What do I add at the beginning and end of a section of code to repeat it 36 times before going on?
You use a for loop:
for ( var i = 0; i < 36; i++ ) {
// This will loop 36 times
}
You add a for loop:
for (var i = 0; i < 36; i++) {
}
You are looking for a for loop: https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Statements/for
Related
I am trying to add tick marks for dial on qml. I made the calculations and created the tick marks manually but want them to appear automatically based on the step size of the dial. My idea is to use a for loop but I don't know how to call the javascript in qml. Is the for loop the way to go and how does the code look like? Or do you have a better, more qml-like solution?
for i = (0,n):
gamma = alpha+i*delta
mix = sin (gamma) * (a+r+l/2)
miy = cos (gamma) * (a+r+l/2)
create tick mark i with mix, miy, gamma, l
end for
This is the logic that I want to put in the loop.
You should write your for loop inside a function like below:
function doing_in_loop() {
for (var i = 0; i < 9; i++) {
console.log(i)
}
}
or do in on a signal:
Component.onCompleted: {
for (var i = 0; i < 9; i++) {
console.log(i)
}
}
I think you can just do it like this:
for (var i = 0; i < 10; i++) {
}
I want to create a loop where the "i" variable is incrementing by one (i++), and I want to add another variable "j" in the loop that increment not by one but 3 per 3 (so j+=3, and then the output looks like 0, 3, 6, 9, 12...).
I have tried so many thing, but here is my code that looks logic :
let j;
for (let i = 0; i < 24; i++) {
j = i += 3;
console.log(j); //It increments by 4, WTF ??
console.log(i); //Exactly the same whereas i should increments per 1
}
I also tried to create a variable "k" that is equal to "i" to leave "i" alone, but still doesn't work.
Thank you so much for your help guys :)
PS : Once solved, do you know how to make the variable j starts by 0 please ?
let j=0;
for (let i = 0; i < 24; i++) {
j+=3
console.log(j); //starts at 3, because in the first line of the function we say j = 0 + 3, so j=3, then once it loops again it gets +3 again, so it's 6 and so on.
console.log(i); //just increments by 1 each loop
Try this, is this what you were trying to achieve?
Like this - you can use comma separators in the initiator and loop statements in the for statement
for (let i = 0, j = 1; i < 24; i++, j += 3) {
console.log("i",i,"j",j);
}
I have an array soter and a counter array. I want to get the the number of name which the count array will provide me. Is it correct ? I am a bit confused about the output. Can someone enligten me on this nested array loop in JavaScript ?
var soter = ['bp','mf','cc'],
count = [0,0,0];
for(var y = 0 ; y < soter.length; y++) {
for(var i = 0 ;i < data.SO_Ter.length; i++) {
if(data.SO_Ter[i].name == soter[y]) {
count[y]++;
That code seems correct to me, supposing the well formed object data and child SO_Ter .
So you go through the outer loop, positions 0 to 2, and for each one of them you will check that each of the items in data.SO_Ter is equal to the soter value.
If you find that value, you increment the count in 1.
Does it make sense?
To make it easier, it would be like:
for(var i = 0 ;i < data.SO_Ter.length; i++) {
if(data.SO_Ter[i].name == soter[0]) {
count[0]++;
for(var i = 0 ;i < data.SO_Ter.length; i++) {
if(data.SO_Ter[i].name == soter[1]) {
count[1]++;
for(var i = 0 ;i < data.SO_Ter.length; i++) {
if(data.SO_Ter[i].name == soter[2]) {
count[2]++;
So since you do it 3 times, you just replace those with an outer for loop.
UPDATE
count[0] represents how many times the word 'bp' has been found
count[1] represents how many times the word 'mf' has been found
count[2] represents how many times the word 'cc' has been found
I am doing a loop, and through each loop I would like to add a 0 to the child loop's max range.
Example:
for(var i=0;i<10;i++)
for(var n=0;n< [?] ;n++)
The child loop should be looping from 0 to 1,10,100,1000 and so on each time around it should add a 0 to the max range.
Maybe I'm just bad at math idk but how would I do this? Thanks.
Use the power of Math.pow:
for(var i = 0; i < 10; i++)
for(var n = 0; n < Math.pow(10, i); n++)
you can do something like this :
for(var i=0;i<10;i++)
for(var n=0;n<Math.pow(10,i);n++)
This is my code, but it does not work.
for (i = 0; i < 5; i++) {
$(function(){
$('.tt'+ [i]).appendTo('.td'+ [i]);
});
}
I want the result:
$('.tt1').appendTo('.td1')
$('.tt2').appendTo('.td2')
$('.tt3').appendTo('.td3')
$('.tt4').appendTo('.td4')
$('.tt5').appendTo('.td5')
Please correct me, thanks you in advance!
You have some syntax errors, try this:
for (var i = 0; i <= 5; i++) {
$('.tt'+ i).appendTo('.td'+ i);
}
As already mentioned: remove the array initialization.
If you want to iterate from 1 to 5 then do so (not var = 0, but var i = 1):
for (var i = 1; i < 6; i++) {
$('.tt'+ i).appendTo('.td'+ i);
}
Also I don't see any sense in wrapping it the appendTo call.
The 1st Thing
You will never jump into the i=5 iteration
$('.tt5').appendTo('.td5')
because your for loop
for (i = 0; i < 5; i++)
ends at i = 5
Change it to
for (i = 1; i <= 5; i++)
It starts at i=1 because your example didn't show a ".tt0"
The 2nd thing
Remote the brackets!
Change
$('.tt'+ [i]).appendTo('.td'+ [i]);
to
$('.tt'+ i).appendTo('.td'+ i);
Otherwise you will create an Array and the JS interpreter performs an unnecessary Array.toString() operation.
The 3rd thing
I think you can remove the surrounding function inside the for loop
$(function(){
...
}
Just use:
for (var i = 1; i <= 5; i++) {
$('.tt'+ i).appendTo('.td'+ i);
}
See Fiddle
http://jsfiddle.net/Spaghettirocker/knkpaczg/1/