Does using rounded numbers decrease CPU usage in Javascript? - javascript

I'm performing a lot of calculations in javascript. I was wondering if using rounded numbers would decrease CPU usage? When I look at the inner workings of my code using console.log, the numbers have upwards of 15 decimal places.

Sometimes highly optimized engines can tell the difference between an integer and a double. For instance 1+1 might use integer math where 1.0+1 might not. Most likely this "integerness" will quickly get lost, functions like Math.pow, Math.sqrt, etc. will likely lose the property. However I would not rely on this behavior and even rounded number might not have this effect (i.e. they might still be floats after rounding).
Also, as an aside, there's probably so much overhead in the JS engine that the difference between using a float and an integer would not be that big (given that the difference is maybe a factor of 2-3 on the processor itself and the overhead is probably at least a factor of 10).

No. JavaScript does not distinguish between integers and real numbers. It only has double-precision floats.
This means that accuracy will be best with integers or binary fractions (within the range of about 15 significant digits), but actual performance won't vary much, if at all.

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Working with accurate currency values in Javascript

I'm working on a system that uses financial data. I'm getting subtle rounding errors due to the use of floating point numbers. I'm wondering if there's a better way to deal with this.
One of the issues is that I'm working with a mixture of different currencies, which might have up to 12 decimals, and large numbers for other currencies.
This means that the smallest number I need to represent is 0.000000000001 * (1*10^-12) and the largest 100,000,000,000 (1*10^11).
Are there any recommended ways to work with numbers of this size and not lose precision?
If you're really trying to stay in the JS realm you might consider Decimal.js which should cover your precision range.
If I were writing this and needed to make sure there were no rounding errors I would likely try and use a GMP extension for another lang inside a microservice which was only tasked with the financial math. GMPY2 for Python3 is probably a good bet for something quick and easy.

How to implement parseFloat

Wondering how a low-level implementation of parseFloat such as how it works in JavaScript would be implemented.
All the examples I've seen of typecasting resort to using it at some point, such as this, this, or this. On the other hand, there is this file which is quite large (from here).
Wondering if it is just a very complicated function or there is a straightforward implementation. Wondering just generally how it works if it is too complicated.
Perhaps this is closer to it.
The essential mathematics of parseFloat is very simple, requiring no more than elementary-school arithmetic. If we have a decimal numeral, we can easily convert it to binary by:
Divide the integer part by two. The remainder (zero or one) becomes a bit in a binary numeral we are building. The quotient replaces the integer part, and we repeat until the integer part is zero. For example, starting with 13, we divide to get a quotient of 6 and a remainder of 1. Then we divide 6 to get a quotient of 3 and a remainder of 0. Then 1 and 1, then 0 and 1, and we are done. The bits we produced, in reverse order, were 1101, and that is the binary numeral for 13.
Multiply the sub-integer part by two. The integer part becomes another bit in the binary numeral. Repeat with the sub-integer part until it is zero or we have enough bits to determine the result. For example, with .1875, we multiply by two to get .375, which has an integer part of 0. Doubling again produces .75, which again has an integer part of 0. Next we get 1.5, which has an integer part of 1. Now when the sub-integer part, .5, is doubled, we get 1 with a sub-integer part of 0. The new bits are .0011.
To determine a floating-point number, we need as many bits as fit in the significand (starting with the leading 1 bit from the binary numeral), and, for rounding purposes, we need to know the next bit and whether any bits after that are non-zero. (The information about the extra bits tells us whether the difference between the source value and the bits that fit in the significand is zero, not zero but less than 1/2 of the lowest bit that fits, exactly 1/2 of the lowest bit, or more than 1/2 of the lowest bit. This information is enough to decide whether to round up or down in any of the usual rounding modes.)
The information above tells you when to stop multiplying in the second part of the algorithm. As soon as you have all the significand bits, plus one more, plus you have either one non-zero bit or the sub-integer part is zero, you have all the information you need and can stop.
Then you construct a floating-point value by rounding the bits according to whatever rounding rule you are using (often round-to-nearest-ties-to-even), putting the bits into the significand of a floating-point object, and setting the exponent to record the position of the leading bit of the binary numeral.
There are some embellishments for checking for overflow or underflow or handling subnormal values. However, the basic arithmetic is simply elementary-school arithmetic.
Problems arise because the above uses arbitrary-size arrays and because it does not support scientific notation where an “e” is used to introduce a decimal exponent, as in “2.79e34”. The above algorithm requires that we maintain all the space needed to multiply and divide decimal numerals of any length given to us. Usually, we do not want to do that, and we also want faster algorithms. Note that supporting scientific notation with the above algorithm would also require arbitrary-size arrays. To fill out the decimal numeral for “2.79e34”, we have to fill an array with “27900000000000000000000000000000000”.
So algorithms are developed to do the conversion in smarter ways. Instead of doing exact calculations, we may do precise calculations but carefully analyze the errors produced to ensure they are too small to prevent us from getting the right answer. Also, data may be prepared in advance, such as tables with information about powers of ten, so that we have approximate values of powers of ten already in binary without having to compute them each time a conversion is performed.
The complications of converting decimal to binary floating-point arise out of this desire for algorithms that are fast and use limited resources. Allowing some errors causes a need for mathematical proofs to ensure the computations are correct, and trying to make the routines fast and resource-efficient lead people to think of clever techniques to use, which become tricky and require proof.

Make JavaScript Math.sqrt() print more digits

If I write document.write(Math.sqrt(2)) on my HTML page, I get 1.4142135623730951.
Is there any way to make the method output more than 16 decimal places?
No, there is not. Mathematical operations in Javascript are performed using 64-bit floating point values, and 16 digits of precision is right around the limit of what they can represent accurately.
To get more digits of the result, you will need to use an arbitrary-precision math library. I'm not aware offhand of any of these for Javascript that support square roots, though -- the one I was able to find offhand (Big.js) only supports addition, subtraction, and comparisons.
You can use toPrecision. However, ECMA requries only a precision of up to 21 significant digits:
console.log(Math.sqrt(2).toPrecision(21))
But keep in mind that the precision of real values on computer has some limits (see duskwuff's answer).
See also:
toFixed
toExponential

Why am I seeing inexact floating-point results in ECMAScript / ActionScript 3?

Hey all, let's jump straight to a code sample to show how ECMAScript/JavaScript/AS3 can't do simple math right (AS3 uses a 'IEEE-754 double-precision floating-point number' for the Number class which is supposedly identical to that used in JavaScript)...
trace(1.1); //'1.1': Ok, fine, looks good.
trace(1.1*100); //'110.00000000000001': What!?
trace((1.1*100)/100); //'1.1': Brings it back to 1.1 (since we're apparently multiplying by *approximately* 100 and then dividing by the same *approximate* '100' amount)
trace(1.1*100-110); //'1.4210854715202004e-14': Proof that according to AS3, 1.1*100!=110 (i.e. this isn't just a bug in Number.toString())
trace(1.1*100==110); //'false': Even further proof that according to AS3, 1.1*100!=110
What gives?
Welcome to the wonderful world of floating point calculation accuracy. In general, floating point calculations will give you results that are very very nearly correct, but comparing outputs for absolute equality is unlikely to give you results you expect without the use of rounding functions.
This is just a side effect of using floating point numbers - these are binary representations of decimal numbers, there will always be some approximations.
Long explanation
Floating point inconsistencies are a known problem in many languages. This is because computers aren't designed to handle floating point numbers.
Have fun
As moonshadow states, you're running into issues with floating point precision. Floating point numbers aren't suited to the task of representing and performing arithmetic upon decimal values in the manner that you would expect. These kinds of problems are seen most often when people try to using floating point numbers for financial calculations. The wikipedia entry is good, but you might get more out of this page, which steps through an error-prone financial calculation: http://c2.com/cgi/wiki?FloatingPointCurrency
To accurately deal with decimal numbers you need a decimal library. I've outlined two BigDecimal-style libraries written in javascript that may suit your needs in another SO post, hopefully you'll find them useful:
https://stackoverflow.com/questions/744099/javascript-bigdecimal-library/1575569

JavaScript 64 bit numeric precision

Is there a way to represent a number with higher than 53-bit precision in JavaScript? In other words, is there a way to represent 64-bit precision number?
I am trying to implement some logic in which each bit of a 64-bit number represents something. I lose the lower significant bits when I try to set bits higher than 2^53.
Math.pow(2,53) + Math.pow(2,0) == Math.pow(2,53)
Is there a way to implement a custom library or something to achieve this?
Google's Closure library has goog.math.Long for this purpose.
The GWT team have added a long emulation support so java longs really hold 64 bits. Do you want 64 bit floats or whole numbers ?
I'd just use either an array of integers or a string.
The numbers in javascript are doubles, I think there is a rounding error involved in your equation.
Perhaps I should have added some technical detail. Basically the GWT long emulation uses a tuple of two numbers, the first holding the high 32 bits and the second the low 32 bits of the 64 bit long.
The library of course contains methods to add stuff like adding two "longs" and getting a "long" result. Within your GWT Java code it just looks like two regular longs - one doesn't need to fiddle or be aware of the tuple. By using this approach GWT avoids the problem you're probably alluding to, namely "longs" dropping the lower bits of precision which isn't acceptable in many cases.
Whilst floats are by definition imprecise / approximations of a value, a whole number like a long isn't. GWT always holds a 64 bit long - maths using such longs never use precision. The exception to this is overflows but that accurately matches what occurs in Java etc when you add two very large long values which require more than 64 bits - eg 2^32-1 + 2^32-1.
To do the same for floating point numbers will require a similar approach. You will need to have a library that uses a tuple.
The following code might work for you; I haven't tested it however yet:
BigDecimal for JavaScript
Yes, 11 bit are reserved for exponent, only 52 bits containt value also called fraction.
Javascript allows bitwise operations on numbers but only first 32 bits are used in those operations according to Javascript standard specification.
I do not understand misleading GWT/Java/long answers in Javascript/double question though? Javascript is not Java.
Why would anyone need 64 bit precision in javascript ?
Longs sometimes hold ID of stuff in a DB so its important not to lose some of the lower bits... but floating point numbers are most of the time used for calculations. To use floats to hold monetary or similar exacting values is plain wrong. If you truely need 64 bit precision do the maths on the server where its faster and so on.

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