If I give Closure Compiler something like this:
window.array = '0123456789'.split('');
It "compiles" it to this:
window.array="0,1,2,3,4,5,6,7,8,9".split(",");
Now as you can tell, that's bigger. Is there any reason why Closure Compiler is doing this?
I think this is what's going on, but I am by no means certain...
The code that causes the insertion of commas is tryMinimizeStringArrayLiteral in PeepholeSubstituteAlternateSyntax.java.
That method contains a list of characters that are likely to have a low Huffman encoding, and are therefore preferable to split on than other characters. You can see the result of this if you try something like this:
"a b c d e f g".split(" "); //Uncompiled, split on spaces
"a,b,c,d,e,f,g".split(","); //Compiled, split on commas (same size)
The compiler will replace the character you try to split on with one it thinks is favourable. It does so by iterating over the characters of the string and finding the most favourable splitting character that does not occur within the string:
// These delimiters are chars that appears a lot in the program therefore
// probably have a small Huffman encoding.
NEXT_DELIMITER: for (char delimiter : new char[]{',', ' ', ';', '{', '}'}) {
for (String cur : strings) {
if (cur.indexOf(delimiter) != -1) {
continue NEXT_DELIMITER;
}
}
String template = Joiner.on(delimiter).join(strings);
//...
}
In the above snippet you can see the array of characters the compiler claims to be optimal to split on. The comma is first (which is why in my space example above, the spaces have been replaced by commas).
I believe the insertion of commas in the case where the string to split on is the empty string may simply be an oversight. There does not appear to be any special treatment of this case, so it's treated like any other split call and each character is joined with the first appropriate character from the array shown in the above snippet.
Another example of how the compiler deals with the split method:
"a,;b;c;d;e;f;g".split(";"); //Uncompiled, split on semi-colons
"a, b c d e f g".split(" "); //Compiled, split on spaces
This time, since the original string already contains a comma (and we don't want to split on the comma character), the comma can't be chosen from the array of low-Huffman-encoded characters, so the next best choice is selected (the space).
Update
Following some further research into this, it is definitely not a bug. This behaviour is actually by design, and in my opinion it's a very clever little optimisation, when you bear in mind that the Closure compiler tends to favour the speed of the compiled code over size.
Above I mentioned Huffman encoding a couple of times. The Huffman coding algorithm, explained very simply, assigns a weight to each character appearing the the text to be encoded. The weight is based on the frequency with which each character appears. These frequencies are used to build a binary tree, with the most common character at the root. That means the most common characters are quicker to decode, since they are closer to the root of the tree.
And since the Huffman algorithm is a large part of the DEFLATE algorithm used by gzip. So if your web server is configured to use gzip, your users will be benefiting from this clever optimisation.
This issue was fixed on Apr 20, 2012 see revision:
https://code.google.com/p/closure-compiler/source/detail?r=1267364f742588a835d78808d0eef8c9f8ba8161
Ironically, split in the compiled code has nothing to do with split in the source. Consider:
Source : a = ["0","1","2","3","4","5"]
Compiled: a="0,1,2,3,4,5".split(",")
Here, split is just a way to represent long arrays (long enough for sum of all quotes + commas to be longer than split(","") ). So, what's going on in your example? First, the compiler sees a string function applied to a constant and evaluates it right away:
'0123456789'.split('') => ["0","1","2","3","4","5","6","7","8","9"]
At some later point, when generating output, the compiler considers this array to be "long" and writes it in the above "split" form:
["0","1","2","3","4","5","6","7","8","9"] => "0,1,2,3,4,5,6,7,8,9".split(",")
Note that all information about split('') in the source is already lost at this point.
If the source string were shorter, it would be generated in the array array form, without extra splitting:
Source : a = '0123'.split('')
Compiled: a=["0","1","2","3"]
Related
I've a little problem.
I'm using NodeJS as backend. Now, an user has a field "biography", where the user can write something about himself.
Suppose that this field has 220 maxlength, and suppose this as input:
๐ถ๐ป๐ฆ๐ป๐ง๐ป๐จ๐ป๐ฉ๐ป๐ฑ๐ปโโ๏ธ๐ฑ๐ป๐ด๐ป๐ต๐ป๐ฒ๐ป๐ณ๐ปโโ๏ธ๐ณ๐ป๐ฎ๐ปโโ๏ธ๐ฎ๐ป๐ท๐ปโโ๏ธ๐ท๐ป๐๐ปโโ๏ธ๐๐ป๐ต๐ปโโ๏ธ๐ฉ๐ปโโ๏ธ๐จ๐ปโโ๏ธ๐ฉ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ
As you can see there aren't 220 emojis (there are 37 emojis), but if I do in my nodejs server
console.log(bio.length)
where bio is the input text, I got 221. How could I "parse" the string input to get the correct length? Is it a problem about unicode?
SOLVED
I used this library: https://github.com/orling/grapheme-splitter
I tried that:
var Grapheme = require('grapheme-splitter');
var splitter = new Grapheme();
console.log(splitter.splitGraphemes(bio).length);
and the length is 37. It works very well!
str.length gives the count of UTF-16 units.
Unicode-proof way to get string length in codepoints (in characters) is [...str].length as iterable protocol splits the string to codepoints.
If we need the length in graphemes (grapheme clusters), we have these native ways:
a. Unicode property escapes in RegExp. See for example: Unicode-aware version of \w or Matching emoji.
b. Intl.Segmenter โ coming soon, probably in ES2021. Can be tested with a flag in the last V8 versions (realization was synced with the last spec in V8 86). Unflagged (shipped) in V8 87.
See also:
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)
What every JavaScript developer should know about Unicode
JavaScript has a Unicode problem
Unicode-aware regular expressions in ES2015
ES6 Strings (and Unicode, โค) in Depth
JavaScript for impatient programmers. Unicode โ a brief introduction
TL;DR there are solutions, but they donโt work in every case. Unicode can feel like a dark art.
There seems to be limitations in various solutions I have seen presented, with the issue going beyond emojis and covering other characters in the Unicode range. Consider รฉ can be stored as รฉ or e + โ, if using combing characters. This can even lead to two strings that look the same not being equal. Also note, in certain cases a single emoji can be 11 characters when stored and as a result 22 bytes, assuming UTF16.
The way this is handled and how characters are combined, or displayed, can even vary between browsers and operating systems. So, while you may think you cracked it, there is a risk another environment breaks this. Be sure to test where it matters.
Now, there is the front-end vs back-end problem: you solved the character count problem so it works well for human users, now your single emoji blows right past the allocated field size in the database. Less of an issue with databases such as mongo, but can be one with SQL databases, where field allocation was conservative. This means how you solve your problem will depend where the hardest limitation comes in.
Note, that a basic solution does involve converting a string to an array and getting the length, accepting limitations:
Array.from(str)
This will fall apart when characters are combined and dealing with astral planes.
A few high level approaches, that take into account limitations:
use approaches that solve the front-end issue, as best as possible, and then ensure storage issues are resolved
be more conservative with the advertised front-end limits, if the database or other storage canโt be adjusted
limit the character types that can be entered
clearly indicate limitations of the length calculation
Additionally, given the complexity of the issue it may be worth seeing if there is a popular JS library that already deals with this? I did not find one at the time of writing. Hopefully this is something that would become core to Javascript at some point.
Other pages to read:
https://blog.jonnew.com/posts/poo-dot-length-equals-two
https://mathiasbynens.be/notes/javascript-unicode
https://www.contentful.com/blog/2016/12/06/unicode-javascript-and-the-emoji-family/
https://dmitripavlutin.com/what-every-javascript-developer-should-know-about-unicode/
I answered to a similar question here
But basically, here it is :
'๐'.match(/./gu).length == 1
As :
'๐'.length == 2
More precision in my original post
function fancyCount2(str){
const joiner = "\u{200D}";
const split = str.split(joiner);
let count = 0;
for(const s of split){
//removing the variation selectors
const num = Array.from(s.split(/[\ufe00-\ufe0f]/).join("")).length;
count += num;
}
//assuming the joiners are used appropriately
return count / split.length;
}
With a regex that can parse emojis, this can be done easily and without the use of external libraries. Please see the code snippets for examples. ๐ท๐ปโโ๏ธ
Note that grapheme-splitter as suggested in the question will overcount and split apart compound emojis that contain other emojis, such as this one: ๐ง๐ปโ๐คโ๐ง๐ป. This is reported as three distinct "graphemes", ๐ง๐ปโ and ๐คโ and ๐ง๐ป
Here we are using the 'compact', literal version so it'll fit, but there's a safe, long version that uses Unicode escapes as well.
For more info on the regex see also this answer.
/*the pattern (compact version)*/
var emojiPattern = String.raw`(?:๐ง๐ปโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ปโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ปโโค๏ธโ๐โ๐ง๐พ|๐ง๐ปโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ผโโค๏ธโ๐โ๐ง๐ป|๐ง๐ผโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ผโโค๏ธโ๐โ๐ง๐พ|๐ง๐ผโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ป|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐พ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐พโโค๏ธโ๐โ๐ง๐ป|๐ง๐พโโค๏ธโ๐โ๐ง๐ผ|๐ง๐พโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐พโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ป|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ป|๐จ๐ปโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ปโโค๏ธโ๐โ๐จ๐พ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ป|๐จ๐ผโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ผโโค๏ธโ๐โ๐จ๐พ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ป|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐พ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐พโโค๏ธโ๐โ๐จ๐ป|๐จ๐พโโค๏ธโ๐โ๐จ๐ผ|๐จ๐พโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐พโโค๏ธโ๐โ๐จ๐พ|๐จ๐พโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ป|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐พ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ฟ|๐ด๓ ง๓ ข๓ ฅ๓ ฎ๓ ง๓ ฟ|๐ด๓ ง๓ ข๓ ณ๓ ฃ๓ ด๓ ฟ|๐ด๓ ง๓ ข๓ ท๓ ฌ๓ ณ๓ 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๐ฝโโ๏ธ|๐
๐พโโ๏ธ|๐
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โ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐ฃ๐ปโโ๏ธ|๐ฃ๐ผโโ๏ธ|๐ฃ๐ฝโโ๏ธ|๐ฃ๐พโโ๏ธ|๐ฃ๐ฟโโ๏ธ|๐ฃ๐ปโโ๏ธ|๐ฃ๐ผโโ๏ธ|๐ฃ๐ฝโโ๏ธ|๐ฃ๐พโโ๏ธ|๐ฃ๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐ด๐ปโโ๏ธ|๐ด๐ผโโ๏ธ|๐ด๐ฝโโ๏ธ|๐ด๐พโโ๏ธ|๐ด๐ฟโโ๏ธ|๐ด๐ปโโ๏ธ|๐ด๐ผโโ๏ธ|๐ด๐ฝโโ๏ธ|๐ด๐พโโ๏ธ|๐ด๐ฟโโ๏ธ|๐ต๐ปโโ๏ธ|๐ต๐ผโโ๏ธ|๐ต๐ฝโโ๏ธ|๐ต๐พโโ๏ธ|๐ต๐ฟโโ๏ธ|๐ต๐ปโโ๏ธ|๐ต๐ผโโ๏ธ|๐ต๐ฝโโ๏ธ|๐ต๐พโโ๏ธ|๐ต๐ฟโโ๏ธ|๐คธ๐ปโโ๏ธ|๐คธ๐ผโโ๏ธ|๐คธ๐ฝโโ๏ธ|๐คธ๐พโโ๏ธ|๐คธ๐ฟโโ๏ธ|๐คธ๐ปโโ๏ธ|๐คธ๐ผโโ๏ธ|๐คธ๐ฝโโ๏ธ|๐คธ๐พโโ๏ธ|๐คธ๐ฟโโ๏ธ|๐คฝ๐ปโโ๏ธ|๐คฝ๐ผโโ๏ธ|๐คฝ๐ฝโโ๏ธ|๐คฝ๐พโโ๏ธ|๐คฝ๐ฟโโ๏ธ|๐คฝ๐ปโโ๏ธ|๐คฝ๐ผโโ๏ธ|๐คฝ๐ฝโโ๏ธ|๐คฝ๐พโโ๏ธ|๐คฝ๐ฟโโ๏ธ|๐คพ๐ปโโ๏ธ|๐คพ๐ผโโ๏ธ|๐คพ๐ฝโโ๏ธ|๐คพ๐พโโ๏ธ|๐คพ๐ฟโโ๏ธ|๐คพ๐ปโโ๏ธ|๐คพ๐ผโโ๏ธ|๐คพ๐ฝโโ๏ธ|๐คพ๐พโโ๏ธ|๐คพ๐ฟโโ๏ธ|๐คน๐ปโโ๏ธ|๐คน๐ผโโ๏ธ|๐คน๐ฝโโ๏ธ|๐คน๐พโโ๏ธ|๐คน๐ฟโโ๏ธ|๐คน๐ปโโ๏ธ|๐คน๐ผโโ๏ธ|๐คน๐ฝโโ๏ธ|๐คน๐พโโ๏ธ|๐คน๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ถโ๐ซ๏ธ|๐ต๏ธโโ๏ธ|๐ต๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐ณ๏ธโ๐|๐ณ๏ธโโง๏ธ|โน๐ปโโ๏ธ|โน๐ผโโ๏ธ|โน๐ฝโโ๏ธ|โน๐พโโ๏ธ|โน๐ฟโโ๏ธ|โน๐ปโโ๏ธ|โน๐ผโโ๏ธ|โน๐ฝโโ๏ธ|โน๐พโโ๏ธ|โน๐ฟโโ๏ธ|๐ฎโ๐จ|๐ตโ๐ซ|โค๏ธโ๐ฅ|โค๏ธโ๐ฉน|๐งโโ๏ธ|๐งโโ๏ธ|๐จโ๐ฆฐ|๐จโ๐ฆฑ|๐จโ๐ฆณ|๐จโ๐ฆฒ|๐ฉโ๐ฆฐ|๐งโ๐ฆฐ|๐ฉโ๐ฆฑ|๐งโ๐ฆฑ|๐ฉโ๐ฆณ|๐งโ๐ฆณ|๐ฉโ๐ฆฒ|๐งโ๐ฆฒ|๐ฑโโ๏ธ|๐ฑโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐
โโ๏ธ|๐
โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐คฆโโ๏ธ|๐คฆโโ๏ธ|๐คทโโ๏ธ|๐คทโโ๏ธ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐|๐จโ๐|๐ฉโ๐|๐งโ๐ซ|๐จโ๐ซ|๐ฉโ๐ซ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐พ|๐จโ๐พ|๐ฉโ๐พ|๐งโ๐ณ|๐จโ๐ณ|๐ฉโ๐ณ|๐งโ๐ง|๐จโ๐ง|๐ฉโ๐ง|๐งโ๐ญ|๐จโ๐ญ|๐ฉโ๐ญ|๐งโ๐ผ|๐จโ๐ผ|๐ฉโ๐ผ|๐งโ๐ฌ|๐จโ๐ฌ|๐ฉโ๐ฌ|๐งโ๐ป|๐จโ๐ป|๐ฉโ๐ป|๐งโ๐ค|๐จโ๐ค|๐ฉโ๐ค|๐งโ๐จ|๐จโ๐จ|๐ฉโ๐จ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐|๐จโ๐|๐ฉโ๐|๐งโ๐|๐จโ๐|๐ฉโ๐|๐ฎโโ๏ธ|๐ฎโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ทโโ๏ธ|๐ทโโ๏ธ|๐ณโโ๏ธ|๐ณโโ๏ธ|๐คตโโ๏ธ|๐คตโโ๏ธ|๐ฐโโ๏ธ|๐ฐโโ๏ธ|๐ฉโ๐ผ|๐จโ๐ผ|๐งโ๐ผ|๐งโ๐|๐ฆธโโ๏ธ|๐ฆธโโ๏ธ|๐ฆนโโ๏ธ|๐ฆนโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ถโโ๏ธ|๐ถโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโ๐ฆฏ|๐จโ๐ฆฏ|๐ฉโ๐ฆฏ|๐งโ๐ฆผ|๐จโ๐ฆผ|๐ฉโ๐ฆผ|๐งโ๐ฆฝ|๐จโ๐ฆฝ|๐ฉโ๐ฆฝ|๐โโ๏ธ|๐โโ๏ธ|๐ฏโโ๏ธ|๐ฏโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ฃโโ๏ธ|๐ฃโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|โน๏ธโโ๏ธ|โน๏ธโโ๏ธ|๐ดโโ๏ธ|๐ดโโ๏ธ|๐ตโโ๏ธ|๐ตโโ๏ธ|๐คธโโ๏ธ|๐คธโโ๏ธ|๐คผโโ๏ธ|๐คผโโ๏ธ|๐คฝโโ๏ธ|๐คฝโโ๏ธ|๐คพโโ๏ธ|๐คพโโ๏ธ|๐คนโโ๏ธ|๐คนโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐จโ๐ฆ|๐จโ๐ง|๐ฉโ๐ฆ|๐ฉโ๐ง|๐โ๐ฆบ|๐ปโโ๏ธ|๐ดโโ ๏ธ|๐โโฌ|๐ฆ๐จ|๐ฆ๐ฉ|๐ฆ๐ช|๐ฆ๐ซ|๐ฆ๐ฌ|๐ฆ๐ฎ|๐ฆ๐ฑ|๐ฆ๐ฒ|๐ฆ๐ด|๐ฆ๐ถ|๐ฆ๐ท|๐ฆ๐ธ|๐ฆ๐น|๐ฆ๐บ|๐ฆ๐ผ|๐ฆ๐ฝ|๐ฆ๐ฟ|๐ง๐ฆ|๐ง๐ง|๐ง๐ฉ|๐ง๐ช|๐ง๐ซ|๐ง๐ฌ|๐ง๐ญ|๐ง๐ฎ|๐ง๐ฏ|๐ง๐ฑ|๐ง๐ฒ|๐ง๐ณ|๐ง๐ด|๐ง๐ถ|๐ง๐ท|๐ง๐ธ|๐ง๐น|๐ง๐ป|๐ง๐ผ|๐ง๐พ|๐ง๐ฟ|๐จ๐ฆ|๐จ๐จ|๐จ๐ฉ|๐จ๐ซ|๐จ๐ฌ|๐จ๐ญ|๐จ๐ฎ|๐จ๐ฐ|๐จ๐ฑ|๐จ๐ฒ|๐จ๐ณ|๐จ๐ด|๐จ๐ต|๐จ๐ท|๐จ๐บ|๐จ๐ป|๐จ๐ผ|๐จ๐ฝ|๐จ๐พ|๐จ๐ฟ|๐ฉ๐ช|๐ฉ๐ฌ|๐ฉ๐ฏ|๐ฉ๐ฐ|๐ฉ๐ฒ|๐ฉ๐ด|๐ฉ๐ฟ|๐ช๐ฆ|๐ช๐จ|๐ช๐ช|๐ช๐ฌ|๐ช๐ญ|๐ช๐ท|๐ช๐ธ|๐ช๐น|๐ช๐บ|๐ซ๐ฎ|๐ซ๐ฏ|๐ซ๐ฐ|๐ซ๐ฒ|๐ซ๐ด|๐ซ๐ท|๐ฌ๐ฆ|๐ฌ๐ง|๐ฌ๐ฉ|๐ฌ๐ช|๐ฌ๐ซ|๐ฌ๐ฌ|๐ฌ๐ญ|๐ฌ๐ฎ|๐ฌ๐ฑ|๐ฌ๐ฒ|๐ฌ๐ณ|๐ฌ๐ต|๐ฌ๐ถ|๐ฌ๐ท|๐ฌ๐ธ|๐ฌ๐น|๐ฌ๐บ|๐ฌ๐ผ|๐ฌ๐พ|๐ญ๐ฐ|๐ญ๐ฒ|๐ญ๐ณ|๐ญ๐ท|๐ญ๐น|๐ญ๐บ|๐ฎ๐จ|๐ฎ๐ฉ|๐ฎ๐ช|๐ฎ๐ฑ|๐ฎ๐ฒ|๐ฎ๐ณ|๐ฎ๐ด|๐ฎ๐ถ|๐ฎ๐ท|๐ฎ๐ธ|๐ฎ๐น|๐ฏ๐ช|๐ฏ๐ฒ|๐ฏ๐ด|๐ฏ๐ต|๐ฐ๐ช|๐ฐ๐ฌ|๐ฐ๐ญ|๐ฐ๐ฎ|๐ฐ๐ฒ|๐ฐ๐ณ|๐ฐ๐ต|๐ฐ๐ท|๐ฐ๐ผ|๐ฐ๐พ|๐ฐ๐ฟ|๐ฑ๐ฆ|๐ฑ๐ง|๐ฑ๐จ|๐ฑ๐ฎ|๐ฑ๐ฐ|๐ฑ๐ท|๐ฑ๐ธ|๐ฑ๐น|๐ฑ๐บ|๐ฑ๐ป|๐ฑ๐พ|๐ฒ๐ฆ|๐ฒ๐จ|๐ฒ๐ฉ|๐ฒ๐ช|๐ฒ๐ซ|๐ฒ๐ฌ|๐ฒ๐ญ|๐ฒ๐ฐ|๐ฒ๐ฑ|๐ฒ๐ฒ|๐ฒ๐ณ|๐ฒ๐ด|๐ฒ๐ต|๐ฒ๐ถ|๐ฒ๐ท|๐ฒ๐ธ|๐ฒ๐น|๐ฒ๐บ|๐ฒ๐ป|๐ฒ๐ผ|๐ฒ๐ฝ|๐ฒ๐พ|๐ฒ๐ฟ|๐ณ๐ฆ|๐ณ๐จ|๐ณ๐ช|๐ณ๐ซ|๐ณ๐ฌ|๐ณ๐ฎ|๐ณ๐ฑ|๐ณ๐ด|๐ณ๐ต|๐ณ๐ท|๐ณ๐บ|๐ณ๐ฟ|๐ด๐ฒ|๐ต๐ฆ|๐ต๐ช|๐ต๐ซ|๐ต๐ฌ|๐ต๐ญ|๐ต๐ฐ|๐ต๐ฑ|๐ต๐ฒ|๐ต๐ณ|๐ต๐ท|๐ต๐ธ|๐ต๐น|๐ต๐ผ|๐ต๐พ|๐ถ๐ฆ|๐ท๐ช|๐ท๐ด|๐ท๐ธ|๐ท๐บ|๐ท๐ผ|๐ธ๐ฆ|๐ธ๐ง|๐ธ๐จ|๐ธ๐ฉ|๐ธ๐ช|๐ธ๐ฌ|๐ธ๐ญ|๐ธ๐ฎ|๐ธ๐ฏ|๐ธ๐ฐ|๐ธ๐ฑ|๐ธ๐ฒ|๐ธ๐ณ|๐ธ๐ด|๐ธ๐ท|๐ธ๐ธ|๐ธ๐น|๐ธ๐ป|๐ธ๐ฝ|๐ธ๐พ|๐ธ๐ฟ|๐น๐ฆ|๐น๐จ|๐น๐ฉ|๐น๐ซ|๐น๐ฌ|๐น๐ญ|๐น๐ฏ|๐น๐ฐ|๐น๐ฑ|๐น๐ฒ|๐น๐ณ|๐น๐ด|๐น๐ท|๐น๐น|๐น๐ป|๐น๐ผ|๐น๐ฟ|๐บ๐ฆ|๐บ๐ฌ|๐บ๐ฒ|๐บ๐ณ|๐บ๐ธ|๐บ๐พ|๐บ๐ฟ|๐ป๐ฆ|๐ป๐จ|๐ป๐ช|๐ป๐ฌ|๐ป๐ฎ|๐ป๐ณ|๐ป๐บ|๐ผ๐ซ|๐ผ๐ธ|๐ฝ๐ฐ|๐พ๐ช|๐พ๐น|๐ฟ๐ฆ|๐ฟ๐ฒ|๐ฟ๐ผ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐คฒ๐ป|๐คฒ๐ผ|๐คฒ๐ฝ|๐คฒ๐พ|๐คฒ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐
๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
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๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐คฆ๐ป|๐คฆ๐ผ|๐คฆ๐ฝ|๐คฆ๐พ|๐คฆ๐ฟ|๐คท๐ป|๐คท๐ผ|๐คท๐ฝ|๐คท๐พ|๐คท๐ฟ|๐ฎ๐ป|๐ฎ๐ผ|๐ฎ๐ฝ|๐ฎ๐พ|๐ฎ๐ฟ|๐ต๐ป|๐ต๐ผ|๐ต๐ฝ|๐ต๐พ|๐ต๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ฅท๐ป|๐ฅท๐ผ|๐ฅท๐ฝ|๐ฅท๐พ|๐ฅท๐ฟ|๐ท๐ป|๐ท๐ผ|๐ท๐ฝ|๐ท๐พ|๐ท๐ฟ|๐คด๐ป|๐คด๐ผ|๐คด๐ฝ|๐คด๐พ|๐คด๐ฟ|๐ธ๐ป|๐ธ๐ผ|๐ธ๐ฝ|๐ธ๐พ|๐ธ๐ฟ|๐ณ๐ป|๐ณ๐ผ|๐ณ๐ฝ|๐ณ๐พ|๐ณ๐ฟ|๐ฒ๐ป|๐ฒ๐ผ|๐ฒ๐ฝ|๐ฒ๐พ|๐ฒ๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐คต๐ป|๐คต๐ผ|๐คต๐ฝ|๐คต๐พ|๐คต๐ฟ|๐ฐ๐ป|๐ฐ๐ผ|๐ฐ๐ฝ|๐ฐ๐พ|๐ฐ๐ฟ|๐คฐ๐ป|๐คฐ๐ผ|๐คฐ๐ฝ|๐คฐ๐พ|๐คฐ๐ฟ|๐คฑ๐ป|๐คฑ๐ผ|๐คฑ๐ฝ|๐คฑ๐พ|๐คฑ๐ฟ|๐ผ๐ป|๐ผ๐ผ|๐ผ๐ฝ|๐ผ๐พ|๐ผ๐ฟ|๐
๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
๐ฟ|๐คถ๐ป|๐คถ๐ผ|๐คถ๐ฝ|๐คถ๐พ|๐คถ๐ฟ|๐ฆธ๐ป|๐ฆธ๐ผ|๐ฆธ๐ฝ|๐ฆธ๐พ|๐ฆธ๐ฟ|๐ฆน๐ป|๐ฆน๐ผ|๐ฆน๐ฝ|๐ฆน๐พ|๐ฆน๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ถ๐ป|๐ถ๐ผ|๐ถ๐ฝ|๐ถ๐พ|๐ถ๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐บ๐ป|๐บ๐ผ|๐บ๐ฝ|๐บ๐พ|๐บ๐ฟ|๐ด๐ป|๐ด๐ผ|๐ด๐ฝ|๐ด๐พ|๐ด๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ฃ๐ป|๐ฃ๐ผ|๐ฃ๐ฝ|๐ฃ๐พ|๐ฃ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ด๐ป|๐ด๐ผ|๐ด๐ฝ|๐ด๐พ|๐ด๐ฟ|๐ต๐ป|๐ต๐ผ|๐ต๐ฝ|๐ต๐พ|๐ต๐ฟ|๐คธ๐ป|๐คธ๐ผ|๐คธ๐ฝ|๐คธ๐พ|๐คธ๐ฟ|๐คฝ๐ป|๐คฝ๐ผ|๐คฝ๐ฝ|๐คฝ๐พ|๐คฝ๐ฟ|๐คพ๐ป|๐คพ๐ผ|๐คพ๐ฝ|๐คพ๐พ|๐คพ๐ฟ|๐คน๐ป|๐คน๐ผ|๐คน๐ฝ|๐คน๐พ|๐คน๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ญ๐ป|๐ญ๐ผ|๐ญ๐ฝ|๐ญ๐พ|๐ญ๐ฟ|๐ซ๐ป|๐ซ๐ผ|๐ซ๐ฝ|๐ซ๐พ|๐ซ๐ฟ|๐ฌ๐ป|๐ฌ๐ผ|๐ฌ๐ฝ|๐ฌ๐พ|๐ฌ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|#๏ธโฃ|0๏ธโฃ|1๏ธโฃ|2๏ธโฃ|3๏ธโฃ|4๏ธโฃ|5๏ธโฃ|6๏ธโฃ|7๏ธโฃ|8๏ธโฃ|9๏ธโฃ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โน๐ป|โน๐ผ|โน๐ฝ|โน๐พ|โน๐ฟ|๐|๐|๐|๐|๐|๐
|๐คฃ|๐|๐|๐|๐|๐|๐|๐ฅฐ|๐|๐คฉ|๐|๐|๐|๐|๐ฅฒ|๐|๐|๐|๐คช|๐|๐ค|๐ค|๐คญ|๐คซ|๐ค|๐ค|๐คจ|๐|๐|๐ถ|๐|๐|๐|๐ฌ|๐คฅ|๐|๐|๐ช|๐คค|๐ด|๐ท|๐ค|๐ค|๐คข|๐คฎ|๐คง|๐ฅต|๐ฅถ|๐ฅด|๐ต|๐คฏ|๐ค |๐ฅณ|๐ฅธ|๐|๐ค|๐ง|๐|๐|๐|๐ฎ|๐ฏ|๐ฒ|๐ณ|๐ฅบ|๐ฆ|๐ง|๐จ|๐ฐ|๐ฅ|๐ข|๐ญ|๐ฑ|๐|๐ฃ|๐|๐|๐ฉ|๐ซ|๐ฅฑ|๐ค|๐ก|๐ |๐คฌ|๐|๐ฟ|๐|๐ฉ|๐คก|๐น|๐บ|๐ป|๐ฝ|๐พ|๐ค|๐บ|๐ธ|๐น|๐ป|๐ผ|๐ฝ|๐|๐ฟ|๐พ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐งก|๐|๐|๐|๐|๐ค|๐ค|๐ค|๐ฏ|๐ข|๐ฅ|๐ซ|๐ฆ|๐จ|๐ณ|๐ฃ|๐ฌ|๐จ|๐ฏ|๐ญ|๐ค|๐|๐ค|๐|๐|๐|๐ค|๐ค|๐ค|๐ค|๐ค|๐ค|๐|๐|๐|๐|๐|๐|๐|๐|๐ค|๐ค|๐|๐|๐|๐คฒ|๐ค|๐|๐
|๐คณ|๐ช|๐ฆพ|๐ฆฟ|๐ฆต|๐ฆถ|๐|๐ฆป|๐|๐ง |๐ซ|๐ซ|๐ฆท|๐ฆด|๐|๐|๐
|๐|๐ถ|๐ง|๐ฆ|๐ง|๐ง|๐ฑ|๐จ|๐ง|๐ฉ|๐ง|๐ด|๐ต|๐|๐|๐
|๐|๐|๐|๐ง|๐|๐คฆ|๐คท|๐ฎ|๐ต|๐|๐ฅท|๐ท|๐คด|๐ธ|๐ณ|๐ฒ|๐ง|๐คต|๐ฐ|๐คฐ|๐คฑ|๐ผ|๐
|๐คถ|๐ฆธ|๐ฆน|๐ง|๐ง|๐ง|๐ง|๐ง|๐ง|๐ง|๐|๐|๐ถ|๐ง|๐ง|๐|๐|๐บ|๐ด|๐ฏ|๐ง|๐ง|๐คบ|๐|๐|๐|๐|๐ฃ|๐|๐|๐ด|๐ต|๐คธ|๐คผ|๐คฝ|๐คพ|๐คน|๐ง|๐|๐|๐ญ|๐ซ|๐ฌ|๐|๐|๐ช|๐ฃ|๐ค|๐ฅ|๐ซ|๐ฃ|๐ฆฐ|๐ฆฑ|๐ฆณ|๐ฆฒ|๐ต|๐|๐ฆ|๐ฆง|๐ถ|๐|๐ฆฎ|๐ฉ|๐บ|๐ฆ|๐ฆ|๐ฑ|๐|๐ฆ|๐ฏ|๐
|๐|๐ด|๐|๐ฆ|๐ฆ|๐ฆ|๐ฆฌ|๐ฎ|๐|๐|๐|๐ท|๐|๐|๐ฝ|๐|๐|๐|๐ช|๐ซ|๐ฆ|๐ฆ|๐|๐ฆฃ|๐ฆ|๐ฆ|๐ญ|๐|๐|๐น|๐ฐ|๐|๐ฟ|๐ฆซ|๐ฆ|๐ฆ|๐ป|๐จ|๐ผ|๐ฆฅ|๐ฆฆ|๐ฆจ|๐ฆ|๐ฆก|๐พ|๐ฆ|๐|๐|๐ฃ|๐ค|๐ฅ|๐ฆ|๐ง|๐|๐ฆ
|๐ฆ|๐ฆข|๐ฆ|๐ฆค|๐ชถ|๐ฆฉ|๐ฆ|๐ฆ|๐ธ|๐|๐ข|๐ฆ|๐|๐ฒ|๐|๐ฆ|๐ฆ|๐ณ|๐|๐ฌ|๐ฆญ|๐|๐ |๐ก|๐ฆ|๐|๐|๐|๐ฆ|๐|๐|๐|๐ชฒ|๐|๐ฆ|๐ชณ|๐ท|๐ธ|๐ฆ|๐ฆ|๐ชฐ|๐ชฑ|๐ฆ |๐|๐ธ|๐ฎ|๐ต|๐น|๐ฅ|๐บ|๐ป|๐ผ|๐ท|๐ฑ|๐ชด|๐ฒ|๐ณ|๐ด|๐ต|๐พ|๐ฟ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฅญ|๐|๐|๐|๐|๐|๐|๐ซ|๐ฅ|๐
|๐ซ|๐ฅฅ|๐ฅ|๐|๐ฅ|๐ฅ|๐ฝ|๐ถ|๐ซ|๐ฅ|๐ฅฌ|๐ฅฆ|๐ง|๐ง
|๐|๐ฅ|๐ฐ|๐|๐ฅ|๐ฅ|๐ซ|๐ฅจ|๐ฅฏ|๐ฅ|๐ง|๐ง|๐|๐|๐ฅฉ|๐ฅ|๐|๐|๐|๐ญ|๐ฅช|๐ฎ|๐ฏ|๐ซ|๐ฅ|๐ง|๐ฅ|๐ณ|๐ฅ|๐ฒ|๐ซ|๐ฅฃ|๐ฅ|๐ฟ|๐ง|๐ง|๐ฅซ|๐ฑ|๐|๐|๐|๐|๐|๐|๐ |๐ข|๐ฃ|๐ค|๐ฅ|๐ฅฎ|๐ก|๐ฅ|๐ฅ |๐ฅก|๐ฆ|๐ฆ|๐ฆ|๐ฆ|๐ฆช|๐ฆ|๐ง|๐จ|๐ฉ|๐ช|๐|๐ฐ|๐ง|๐ฅง|๐ซ|๐ฌ|๐ญ|๐ฎ|๐ฏ|๐ผ|๐ฅ|๐ซ|๐ต|๐ถ|๐พ|๐ท|๐ธ|๐น|๐บ|๐ป|๐ฅ|๐ฅ|๐ฅค|๐ง|๐ง|๐ง|๐ง|๐ฅข|๐ฝ|๐ด|๐ฅ|๐ช|๐บ|๐|๐|๐|๐|๐บ|๐พ|๐งญ|๐|๐|๐ป|๐|๐|๐|๐|๐|๐|๐|๐|๐งฑ|๐ชจ|๐ชต|๐|๐|๐|๐ |๐ก|๐ข|๐ฃ|๐ค|๐ฅ|๐ฆ|๐จ|๐ฉ|๐ช|๐ซ|๐ฌ|๐ญ|๐ฏ|๐ฐ|๐|๐ผ|๐ฝ|๐|๐|๐|๐|๐|๐|๐|๐|๐
|๐|๐|๐|๐ |๐ก|๐ข|๐|๐ช|๐|๐|๐|๐
|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ป|๐|๐|๐|๐|๐|๐ต|๐ฆฝ|๐ฆผ|๐บ|๐ฒ|๐ด|๐น|๐ผ|๐|๐ฃ|๐ค|๐ข|๐จ|๐ฅ|๐ฆ|๐|๐ง|๐ถ|๐ค|๐ณ|๐ฅ|๐ข|๐ฉ|๐ซ|๐ฌ|๐ช|๐บ|๐|๐|๐ |๐ก|๐ฐ|๐|๐ธ|๐|๐งณ|๐ฐ|๐|๐ง|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ |๐|๐ก|๐|๐ข|๐|๐ฃ|๐|๐ค|๐|๐ฅ|๐|๐ฆ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ก|๐|๐|๐ช|๐|๐ |๐|๐ค|๐ฅ|๐ฆ|๐ง|๐จ|๐ฉ|๐ช|๐ซ|๐ฌ|๐|๐|๐|๐ฅ|๐ง|๐|๐|๐|๐|๐|๐งจ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐งง|๐|๐|๐|๐|๐ซ|๐|๐|๐
|๐ฅ|๐ฅ|๐ฅ|๐ฅ|๐|๐|๐|๐|๐พ|๐ฅ|๐ณ|๐|๐|๐|๐ฅ|๐|๐ธ|๐ฅ|๐ฅ|๐ฅ
|๐ฃ|๐คฟ|๐ฝ|๐ฟ|๐ท|๐ฅ|๐ฏ|๐ช|๐ช|๐ฑ|๐ฎ|๐ช|๐งฟ|๐ฎ|๐น|๐ฐ|๐ฒ|๐งฉ|๐งธ|๐ช
|๐ช|๐|๐|๐ด|๐ญ|๐ผ|๐จ|๐งต|๐ชก|๐งถ|๐ชข|๐|๐ถ|๐ฅฝ|๐ฅผ|๐ฆบ|๐|๐|๐|๐งฃ|๐งค|๐งฅ|๐งฆ|๐|๐|๐ฅป|๐ฉฑ|๐ฉฒ|๐ฉณ|๐|๐|๐|๐|๐|๐|๐|๐ฉด|๐|๐|๐ฅพ|๐ฅฟ|๐ |๐ก|๐ฉฐ|๐ข|๐|๐|๐ฉ|๐|๐งข|๐ช|๐ฟ|๐|๐|๐|๐|๐|๐|๐|๐ข|๐ฃ|๐ฏ|๐|๐|๐ผ|๐ต|๐ถ|๐|๐|๐|๐ค|๐ง|๐ป|๐ท|๐ช|๐ธ|๐น|๐บ|๐ป|๐ช|๐ฅ|๐ช|๐ฑ|๐ฒ|๐|๐|๐ |๐|๐|๐ป|๐ฅ|๐จ|๐ฑ|๐ฒ|๐ฝ|๐พ|๐ฟ|๐|๐งฎ|๐ฅ|๐|๐ฝ|๐ฌ|๐บ|๐ท|๐ธ|๐น|๐ผ|๐|๐|๐ฏ|๐ก|๐ฆ|๐ฎ|๐ช|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฐ|๐|๐|๐|๐ท|๐ฐ|๐ช|๐ด|๐ต|๐ถ|๐ท|๐ธ|๐ณ|๐งพ|๐น|๐ง|๐จ|๐ฉ|๐ค|๐ฅ|๐ฆ|๐ซ|๐ช|๐ฌ|๐ญ|๐ฎ|๐ณ|๐|๐|๐|๐|๐|๐ผ|๐|๐|๐|๐
|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐จ|๐ช|๐ |๐ก|๐ซ|๐ช|๐น|๐ก|๐ช|๐ง|๐ช|๐ฉ|๐|๐ฆฏ|๐|๐ช|๐งฐ|๐งฒ|๐ช|๐งช|๐งซ|๐งฌ|๐ฌ|๐ญ|๐ก|๐|๐ฉธ|๐|๐ฉน|๐ฉบ|๐ช|๐|๐ช|๐ช|๐|๐|๐ช|๐ฝ|๐ช |๐ฟ|๐|๐ชค|๐ช|๐งด|๐งท|๐งน|๐งบ|๐งป|๐ชฃ|๐งผ|๐ชฅ|๐งฝ|๐งฏ|๐|๐ฌ|๐ชฆ|๐ฟ|๐ชง|๐ง|๐ฎ|๐ฐ|๐น|๐บ|๐ป|๐ผ|๐พ|๐|๐|๐|๐
|๐ธ|๐ซ|๐ณ|๐ญ|๐ฏ|๐ฑ|๐ท|๐ต|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฏ|๐|๐|๐|๐ผ|๐ฝ|๐ฆ|๐
|๐|๐ถ|๐ณ|๐ด|๐ฑ|๐ฒ|๐ฑ|๐|๐ฐ|๐|๐ |๐ก|๐ข|๐ฃ|๐ค|๐
ฐ|๐|๐
ฑ|๐|๐|๐|๐|๐|๐|๐
พ|๐|๐
ฟ|๐|๐|๐|๐|๐|๐ท|๐ถ|๐ฏ|๐|๐น|๐|๐ฒ|๐|๐ธ|๐ด|๐ณ|๐บ|๐ต|๐ด|๐ |๐ก|๐ข|๐ต|๐ฃ|๐ค|๐ฅ|๐ง|๐จ|๐ฉ|๐ฆ|๐ช|๐ซ|๐ถ|๐ท|๐ธ|๐น|๐บ|๐ป|๐ |๐|๐ณ|๐ฒ|๐|๐ฉ|๐|๐ด|๐ณ|๐ป|๐ผ|๐ฝ|๐พ|๐ฟ|โบ|โน|โ |โฃ|โค|โ|โ|โ|โ|โ|โท|โน|โ|โ|โฐ|โช|โฉ|โฒ|โบ|โจ|โฝ|โ|โต|โด|โ|โ|โณ|โ|โฐ|โฑ|โฒ|โ|โญ|โ|โ
|โ|โ|โ|โฑ|โก|โ|โ|โ|โ|โจ|โฝ|โพ|โณ|โธ|โ |โฅ|โฆ|โฃ|โ|โ|โ|โจ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โฐ|โฑ|โฟ|โ |โ|โข|โฃ|โฌ|โ|โก|โ|โฌ|โ|โฌ
|โ|โ|โ|โฉ|โช|โคด|โคต|โ|โก|โธ|โฏ|โ|โฆ|โช|โฎ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โถ|โฉ|โญ|โฏ|โ|โช|โฎ|โซ|โฌ|โธ|โน|โบ|โ|โ|โ|โง|โ|โ|โ|โ|โพ|โผ|โ|โ|โ|โ|โ|ใฐ|โ|โป|โ|โญ|โ
|โ|โ|โ|โ|โฐ|โฟ|ใฝ|โณ|โด|โ|ยฉ|ยฎ|โข|โน|โ|ใ|ใ|โซ|โช|โฌ|โฌ|โผ|โป|โพ|โฝ|โช|โซ)`
/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g");
/*count of emojis*/
let emoCount = [..."๐ถ๐ป๐ฆ๐ป๐ง๐ป๐จ๐ป๐ฉ๐ป๐ฑ๐ปโโ๏ธ๐ฑ๐ป๐ด๐ป๐ต๐ป๐ฒ๐ป๐ณ๐ปโโ๏ธ๐ณ๐ป๐ฎ๐ปโโ๏ธ๐ฎ๐ป๐ท๐ปโโ๏ธ๐ท๐ป๐๐ปโโ๏ธ๐๐ป๐ต๐ปโโ๏ธ๐ฉ๐ปโโ๏ธ๐จ๐ปโโ๏ธ๐ฉ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ".matchAll(emoRegex)].length
console.log(emoCount) //37
/*modifying the pattern to count other characters too*/
let generalCounter = new RegExp(emojiPattern+"|.", "g") //emoji or regular character
let allCount = [..."$%^ other stuff equalling 28๐ถ๐ฆ๐ป๐ง๐ป๐จ๐ป๐ฉ๐ป๐ฑ๐ปโโ๏ธ๐ฑ๐ป๐ด๐ป๐ต๐ป๐ฒ๐ป๐ณ๐ปโโ๏ธ๐ณ๐ป๐ฎ๐ปโโ๏ธ๐ฎ๐ป๐ท๐ปโโ๏ธ๐ท๐ป๐๐ปโโ๏ธ๐๐ป๐ต๐ปโโ๏ธ๐ฉ๐ปโโ๏ธ๐จ๐ปโโ๏ธ๐ฉ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ".matchAll(generalCounter)].length
console.log(allCount) //28+37 = 65
As you can see from the below example, this is to do with unicode encoding,
There's some great resources such as the one I took this example from.
https://blog.jonnew.com/posts/poo-dot-length-equals-two
console.log("๐ฉโโค๏ธโ๐โ๐ฉ".length === 11);
For anyone interested, I had a similar problem where I wanted to count the length of an emoji at the end of a string.
This is the solution I came up with:
var emoji = new RegExp('(\\p{Extended_Pictographic})((\u200D\\p{Extended_Pictographic})*)$', 'u');
var testStrings = ['๐จโ๐ฉโ๐ง', '๐', '๐ฒ'];
for(var string = 0; string < testStrings.length; string++){
var match = testStrings[string].match(emoji);
var chars = match == null ? 0 : match[0].length;
console.log(testStrings[string] + ': ' + chars);
}
Explanation: \\p{Extended_Pictographic} matches an emoji like ๐, consisting of two characters. Emojis like ๐จโ๐ฉโ๐ง consists of 4 emojis (๐จ, ๐ฉ, ๐ง,๐ฆ) combined by a zero width joiner (\u200D).
The regex matches any emoji at the end ($). If there is a match the length is counted. I am sure it could be adopted for your use-case by matching all emojis in a given string and then subtracting the surplus. It's not a complete implementation for your particular question but I hope this gets you on the right track.
use lodash toArray method
console.log(_.toArray("๐จโ๐ฉโ๐ง").length); // 1
console.log(_.toArray("๐จโ๐ฉโ๐ง๐งโโ๏ธ๐ฉโ๐งโ๐ง").length); // 3
Check here for Codesandbox
I suggest using the runes package to accomplish correct multi-byte string conversions cause else you will get more issues if using reducers and more to reverse strings for example.
Take a look at this great small package: runes
I've a little problem.
I'm using NodeJS as backend. Now, an user has a field "biography", where the user can write something about himself.
Suppose that this field has 220 maxlength, and suppose this as input:
๐ถ๐ป๐ฆ๐ป๐ง๐ป๐จ๐ป๐ฉ๐ป๐ฑ๐ปโโ๏ธ๐ฑ๐ป๐ด๐ป๐ต๐ป๐ฒ๐ป๐ณ๐ปโโ๏ธ๐ณ๐ป๐ฎ๐ปโโ๏ธ๐ฎ๐ป๐ท๐ปโโ๏ธ๐ท๐ป๐๐ปโโ๏ธ๐๐ป๐ต๐ปโโ๏ธ๐ฉ๐ปโโ๏ธ๐จ๐ปโโ๏ธ๐ฉ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ
As you can see there aren't 220 emojis (there are 37 emojis), but if I do in my nodejs server
console.log(bio.length)
where bio is the input text, I got 221. How could I "parse" the string input to get the correct length? Is it a problem about unicode?
SOLVED
I used this library: https://github.com/orling/grapheme-splitter
I tried that:
var Grapheme = require('grapheme-splitter');
var splitter = new Grapheme();
console.log(splitter.splitGraphemes(bio).length);
and the length is 37. It works very well!
str.length gives the count of UTF-16 units.
Unicode-proof way to get string length in codepoints (in characters) is [...str].length as iterable protocol splits the string to codepoints.
If we need the length in graphemes (grapheme clusters), we have these native ways:
a. Unicode property escapes in RegExp. See for example: Unicode-aware version of \w or Matching emoji.
b. Intl.Segmenter โ coming soon, probably in ES2021. Can be tested with a flag in the last V8 versions (realization was synced with the last spec in V8 86). Unflagged (shipped) in V8 87.
See also:
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)
What every JavaScript developer should know about Unicode
JavaScript has a Unicode problem
Unicode-aware regular expressions in ES2015
ES6 Strings (and Unicode, โค) in Depth
JavaScript for impatient programmers. Unicode โ a brief introduction
TL;DR there are solutions, but they donโt work in every case. Unicode can feel like a dark art.
There seems to be limitations in various solutions I have seen presented, with the issue going beyond emojis and covering other characters in the Unicode range. Consider รฉ can be stored as รฉ or e + โ, if using combing characters. This can even lead to two strings that look the same not being equal. Also note, in certain cases a single emoji can be 11 characters when stored and as a result 22 bytes, assuming UTF16.
The way this is handled and how characters are combined, or displayed, can even vary between browsers and operating systems. So, while you may think you cracked it, there is a risk another environment breaks this. Be sure to test where it matters.
Now, there is the front-end vs back-end problem: you solved the character count problem so it works well for human users, now your single emoji blows right past the allocated field size in the database. Less of an issue with databases such as mongo, but can be one with SQL databases, where field allocation was conservative. This means how you solve your problem will depend where the hardest limitation comes in.
Note, that a basic solution does involve converting a string to an array and getting the length, accepting limitations:
Array.from(str)
This will fall apart when characters are combined and dealing with astral planes.
A few high level approaches, that take into account limitations:
use approaches that solve the front-end issue, as best as possible, and then ensure storage issues are resolved
be more conservative with the advertised front-end limits, if the database or other storage canโt be adjusted
limit the character types that can be entered
clearly indicate limitations of the length calculation
Additionally, given the complexity of the issue it may be worth seeing if there is a popular JS library that already deals with this? I did not find one at the time of writing. Hopefully this is something that would become core to Javascript at some point.
Other pages to read:
https://blog.jonnew.com/posts/poo-dot-length-equals-two
https://mathiasbynens.be/notes/javascript-unicode
https://www.contentful.com/blog/2016/12/06/unicode-javascript-and-the-emoji-family/
https://dmitripavlutin.com/what-every-javascript-developer-should-know-about-unicode/
I answered to a similar question here
But basically, here it is :
'๐'.match(/./gu).length == 1
As :
'๐'.length == 2
More precision in my original post
function fancyCount2(str){
const joiner = "\u{200D}";
const split = str.split(joiner);
let count = 0;
for(const s of split){
//removing the variation selectors
const num = Array.from(s.split(/[\ufe00-\ufe0f]/).join("")).length;
count += num;
}
//assuming the joiners are used appropriately
return count / split.length;
}
With a regex that can parse emojis, this can be done easily and without the use of external libraries. Please see the code snippets for examples. ๐ท๐ปโโ๏ธ
Note that grapheme-splitter as suggested in the question will overcount and split apart compound emojis that contain other emojis, such as this one: ๐ง๐ปโ๐คโ๐ง๐ป. This is reported as three distinct "graphemes", ๐ง๐ปโ and ๐คโ and ๐ง๐ป
Here we are using the 'compact', literal version so it'll fit, but there's a safe, long version that uses Unicode escapes as well.
For more info on the regex see also this answer.
/*the pattern (compact version)*/
var emojiPattern = String.raw`(?:๐ง๐ปโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ปโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ปโโค๏ธโ๐โ๐ง๐พ|๐ง๐ปโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ผโโค๏ธโ๐โ๐ง๐ป|๐ง๐ผโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ผโโค๏ธโ๐โ๐ง๐พ|๐ง๐ผโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ป|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐พ|๐ง๐ฝโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐พโโค๏ธโ๐โ๐ง๐ป|๐ง๐พโโค๏ธโ๐โ๐ง๐ผ|๐ง๐พโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐พโโค๏ธโ๐โ๐ง๐ฟ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ป|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ผ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐ฝ|๐ง๐ฟโโค๏ธโ๐โ๐ง๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ผโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ฝโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐พโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ป|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ผ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ฝ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐พ|๐ฉ๐ฟโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ป|๐จ๐ปโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ปโโค๏ธโ๐โ๐จ๐พ|๐จ๐ปโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ป|๐จ๐ผโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ผโโค๏ธโ๐โ๐จ๐พ|๐จ๐ผโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ป|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐พ|๐จ๐ฝโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐พโโค๏ธโ๐โ๐จ๐ป|๐จ๐พโโค๏ธโ๐โ๐จ๐ผ|๐จ๐พโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐พโโค๏ธโ๐โ๐จ๐พ|๐จ๐พโโค๏ธโ๐โ๐จ๐ฟ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ป|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ผ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ฝ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐พ|๐จ๐ฟโโค๏ธโ๐โ๐จ๐ฟ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ปโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ผโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ฝโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐พโโค๏ธโ๐โ๐ฉ๐ฟ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ป|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ผ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ฝ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐พ|๐ฉ๐ฟโโค๏ธโ๐โ๐ฉ๐ฟ|๐ด๓ ง๓ ข๓ ฅ๓ ฎ๓ ง๓ ฟ|๐ด๓ ง๓ ข๓ ณ๓ ฃ๓ ด๓ ฟ|๐ด๓ ง๓ ข๓ ท๓ ฌ๓ ณ๓ 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๐ฝโโ๏ธ|๐
๐พโโ๏ธ|๐
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โ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐ฃ๐ปโโ๏ธ|๐ฃ๐ผโโ๏ธ|๐ฃ๐ฝโโ๏ธ|๐ฃ๐พโโ๏ธ|๐ฃ๐ฟโโ๏ธ|๐ฃ๐ปโโ๏ธ|๐ฃ๐ผโโ๏ธ|๐ฃ๐ฝโโ๏ธ|๐ฃ๐พโโ๏ธ|๐ฃ๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐๐ปโโ๏ธ|๐๐ผโโ๏ธ|๐๐ฝโโ๏ธ|๐๐พโโ๏ธ|๐๐ฟโโ๏ธ|๐ด๐ปโโ๏ธ|๐ด๐ผโโ๏ธ|๐ด๐ฝโโ๏ธ|๐ด๐พโโ๏ธ|๐ด๐ฟโโ๏ธ|๐ด๐ปโโ๏ธ|๐ด๐ผโโ๏ธ|๐ด๐ฝโโ๏ธ|๐ด๐พโโ๏ธ|๐ด๐ฟโโ๏ธ|๐ต๐ปโโ๏ธ|๐ต๐ผโโ๏ธ|๐ต๐ฝโโ๏ธ|๐ต๐พโโ๏ธ|๐ต๐ฟโโ๏ธ|๐ต๐ปโโ๏ธ|๐ต๐ผโโ๏ธ|๐ต๐ฝโโ๏ธ|๐ต๐พโโ๏ธ|๐ต๐ฟโโ๏ธ|๐คธ๐ปโโ๏ธ|๐คธ๐ผโโ๏ธ|๐คธ๐ฝโโ๏ธ|๐คธ๐พโโ๏ธ|๐คธ๐ฟโโ๏ธ|๐คธ๐ปโโ๏ธ|๐คธ๐ผโโ๏ธ|๐คธ๐ฝโโ๏ธ|๐คธ๐พโโ๏ธ|๐คธ๐ฟโโ๏ธ|๐คฝ๐ปโโ๏ธ|๐คฝ๐ผโโ๏ธ|๐คฝ๐ฝโโ๏ธ|๐คฝ๐พโโ๏ธ|๐คฝ๐ฟโโ๏ธ|๐คฝ๐ปโโ๏ธ|๐คฝ๐ผโโ๏ธ|๐คฝ๐ฝโโ๏ธ|๐คฝ๐พโโ๏ธ|๐คฝ๐ฟโโ๏ธ|๐คพ๐ปโโ๏ธ|๐คพ๐ผโโ๏ธ|๐คพ๐ฝโโ๏ธ|๐คพ๐พโโ๏ธ|๐คพ๐ฟโโ๏ธ|๐คพ๐ปโโ๏ธ|๐คพ๐ผโโ๏ธ|๐คพ๐ฝโโ๏ธ|๐คพ๐พโโ๏ธ|๐คพ๐ฟโโ๏ธ|๐คน๐ปโโ๏ธ|๐คน๐ผโโ๏ธ|๐คน๐ฝโโ๏ธ|๐คน๐พโโ๏ธ|๐คน๐ฟโโ๏ธ|๐คน๐ปโโ๏ธ|๐คน๐ผโโ๏ธ|๐คน๐ฝโโ๏ธ|๐คน๐พโโ๏ธ|๐คน๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ง๐ปโโ๏ธ|๐ง๐ผโโ๏ธ|๐ง๐ฝโโ๏ธ|๐ง๐พโโ๏ธ|๐ง๐ฟโโ๏ธ|๐ถโ๐ซ๏ธ|๐ต๏ธโโ๏ธ|๐ต๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐๏ธโโ๏ธ|๐ณ๏ธโ๐|๐ณ๏ธโโง๏ธ|โน๐ปโโ๏ธ|โน๐ผโโ๏ธ|โน๐ฝโโ๏ธ|โน๐พโโ๏ธ|โน๐ฟโโ๏ธ|โน๐ปโโ๏ธ|โน๐ผโโ๏ธ|โน๐ฝโโ๏ธ|โน๐พโโ๏ธ|โน๐ฟโโ๏ธ|๐ฎโ๐จ|๐ตโ๐ซ|โค๏ธโ๐ฅ|โค๏ธโ๐ฉน|๐งโโ๏ธ|๐งโโ๏ธ|๐จโ๐ฆฐ|๐จโ๐ฆฑ|๐จโ๐ฆณ|๐จโ๐ฆฒ|๐ฉโ๐ฆฐ|๐งโ๐ฆฐ|๐ฉโ๐ฆฑ|๐งโ๐ฆฑ|๐ฉโ๐ฆณ|๐งโ๐ฆณ|๐ฉโ๐ฆฒ|๐งโ๐ฆฒ|๐ฑโโ๏ธ|๐ฑโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐
โโ๏ธ|๐
โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐คฆโโ๏ธ|๐คฆโโ๏ธ|๐คทโโ๏ธ|๐คทโโ๏ธ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐|๐จโ๐|๐ฉโ๐|๐งโ๐ซ|๐จโ๐ซ|๐ฉโ๐ซ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐พ|๐จโ๐พ|๐ฉโ๐พ|๐งโ๐ณ|๐จโ๐ณ|๐ฉโ๐ณ|๐งโ๐ง|๐จโ๐ง|๐ฉโ๐ง|๐งโ๐ญ|๐จโ๐ญ|๐ฉโ๐ญ|๐งโ๐ผ|๐จโ๐ผ|๐ฉโ๐ผ|๐งโ๐ฌ|๐จโ๐ฌ|๐ฉโ๐ฌ|๐งโ๐ป|๐จโ๐ป|๐ฉโ๐ป|๐งโ๐ค|๐จโ๐ค|๐ฉโ๐ค|๐งโ๐จ|๐จโ๐จ|๐ฉโ๐จ|๐งโโ๏ธ|๐จโโ๏ธ|๐ฉโโ๏ธ|๐งโ๐|๐จโ๐|๐ฉโ๐|๐งโ๐|๐จโ๐|๐ฉโ๐|๐ฎโโ๏ธ|๐ฎโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ทโโ๏ธ|๐ทโโ๏ธ|๐ณโโ๏ธ|๐ณโโ๏ธ|๐คตโโ๏ธ|๐คตโโ๏ธ|๐ฐโโ๏ธ|๐ฐโโ๏ธ|๐ฉโ๐ผ|๐จโ๐ผ|๐งโ๐ผ|๐งโ๐|๐ฆธโโ๏ธ|๐ฆธโโ๏ธ|๐ฆนโโ๏ธ|๐ฆนโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ถโโ๏ธ|๐ถโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโ๐ฆฏ|๐จโ๐ฆฏ|๐ฉโ๐ฆฏ|๐งโ๐ฆผ|๐จโ๐ฆผ|๐ฉโ๐ฆผ|๐งโ๐ฆฝ|๐จโ๐ฆฝ|๐ฉโ๐ฆฝ|๐โโ๏ธ|๐โโ๏ธ|๐ฏโโ๏ธ|๐ฏโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|๐ฃโโ๏ธ|๐ฃโโ๏ธ|๐โโ๏ธ|๐โโ๏ธ|โน๏ธโโ๏ธ|โน๏ธโโ๏ธ|๐ดโโ๏ธ|๐ดโโ๏ธ|๐ตโโ๏ธ|๐ตโโ๏ธ|๐คธโโ๏ธ|๐คธโโ๏ธ|๐คผโโ๏ธ|๐คผโโ๏ธ|๐คฝโโ๏ธ|๐คฝโโ๏ธ|๐คพโโ๏ธ|๐คพโโ๏ธ|๐คนโโ๏ธ|๐คนโโ๏ธ|๐งโโ๏ธ|๐งโโ๏ธ|๐จโ๐ฆ|๐จโ๐ง|๐ฉโ๐ฆ|๐ฉโ๐ง|๐โ๐ฆบ|๐ปโโ๏ธ|๐ดโโ ๏ธ|๐โโฌ|๐ฆ๐จ|๐ฆ๐ฉ|๐ฆ๐ช|๐ฆ๐ซ|๐ฆ๐ฌ|๐ฆ๐ฎ|๐ฆ๐ฑ|๐ฆ๐ฒ|๐ฆ๐ด|๐ฆ๐ถ|๐ฆ๐ท|๐ฆ๐ธ|๐ฆ๐น|๐ฆ๐บ|๐ฆ๐ผ|๐ฆ๐ฝ|๐ฆ๐ฟ|๐ง๐ฆ|๐ง๐ง|๐ง๐ฉ|๐ง๐ช|๐ง๐ซ|๐ง๐ฌ|๐ง๐ญ|๐ง๐ฎ|๐ง๐ฏ|๐ง๐ฑ|๐ง๐ฒ|๐ง๐ณ|๐ง๐ด|๐ง๐ถ|๐ง๐ท|๐ง๐ธ|๐ง๐น|๐ง๐ป|๐ง๐ผ|๐ง๐พ|๐ง๐ฟ|๐จ๐ฆ|๐จ๐จ|๐จ๐ฉ|๐จ๐ซ|๐จ๐ฌ|๐จ๐ญ|๐จ๐ฎ|๐จ๐ฐ|๐จ๐ฑ|๐จ๐ฒ|๐จ๐ณ|๐จ๐ด|๐จ๐ต|๐จ๐ท|๐จ๐บ|๐จ๐ป|๐จ๐ผ|๐จ๐ฝ|๐จ๐พ|๐จ๐ฟ|๐ฉ๐ช|๐ฉ๐ฌ|๐ฉ๐ฏ|๐ฉ๐ฐ|๐ฉ๐ฒ|๐ฉ๐ด|๐ฉ๐ฟ|๐ช๐ฆ|๐ช๐จ|๐ช๐ช|๐ช๐ฌ|๐ช๐ญ|๐ช๐ท|๐ช๐ธ|๐ช๐น|๐ช๐บ|๐ซ๐ฎ|๐ซ๐ฏ|๐ซ๐ฐ|๐ซ๐ฒ|๐ซ๐ด|๐ซ๐ท|๐ฌ๐ฆ|๐ฌ๐ง|๐ฌ๐ฉ|๐ฌ๐ช|๐ฌ๐ซ|๐ฌ๐ฌ|๐ฌ๐ญ|๐ฌ๐ฎ|๐ฌ๐ฑ|๐ฌ๐ฒ|๐ฌ๐ณ|๐ฌ๐ต|๐ฌ๐ถ|๐ฌ๐ท|๐ฌ๐ธ|๐ฌ๐น|๐ฌ๐บ|๐ฌ๐ผ|๐ฌ๐พ|๐ญ๐ฐ|๐ญ๐ฒ|๐ญ๐ณ|๐ญ๐ท|๐ญ๐น|๐ญ๐บ|๐ฎ๐จ|๐ฎ๐ฉ|๐ฎ๐ช|๐ฎ๐ฑ|๐ฎ๐ฒ|๐ฎ๐ณ|๐ฎ๐ด|๐ฎ๐ถ|๐ฎ๐ท|๐ฎ๐ธ|๐ฎ๐น|๐ฏ๐ช|๐ฏ๐ฒ|๐ฏ๐ด|๐ฏ๐ต|๐ฐ๐ช|๐ฐ๐ฌ|๐ฐ๐ญ|๐ฐ๐ฎ|๐ฐ๐ฒ|๐ฐ๐ณ|๐ฐ๐ต|๐ฐ๐ท|๐ฐ๐ผ|๐ฐ๐พ|๐ฐ๐ฟ|๐ฑ๐ฆ|๐ฑ๐ง|๐ฑ๐จ|๐ฑ๐ฎ|๐ฑ๐ฐ|๐ฑ๐ท|๐ฑ๐ธ|๐ฑ๐น|๐ฑ๐บ|๐ฑ๐ป|๐ฑ๐พ|๐ฒ๐ฆ|๐ฒ๐จ|๐ฒ๐ฉ|๐ฒ๐ช|๐ฒ๐ซ|๐ฒ๐ฌ|๐ฒ๐ญ|๐ฒ๐ฐ|๐ฒ๐ฑ|๐ฒ๐ฒ|๐ฒ๐ณ|๐ฒ๐ด|๐ฒ๐ต|๐ฒ๐ถ|๐ฒ๐ท|๐ฒ๐ธ|๐ฒ๐น|๐ฒ๐บ|๐ฒ๐ป|๐ฒ๐ผ|๐ฒ๐ฝ|๐ฒ๐พ|๐ฒ๐ฟ|๐ณ๐ฆ|๐ณ๐จ|๐ณ๐ช|๐ณ๐ซ|๐ณ๐ฌ|๐ณ๐ฎ|๐ณ๐ฑ|๐ณ๐ด|๐ณ๐ต|๐ณ๐ท|๐ณ๐บ|๐ณ๐ฟ|๐ด๐ฒ|๐ต๐ฆ|๐ต๐ช|๐ต๐ซ|๐ต๐ฌ|๐ต๐ญ|๐ต๐ฐ|๐ต๐ฑ|๐ต๐ฒ|๐ต๐ณ|๐ต๐ท|๐ต๐ธ|๐ต๐น|๐ต๐ผ|๐ต๐พ|๐ถ๐ฆ|๐ท๐ช|๐ท๐ด|๐ท๐ธ|๐ท๐บ|๐ท๐ผ|๐ธ๐ฆ|๐ธ๐ง|๐ธ๐จ|๐ธ๐ฉ|๐ธ๐ช|๐ธ๐ฌ|๐ธ๐ญ|๐ธ๐ฎ|๐ธ๐ฏ|๐ธ๐ฐ|๐ธ๐ฑ|๐ธ๐ฒ|๐ธ๐ณ|๐ธ๐ด|๐ธ๐ท|๐ธ๐ธ|๐ธ๐น|๐ธ๐ป|๐ธ๐ฝ|๐ธ๐พ|๐ธ๐ฟ|๐น๐ฆ|๐น๐จ|๐น๐ฉ|๐น๐ซ|๐น๐ฌ|๐น๐ญ|๐น๐ฏ|๐น๐ฐ|๐น๐ฑ|๐น๐ฒ|๐น๐ณ|๐น๐ด|๐น๐ท|๐น๐น|๐น๐ป|๐น๐ผ|๐น๐ฟ|๐บ๐ฆ|๐บ๐ฌ|๐บ๐ฒ|๐บ๐ณ|๐บ๐ธ|๐บ๐พ|๐บ๐ฟ|๐ป๐ฆ|๐ป๐จ|๐ป๐ช|๐ป๐ฌ|๐ป๐ฎ|๐ป๐ณ|๐ป๐บ|๐ผ๐ซ|๐ผ๐ธ|๐ฝ๐ฐ|๐พ๐ช|๐พ๐น|๐ฟ๐ฆ|๐ฟ๐ฒ|๐ฟ๐ผ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐ค๐ป|๐ค๐ผ|๐ค๐ฝ|๐ค๐พ|๐ค๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐คฒ๐ป|๐คฒ๐ผ|๐คฒ๐ฝ|๐คฒ๐พ|๐คฒ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐
๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
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๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐คฆ๐ป|๐คฆ๐ผ|๐คฆ๐ฝ|๐คฆ๐พ|๐คฆ๐ฟ|๐คท๐ป|๐คท๐ผ|๐คท๐ฝ|๐คท๐พ|๐คท๐ฟ|๐ฎ๐ป|๐ฎ๐ผ|๐ฎ๐ฝ|๐ฎ๐พ|๐ฎ๐ฟ|๐ต๐ป|๐ต๐ผ|๐ต๐ฝ|๐ต๐พ|๐ต๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ฅท๐ป|๐ฅท๐ผ|๐ฅท๐ฝ|๐ฅท๐พ|๐ฅท๐ฟ|๐ท๐ป|๐ท๐ผ|๐ท๐ฝ|๐ท๐พ|๐ท๐ฟ|๐คด๐ป|๐คด๐ผ|๐คด๐ฝ|๐คด๐พ|๐คด๐ฟ|๐ธ๐ป|๐ธ๐ผ|๐ธ๐ฝ|๐ธ๐พ|๐ธ๐ฟ|๐ณ๐ป|๐ณ๐ผ|๐ณ๐ฝ|๐ณ๐พ|๐ณ๐ฟ|๐ฒ๐ป|๐ฒ๐ผ|๐ฒ๐ฝ|๐ฒ๐พ|๐ฒ๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐คต๐ป|๐คต๐ผ|๐คต๐ฝ|๐คต๐พ|๐คต๐ฟ|๐ฐ๐ป|๐ฐ๐ผ|๐ฐ๐ฝ|๐ฐ๐พ|๐ฐ๐ฟ|๐คฐ๐ป|๐คฐ๐ผ|๐คฐ๐ฝ|๐คฐ๐พ|๐คฐ๐ฟ|๐คฑ๐ป|๐คฑ๐ผ|๐คฑ๐ฝ|๐คฑ๐พ|๐คฑ๐ฟ|๐ผ๐ป|๐ผ๐ผ|๐ผ๐ฝ|๐ผ๐พ|๐ผ๐ฟ|๐
๐ป|๐
๐ผ|๐
๐ฝ|๐
๐พ|๐
๐ฟ|๐คถ๐ป|๐คถ๐ผ|๐คถ๐ฝ|๐คถ๐พ|๐คถ๐ฟ|๐ฆธ๐ป|๐ฆธ๐ผ|๐ฆธ๐ฝ|๐ฆธ๐พ|๐ฆธ๐ฟ|๐ฆน๐ป|๐ฆน๐ผ|๐ฆน๐ฝ|๐ฆน๐พ|๐ฆน๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ถ๐ป|๐ถ๐ผ|๐ถ๐ฝ|๐ถ๐พ|๐ถ๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐บ๐ป|๐บ๐ผ|๐บ๐ฝ|๐บ๐พ|๐บ๐ฟ|๐ด๐ป|๐ด๐ผ|๐ด๐ฝ|๐ด๐พ|๐ด๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ฃ๐ป|๐ฃ๐ผ|๐ฃ๐ฝ|๐ฃ๐พ|๐ฃ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ด๐ป|๐ด๐ผ|๐ด๐ฝ|๐ด๐พ|๐ด๐ฟ|๐ต๐ป|๐ต๐ผ|๐ต๐ฝ|๐ต๐พ|๐ต๐ฟ|๐คธ๐ป|๐คธ๐ผ|๐คธ๐ฝ|๐คธ๐พ|๐คธ๐ฟ|๐คฝ๐ป|๐คฝ๐ผ|๐คฝ๐ฝ|๐คฝ๐พ|๐คฝ๐ฟ|๐คพ๐ป|๐คพ๐ผ|๐คพ๐ฝ|๐คพ๐พ|๐คพ๐ฟ|๐คน๐ป|๐คน๐ผ|๐คน๐ฝ|๐คน๐พ|๐คน๐ฟ|๐ง๐ป|๐ง๐ผ|๐ง๐ฝ|๐ง๐พ|๐ง๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐ญ๐ป|๐ญ๐ผ|๐ญ๐ฝ|๐ญ๐พ|๐ญ๐ฟ|๐ซ๐ป|๐ซ๐ผ|๐ซ๐ฝ|๐ซ๐พ|๐ซ๐ฟ|๐ฌ๐ป|๐ฌ๐ผ|๐ฌ๐ฝ|๐ฌ๐พ|๐ฌ๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|๐๐ป|๐๐ผ|๐๐ฝ|๐๐พ|๐๐ฟ|#๏ธโฃ|0๏ธโฃ|1๏ธโฃ|2๏ธโฃ|3๏ธโฃ|4๏ธโฃ|5๏ธโฃ|6๏ธโฃ|7๏ธโฃ|8๏ธโฃ|9๏ธโฃ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โ๐ป|โ๐ผ|โ๐ฝ|โ๐พ|โ๐ฟ|โน๐ป|โน๐ผ|โน๐ฝ|โน๐พ|โน๐ฟ|๐|๐|๐|๐|๐|๐
|๐คฃ|๐|๐|๐|๐|๐|๐|๐ฅฐ|๐|๐คฉ|๐|๐|๐|๐|๐ฅฒ|๐|๐|๐|๐คช|๐|๐ค|๐ค|๐คญ|๐คซ|๐ค|๐ค|๐คจ|๐|๐|๐ถ|๐|๐|๐|๐ฌ|๐คฅ|๐|๐|๐ช|๐คค|๐ด|๐ท|๐ค|๐ค|๐คข|๐คฎ|๐คง|๐ฅต|๐ฅถ|๐ฅด|๐ต|๐คฏ|๐ค |๐ฅณ|๐ฅธ|๐|๐ค|๐ง|๐|๐|๐|๐ฎ|๐ฏ|๐ฒ|๐ณ|๐ฅบ|๐ฆ|๐ง|๐จ|๐ฐ|๐ฅ|๐ข|๐ญ|๐ฑ|๐|๐ฃ|๐|๐|๐ฉ|๐ซ|๐ฅฑ|๐ค|๐ก|๐ |๐คฌ|๐|๐ฟ|๐|๐ฉ|๐คก|๐น|๐บ|๐ป|๐ฝ|๐พ|๐ค|๐บ|๐ธ|๐น|๐ป|๐ผ|๐ฝ|๐|๐ฟ|๐พ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐งก|๐|๐|๐|๐|๐ค|๐ค|๐ค|๐ฏ|๐ข|๐ฅ|๐ซ|๐ฆ|๐จ|๐ณ|๐ฃ|๐ฌ|๐จ|๐ฏ|๐ญ|๐ค|๐|๐ค|๐|๐|๐|๐ค|๐ค|๐ค|๐ค|๐ค|๐ค|๐|๐|๐|๐|๐|๐|๐|๐|๐ค|๐ค|๐|๐|๐|๐คฒ|๐ค|๐|๐
|๐คณ|๐ช|๐ฆพ|๐ฆฟ|๐ฆต|๐ฆถ|๐|๐ฆป|๐|๐ง |๐ซ|๐ซ|๐ฆท|๐ฆด|๐|๐|๐
|๐|๐ถ|๐ง|๐ฆ|๐ง|๐ง|๐ฑ|๐จ|๐ง|๐ฉ|๐ง|๐ด|๐ต|๐|๐|๐
|๐|๐|๐|๐ง|๐|๐คฆ|๐คท|๐ฎ|๐ต|๐|๐ฅท|๐ท|๐คด|๐ธ|๐ณ|๐ฒ|๐ง|๐คต|๐ฐ|๐คฐ|๐คฑ|๐ผ|๐
|๐คถ|๐ฆธ|๐ฆน|๐ง|๐ง|๐ง|๐ง|๐ง|๐ง|๐ง|๐|๐|๐ถ|๐ง|๐ง|๐|๐|๐บ|๐ด|๐ฏ|๐ง|๐ง|๐คบ|๐|๐|๐|๐|๐ฃ|๐|๐|๐ด|๐ต|๐คธ|๐คผ|๐คฝ|๐คพ|๐คน|๐ง|๐|๐|๐ญ|๐ซ|๐ฌ|๐|๐|๐ช|๐ฃ|๐ค|๐ฅ|๐ซ|๐ฃ|๐ฆฐ|๐ฆฑ|๐ฆณ|๐ฆฒ|๐ต|๐|๐ฆ|๐ฆง|๐ถ|๐|๐ฆฎ|๐ฉ|๐บ|๐ฆ|๐ฆ|๐ฑ|๐|๐ฆ|๐ฏ|๐
|๐|๐ด|๐|๐ฆ|๐ฆ|๐ฆ|๐ฆฌ|๐ฎ|๐|๐|๐|๐ท|๐|๐|๐ฝ|๐|๐|๐|๐ช|๐ซ|๐ฆ|๐ฆ|๐|๐ฆฃ|๐ฆ|๐ฆ|๐ญ|๐|๐|๐น|๐ฐ|๐|๐ฟ|๐ฆซ|๐ฆ|๐ฆ|๐ป|๐จ|๐ผ|๐ฆฅ|๐ฆฆ|๐ฆจ|๐ฆ|๐ฆก|๐พ|๐ฆ|๐|๐|๐ฃ|๐ค|๐ฅ|๐ฆ|๐ง|๐|๐ฆ
|๐ฆ|๐ฆข|๐ฆ|๐ฆค|๐ชถ|๐ฆฉ|๐ฆ|๐ฆ|๐ธ|๐|๐ข|๐ฆ|๐|๐ฒ|๐|๐ฆ|๐ฆ|๐ณ|๐|๐ฌ|๐ฆญ|๐|๐ |๐ก|๐ฆ|๐|๐|๐|๐ฆ|๐|๐|๐|๐ชฒ|๐|๐ฆ|๐ชณ|๐ท|๐ธ|๐ฆ|๐ฆ|๐ชฐ|๐ชฑ|๐ฆ |๐|๐ธ|๐ฎ|๐ต|๐น|๐ฅ|๐บ|๐ป|๐ผ|๐ท|๐ฑ|๐ชด|๐ฒ|๐ณ|๐ด|๐ต|๐พ|๐ฟ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฅญ|๐|๐|๐|๐|๐|๐|๐ซ|๐ฅ|๐
|๐ซ|๐ฅฅ|๐ฅ|๐|๐ฅ|๐ฅ|๐ฝ|๐ถ|๐ซ|๐ฅ|๐ฅฌ|๐ฅฆ|๐ง|๐ง
|๐|๐ฅ|๐ฐ|๐|๐ฅ|๐ฅ|๐ซ|๐ฅจ|๐ฅฏ|๐ฅ|๐ง|๐ง|๐|๐|๐ฅฉ|๐ฅ|๐|๐|๐|๐ญ|๐ฅช|๐ฎ|๐ฏ|๐ซ|๐ฅ|๐ง|๐ฅ|๐ณ|๐ฅ|๐ฒ|๐ซ|๐ฅฃ|๐ฅ|๐ฟ|๐ง|๐ง|๐ฅซ|๐ฑ|๐|๐|๐|๐|๐|๐|๐ |๐ข|๐ฃ|๐ค|๐ฅ|๐ฅฎ|๐ก|๐ฅ|๐ฅ |๐ฅก|๐ฆ|๐ฆ|๐ฆ|๐ฆ|๐ฆช|๐ฆ|๐ง|๐จ|๐ฉ|๐ช|๐|๐ฐ|๐ง|๐ฅง|๐ซ|๐ฌ|๐ญ|๐ฎ|๐ฏ|๐ผ|๐ฅ|๐ซ|๐ต|๐ถ|๐พ|๐ท|๐ธ|๐น|๐บ|๐ป|๐ฅ|๐ฅ|๐ฅค|๐ง|๐ง|๐ง|๐ง|๐ฅข|๐ฝ|๐ด|๐ฅ|๐ช|๐บ|๐|๐|๐|๐|๐บ|๐พ|๐งญ|๐|๐|๐ป|๐|๐|๐|๐|๐|๐|๐|๐|๐งฑ|๐ชจ|๐ชต|๐|๐|๐|๐ |๐ก|๐ข|๐ฃ|๐ค|๐ฅ|๐ฆ|๐จ|๐ฉ|๐ช|๐ซ|๐ฌ|๐ญ|๐ฏ|๐ฐ|๐|๐ผ|๐ฝ|๐|๐|๐|๐|๐|๐|๐|๐|๐
|๐|๐|๐|๐ |๐ก|๐ข|๐|๐ช|๐|๐|๐|๐
|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ป|๐|๐|๐|๐|๐|๐ต|๐ฆฝ|๐ฆผ|๐บ|๐ฒ|๐ด|๐น|๐ผ|๐|๐ฃ|๐ค|๐ข|๐จ|๐ฅ|๐ฆ|๐|๐ง|๐ถ|๐ค|๐ณ|๐ฅ|๐ข|๐ฉ|๐ซ|๐ฌ|๐ช|๐บ|๐|๐|๐ |๐ก|๐ฐ|๐|๐ธ|๐|๐งณ|๐ฐ|๐|๐ง|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ |๐|๐ก|๐|๐ข|๐|๐ฃ|๐|๐ค|๐|๐ฅ|๐|๐ฆ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ก|๐|๐|๐ช|๐|๐ |๐|๐ค|๐ฅ|๐ฆ|๐ง|๐จ|๐ฉ|๐ช|๐ซ|๐ฌ|๐|๐|๐|๐ฅ|๐ง|๐|๐|๐|๐|๐|๐งจ|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐งง|๐|๐|๐|๐|๐ซ|๐|๐|๐
|๐ฅ|๐ฅ|๐ฅ|๐ฅ|๐|๐|๐|๐|๐พ|๐ฅ|๐ณ|๐|๐|๐|๐ฅ|๐|๐ธ|๐ฅ|๐ฅ|๐ฅ
|๐ฃ|๐คฟ|๐ฝ|๐ฟ|๐ท|๐ฅ|๐ฏ|๐ช|๐ช|๐ฑ|๐ฎ|๐ช|๐งฟ|๐ฎ|๐น|๐ฐ|๐ฒ|๐งฉ|๐งธ|๐ช
|๐ช|๐|๐|๐ด|๐ญ|๐ผ|๐จ|๐งต|๐ชก|๐งถ|๐ชข|๐|๐ถ|๐ฅฝ|๐ฅผ|๐ฆบ|๐|๐|๐|๐งฃ|๐งค|๐งฅ|๐งฆ|๐|๐|๐ฅป|๐ฉฑ|๐ฉฒ|๐ฉณ|๐|๐|๐|๐|๐|๐|๐|๐ฉด|๐|๐|๐ฅพ|๐ฅฟ|๐ |๐ก|๐ฉฐ|๐ข|๐|๐|๐ฉ|๐|๐งข|๐ช|๐ฟ|๐|๐|๐|๐|๐|๐|๐|๐ข|๐ฃ|๐ฏ|๐|๐|๐ผ|๐ต|๐ถ|๐|๐|๐|๐ค|๐ง|๐ป|๐ท|๐ช|๐ธ|๐น|๐บ|๐ป|๐ช|๐ฅ|๐ช|๐ฑ|๐ฒ|๐|๐|๐ |๐|๐|๐ป|๐ฅ|๐จ|๐ฑ|๐ฒ|๐ฝ|๐พ|๐ฟ|๐|๐งฎ|๐ฅ|๐|๐ฝ|๐ฌ|๐บ|๐ท|๐ธ|๐น|๐ผ|๐|๐|๐ฏ|๐ก|๐ฆ|๐ฎ|๐ช|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฐ|๐|๐|๐|๐ท|๐ฐ|๐ช|๐ด|๐ต|๐ถ|๐ท|๐ธ|๐ณ|๐งพ|๐น|๐ง|๐จ|๐ฉ|๐ค|๐ฅ|๐ฆ|๐ซ|๐ช|๐ฌ|๐ญ|๐ฎ|๐ณ|๐|๐|๐|๐|๐|๐ผ|๐|๐|๐|๐
|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐จ|๐ช|๐ |๐ก|๐ซ|๐ช|๐น|๐ก|๐ช|๐ง|๐ช|๐ฉ|๐|๐ฆฏ|๐|๐ช|๐งฐ|๐งฒ|๐ช|๐งช|๐งซ|๐งฌ|๐ฌ|๐ญ|๐ก|๐|๐ฉธ|๐|๐ฉน|๐ฉบ|๐ช|๐|๐ช|๐ช|๐|๐|๐ช|๐ฝ|๐ช |๐ฟ|๐|๐ชค|๐ช|๐งด|๐งท|๐งน|๐งบ|๐งป|๐ชฃ|๐งผ|๐ชฅ|๐งฝ|๐งฏ|๐|๐ฌ|๐ชฆ|๐ฟ|๐ชง|๐ง|๐ฎ|๐ฐ|๐น|๐บ|๐ป|๐ผ|๐พ|๐|๐|๐|๐
|๐ธ|๐ซ|๐ณ|๐ญ|๐ฏ|๐ฑ|๐ท|๐ต|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐|๐ฏ|๐|๐|๐|๐ผ|๐ฝ|๐ฆ|๐
|๐|๐ถ|๐ณ|๐ด|๐ฑ|๐ฒ|๐ฑ|๐|๐ฐ|๐|๐ |๐ก|๐ข|๐ฃ|๐ค|๐
ฐ|๐|๐
ฑ|๐|๐|๐|๐|๐|๐|๐
พ|๐|๐
ฟ|๐|๐|๐|๐|๐|๐ท|๐ถ|๐ฏ|๐|๐น|๐|๐ฒ|๐|๐ธ|๐ด|๐ณ|๐บ|๐ต|๐ด|๐ |๐ก|๐ข|๐ต|๐ฃ|๐ค|๐ฅ|๐ง|๐จ|๐ฉ|๐ฆ|๐ช|๐ซ|๐ถ|๐ท|๐ธ|๐น|๐บ|๐ป|๐ |๐|๐ณ|๐ฒ|๐|๐ฉ|๐|๐ด|๐ณ|๐ป|๐ผ|๐ฝ|๐พ|๐ฟ|โบ|โน|โ |โฃ|โค|โ|โ|โ|โ|โ|โท|โน|โ|โ|โฐ|โช|โฉ|โฒ|โบ|โจ|โฝ|โ|โต|โด|โ|โ|โณ|โ|โฐ|โฑ|โฒ|โ|โญ|โ|โ
|โ|โ|โ|โฑ|โก|โ|โ|โ|โ|โจ|โฝ|โพ|โณ|โธ|โ |โฅ|โฆ|โฃ|โ|โ|โ|โจ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โฐ|โฑ|โฟ|โ |โ|โข|โฃ|โฌ|โ|โก|โ|โฌ|โ|โฌ
|โ|โ|โ|โฉ|โช|โคด|โคต|โ|โก|โธ|โฏ|โ|โฆ|โช|โฎ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โ|โถ|โฉ|โญ|โฏ|โ|โช|โฎ|โซ|โฌ|โธ|โน|โบ|โ|โ|โ|โง|โ|โ|โ|โ|โพ|โผ|โ|โ|โ|โ|โ|ใฐ|โ|โป|โ|โญ|โ
|โ|โ|โ|โ|โฐ|โฟ|ใฝ|โณ|โด|โ|ยฉ|ยฎ|โข|โน|โ|ใ|ใ|โซ|โช|โฌ|โฌ|โผ|โป|โพ|โฝ|โช|โซ)`
/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g");
/*count of emojis*/
let emoCount = [..."๐ถ๐ป๐ฆ๐ป๐ง๐ป๐จ๐ป๐ฉ๐ป๐ฑ๐ปโโ๏ธ๐ฑ๐ป๐ด๐ป๐ต๐ป๐ฒ๐ป๐ณ๐ปโโ๏ธ๐ณ๐ป๐ฎ๐ปโโ๏ธ๐ฎ๐ป๐ท๐ปโโ๏ธ๐ท๐ป๐๐ปโโ๏ธ๐๐ป๐ต๐ปโโ๏ธ๐ฉ๐ปโโ๏ธ๐จ๐ปโโ๏ธ๐ฉ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ".matchAll(emoRegex)].length
console.log(emoCount) //37
/*modifying the pattern to count other characters too*/
let generalCounter = new RegExp(emojiPattern+"|.", "g") //emoji or regular character
let allCount = [..."$%^ other stuff equalling 28๐ถ๐ฆ๐ป๐ง๐ป๐จ๐ป๐ฉ๐ป๐ฑ๐ปโโ๏ธ๐ฑ๐ป๐ด๐ป๐ต๐ป๐ฒ๐ป๐ณ๐ปโโ๏ธ๐ณ๐ป๐ฎ๐ปโโ๏ธ๐ฎ๐ป๐ท๐ปโโ๏ธ๐ท๐ป๐๐ปโโ๏ธ๐๐ป๐ต๐ปโโ๏ธ๐ฉ๐ปโโ๏ธ๐จ๐ปโโ๏ธ๐ฉ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ๐จ๐ปโ๐พ".matchAll(generalCounter)].length
console.log(allCount) //28+37 = 65
As you can see from the below example, this is to do with unicode encoding,
There's some great resources such as the one I took this example from.
https://blog.jonnew.com/posts/poo-dot-length-equals-two
console.log("๐ฉโโค๏ธโ๐โ๐ฉ".length === 11);
For anyone interested, I had a similar problem where I wanted to count the length of an emoji at the end of a string.
This is the solution I came up with:
var emoji = new RegExp('(\\p{Extended_Pictographic})((\u200D\\p{Extended_Pictographic})*)$', 'u');
var testStrings = ['๐จโ๐ฉโ๐ง', '๐', '๐ฒ'];
for(var string = 0; string < testStrings.length; string++){
var match = testStrings[string].match(emoji);
var chars = match == null ? 0 : match[0].length;
console.log(testStrings[string] + ': ' + chars);
}
Explanation: \\p{Extended_Pictographic} matches an emoji like ๐, consisting of two characters. Emojis like ๐จโ๐ฉโ๐ง consists of 4 emojis (๐จ, ๐ฉ, ๐ง,๐ฆ) combined by a zero width joiner (\u200D).
The regex matches any emoji at the end ($). If there is a match the length is counted. I am sure it could be adopted for your use-case by matching all emojis in a given string and then subtracting the surplus. It's not a complete implementation for your particular question but I hope this gets you on the right track.
use lodash toArray method
console.log(_.toArray("๐จโ๐ฉโ๐ง").length); // 1
console.log(_.toArray("๐จโ๐ฉโ๐ง๐งโโ๏ธ๐ฉโ๐งโ๐ง").length); // 3
Check here for Codesandbox
I suggest using the runes package to accomplish correct multi-byte string conversions cause else you will get more issues if using reducers and more to reverse strings for example.
Take a look at this great small package: runes
I am trying to write a function to calculate how likely two strings are to mean the same thing. In order to do this I am converting to lower case and removing special characters from the strings before I compare them. Currently I am removing the strings '.com' and 'the' using String.replace(substring, '') and special characters using String.replace(regex, '')
str = str.toLowerCase()
.replace('.com', '')
.replace('the', '')
.replace(/[&\/\\#,+()$~%.'":*?<>{}]/g, '');
Is there a better regex that I can use to remove the common patterns like '.com' and 'the' as well as the special characters? Or some other way to make this more efficient?
As my dataset grows I may find other common meaningless patterns that need to be removed before trying to match strings and would like to avoid the performance hit of chaining more replace functions.
Examples:
Fish & Chips? => fish chips
stackoverflow.com => stackoverflow
The Lord of the Rings => lord of rings
You can connect the replace calls to a single one with a rexexp like this:
str = str.toLowerCase().replace(/\.com|the|[&\/\\#,+()$~%.'":*?<>{}]/g, '');
The different strings to remove are inside parentheses () and separated by pipes |
This makes it easy enough to add more string to the regexp.
If you are storing the words to remove in an array, you can generate the regex using the RegExp constructor, e.g.:
var words = ["\\.com", "the"];
var rex = new RegExp(words.join("|") + "|[&\\/\\\\#,+()$~%.'\":*?<>{}]", "g");
Then reuse rex for each string:
str = str.toLowerCase().replace(rex, "");
Note the additional escaping required because instead of a regular expression literal, we're using a string, so the backslashes (in the words array and in the final bit) need to be escaped, as does the " (because I used " for the string quotes).
The problem with this question is that im sure you have a very concrete idea in your mind of what you want to do, but the solution you have arrived at (removing un-informative letters before making a is-identical comparison) may not be the best for the comparison you want to do.
I think perhaps a better idea would be to use a different method comparison and a different datastructure than a string. A very simple example would be to condense your strings to sets with set('string') and then compare set similarity/difference. Another method might be to create a Directed Acyclic Graph, or sub-string Trei. The main point is that it's probably ok to reduce the information from the original string and store/compare that - however don't underestimate the value of storing the original string, as it will help you down the road if you want to change the way you compare.
Finally, if your strings are really really really long, you might want to use a perceptual hash - which is like an MD5 hash except similar strings have similar hashes. However, you will most likely have to roll your own for short strings, and define what you think is important data, and what is superfluous.
I've just needed to compare to strings in JavaScript, and the comparision of specific strings failed sometimes.
One value was obtained with jQuery via the text() method (from some auto-generated HTML):
var value1 = $('#somelement').text();
The other value is hardcoded in a JavaScript file (from me).
After some testing I found that these strings have different encodings, which became clear when I logged them with the escape() function.
Firebug showed me something like this:
console.log(escape(value1));
"blabla%A0%28blub%29"
console.log(escape(value2));
"blabla%20%28blub%29"
So at the end it's the whitespace with different encodings which made my comparison fails.
So my question is: how to handle this correctly? Can I just replace the whitespace to be equal? But I guess there are other control characters - like tab, return and so on - which could mess up my comparison?
So at the end it's the whitespace with different encodings which made my comparison fails.
No, it is not a different encoding. It is just a different whitespace - a non-breaking space.
Can I just replace the white space to be equal? But I guess there are other control characters - like tab, return and so on - which could mess up my comparison?
You can replace all of them. You might want to try something like
value1.replace(/\s+/g, " ").replace(/^\s*|\s$/g, "") == value2
which joins multiple whitespaces (of all kinds, including returns) to a single space and also trims the string before the comparison.
I am not really interested in security or anything of that nature, but I need some function(s) that allow me to "compress"/"decompress" a string. I have tried Base64, but that has a big issue with the size of the string, it makes it longer. I also know about this Huffman stuff, but that doesn't work either because it too makes it longer (less in terms of memory, it is an integer).
In other words, I want some arbitrary string 'djshdjkash' to be encoded to some other string 'dhaldhnctu'. Be able to go from one to another, and have the new string's length be equal to or less than the original.
Is this possible with Javascript, has it already been done?
Needed to clarify, as I said security is not the objective, just to disguise the string and keeps its length (or shorten it). Base64 is the best example, but it makes strings longer. ROT13 is neat, but doesn't cover all ASCII characters, only letters.
You need compression, not encoding. Encoding generally adds bits. Google "String Compression Algorithms."
Since ROT13 is out because it only affects alphas, why not just implement something across a larger character set. Set up a from array of characters containing your entire printable character set and a to array containing the same characters in a different order.
Then for every character in your string, if it's in the from array, replace it with the equivalent position in the to array.
This yields no compression at all but will satisfy all your requirements (shorter or same length, disguised string).
In pseudo-code, something like:
chfrom = "ABCDEF..."
chto = "1$#zX^..."
def encode(s1):
s2 = ""
foreach ch in s1:
idx = chfrom.find(ch)
if idx == -1:
s2 += ch
else:
s2 += chto[idx]
return s2
def decode(s1):
# same as encode but swap chfrom and chto.
ROT13?
http://en.wikipedia.org/wiki/ROT13
I'm not sure what exactly you want to compress. If it is the length of the string (as seen by String.length(), you could compress two ASCII characters into a Unicode character. So a string like hello, world (12 characters) might result in \u6865\u6c6c\u6f2c\u206f\u6f72\u6c64 (6 characters). You have to be very careful though that you don't generate invalid characters like \uFFFF and that you can always go back from the compressed string to the uncompressed one.
On the other hand, if you want to reduce the length of the string literal, this way is completely wrong. So please clarify under what circumstances you want to compress the strings.
You can use a simple substitution cipher. Here's an example in JavaScript.
Note that there are tools out there to break substitution ciphers. Make sure security isn't an issue here before going down this path.