Develop Reference

How to change div style on the places of loading web?

I just started creating these Loading bar by me:
<div id="loading">
<div style="width: 650px;height: 40px;background-color: white;left:calc(50% - 325px);top: calc(50% - 20px);position: absolute;">
<div style="width:640px;height:30px;background-color:#0087cc;margin-top:5px;margin-left:5px">
<div id="myBtn" style="width:20px;height:30px;background-color:white;transition: all 2s;transition: all 0.5s ease 0s;">
</div>
</div>
</div>
</div>
The white bar is increasing from left to right , so on the end of web page i put these JS - so it makes end of loading bar and change display property o whole loading div :
$(window).load(function() {
document.getElementById("myn").style.width = "640px";
setTimeout(function(){$('#loading').fadeOut()}, 2700);
})
But I need to change the div width of that bar on the most place (for example after loading 10 picture change with to 100px and after loading another 10 pics change with to 200px ect ) on the web to create progress change of loading bar when the page will loading.
How can I change that div width on the most places of web to create continuously move of loading bar on loading web page.
And : I dont want to use Progressbar, I like to make things by myself :-)
Thanks for your help

The following code snippet wil do, as far as I understand, what you want. On a press of a button (or when some images are loaded), the width will increase by 16 pixels. This could be any variable and jQuery can be used to animate it as well. This is just an example to illustrate the principle.
$('#button').click(function() {
var width = $('.progress').width();
if (width < 256) {
width = width + 16;
$('.progress').width(width)
}
});
div.progress-bar {
width: 256px;
height: 32px;
border: 1px solid black;
}
div.progress {
width: 0px;
height: 100%;
background-color: #e0e0e0;
}
button#button {
margin-top: 32px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="progress-bar">
<div class="progress">
</div>
</div>
<button id="button">MORE PROGRESS!</button>

Finally i Use this code to change div width on the place of loading web :
//First is width 20 in the css
#myBtn {width:20px;height:30px;background-color:white;transition: all 0.5s ease 0s;}
**The HTML :**
// width 62.5% after load div#2013
$('#2013').load("load" , function() {
$('#myBtn').css('width', '62.5%');
});
some images
//last 100% after load div#2010 with images and with fadeout
$('#2010').load("load" , function() {
$('#myBtn').css('width', '100%');
setTimeout(function(){$('#loading').fadeOut()}, 2700);
});

JavaScript - Make an image turn white on click

I've got a bunch of images, on click I want the images to turn white emulating some kind of fade effect. So you click it and for 1 second it fades from the original image to just white. I also need it to turn back to the original image when the user clicks something else.
Is this possible with JavaScript? - If so what should I be looking at (I'm really bad with graphics).
I've had a go at trying this with opacity but I don't want the background to be visible behind the image

Psuedo-element Solution
You could use a wrapper with a pseudo-element to overlay what you're looking for -- and the animations are handled by a toggled CSS class (which is ideal for performance).
CodePen Demonstration
HTML
<div class="whiteclicker">
<img src="http://lorempixel.com/400/200" alt=""/>
</div>
SCSS
#import "compass/css3/transition";
body { background: gainsboro; text-align: center; }
.whiteclicker {
display: inline-block;
position: relative;
&::after {
content: "";
display: block;
position: absolute;
top:0; left:0; right:0; bottom:0;
background: white;
opacity: 0;
#include transition(opacity 1s ease);
}
&.active::after {
opacity: 1;
}
}
JS
$('.whiteclicker').click(function(){
$(this).toggleClass('active');
});

To ameliorate the Spencer Wieczorek solution (the way two seems to be the best solution on my opinion) :
What about creating the white div on the fly (and fade it in and out) instead of put it in the html code ?
See the fiddle.
$("#myImage").click(function(){
$(this)
.parent().css({position:'relative'}).end()
.after($('<div>')
.hide()
.css({position:'absolute'
, top: $(this).position().top
, left: $(this).position().left
, width: $(this).width()
, height: $(this).height()
, background: '#FFF'
})
.fadeIn('fast')
.on({
click : function(e){
$(this).fadeOut('fast', function(){ $(this).remove();});
}
})
);
});
Then, you don't have anything to add to the html code or in the css styles, Jquery does everything.
#Spencer Wieczorek : I did my own answer, because I did not agree with your way of designing the css style (the fixed position is really not good, especially if the page is scrolled for example...). Mine is more ... standalone-y ;)

You might want to try having two images stacked on each other.
See this:
<script type="text/javascript">
var image1 = '<img class="images" src="Image 1" onClick="switch();" />';
var image2 = '<img class="images" src="Image 2" onClick="switch();" />';
var currentImage = 1;
function switch(){
if(currentImage==1){
currentImage++;
document.getElementById("image").innerHTML = image2;
}
if(currentImage==2){
currentImage--;
document.getElementById("image").innerHTML = image1;
}
}
</script>
<style>
.images{ position:fixed; top: 0; left: 0; }
</style>
<img class="images" src="Black image" />
<div id="image"><img class="images" src="Image 1" onClick="switch();" /></div>
For the fade I'm just gonna see how you could do it.
EDIT:
<script type="text/javascript">
var fadecount = 100;
function fade() {
document.getElementById("imageToFade").style.opacity = fadecount;
fadecount--;
if(fadecount==0){
clearTimeout(fade);
}
}
function start_fade(){
var fade = setTimeout(fade(), 10);
}
</script>

With Base 64 you can just have the binary version of the picture and then an all white picture and based on the .click you reassign the src to the white base64...
document.getElementById("img").src = "data:image/png;base64, iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg=="
just change to the all white version after the click, technically js driven from click event, and doesn't involve two different elements existing just at different layers...

show loading icon until the page is load?

I wanted to show a loading icon to users until the page elements are fully loaded. How can I do that with javascript and I want to do it with javascript, not jquery?
Here is a link how google does it
How can I do this?
triggering some function on onload event or something like this .. I know it will be done somewhat like this or any other ways to do it?
Or there is some event for it?
UPDATE
I did something using display property I hide the body element but and onload of body tag I change its property but where to put the loading icon and add more interactivity.

HTML
<body>
<div id="load"></div>
<div id="contents">
jlkjjlkjlkjlkjlklk
</div>
</body>
JS
document.onreadystatechange = function () {
var state = document.readyState
if (state == 'interactive') {
document.getElementById('contents').style.visibility="hidden";
} else if (state == 'complete') {
setTimeout(function(){
document.getElementById('interactive');
document.getElementById('load').style.visibility="hidden";
document.getElementById('contents').style.visibility="visible";
},1000);
}
}
CSS
#load{
width:100%;
height:100%;
position:fixed;
z-index:9999;
background:url("/loading.gif") no-repeat center center rgba(0,0,0,0.25)
}
Note:
you wont see any loading gif if your page is loaded fast, so use this code on a page with high loading time, and i also recommend to put your js on the bottom of the page.
DEMO
http://jsfiddle.net/6AcAr/ - with timeout(only for demo)
http://jsfiddle.net/47PkH/ - no timeout(use this for actual page)
update
http://jsfiddle.net/d9ngT/

The easiest way to put the loader in the website.
HTML:
<div id="loading"></div>
CSS:
#loading {
position: fixed;
width: 100%;
height: 100vh;
background: #fff url('images/loader.gif') no-repeat center center;
z-index: 9999;
}
JQUERY:
<script>
jQuery(document).ready(function() {
jQuery('#loading').fadeOut(3000);
});
</script>

add class="loading" in the body tag then use below script with follwing css code
body {
-webkit-transition: background-color 1s;
transition: background-color 1s;
}
html, body { min-height: 100%; }
body.loading {
background: #333 url('http://code.jquery.com/mobile/1.3.1/images/ajax-loader.gif') no-repeat 50% 50%;
-webkit-transition: background-color 0;
transition: background-color 0;
opacity: 0;
-webkit-transition: opacity 0;
transition: opacity 0;
}
Use this code
var body = document.getElementsByTagName('body')[0];
var removeLoading = function() {
setTimeout(function() {
body.className = body.className.replace(/loading/, '');
}, 3000);
};
removeLoading();
Demo: https://jsfiddle.net/0qpuaeph/

HTML, CSS, JS are all good as given in above answers. However they won't stop user from clicking the loader and visiting page. And if page time is large, it looks broken and defeats the purpose.
So in CSS consider adding
pointer-events: none;
cursor: default;
Also, instead of using gif files, if you are using fontawesome which everybody uses now a days, consider using in your html
<i class="fa fa-spinner fa-spin">

Element making ajax call can call loading(targetElementId) method as below to put loading/icon in target div and it'll get over written by ajax results when ready. This works great for me.
<div style='display:none;'><div id="loading" class="divLoading"><p>Loading... <img src="loading_image.gif" /></p></div></div>
<script type="text/javascript">
function loading(id) {
jQuery("#" + id).html(jQuery("#loading").html());
jQuery("#" + id).show();
}

HTML page
<div id="overlay">
<img src="<?php echo base_url()?>assest/website/images/loading1.gif" alt="Loading" />
Loading...
</div>
Script
$(window).load(function(){
//PAGE IS FULLY LOADED
//FADE OUT YOUR OVERLAYING DIV
$('#overlay').fadeOut();
});

firstly, in your main page use a loading icon
then, delete your </body> and </HTML> from your main page and replace it by
<?php include('footer.php');?>
in the footer.php file type :
<?php
$iconPath="myIcon.ico" // myIcon is the final icon
echo '<script>changeIcon($iconPath)</script>'; // where changeIcon is a javascript function whiwh change your icon.
echo '</body>';
echo '</HTML>';
?>

css transition with javascript has no transition

when I try to make a simple transition with pure CSS all works fine.
But when I try to call a javascript-function which modiefies the CSS when clicked on a link, there is no transition. I want to fade in a grey layer.
HTML:
<a href="someImage.jpg" id="test">
<img src="someImage.jpg" alt="" />
</a>
<section id="grey">
</section>
JS:
var grey = document.getElementById("grey");
var link = document.getElementById("test");
link.onclick = function () {
grey.style.display = "block";
grey.style.opacity = "1";
return false;
};
CSS:
section {
display:none;
size and position...
opacity: 0;
background-color: rgba(0,0,0,0.5);
transition: opacity 1s .5s;
}
(see http://jsfiddle.net/7zEhx/5/ )
I'm using FF22, does anyone know any solutions?

display: none elements don’t transition, and the display: block hasn’t kicked in before you set the other style. There are horrible hacks like this:
setTimeout(function() {
grey.style.opacity = "1";
}, 0);
But I’d just set width to 0 instead of setting display and then put it back at 100%.
Updated jsFiddle

jQuery fade to new image

How can I fade one image into another with jquery? As far as I can tell you would use fadeOut, change the source with attr() and then fadeIn again. But this doesn't seem to work in order. I don't want to use a plugin because I expect to add quite a few alterations.
Thanks.

In the simplest case, you'll need to use a callback on the call to fadeOut().
Assuming an image tag already on the page:
<img id="image" src="http://sstatic.net/so/img/logo.png" />
You pass a function as the callback argument to fadeOut() that resets the src attribute and then fades back using fadeIn():
$("#image").fadeOut(function() {
$(this).load(function() { $(this).fadeIn(); });
$(this).attr("src", "http://sstatic.net/su/img/logo.png");
});
For animations in jQuery, callbacks are executed after the animation completes. This gives you the ability to chain animations sequentially. Note the call to load(). This makes sure the image is loaded before fading back in (Thanks to Y. Shoham).
Here's a working example

$("#main_image").fadeOut("slow",function(){
$("#main_image").load(function () { //avoiding blinking, wait until loaded
$("#main_image").fadeIn();
});
$("#main_image").attr("src","...");
});

Well, you can place the next image behind the current one, and fadeOut the current one so that it looks like as though it is fading into the next image.
When fading is done, you swap back the images. So roughly:
<style type="text/css">
.swappers{
position:absolute;
width:500px;
height:500px;
}
#currentimg{
z-index:999;
}
</style>
<div>
<img src="" alt="" id="currentimg" class="swappers">
<img src="" alt="" id="nextimg" class="swappers">
</div>
<script type="text/javascript">
function swap(newimg){
$('#nextimg').attr('src',newimg);
$('#currentimg').fadeOut(
'normal',
function(){
$(this).attr('src', $('#nextimg').attr('src')).fadeIn();
}
);
}
</script>

Are you sure you're using the callback you pass into fadeOut to change the source attr and then calling fadeIn? You can't call fadeOut, attr() and fadeIn sequentially. You must wait for fadeOut to complete...

Old question but I thought I'd throw in an answer. I use this for the large header image on a homepage. Works well by manipulating the z-index for the current and next images, shows the next image right under the current one, then fades the current one out.
CSS:
#jumbo-image-wrapper
{
width: 100%;
height: 650px;
position: relative;
}
.jumbo-image
{
width: 100%;
height: 100%;
position: absolute;
top: 0px;
left: 0px;
}
HTML:
<div id="jumbo-image-wrapper">
<div class="jumbo-image" style="background-image: url('img/your-image.jpg');">
</div>
<div class="jumbo-image" style="background-image: url('img/your-image-2'); display: none;">
</div>
</div>
Javascript (jQuery):
function jumboScroll()
{
var num_images = $("#jumbo-image-wrapper").children(".jumbo-image").length;
var next_index = jumbo_index+1;
if (next_index == num_images)
{
next_index = 0;
}
$("#jumbo-image-wrapper").children(".jumbo-image").eq(jumbo_index).css("z-index", "10");
$("#jumbo-image-wrapper").children(".jumbo-image").eq(next_index).css("z-index", "9");
$("#jumbo-image-wrapper").children(".jumbo-image").eq(next_index).show();
$("#jumbo-image-wrapper").children(".jumbo-image").eq(jumbo_index).fadeOut("slow");
jumbo_index = next_index;
setTimeout(function(){
jumboScroll();
}, 7000);
}
It will work no matter how many "slides" with class .jumbo-image are in the #jumbo-image-wrapper div.

For those who want the image to scale according to width percentage (which scale according to your browser width), obviously you don't want to set height and width in PIXEL in CSS.
This is not the best way, but I don't want to use any of the JS plugin.
So what can you do is:
Create one same size transparent PNG and put an ID to it as
second-banner
Name your original image as first-banner
Put both of them under a DIV
Here is the CSS structure for your reference:
.design-banner {
position: relative;
width: 100%;
#first-banner {
position: absolute;
width: 100%;
}
#second-banner {
position: relative;
width: 100%;
}
}
Then, you can safely fade out your original banner without the content which placed after your image moving and blinking up and down