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post data from one page to another on button click using java script

<form name="payform" action="payment.html" method="POST">
Amount: <input type="text" id="amount">
<button id="buttonPay" type="submit" onclick="someFunction()">Submit</button>
</form>
I need to post the text box content along with some variables which are defined outside of the form.

To pass any data with a form submit you could add an input hidden tag inside your form (it has to be inside the form tag):
<input type="hidden" name="varKey" value="varVal" />
If the data lies outside the form tag for some reason, use jQuery to get the data and update the hidden tag's value

<?php
$out_side_var = "myData";
?>
<form name="payform" action="payment.html" method="POST">
Amount: <input type="text" id="amount">
<input type="hidden" name="myData" id="myData" value='<?php echo $out_side_var ?>'>
<button id="buttonPay" type="button" onclick="someFunction()">Submit</button>
</form>

2 second interval before the auto save button in form

Can I Make a 2 second interval before the auto-save perform? this code shows my webpage with a single textbox in it, and it auto show my DTRSearch.php result. This code is working perfectly.
<div id="search">
<input type="text" placeholder="Scan" id="t1" name="t1" onkeyup="aa();"
autofocus/></div>
<script type="text/javascript">
function aa(){
xmlhttp=new XMLHttpRequest();
xmlhttp.open("GET","DTRSearch.php?
nmnm="+document.getElementById("t1").value,false);
xmlhttp.send(null);
document.getElementById("searchdiv").innerHTML=xmlhttp.responseText;
document.getElementById("searchdiv").style.visibility='visible';
}
</script>
<div id="searchdiv" style="visibility:hidden; position:absolute">
</div>
DTRSearch.php it query a single row, this a simple form with a submit button, i want this form to perform an auto-save but before that it should show the form for 2 second
<form action="GetDTRSearch.php" method="get">
<input type="text" value="<?php echo $id_number;>" name="ID_Number" /><br />
<input type="text" value="<?php echo $fullname; ?>"name="Fullname" /><br />
<p class="Ok"><input type="submit" value="Click Confirm" /></p>

Change the button to a simple button instead of an input type submit. Instead, add a click listener to the Submit button. The click listener should call a setTimeout() function to execute the form submission after 2 seconds.
<form id="theForm" action="DTRSearch.php" method="get">
<input type="text" value="<?php echo $id_number;>" name="ID_Number" /><br />
<input type="text" value="<?php echo $fullname; ?>"name="Fullname" /><br />
<p class="Ok"><button id="submitButton" value="Click Confirm" /></p>
Then, assuming you have JQuery, add the following script:
<script>
$(document).ready(function() {
$("#submitButton").click(function() {
setTimeout(function() {
$("#theForm").submit();
}, 2000);
});
});
</script>

This is the sample html code you need to change.
<form name="myForm" id="myForm" action="GetDTRSearch.php" method="get">
<input type="text" value="<?php echo $id_number;>" name="ID_Number" /><br />
<input type="text" value="<?php echo $fullname; ?>"name="Fullname" /><br />
<p class="Ok"><input type="submit" value="Click Confirm" /></p>
</form>
Below code the form will be automatically post back to server after 2 seconds to the action method.
make sure this code will be executed after the data will fetch from DTRSearch.php else it will send blank value to the server. You can use this on submit click or you can directly make function and call this after data is fetched.
setTimeout(function() {
document.forms["myForm"].submit();
}, 2000);

how to give name in auto submit form javascript

This is my code that I am using to submit form with post value
<form action="<?php echo DOMAIN; ?>contact/booking-form.php" method="post">
<input type="text" name="name" value="<?php echo $name; ?>" />
<input type="text" name="email" value="<?php echo $email; ?>" />
<input type="submit" name="submit" id="submit" />
<script>document.getElementById('submit').submit();</script>
</form>
Can anybody help me to pass name="submit" value of submit button to another page?

A submit button is only going to be a successful control if it is used to submit the form (and even then only if it has a name and a value … which yours does not).
If you want submit=submit in your form data when you submit the form with JavaScript, then don't use a submit button to put that data in the form in the first place. Use a hidden input.
<input type="submit">
<input type="hidden" name="submit" id="submit" value="submit">
Then you have two other problems.
First, submit is a method of form elements, not inputs. So you need to change your script to call the right element.
<script>document.getElementById('submit').form.submit();</script>
Second, if a form has a control called submit then that will clobber the submit method. So you need to get one from a different form (not supported in old versions of Internet Explorer):
<script>
var form = document.getElementById('submit').form;
var submit_method = document.createElement("form").submit;
submit_method.call(form);
</script>

<form id=submit action="<?php echo DOMAIN; ?>contact/booking-form.php" name="form1" method="post">
<input type="text" name="name" value="<?php echo $name; ?>" />
<input type="text" name="email" value="<?php echo $email; ?>" />
</form>
<script >
document.form1.submit()
</script>

there is no sumit button in your code. first add in html
<input type="submit" value="submit" id="submit"/>
<script>
document.getElementById("submit").value = "newSubmitButtonValue";
</script>

Two actions two submit button in php?

I've form tag like this
sample name:register.php page
<form id="formElem" name="formElem" action="form10.php" method="post">
<input id="pd" name="pd" type="text" AUTOCOMPLETE=OFF />
<input id="pd1" name="fname" type="text" AUTOCOMPLETE=OFF />
<input id="pd2" name="mname" type="text" AUTOCOMPLETE=OFF />
<input id="pd2" name="lname" type="text" AUTOCOMPLETE=OFF />
6 more input boxes
<button name="submit" type="submit">Register</button>
<button name="preview" type="submit">Preview</button>
</form>
I'm sending this info to next form10.php page and displaying all the 10 input values on that page
I'm using $pd= htmlentities($_POST['pd']); $fname= htmlentities($_POST['fname']); to fetch values from form tag and such 10 variables and I'm echoing those entered value
on form10.php file after successful submit button.
like i entered fname, mname, lname came from form tag and displayed on form10.php page.
first name <?echo $fname?>
but now problem is user can see the next page (form10.php) after entering only 10 textboxes values inside form tag.
but I want to give preview option to user so that user can preview that next page either filling any of 1 to 10 textbox values. means he has filled fname and lname but not rest of 8 fields and he clicks on preview button I want to open form10_preview.php which same as form10.php but as user has entered only fname and lname so echo only those values which he as supplied.
Now problem is how can i can have two submit button and two actions in one form?

I think it is better to control form submit rules clientside. Remove the action from your form, and change the button type to be button :
<form id="formElem" name="formElem" action="" method="post">
<input id="pd" name="pd" type="text" AUTOCOMPLETE=OFF />
<input id="pd1" name="fname" type="text" AUTOCOMPLETE=OFF />
<input id="pd2" name="mname" type="text" AUTOCOMPLETE=OFF />
<input id="pd2" name="lname" type="text" AUTOCOMPLETE=OFF />
6 more input boxes
<button id="register" type="button">Register</button>
<button id="preview" type="button">Preview</button>
</form>
Then let javascript control the flow of the submitting :
var formElem = document.getElementById('formElem'),
btnSubmit = document.getElementById('register'),
btnPreview = document.getElementById('preview');
function formSubmit() {
switch (this.id) {
case 'register' :
formElem.action='post10.php';
break;
case 'preview' :
formElem.action='preview10.php';
break;
}
formElem.submit();
}
btnSubmit.onclick = formSubmit;
btnPreview.onclick = formSubmit;

You could have the form point to its own page and handle each submit value separately. At the top of the file with the form, you'll need to start the output buffer and a session. This allows the use of header() to redirect, and storage of session variables.
<?php
ob_start();
session_start();
?>
The form will point to itself by removing the action attribute:
<form id="formElem" name="formElem" method="post">
<input id="pd" name="pd" type="text" AUTOCOMPLETE=OFF />
<input id="pd1" name="fname" type="text" AUTOCOMPLETE=OFF />
<input id="pd2" name="mname" type="text" AUTOCOMPLETE=OFF />
<input id="pd2" name="lname" type="text" AUTOCOMPLETE=OFF />
6 more input boxes
<button name="submit" type="submit">Register</button>
<button name="preview" type="submit">Preview</button>
</form>
We process each of the buttons via their name in the POST array:
<?php
if(isset($_POST['submit'])){
foreach ($_POST as $key => $value) {
$_SESSION[$key] = $value;
}
header("Location: form10.php");
}
if(isset($_POST['preview'])){
foreach ($_POST as $key => $value) {
$_SESSION[$key] = $value;
}
header("Location: form10_preview.php");
}
?>
And at the very end of the file, we flush the output buffer:
<?php ob_end_flush(); ?>
So, essentially the form has one action, which is to submit the values to itself. Finally, both form10.php and form10_preview.php will need session_start(); at the top of the file to access the Session variables we've created, like so:
<?php
session_start();
$inputs = array("pd", "fname", "mname", "lname", etc...);
foreach ($inputs as $input) {
echo $_SESSION[$input];
}
?>

Form post Send data to another page , verify and then post

I have a form with ,
In the form after user clicks on Submit , he will be taken to another page which would show all the data entered, Which would allow the user to verify the content.(User will have a look at the content , to see what he entered is correct).
Once user verifies he would submit the data and Insert to DB should be done.
I want to know a method in which i could carry on the approach, to do this.
How can i implement this
EDIT MORE EXPLAIN
addemp.php
The Main Div With Form
<div class="panel-body">
<form>
Employee : <input Type="text" id="name">
<input type="submit" value="check">
</div>
The Second Div in the same form should show once submit is clicked
<div class="submit panel-body">
<form>
Employee : <Employee Name asin main div>
<input type="submit" > <--! this submit would post data
</form>
</div>
how to pass the value from 1st div to the second , and from the second INSERT to db.how can i do without page refresh ?

Use following script on location file
$action='';
if(isset($_POST['submit'])){
//create form here
//Change the action of form
$action = 'save.php';
}
echo '<form method="POST" action="'.$action.'">
<input type="text" name="nric" value="'.isset($_POST['nric'])?$_POST['nric'].'" />
<input type="text" name="empName" value="'.isset($_POST['empName'])?$_POST['empName'].'" />
<input type="text" name="location" value="'.isset($_POST['location'])?$_POST['location'].'" />
<input type="submit" value="Submit"/>
</form>';

EDIT: You don't need to use a form in this case. You can simply use JQuery to show the data from text boxes in a DIV and a button that will POST the data for you on the server.
<input type="text" name="nric" id="nric" />
<input type="text" name="empName" id="empName" />
<input type="text" name="location" id="location" />
<input id="sndData" type="button" value="Submit" />
<div id="showData"></div>
JQuery:
$('#sndData').click(function(){
var makeData = "<p>NRIC: "+$('#nric').val()+"</p><p>Employee Name: "+$('#empName').val()+"</p><p>Location: "+$('#location').val()+"</p>";
$('#showData').html(makeData);
});
When you've done that, just create/show a HTML button that will POST the data for you.
If this answers your question, please mark it as an answer.