I am trying get this background to fade in on click. I found one tutorial that was helpful, and I ended up created the code so it has two images, and they fade in and out on click to bring up the picture.
Here's the work: http://www.mccraymusic.com/bgchangetest.html
Only a couple of issues though:
How do I make this work without the images getting selected at random? I'd like it to just switch from the plain black image to the image with the drum set. (And cross-fade to if possible, but not necessary)
How do I center the image on the page, so the image of the drums are centered?
I'm guessing this is what you're after:
$(function() {
var images = ["black.jpg","bg.jpg"];
$('<img>').attr({'src':'http://www.mccraymusic.com/assets/images/'+images[0],'id':'bg','alt':''}).appendTo('#bg-wrapper').parent().fadeIn(0);
$('.entersite').click(function(e) {
e.preventDefault();
var image = images[1];
$('#bg').parent().fadeOut(200, function() {
$('#bg').attr('src', 'http://www.mccraymusic.com/assets/images/'+image);
$(this).fadeIn(1000);
});
$(this).fadeOut(1000, function() {
$(this).remove();
});
});
});
DEMONSTRATION
Also added :
display: block;
margin-left: auto;
margin-right: auto;
to your #bg element to center the image.
Alright, assuming you use JQuery
You have #backgroundid and #imageid
Begin by setting
$('#backgroundid').css('opacity',1);
$('#imageid').css('opacity',0); // setting opacity (transparency) to 0, invisible
Now you have #buttonid.
Set up a jquery event so that when it's clicked, you fade out the background, and fade in the image using JQuery's animate.
$('#buttonid').click(function() {
$('#backgroundid').animate(function() {
opacity : 0 // fade it to 0 opacity, invisible
}, 1000); // animation will take 1000ms, 1second
$('#imageid').animate(function() {
opacity : 1 // fade it to full opacity, solid
}, 1000);
});
Now about that image centering.
You can either let css manage it with
body { /* Body or #imageid parent */
text-align : center;
}
#imageid {
margin: 0px auto;
}
Or you can stick to a JQuery solution, using absolute/fixed positioning.
First, use some css to fix the position of your image
#imageid {
position: absolute; // or fixed, if you want
}
Now use JQuery to reposition it
function positionImage() {
var imagewidth = $('#imageid').width();
var imageheight = $('#imageid').height();
$('#imageid').css('left', ($(window).width() - imagewidth) / 2);
$('#imageid').css('top', ($(window).height() - imageheight) / 2);
}
$(document).ready(positionImage); // bind the ready event to reposition
$(window).resize(positionImage); // on window resize, reposition image too
if you keep a div element with height and width as 100% and bgcolor as black. And then change the opacity of the div as desired to get the fade in/out effect, that should generate the same effect. I guess..
You are better off using any available jQuery plugin as they would have optimized and fixed bugs for multiple browsers.
Try lightBoxMe plugin
http://buckwilson.me/lightboxme/
This is the simplest plugin available!
Related
I have a image that is created to have 4 images in one See this image
Now, what I am trying to do is get the css to load just the first square at the top. Then when a user hovers over that image it will switch between all four images.
So it will display black on load, then when a user hovers over it, the image changes to red, then blue, then green, then back to black. It then repeats over and over until the mouse is moved off the image area.
I know that I can do this by converting the png to a gif but the image is generated outside of my control so this method is needed.
If anyone can help I will be forever grateful.
Cheers.
You should use CSS sprites and to make the change happend when over use setInterval function to change position ( here the height of each block of your image mesures 300px , so we incerement by +300 ) every defined interval time ,
Below snippet I've used .hover() jquery function to set and clear annimation .
var interval;
$(function(){
$("#image").hover(
function() {
var bottom = 0;
$this = $(this);
interval = setInterval(function() {
bottom >= 900 ? bottom = 0 : bottom+=300;
$this.css({'background-position' : '0px -'+bottom+'px'});
} , 1000)
},
function(){
$this.css({'background-position' : '0 0'})
clearInterval(interval);
}
);
});
#image {
width:150px;
height:150px;
background: url('https://i.stack.imgur.com/h8h14.png') 0 0px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="image" ><div>
I have the back to top button that appears when you reach a point on the page, which is working fine, however, when it appears the text is on two lines until the box has finished the animation to appear. So, is there anyway to prevent this? What I mean by the animation is: btt.show('slow');
Code:
$(document).ready(function () {
var btt = $('.back-to-top');
btt.on('click' , function(e) {
$('html, body').animate({
scrollTop: 0
}, 500);
btt.hide('slow');
e.preventDefault();
});
$(window).on('scroll', function () {
var self = $(this),
height = self.height(),
top = self.scrollTop();
if (top > 500) {
btt.show('slow');
} else {
btt.hide('slow');
}
});
});
Example: http://codepen.io/Riggster/pen/WvNvQm
The problem is caused by animating the width of a box, I think it might be better to animate the position of it instead, but - even better - lets use CSS animations!
$(window).on('scroll', function () {
if ($(window).scrollTop() >= 500) {
$(".button").addClass('show');
} else {
$(".button").removeClass('show');
}
});
#wrapper {
width: 100%;
height: 2000px;
}
.button {
position: fixed;
bottom: 50px;
right: -100px;
/* You might still need prefixes here. Use as preferred. */
transition: right 500ms;
}
.button.show {
right: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.0/jquery.min.js"></script>
<div id="wrapper">
<div class="button">Here's my button!</div>
</div>
I've defined your button as hidden by default, by giving it a position of right: -100px. When we hit the correct scroll position, we add the class show and that triggers the animation performed by CSS and not javascript, as we have the transition property for the property right defined - that way the browser does the heavy lifting.
Toggling show/hide alters your elements width. You either have to put it in a container with display: inline
Or more ideally you might want to change show/hide to jQuery fadeIn() / fadeOut() which is more appropriate for "Back to Top" indicators.
Here is your codepen example modified with inline container:
http://codepen.io/anon/pen/MwWweY
I've got an app that looks like a Windows desktop. There are icons that open draggable windows (divs) which display the content.
When I close a window, this happens:
$('#element'+boxId).animate({height: 0, opacity: 0}, 'fast');
When I open a window, this happens
$('#element'+boxId).slideDown();
Problem is, once a window is closed, I cannot reopen it. If I want to see that window again I have to refresh the page and then open it.
Is there some way to do a cool fade out that does not completely remove the element?
I have also tried regular old slideUp() but that does the same thing.
This works fine, just not as cool looking.
document.getElementById('element'+boxId).style.display = "none";
The problem is that you are hiding it by affecting the height and opacity, and those aren't being reset by the slideDown. Here's one option:
http://jsfiddle.net/uggVb/
$('#hide').click(function (e) {
e.preventDefault();
var $div = $('#theDiv');
$div.data('originalHeight', $div.css('height'));
$('#theDiv').animate({
height: 0,
opacity: 0
}, 'fast');
//$('#theDiv').slideUp('fast');
});
$('#show').click(function (e) {
e.preventDefault();
$('#theDiv').animate({
height: $('#theDiv').data('originalHeight'),
opacity: 1
}, 'fast');
//$('#theDiv').slideDown('fast');
});
You could use the slide functions instead of the animate functions, either work.
How about only using jQuery to add and remove a hide class and use CSS transitions for the properties you want to animate?
jQuery:
$('#whatever').click(function(ev) {
var $el = $('#element' + boxId);
$el.toggleClass('hide');
});
CSS:
#element { /* or #element{{boxId}} or some class added to those elements */
opacity: 1;
overflow: hidden;
width: 100px; height: 100px;
transition: height 300ms, opacity 300ms;
}
#element.hide {
opacity: 0;
height: 0;
}
See demo
Not sure if it is what you want but you can look into jQuery hide/show functions
$('#element'+boxId).hide();
if you want slower/faster animation you can give hide parameter which represents animation speed(in miliseconds)
$('#element'+boxId).hide(1000);
So on click of these polaroid like images, I replace them with <div class="poof"></div> using jQuery's .replaceWith(). The reason I do this is to display a poof animated gif animation that I style to that class with js.
However, on click of the .polaroid, the polaroid images, the .poof div replaces that html every time, but its background never shows.
Try it for yourself, here:
Click an image, it is replaced by the .poof div, but the poof animation doesn't show.
I would greatly appreciate it someone could help me figure out why this is and how to get the animation to show each time.
Here is my javascript:
$(function(){
var time=1;
$('.polaroid').click(function(){
$(this).replaceWith('<div class="poof"></div>');
$('.poof').css('height', $(this).height()).css('width', $(this).width()).css('background', 'transparent url(poof.gif?t='+time+') center no-repeat');
time++;
});
});
Here is .poof's CSS:
.poof{
height:32px;
width:32px;
}
You are getting the height and width of an object that was remove / replaced in the DOM
Change to this:
var heights = 32;
var widths = 32;
$('.polaroid').click(function(){
heights = $(this).height();
widths = $(this).width();
$('.poof').css('height', heights).css('width', widths).css('background', 'transparent url(http://i.imgur.com/FsVe2LC.gif?t='+time+') center no-repeat');
time++;
setTimeout(function(){
$('.poof').remove();
}, 1500);
});
I am trying to add a scroll event which will change the background of a div which also acts as the window background (it has 100% width and height). This is as far as I get. I am not so good at jquery. I have seen tutorials with click event listeners. but applying the same concept , like, returning scroll event as false, gets me nowhere. also I saw a tutorial on SO where the person suggest use of array. but I get pretty confused using arrays (mostly due to syntax).
I know about plugins like waypoints.js and skrollr.js which can be used but I need to change around 50-60 (for the illusion of a video being played when scrolled) ... but it wont be feasible.
here is the code im using:-
*
{
border: 2px solid black;
}
#frame
{
background: url('1.jpg') no-repeat;
height: 1000px;
width: 100%;
}
</style>
<script>
$(function(){
for ( i=0; i = $.scrolltop; i++)
{
$("#frame").attr('src', ''+i+'.jpg');
}
});
</script>
<body>
<div id="frame"></div>
</body>
Inside your for loop, you are setting the src attribute of #frame but it is a div not an img.
So, instead of this:
$("#frame").attr('src', ''+i+'.jpg');
Try this:
$("#frame").css('background-image', 'url(' + i + '.jpg)');
To bind a scroll event to a target element with jQuery:
$('#target').scroll(function() {
//do stuff here
});
To bind a scroll event to the window with jQuery:
$(window).scroll(function () {
//do stuff here
});
Here is the documentation for jQuery .scroll().
UPDATE:
If I understand right, here is a working demo on jsFiddle of what you want to achieve.
CSS:
html, body {
min-height: 1200px; /* for testing the scroll bar */
}
div#frame {
display: block;
position: fixed; /* Set this to fixed to lock that element on the position */
width: 300px;
height: 300px;
z-index: -1; /* Keep the bg frame at the bottom of other elements. */
}
Javascript:
$(document).ready(function() {
switchImage();
});
$(window).scroll(function () {
switchImage();
});
//using images from dummyimages.com for demonstration (300px by 300px)
var images = ["http://dummyimage.com/300x300/000000/fff",
"http://dummyimage.com/300x300/ffcc00/000",
"http://dummyimage.com/300x300/ff0000/000",
"http://dummyimage.com/300x300/ff00cc/000",
"http://dummyimage.com/300x300/ccff00/000"
];
//Gets a valid index from the image array using the scroll-y value as a factor.
function switchImage()
{
var sTop = $(window).scrollTop();
var index = sTop > 0 ? $(document).height() / sTop : 0;
index = Math.round(index) % images.length;
//console.log(index);
$("#frame").css('background-image', 'url(' + images[index] + ')');
}
HTML:
<div id="frame"></div>
Further Suggestions:
I suggest you change the background-image of the body, instead of the div. But, if you have to use a div for this; then you better add a resize event-istener to the window and set/update the height of that div with every resize. The reason is; height:100% does not work as expected in any browser.
I've done this before myself and if I were you I wouldn't use the image as a background, instead use a normal "img" tag prepend it to the top of your page use some css to ensure it stays in the back under all of the other elements. This way you could manipulate the size of the image to fit screen width better. I ran into a lot of issues trying to get the background to size correctly.
Html markup:
<body>
<img src="1.jpg" id="img" />
</body>
Script code:
$(function(){
var topPage = 0, count = 0;
$(window).scroll( function() {
topPage = $(document).scrollTop();
if(topPage > 200) {
// function goes here
$('img').attr('src', ++count +'.jpg');
}
});
});
I'm not totally sure if this is what you're trying to do but basically, when the window is scrolled, you assign the value of the distance to the top of the page, then you can run an if statement to see if you are a certain point. After that just simply change run the function you would like to run.
If you want to supply a range you want the image to change from do something like this, so what will happen is this will allow you to run a function only between the specificied range between 200 and 400 which is the distance from the top of the page.
$(function(){
var topPage = 0, count = 0;
$(window).scroll( function() {
topPage = $(document).scrollTop();
if(topPage > 200 && topPage < 400) {
// function goes here
$('#img').attr('src', ++count +'.jpg');
}
});
});