Develop Reference

Is there something similar to nullish coalescing operator but for if statements? [duplicate]

How do I determine if variable is undefined or null?
My code is as follows:
var EmpName = $("div#esd-names div#name").attr('class');
if(EmpName == 'undefined'){
// DO SOMETHING
};
<div id="esd-names">
<div id="name"></div>
</div>
But if I do this, the JavaScript interpreter halts execution.

You can use the qualities of the abstract equality operator to do this:
if (variable == null){
// your code here.
}
Because null == undefined is true, the above code will catch both null and undefined.

The standard way to catch null and undefined simultaneously is this:
if (variable == null) {
// do something
}
--which is 100% equivalent to the more explicit but less concise:
if (variable === undefined || variable === null) {
// do something
}
When writing professional JS, it's taken for granted that type equality and the behavior of == vs === is understood. Therefore we use == and only compare to null.
Edit again
The comments suggesting the use of typeof are simply wrong. Yes, my solution above will cause a ReferenceError if the variable doesn't exist. This is a good thing. This ReferenceError is desirable: it will help you find your mistakes and fix them before you ship your code, just like compiler errors would in other languages. Use try/catch if you are working with input you don't have control over.
You should not have any references to undeclared variables in your code.

Combining the above answers, it seems the most complete answer would be:
if( typeof variable === 'undefined' || variable === null ){
// Do stuff
}
This should work for any variable that is either undeclared or declared and explicitly set to null or undefined. The boolean expression should evaluate to false for any declared variable that has an actual non-null value.

if (variable == null) {
// Do stuff, will only match null or undefined, this won't match false
}

if (typeof EmpName != 'undefined' && EmpName) {
will evaluate to true if value is not:
null
undefined
NaN
empty string ("")
0
false

Probably the shortest way to do this is:
if(EmpName == null) { /* DO SOMETHING */ };
Here is proof:
function check(EmpName) {
if(EmpName == null) { return true; };
return false;
}
var log = (t,a) => console.log(`${t} -> ${check(a)}`);
log('null', null);
log('undefined', undefined);
log('NaN', NaN);
log('""', "");
log('{}', {});
log('[]', []);
log('[1]', [1]);
log('[0]', [0]);
log('[[]]', [[]]);
log('true', true);
log('false', false);
log('"true"', "true");
log('"false"', "false");
log('Infinity', Infinity);
log('-Infinity', -Infinity);
log('1', 1);
log('0', 0);
log('-1', -1);
log('"1"', "1");
log('"0"', "0");
log('"-1"', "-1");
// "void 0" case
console.log('---\n"true" is:', true);
console.log('"void 0" is:', void 0);
log(void 0,void 0); // "void 0" is "undefined"
And here are more details about == (source here)
BONUS: reason why === is more clear than == (look on agc answer)

jQuery attr() function returns either a blank string or the actual value (and never null or undefined). The only time it returns undefined is when your selector didn't return any element.
So you may want to test against a blank string. Alternatively, since blank strings, null and undefined are false-y, you can just do this:
if (!EmpName) { //do something }

Edited answer: In my opinion, you shouldn't use the function from my below old answer. Instead, you should probably know the type of your variable and use the according to check directly (for example, wondering if an array is empty? just do if(arr.length===0){} etc.). This answer doesn't even answer OP's question.
I've come to write my own function for this. JavaScript is weird.
It is usable on literally anything. (Note that this also checks if the variable contains any usable values. But since this information is usually also needed, I think it's worth posting). Please consider leaving a note.
function empty(v) {
let type = typeof v;
if (type === 'undefined') {
return true;
}
if (type === 'boolean') {
return !v;
}
if (v === null) {
return true;
}
if (v === undefined) {
return true;
}
if (v instanceof Array) {
if (v.length < 1) {
return true;
}
} else if (type === 'string') {
if (v.length < 1) {
return true;
}
if (v === '0') {
return true;
}
} else if (type === 'object') {
if (Object.keys(v).length < 1) {
return true;
}
} else if (type === 'number') {
if (v === 0) {
return true;
}
}
return false;
}
TypeScript-compatible.
This function should do exactly the same thing like PHP's empty() function (see RETURN VALUES)
Considers undefined, null, false, 0, 0.0, "0" {}, [] as empty.
"0.0", NaN, " ", true are considered non-empty.

The shortest and easiest:
if(!EmpName ){
// DO SOMETHING
}
this will evaluate true if EmpName is:
null
undefined
NaN
empty
string ("")
0
false

If the variable you want to check is a global, do
if (window.yourVarName) {
// Your code here
}
This way to check will not throw an error even if the yourVarName variable doesn't exist.
Example: I want to know if my browser supports History API
if (window.history) {
history.back();
}
How this works:
window is an object which holds all global variables as its properties, and in JavaScript it is legal to try to access a non-existing object property. If history doesn't exist then window.history returns undefined. undefined is falsey, so code in an if(undefined){} block won't run.

In JavaScript, as per my knowledge, we can check an undefined, null or empty variable like below.
if (variable === undefined){
}
if (variable === null){
}
if (variable === ''){
}
Check all conditions:
if(variable === undefined || variable === null || variable === ''){
}

Since you are using jQuery, you can determine whether a variable is undefined or its value is null by using a single function.
var s; // undefined
jQuery.isEmptyObject(s); // will return true;
s = null; // defined as null
jQuery.isEmptyObject(s); // will return true;
// usage
if(jQuery.isEmptyObject(s)){
alert('Either variable: s is undefined or its value is null');
}else{
alert('variable: s has value ' + s);
}
s = 'something'; // defined with some value
jQuery.isEmptyObject(s); // will return false;

I've just had this problem i.e. checking if an object is null.
I simply use this:
if (object) {
// Your code
}
For example:
if (document.getElementById("enterJob")) {
document.getElementById("enterJob").className += ' current';
}

You can simply use the following (I know there are shorter ways to do this, but this may make it easier to visually observe, at least for others looking at the code).
if (x === null || x === undefined) {
// Add your response code here, etc.
}
source: https://www.growthsnippets.com/how-can-i-determine-if-a-variable-is-undefined-or-null/

jQuery check element not null:
var dvElement = $('#dvElement');
if (dvElement.length > 0) {
// Do something
}
else{
// Else do something else
}

With the newest javascript changes, you can use the new logical operator ??= to check if the left operand is null or undefined and if so assign the value of right operand.
SO,
if(EmpName == null){ // if Variable EmpName null or undefined
EmpName = 'some value';
};
Is equivalent to:
EmpName ??= 'some value';

The easiest way to check is:
if(!variable) {
// If the variable is null or undefined then execution of code will enter here.
}

I run this test in the Chrome console. Using (void 0) you can check undefined:
var c;
undefined
if (c === void 0) alert();
// output = undefined
var c = 1;
// output = undefined
if (c === void 0) alert();
// output = undefined
// check c value c
// output = 1
if (c === void 0) alert();
// output = undefined
c = undefined;
// output = undefined
if (c === void 0) alert();
// output = undefined

With the solution below:
const getType = (val) => typeof val === 'undefined' || !val ? null : typeof val;
const isDeepEqual = (a, b) => getType(a) === getType(b);
console.log(isDeepEqual(1, 1)); // true
console.log(isDeepEqual(null, null)); // true
console.log(isDeepEqual([], [])); // true
console.log(isDeepEqual(1, "1")); // false
etc...
I'm able to check for the following:
null
undefined
NaN
empty
string ("")
0
false

To test if a variable is null or undefined I use the below code.
if(typeof sVal === 'undefined' || sVal === null || sVal === ''){
console.log('variable is undefined or null');
}

if you create a function to check it:
export function isEmpty (v) {
if (typeof v === "undefined") {
return true;
}
if (v === null) {
return true;
}
if (typeof v === "object" && Object.keys(v).length === 0) {
return true;
}
if (Array.isArray(v) && v.length === 0) {
return true;
}
if (typeof v === "string" && v.trim().length === 0) {
return true;
}
return false;
}

(null == undefined) // true
(null === undefined) // false
Because === checks for both the type and value. Type of both are different but value is the same.

Let's look at this,
let apple; // Only declare the variable as apple
alert(apple); // undefined
In the above, the variable is only declared as apple. In this case, if we call method alert it will display undefined.
let apple = null; /* Declare the variable as apple and initialized but the value is null */
alert(apple); // null
In the second one it displays null, because variable of apple value is null.
So you can check whether a value is undefined or null.
if(apple !== undefined || apple !== null) {
// Can use variable without any error
}

The foo == null check should do the trick and resolve the "undefined OR null" case in the shortest manner. (Not considering "foo is not declared" case.) But people who are used to have 3 equals (as the best practice) might not accept it. Just look at eqeqeq or triple-equals rules in eslint and tslint...
The explicit approach, when we are checking if a variable is undefined or null separately, should be applied in this case, and my contribution to the topic (27 non-negative answers for now!) is to use void 0 as both short and safe way to perform check for undefined.
Using foo === undefined is not safe because undefined is not a reserved word and can be shadowed (MDN). Using typeof === 'undefined' check is safe, but if we are not going to care about foo-is-undeclared case the following approach can be used:
if (foo === void 0 || foo === null) { ... }

You can do something like this, I think its more efficient for multiple value check on the same variable in one condition
const x = undefined;
const y = null;
const z = 'test';
if ([undefined, null].includes(x)) {
// Will return true
}
if ([undefined, null].includes(y)) {
// Will return true
}
if ([undefined, null].includes(z)) {
// Will return false
}

No one seems to have to posted this yet, so here we go:
a?.valueOf() === undefined works reliably for either null or undefined.
The following works pretty much like a == null or a == undefined, but it could be more attractive for purists who don't like == 😎
function check(a) {
const value = a?.valueOf();
if (value === undefined) {
console.log("a is null or undefined");
}
else {
console.log(value);
}
}
check(null);
check(undefined);
check(0);
check("");
check({});
check([]);
On a side note, a?.constructor works too:
function check(a) {
if (a?.constructor === undefined) {
console.log("a is null or undefined");
}
}
check(null);
check(undefined);
check(0);
check("");
check({});
check([]);

Calling typeof null returns a value of “object”, as the special value null is considered to be an empty object reference. Safari through version 5 and Chrome through version 7 have a quirk where calling typeof on a regular expression returns “function” while all other browsers return “object”.

var x;
if (x === undefined) {
alert ("only declared, but not defined.")
};
if (typeof y === "undefined") {
alert ("not even declared.")
};
You can only use second one: as it will check for both definition and declaration

var i;
if (i === null || typeof i === 'undefined') {
console.log(i, 'i is undefined or null')
}
else {
console.log(i, 'i has some value')
}

I still think the best/safe way to test these two conditions is to cast the value to a string:
var EmpName = $("div#esd-names div#name").attr('class');
// Undefined check
if (Object.prototype.toString.call(EmpName) === '[object Undefined]'){
// Do something with your code
}
// Nullcheck
if (Object.prototype.toString.call(EmpName) === '[object Null]'){
// Do something with your code
}

JavaScript null check

I've come across the following code:
function test(data) {
if (data != null && data !== undefined) {
// some code here
}
}
I'm somewhat new to JavaScript, but, from other questions I've been reading here, I'm under the impression that this code does not make much sense.
In particular, this answer states that
You'll get an error if you access an undefined variable in any context other than typeof.
Update: The (quote of the) answer above may be misleading. It should say «an undeclared variable», instead of «an undefined variable».
As I found out, in the answers by Ryan ♦, maerics, and nwellnhof, even when no arguments are provided to a function, its variables for the arguments are always declared. This fact also proves wrong the first item in the list below.
From my understanding, the following scenarios may be experienced:
The function was called with no arguments, thus making data an undefined variable, and raising an error on data != null.
The function was called specifically with null (or undefined), as its argument, in which case data != null already protects the inner code, rendering && data !== undefined useless.
The function was called with a non-null argument, in which case it will trivially pass both data != null and data !== undefined.
Q: Is my understanding correct?
I've tried the following, in Firefox's console:
--
[15:31:31.057] false != null
[15:31:31.061] true
--
[15:31:37.985] false !== undefined
[15:31:37.989] true
--
[15:32:59.934] null != null
[15:32:59.937] false
--
[15:33:05.221] undefined != null
[15:33:05.225] false
--
[15:35:12.231] "" != null
[15:35:12.235] true
--
[15:35:19.214] "" !== undefined
[15:35:19.218] true
I can't figure out a case where the data !== undefined after data != null might be of any use.

An “undefined variable” is different from the value undefined.
An undefined variable:
var a;
alert(b); // ReferenceError: b is not defined
A variable with the value undefined:
var a;
alert(a); // Alerts “undefined”
When a function takes an argument, that argument is always declared even if its value is undefined, and so there won’t be any error. You are right about != null followed by !== undefined being useless, though.

In JavaScript, null is a special singleton object which is helpful for signaling "no value". You can test for it by comparison and, as usual in JavaScript, it's a good practice to use the === operator to avoid confusing type coercion:
var a = null;
alert(a === null); // true
As #rynah mentions, "undefined" is a bit confusing in JavaScript. However, it's always safe to test if the typeof(x) is the string "undefined", even if "x" is not a declared variable:
alert(typeof(x) === 'undefined'); // true
Also, variables can have the "undefined value" if they are not initialized:
var y;
alert(typeof(y) === 'undefined'); // true
Putting it all together, your check should look like this:
if ((typeof(data) !== 'undefined') && (data !== null)) {
// ...
However, since the variable "data" is always defined since it is a formal function parameter, using the "typeof" operator is unnecessary and you can safely compare directly with the "undefined value".
function(data) {
if ((data !== undefined) && (data !== null)) {
// ...
This snippet amounts to saying "if the function was called with an argument which is defined and is not null..."

In your case use data==null (which is true ONLY for null and undefined - on second picture focus on rows/columns null-undefined)
function test(data) {
if (data != null) {
console.log('Data: ', data);
}
}
test(); // the data=undefined
test(null); // the data=null
test(undefined); // the data=undefined
test(0);
test(false);
test('something');
Here you have all (src):
if
== (its negation !=)
=== (its negation !==)

Q: The function was called with no arguments, thus making data an undefined variable, and raising an error on data != null.
A: Yes, data will be set to undefined. See section 10.5 Declaration Binding Instantiation of the spec. But accessing an undefined value does not raise an error. You're probably confusing this with accessing an undeclared variable in strict mode which does raise an error.
Q: The function was called specifically with null (or undefined), as its argument, in which case data != null already protects the inner code, rendering && data !== undefined useless.
Q: The function was called with a non-null argument, in which case it will trivially pass both data != null and data !== undefined.
A: Correct. Note that the following tests are equivalent:
data != null
data != undefined
data !== null && data !== undefined
See section 11.9.3 The Abstract Equality Comparison Algorithm and section 11.9.6 The Strict Equality Comparison Algorithm of the spec.

typeof foo === "undefined" is different from foo === undefined, never confuse them. typeof foo === "undefined" is what you really need. Also, use !== in place of !=
So the statement can be written as
function (data) {
if (typeof data !== "undefined" && data !== null) {
// some code here
}
}
Edit:
You can not use foo === undefined for undeclared variables.
var t1;
if(typeof t1 === "undefined")
{
alert("cp1");
}
if(t1 === undefined)
{
alert("cp2");
}
if(typeof t2 === "undefined")
{
alert("cp3");
}
if(t2 === undefined) // fails as t2 is never declared
{
alert("cp4");
}

I think, testing variables for values you do not expect is not a good idea in general. Because the test as your you can consider as writing a blacklist of forbidden values. But what if you forget to list all the forbidden values? Someone, even you, can crack your code with passing an unexpected value. So a more appropriate approach is something like whitelisting - testing variables only for the expected values, not unexpected. For example, if you expect the data value to be a string, instead of this:
function (data) {
if (data != null && data !== undefined) {
// some code here
// but what if data === false?
// or data === '' - empty string?
}
}
do something like this:
function (data) {
if (typeof data === 'string' && data.length) {
// consume string here, it is here for sure
// cleaner, it is obvious what type you expect
// safer, less error prone due to implicit coercion
}
}

The simple way to do your test is :
function (data) {
if (data) { // check if null, undefined, empty ...
// some code here
}
}

var a;
alert(a); //Value is undefined
var b = "Volvo";
alert(b); //Value is Volvo
var c = null;
alert(c); //Value is null

How to check 'undefined' value in jQuery

Possible Duplicate:
Detecting an undefined object property in JavaScript
javascript undefined compare
How we can add a check for an undefined variable, like:
function A(val) {
if (val == undefined)
// do this
else
// do this
}

JQuery library was developed specifically to simplify and to unify certain JavaScript functionality.
However if you need to check a variable against undefined value, there is no need to invent any special method, since JavaScript has a typeof operator, which is simple, fast and cross-platform:
if (typeof value === "undefined") {
// ...
}
It returns a string indicating the type of the variable or other unevaluated operand. The main advantage of this method, compared to if (value === undefined) { ... }, is that typeof will never raise an exception in case if variable value does not exist.

In this case you can use a === undefined comparison: if(val === undefined)
This works because val always exists (it's a function argument).
If you wanted to test an arbitrary variable that is not an argument, i.e. might not be defined at all, you'd have to use if(typeof val === 'undefined') to avoid an exception in case val didn't exist.

Note that typeof always returns a string, and doesn't generate an error if the variable doesn't exist at all.
function A(val){
if(typeof(val) === "undefined")
//do this
else
//do this
}

I know I am late to answer the function but jquery have a in build function to do this
if(jQuery.type(val) === "undefined"){
//Some code goes here
}
Refer jquery API document of jquery.type https://api.jquery.com/jQuery.type/ for the same.

You can use shorthand technique to check whether it is undefined or null
function A(val)
{
if(val || "")
//do this
else
//do this
}
hope this will help you

when I am testing "typeof obj === undefined", the alert(typeof obj) returning object, even though obj is undefined.
Since obj is type of Object its returning Object, not undefined.
So after hours of testing I opted below technique.
if(document.getElementById(obj) !== null){
//do...
}else{
//do...
}
I am not sure why the first technique didn't work.But I get done my work using this.

If you have names of the element and not id we can achieve the undefined check on all text elements (for example) as below and fill them with a default value say 0.0:
var aFieldsCannotBeNull=['ast_chkacc_bwr','ast_savacc_bwr'];
jQuery.each(aFieldsCannotBeNull,function(nShowIndex,sShowKey) {
var $_oField = jQuery("input[name='"+sShowKey+"']");
if($_oField.val().trim().length === 0){
$_oField.val('0.0')
}
})

I am not sure it is the best solution, but it works fine:
if($someObject['length']!=0){
//do someting
}

function isValue(value, def, is_return) {
if ( $.type(value) == 'null'
|| $.type(value) == 'undefined'
|| $.trim(value) == ''
|| ($.type(value) == 'number' && !$.isNumeric(value))
|| ($.type(value) == 'array' && value.length == 0)
|| ($.type(value) == 'object' && $.isEmptyObject(value)) ) {
return ($.type(def) != 'undefined') ? def : false;
} else {
return ($.type(is_return) == 'boolean' && is_return === true ? value : true);
}
}
try this~ all type checker

Check if undefined or not
if(typeof myVal === "undefined") {
//some code
}
Check if undefined or null or empty or false or 0
if(!myVal) {
// some code
} else {
// myVal is flawless
}

if Not undefined and indexOf ('foo') do something

So I'm trying to call where if not undefined and index is foo so I use:
if (typeof(getdata(js, 'box1')) != "undefined"
&& (getdata(js, 'box1')).indexOf('foo') >= 0) {
// Do something
}
This works fine but I dont want to call the getdata twice. Is there way to say if getdata is not undefined and the indexOf is foo then do something, without calling the getdata() function twice?

Alternative:
if (/foo/.test(getdata(js, "box1"))) {
// do something
}
While this allows you to get away with a single check, involving a regular expression for such a simple test could be frowned upon :)
You're better off using a local variable for storing the outcome of the function call:
var data = getdata(js, "box1");
if (data && data.indexOf("foo") ==! -1) {
// do something
}
Also note that typeof is an operator and not a function:
typeof something // instead of typeof(something)

Have you tried
var data = getdata(js, 'box1');
if(typeof(data) != 'undefined' && data.indexOf('foo') >= 0) {
}

You can read the indexOf of the value or an empty string if the value is undefined or null.
if ( (getdata(js, 'box1') || '').indexOf('foo') !=-1) {
// Do something
}
Hopefully your function will only return a string, undefined or null.

How to check if function exists in JavaScript?

My code is
function getID( swfID ){
if(navigator.appName.indexOf("Microsoft") != -1){
me = window[swfID];
}else{
me = document[swfID];
}
}
function js_to_as( str ){
me.onChange(str);
}
However, sometimes my onChange does not load. Firebug errors with
me.onChange is not a function
I want to degrade gracefully because this is not the most important feature in my program. typeof gives the same error.
Any suggestions on how to make sure that it exists and then only execute onChange?
(None of the methods below except try catch one work)

Try something like this:
if (typeof me.onChange !== "undefined") {
// safe to use the function
}
or better yet (as per UpTheCreek upvoted comment)
if (typeof me.onChange === "function") {
// safe to use the function
}

I had this problem. if (obj && typeof obj === 'function') { ... } kept throwing a reference error if obj happened to be undefined, so in the end I did the following:
if (typeof obj !== 'undefined' && typeof obj === 'function') { ... }
However, a colleague pointed out to me that checking if it's !== 'undefined' and then === 'function' is redundant, thus:
Simpler:
if (typeof obj === 'function') { ... }
Much cleaner and works great.

Modern JavaScript to the rescue!
me.onChange?.(str)
The Optional Chaining syntax (?.) solves this
in JavaScript since ES2020
in Typescript since version 3.7
In the example above, if a me.onChange property exists and is a function, it is called.
If no me.onChange property exists, nothing happens: the expression just returns undefined.
Note - if a me.onChange property exists but is not a function, a TypeError will be thrown just like when you call any non-function as a function in JavaScript. Optional Chaining doesn't do any magic to make this go away.

How about:
if('functionName' in Obj){
//code
}
e.g.
var color1 = new String("green");
"length" in color1 // returns true
"indexOf" in color1 // returns true
"blablabla" in color1 // returns false
or as for your case:
if('onChange' in me){
//code
}
See MDN docs.

If you're using eval to convert a string to function, and you want to check if this eval'd method exists, you'll want to use typeof and your function string inside an eval:
var functionString = "nonexsitantFunction"
eval("typeof " + functionString) // returns "undefined" or "function"
Don't reverse this and try a typeof on eval. If you do a ReferenceError will be thrown:
var functionString = "nonexsitantFunction"
typeof(eval(functionString)) // returns ReferenceError: [function] is not defined

Try typeof -- Look for 'undefined' to say it doesn't exist, 'function' for a function. JSFiddle for this code
function thisishere() {
return false;
}
alert("thisishere() is a " + typeof thisishere);
alert("thisisnthere() is " + typeof thisisnthere);
Or as an if:
if (typeof thisishere === 'function') {
// function exists
}
Or with a return value, on a single line:
var exists = (typeof thisishere === 'function') ? "Value if true" : "Value if false";
var exists = (typeof thisishere === 'function') // Returns true or false

Didn't see this suggested:
me.onChange && me.onChange(str);
Basically if me.onChange is undefined (which it will be if it hasn't been initiated) then it won't execute the latter part. If me.onChange is a function, it will execute me.onChange(str).
You can even go further and do:
me && me.onChange && me.onChange(str);
in case me is async as well.

For me the easiest way :
function func_exists(fname)
{
return (typeof window[fname] === 'function');
}

Put double exclamation mark i.e !! before the function name that you want to check. If it exists, it will return true.
function abc(){
}
!!window.abc; // return true
!!window.abcd; // return false

//Simple function that will tell if the function is defined or not
function is_function(func) {
return typeof window[func] !== 'undefined' && $.isFunction(window[func]);
}
//usage
if (is_function("myFunction") {
alert("myFunction defined");
} else {
alert("myFunction not defined");
}

function function_exists(function_name)
{
return eval('typeof ' + function_name) === 'function';
}
alert(function_exists('test'));
alert(function_exists('function_exists'));
OR
function function_exists(func_name) {
// discuss at: http://phpjs.org/functions/function_exists/
// original by: Kevin van Zonneveld (http://kevin.vanzonneveld.net)
// improved by: Steve Clay
// improved by: Legaev Andrey
// improved by: Brett Zamir (http://brett-zamir.me)
// example 1: function_exists('isFinite');
// returns 1: true
if (typeof func_name === 'string') {
func_name = this.window[func_name];
}
return typeof func_name === 'function';
}

function js_to_as( str ){
if (me && me.onChange)
me.onChange(str);
}

I'll go 1 step further to make sure the property is indeed a function
function js_to_as( str ){
if (me && me.onChange && typeof me.onChange === 'function') {
me.onChange(str);
}
}

I like using this method:
function isFunction(functionToCheck) {
var getType = {};
return functionToCheck && getType.toString.call(functionToCheck) === '[object Function]';
}
Usage:
if ( isFunction(me.onChange) ) {
me.onChange(str); // call the function with params
}

I had the case where the name of the function varied according to a variable (var 'x' in this case) added to the functions name. This works:
if ( typeof window['afunction_'+x] === 'function' ) { window['afunction_'+x](); }

The Underscore.js library defines it in the isFunction method as this (which comments suggest may cater for some browser bugs)
typeof obj == 'function' || false
http://underscorejs.org/docs/underscore.html#section-143

If you're checking for a function that is a jQuery plugin, you need to use $.fn.myfunction
if (typeof $.fn.mask === 'function') {
$('.zip').mask('00000');
}

Here is a working and simple solution for checking existence of a function and triggering that function dynamically by another function;
Trigger function
function runDynamicFunction(functionname){
if (typeof window[functionname] == "function") { //check availability
window[functionname]("this is from the function it"); // run function and pass a parameter to it
}
}
and you can now generate the function dynamically maybe using php like this
function runThis_func(my_Parameter){
alert(my_Parameter +" triggerd");
}
now you can call the function using dynamically generated event
<?php
$name_frm_somware ="runThis_func";
echo "<input type='button' value='Button' onclick='runDynamicFunction(\"".$name_frm_somware."\");'>";
?>
the exact HTML code you need is
<input type="button" value="Button" onclick="runDynamicFunction('runThis_func');">

In a few words: catch the exception.
I am really surprised nobody answered or commented about Exception Catch on this post yet.
Detail: Here goes an example where I try to match a function which is prefixed by mask_ and suffixed by the form field "name". When JavaScript does not find the function, it should throw an ReferenceError which you can handle as you wish on the catch section.
function inputMask(input) {
try {
let maskedInput = eval("mask_"+input.name);
if(typeof maskedInput === "undefined")
return input.value;
else
return eval("mask_"+input.name)(input);
} catch(e) {
if (e instanceof ReferenceError) {
return input.value;
}
}
}

With no conditions
me.onChange=function(){};
function getID( swfID ){
if(navigator.appName.indexOf("Microsoft") != -1){
me = window[swfID];
}else{
me = document[swfID];
}
}
function js_to_as( str ){
me.onChange(str);
}

I would suspect that me is not getting correctly assigned onload.
Moving the get_ID call into the onclick event should take care of it.
Obviously you can further trap as previously mentioned:
function js_to_as( str) {
var me = get_ID('jsExample');
if (me && me.onChange) {
me.onChange(str);
}
}

I always check like this:
if(!myFunction){return false;}
just place it before any code that uses this function

This simple jQuery code should do the trick:
if (jQuery.isFunction(functionName)) {
functionName();
}

I have tried the accepted answer; however:
console.log(typeof me.onChange);
returns 'undefined'.
I've noticed that the specification states an event called 'onchange' instead of 'onChange' (notice the camelCase).
Changing the original accepted answer to the following worked for me:
if (typeof me.onchange === "function") {
// safe to use the function
}

I have also been looking for an elegant solution to this problem. After much reflection, I found this approach best.
const func = me.onChange || (str => {});
func(str);

I would suggest using:
function hasMethod(subject, methodName) {
return subject != null && typeof subject[methodName] == "function";
}
The first check subject != null filters out nullish values (null and undefined) which don't have any properties. Without this check subject[methodName] could throw an error:
TypeError: (undefined|null) has no properties
Checking for only a truthy value isn't enough, since 0 and "" are both falsy but do have properties.
After validating that subject is not nullish you can safely access the property and check if it matches typeof subject[methodName] == "function".
Applying this to your code you can now do:
if (hasMethod(me, "onChange")) {
me.onChange(str);
}

function sum(nb1,nb2){
return nb1+nb2;
}
try{
if(sum() != undefined){/*test if the function is defined before call it*/
sum(3,5); /*once the function is exist you can call it */
}
}catch(e){
console.log("function not defined");/*the function is not defined or does not exists*/
}

And then there is this...
( document.exitPointerLock || Function )();

Try this one:
Window.function_exists=function(function_name,scope){
//Setting default scope of none is provided
If(typeof scope === 'undefined') scope=window;
//Checking if function name is defined
If (typeof function_name === 'undefined') throw new
Error('You have to provide an valid function name!');
//The type container
var fn= (typeof scope[function_name]);
//Function type
If(fn === 'function') return true;
//Function object type
if(fn.indexOf('function')!== false) return true;
return false;
}
Be aware that I've write this with my cellphone
Might contain some uppercase issues and/or other corrections needed like for example functions name
If you want a function like PHP to check if the var is set:
Window.isset=function (variable_con){
If(typeof variable_con !== 'undefined') return true;
return false;
}

To illustrate the preceding answers, here a quick JSFiddle snippet :
function test () {
console.log()
}
console.log(typeof test) // >> "function"
// implicit test, in javascript if an entity exist it returns implcitly true unless the element value is false as :
// var test = false
if(test){ console.log(true)}
else{console.log(false)}
// test by the typeof method
if( typeof test === "function"){ console.log(true)}
else{console.log(false)}
// confirm that the test is effective :
// - entity with false value
var test2 = false
if(test2){ console.log(true)}
else{console.log(false)}
// confirm that the test is effective :
// - typeof entity
if( typeof test ==="foo"){ console.log(true)}
else{console.log(false)}
/* Expected :
function
true
true
false
false
*/