Develop Reference

I want to update value from DB. but my code won't work

Main
public function update_sample(){
$id3 = sanitize($this->input->post('id3'));
$sample3 = sanitize($this->input->post('sample3'));
if($this->session->userdata('position_id') != ""){
$username = $this->model->get_users($this->session->userdata('user_id'))->row()->username;
$query = $this->model->update_sample($data);
$data = array(
"success" => 1,
"message" => 'Note: You have successfully updated');
}else{
$this->logout();
}
generate_json($data);
}
model
public function update_sample($sample){
$sql = "UPDATE test SET sample=? WHERE id=? AND enabled= 1";
$data = array($sample);
return $this->db->query($sql, $data);
}
js
$("#table-grid").delegate(".btnUpdate", "click", function(){
var id = $(this).data('value');
$.ajax({
type: 'post',
url: base_url+'Main/view_details',
data: {'id3': id},
success: function(data){
var res1 = data.result1;
if(data.success==1){
document.getElementById("sample3").value = res1[0].samples;
$('#update').modal();
}
}
});
});
I want to update Data from database I've been stuck here for long.

I don't know how your class is created, but it looks like your function only returns true for query execution, you'll need to check for "affected_rows".
Try the code below, with a little luck it may work, otherwise you have to check the $result variable and modify the code corresponding to the result.
public function update_sample($sample){
$sql = "UPDATE test SET sample=? WHERE id=? AND enabled= 1";
$data = array($sample);
$result = $this->db->query($sql, $data);
return $result && $result->affected_rows > 0 ? true : false;
}

Ajax callback from PHP file

I'm trying to pass two number and check if their product is true or false. I can see call made successfully in network tab and when i click that link, output is correct to. But i m stuck at retrieving that result. It doesn't show anything in data1.
function call(){
console.log(fun);
$.ajax({
url: "http://localhost/mt2/checkanswer.php",
dataType: "jsonp",
type: "POST",
//window.alert("what");
data: {
num1:2,
num2:2,
answer:5
},
success: function( data1 ) {
console.log(data1);
$( "#timeDiv" ).html( "<strong>" + data1 + "</strong><br>");
}
<?php
// get two numbers and the answer (their product) and return true or false if the answer is correct or not.
// using this as an api call, return json data
// calling <your host>/checkanswer.php?num1=4&num2=5&answer=20 will return true
// calling <your host>/checkanswer.php?num1=4&num2=5&answer=21 will return false
if(isset($_GET['num1']) && isset($_GET['num2']) && isset($_GET['answer']) && is_numeric($_GET['num1']) && is_numeric($_GET['num2']) && is_numeric($_GET['answer'])) {
$product = $_GET["num1"] * $_GET["num2"];
if ($product === intval($_GET['answer'])) {
$result = true;
} else {
$result = false;
}
header('Content-type: application/json');
echo json_encode($result);
}
?>
https://drive.google.com/open?id=1ocF344ZxG3HXJR0WQha1kOoVM9bCepnI "console"

The issue is your Javascript is submitting the data via JS as a post request and your PHP is looking for a get request.
if(isset($_GET['num1']) && isset($_GET['num2']) && isset($_GET['answer']) && is_numeric($_GET['num1']) && is_numeric($_GET['num2']) && is_numeric($_GET['answer'])) {
..
}
So either change method: 'POST' to method: 'GET' or change $_GET[..] to $_POST[..].
Also that's one wild if statement. You could break it up so it's not so long and isn't as hard to read. This also allows you to add some additional information based on where your code 'fails.'
if ( isset($_GET['num1'], $_GET['num2'], $_GET['answer']) ) {
if ( !is_numeric([$_GET['num1'], $_GET['num2'], $_GET['answer']]) ) {
// Our numbers aren't numeric!
$message = 'Not all variables are numeric';
$result = false;
} else {
$message = 'We did it!';
$result = $_GET['num1'] + $_GET['num2'] == $_GET['answer'];
}
} else {
// We didn't have all of our request params passed!
$message = 'We didn\'t have all our variables';
$result = false;
}
header('Content-type: application/json');
echo json_encode([ 'message' => $message, 'result' => $result]);
Edit
Based on epascarello's comment remove dataType: 'jsonp'.

Ajax and PHP : SELECT query database

I have an UI in which the user can add objects (stored as JSON in my database). So, when the user is clicking on a button, it calls the ajax wich calls my php to get the desired JSON code.
The problem is that my ajax returns me "success" but with no JSON code. I don't know where the problem is located.
Here's my JS/AJAX:
var object, objectJson;
var objectName = $(this).attr("attr-lib");
var objectId = $(this).attr("attr-id");
$.ajax({
url: 'scriptObject.php',
type: 'POST',
data: {objectId: objectId},
dataType: 'json',
success: function(response) {
console.log("success");
console.log(response);
}
});
Here's my scriptObject.php:
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result = mysql_query($query);
if($result)
{
if(mysql_num_rows($result) > 0)
{
$objJSON = mysql_fetch_array($result);
$res = array("status"=>"success", "objectJson" => $objJSON['objectJson']);
}
else
{
$res = array("status"=>"error", "message" => "No records found.");
}
}
else
$res = array("status"=>"error", "message" => "Problem in fetching data.");
echo json_encode($res);
[EDIT]
It answers me:
{"status":"error","message":"Problem in fetching data."}

Try following
<script type="text/javascript">
var object, objectJson;
var objectName = $(this).attr("attr-lib");
var objectId = $(this).attr("attr-id");
$.ajax({
url: 'scriptObject.php',
type: 'POST',
dataType : 'json',
data: { objectId: objectId },
success: function(response) {
var json = $.parseJSON(response);
if(json.status == 'error')
console.log(json.message);
else if(json.status == 'success')
console.log(json.objectJson);
}
});
</script>
and in scriptObject.php
<?php
// your database connection goes here
include 'config.php';
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result = mysql_query($query);
if($result)
{
if(mysql_num_rows($result) > 0)
{
$objJSON = mysql_fetch_array($result);
$res = array("status"=>"success", "objectJson" => $objJSON['objectJson']);
}
else
{
$res = array("status"=>"error", "message" => "No records found.");
}
}
else
$res = array("status"=>"error", "message" => "Problem in fetching data.".mysql_error());
echo json_encode($res);
?>

scriptObject.php
if(isset($_POST['objectId']))
{
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result=mysql_query($query);
echo json_encode($result);
die;
}
you are execution the php code inside a function.
how does the compiler or the interpreter know to execute a function inside your php file.

Add dataType to your ajax options
$.ajax({
url: 'scriptObject.php',
type: 'POST',
data: objectId,
dataType : 'json',
success: function(response) {
console.log("success");
console.log(response);
}
});
then your php code
function getObjectJson() {
$objectId = $_POST["objectId"];
$query = "SELECT objectJson FROM object WHERE objectId = ' $objectId '";
$result=mysql_query($query);
echo json_encode($result);
}

Ajax login issues

I'm having issues with an Ajax login function. There was another question similar to mine that I was able to find but it proved no use.
I have no idea what is the issue, this works on another program as well with no issues, hopefully someone can see my mistake
From testing I think the issue is in the "checkLogIn" function because when I run the application the alert within the function shows
Ajax:
$("#checkLogIn").click(function()
{
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: checkLogIn(),
})
.done(function(data)
{
if(data == false)
{
alert("failure");
}
else
{
alert("Success");
$.mobile.changePage("#page");
}
})
.always(function(){})
.fail(function(){alert("Error");});
});
function checkLogIn()
{
alert();
return JSON.stringify({
"userName": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
}
I'll also include the PHP but the PHP works 100% after testing it.
PHP:
$app->post('/logIn/', 'logIn');
function logIn()
{
//global $hashedPassword;
$request = \Slim\Slim::getInstance()->request();
$q = json_decode($request->getBody());
//$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where userName=:userName AND password=:password";
try {
$db = getConnection();
$stmt = $db->prepare($sql);
$stmt->bindParam("userName", $q->userName);
$stmt->bindParam("password", $q->password);
$stmt->execute();
//$row=$stmt->fetch(PDO::FETCH_ASSOC);
//$verify = password_verify($q->password, $row['password']);
$db = null;
//if($verify == true)
//{
// echo "Password is correct";
//}
//else
// echo "Password is incorrect";
echo "Success";
} catch (PDOException $e) {
echo $e->getMessage();
}
}
I have commented out any and all hashing until I can get this working properly

There is no problem with the ajax script. From my assumption you always get Error alert. That is because you added dataType: "json", which means you are requesting the response from the rootURL + '/logIn/' as json Object. But in the php you simply echoing Success as a plain text. That makes the ajax to get into fail function. So, You need to send the response as json. For more details about contentType and datatype in ajax refer this link.
So you need to change echo "Success"; to echo json_encode(array('success'=>true)); in the php file. Now you'll get Success alert. Below I added a good way to handle the json_encoded response in the php file.
$app->post ( '/logIn/', 'logIn' );
function logIn() {
global $hashedPassword;
$request = \Slim\Slim::getInstance ()->request ();
$q = json_decode ( $request->getBody () );
$hashedPassword = password_hash($q->password, PASSWORD_BCRYPT);
$sql = "SELECT * FROM users where userName=:userName";
try {
$db = getConnection ();
$stmt = $db->prepare ( $sql );
$stmt->bindParam ( "userName", $q->userName );
$stmt->execute ();
$row=$stmt->fetch(PDO::FETCH_ASSOC);
$verify = false;
if(isset($row['password']) && !empty($row['password']))
$verify = password_verify($hashedPassword, $row['password']);
$db = null;
$response = array();
$success = false;
if($verify == true)
{
$success = true;
$response[] = "Password is correct";
}
else
{
$success = false;
$response[] = "Password is incorect";
}
echo json_encode(array("success"=>$success,"response"=>$response));
} catch ( PDOException $e ) {
echo $e->getMessage ();
}
}
And I modified the ajax code. There I showed you how to get the response from the json_encoded Object.
$("document").ready(function(){
$("#checkLogIn").click(function()
{
var post_data = JSON.stringify({
"userName": $("#enterUser").val(),
"password": $("#enterPass").val(),
});
$.ajax({
type: 'POST',
contentType: 'application/json',
url: rootURL + '/logIn/',
dataType: "json",
data: post_data,
})
.done(function(data)
{
// data will contain the echoed json_encoded Object. To access that you need to use data.success.
// So it will contain true or false. Based on that you'll write your rest of the code.
if(data.success == false)
{
var response = "";
$.each(data.response, function(index, value){
response += value;
});
alert("Success:"+response);
}
else
{
var response = "";
$.each(data.response, function(index, value){
response += value;
});
alert("Failed:"+response);
$.mobile.changePage("#page");
}
})
.always(function(){})
.fail(function(){alert("Error");});
});
});
Hope it helps.

best option to get php array variable in Javascript produced by php script that requested through an ajax call

Currently I am trying to create a live search bar that only produce 5 results max and more option if there is over 5 results. So what I have done so far is a jquery ajax script to call a php script that runs asynchronously on key up in textbox I have.
I want to get the php array then I will code it further using javascript.
This is my code now:
Javascript code
<script type="text/javascript">
function find(value)
{
$( "#test" ).empty();
$.ajax({
url: 'searchDb.php',
type: 'POST',
data: {"asyn": value},
success: function(data) {
return $lala;
var lala = $lala;
$( "#test" ).html($lala);
}
});
}
</script>
SearchDb PHP code:
<?php
function searchDb($abc, $limit = null){
if (isset($abc) && $abc) {
$sql = "SELECT testa FROM test WHERE testa LIKE '%$abc%'";
if($limit !== null){
$sql .= "LIMIT ". $limit;
}
$result = mysql_query($sql) or die('Error, insert query failed') ;
$lists = array();
while ( $row = mysql_fetch_assoc($result))
{
$var = "<div>".$row["testa"]."</div>";
array_push($lists, $var);
}
}
return $lists;
}
$abc = $_POST['asyn'];
$limit = 6;
$lala = searchDb($abc);
print_r($lala);
?>
How can I get $lala

Have you considered encoding the PHP array into JSON? So instead of just echoing the array $lala, do:
echo json_encode($lala);
Then, on the Javascript side, you'll use jQuery to parse the json.
var jsonResponse = $.parseJSON(data);
Then you'll be able to use this jsonResponse variable to access the data returned.

You need to read jQuery .ajax and also you must view this answer it's very important for you
$.ajax({
url: 'searchDb.php',
cache: false,
type: 'post'
})
.done(function(html) {
$("#yourClass").append(html);
});
In your searchDb.php use echo and try this code:
function searchDb($str, $limit = null){
$lists = array();
if (isset($str) && !empty($data)) {
$sql = "SELECT testa FROM test WHERE testa LIKE '%$data%'";
if(0 < $limit){
$sql .= "LIMIT ". $limit;
}
$result = mysql_query($sql) or die('Error, insert query failed') ;
while ( $row = mysql_fetch_assoc($result))
{
$lists[] = "<div>".$row["testa"]."</div>";
}
}
return implode('', $lists);
}
$limit = 6;
$data = searchDb($_POST['asyn'], $limit);
echo $data;
?>

If you dont have or your page searchDb.php dont throw any error, then you just need to echo $lala; and you will get result in success part of your ajax function
ALso in your ajax funciton you have
//you are using data here
success: function(data) {
return $lala;
var lala = $lala;
$( "#test" ).html($lala);
}
you must try some thing like this
success: function(data) {
var lala = data;
$( "#test" ).html($lala);
}