I am trying to add products to a database, along with some pictures, server-side is PHP. I want to upload everything asynchronously via AJAX. I want the pictures saved in a directory name after the product id ( thumbs/productID ).
The first part, which is submiting the product information and retrieving its id is done. However, when uploading the files, I can't upload both files and strings, to inform my script in which folder to save. I can however send only the files.
Is there any way to send both files and text at the same time? Any help would be appreciated.
$('#register-product').on('submit', function ( evt ) {
evt.preventDefault();
var i = 0, len = document.getElementsByName("images").length-1, reader, file;
var myFiles = document.getElementsByName("images");
// Adds all files to formdata
for ( ; i < len; i++ ) {
file = myFiles[i].files[0];
if (!!file.type.match(/image.*/)) {
if ( window.FileReader ) {
reader = new FileReader();
reader.readAsDataURL(file);
}
if (formdata) {
formdata.append("images[]", file);
}
}
}
// Send data to the server.
if (formdata) {
$.ajax({
url: "upload.php",
type: "POST",
// data: formdata, // This is correct
data: {formdata, id: 1}, // This doesn't work
processData: false,
contentType: false,
success: function (res) {
console.log(res);
}
});
}
});
Just append another value to your formdata:
//...
formdata.append("id", 1);
if (formdata) { //...
You can access it as you wont through $_POST["id"].
You can´t not send files with AJAX post request.
The header data for the files will not be sent.
So you need to do some iframe tricks or use the file API.
Related
Here i have a form in which i have a input type file to upload my file when the upload button is click i need to post the multipart/form-data to web api
where i upload the file to Minio Server.I have pasted the javascript and web api i use below.
When i press upload button after i get 500 (Internal Server Error).Help me with suggestions.
$("#upload").click(function () {
var file = new FormData($('#uploadform')[0]);
file.append('tax_file', $('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
url: 'http://localhost:53094/api/values',
data: file,
//use contentType, processData for sure.
contentType: "multipart/form-data",
processData: false,
beforeSend: function () {},
success: function (msg) {
$(".modal .ajax_data").html("<pre>" + msg +
"</pre>");
$('#close').hide();
},
error: function () {
$(".modal .ajax_data").html(
"<pre>Sorry! Couldn't process your request.</pre>"
);
$('#done').hide();
}
});
});
[HttpPost]
public string Post(IFormFile file)
{
try
{
var stream = file.OpenReadStream();
var name = file.FileName;
minio.PutObjectAsync("student-maarklist", "sample.jpeg", stream, file.Length);
return "Success";
}
catch (Exception ex)
{
return ex.Message;
}
}
I think you need not mention localhost just the path to the file will do. or replace it with IP of the localhost.
Sorry i have dont a mistake the name i appended in javascript is not save as the name i gave in web api.
I changed,
file.append('tax_file', $('input[type=file]')[0].files[0]);
To
file.append('file', $('input[type=file]')[0].files[0]);
and it worked .
I have created a small asp.net web forms application, to manage emails , i have created a little interface contains mandatory information to send a email, like from , to , subject etc. now i want to attach files to the email, i have used asp.net file upload controller to upload files,
and have to attach multiple files,
Now i want to send this details to code behind, so i thought the best way is to use ajax calls , because i don't want to refresh my page, but i can't figure out the way how to send the attached files to the server side,
i have read some articles and they saying i have to use FormData to send the files ,
then i have created a FormData object and appended all the attached files to the object.but how to pass this object to server side,
my js code as below,
function sendEmail() {
var data = new FormData();
var files = $('.attachment');
$.each(files, function (key, value) {
var file = $(value).data('file');
data.append(file.name, file);
});
$.ajax({
url: "OpenJobs.aspx/sendEmail",
type: "POST",
async: false,
contentType: false, // Not to set any content header
processData: false, // Not to process data
data: null,
success: function (result) {
alert(result);
},
error: function (err) {
alert(err.statusText);
}
});
}
Any help?
You need to use Generic handler to upload files using ajax, try below code:
function sendEmail() {
var formData = new FormData();
var files = $('.attachment');
$.each(files, function (key, value) {
var file = $(value).data('file');
formData.append(file.name, file);
});
$.ajax({
url: "FileUploadHandler.ashx",
type: "POST",
contentType: false, // Not to set any content header
processData: false, // Not to process data
data: formData,
success: function (result) {
alert(result);
},
error: function (err) {
alert(err.statusText);
}
});
}
Generic handler
<%# WebHandler Language="C#" Class="FileUploadHandler" %>
using System;
using System.Web;
public class FileUploadHandler : IHttpHandler
{
public void ProcessRequest (HttpContext context)
{
if (context.Request.Files.Count > 0)
{
HttpFileCollection files = context.Request.Files;
for (int i = 0; i < files.Count; i++)
{
HttpPostedFile file = files[i];
string fname = context.Server.MapPath("~/uploads/" + file.FileName);
file.SaveAs(fname);
}
context.Response.ContentType = "text/plain";
}
}
}
I have a React + Rails chat application and I want to add attachments to the same.
I'm using React Dropzone component to do attach images. Every time an image successfully gets added to the dropzone, it calls the attachToS3 function and posts that image to S3 as well. On successful posting it sets the state of new_message_content as the url of the file.
Once, the user has uploaded all the files, they can click on send which inserts the new_message_content as a new message in the conversation.
Since, I'm allowing users to add multiple files at the same time therefore my state only contains the url of the last uploaded file and not an array of all the URL's.
My dropzone is being rendered as follows:
renderFileDropzone() {
let componentConfig = { postUrl: 'random_url'},
djsConfig = { autoProcessQueue: true, addRemoveLinks: true },
eventHandlers = { addedfile: this.attachToS3.bind(this) };
return(
<div>
<div className="dashboard-modal">
<div className="dashboard-modal-content">
<div className="dashboard-modal-header">
<h5>Send files to {this.state.counterparty.name}</h5>
<span onClick={this.closeDropzone.bind(this)} className="icon-cancel modal-close"></span>
</div>
<form>
<div className="dashboard-modal-body">
<DropzoneComponent config={componentConfig} eventHandlers = {eventHandlers} djsConfig = {djsConfig} />
<button onClick={this.sendMessage.bind(this)} type="submit" className="btn btn-secondary">Send Files</button>
</div>
</form>
</div>
</div>
<div className="modal-bg bg-transparent-black"></div>
</div>
)
}
Now, my Dropzone component allows multiple file uploads at the same time but since I can't do a direct upload to Amazon S3 of multiple files at the same time so I pass the files, one by one.
attachToS3 function
attachToS3(file) {
let self = this;
API.get('user/s3_post_attachment', {filename : file.name}, function (s3_params) {
let formData = new FormData();
Object.keys(s3_params.formdata).forEach(function(k) {
formData.append(k, s3_params.formdata[k]);
});
formData.append('file', file);
$.ajax({
url: s3_params.url,
type: 'POST',
data: formData,
async: true,
dataType: "xml",
success: function (data) {
let file_url = $(data).find('Location').html();
self.setState({ new_message_content : file_url });
},
cache: false,
contentType: false,
processData: false
});
});
}
I tried adding a localStorage to my attachToS3 function, like this:
var url_array = JSON.parse(localStorage.getItem('allFiles'));
if (url_array == null) url_array = [];
var url = {
'url' : file_url
};
localStorage.setItem('url', JSON.stringify(url));
url_array.push(url);
localStorage.setItem('allURL', JSON.stringify(url_array));
But it's not working and I'm getting an error url_array.push is not a function.
Is there any way to get all the file url's in an array?
I am working on a simple chrome-extension that needs to upload files to the user's dropbox folder. I am using the simple AJAX requests as mentioned below to upload files, however it works for files with extensions such as .txt, .json, .c, etc i.e. files whose mime type is of type text/plain or similar type but all other file types such as pdfs, image files etc get corrupted and produce blank contents. What am I missing in uploading the files the correct way.
function startUpload()
{
var folderPath = $(this).closest('tr').attr('path')+'/';
var file = $("#upload_file")[0].files[0];
if (!file){
alert ("No file selected to upload.");
return false;
}
var reader = new FileReader();
reader.readAsText(file, "UTF-8");
reader.onload = function (evt) {
uploadFile(folderPath+file.name,evt.target.result,file.size,file.type);
}
}
//function to upload file to folder
function uploadFile(filepath,data,contentLength,contentType){
var url = "https://api-content.dropbox.com/1/files_put/auto"+filepath;
var headers = {
Authorization: 'Bearer ' + getAccessToken(),
contentLength: contentLength,
};
var args = {
url: url,
headers: headers,
crossDomain: true,
crossOrigin: true,
type: 'PUT',
contentType: contentType,
data : data,
dataType: 'json',
success: function(data)
{
getMetadata(filepath.substring(0,filepath.lastIndexOf('/')),createFolderViews);
},
error: function(jqXHR)
{
console.log(jqXHR);
}
};
$.ajax(args);
}
I believe the issue is reader.readAsTextFile(file, "UTF-8"). If the file isn't a text file, this will misinterpret the contents. I think you want reader.readAsBinaryString or reader.readAsArrayBuffer. (I haven't tested it myself.)
EDIT
After testing this myself, I found that readAsArrayBuffer is what you need, but you also need to add processData: false as an option to $.ajax to prevent jQuery from trying to convert the data to fields in a form submission.
Also be sure to use dataType: 'json' to properly parse the response from the server.
Without using any forms whatsoever, can I just send a file/files from <input type="file"> to 'upload.php' using POST method using jQuery. The input tag is not inside any form tag. It stands individually. So I don't want to use jQuery plugins like 'ajaxForm' or 'ajaxSubmit'.
You can use FormData to submit your data by a POST request. Here is a simple example:
var myFormData = new FormData();
myFormData.append('pictureFile', pictureInput.files[0]);
$.ajax({
url: 'upload.php',
type: 'POST',
processData: false, // important
contentType: false, // important
dataType : 'json',
data: myFormData
});
You don't have to use a form to make an ajax request, as long as you know your request setting (like url, method and parameters data).
All answers here are still using the FormData API. It is like a "multipart/form-data" upload without a form. You can also upload the file directly as content inside the body of the POST request using xmlHttpRequest like this:
var xmlHttpRequest = new XMLHttpRequest();
var file = ...file handle...
var fileName = ...file name...
var target = ...target...
var mimeType = ...mime type...
xmlHttpRequest.open('POST', target, true);
xmlHttpRequest.setRequestHeader('Content-Type', mimeType);
xmlHttpRequest.setRequestHeader('Content-Disposition', 'attachment; filename="' + fileName + '"');
xmlHttpRequest.send(file);
Content-Type and Content-Disposition headers are used for explaining what we are sending (mime-type and file name).
I posted similar answer also here.
UPDATE (January 2023):
You can also use the Fetch API to upload a file directly as binary content (as also was suggested in the comments).
const file = ...file handle...
const fileName = ...file name...
const target = ...target...
const mimeType = ...mime type...
const promise = fetch(target, {
method: 'POST',
body: file,
headers: {
'Content-Type': mimeType,
'Content-Disposition', `attachment; filename="${fileName}"`,
},
},
});
promise.then(
(response) => { /*...do something with response*/ },
(error) => { /*...handle error*/ },
);
See also a related question here: https://stackoverflow.com/a/48568899/1697459
Step 1: Create HTML Page where to place the HTML Code.
Step 2: In the HTML Code Page Bottom(footer)Create Javascript: and put Jquery Code in Script tag.
Step 3: Create PHP File and php code copy past. after Jquery Code in $.ajax Code url apply which one on your php file name.
JS
//$(document).on("change", "#avatar", function() { // If you want to upload without a submit button
$(document).on("click", "#upload", function() {
var file_data = $("#avatar").prop("files")[0]; // Getting the properties of file from file field
var form_data = new FormData(); // Creating object of FormData class
form_data.append("file", file_data) // Appending parameter named file with properties of file_field to form_data
form_data.append("user_id", 123) // Adding extra parameters to form_data
$.ajax({
url: "/upload_avatar", // Upload Script
dataType: 'script',
cache: false,
contentType: false,
processData: false,
data: form_data, // Setting the data attribute of ajax with file_data
type: 'post',
success: function(data) {
// Do something after Ajax completes
}
});
});
HTML
<input id="avatar" type="file" name="avatar" />
<button id="upload" value="Upload" />
Php
print_r($_FILES);
print_r($_POST);
Basing on this tutorial, here a very basic way to do that:
$('your_trigger_element_selector').on('click', function(){
var data = new FormData();
data.append('input_file_name', $('your_file_input_selector').prop('files')[0]);
// append other variables to data if you want: data.append('field_name_x', field_value_x);
$.ajax({
type: 'POST',
processData: false, // important
contentType: false, // important
data: data,
url: your_ajax_path,
dataType : 'json',
// in PHP you can call and process file in the same way as if it was submitted from a form:
// $_FILES['input_file_name']
success: function(jsonData){
...
}
...
});
});
Don't forget to add proper error handling
Try this puglin simpleUpload, no need form
Html:
<input type="file" name="arquivo" id="simpleUpload" multiple >
<button type="button" id="enviar">Enviar</button>
Javascript:
$('#simpleUpload').simpleUpload({
url: 'upload.php',
trigger: '#enviar',
success: function(data){
alert('Envio com sucesso');
}
});
A non-jquery (React) version:
JS:
function fileInputUpload(e){
let formData = new FormData();
formData.append(e.target.name, e.target.files[0]);
let response = await fetch('/api/upload', {
method: 'POST',
body: formData
});
let result = await response.json();
console.log(result.message);
}
HTML/JSX:
<input type='file' name='fileInput' onChange={(e) => this.fileInput(e)} />
You might not want to use onChange, but you can attach the uploading part to any another function.
Sorry for being that guy but AngularJS offers a simple and elegant solution.
Here is the code I use:
ngApp.controller('ngController', ['$upload',
function($upload) {
$scope.Upload = function($files, index) {
for (var i = 0; i < $files.length; i++) {
var file = $files[i];
$scope.upload = $upload.upload({
file: file,
url: '/File/Upload',
data: {
id: 1 //some data you want to send along with the file,
name: 'ABC' //some data you want to send along with the file,
},
}).progress(function(evt) {
}).success(function(data, status, headers, config) {
alert('Upload done');
}
})
.error(function(message) {
alert('Upload failed');
});
}
};
}]);
.Hidden {
display: none
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<script src="https://ajax.googleapis.com/ajax/libs/angularjs/1.2.23/angular.min.js"></script>
<div data-ng-controller="ngController">
<input type="button" value="Browse" onclick="$(this).next().click();" />
<input type="file" ng-file-select="Upload($files, 1)" class="Hidden" />
</div>
On the server side I have an MVC controller with an action the saves the files uploaded found in the Request.Files collection and returning a JsonResult.
If you use AngularJS try this out, if you don't... sorry mate :-)