within a document no matter what tags they are?

JSFIDDLE
CSS:
.fixed-button {
width: 125px;
background: #FFFFFF;
border-style: solid;
border-width: 1px;
border-radius: 3px;
padding: 5px;
margin-left: 0px;
position: fixed;
z-index: 999;
top: 70px;
}
HTML:
<button class="fixed-button"> fixed-button </button>
I hope you got the answer. You can change the position of button where ever you need

Style all but one element to dim background

Looking to achieve a dimmed-background effect by dimming (or changing the opacity of) all elements on the page but one; I've been trying out :not() as well as some jQuery selectors to try and exclude all but the element, but to no avail. Does anyone know of the best way to do this with SASS/Compass or, failing that, jQuery?
So far, I've tried things like:
.opacityFade:not(.classToExclude) {
STYLES HERE
}
or
$('controlElement').click(function(){
$(body).not('desiredTargetToExclude').toggleClass('classThatFadesStuffOut');
});
Ideally, I'd like to avoid having to write more JS and better separate responsibilities,but there might not be a way to do that. Little new to Front-End development, so I'm not aware of a best way to go about doing this; thanks!!

You can achieve this by placing a blanket over all elements, and then pulling the element you want to display out of the DOM order with the z-index property
.item {
background: #f00;
width: 100px;
height: 100px;
display: inline-block;
margin: 10px;
}
.item.selected {
position: relative;
z-index: 200
}
.blanket {
position: absolute;
left: 0;
top: 0;
width: 100%;
height: 100%;
background: black;
opacity: 0.5;
z-index: 100;
}
Note that the element needs to have a non static position.
See http://jsfiddle.net/cyberdash/fCMaT/

you could add another class to the non-dimmed/active div. I'll put together a fiddle.
http://jsfiddle.net/nqT7V/
In Jquery:
$(".item").click(function(){
var $this = $(this);
$this.parent().addClass("dimmed");
$this.parent().find(".item").removeClass("active");
$this.addClass("active");
});
$(".holder").click(function(e){
if (e.target != this) return;
var $this = $(this);
if ($this.hasClass("dimmed")){
$this
.removeClass("dimmed")
.find(".item").removeClass("active");
}
});

Imagemap with overlying div: Mouseover disappears on div

Could anyone give me a hint how to solve this?
Fiddle: http://jsfiddle.net/9Br6h/
Have a look at the part left under... with the flag. On the area the mouseover is visible.. but it disappears on the flag - that is the thing I want to remove. It should stay visible.
But please keep in mind that this is a very simple example. In real I've tons of areas and flags. ;o)
jQuery(document).ready(function($) {
// add div for showing dates
$('body').append('<div id="mo_termin"></div>');
// show div on mouseover
$('area').mouseover(function(event) {
var left = event.pageX + 30;
var top = event.pageY + 5;
display = '<div class="views-field-field-body">Keine Termine</div>';
$('#mo_termin').css({top: top,left: left}).html(display).show();
});
$('area').mouseout(function() {
$('#mo_termin').html('').hide();
});
});

you can use the css property pointer-events: none;as well.
#karte .flag {
pointer-events: none; /*Added line*/
position: absolute;
background: url('http://static.netzwelt.de/farcade/images/capturetheflag1.gif') no-repeat;
width: 50px;
height: 50px;
top: 200px;
left: 50px;
}
Here is the Demo http://jsfiddle.net/9Br6h/2/.

Assuming that the flag completely covers the 'hover' area underneath it, you can modify your code so that the line that sets the mouseover event reads as follows:
// show div on mouseover
$('area, .flag').mouseover(function(event) {
Here is an example: http://jsfiddle.net/9Br6h/1/

Javascript - make popup div open below clicked link

Sorry for the unclear title, I can't formulate a better concise explanation.
I have a list, and within each list item is a link which opens an othersiwse hidden <div> using the following jQuery:
$('a.showreranks').click(function () {
$('body').append('<div class="overlay"></div>');
$('#rerank_details').slideToggle(300);
return false;
});
rerank_details being the id of the div and showreranks being the class of all the links.
This is the CSS of the div:
#rerank_details {
display: none;
background: white;
position: absolute;
border: 1px solid black;
border-radius: 6px;
width: 305px;
padding: 15px;
overflow: hidden;
top: 50%;
left: 50%;
height: 200x;
text-shadow: none;
z-index: 50;
}
So, you see, the opened div is centered when it's opened. It is then populated with info relating to the list item that was clicked but you don't need to worry about that. What I need help with is the following - I don't want the div to be centered on the screen. Instead I'd like it to be positioned right below the link that was clicked. Note that there could be a lot of links on the page, one below the other and the vertical distances could be irregular. How do I accomplish this?

I think that this is what you are trying to do:
http://jsfiddle.net/SO_AMK/r7ZDm/

The answer has already been accepted, but perhaps this is a cleaner version. The animations are all fixed.

if it doesn't have to be within the normal flow of the DOM just use absolute positioning and the event object.
function(event){
var box = //get a handle to box
box.style.position = 'aboslute';
box.style.left = event.page.x;
box.style.top = event.page.y;
}

Not worked true tooltip box in jQuery

Don't know why the tooltip box(class .show_tooltip) shows up on the left when mouse enters on li a. I want to display each tooltip box on top of the same link that mouse is, i.e. just above/left of the link. Links have to be on the right just as they are now, so please do not change my html code) DEMO
Example : Mouseover on "how": What can I do to get it like this?
These codes are a small specimen part from my original code, which is quite long.
CSS:
.show_tooltip{
background-color: #E5F4FE;
display: none;
padding: 5px 10px;
border: #5A5959 1px solid;
position: absolute;
z-index: 9999;
color: #0C0C0C;
/*margin: 0 0 0 0;
top: 0;
bottom: 0;*/
}
HTML:
<ul>
<li>
<div class="show_tooltip">
put returns between paragraphs
</div>
about
</li>
<li>
<div class="show_tooltip">
for linebreak add 2 spaces at end
</div>
how
</li>
</ul>
jQuery:
$("li a").mouseenter(function(){
$(this).prev().fadeIn();
}).mousemove(function(e) {
$('.tooltip').css('bottom', e.pageY - 10);
$('.tooltip').css('right', e.pageX + 10);
}).mouseout(function(){
$(this).prev().fadeOut();
})

Firstly, you are making the markup complicated that way, but since you told not to modify the HTML, here's what you can do to place the tooltip just next to the link.
Working Demo -> http://jsfiddle.net/bikerabhinav/AQh6y/8/
Explanation:
Get the width of parent container (to act as the axis/base)
var t = $('ul').outerWidth();
Get the left-offset of link :
var l = $(this).offset();
Apply these to the CSS of tooltip. Position it absolutely:
$("li a").mouseenter(function(){
var l = $(this).offset();
var t = $('ul').outerWidth();
$(this).prev().css({right:t+20-l.left,top:l.top}).fadeIn();
}).mousemove(function(e) {
$('.tooltip').css('bottom', e.pageY - 10);
$('.tooltip').css('right', e.pageX + 10);
}).mouseout(function(){
$(this).prev().fadeOut();
});
PS: this is more of a hack basically, but I hope you get what I'm trying to do here. A much better way would be if you clean up the HTML

is that you want --> DEMO
change position: fixed; in .show_tooltip{}