I have a string in JavaScript (e.g., #box2), and I just want the 2 from it.
I tried:
var thestring = $(this).attr('href');
var thenum = thestring.replace(/(^.+)(\w\d+\w)(.+$)/i, '$2');
alert(thenum);
It still returns #box2 in the alert. How can I get it to work?
It needs to accommodate for any length number attached on the end.
For this specific example,
var thenum = thestring.replace(/^\D+/g, ''); // Replace all leading non-digits with nothing
In the general case:
thenum = "foo3bar5".match(/\d+/)[0] // "3"
Here's a bonus: regex generator.
function getre(str, num) {
if(str === num)
return 'nice try';
var res = [/^\D+/g,/\D+$/g,/^\D+|\D+$/g,/\D+/g,/\D.*/g, /.*\D/g,/^\D+|\D.*$/g,/.*\D(?=\d)|\D+$/g];
for(var i = 0; i < res.length; i++)
if(str.replace(res[i], '') === num)
return 'num = str.replace(/' + res[i].source + '/g, "")';
return 'no idea';
};
function update() {
$ = function(x) { return document.getElementById(x) };
var re = getre($('str').value, $('num').value);
$('re').innerHTML = 'Numex speaks: <code>' + re + '</code>';
}
<p>Hi, I'm Numex, the Number Extractor Oracle.
<p>What is your string? <input id="str" value="42abc"></p>
<p>What number do you want to extract? <input id="num" value="42"></p>
<p><button onclick="update()">Insert Coin</button></p>
<p id="re"></p>
You should try the following:
var txt = "#div-name-1234-characteristic:561613213213";
var numb = txt.match(/\d/g);
numb = numb.join("");
alert (numb);
Result
1234561613213213
I think this regular expression will serve your purpose:
var num = txt.replace(/[^0-9]/g, '');
Where txt is your string.
It basically rips off anything that is not a digit.
I think you can achieve the same thing by using this as well:
var num = txt.replace(/\D/g, '');
Try the following: string.replace(/[^0-9]/g, ''); This will delete all non-digit characters, leaving only digits in the string
function retnum(str) {
var num = str.replace(/[^0-9]/g, '');
return parseInt(num,10);
}
console.log('abca12bc45qw'.replace(/[^0-9]/g, ''));
console.log('#box2'.replace(/[^0-9]/g, ''));
Using the match function.
var thenum = "0a1bbb2".match(/\d+$/)[0];
console.log(thenum);
And this is a snippet which extracts prices with currency and formatting:
var price = "£1,739.12";
parseFloat(price.replace(/[^\d\.]*/g, '')); // 1739.12
I tried all the combinations cited in the previous answer with this code and got it working. It was the only one that worked on that string → (12) 3456-7890
var str = "(12) 3456-7890";
str.replace(/\D+/g, '');
Result: "1234567890"
Obs: I know that a string like that will not be on the attribute, but whatever, the solution is better, because it’s more complete.
You may use the great parseInt() method.
It will convert the leading digits to a number:
parseInt("-10px");
// Will give you -10
You can extract numbers from a string using a regex expression:
let string = "xxfdx25y93.34xxd73";
let res = string.replace(/\D/g, "");
console.log(res);
Output: 25933473
Wrap it into a vanilla JavaScript function:
function onlyNumbers(text){
return text.replace(/\D/g, "");
}
For a string such as #box2, this should work:
var thenum = thestring.replace(/^.*?(\d+).*/,'$1');
jsFiddle:
http://jsfiddle.net/dmeku/
function justNumbers(string)
{
var numsStr = string.replace(/[^0-9]/g, '');
return parseInt(numsStr);
}
console.log(justNumbers('abcdefg12hijklmnop'));
You can do a function like this
function justNumbers(string)
{
var numsStr = string.replace(/[^0-9]/g, '');
return parseInt(numsStr);
}
Remember: if the number has a zero in front of it, the int won’t have it
If you want to parse a number from a price like $6,694.20, it can be done this way:
parseFloat('$6,694.20'.replace(/^\D|,+/g, ''))
Or via a function:
function parsePrice(value) {
return parseFloat(value.replace(/^\D|,+/g, ''))
}
parsePrice('$6,694.20') // 6694.2
To return an int from the string, you can do the following code. It removes all not number characters and returns an integer.
Number("strin[g]3".replace(/\D+/g, ""))
You can use a regular expression.
var txt="some text 2";
var numb = txt.match(/\d/g);
alert (numb);
That will alert 2.
let str = "Total Work Duration: 189.56 Hrs.Present: 23.5 Absent: 2";
/* The provided regex globally matches the character
"." and a digit from the string */
let numArr = str.match(/[\d\.]+/g)
/* It returns an array [189.56, ., 23.5, 2], and
uses the filter function to remove the '.' */
numArr = numArr.filter(n => n != '.')
console.log(numArr)
If someone need to preserve dots in extracted numbers:
var some = '65,87 EUR';
var number = some.replace(",",".").replace(/[^0-9&.]/g,'');
console.log(number); // returns 65.87
You can use Underscore.js' string library as follows:
var common = "#box"
var href = "#box1"
_(href).strRight(common)
The result will be: 1
See: Underscore.string
Demo:
http://jsfiddle.net/abdennour/Vyqtt/
HTML code:
<p>
<a href="#box1" >img1</a>
<a href="#box2" >img2</a>
<a href="#box3" >img3</a>
<a href="#box4" >img4</a>
</p>
<div style="font-size:30px"></div>
JavaScript code:
var comm = "#box"
$('a').click(function() {
$('div').html(_($(this).attr('href')).strRight(comm))})
If you have a suffix as follows:
href="box1az"
You can use the following demo:
http://jsfiddle.net/abdennour/Vyqtt/1/
function retrieveNumber(all, prefix, suffix) {
var left = _(all).strRight(prefix);
return _(left).strLeft(suffix);
}
Here's a solution that checks for no data:
var someStr = 'abc'; // Add 123 to string to see the inverse
var thenum = someStr.match(/\d+/);
if (thenum != null)
{
console.log(thenum[0]);
}
else
{
console.log('Not a number');
}
var elValue = "-12,erer3 4,-990.234sdsd";
var isNegetive = false;
if(elValue.indexOf("-") == 0)
isNegetive = true;
elValue = elValue.replace( /[^\d\.]*/g, '');
elValue = isNaN(Number(elValue)) ? 0 : Number(elValue);
if(isNegetive)
elValue = 0 - elValue;
alert(elValue); // -1234990.234
With regular expressions, how to get numbers from a string, for example:
String myString = "my 2 first gifts were made by my 4 brothers";
myString = myString.replaceAll("\\D+", "");
System.out.println("myString: " + myString);
The result of myString is "24".
You can see an example of this running code at http://ideone.com/iOCf5G.
Use this one-line code to get the first number in a string without getting errors:
var myInt = parseInt(myString.replace(/^[^0-9]+/, ''), 10);
Please check the below JavaScript code. There you can get only a number.
var txt = "abc1234char5678#!9";
var str = txt.match(/\d+/g, "") + '';
var s = str.split(',').join('');
alert(Number(s));
Output: 1234567789
You need to add "(/\d+/g)" which will remove all non-number text, but it will still be a string at this point. If you create a variable and "parseInt" through the match, you can set the new variables to the array values. Here is an example of how I got it to work:
var color = $( this ).css( "background-color" );
var r = parseInt(color.match(/\d+/g)[0]);
var g = parseInt(color.match(/\d+/g)[1]);
var b = parseInt(color.match(/\d+/g)[2]);
This answer will cover most of the scenarios. I came across this situation when a user tried to copy paste the phone number.
$('#help_number').keyup(function() {
$(this).val().match(/\d+/g).join("")
});
Explanation:
str = "34%^gd 5-67 6-6ds"
str.match(/\d+/g)
It will give an array of strings as output:
["34", "56766"]
str.match(/\d+/g).join("")
join() will convert and concatenate that array data into a single string.
Output:
"3456766"
In my example, I needed the output as 209-356-6788, so I used replace():
$('#help_number').keyup(function() {
$(this).val($(this).val().match(/\d+/g).join("").replace(/(\d{3})\-?(\d{3})\-?(\d{4})/, '$1-$2-$3'))
});
Written without a regular expression:
// Without Regex
function extractNumber(string) {
let numArray = string.split('').map(item => {
if (typeof +item === 'number' && !isNaN(+item))
return +item
})
return +numArray.join('')
}
extractNumber('#1200milion$') // 1200
In one of my projects I had to take a rating value from a string. This is what I used:
let text = '#xbox2'
let num = text.trim().
split('').
map(num => Number(num)).
filter(x => Number.isInteger(x))
Use:
changeStrangeDate(dateString: string) {
var sum = 0;
var numbers = dateString.match(/\d+/g);
if (numbers.length > 1) {
numbers.forEach(element => {
sum += parseInt(element);
}
);
}
console.log(new Date(sum).toDateString());
return new Date(sum).toUTCString();
}
You can do it like that and then call a function where you need it, with a parameter.
this.changeStrangeDate('/Date(1551401820000-0100)/');
I have a string in JavaScript like this:
var str = "1:A;2:B;3:A;4:c;5:D";
How to retreive option in front of 2, that is B.
Presently am getting this using for loop by splitting the string every ;,
but I want to know if there is any better way to achieve this without using looping concept.
You can use the split function, as below;
var str = "1:A;2:B;3:A;4:c;5:D";
var result = str.split(":");
document.getElementById("Location").innerHTML = res[2];
If you know that this will be a pattern you can use something like:
var str = "1:A;2:B;3:A;4:c;5:D";
var i = 2;
console.log(str[str.indexOf(i)+2]);
//Output "B"
If you wanted to get the option in front of 2 you could use either:
a loop (preferred in my option)
indexOf
Javascript:
function getAnswer(str) {
var position = str.indexOf(';2:')
// not found in string, or '2' is the first answer
if(position === -1) {
return;
}
return str.substring(position - 1, position)
}
Might be recursive approach help you.
var str = "1:A;2:B;3:A;4:c;5:D",
arr = str.split(";"),
len = arr.length;
function getVal(len){
if(len !== 0){
getVal(len-1);
if(arr[len-1].indexOf(2) === 0){
console.log(arr[len-1].split(":")[1])
};
};
};
getVal(len);
RegExp
var num = '2';
"1:A;2:B;3:A;4:c;5:D".match((new RegExp(num+"\\:([\\S\\s]+?)\\;", "")))[1];
Fiddle
This uses RegExp (Regular Expressions) What this does is it will look for a '2' in the string, then get the option associated with it
Substring
I couldn't think of a better word so forgive me. You can use substring and .indexOf()
var num = '2',
string = "1:A;2:B;3:A;4:c;5:D",
index = string.indexOf(num+':');
string.substring(index+num.length+1,index+num.length+2);
Fiddle
Similar
The substring answer is a little easier to understand but the following does the sameish
var num = '2',
string = "1:A;2:B;3:A;4:c;5:D";
string[string.indexOf(num+':')+num.length+1];
Fiddle
Foolproof
This should work in most situations. This will also get the option if it is more than one letter long
var string = "1:A;2:B;3:A;4:c;5:D",
num = '2',
result;
if (string.indexOf(';'+num+':') < 0) {
result = string.match(new RegExp(num+"\\:([\\S\\s]+?)\\;", ""))[1];
} else {
result = string.match((new RegExp('\\;'+num+"\\:([\\S\\s]+?)\\;", "")))[1];
}
Shorter:
var string = "1:A;2:B;3:A;4:c;5:D", num = '2', result = string.indexOf(";"+num+":") < 0? string.match(new RegExp(num+"\\:([\\S\\s]+?)\\;",""))[1] : string.match(new RegExp("\\;"+num+"\\:([\\S\\s]+?)\\;",""))[1];
alert(result);
Fiddle (I have made it a one-liner)
i have comma separated string like
var test = 1,3,4,5,6,
i want to remove particular character from this string using java script
can anyone suggests me?
JavaScript strings provide you with replace method which takes as a parameter a string of which the first instance is replaced or a RegEx, which if being global, replaces all instances.
Example:
var str = 'aba';
str.replace('a', ''); // results in 'ba'
str.replace(/a/g, ''); // results in 'b'
If you alert str - you will get back the same original string cause strings are immutable.
You will need to assign it back to the string :
str = str.replace('a', '');
Use replace and if you want to remove multiple occurrence of the character use
replace like this
var test = "1,3,4,5,6,";
var newTest = test.replace(/,/g, '-');
here newTest will became "1-3-4-5-6-"
you can make use of JavaScript replace() Method
var str="Visit Microsoft!";
var n=str.replace("Microsoft","My Blog");
var test = '1,3,4,5,6';
//to remove character
document.write(test.replace(/,/g, ''));
//to remove number
function removeNum(string, val){
var arr = string.split(',');
for(var i in arr){
if(arr[i] == val){
arr.splice(i, 1);
i--;
}
}
return arr.join(',');
}
var str = removeNum(test,3);
document.write(str); // output 1,4,5,6
You can also
var test1 = test.split(',');
delete test1[2];
var test2 = test1.toString();
Have fun :)
you can split the string by comma into an array and then remove the particular element [character or number or even string] from that array. once the element(s) removed, you can join the elements in the array into a string again
// Array Remove - By John Resig (MIT Licensed)
Array.prototype.remove = function(from, to) {
var rest = this.slice((to || from) + 1 || this.length);
this.length = from < 0 ? this.length + from : from;
return this.push.apply(this, rest);
};
You can use this function
function removeComma(inputNumber,char='') {
return inputNumber.replace(/,/g, char);
}
Update
function removeComma(inputNumber) {
inputNumber = inputNumber.toString();
return Number(inputNumber.replace(/,/g, ''));
}
I have a string that and I am trying to extract the characters before the quote.
Example is extract the 14 from 14' - €14.99
I am using the follwing code to acheive this.
$menuItem.text().match(/[^']*/)[0]
My problem is that if the string is something like €0.88 I wish to get an empty string returned. However I get back the full string of €0.88.
What I am I doing wrong with the match?
This is the what you should use to split:
string.slice(0, string.indexOf("'"));
And then to handle your non existant value edge case:
function split(str) {
var i = str.indexOf("'");
if(i > 0)
return str.slice(0, i);
else
return "";
}
Demo on JsFiddle
Nobody seems to have presented what seems to me as the safest and most obvious option that covers each of the cases the OP asked about so I thought I'd offer this:
function getCharsBefore(str, chr) {
var index = str.indexOf(chr);
if (index != -1) {
return(str.substring(0, index));
}
return("");
}
try this
str.substring(0,str.indexOf("'"));
Here is an underscore mixin in coffescript
_.mixin
substrBefore : ->
[char, str] = arguments
return "" unless char?
fn = (s)-> s.substr(0,s.indexOf(char)+1)
return fn(str) if str?
fn
or if you prefer raw javascript : http://jsfiddle.net/snrobot/XsuQd/
You can use this to build a partial like:
var beforeQuote = _.substrBefore("'");
var hasQuote = beforeQuote("14' - €0.88"); // hasQuote = "14'"
var noQoute = beforeQuote("14 €0.88"); // noQuote = ""
Or just call it directly with your string
var beforeQuote = _.substrBefore("'", "14' - €0.88"); // beforeQuote = "14'"
I purposely chose to leave the search character in the results to match its complement mixin substrAfter (here is a demo: http://jsfiddle.net/snrobot/SEAZr/ ). The later mixin was written as a utility to parse url queries. In some cases I am just using location.search which returns a string with the leading ?.
I use "split":
let string = "one-two-three";
let um = string.split('-')[0];
let dois = string.split('-')[1];
let tres = string.split('-')[2];
document.write(tres) //three
I need to extract a single variable number from a string. The string always looks like this:
javascript:change(5);
with the variable being 5.
How can I isolate it? Many thanks in advance.
Here is one way, assuming the number is always surrounded by parentheses:
var str = 'javascript:change(5);';
var lastBit = str.split('(')[1];
var num = lastBit.split(')')[0];
Use regular expressions:-
var test = "javascript:change(5);"
var number = new RegExp("\\d+", "g")
var match = test.match(number);
alert(match);
A simple RegExp can solve this one:
var inputString = 'javascript:change(5);';
var results = /javascript:change\((\d+)\)/.exec(inputString);
if (results)
{
alert(results[1]); // 5
}
Using the javascript:change part in the match as well ensures that if the string isn't in the proper format, you wont get a value from the matches.
var str = 'javascript:change(5);', result = str.match(/\((\d+)\)/);
if ( result ) {
alert( result[1] )
}