I have 2 inputs where dates are selected #startdate and #enddate. I am using datepicker and have currently disabled weekends and holidays, this is working great!
I then have a #days input which calculates the difference between the 2 dates, this date difference then has a weekend count taken from it.
I would like to create a holiday count so I can also minus this from the differnce in days.
So i would end up with
$('#days').val((Math.abs(($d2new-$d1new)/86400000) - weekend_count - holidaycount) + 1);
My current code is as follows (this has been taken form other stackoverflow questions and is working great :) towards the bottom is the var holidaycount which is what i am struggling with. Any help would be greatly appreciated.
//holidays
var natDays = [
[1, 1, 'uk'],
[1, 2, 'uk'],
[1, 3, 'uk'],
[1, 4, 'uk'],
[12, 24, 'uk'],
[12, 25, 'uk'],
[12, 26, 'uk'],
[12, 27, 'uk'],
[12, 28, 'uk'],
[12, 29, 'uk'],
[12, 30, 'uk'],
[12, 31, 'uk']
];
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
function nationalDays(date) {
for (i = 0; i < natDays.length; i++) {
if (date.getMonth() == natDays[i][0] - 1 && date.getDate() == natDays[i][1]) {
return [false, natDays[i][2] + '_day'];
}
}
return [true, ''];
}
// do initialization here
$("#startdate").datepicker({
dateFormat: 'dd-mm-yy',
changeMonth: true,
changeYear: true,
firstDay: 1,
yearRange: '0:+100',
beforeShowDay: noWeekendsOrHolidays,
onSelect: function( selectedDate ) {
$("#enddate").datepicker("option","minDate",selectedDate );
$("#enddate2").datepicker("option","minDate",selectedDate );
},
minDate: '+1d',
maxDate: '+' + DAY_DIFFERENCE + 'd'
});
// do initialization here
$("#enddate").datepicker({
dateFormat: 'dd-mm-yy',
changeMonth: true,
changeYear: true,
firstDay: 1,
yearRange: '0:+100',
beforeShowDay: noWeekendsOrHolidays,
maxDate: '+' + DAY_DIFFERENCE + 'd'
});
// do initialization here
$("#enddate2").datepicker({
dateFormat: 'dd-mm-yy',
changeMonth: true,
changeYear: true,
firstDay: 1,
yearRange: '0:+100',
beforeShowDay: noWeekendsOrHolidays,
onSelect: function( selectedDate ) {
$d1 = $('#startdate').val();
$d2 = $('#enddate2').val();
$myDateParts1 = $d1.split("-");
$myDateParts2 = $d2.split("-");
$d1flip = new Date($myDateParts1[2], ($myDateParts1[1]-1), $myDateParts1[0]);
$d2flip = new Date($myDateParts2[2], ($myDateParts2[1]-1), $myDateParts2[0]);
$newdate1 = $d1flip.format("ddd mmm dd hh:MM:ss yyyy");
$newdate2 = $d2flip.format("ddd mmm dd hh:MM:ss yyyy");
// For Opera and older winXP IE n such
$d1new = Date.parse($newdate1);
$d2new = Date.parse($newdate2);
var weekend_count = 0;
for (i = $d1new.valueOf(); i <= $d2new.valueOf(); i+= 86400000){
var temp = new Date(i);
if (temp.getDay() == 0 || temp.getDay() == 6) {
weekend_count++;
}
}
var holidaycount = 0;
for (i = $d1new.valueOf(); i <= $d2new.valueOf(); i+= 86400000){
var temp = new Date(i);
if (**date in var natDays & is in selected difference range**) {
holidaycount++;
}
}
console.log(weekend_count);
console.log(holidaycount);
$('#days').val((Math.abs(($d2new-$d1new)/86400000) - weekend_count - holidaycount) + 1);
}
});
}, 'html');
return false;
});
}
EDIT
From the answer, I have inserted the function and tried this....
console.log(holidaycount); returns 0 but with the chosen dates i selected it should have been 10
var holidaycount = 0;
for (i = $d1new.valueOf(); i <= $d2new.valueOf(); i+= 86400000){
var temp = new Date(i);
if (isHoliday(temp)) {
holidaycount++;
}
}
UPDATE: modified getMonth() to getMonth() + 1 accordingly to the comments.
**date in var natDays & is in selected difference range**
date is in selected difference range is always true as new Date(i) is inside said range (just like in the loop for weekend_count: you didn't bother with checking whether you're in the range).
Now, checking if the date inside temp is a holiday, you may want to use a function (though you still can do it straight in your code):
/* dateObject is a JS Date object (e.g. dateObject = new Date();) */
/* country is the country we test holidays for */
function isHoliday(dateObject, country) {
/* let's assume natDays is global, otherwise pass it as a third argument to this function */
for(var i = 0; i < natDays.length; i++) {
/* natDays[i][0] is a day, natDays[i][1] is a month, natDays[i][2] is a country indicator */
if(parseInt(dateObject.getDate()) == parseInt(natDays[i][0]) && parseInt(dateObject.getMonth()) + 1 == parseInt(natDays[i][1]) && country.toLowerCase() == natDays[i][2].toLowerCase()) {
/* found a day and a month matching our current Date's day and month: interrupt and tell caller dateObject is a holiday */
return true;
}
}
/* end of loop, we parsed all possible holidays without finding any match for our Date: tell caller the given Date is not a holiday */
return false;
}
Now to put it in your code:
if (isHoliday(temp, 'uk')) {
holidaycount++;
}
This should do the trick, though it may require some refactoring (did not test this code), and there is probably more elegant ways to do it (like modding the Date object's prototype to use this function as a method of the object).
Related
Good afternoon. In my project, I need to display a calendar for a year. I did it with datepicker. Now I need to make it so that I can select the year of this calendar from another page. Please tell me how to do this? (A year comes to the page with a request)
function drawDatepicker(){
$('#picker').datepicker({
showOtherMonths: true,
selectOtherMonths: true,
numberOfMonths: [3,4],
stepMonths: 0,
yearRange: chouseYear + ":" + chouseYear,
showCurrentAtPos: new Date().getMonth(),
onSelect: function (dateText, datePicker) {
datePicker.drawMonth += $("#picker").datepicker("option", "showCurrentAtPos");
var radVal = $('input[name="typeDay"]:checked').val();
if(radVal == 1){
addOrRemoveDate(dateText, day_off);
}
if(radVal == 2){
addOrRemoveDate(dateText, radonica);
}
console.log(day_off);
console.log(radonica);
},
beforeShowDay: function (date) {
var year = date.getFullYear();
var month = padNumber(date.getMonth() + 1);
var day = padNumber(date.getDate());
var dateString = day + "." + month + "." + year;
var gotDate1 = jQuery.inArray(dateString, day_off);
if (gotDate1 >= 0) {
return [true, "ui-state-highlight"];
}
var gotDate2 = jQuery.inArray(dateString, radonica);
if (gotDate2>=0){
return [true, "ui-widget-header"];
}
return [true, ""];
}
});
}
Screen calendar
I found this solution to the problem. I specified defaultDate 01.01 of the desired year and showCurrentAtPos to 0. If the current year is specified, then defaultDate is today, and showCurrentAtPos is the number of the month
defaultDate: defaultDate,
showCurrentAtPos: sCAPos,
I am trying to exclude Array Dates and Sundays in Dependent Datepicker.
The first datepicker works really well while the second datepicker doesn't exclude Array dates and sundays in Maxdate.
Second datepicker must selectable within 7 working days which should exclude Sunday and Array Dates.
I believe there's should be an easy way to achieve this.
Any Suggestion?
Here's the code :(
$(document).ready(function() {
var d = new Date();
var array = ["10-12-2019","05-12-2019"];
var monthNames = ["January", "February", "March", "April", "May", "June",
"July", "August", "September", "October", "November", "December"];
today = monthNames[d.getMonth()] + ' ' + d.getDate() + ' ' + d.getFullYear();
function includeDate(date) {
var dateStr = jQuery.datepicker.formatDate('dd-mm-yy', date);
// Date 0 = Sunday & 6 = Saturday
return date.getDay() !== 0 && array.indexOf(dateStr) === -1;
}
function getTomorrow(date) {
return new Date(date.getFullYear(), date.getMonth(), date.getDate() + 1);
}
$('#datepicker2').attr('readonly', 'readonly');
$('#datepicker1').datepicker(
{
defaultDate: "+1d",
inline: true,
showOtherMonths: true,
changeMonth: true,
selectOtherMonths: true,
required: true,
showOn: "focus",
numberOfMonths: 1,
minDate: 1,
beforeShowDay: function(date) {
return [includeDate(date)];
},
maxDate: (function(max) {
var nextAvailable = new Date();
var count = 0;
var extra = 0;
while(count < max) {
nextAvailable = getTomorrow(nextAvailable);
if ( !includeDate(nextAvailable) ) {
extra++;
} else {
count++;
}
}
return max + extra;
})
(3)
});
$('#datepicker1').change(function () {
var from = $('#datepicker1').datepicker('getDate');
var date_diff = Math.ceil((from.getTime() - Date.parse(today)) / 86400000);
var maxDate_d = date_diff + 7 +'d';
date_diff = date_diff + 'd';
$('#datepicker2').val('').removeAttr('readonly').removeClass('hasDatepicker').datepicker({
inline: true,
showOtherMonths: true,
changeMonth: true,
selectOtherMonths: true,
required: true,
showOn: "focus",
numberOfMonths: 1,
minDate: date_diff +1,
beforeShowDay: function(date) {
return [includeDate(date)];
},
maxDate: (function(max) {
var nextAvailable = $('#datepicker1').datepicker('getDate');
var count = 0;
var extra = 0;
while(count < max) {
nextAvailable = getTomorrow(nextAvailable);
if ( !includeDate(nextAvailable) ) {
extra++;
} else {
count++;
}
}
return max + extra;
})
(7)
});
});
});
http://jsfiddle.net/nLveychs/83/
For your code, it is almost right. You just forgot one thing for the second date picker. That is, you did not add the date_diff value to the return value of the maxDate() anonymous function. I was going to pass the date_diff by adding it to the parameter. Nonetheless, I found a bug. It can't be done that way, because any previous un-selectable days, will turn into additional extra days. Thus, the only way to add date_diff is start from the day of date picker1 and add the return value of maxDate's anonymous function to date_diff.
I also took out some unnecessary codes. You can just get the date differences simply subtracting datepicker1 date to today date without needing to parse a date string. Plus, date_diff can be as was without needing a "d" to be added to it.
Also, take note that, when you calculate the different days between two dates, for your code, it work that way, because datepicker's date picked object is set to the 0 hour of the day. That code may not work for other scenario. The for sure way to get the day difference between two dates is by setting their hours, minutes, seconds, and milliseconds(if needed) to zeroes.
<script src="https://ajax.aspnetcdn.com/ajax/jQuery/jquery-3.4.1.min.js"></script>
<script src="//code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<script>
$(document).ready(function() {
var array = ["10-12-2019","05-12-2019"];
function includeDate(date) {
var dateStr = jQuery.datepicker.formatDate('dd-mm-yy', date);
// Date 0 = Sunday & 6 = Saturday
return date.getDay() !== 0 && array.indexOf(dateStr) === -1;
}
function getTomorrow(date) {
return new Date(date.getFullYear(), date.getMonth(), date.getDate() + 1);
}
$('#datepicker2').attr('readonly', 'readonly');
$('#datepicker1').datepicker(
{
defaultDate: "+1d",
inline: true,
showOtherMonths: true,
changeMonth: true,
selectOtherMonths: true,
required: true,
showOn: "focus",
numberOfMonths: 1,
minDate: 1,
beforeShowDay: function(date) {
return [includeDate(date)];
},
maxDate: (function(max) {
var nextAvailable = new Date();
var count = 0;
var extra = 0;
while(count < max) {
nextAvailable = getTomorrow(nextAvailable);
if ( !includeDate(nextAvailable) ) {
extra++;
} else {
count++;
}
}
return max + extra;
})
(3)
});
$('#datepicker1').change(function () {
var from = $('#datepicker1').datepicker('getDate');
// Date diff can be obtained like this without needing to parse a date string.
var date_diff = Math.ceil((from - new Date()) / 86400000);
$('#datepicker2').val('').removeAttr('readonly').removeClass('hasDatepicker').datepicker({
inline: true,
showOtherMonths: true,
changeMonth: true,
selectOtherMonths: true,
required: true,
showOn: "focus",
numberOfMonths: 1,
minDate: date_diff + 1,
beforeShowDay: function(date) {
return [includeDate(date)];
},
maxDate: (function(max) {
var nextAvailable = $('#datepicker1').datepicker('getDate');
var count = 0;
var extra = 0;
while(count < max) {
nextAvailable = getTomorrow(nextAvailable);
if ( !includeDate(nextAvailable) ) {
extra++;
} else {
count++;
}
}
/*
* Date diffent have to be added to return value.
*/
return max + date_diff + extra;
})
(7)
});
});
});
</script>
<p>datepicker1 <input id="datepicker1"></p>
<p>datepicker2 <input id="datepicker2"></p>
I am trying to exclude disabled dates when counting MaxDate.
I tried many ways but still doesn't work.
Any suggestion?
02-12-2019 and Sundays has been disabled but the Maxdate include the disabled date.
Maxdate should be 3 days which excludes disabled days and Maxdays starts by today.
My goal is to add days if the days between today until max days has disabled.
Add 1 day per disabled day
Update
Now i am able to Exclude sunday when counting maxdate but i still can't exclude the array date where it should add one more day after 02-12-2019.
Updated Code :(
<script>
var array = ["02-12-2019"]
//new
function includeDate(date) {
return date.getDay() !== 7 && date.getDay() !== 0;
}
function getTomorrow(date) {
return new Date(date.getFullYear(), date.getMonth(), date.getDate() + 1);
}
//prev
$('input').datepicker(
{
defaultDate: "+1d",
inline: true,
showOtherMonths: true,
changeMonth: true,
selectOtherMonths: true,
required: true,
showOn: "focus",
numberOfMonths: 1,
minDate: 1,
beforeShowDay: function(date) {
var string = jQuery.datepicker.formatDate('dd-mm-yy', date);
var isDisabled = ($.inArray(string, array) != -1);
return [includeDate(date) && !isDisabled];
},
maxDate: (function(max) {
var today = new Date();
var nextAvailable = getTomorrow(today);
var count = 0;
var countz = 1;
var newMax = 0;
while(count < max) {
if (includeDate(nextAvailable) ) {
count++;
}
if (includeDate(nextAvailable) ) {
countz++;
}
newMax++;
nextAvailable = getTomorrow(nextAvailable);
}
return newMax;
})
(3)
});
http://jsfiddle.net/3o1dmvw5/96/
This below should be the solution. The problem with your code is that you forgot to verify the date string to see if it is in the array or not using your includeDate() function. Thus, your includeDate() function allow that date, while maxDate didn't allow that date.
Also, you can also use array.indexOf() instead of jQuery's inArray. I am pretty sure that native array.indexOf() probably is faster.
Besides that, I modify your maxDate() function a little bit. It now look less confusing. I used window onload so that I can debug the code easy. You can just take that out.
For my version, when it come to verify the days, beforeShowDay and includeDate does the same thing. Thus, I edited beforeShowDay() to just return the value from the function includeDate().
Also, you should change the input selector to an ID(#) or Class(.). Otherwise, your datepicker will proc on all input fields.
Also, I modified you includeDate() function. There isn't a day 7 as 0 - 6 = Sunday - Saturday.
<script src="https://ajax.aspnetcdn.com/ajax/jQuery/jquery-3.4.1.min.js"></script>
<script src="//code.jquery.com/ui/1.9.2/jquery-ui.js"></script>
<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<script>
var array = ["02-12-2019"]
//new
function includeDate(date) {
var dateStr = jQuery.datepicker.formatDate('dd-mm-yy', date);
// Date 0 = Sunday & 6 = Saturday
return date.getDay() !== 0 && array.indexOf(dateStr) === -1;
}
function getTomorrow(date) {
return new Date(date.getFullYear(), date.getMonth(), date.getDate() + 1);
}
//prev
window.onload = function(){
$('input').datepicker(
{
defaultDate: "+1d",
inline: true,
showOtherMonths: true,
changeMonth: true,
selectOtherMonths: true,
required: true,
showOn: "focus",
numberOfMonths: 1,
minDate: 1,
beforeShowDay: function(date) {
return [includeDate(date)];
},
maxDate: (function(max) {
// Next available is today at first.
var nextAvailable = new Date();
var count = 0;
var extra = 0;
while(count < max) {
/*
* Next available is here so that getTomorrow does not need
* to run an extra time when the loop is completed.
*
*/
nextAvailable = getTomorrow(nextAvailable);
// If the day is not available then we need to add an extra day.
if ( !includeDate(nextAvailable) ) {
extra++;
// Else we just increase the count.
} else {
count++;
}
}
// Return max + extra.
return max + extra;
})
(3)
});
};
</script>
<p>Date: <input type="text" id="datepicker"></p>
I'm using the code from JQuery UI Datepicker Disbale Next Day After 12pm to disable weekends, public holidays and next day (if selected after 10am), but I'm stuck on how to only allow Tuesday, Wednesday and Thursday to be selected.
// dates
var dateMin = new Date();
var weekDays = AddWeekDays(1);
dateMin.setDate(dateMin.getDate() + weekDays);
var natDays = [
[1, 1, 'uk'],
[12, 25, 'uk'],
[12, 26, 'uk']
];
function noWeekendsOrHolidays(date) {
var noWeekend = $j.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
function nationalDays(date) {
for (i = 0; i < natDays.length; i++) {
if (date.getMonth() == natDays[i][0] - 1 && date.getDate() == natDays[i][1]) {
return [false, natDays[i][2] + '_day'];
}
}
return [true, ''];
}
function AddWeekDays(weekDaysToAdd) {
var mydate = new Date();
if (mydate.getHours()>=10)
var daysToAdd = 1;
else var daysToAdd = 0;
var day = mydate.getDay()
weekDaysToAdd = weekDaysToAdd - (5 - day)
if ((5 - day) < weekDaysToAdd || weekDaysToAdd == 1) {
daysToAdd = (5 - day) + 2 + daysToAdd
} else { // (5-day) >= weekDaysToAdd
daysToAdd = (5 - day) + daysToAdd
}
while (weekDaysToAdd != 0) {
var week = weekDaysToAdd - 5
if (week > 0) {
daysToAdd = 7 + daysToAdd
weekDaysToAdd = weekDaysToAdd - 5
} else { // week < 0
daysToAdd = (5 + week) + daysToAdd
weekDaysToAdd = weekDaysToAdd - (5 + week)
}
}
return daysToAdd;
}
$j('.input-text.addon.addon-custom').datepicker({
beforeShowDay: noWeekendsOrHolidays,
minDate : dateMin,
defaultDate: +1,
firstDay: 1,
changeFirstDay: true,
dateFormat: "DD, dd MM yy"
});
Any help would be very much appreciated.
Fiddle here: http://jsfiddle.net/prydonian/4k4gga6j/
On your datepicker function, add the "beforeShowDay" option like this.
jQuery('#datepicker').datepicker({
minDate: dateMin,
defaultDate: +1,
firstDay: 1,
changeFirstDay: true,
dateFormat: "DD, dd MM yy",
beforeShowDay: function(day){
if (day.getDay()<2 || day.getDay()>4){
return [false, ""];
}
return noWeekendsOrHolidays(day);
}
});
here is the Fiddle updated: http://jsfiddle.net/4k4gga6j/3/
If I understood you right, you need to exclude any day other than Tuesday, Wednesday and Thursday? If the answer is yes, then you should add the following code to your existing noWeekendsOrHolidays method:
($.inArray(date.getDay(), [2, 3, 4]) != -1)
here is updated jsFiddle http://jsfiddle.net/4k4gga6j/4/
I use a datepicker for choosing an appointment day. I already set the date range to be only for the next month. That works fine. I want to exclude Saturdays and Sundays from the available choices. Can this be done? If so, how?
There is the beforeShowDay option, which takes a function to be called for each date, returning true if the date is allowed or false if it is not. From the docs:
beforeShowDay
The function takes a date as a parameter and must return an array with [0] equal to true/false indicating whether or not this date is selectable and 1 equal to a CSS class name(s) or '' for the default presentation. It is called for each day in the datepicker before is it displayed.
Display some national holidays in the datepicker.
$(".selector").datepicker({ beforeShowDay: nationalDays})
natDays = [
[1, 26, 'au'], [2, 6, 'nz'], [3, 17, 'ie'],
[4, 27, 'za'], [5, 25, 'ar'], [6, 6, 'se'],
[7, 4, 'us'], [8, 17, 'id'], [9, 7, 'br'],
[10, 1, 'cn'], [11, 22, 'lb'], [12, 12, 'ke']
];
function nationalDays(date) {
for (i = 0; i < natDays.length; i++) {
if (date.getMonth() == natDays[i][0] - 1
&& date.getDate() == natDays[i][1]) {
return [false, natDays[i][2] + '_day'];
}
}
return [true, ''];
}
One built in function exists, called noWeekends, that prevents the selection of weekend days.
$(".selector").datepicker({ beforeShowDay: $.datepicker.noWeekends })
To combine the two, you could do something like (assuming the nationalDays function from above):
$(".selector").datepicker({ beforeShowDay: noWeekendsOrHolidays})
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
Update: Note that as of jQuery UI 1.8.19, the beforeShowDay option also accepts an optional third paremeter, a popup tooltip
If you don't want the weekends to appear at all, simply:
CSS
th.ui-datepicker-week-end,
td.ui-datepicker-week-end {
display: none;
}
The datepicker has this functionality built in!
$( "#datepicker" ).datepicker({
beforeShowDay: $.datepicker.noWeekends
});
http://api.jqueryui.com/datepicker/#utility-noWeekends
These answers were very helpful. Thank you.
My contribution below adds an array where multiple days can return false (we're closed every Tuesday, Wednesday and Thursday). And I bundled the specific dates plus years and the no-weekends functions.
If you want weekends off, add [Saturday], [Sunday] to the closedDays array.
$(document).ready(function(){
$("#datepicker").datepicker({
beforeShowDay: nonWorkingDates,
numberOfMonths: 1,
minDate: '05/01/09',
maxDate: '+2M',
firstDay: 1
});
function nonWorkingDates(date){
var day = date.getDay(), Sunday = 0, Monday = 1, Tuesday = 2, Wednesday = 3, Thursday = 4, Friday = 5, Saturday = 6;
var closedDates = [[7, 29, 2009], [8, 25, 2010]];
var closedDays = [[Monday], [Tuesday]];
for (var i = 0; i < closedDays.length; i++) {
if (day == closedDays[i][0]) {
return [false];
}
}
for (i = 0; i < closedDates.length; i++) {
if (date.getMonth() == closedDates[i][0] - 1 &&
date.getDate() == closedDates[i][1] &&
date.getFullYear() == closedDates[i][2]) {
return [false];
}
}
return [true];
}
});
The solution here that everyone likes seems to very intense... personally I think it's much easier to do something like this:
var holidays = ["12/24/2012", "12/25/2012", "1/1/2013",
"5/27/2013", "7/4/2013", "9/2/2013", "11/28/2013",
"11/29/2013", "12/24/2013", "12/25/2013"];
$( "#requestShipDate" ).datepicker({
beforeShowDay: function(date){
show = true;
if(date.getDay() == 0 || date.getDay() == 6){show = false;}//No Weekends
for (var i = 0; i < holidays.length; i++) {
if (new Date(holidays[i]).toString() == date.toString()) {show = false;}//No Holidays
}
var display = [show,'',(show)?'':'No Weekends or Holidays'];//With Fancy hover tooltip!
return display;
}
});
This way your dates are human readable. It's not really that different it just makes more sense to me this way.
You can use noWeekends function to disable the weekend selection
$(function() {
$( "#datepicker" ).datepicker({
beforeShowDay: $.datepicker.noWeekends
});
});
This version of code will make u to get the holiday dates from the sql database and disable the specified date in the UI Datepicker
$(document).ready(function (){
var holiDays = (function () {
var val = null;
$.ajax({
'async': false,
'global': false,
'url': 'getdate.php',
'success': function (data) {
val = data;
}
});
return val;
})();
var natDays = holiDays.split('');
function nationalDays(date) {
var m = date.getMonth();
var d = date.getDate();
var y = date.getFullYear();
for (var i = 0; i ‘ natDays.length-1; i++) {
var myDate = new Date(natDays[i]);
if ((m == (myDate.getMonth())) && (d == (myDate.getDate())) && (y == (myDate.getFullYear())))
{
return [false];
}
}
return [true];
}
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
$(function() {
$("#shipdate").datepicker({
minDate: 0,
dateFormat: 'DD, d MM, yy',
beforeShowDay: noWeekendsOrHolidays,
showOn: 'button',
buttonImage: 'images/calendar.gif',
buttonImageOnly: true
});
});
});
Create a Database in sql and put you holiday dates in MM/DD/YYYY format as Varchar
Put the below contents in a file getdate.php
[php]
$sql="SELECT dates FROM holidaydates";
$result = mysql_query($sql);
$chkdate = $_POST['chkdate'];
$str='';
while($row = mysql_fetch_array($result))
{
$str .=$row[0].'';
}
echo $str;
[/php]
Happy Coding !!!! :-)
$("#selector").datepicker({ beforeShowDay: highlightDays });
...
var dates = [new Date("1/1/2011"), new Date("1/2/2011")];
function highlightDays(date) {
for (var i = 0; i < dates.length; i++) {
if (date - dates[i] == 0) {
return [true,'', 'TOOLTIP'];
}
}
return [false];
}
In this version, month, day, and year determines which days to block on the calendar.
$(document).ready(function (){
var d = new Date();
var natDays = [[1,1,2009],[1,1,2010],[12,31,2010],[1,19,2009]];
function nationalDays(date) {
var m = date.getMonth();
var d = date.getDate();
var y = date.getFullYear();
for (i = 0; i < natDays.length; i++) {
if ((m == natDays[i][0] - 1) && (d == natDays[i][1]) && (y == natDays[i][2]))
{
return [false];
}
}
return [true];
}
function noWeekendsOrHolidays(date) {
var noWeekend = $.datepicker.noWeekends(date);
if (noWeekend[0]) {
return nationalDays(date);
} else {
return noWeekend;
}
}
$(function() {
$(".datepicker").datepicker({
minDate: new Date(d.getFullYear(), 1 - 1, 1),
maxDate: new Date(d.getFullYear()+1, 11, 31),
hideIfNoPrevNext: true,
beforeShowDay: noWeekendsOrHolidays,
});
});
});
In the latest Bootstrap 3 version (bootstrap-datepicker.js) beforeShowDay expects a result in this format:
{ enabled: false, classes: "class-name", tooltip: "Holiday!" }
Alternatively, if you don't care about the CSS and tooltip then simply return a boolean false to make the date unselectable.
Also, there is no $.datepicker.noWeekends, so you need to do something along the lines of this:
var HOLIDAYS = { // Ontario, Canada holidays
2017: {
1: { 1: "New Year's Day"},
2: { 20: "Family Day" },
4: { 17: "Easter Monday" },
5: { 22: "Victoria Day" },
7: { 1: "Canada Day" },
8: { 7: "Civic Holiday" },
9: { 4: "Labour Day" },
10: { 9: "Thanksgiving" },
12: { 25: "Christmas", 26: "Boxing Day"}
}
};
function filterNonWorkingDays(date) {
// Is it a weekend?
if ([ 0, 6 ].indexOf(date.getDay()) >= 0)
return { enabled: false, classes: "weekend" };
// Is it a holiday?
var h = HOLIDAYS;
$.each(
[ date.getYear() + 1900, date.getMonth() + 1, date.getDate() ],
function (i, x) {
h = h[x];
if (typeof h === "undefined")
return false;
}
);
if (h)
return { enabled: false, classes: "holiday", tooltip: h };
// It's a regular work day.
return { enabled: true };
}
$("#datePicker").datepicker({ beforeShowDay: filterNonWorkingDays });
This work for me:
$( "#datepicker" ).datepicker({
beforeShowDay: function( date ) {
var day = date.getDay();
return [ ( day > 0 && day < 6 ), "" ];
}
});
For Saturday and Sunday You can do something like this
$('#orderdate').datepicker({
daysOfWeekDisabled: [0,6]
});
To Disable the Weekends the API has a built-in feature
$('#data_1 .input-group.date').datepicker({
daysOfWeekDisabled: [0,6],
});
0 = Sunday
6 = Sunday