<div id="pop">
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li>Item 4</li>
<li>Item 5</li>
<li>Item 6</li>
<li>Item 7</li>
</ul>
</div>
<div id="info-1></div>
<div id="info-2></div>
And when you hover over one of the items a window is displayed with some info regarding the item. I have worked this out for one item, now I wanna know how I can make this work for the entire list.
My initial thought was to create one script per each item... but that seems a bit thick considering the functionality of js.
Javascript
$(function(){
$('pop il li').hover(function(){
$('#info-1').show();
},function(){
$('#info-1').hide();
});
});
Now I need the following. Once the "window" is displayed on hover, in I need the window to stay open in some way for me to be able to scroll through the content using my mouse. This is mainly because I have some links inside it and need to access them! Right now, As soon as i leave the li item, the window of course disappears... which is not fun. So, how can i solve it?
UPDATED
I would make one function to handle the action you want for these. Make sure the 'info' divs are in the same order as the 'pop' li's
Here is an example FIDDLE
<div id="pop">
<ul>
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
<li>Item 4</li>
<li>Item 5</li>
<li>Item 6</li>
<li>Item 7</li>
</ul>
</div>
<div class="info"></div>
<div class="info"></div>
<div class="info"></div>
Then use this jquery
$('#pop li').mouseover(function() {
$('.info').hide();
var x = $(this).index();
$('.info').eq(x).show();
});
$('.info').mouseout(function(){
$(this).hide();
});
Related
I create simple drop down menu using Foundation 6
<ul class="dropdown menu" data-dropdown-menu>
<li>
Item 1
<ul class="menu">
<li>Item 1A</li>
</ul>
</li>
<li>Item 2</li>
<li>Item 3</li>
<li>Item 4</li>
</ul>
Now i want to on different event ( like other button to hide or show menu.) But in doc there is no method to do this. When I use jquery trigger on click also not working is there any solution for this ?
Attach an event handler to an element (for example a button) and give it a function like hiding the dropdown menu:
$("button").click(function(){$(".dropdown").hide()})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul class="dropdown menu" data-dropdown-menu>
<li>
Item 1
<ul class="menu">
<li>Item 1A</li>
</ul>
</li>
<li>Item 2</li>
<li>Item 3</li>
<li>Item 4</li>
</ul>
<button>
I'm a button
</button>
To allow it to come back again, try $("button").click(function(){$(".dropdown").toggle()})
I may possible have a requirement where i have to link the parent menu to a link rather than showing sub menu. Right now i am using Slick Menu http://slicknav.com/
Logically parent menu should not be linked as it should show child menu on mobile device. while desktop version we can counter this with hover effect can show sub-menus and click on the parent menu can open link also but on small screen we can either open link or show submenu.
my question right now is that in fiddle example (http://jsfiddle.net/y1dLdd1f/1/) i am linking Parent 1 meny to google.com, but script is blocking this. How can i unblock it and when user click on it it opens the page rather than showing the sub menu if parent menu has a proper link
<ul id="menu">
<li>Parent 1
<ul>
<li>item 3</li>
<li>Parent 3
<ul>
<li>item 8</li>
<li>item 9</li>
<li>item 10</li>
</ul>
</li>
<li>item 4</li>
</ul>
</li>
<li>item 1</li>
<li>non-link item</li>
<li>Parent 2
<ul>
<li>item 5</li>
<li>item 6</li>
<li>item 7</li>
</ul>
</li>
</ul>
Slick menu has a number of available options including "allowParentLinks", all you need should be,...
$(document).ready(function(){
$('#menu').slicknav({
allowParentLinks:"true"
});
});
But to show this working in JSFiddle you would need to add target="_blank" to you <a> tag.
I'm having a problem with jQuery.
I'm doing a mobile menu using jQuery with sub menus. I need to use the same class to activate all the menus because they will be created dynamically, but when I do this, when I click on a item, all the others show their sub-item too.
To be clear, here's an example:
<ul>
<li class="OpenMenu">Menu 1
<ul class="sub-item">
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
</ul>
</li>
<li class="OpenMenu">Menu 2
<ul class="sub-item">
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
</ul>
</li>
<li class="OpenMenu">Menu 3
<ul class="sub-item">
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3</li>
</ul>
</li>
</ul>
I need each menu to show its sub-items only when is clicked, but all using the same class. I'm doing the "open" effect of the menus with jQuery.
You can achieve by below code, find() method will drill down to only its child items and find sub items
$(".OpenMenu").click(function(){
$(this).find('.sub-item').show();
});
DEMO (covers only displaying required sub menu)
To view how to hide other sub items and display only current items, use this http://jsfiddle.net/Lboyrqnc/2/
I am trying to create a menu formated by jQuery. The appearance and functionality of level one items is correct, but the subsquent levels are not correctly formatting as a submenu that appears with mouse over. Rather it simply appears, and does not highlight the items as the level one items do with mouse over or hover (neither function appears in my code).
HTML CODE
<div style="width: 25%">
<ul id="menu">
<li>Item 1</li>
<li>Item 2</li>
<li>Item 3
<ul>
<li>Item 3-1</li>
<li>Item 3-2</li>
<li>Item 3-3</li>
<li>Item 3-4</li>
<li>Item 3-5</li>
</ul>
</li>
<li>Item 4</li>
<li>Item 5</li>
</ul>
</div>
jQuery or JavaScript
$(document).ready(function() {
$('#menu').menu({menus: "div"});
});
JS Fiddle
I figured it out. It is a matter of simply deleting in the JavaScript the following from line 6:
{menus: div}
I am looping through some unordered lists and I'd like to get all of the descendants by using only the saved selectors (both of which are wrapped with jquery objects).
Here is my sample HTML:
<ul>
<li>item 1</li>
<li>item 2</li>
<li>item 3</li>
<li>item 4</li>
<li>item 5</li>
</ul>
<ul>
<li>item 6</li>
<li>item 7</li>
<li>item 8</li>
<li>item 9</li>
<li>item 10</li>
</ul>
<ul>
<li>item 11</li>
<li>item 12</li>
<li>item 13</li>
<li>item 14</li>
<li>item 15</li>
</ul>
<ul>
<li>item 16</li>
<li>item 17</li>
<li>item 18</li>
<li>item 19</li>
<li>item 20</li>
</ul>
Here is my sample JS:
$(document).ready(function() {
allUls = $('ul');
allAs = allUls.find('a');
// shouldn't this next line get all anchors within the second unordered list?
console.log( allUls.eq(1).find(allAs) );
});
So there it is. I was expecting for an array of anchors that are descendants of the second list to be sent to the console. But that's not the case.
You can see for yourself on my jsfiddle example: http://jsfiddle.net/u6uf4/
I'm also open to any "better" solutions you may have. Just keep in mind, I'd like to use only the saved selectors and would like to avoid creating any new selectors for this task.
Thank you for your time and effort for helping a fellow Jquery-er!
The option to pass a jQuery object to find() was only recently added in version 1.6. Your jsfiddle example uses version 1.5.2. Select the latest jQuery version on the left to make it work.
Close, but you don't need to filter by allAs, just filter by 'a'.
allUls.eq(1).find('a')