I want to exclude characters from displaying in a vbulletin template.
For example, if a user writes:
"[Hello World] How are you?"
I want to ecxlude "[" and "]" all that's inside so it only displays:
"How are you?"
Is there a way to do this?
Use JavaScript string operations .getIndexOf() and .substring(). Get the position of the first bracket, get the position of the second bracket, split the string into 3 substrings, the middle section being between the two indexed values, and then add just the first and third substrings together. Like this:
var string = "[Hello World] How are you?";
var bracket1 = string.getIndexOf("[");
var bracket2 = string.getIndexOf("]");
var substring1 = string.substring(0,bracket1);
var substring2 = string.substring(bracket1,bracket2);
var substring3 = string.substring(bracket2,string.length);
var solution = substring 1 + " " + substring 3;
At least, that's the concept. Everything may not be right on, but you could futz with the numbers a little to get it perfect.
Or if you don't need to worry about what comes before [], simply use .split():
var string = "[Hello World] How are you?";
var solutionArray = string.split("]");
var solution = solutionArray[1];
Hope this helps!
Related
I have a string like this:
var myString = "MyString-[ADDAAD]-isGreat";
I want to extract this string into 3 parts:
var stringOne = "MyString-";
var stringTwo = "ADDAAD";
var stringThree = "-isGreat";
I know how to get the string between the two square brackets:
var matches = patternString.match(/\[(.*?)\]/);
now matches[1] contains ADDAAD
But how can I get the other two parts?
Select every character except -, [ and ] using bottom regex.
var myString = "MyString-[ADDAAD]-isGreat";
var parts = myString.match(/[^-\[\]]+/g);
console.log(parts);
So if you want to store values in custom variable, use bottom code
var stringOne = parts[0];
var stringTwo = parts[1];
var stringThree = parts[2];
You may split the string with your regex. Note that all the capturing group contents will be also part of the resulting array. To avoid empty items, you may add .filter(Boolean) after split().
See a JS demo below:
var myString = "MyString-[ADDAAD]-isGreat";
console.log(myString.split(/\[(.*?)]/).filter(Boolean));
console.log("s1-[s2]".split(/\[(.*?)]/).filter(Boolean));
Note you do not have to escape a ] used outside character classes, it is always parsed as a literal closing bracket if there is no corresponding [ before it.
I am trying to get the particular strings from the text below :
var str = "001AN_LAST_BRANCH_HYB_1hhhhh5_PBTsd_JENKIN.bin";
From this i have to get the following strings: "LAST", "BRANCH" and "JENKIN".
I used the code below to get "JENKIN";
var result = str.substr(str.lastIndexOf("_") +1);
It will get the result "JENKIN.bin". I need only "JENKIN".
Also the input string str sometimes contains this ".bin" string.
with substring() function you can extract text you need with defining start and end position. You have already found the start position with str.lastIndexOf("_") +1 and adding end position with str.indexOf(".") to substring() function will give you the result you need.
var result = str.substring(str.lastIndexOf("_") +1,str.indexOf("."));
It depends on how predictable the pattern is. How about:
var parts = str.replace(/\..+/, '').split('_');
And then parts[0] is 001AN, parts[1] is LAST, etc
You can use String.prototype.split to split a string into an array by a given separator:
var str = '001AN_LAST_BRANCH_HYB_1hhhhh5_PBTsd_JENKIN.bin';
var parts = str.split('_');
// parts is ['001AN', 'LAST', 'BRANCH', 'HYB', '1hhhhh5', 'PBTsd', 'JENKIN.bin'];
document.body.innerText = parts[1] + ", " + parts[2] + " and " + parts[6].split('.')[0];
You could do that way:
var re = /^[^_]*_([^_]*)_([^_]*)_.*_([^.]*)\..*$/;
var str = "001AN_LAST_BRANCH_HYB_1hhhhh5_PBTsd_JENKIN.bin";
var matches = re.exec(str);
console.log(matches[1]); // LAST
console.log(matches[2]); // BRANCH
console.log(matches[3]); // JENKIN
This way you can reuse your RegExp anytime you want, and it can be used in other languages too.
Try using String.prototype.match() with RegExp /([A-Z])+(?=_B|_H|\.)/g to match any number of uppercase letters followed by "_B" , "_H" or "."
var str = "001AN_LAST_BRANCH_HYB_1hhhhh5_PBTsd_JENKIN.bin";
var res = str.match(/([A-Z])+(?=_B|_H|\.)/g);
console.log(res)
I don't know why you want to that, but this example would be helpful.
It will be better write what exactly you want.
str = '001AN_LAST_BRANCH_HYB_1hhhhh5_PBTsd_JENKIN.bin'
find = ['LAST', 'BRANCH', 'JENKINS']
found = []
for item in find:
if item in str:
found.append(item)
print found # ['LAST', 'BRANCH']
so my idea is like this..
var songList = ["1. somesong.mid","13. abcdef.mid","153. acde.mid"];
var newString = myString.substr(4); // i want this to dynamically trim the numbers till it has reached the .
// but i wanted the 1. 13. 153. and so on removed.
// i have more value's in my array with different 'numbers' in the beginning
so im having trouble with this can anyone help me find a more simple solution which dynamically chop's down the first character's till the '.' ?
You can do something like
var songList = ["1. somesong.mid","13. abcdef.mid","153. acde.mid"];
songList.forEach(function(value, i){
songList[i] = value.replace(/\d+\./, ''); //value.substr(value.indexOf('.') + 1)
});
Demo: Fiddle
You can use the string .match() method to extract the part up to and including the first . as follows:
var newString = myString.match(/[^.]*./)[0];
That assumes that there will be a match. If you need to allow for no match occurring then perhaps:
var newString = (myString.match(/[^.]*./) || [myString])[0];
If you're saying you want to remove the numbers and keep the rest of the string, then a simple .replace() will do it:
var newString = myString.replace(/^[^.]*. */, "");
I have a string like this : SPList:6E5F5E0D-0CA4-426C-A523-134BA33369D7?SPWeb:C5DD2ADA-E0C4-4971-961F-233789297FE9:.
Using Javascript, I would like to extract the two IDs (which can be different) : 6E5F5E0D-0CA4-426C-A523-134BA33369D7 and C5DD2ADA-E0C4-4971-961F-233789297FE9.
I'm using this regular expression : ^SPList\:(?:[0-9A-Za-z\-]+)\?SPWeb\:(?:[0-9A-Za-z\-]+)\:$.
I expect this expression to extract into two matching groups the two IDs.
By now, my code is :
var input = "SPList:6E5F5E0D-0CA4-426C-A523-134BA33369D7?SPWeb:C5DD2ADA-E0C4-4971-961F-233789297FE9:";
var myregex = /^SPList\:(?:[0-9A-Za-z\-]+)\?SPWeb\:(?:[0-9A-Za-z\-]+)\:$/g;
var match = input.match(myregex);
var listId = match[0];
var webId = match[1];
However, this is not working as expected. The first match contains the whole string, and the second match is undefined.
What is the proper way to extract my ID's?
Here is a jsfiddle that illustrate my issue.
This should suit your needs:
var regex = /^SPList:([0-9A-F-]+)[?]SPWeb:([0-9A-F-]+):$/g;
var match = regex.exec(input);
var listId = match[1];
var webId = match[2];
I simply replaced the non-capturing groups of your initial regex by capturing groups, and used regex.exec(input) instead of input.match(regex) to get the captured data. Also, since the IDs seem to be hexadecimal values, I used A-F instead of A-Z.
try this:
var myregex = /[^\:]([0-9A-Z\-]+)[^\?|\:]/g;
var match = input.match(myregex);
alert("listID: " + match[1] + "\n" + "webID: " + match[3]);
I want to use regular expression in javascript to extract values. The string is in this pattern "title{position}", how should i get title and position in this example?
Assuming that's all there is too it (no nesting of '{}'s or anything) (\w+)\{(\w+)\} will match that instance and group the results as groups 1 and 2. Do you need anything more complicated like a collection of many of these per string or is that enough?
Is that string everything? If so there's no need for matching. Just split the string!
var str = "foo{bar}";
var pieces = str.split(/\{|\}/);
var title = pieces[0];
var position = pieces[1];
alert("Title: " + title + "\nPosition: " + position);
Demonstrated here
If you did want to add results to a structure -
var arr = [];
var text = 'title{position}';
text.replace(/(\w+){(\w+)}/g, function(m, key, value){
//alert('title is-'+key);
//alert('position is-'+value);
arr.push({"title":key,"position":value});
});
console.log(arr);
Demo - http://jsfiddle.net/Sr6Ed/1/