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Following this question and many others, I'm trying to convert an rgb value to a hex value.
Copying/pasting the most used and accepted answer, I've made this script
function componentToHex(c) {
var hex = c.toString(16);
return hex.length == 1 ? "0" + hex : hex;
}
function rgbToHex(rgb) {
var colors = rgb.split("(")
colors = colors[1].split(")")
colors = colors[0].split(",")
var r = 255 - parseInt(colors[0])
var g = 255 - parseInt(colors[1])
var b = 255 - parseInt(colors[2])
return componentToHex(r) + componentToHex(g) + componentToHex(b);
}
alert(rgbToHex("rgb(0, 51, 255)"))
Result:
ffcc00
Expected result:
0033ff
Why is it not working?
Use the parseInt result directly, not 255 minus the value:
var r = parseInt(colors[0])
var g = parseInt(colors[1])
var b = parseInt(colors[2])
You're currently producing the exact opposite color by outputting values complementary to (rather than equivalent to) the input values.
Instead of 255 - parseInt(colors[i]), it should be parseInt(colors[i]).
In your current implementation - if red is 0, 255 - 0 = 255, which in hex is FF.
UPDATE: the problem is with FF's .cloneNode() method: http://jsfiddle.net/beCVL/1/
I know FF and IE internally convert color to RGB, which causes problem, because the color values don't match what is on the server.
Proof:
Chrome 18:
CKEDITOR.instances.selected_text_actual.getData()
>> "s <span style="color: #ff0000">text</span>"
FireFox 11:
CKEDITOR.instances.selected_text_actual.getData()
>> "s <span style="color: rgb(255, 0, 0);">text</span>"
So, the way I want to solve the problem is to make CKEditor's data processor always use the rgb values. Is there a way to do that?
I found that something like this should work:
CKEDITOR.on( 'instanceReady', function( ev ){
var editor = ev.editor,
dataProcessor = editor.dataProcessor,
htmlFilter = dataProcessor && dataProcessor.htmlFilter;
// HTML 4 way to end tags
dataProcessor.writer.selfClosingEnd = '>';
htmlFilter.addRules({
elements:{
$:function(element){
var e = jQuery(element);
e.css("color", e.css("color")); // jquery auto converts to rgb
}
}
});
});
Source: http://sebduggan.com/blog/customising-ckeditor-settings-in-mura/
but, there is no change.
The conversion to RGB is pretty straight forward:
a.attr("style", "color: #444")
[
<div style="color: #444"></div>
]
a.css("color", a.css("color"));
[
<div style="color: rgb(68, 68, 68); "></div>
]
EDIT: the problem is with FF's .cloneNode() method: http://jsfiddle.net/beCVL/1/
As I replied to you in http://cksource.com/forums/viewtopic.php?f=11&t=25141 you can use the original "output HTML" sample that contains the full code that has been copied in the blog that you linked and use the convertRGBToHex function as it does.
And BTW, Firefox respects the styles, the only browser that currently changes that part is IE.
If you want to compare two color values that can each be represented in several different ways, then you have to make sure both are converted to a canonical form (e.g. the exact same form).
So, you can use rgb(x,y,z) as your canonical form if you want, but you will have to make sure that any color values expressed as #xyz or #xxyyzz are first converted to the rgb form before comparing.
Here's a function that converts three values of colors all to rgb(x,y,z) with no spaces and then compares them and returns to you the result:
function colorsAreSame(c1, c2) {
var space = /\s+/g;
function makeRGB(c) {
var r, g, b;
c = c.replace(space, "");
if (c.charAt(0) == "#") {
if (c.length == 4) {
r = parseInt(c.charAt(1), 16);
r = (r * 16) + r;
g = parseInt(c.charAt(2), 16);
g = (g * 16) + g;
b = parseInt(c.charAt(3), 16);
b = (b * 16) + b;
} else if (c.length == 7) {
r = parseInt(c.substr(1, 2), 16);
g = parseInt(c.substr(3, 2), 16);
b = parseInt(c.substr(5, 2), 16);
}
return "rgb(" + r + "," + g + "," + b + ")";
} else {
return(c);
}
}
c1 = makeRGB(c1);
c2 = makeRGB(c2);
return(c1 == c2);
}
The fact that cloning a node changes the style attribute is almost certainly a bug in Gecko but in the mean time element.style.color will return rgb(255, 0, 0) in both cases.
Alright thought I would throw this one out there for the crowd to think over.
Given a function (written in javascript) that expects two strings formated like a hex color (ex #FF0000)
return a hex color that is the average of both of the colors passed.
function averageColors(firstColor,secondColor)
{
...
return avgColor;
}
--edit--
average would be defined as
if the color passed was yellow and the second was light purple the returned color would be a medium orange
I hate sounding like the oh-so-broken jQuery record, but there is a jQuery plugin for this already.
A quick/dirty/convenient/ES6 way to blend two hex colors by a specified perecentage:
// blend two hex colors together by an amount
function blendColors(colorA, colorB, amount) {
const [rA, gA, bA] = colorA.match(/\w\w/g).map((c) => parseInt(c, 16));
const [rB, gB, bB] = colorB.match(/\w\w/g).map((c) => parseInt(c, 16));
const r = Math.round(rA + (rB - rA) * amount).toString(16).padStart(2, '0');
const g = Math.round(gA + (gB - gA) * amount).toString(16).padStart(2, '0');
const b = Math.round(bA + (bB - bA) * amount).toString(16).padStart(2, '0');
return '#' + r + g + b;
}
console.log(blendColors('#00FF66', '#443456', 0.5));
Where amount should be 0 to 1, with 0 being exactly colorA, 1 being exactly colorB, and 0.5 being the "midpoint".
Only requires a few lines of POJS if you don't want to bother with lots of unnecessary stuff:
// Expects input as 'nnnnnn' where each nn is a
// 2 character hex number for an RGB color value
// e.g. #3f33c6
// Returns the average as a hex number without leading #
var averageRGB = (function () {
// Keep helper stuff in closures
var reSegment = /[\da-z]{2}/gi;
// If speed matters, put these in for loop below
function dec2hex(v) {return v.toString(16);}
function hex2dec(v) {return parseInt(v,16);}
return function (c1, c2) {
// Split into parts
var b1 = c1.match(reSegment);
var b2 = c2.match(reSegment);
var t, c = [];
// Average each set of hex numbers going via dec
// always rounds down
for (var i=b1.length; i;) {
t = dec2hex( (hex2dec(b1[--i]) + hex2dec(b2[i])) >> 1 );
// Add leading zero if only one character
c[i] = t.length == 2? '' + t : '0' + t;
}
return c.join('');
}
}());
Smells like homework to me, but here's my clue.
Take each hex value for R, G, and B, and average each of them. If necessary convert to Decimal to do the math.
function d2h(d) {return d.toString(16).padStart(2,'0');}
function h2d(h) {return parseInt(h,16);}
Then return a string containing the concatenated values of the three elements.
Here's a compact set of relevant (interdependent) functions:
Hex ⟷ RGB Color Conversion:
function hexToRgb(h){return['0x'+h[1]+h[2]|0,'0x'+h[3]+h[4]|0,'0x'+h[5]+h[6]|0]}
function rgbToHex(r,g,b){return"#"+((1<<24)+(r<<16)+(g<<8)+ b).toString(16).slice(1);}
Calculate Average of 2 Hex Colors: Requires conversion functions (above)
function avgHex(h1,h2){a=hexToRgb(h1);b=hexToRgb(h2); return rgbToHex(~~((a[0]+b[0])/2),~~((a[1]+b[1])/2),~~((a[2]+b[2])/2));}
Generate Random Hex Color:
function rndHex(){return'#'+('00000'+(Math.random()*(1<<24)|0).toString(16)).slice(-6);}
Run snippet for demo:
// color functions (average/random/conversion)
function hexToRgb(h){return['0x'+h[1]+h[2]|0,'0x'+h[3]+h[4]|0,'0x'+h[5]+h[6]|0]}
function rgbToHex(r,g,b){return"#"+((1<<24)+(r<<16)+(g<<8)+ b).toString(16).slice(1);}
function rndHex(){return'#'+('00000'+(Math.random()*(1<<24)|0).toString(16)).slice(-6);}
function avgHex(h1,h2){a=hexToRgb(h1);b=hexToRgb(h2);return rgbToHex(~~((a[0]+b[0])/2),~~((a[1]+b[1])/2),~~((a[2]+b[2])/2));}
//code below is just for the demo
function auto(){if(chk.checked){tmr=setInterval(rnd,1000)}else{clearTimeout(tmr)}}auto();
function rnd(go){for(h of[h1,h2]){h.value=rndHex();}avgInput();}
addEventListener('input',avgInput);
function avgInput(){ // get avg & colorize
ha.value=avgHex(h1.value,h2.value);
for(h of [h1,h2,ha])h.style.background=h.value;
}
*{font-family:monospace;font-size:5vw; }
<label>Color 1 → <input id='h1'></label><br>
<label>Average → <input id='ha'></label><br>
<label>Color 2 → <input id='h2'></label><br>
<label>Type hex colors or <input type='checkbox' id='chk' onclick='auto()' style=' transform: scale(1.5)'checked>Autorandom</label>
Here is my function, hope it helps.
function averageColors( colorArray ){
var red = 0, green = 0, blue = 0;
for ( var i = 0; i < colorArray.length; i++ ){
red += hexToR( "" + colorArray[ i ] + "" );
green += hexToG( "" + colorArray[ i ] + "" );
blue += hexToB( "" + colorArray[ i ] + "" );
}
//Average RGB
red = (red/colorArray.length);
green = (green/colorArray.length);
blue = (blue/colorArray.length);
console.log(red + ", " + green + ", " + blue);
return new THREE.Color( "rgb("+ red +","+ green +","+ blue +")" );
}
//get the red of RGB from a hex value
function hexToR(h) {return parseInt((cutHex( h )).substring( 0, 2 ), 16 )}
//get the green of RGB from a hex value
function hexToG(h) {return parseInt((cutHex( h )).substring( 2, 4 ), 16 )}
//get the blue of RGB from a hex value
function hexToB(h) {return parseInt((cutHex( h )).substring( 4, 6 ), 16 )}
//cut the hex into pieces
function cutHex(h) {if(h.charAt(1) == "x"){return h.substring( 2, 8 );} else {return h.substring(1,7);}}
Very late to this party, but I was personally looking for a way to average an undefined amount of HEX values. Based on the answer #RobG, I came up with this. Granted, the more colors you add the more brown/greyish they get, but, perhaps it helps!
/**
* Averages an array of hex colors. Returns one hex value (with leading #)
*
* #param {Array} colors - An array of hex strings, e.g. ["#001122", "#001133", ...]
*/
function averageHex(colors) {
// transform all hex codes to integer arrays, e.g. [[R, G, B], [R,G,B], ...]
let numbers = colors.map(function(hex) {
// split in seperate R, G and B
let split = hex.match(/[\da-z]{2}/gi);
// transform to integer values
return split.map(function(toInt) {
return parseInt(toInt, 16);
});
});
// reduce the array by averaging all values, resulting in an average [R, G, B]
let averages = numbers.reduce(function(total, amount, index, array) {
return total.map(function(subtotal, subindex) {
// if we reached the last color, average it out and return the hex value
if (index == array.length - 1) {
let result = Math.round((subtotal + amount[subindex]) / array.length).toString(16);
// add a leading 0 if it is only one character
return result.length == 2 ? '' + result : '0' + result;
} else {
return subtotal + amount[subindex];
}
});
});
// return them as a single hex string
return "#" + averages.join('');
}
console.log(averageHex(["#FF110C", "#0000AA", "#55063d", "#06551e"]));
// expected: #571b44, see also https://www.colorhexa.com/ and enter "#FF110C+#0000AA+#55063d+#06551e"
Here is the function
function avgColor(color1, color2) {
//separate each color alone (red, green, blue) from the first parameter (color1)
//then convert to decimal
let color1Decimal = {
red: parseInt(color1.slice(0, 2), 16),
green: parseInt(color1.slice(2, 4), 16),
blue: parseInt(color1.slice(4, 6), 16)
}
//separate each color alone (red, green, blue) from the second parameter (color2)
//then convert to decimal
let color2Decimal = {
red: parseInt(color2.slice(0, 2), 16),
green: parseInt(color2.slice(2, 4), 16),
blue: parseInt(color2.slice(4, 6), 16),
}
// calculate the average of each color (red, green, blue) from each parameter (color1,color2)
let color3Decimal = {
red: Math.ceil((color1Decimal.red + color2Decimal.red) / 2),
green: Math.ceil((color1Decimal.green + color2Decimal.green) / 2),
blue: Math.ceil((color1Decimal.blue + color2Decimal.blue) / 2)
}
//convert the result to hexadecimal and don't forget if the result is one character
//then convert it to uppercase
let color3Hex = {
red: color3Decimal.red.toString(16).padStart(2, '0').toUpperCase(),
green: color3Decimal.green.toString(16).padStart(2, '0').toUpperCase(),
blue: color3Decimal.blue.toString(16).padStart(2, '0').toUpperCase()
}
//put the colors (red, green, blue) together to have the output
let color3 = color3Hex.red + color3Hex.green + color3Hex.blue
return color3
}
console.log(avgColor("FF33CC", "3300FF"))
// avgColor("FF33CC", "3300FF") => "991AE6"
console.log(avgColor("991AE6", "FF0000"))
// avgColor("991AE6", "FF0000") => "CC0D73"
console.log(avgColor("CC0D73", "0000FF"))
// avgColor("CC0D73", "0000FF") => "6607B9"
To check you can use this link and midpoint 1 then blend
https://meyerweb.com/eric/tools/color-blend/#CC0D73:0000FF:1:hex
I want to create a function that will accept any old string (will usually be a single word) and from that somehow generate a hexadecimal value between #000000 and #FFFFFF, so I can use it as a colour for a HTML element.
Maybe even a shorthand hex value (e.g: #FFF) if that's less complicated. In fact, a colour from a 'web-safe' palette would be ideal.
Here's an adaptation of CD Sanchez' answer that consistently returns a 6-digit colour code:
var stringToColour = function(str) {
var hash = 0;
for (var i = 0; i < str.length; i++) {
hash = str.charCodeAt(i) + ((hash << 5) - hash);
}
var colour = '#';
for (var i = 0; i < 3; i++) {
var value = (hash >> (i * 8)) & 0xFF;
colour += ('00' + value.toString(16)).substr(-2);
}
return colour;
}
Usage:
stringToColour("greenish");
// -> #9bc63b
Example:
http://jsfiddle.net/sUK45/
(An alternative/simpler solution might involve returning an 'rgb(...)'-style colour code.)
Just porting over the Java from Compute hex color code for an arbitrary string to Javascript:
function hashCode(str) { // java String#hashCode
var hash = 0;
for (var i = 0; i < str.length; i++) {
hash = str.charCodeAt(i) + ((hash << 5) - hash);
}
return hash;
}
function intToRGB(i){
var c = (i & 0x00FFFFFF)
.toString(16)
.toUpperCase();
return "00000".substring(0, 6 - c.length) + c;
}
To convert you would do:
intToRGB(hashCode(your_string))
I wanted similar richness in colors for HTML elements, I was surprised to find that CSS now supports hsl() colors, so a full solution for me is below:
Also see How to automatically generate N "distinct" colors? for more alternatives more similar to this.
Edit: updating based on #zei's version (with american spelling)
var stringToColor = (string, saturation = 100, lightness = 75) => {
let hash = 0;
for (let i = 0; i < string.length; i++) {
hash = string.charCodeAt(i) + ((hash << 5) - hash);
hash = hash & hash;
}
return `hsl(${(hash % 360)}, ${saturation}%, ${lightness}%)`;
}
// For the sample on stackoverflow
function colorByHashCode(value) {
return "<span style='color:" + stringToColor(value) + "'>" + value + "</span>";
}
document.body.innerHTML = [
"javascript",
"is",
"nice",
].map(colorByHashCode).join("<br/>");
span {
font-size: 50px;
font-weight: 800;
}
In HSL its Hue, Saturation, Lightness. So the hue between 0-359 will get all colors, saturation is how rich you want the color, 100% works for me. And Lightness determines the deepness, 50% is normal, 25% is dark colors, 75% is pastel. I have 30% because it fit with my color scheme best.
Here is my 2021 version with Reduce Function and HSL Color.
function getBackgroundColor(stringInput) {
let stringUniqueHash = [...stringInput].reduce((acc, char) => {
return char.charCodeAt(0) + ((acc << 5) - acc);
}, 0);
return `hsl(${stringUniqueHash % 360}, 95%, 35%)`;
}
Using the hashCode as in Cristian Sanchez's answer with hsl and modern javascript, you can create a color picker with good contrast like this:
function hashCode(str) {
let hash = 0;
for (var i = 0; i < str.length; i++) {
hash = str.charCodeAt(i) + ((hash << 5) - hash);
}
return hash;
}
function pickColor(str) {
return `hsl(${hashCode(str) % 360}, 100%, 80%)`;
}
one.style.backgroundColor = pickColor(one.innerText)
two.style.backgroundColor = pickColor(two.innerText)
div {
padding: 10px;
}
<div id="one">One</div>
<div id="two">Two</div>
Since it's hsl, you can scale luminance to get the contrast you're looking for.
function hashCode(str) {
let hash = 0;
for (var i = 0; i < str.length; i++) {
hash = str.charCodeAt(i) + ((hash << 5) - hash);
}
return hash;
}
function pickColor(str) {
// Note the last value here is now 50% instead of 80%
return `hsl(${hashCode(str) % 360}, 100%, 50%)`;
}
one.style.backgroundColor = pickColor(one.innerText)
two.style.backgroundColor = pickColor(two.innerText)
div {
color: white;
padding: 10px;
}
<div id="one">One</div>
<div id="two">Two</div>
I find that generating random colors tends to create colors that do not have enough contrast for my taste. The easiest way I have found to get around that is to pre-populate a list of very different colors. For every new string, assign the next color in the list:
// Takes any string and converts it into a #RRGGBB color.
var StringToColor = (function(){
var instance = null;
return {
next: function stringToColor(str) {
if(instance === null) {
instance = {};
instance.stringToColorHash = {};
instance.nextVeryDifferntColorIdx = 0;
instance.veryDifferentColors = ["#000000","#00FF00","#0000FF","#FF0000","#01FFFE","#FFA6FE","#FFDB66","#006401","#010067","#95003A","#007DB5","#FF00F6","#FFEEE8","#774D00","#90FB92","#0076FF","#D5FF00","#FF937E","#6A826C","#FF029D","#FE8900","#7A4782","#7E2DD2","#85A900","#FF0056","#A42400","#00AE7E","#683D3B","#BDC6FF","#263400","#BDD393","#00B917","#9E008E","#001544","#C28C9F","#FF74A3","#01D0FF","#004754","#E56FFE","#788231","#0E4CA1","#91D0CB","#BE9970","#968AE8","#BB8800","#43002C","#DEFF74","#00FFC6","#FFE502","#620E00","#008F9C","#98FF52","#7544B1","#B500FF","#00FF78","#FF6E41","#005F39","#6B6882","#5FAD4E","#A75740","#A5FFD2","#FFB167","#009BFF","#E85EBE"];
}
if(!instance.stringToColorHash[str])
instance.stringToColorHash[str] = instance.veryDifferentColors[instance.nextVeryDifferntColorIdx++];
return instance.stringToColorHash[str];
}
}
})();
// Get a new color for each string
StringToColor.next("get first color");
StringToColor.next("get second color");
// Will return the same color as the first time
StringToColor.next("get first color");
While this has a limit to only 64 colors, I find most humans can't really tell the difference after that anyway. I suppose you could always add more colors.
While this code uses hard-coded colors, you are at least guaranteed to know during development exactly how much contrast you will see between colors in production.
Color list has been lifted from this SO answer, there are other lists with more colors.
If your inputs are not different enough for a simple hash to use the entire color spectrum, you can use a seeded random number generator instead of a hash function.
I'm using the color coder from Joe Freeman's answer, and David Bau's seeded random number generator.
function stringToColour(str) {
Math.seedrandom(str);
var rand = Math.random() * Math.pow(255,3);
Math.seedrandom(); // don't leave a non-random seed in the generator
for (var i = 0, colour = "#"; i < 3; colour += ("00" + ((rand >> i++ * 8) & 0xFF).toString(16)).slice(-2));
return colour;
}
I have opened a pull request to Please.js that allows generating a color from a hash.
You can map the string to a color like so:
const color = Please.make_color({
from_hash: "any string goes here"
});
For example, "any string goes here" will return as "#47291b"
and "another!" returns as "#1f0c3d"
Javascript Solution inspired by Aslam's solution but returns a color in hex color code
/**
*
* #param {String} - stringInput - 'xyz'
* #returns {String} - color in hex color code - '#ae6204'
*/
function getBackgroundColor(stringInput) {
const h = [...stringInput].reduce((acc, char) => {
return char.charCodeAt(0) + ((acc << 5) - acc);
}, 0);
const s = 95, l = 35 / 100;
const a = s * Math.min(l, 1 - l) / 100;
const f = n => {
const k = (n + h / 30) % 12;
const color = l - a * Math.max(Math.min(k - 3, 9 - k, 1), -1);
return Math.round(255 * color).toString(16).padStart(2, '0'); // convert to Hex and prefix "0" if needed
};
return `#${f(0)}${f(8)}${f(4)}`;
}
Yet another solution for random colors:
function colorize(str) {
for (var i = 0, hash = 0; i < str.length; hash = str.charCodeAt(i++) + ((hash << 5) - hash));
color = Math.floor(Math.abs((Math.sin(hash) * 10000) % 1 * 16777216)).toString(16);
return '#' + Array(6 - color.length + 1).join('0') + color;
}
It's a mixed of things that does the job for me.
I used JFreeman Hash function (also an answer in this thread) and Asykäri pseudo random function from here and some padding and math from myself.
I doubt the function produces evenly distributed colors, though it looks nice and does that what it should do.
Here's a solution I came up with to generate aesthetically pleasing pastel colours based on an input string. It uses the first two chars of the string as a random seed, then generates R/G/B based on that seed.
It could be easily extended so that the seed is the XOR of all chars in the string, rather than just the first two.
Inspired by David Crow's answer here: Algorithm to randomly generate an aesthetically-pleasing color palette
//magic to convert strings to a nice pastel colour based on first two chars
//
// every string with the same first two chars will generate the same pastel colour
function pastel_colour(input_str) {
//TODO: adjust base colour values below based on theme
var baseRed = 128;
var baseGreen = 128;
var baseBlue = 128;
//lazy seeded random hack to get values from 0 - 256
//for seed just take bitwise XOR of first two chars
var seed = input_str.charCodeAt(0) ^ input_str.charCodeAt(1);
var rand_1 = Math.abs((Math.sin(seed++) * 10000)) % 256;
var rand_2 = Math.abs((Math.sin(seed++) * 10000)) % 256;
var rand_3 = Math.abs((Math.sin(seed++) * 10000)) % 256;
//build colour
var red = Math.round((rand_1 + baseRed) / 2);
var green = Math.round((rand_2 + baseGreen) / 2);
var blue = Math.round((rand_3 + baseBlue) / 2);
return { red: red, green: green, blue: blue };
}
GIST is here: https://gist.github.com/ro-sharp/49fd46a071a267d9e5dd
Here is another try:
function stringToColor(str){
var hash = 0;
for(var i=0; i < str.length; i++) {
hash = str.charCodeAt(i) + ((hash << 3) - hash);
}
var color = Math.abs(hash).toString(16).substring(0, 6);
return "#" + '000000'.substring(0, 6 - color.length) + color;
}
All you really need is a good hash function. On node, I just use
const crypto = require('crypto');
function strToColor(str) {
return '#' + crypto.createHash('md5').update(str).digest('hex').substr(0, 6);
}
After having a look at the rather code intensive and rather old answers, I thought I'd review this issue from a 2021 standpoint just for fun, hope it is of use to anyone. Having the HSL color model and the crypto API implemented in pretty much all browsers (except IE of course) today, it could be solved as simple as that:
async function getColor(text, minLightness = 40, maxLightness = 80, minSaturation = 30, maxSaturation = 100) {
let hash = await window.crypto.subtle.digest("SHA-1", new TextEncoder().encode(text));
hash = new Uint8Array(hash).join("").slice(16);
return "hsl(" + (hash % 360) + ", " + (hash % (maxSaturation - minSaturation) + minSaturation) + "%, " + (hash % (maxLightness - minLightness) + minLightness) + "%)";
}
function generateColor() {
getColor(document.getElementById("text-input").value).then(color => document.querySelector(".swatch").style.backgroundColor = color);
}
input {
padding: 5px;
}
.swatch {
margin-left: 10px;
width: 28px;
height: 28px;
background-color: white;
border: 1px solid gray;
}
.flex {
display: flex;
}
<html>
<body>
<div class="flex">
<form>
<input id="text-input" type="text" onInput="generateColor()" placeholder="Type here"></input>
</form>
<div class="swatch"></div>
</div>
</body>
</html>
This should be way faster than generating hashes manually, and also offers a way to define saturation and lightness in case you don't want colors that are too flat or too bright or too dark (e.g. if you want to write text on those colors).
2023 version plain and simple TypeScript arrow function that returns HSL color.
const stringToColor = (value: string) => {
let hash = 0;
for (let i = 0; i < value.length; i++) {
hash = value.charCodeAt(i) + ((hash << 5) - hash);
}
return `hsl(${hash % 360}, 85%, 35%)`;
};
This function does the trick. It's an adaptation of this, fairly longer implementation this repo ..
const color = (str) => {
let rgb = [];
// Changing non-hexadecimal characters to 0
str = [...str].map(c => (/[0-9A-Fa-f]/g.test(c)) ? c : 0).join('');
// Padding string with zeroes until it adds up to 3
while (str.length % 3) str += '0';
// Dividing string into 3 equally large arrays
for (i = 0; i < str.length; i += str.length / 3)
rgb.push(str.slice(i, i + str.length / 3));
// Formatting a hex color from the first two letters of each portion
return `#${rgb.map(string => string.slice(0, 2)).join('')}`;
}
I have a situation where i want to display a background based on the username of the user and display the username's first letter on top.
i used the belove code for that it worked well for me
var stringToColour = function (str) {
var hash = 0;
for (var i = 0; i < str.length; i++) {
hash = str.charCodeAt(i) + ((hash << 5) - hash);
}
var colour = '#';
for (var i = 0; i < 3; i++) {
var value = (hash >> (i * 8)) & 0xff;
colour += ('00' + value.toString(16)).substr(-2);
}
return colour;}
To find the appropriate colour you can use
function lightOrDark(color) {
// Check the format of the color, HEX or RGB?
if (color.match(/^rgb/)) {
// If HEX --> store the red, green, blue values in separate variables
color = color.match(
/^rgba?\((\d+),\s*(\d+),\s*(\d+)(?:,\s*(\d+(?:\.\d+)?))?\)$/,
);
var r = color[1];
var g = color[2];
var b = color[3];
} else {
// If RGB --> Convert it to HEX: http://gist.github.com/983661
color = +(
'0x' + color.slice(1).replace(color.length < 5 && /./g, '$&$&')
);
r = color >> 16;
g = (color >> 8) & 255;
b = color & 255;
}
// HSP equation from http://alienryderflex.com/hsp.html
var hsp = Math.sqrt(0.299 * (r * r) + 0.587 * (g * g) + 0.114 * (b * b));
// Using the HSP value, determine whether the color is light or dark
if (hsp > 127.5) {
return 'light';
} else {
return 'dark';
}
}
my code is for Java.
Thanks for all.
public static int getColorFromText(String text)
{
if(text == null || text.length() < 1)
return Color.BLACK;
int hash = 0;
for (int i = 0; i < text.length(); i++)
{
hash = text.charAt(i) + ((hash << 5) - hash);
}
int c = (hash & 0x00FFFFFF);
c = c - 16777216;
return c;
}
I convert this in one line for Python
import hashlib
hash = hashlib.sha1(b'user#email.com').hexdigest()
print("#" + hash[0:6])
Using javascript with or without Jquery, I need to a create a gradient of colours based on a start and finish color. Is this possible to do programmatically?
The end colour is only ever going to be darker shade of the start colour and it's for an unordered list which I have no control over the number of li items. I'm looking for a solution that allows me to pick a start and end color, convert the hex value into RGB so it can be manipulated in code. The starting RGB values gets incremented by a step value calculated based upon the number of items.
so if the list had 8 items then the it needs to increment the seperate Red Green Blue values in 8 steps to achieve the final colour. Is there a better way to do it and if so where can I find some sample code?
I created a JS library, RainbowVis-JS to solve this general problem. You just have to set the number of items using setNumberRange and set the start and end colour using setSpectrum. Then you get the hex colour code with colourAt.
var numberOfItems = 8;
var rainbow = new Rainbow();
rainbow.setNumberRange(1, numberOfItems);
rainbow.setSpectrum('red', 'black');
var s = '';
for (var i = 1; i <= numberOfItems; i++) {
var hexColour = rainbow.colourAt(i);
s += '#' + hexColour + ', ';
}
document.write(s);
// gives:
// #ff0000, #db0000, #b60000, #920000, #6d0000, #490000, #240000, #000000,
You are welcome to look at the library's source code. :)
Correct function to generate array of colors!
function hex (c) {
var s = "0123456789abcdef";
var i = parseInt (c);
if (i == 0 || isNaN (c))
return "00";
i = Math.round (Math.min (Math.max (0, i), 255));
return s.charAt ((i - i % 16) / 16) + s.charAt (i % 16);
}
/* Convert an RGB triplet to a hex string */
function convertToHex (rgb) {
return hex(rgb[0]) + hex(rgb[1]) + hex(rgb[2]);
}
/* Remove '#' in color hex string */
function trim (s) { return (s.charAt(0) == '#') ? s.substring(1, 7) : s }
/* Convert a hex string to an RGB triplet */
function convertToRGB (hex) {
var color = [];
color[0] = parseInt ((trim(hex)).substring (0, 2), 16);
color[1] = parseInt ((trim(hex)).substring (2, 4), 16);
color[2] = parseInt ((trim(hex)).substring (4, 6), 16);
return color;
}
function generateColor(colorStart,colorEnd,colorCount){
// The beginning of your gradient
var start = convertToRGB (colorStart);
// The end of your gradient
var end = convertToRGB (colorEnd);
// The number of colors to compute
var len = colorCount;
//Alpha blending amount
var alpha = 0.0;
var saida = [];
for (i = 0; i < len; i++) {
var c = [];
alpha += (1.0/len);
c[0] = start[0] * alpha + (1 - alpha) * end[0];
c[1] = start[1] * alpha + (1 - alpha) * end[1];
c[2] = start[2] * alpha + (1 - alpha) * end[2];
saida.push(convertToHex (c));
}
return saida;
}
// Exemplo de como usar
var tmp = generateColor('#000000','#ff0ff0',10);
for (cor in tmp) {
$('#result_show').append("<div style='padding:8px;color:#FFF;background-color:#"+tmp[cor]+"'>COLOR "+cor+"° - #"+tmp[cor]+"</div>")
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="result_show"></div>
Yes, absolutely.
I do this in Java, should be fairly simple to do in JavaScript too.
First, you'll need to break the colors up into RGB components.
Then calculate the differences between start and finish of the components.
Finally, calculate percentage difference and multiply by the start color of each component, then add it to the start color.
Assuming you can get the RGB values, this should do it:
var diffRed = endColor.red - startColor.red;
var diffGreen = endColor.green - startColor.green;
var diffBlue = endColor.blue - startColor.blue;
diffRed = (diffRed * percentFade) + startColor.red;
diffGreen = (diffGreen * percentFade) + startColor.green;
diffBlue = (diffBlue * percentFade) + startColor.blue;
The "percentFade" is a floating decimal, signifying how far to fade into the "endColor". 1 would be a full fade (thus creating the end color). 0 would be no fade (the starting color).
I use this function based on #desau answer:
getGradientColor = function(start_color, end_color, percent) {
// strip the leading # if it's there
start_color = start_color.replace(/^\s*#|\s*$/g, '');
end_color = end_color.replace(/^\s*#|\s*$/g, '');
// convert 3 char codes --> 6, e.g. `E0F` --> `EE00FF`
if(start_color.length == 3){
start_color = start_color.replace(/(.)/g, '$1$1');
}
if(end_color.length == 3){
end_color = end_color.replace(/(.)/g, '$1$1');
}
// get colors
var start_red = parseInt(start_color.substr(0, 2), 16),
start_green = parseInt(start_color.substr(2, 2), 16),
start_blue = parseInt(start_color.substr(4, 2), 16);
var end_red = parseInt(end_color.substr(0, 2), 16),
end_green = parseInt(end_color.substr(2, 2), 16),
end_blue = parseInt(end_color.substr(4, 2), 16);
// calculate new color
var diff_red = end_red - start_red;
var diff_green = end_green - start_green;
var diff_blue = end_blue - start_blue;
diff_red = ( (diff_red * percent) + start_red ).toString(16).split('.')[0];
diff_green = ( (diff_green * percent) + start_green ).toString(16).split('.')[0];
diff_blue = ( (diff_blue * percent) + start_blue ).toString(16).split('.')[0];
// ensure 2 digits by color
if( diff_red.length == 1 ) diff_red = '0' + diff_red
if( diff_green.length == 1 ) diff_green = '0' + diff_green
if( diff_blue.length == 1 ) diff_blue = '0' + diff_blue
return '#' + diff_red + diff_green + diff_blue;
};
Example:
getGradientColor('#FF0000', '#00FF00', 0.4);
=> "#996600"
desau's answer is great. Here it is in javascript:
function hexToRgb(hex) {
var result = /^#?([a-f\d]{2})([a-f\d]{2})([a-f\d]{2})$/i.exec(hex);
return result ? {
r: parseInt(result[1], 16),
g: parseInt(result[2], 16),
b: parseInt(result[3], 16)
} : null;
}
function map(value, fromSource, toSource, fromTarget, toTarget) {
return (value - fromSource) / (toSource - fromSource) * (toTarget - fromTarget) + fromTarget;
}
function getColour(startColour, endColour, min, max, value) {
var startRGB = hexToRgb(startColour);
var endRGB = hexToRgb(endColour);
var percentFade = map(value, min, max, 0, 1);
var diffRed = endRGB.r - startRGB.r;
var diffGreen = endRGB.g - startRGB.g;
var diffBlue = endRGB.b - startRGB.b;
diffRed = (diffRed * percentFade) + startRGB.r;
diffGreen = (diffGreen * percentFade) + startRGB.g;
diffBlue = (diffBlue * percentFade) + startRGB.b;
var result = "rgb(" + Math.round(diffRed) + ", " + Math.round(diffGreen) + ", " + Math.round(diffBlue) + ")";
return result;
}
function changeBackgroundColour() {
var count = 0;
window.setInterval(function() {
count = (count + 1) % 200;
var newColour = getColour("#00FF00", "#FF0000", 0, 200, count);
document.body.style.backgroundColor = newColour;
}, 20);
}
changeBackgroundColour();
There is a JavaScript library which can create color gradients:
javascript-color-gradient
import Gradient from "javascript-color-gradient";
const colorGradient = new Gradient();
colorGradient.setGradient("#e6062d", "#408247"); // from red to green
colorGradient.setMidpoint(8); // set to 8 color steps
colorGradient.getArray(); // get all 8 colors: [ "#d11630", "#bd2534", ... ]
colorGradient.getColor(1); // #bd2534
Based on #drinor's answer - TypeScript support
const getGradientColor = (startColor: string, endColor: string, percent: number) => {
// strip the leading # if it's there
startColor = startColor.replace(/^\s*#|\s*$/g, '');
endColor = endColor.replace(/^\s*#|\s*$/g, '');
// convert 3 char codes --> 6, e.g. `E0F` --> `EE00FF`
if (startColor.length === 3) {
startColor = startColor.replace(/(.)/g, '$1$1');
}
if (endColor.length === 3) {
endColor = endColor.replace(/(.)/g, '$1$1');
}
// get colors
const startRed = parseInt(startColor.substr(0, 2), 16),
startGreen = parseInt(startColor.substr(2, 2), 16),
startBlue = parseInt(startColor.substr(4, 2), 16);
const endRed = parseInt(endColor.substr(0, 2), 16),
endGreen = parseInt(endColor.substr(2, 2), 16),
endBlue = parseInt(endColor.substr(4, 2), 16);
// calculate new color
let diffRed = endRed - startRed;
let diffGreen = endGreen - startGreen;
let diffBlue = endBlue - startBlue;
diffRed = ((diffRed * percent) + startRed);
diffGreen = ((diffGreen * percent) + startGreen);
diffBlue = ((diffBlue * percent) + startBlue);
let diffRedStr = diffRed.toString(16).split('.')[0];
let diffGreenStr = diffGreen.toString(16).split('.')[0];
let diffBlueStr = diffBlue.toString(16).split('.')[0];
// ensure 2 digits by color
if (diffRedStr.length === 1) diffRedStr = '0' + diffRedStr;
if (diffGreenStr.length === 1) diffGreenStr = '0' + diffGreenStr;
if (diffBlueStr.length === 1) diffBlueStr = '0' + diffBlueStr;
return '#' + diffRedStr + diffGreenStr + diffBlueStr;
}
example:
getGradientColor('#FF0000', '#00FF00', 0.4);
=> "#996600"
The xolor library has a gradient function. This will create an array with 8 colors in a gradient from a start color to an end color:
var gradientColors = []
var startColor = "rgb(100,200,50)", endColor = "green"
var start = xolor(startColor)
for(var n=0; n<8; n++) {
gradientColors.push(start.gradient(endColor, n/8))
}
See more on github: https://github.com/fresheneesz/xolor
chroma.js:
chroma.scale(['#fafa6e','#2A4858']).mode('lch').colors(6)
Not such mighty but in most cases working and you do not have to include any other libraries except jQuery for the following code:
HTML:
<div id="colors"></div>
JavaScript:
function rainbow(value, s, l, max, min, start, end) {
value = ((value - min) * (start - end) / max)+end;
return 'hsl(' + value + ','+s+'%,'+l+'%)';
}
function createRainbowDiv(start,end){
var gradient = $("<div>").css({display:"flex", "flex-direction":"row",height:"100%"});
for (var i = start; ((i <= end) && (i >= start)) || ((i >= end) && (i <= start));
i += (end-start) / Math.abs(end-start)){
gradient.append($("<div>").css({float:"left","background-color":rainbow(i, 100,50, Math.max(start,end), Math.min(start,end), start,end),flex:1}));
}
return gradient;
}
$("#colors").append(createRainbowDiv(0,150));
$("#colors").css("width","100%").css("height","10px");
This should make an div that contains a rainbow. See http://jsfiddle.net/rootandy/54rV7/
I needed to create a large enough array of color options for an unknown set of dynamic elements, but I needed each element to increment their way through a beginning color and an ending color. This sort of follows the "percent fade" approach except I had a difficult time following that logic. This is how I approached it using inputs of two rgb color values and calculating the number of elements on the page.
Here is a link to a codepen that demonstrates the concept.
Below is a code snippet of the problem.
<style>
#test {
width:200px;
height:100px;
border:solid 1px #000;
}
.test {
width:49%;
height:100px;
border:solid 1px #000;
display: inline-block;
}
</style>
</head>
<body>
<div id="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<div class="test"></div>
<script>
var GColor = function(r,g,b) {
r = (typeof r === 'undefined')?0:r;
g = (typeof g === 'undefined')?0:g;
b = (typeof b === 'undefined')?0:b;
return {r:r, g:g, b:b};
};
// increases each channel by the difference of the two
// divided by 255 (the number of colors stored in the range array)
// but only stores a whole number
// This should respect any rgb combinations
// for start and end colors
var createColorRange = function(c1) {
var colorList = [], tmpColor, rr = 0, gg = 0, bb = 0;
for (var i=0; i<255; i++) {
tmpColor = new GColor();
if (rExp >= 0) {
tmpColor.r = Math.floor(c1.r - rr);
rr += rAdditive;
} else {
tmpColor.r = Math.floor(c1.r + rr);
rr += rAdditive;
}
if (gExp >= 0) {
tmpColor.g = Math.floor(c1.g - gg);
gg += gAdditive;
} else {
tmpColor.g = Math.floor(c1.g + gg);
gg += gAdditive;
}
if (bExp >= 0) {
tmpColor.b = Math.floor(c1.b - bb);
bb += bAdditive;
} else {
tmpColor.b = Math.floor(c1.b + bb);
bb += bAdditive;
}
console.log(tmpColor);
colorList.push(tmpColor);
}
return colorList;
};
/* ==================
Testing Code Below
================== */
var firstColor = new GColor(255, 24, 0);
var secondColor = new GColor(255, 182, 0);
// Determine the difference
var rExp = firstColor.r - secondColor.r;
// Divide that difference by length of the array
// you would like to create (255 in this case)
var rAdditive = Math.abs(rExp)/255;
var gExp = firstColor.g - secondColor.g;
var gAdditive = Math.abs(gExp)/255;
var bExp = firstColor.b - secondColor.b;
var bAdditive = Math.abs(bExp)/255;
var range = createColorRange(firstColor, secondColor);
console.log(range);
var pointer = 0;
// This gently cycles through
// all the colors on a single element
function rotateColors() {
var currentColor = range[pointer];
document.getElementById("test").style.backgroundColor = "rgb("+currentColor.r+","+currentColor.g+","+currentColor.b+")";
pointer++;
if (pointer < range.length) window.setTimeout(rotateColors, 5);
}
rotateColors();
// say I have 5 elements
// so I need 5 colors
// I already have my first and last colors
// but I need to locate the colors between
// my start color and my end color
// inside of this range
// so I divide the range's length by the
// number of colors I need
// and I store the index values of the middle values
// those index numbers will then act as my keys to retrieve those values
// and apply them to my element
var myColors = {};
var objects = document.querySelectorAll('.test');
myColors.num = objects.length;
var determineColors = function(numOfColors, colorArray) {
var colors = numOfColors;
var cRange = colorArray;
var distance = Math.floor(cRange.length/colors);
var object = document.querySelectorAll('.test');
var j = 0;
for (var i = 0; i < 255; i += distance) {
if ( (i === (distance*colors)) ) {
object[j].style.backgroundColor = "rgb(" + range[255].r + ", " + range[255].g + ", " + range[255].b + ")";
j = 0;
// console.log(range[i]);
} else {
// Apply to color to the element
object[j].style.backgroundColor = "rgb(" + range[i].r + ", " + range[i].g + ", " + range[i].b + ")";
// Have each element bleed into the next with a gradient
// object[j].style.background = "linear-gradient( 90deg, rgb(" + range[i].r + ", " + range[i].g + ", " + range[i].b + "), rgb(" + range[i+distance].r + ", " + range[i+distance].g + ", " + range[i+distance].b + "))";
j++;
}
}
};
setTimeout( determineColors(myColors.num, range), 2000);
</script>
</body>
You can retrieve the list of elements. I'm not familiar with jQuery, but prototypejs has Element.childElements() which will return an array. Once you know the length of the array, you can determine how much to change the pixel components for each step. Some of the following code I haven't tested out in the form I'm presenting it in, but it should hopefully give you an idea.
function hex (c) {
var s = "0123456789abcdef";
var i = parseInt (c);
if (i == 0 || isNaN (c))
return "00";
i = Math.round (Math.min (Math.max (0, i), 255));
return s.charAt ((i - i % 16) / 16) + s.charAt (i % 16);
}
/* Convert an RGB triplet to a hex string */
function convertToHex (rgb) {
return hex(rgb[0]) + hex(rgb[1]) + hex(rgb[2]);
}
/* Remove '#' in color hex string */
function trim (s) { return (s.charAt(0) == '#') ? s.substring(1, 7) : s }
/* Convert a hex string to an RGB triplet */
function convertToRGB (hex) {
var color[];
color[0] = parseInt ((trim(hex)).substring (0, 2), 16);
color[1] = parseInt ((trim(hex)).substring (2, 4), 16);
color[2] = parseInt ((trim(hex)).substring (4, 6), 16);
}
/* The start of your code. */
var start = convertToRGB ('#000000'); /* The beginning of your gradient */
var end = convertToRGB ('#ffffff'); /* The end of your gradient */
var arr = $('.gradientList').childElements();
var len = arr.length(); /* The number of colors to compute */
var alpha = 0.5; /* Alpha blending amount */
for (i = 0; i < len; i++) {
var c = [];
c[0] = start[0] * alpha + (1 - alpha) * end[0];
c[1] = start[1] * alpha + (1 - alpha) * end[1];
c[2] = start[2] * alpha + (1 - alpha) * end[2];
/* Set the background color of this element */
arr[i].setStyle ({ 'background-color': convertToHex (c) });
}
Basic Javascript - Background Gradient
Here's a ready-made function to set an elements background to be a gradient
Using CSS
Element.prototype.setGradient = function( from, to, vertical ){
this.style.background = 'linear-gradient(to '+(vertical ? 'top' : 'left')+', '+from+', '+to+' 100%)';
}
And Usage :
document.querySelector('.mydiv').setGradient('red','green');
This was tested working with chrome, I'll try to update for other browsers
Using Canvas
The most basic horizontal would be :
Element.prototype.setGradient = function( fromColor, toColor ){
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
var b = this.getBoundingClientRect();
var grd = ctx.createLinearGradient(0, 0, b.width, 0);
canvas.width = b.width;
canvas.height = b.height;
grd.addColorStop(0, fromColor);
grd.addColorStop(1, toColor);
ctx.fillStyle = grd;
ctx.fillRect(0, 0, b.width, b.height);
this.style.backgroundImage = 'url('+canvas.toDataURL()+')';
}
And Usage :
document.querySelector('.mydiv').setGradient('red','green');
A Fiddle :
https://jsfiddle.net/jch39bey/
-
Adding Vertical Gradient
A simple flag to set vertical
Element.prototype.setGradient = function( fromColor, toColor, vertical ){
var canvas = document.createElement('canvas');
var ctx = canvas.getContext('2d');
var b = this.getBoundingClientRect();
var grd = ctx.createLinearGradient(0, 0, vertical ? 0 : b.width, vertical ? b.height : 0);
canvas.width = b.width;
canvas.height = b.height;
grd.addColorStop(0, fromColor);
grd.addColorStop(1, toColor);
ctx.fillStyle = grd;
ctx.fillRect(0, 0, b.width, b.height);
this.style.backgroundImage = 'url('+canvas.toDataURL()+')';
}
And Usage :
document.querySelector('.mydiv').setGradient('red','green',true);
Based on #desau's answer and some code from elsewhere, here's a jQuery step-by-step walkthrough:
function coloursBetween(fromColour, toColour, numberOfColours){
var colours = []; //holds output
var fromSplit = getRGBAValues(hexToRGBA(fromColour, 1.0)); //get raw values from hex
var toSplit = getRGBAValues(hexToRGBA(toColour, 1.0));
var fromRed = fromSplit[0]; //the red value as integer
var fromGreen = fromSplit[1];
var fromBlue = fromSplit[2];
var toRed = toSplit[0];
var toGreen = toSplit[1];
var toBlue = toSplit[2];
var difRed = toRed - fromRed; //difference between the two
var difGreen = toGreen - fromGreen;
var difBlue = toBlue - fromBlue;
var incrementPercentage = 1 / (numberOfColours-1); //how much to increment percentage by
for (var n = 0; n < numberOfColours; n++){
var percentage = n * incrementPercentage; //calculate percentage
var red = (difRed * percentage + fromRed).toFixed(0); //round em for legibility
var green = (difGreen * percentage + fromGreen).toFixed(0);
var blue = (difBlue * percentage + fromBlue).toFixed(0);
var colour = 'rgba(' + red + ',' + green + ',' + blue + ',1)'; //create string literal
colours.push(colour); //push home
}
return colours;
}
function getRGBAValues(string) {
var cleaned = string.substring(string.indexOf('(') +1, string.length-1);
var split = cleaned.split(",");
var intValues = [];
for(var index in split){
intValues.push(parseInt(split[index]));
}
return intValues;
}
function hexToRGBA(hex, alpha){
var c;
if(/^#([A-Fa-f0-9]{3}){1,2}$/.test(hex)){
c= hex.substring(1).split('');
if(c.length== 3){
c= [c[0], c[0], c[1], c[1], c[2], c[2]];
}
c= '0x'+c.join('');
return 'rgba('+[(c>>16)&255, (c>>8)&255, c&255].join(',')+','+alpha+')';
}
return rgba(0,0,0,1);
//throw new Error('Bad Hex');
}
There are three functions:
coloursBetween(fromColour, toColour, numberOfColours)
getRGBAValues(string)
hexToRGBA(hex, alpha)
Call the main function coloursBetween() passing in the starting colour and the ending colour, as well as the total number of colours you want to have returned. So if you request ten colours returned, you get the first from colour + 8 gradient colours + the final to colour.
The coloursBetween function starts by converting the incoming hex colours (e.g. #FFFFFF, #000000) into rgba (e.g. rgba(255,255,255,1) rgba(0,0,0,1)) and then subtracting the Red, Green and Blue values from each.
The difference between the Reds, Greens and Blues is then calculated. In this example it's -255 in each case. An increment is calculated and used to multiply new incremental values for the Red, Green and Blue. Alpha is always assumed to be one (full opacity). The new value is then added to the colours array and after the for loop has completed, it's returned.
Finally, call like this (going from Red to Blue):
var gradientColours = coloursBetween("#FF0000", "#0000FF", 5);
which you can use to for something like this:
Here's a script that does just what you're asking for:
https://gist.github.com/av01d/538b3fffc78fdc273894d173a83c563f
Very easy to use:
let colors;
colors = ColorSteps.getColorSteps('#000', 'rgba(255,0,0,0.1)', 10);
colors = ColorSteps.getColorSteps('red', 'blue', 5);
colors = ColorSteps.getColorSteps('hsl(180, 50%, 50%)', 'rgba(200,100,20,0.5)', 10);