I am preparing a web app which allows user to design Identity cards.
I am using ng-drag-drop https://www.npmjs.com/package/ng-drag-drop for the same.
I wish to get co-ordinates of a div box inside a bigger div box.
As per the image, I want (x,y) with respect to outer div
Things to achieve:
place inner div at specific position inside div
drag around -- fetch new co-ordinates
Problem : when I reposition the box programmatically and then move it around, the x,y values are coming negative –
HTML:
<div class="card-boundary" #boundary>
<img width="1039" height="673" [ngStyle]="bgStyle" />
<div cdkDragLockAxis="elem.dragLock" (cdkDragEnded)="dragEnd($event)" (cdkDragStarted)="onElemClick(elem,$event)" cdkDragBoundary=".card-boundary" cdkDrag *ngFor="let elem of elemList" [ngClass]="{'example-box-selected':(selectedElem && elem.field == selectedElem.field)}"
(click)="onElemClick(elem,$event)" class="example-box" style="text-align: start" [ngStyle]="elem" #item>
{{elem.sample}}
</div>
</div>
Typescript:
dragEnd(event: CdkDragEnd) {
const transform = event.source.element.nativeElement.style.transform;
let regex = /translate3d\(\s?(?<x>[-]?\d*)px,\s?(?<y>[-]?\d*)px,\s?(?<z>[-]?\d*)px\)/;
var values = regex.exec(transform);
this.selectedElem.startX = +values[1];
this.selectedElem.startY = +values[2];
}
CSS:
.card-boundary {
width: 1039px;
height: 676px;
max-width: 100%;
position: relative;
background-color: #fff
}
.bg-boundary {
width: 1039px;
height: 676px;
max-width: 100%;
}
.example-box {
cursor: move;
position: relative;
z-index: 1;
}
.example-box-selected {
cursor: move;
background: #eee;
position: relative;
z-index: 1;
}
When the position of an element is changed using css transform, the values of transform indicate the position change from its' original position.
Also when an element is moved using transform, its' original position will never change, as the new position should always be calculated from original position + change in position.
So if you can get the original position of the element, you can add the transform values to the original position values to get the current position.
The below code will give you the current position of the element with respect to its' offsetParent.
dragEnd(event: CdkDragEnd) {
const element = event.source.element.nativeElement;
const transform = element.style.transform;
let regex = /translate3d\(\s?(?<x>[-]?\d*)px,\s?(?<y>[-]?\d*)px,\s?(?<z>[-]?\d*)px\)/;
var values = regex.exec(transform);
this.selectedElem.startX = element.offsetLeft + +values[1];
this.selectedElem.startY = element.offsetTop + +values[2];
}
PS: offsetParent = 'closest positioned parent' || document.body
Pretty simple problem, but I can't find a solution. This plugin claims to do it, but I can't get it to work on my site at all, not as a called script, not inline, nothing. So, I have two columns of divs, the ones on one side larger than the other. I have set it up so the second column container will match the height of the first (which is determined elsewhere and thus varies) and set it to overflow:hidden, but what I want to do do is to remove the overflowing divs entirely so it always ends on the last complete div. Here's the fiddle: https://jsfiddle.net/bw2v39ru/2/
This is the JS to equalize the heights $('.row2').css('height', $('.row1').height()+'px');
In that example, only two of he block2 spans should be visible and the overflowing ones removed completely instead of leaving half a block.
Try this: https://jsfiddle.net/bw2v39ru/9/
Besides the code below - you will have to e.g. insert a <br style="clear:both;" /> in the parent DIV since the children has float: left
$('.row2').css('height', $('.row1').height());
var maxHeight = $("#main").outerHeight();
$("#main span").each(function() {
var elm = $(this);
if (elm.offset().top + elm.height() > maxHeight)
elm.remove();
});
as promised, here is my answer. Custom build jsfiddle from pure JavaScript.
https://jsfiddle.net/www139/vjgnsrpg/
Here is a code snippit for you. It assumes that all of your block2 elements have a fixed height. Also I changed the .row1 and .row2 classes to ids to make the solution easier to create. Feel free to change it back but remember to use document.getElementsByClassName('class')[i] instead.
//make sure you execute this script onload inside a jquery document ready or window.onload
//get the rendered height of both rows
//enter margin for blocks here
//this also assumes that the height of your block1 and block2 elements are fixed
var margin = 5;
var rowOneHeight = document.getElementById('row1').offsetHeight;
//get height of block2 element including vertical margin (multiplied twice)
var blockTwoHeight = document.getElementById('row2').getElementsByClassName('block2')[0].offsetHeight + 2 * margin;
var howManyBlocksCanFit = Math.floor(rowOneHeight / blockTwoHeight);
var numberOfBlocks = document.getElementById('row2').getElementsByClassName('block2').length;
for (var i = 0; i != numberOfBlocks - howManyBlocksCanFit; i++) {
document.getElementById('row2').removeChild(document.getElementById('row2').lastElementChild);
}
#main {
width: 240px;
}
#row1 {
float: left;
}
#row2 {
float: right;
overflow: hidden;
}
.block1 {
display: block;
margin: 5px;
width: 100px;
height: 50px;
border: 1px solid red;
}
.block2 {
display: block;
margin: 5px;
width: 100px;
height: 100px;
border: 1px solid red;
}
<div id="main">
<div id="row1">
<span class="block1"></span>
<span class="block1"></span>
<span class="block1"></span>
<span class="block1"></span>
<span class="block1"></span>
</div>
<div id="row2">
<span class="block2"></span>
<span class="block2"></span>
<span class="block2"></span>
<span class="block2"></span>
<span class="block2"></span>
</div>
</div>
Hope this helps you, please tell me if there was something I didn't understand in your question to improve my answer.
I programmed it for you, this works after your existing JS code line:
var row2 = $('div.row2'),
block2elements = row2.children('span.block2');
// Function to use also for other situations
function calculateElementsHeight(elements) {
var height = 0;
$.each(elements, function(i, elementRaw ){
height += $(elementRaw).height();
})
return height;
}
for(var i = 0; block2elements.length > i; i++) {
block2elements = row2.children('span.block2'); // Get new state of the block2 elements
if(row2.height() < calculateElementsHeight(block2elements)) {
block2elements.last().remove();
}
}
I am attempting to create a function where by a button is clicked and the background image is selected for a div. Here is what I have started below but it does not seem to work can anyone point out where Im going wrong... :)
<style type="text/css">
#txt{
width: auto;
height: auto;
border: solid #000;
}
</style>
<script type="text/javascript">
function backg1(){
var test = new string ();
test = document.getElementById('txt');
test.style.backgroundImage="url('cloud.jpg')";
}
</script>
</head>
<body>
<div id="txt">
<input type="button" value="BG1" onclick="backg1()"/>
</div>
Since your <div> originally contains nothing but the button input, it has no size outside the boundaries of that button. You will need to set an explicit width and height (along with position: relative) to see the background.
I would recommend setting them to the same dimensions as your image.
/* in the CSS */
#txt{
/* use the width, height of your image */
width: 400px;
height: 250px;
position: relative;
border: solid #000;
}
Or if you need to set them dynamically:
function backg1() {
test = document.getElementById('txt');
test.style.backgroundImage="url('cloud.jpg')";
// <div> needs a width & height for the background image to be visible outside the
// bounds of the one element contained in the div.
test.style.width = "400px";
test.style.height = "250px";
test.style.position = "relative";
}
There is a javascript error at this line.
var test = new string ();
You can make it like var test = new String(); Then it should work.
Moreover, i observed that you are creating string object and then you are overriding with DOM object. Not sure why it so like that. You can just create a variable like var test;
I'm trying to show 16 by 16 pixel image at X=100 & Y=100 but am stuck. The image is to be displayed over the top of whatever is on the page. Altering the top and left properties don't do anything.
Whatever I do, the image seems to show up at pos 0,0.
shimDiv.style.position = 'absolute';
shimDiv.style.top = 100;
shimDiv.style.left = 100;
shimDiv.style.width = "1000px"; // todo: change me!
shimDiv.style.height = "1000px"; // todo: change me!
shimDiv.style.zIndex = 3;
document.body.appendChild(shimDiv);
$("#shim").append('<img id="icon" src="../Images/info.png" alt="todo:" />');
That's because you've not specified the units for the top and left positions:
shimDiv.style.top = '100px';
shimDiv.style.left = '100px';
Hmm, maybe this is an oversimplification, but this should accomplish what you are asking:
$('body').append('<img id="icon" src="../Images/info.png" style="position: absolute; top: 100px; left: 100px; width: 1000px; height: 1000px; z-index: 1000;" />');
It seems in your code sample that the creation code for the parent div element is missing, but the above code should be all that is necessary.
Hope that helps...
I have a scrolled div and I want to have an event when I click on it, it will force this div to scroll to view an element inside.
I wrote its JavasSript like this:
document.getElementById(chr).scrollIntoView(true);
but this scrolls all the page while scrolling the div itself.
How to fix that?
I want to say it like this:
MyContainerDiv.getElementById(chr).scrollIntoView(true);
You need to get the top offset of the element you'd like to scroll into view, relative to its parent (the scrolling div container):
var myElement = document.getElementById('element_within_div');
var topPos = myElement.offsetTop;
The variable topPos is now set to the distance between the top of the scrolling div and the element you wish to have visible (in pixels).
Now we tell the div to scroll to that position using scrollTop:
document.getElementById('scrolling_div').scrollTop = topPos;
If you're using the prototype JS framework, you'd do the same thing like this:
var posArray = $('element_within_div').positionedOffset();
$('scrolling_div').scrollTop = posArray[1];
Again, this will scroll the div so that the element you wish to see is exactly at the top (or if that's not possible, scrolled as far down as it can so it's visible).
You would have to find the position of the element in the DIV you want to scroll to, and set the scrollTop property.
divElem.scrollTop = 0;
Update:
Sample code to move up or down
function move_up() {
document.getElementById('divElem').scrollTop += 10;
}
function move_down() {
document.getElementById('divElem').scrollTop -= 10;
}
Method 1 - Smooth scrolling to an element inside an element
var box = document.querySelector('.box'),
targetElm = document.querySelector('.boxChild'); // <-- Scroll to here within ".box"
document.querySelector('button').addEventListener('click', function(){
scrollToElm( box, targetElm , 600 );
});
/////////////
function scrollToElm(container, elm, duration){
var pos = getRelativePos(elm);
scrollTo( container, pos.top , 2); // duration in seconds
}
function getRelativePos(elm){
var pPos = elm.parentNode.getBoundingClientRect(), // parent pos
cPos = elm.getBoundingClientRect(), // target pos
pos = {};
pos.top = cPos.top - pPos.top + elm.parentNode.scrollTop,
pos.right = cPos.right - pPos.right,
pos.bottom = cPos.bottom - pPos.bottom,
pos.left = cPos.left - pPos.left;
return pos;
}
function scrollTo(element, to, duration, onDone) {
var start = element.scrollTop,
change = to - start,
startTime = performance.now(),
val, now, elapsed, t;
function animateScroll(){
now = performance.now();
elapsed = (now - startTime)/1000;
t = (elapsed/duration);
element.scrollTop = start + change * easeInOutQuad(t);
if( t < 1 )
window.requestAnimationFrame(animateScroll);
else
onDone && onDone();
};
animateScroll();
}
function easeInOutQuad(t){ return t<.5 ? 2*t*t : -1+(4-2*t)*t };
.box{ width:80%; border:2px dashed; height:180px; overflow:auto; }
.boxChild{
margin:600px 0 300px;
width: 40px;
height:40px;
background:green;
}
<button>Scroll to element</button>
<div class='box'>
<div class='boxChild'></div>
</div>
Method 2 - Using Element.scrollIntoView:
Note that browser support isn't great for this one
var targetElm = document.querySelector('.boxChild'), // reference to scroll target
button = document.querySelector('button'); // button that triggers the scroll
// bind "click" event to a button
button.addEventListener('click', function(){
targetElm.scrollIntoView()
})
.box {
width: 80%;
border: 2px dashed;
height: 180px;
overflow: auto;
scroll-behavior: smooth; /* <-- for smooth scroll */
}
.boxChild {
margin: 600px 0 300px;
width: 40px;
height: 40px;
background: green;
}
<button>Scroll to element</button>
<div class='box'>
<div class='boxChild'></div>
</div>
Method 3 - Using CSS scroll-behavior:
.box {
width: 80%;
border: 2px dashed;
height: 180px;
overflow-y: scroll;
scroll-behavior: smooth; /* <--- */
}
#boxChild {
margin: 600px 0 300px;
width: 40px;
height: 40px;
background: green;
}
<a href='#boxChild'>Scroll to element</a>
<div class='box'>
<div id='boxChild'></div>
</div>
Native JS, Cross Browser, Smooth Scroll (Update 2020)
Setting ScrollTop does give the desired result but the scroll is very abrupt. Using jquery to have smooth scroll was not an option. So here's a native way to get the job done that supports all major browsers. Reference - caniuse
// get the "Div" inside which you wish to scroll (i.e. the container element)
const El = document.getElementById('xyz');
// Lets say you wish to scroll by 100px,
El.scrollTo({top: 100, behavior: 'smooth'});
// If you wish to scroll until the end of the container
El.scrollTo({top: El.scrollHeight, behavior: 'smooth'});
That's it!
And here's a working snippet for the doubtful -
document.getElementById('btn').addEventListener('click', e => {
e.preventDefault();
// smooth scroll
document.getElementById('container').scrollTo({top: 175, behavior: 'smooth'});
});
/* just some styling for you to ignore */
.scrollContainer {
overflow-y: auto;
max-height: 100px;
position: relative;
border: 1px solid red;
width: 120px;
}
body {
padding: 10px;
}
.box {
margin: 5px;
background-color: yellow;
height: 25px;
display: flex;
align-items: center;
justify-content: center;
}
#goose {
background-color: lime;
}
<!-- Dummy html to be ignored -->
<div id="container" class="scrollContainer">
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div id="goose" class="box">goose</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
</div>
<button id="btn">goose</button>
Update: As you can perceive in the comments, it seems that Element.scrollTo() is not supported in IE11. So if you don't care about IE11 (you really shouldn't, Microsoft is retiring IE11 in June 2022), feel free to use this in all your projects. Note that support exists for Edge! So you're not really leaving your Edge/Windows users behind ;)
Reference
To scroll an element into view of a div, only if needed, you can use this scrollIfNeeded function:
function scrollIfNeeded(element, container) {
if (element.offsetTop < container.scrollTop) {
container.scrollTop = element.offsetTop;
} else {
const offsetBottom = element.offsetTop + element.offsetHeight;
const scrollBottom = container.scrollTop + container.offsetHeight;
if (offsetBottom > scrollBottom) {
container.scrollTop = offsetBottom - container.offsetHeight;
}
}
}
document.getElementById('btn').addEventListener('click', ev => {
ev.preventDefault();
scrollIfNeeded(document.getElementById('goose'), document.getElementById('container'));
});
.scrollContainer {
overflow-y: auto;
max-height: 100px;
position: relative;
border: 1px solid red;
width: 120px;
}
body {
padding: 10px;
}
.box {
margin: 5px;
background-color: yellow;
height: 25px;
display: flex;
align-items: center;
justify-content: center;
}
#goose {
background-color: lime;
}
<div id="container" class="scrollContainer">
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div id="goose" class="box">goose</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
<div class="box">duck</div>
</div>
<button id="btn">scroll to goose</button>
Code should be:
var divElem = document.getElementById('scrolling_div');
var chElem = document.getElementById('element_within_div');
var topPos = divElem.offsetTop;
divElem.scrollTop = topPos - chElem.offsetTop;
You want to scroll the difference between child top position and div's top position.
Get access to child elements using:
var divElem = document.getElementById('scrolling_div');
var numChildren = divElem.childNodes.length;
and so on....
If you are using jQuery, you could scroll with an animation using the following:
$(MyContainerDiv).animate({scrollTop: $(MyContainerDiv).scrollTop() + ($('element_within_div').offset().top - $(MyContainerDiv).offset().top)});
The animation is optional: you could also take the scrollTop value calculated above and put it directly in the container's scrollTop property.
We can resolve this problem without using JQuery and other libs.
I wrote following code for this purpose:
You have similar structure ->
<div class="parent">
<div class="child-one">
</div>
<div class="child-two">
</div>
</div>
JS:
scrollToElement() {
var parentElement = document.querySelector('.parent');
var childElement = document.querySelector('.child-two');
parentElement.scrollTop = childElement.offsetTop - parentElement.offsetTop;
}
We can easily rewrite this method for passing parent and child as an arguments
Another example of using jQuery and animate.
var container = $('#container');
var element = $('#element');
container.animate({
scrollTop: container.scrollTop = container.scrollTop() + element.offset().top - container.offset().top
}, {
duration: 1000,
specialEasing: {
width: 'linear',
height: 'easeOutBounce'
},
complete: function (e) {
console.log("animation completed");
}
});
None of other answer fixed my issue.
I played around with scrollIntoView arguments and managed to found a solution. Setting inline to start and block to nearest prevents parent element (or entire page) to scroll:
document.getElementById(chr).scrollIntoView({
behavior: 'smooth',
block: 'nearest',
inline: 'start'
});
There are two facts :
1) Component scrollIntoView is not supported by safari.
2) JS framework jQuery can do the job like this:
parent = 'some parent div has css position==="fixed"' || 'html, body';
$(parent).animate({scrollTop: $(child).offset().top}, duration)
Here's a simple pure JavaScript solution that works for a target Number (value for scrollTop), target DOM element, or some special String cases:
/**
* target - target to scroll to (DOM element, scrollTop Number, 'top', or 'bottom'
* containerEl - DOM element for the container with scrollbars
*/
var scrollToTarget = function(target, containerEl) {
// Moved up here for readability:
var isElement = target && target.nodeType === 1,
isNumber = Object.prototype.toString.call(target) === '[object Number]';
if (isElement) {
containerEl.scrollTop = target.offsetTop;
} else if (isNumber) {
containerEl.scrollTop = target;
} else if (target === 'bottom') {
containerEl.scrollTop = containerEl.scrollHeight - containerEl.offsetHeight;
} else if (target === 'top') {
containerEl.scrollTop = 0;
}
};
And here are some examples of usage:
// Scroll to the top
var scrollableDiv = document.getElementById('scrollable_div');
scrollToTarget('top', scrollableDiv);
or
// Scroll to 200px from the top
var scrollableDiv = document.getElementById('scrollable_div');
scrollToTarget(200, scrollableDiv);
or
// Scroll to targetElement
var scrollableDiv = document.getElementById('scrollable_div');
var targetElement= document.getElementById('target_element');
scrollToTarget(targetElement, scrollableDiv);
given you have a div element you need to scroll inside, try this piece of code
document.querySelector('div').scroll(x,y)
this works with me inside a div with a scroll, this should work with you in case you pointed the mouse over this element and then tried to scroll down or up. If it manually works, it should work too
User Animated Scrolling
Here's an example of how to programmatically scroll a <div> horizontally, without JQuery. To scroll vertically, you would replace JavaScript's writes to scrollLeft with scrollTop, instead.
JSFiddle
https://jsfiddle.net/fNPvf/38536/
HTML
<!-- Left Button. -->
<div style="float:left;">
<!-- (1) Whilst it's pressed, increment the scroll. When we release, clear the timer to stop recursive scroll calls. -->
<input type="button" value="«" style="height: 100px;" onmousedown="scroll('scroller',3, 10);" onmouseup="clearTimeout(TIMER_SCROLL);"/>
</div>
<!-- Contents to scroll. -->
<div id="scroller" style="float: left; width: 100px; height: 100px; overflow: hidden;">
<!-- <3 -->
<img src="https://cdn.sstatic.net/Sites/stackoverflow/company/img/logos/so/so-logo.png?v=9c558ec15d8a" alt="image large" style="height: 100px" />
</div>
<!-- Right Button. -->
<div style="float:left;">
<!-- As (1). (Use a negative value of 'd' to decrease the scroll.) -->
<input type="button" value="»" style="height: 100px;" onmousedown="scroll('scroller',-3, 10);" onmouseup="clearTimeout(TIMER_SCROLL);"/>
</div>
JavaScript
// Declare the Shared Timer.
var TIMER_SCROLL;
/**
Scroll function.
#param id Unique id of element to scroll.
#param d Amount of pixels to scroll per sleep.
#param del Size of the sleep (ms).*/
function scroll(id, d, del){
// Scroll the element.
document.getElementById(id).scrollLeft += d;
// Perform a delay before recursing this function again.
TIMER_SCROLL = setTimeout("scroll('"+id+"',"+d+", "+del+");", del);
}
Credit to Dux.
Auto Animated Scrolling
In addition, here are functions for scrolling a <div> fully to the left and right. The only thing we change here is we make a check to see if the full extension of the scroll has been utilised before making a recursive call to scroll again.
JSFiddle
https://jsfiddle.net/0nLc2fhh/1/
HTML
<!-- Left Button. -->
<div style="float:left;">
<!-- (1) Whilst it's pressed, increment the scroll. When we release, clear the timer to stop recursive scroll calls. -->
<input type="button" value="«" style="height: 100px;" onclick="scrollFullyLeft('scroller',3, 10);"/>
</div>
<!-- Contents to scroll. -->
<div id="scroller" style="float: left; width: 100px; height: 100px; overflow: hidden;">
<!-- <3 -->
<img src="https://cdn.sstatic.net/Sites/stackoverflow/company/img/logos/so/so-logo.png?v=9c558ec15d8a" alt="image large" style="height: 100px" />
</div>
<!-- Right Button. -->
<div style="float:left;">
<!-- As (1). (Use a negative value of 'd' to decrease the scroll.) -->
<input type="button" value="»" style="height: 100px;" onclick="scrollFullyRight('scroller',3, 10);"/>
</div>
JavaScript
// Declare the Shared Timer.
var TIMER_SCROLL;
/**
Scroll fully left function; completely scrolls a <div> to the left, as far as it will go.
#param id Unique id of element to scroll.
#param d Amount of pixels to scroll per sleep.
#param del Size of the sleep (ms).*/
function scrollFullyLeft(id, d, del){
// Fetch the element.
var el = document.getElementById(id);
// Scroll the element.
el.scrollLeft += d;
// Have we not finished scrolling yet?
if(el.scrollLeft < (el.scrollWidth - el.clientWidth)) {
TIMER_SCROLL = setTimeout("scrollFullyLeft('"+id+"',"+d+", "+del+");", del);
}
}
/**
Scroll fully right function; completely scrolls a <div> to the right, as far as it will go.
#param id Unique id of element to scroll.
#param d Amount of pixels to scroll per sleep.
#param del Size of the sleep (ms).*/
function scrollFullyRight(id, d, del){
// Fetch the element.
var el = document.getElementById(id);
// Scroll the element.
el.scrollLeft -= d;
// Have we not finished scrolling yet?
if(el.scrollLeft > 0) {
TIMER_SCROLL = setTimeout("scrollFullyRight('"+id+"',"+d+", "+del+");", del);
}
}
This is what has finally served me
/** Set parent scroll to show element
* #param element {object} The HTML object to show
* #param parent {object} The HTML object where the element is shown */
var scrollToView = function(element, parent) {
//Algorithm: Accumulate the height of the previous elements and add half the height of the parent
var offsetAccumulator = 0;
parent = $(parent);
parent.children().each(function() {
if(this == element) {
return false; //brake each loop
}
offsetAccumulator += $(this).innerHeight();
});
parent.scrollTop(offsetAccumulator - parent.innerHeight()/2);
}
I needed to scroll a dynamically loading element on a page so my solution was a little more involved.
This will work on static elements that are not lazy loading data and data being dynamically loaded.
const smoothScrollElement = async (selector: string, scrollBy = 12, prevCurrPos = 0) => {
const wait = (timeout: number) => new Promise(resolve => setTimeout(resolve, timeout));
const el = document.querySelector(selector) as HTMLElement;
let positionToScrollTo = el.scrollHeight;
let currentPosition = Math.floor(el.scrollTop) || 0;
let pageYOffset = (el.clientHeight + currentPosition);
if (positionToScrollTo == pageYOffset) {
await wait(1000);
}
if ((prevCurrPos > 0 && currentPosition <= prevCurrPos) !== true) {
setTimeout(async () => {
el.scrollBy(0, scrollBy);
await smoothScrollElement(selector, scrollBy, currentPosition);
}, scrollBy);
}
};
browser does scrolling automatically to an element that gets focus, so what you can also do it to wrap the element that you need to be scrolled to into <a>...</a> and then when you need scroll just set the focus on that a