Can anyone give me the regular expression for currency which have the following formats :
1000 - valid
1,000 - valid
1,000.00 or 1000.00 - valid.
This means, the number May or May Not contain a comma(,) separator every 3 digits.
The number May Or May Not contain a dot (.), and if it carries a dot(.) it should show atleast 1 number after the decimal place.
And lastly it should be numerical characters only. If I need to make my question clear kindly suggest.
/^\d{1,3}(?:(?:,\d{3})*|(?:\d{3})*)(?:\.\d{1,2})?$/
"Between one and three digits, then any number of groups of three digits prefixed by a comma or any number of groups of three digits not prefixed by said comma (disallowing a mix of the two kinds of groups), then an optional group of one or two digits prefixed by a dot."
Note: This regex assumes that you want to validate an entire string against the criteria outlined in your question. If you want to use it to find such numbers in a longer string, you will need to remove the ^ and $ from the beginning and end of the expression.
Something like so should work: (,?\d{3})+(\.\d{2})?. The regex will attempt to match a sequence of 3 digits precedeed by an optional comma, which is then, finally followed by an optional decimal point and 2 digits.
Please refer to this tutorial for more information.
EDIT: As per the comment below, the above regex can fail. I would recommend first using this regular expression: ^[\d][\d.,]+$ to make sure that you only have digits, thousand and decimal seperators. This regular expression will also make sure that the number starts with a digit, not with anything else. You could most likely have one regular expression which does everything, but it will most likely be quite complex.
Related
I am trying to parse a string which has two numbers, both can be between 1 and 3 digits, and will have a colon in between. Here are some examples:
"1:1"
"1:12"
"12:1"
"123:12"
Also, the given string may also be invalid, and I need to detect if it is. My attempts so far to make sure the string is valid have looked like this: .match(/[1-9]\:[1-9]/);. But then I noticed that this wont work if a string such as this is inputted: "characters12:4characters". How would I go about validating the string to make sure it is in the format x:y?
Any help would be deeply appreciated.
Edit: numbers which contain 0 at the beginning is valid, but may not be given.
You may use
/^\d{1,3}:\d{1,3}$/
See the regex demo
Details
^ - start of a string
\d{1,3} - one, two or three digits (\d is a shorthand character class that matches any digit (it can also be written as a [0-9] character class) and {1,3} is a limited quantifier that matches1 to 3 consecutive occurrences of the quantified subpattern)
: - a colon
\d{1,3} - one, two or three digits
$ - end of the string.
I wrote Regular expression for the below cases :
only numbers(length:4)
only alphabets(should contain vowel)
([0-9]{1,4})|((?=[a-z]*[aeiou])[a-z]*)
eg: 9987, tyde
How to add the below condition?
Ignore the first two cases if the string contains alphanumeric
characters.
eg: 9ty87
If I decypher well your question, I think your are looking for that:
a string with only digits and between one and four characters
a string with only letters with at least a vowel
a string with only letters and digits with at least one letter and one digit.
pattern:
/^(?:[0-9]{1,4}|[bcdfghj-np-tv-z]*[aeiou][a-z]*|[a-z]+[0-9][a-z0-9]*|[0-9]+[a-z][a-z0-9]*)$/i
or more factorized
/^(?:[0-9]{1,4}(?:[0-9]*[a-z][a-z0-9]*)?|[bcdfghj-np-tv-z]*(?:[aeiou][a-z]*|[a-z]+[0-9][a-z0-9]*))$/i
It is a simple alternation (I don't think you need something more complicated). So only one of the branches will succeed.
Note that anchors ^ and $ are essential for this kind of task to ensure that whole string is taken in account.
I'm relative new to RegEx and I've encountered a problem. I want to regex a name. I want it to be max 100 characters, contain at least 2 alphabetic characters and it will allow the character '-'.
I have no problem to only check for alphabetic characters or both alphabetic characters and hyphen but I dont't want a name that potantially can be '---------'.
My code without check for hyphens is
var nameRegExp = /^([a-z]){2,100}$/;
An explanation for the code is appreciated as well.
Thanks!
I guess
/^(?=.*[a-z].*[a-z])[a-z-]{1,100}$/
the lookahead part (^(?=.*[a-z].*[a-z])) checks if there are at least two letters. This pattern ("start of string, followed by...") is a common way to express additional conditions in regexes.
You can limit the number of - by adding a negative assertion, as #Mike pointed out:
/^(?=.*[a-z].*[a-z])(?!(?:.*-){11,})[a-z-]{1,100}$/ // max 10 dashes
however it might be easier to write an expression that would match "good" strings instead of trying to forbid "bad" ones. For example, this
/^[a-z]+(-[a-z]+)*$/
looks like a good approximation for a "name". It allows foo and foo-bar-baz, but not the stuff like ---- or foo----bar----.
To limit the number of - you could add a negative look-ahead, where the number 3 is one more than the maximum number you want to allow
/^(?!(?:[a-z]*-){3,})(?=-*[a-z]-*[a-z])[a-z-]{2,100}$/
I need to validate some form fileds that contain brazilian money (its name is "Real") using Javascript. It has the following format:
0,01
0,12
1,23
12,34
123,45
1.234,56
12.235,67
123.456,78
1.234.567,89
12.345.678,90
123.456.789,01
1.234.567.890,12
My regex knowledge is weak, can somebody help me please?
Does this do what you want?
^\d{1,3}(?:\.\d{3})*,\d{2}$
That says "1 to 3 digits, optionally followed by any number of groups of three digits preceded by a period, followed by a comma and two more digits." If you want to allow the leading whitespace present in your example, add \s* to the front:
^\s*\d{1,3}(?:\.\d{3})*,\d{2}$
EDIT: As #ElRonnoco pointed out, the above regular expression accepts leading zeroes (e.g. 010.100,00). To disallow those, you may use this longer version:
^\s*(?:[1-9]\d{0,2}(?:\.\d{3})*|0),\d{2}$
EDIT 2 The above regular expressions all match a string containing a single monetary amount and nothing else. It's not clear from the question if that's the intent.
EDIT 3 To allow numbers that have no decimal part, or only one decimal digit, change it like this:
^\s*(?:[1-9]\d{0,2}(?:\.\d{3})*|0)(?:,\d{1,2})?$
I would give this regex a try:
\d+(?:\.\d{3})*?,\d{2}
What it says is:
- match digits until
a. a dot followed by 3 digits is found (and this step can be repeated several times)
b. or a comma followed by 2 digits is found
EDIT:
- thanks for the comments, I forgot about the constraint for the first value
updated regex
\d{1,3}(?:\.\d{3})*?,\d{2}
Complementing Mark's reply:
Who needs "." in the string and not "," to count cents. And need find the values in middle a text :
(?:[1-9]\d{0,2}(?:\,\d{3})*|0)(?:.\d{1,2})?
https://regexr.com/61166
What can be a regular expression for following type of string
E.g. 1, 2-3, 4..5, <6, <=7, >8, >=9
Here I am using equals, range (-), sequence (..) & greater than/equal to operators for numbers less than 100. These numbers are separated by a comma.
Pls help me in writing a regular expression for this. Thanks in advance.
Atul
How about something like this:
^(\d+(-|\.\.)|[<>]=?)?\d+$
Example using Python:
>>> import re
>>> pattern = '^(\d+(-|\.\.)|[<>]=?)?\d+$'
>>> for s in '1, 2-3, 4..5, <6, <=7, >8, >=9'.split(','):
... print(re.match(pattern, s.strip()).group(0))
...
1
2-3
4..5
<6
<=7
>8
>=9
To be clear, this regex matches only one element in the list. I highly recommend that you preprocess your input by splitting it on commas and trimming the individual elements, like I did in the example above. Even though that's not strictly necessary (you can add this logic to the regex I gave here), it will but quite a bit more efficient and readable.
How the regex works:
Observe that every valid string ends with one or more digits, thus \d+$.
There may or may not be something before that, thus, ^(...)?\d+$.
Those prefixes are either the start of a range, or a comparison:
\d+(-|\.\.) matches a number followed by a dash or two periods.
<=? matches "<" as well as "<=". Likewise for >=?. We can abbreviate this to [<>]=?.
Combining these two options using a pipe (|), which signifies choice, we get
^(\d+(-|\.\.)|[<>]=?)?\d+$
Try this expression:
^(?:\d+(?:(?:\.\.|-)\d+)?|[<>]=?\d+)(?:,\s*\d+(?:(?:\.\.|-)\d+)?|[<>]=?\d+)*$
It consists of the alternation of
\d+(?:(?:\.\.|-)\d+)? for a number followed by an optional expression for a range or sequence, and
[<>]=?\d+ for the inequalities.
That’s repeated in the second parts with a comma and optional whitespace for the list.
And for the condition of only allowing numbers less than 100, you can replace \d+ with [1-9]\d for 1..99 or (?:0|[1-9]\d) for 0..99.
You should totally use a regular expression tool like regex buddy.
You're trying to verify that your string generally looks like the sample?
1, 2-3, 4..5, <6, <=7, >8, >=9
matches
\s*(\d+|\d+-\d+|\d+\.\.\d+|[<>]=?\d+)\s*(,\s*(\d+|\d+-\d+|\d+\.\.\d+|[<>]=?\d+)\s*)*
It's easier to split on , and then match each part with
\s*(\d+|\d+-\d+|\d+\.\.\d+|[<>]=?\d+)\s*
That reads:
white space trimmed, match digits or digits dash digits, or digits dot dot digits, or one of less-than or greater-than with optional equal to digits.
You can compress that down to the harder to read:
\s*((\d+(-|\.\.)|[<>]=?)?\d+)\s*
If you want all your digits to be 1-2 digits only, then change all the \d+ to \d{1,2} or \d\d?