I need a regular expression to allow all alphabet characters plus Greek/German alphabet in a string but replace those symbols ?,&,^,". with *
I skipped the list with characters to escape to made the question simple.
I really want to see how to construct this and afterwards include alphabet sets using ASCII codes.
if you have a finite and short set of elements to replace you could just use a class e.g.
string.replace(/[?\^&]/g, '*');
and add as many symbols as you want to reject. you could also add ranges of unicode symbols you want to replace (e.g. \u017F-\036F\u0400-\uFFFF )
otherwise use a a class to specify what symbols don't need to be replaced, like a-z, accented/diacritic letters and greek symbols
string.replace(/[^a-z\00C0-\017E\u0370-\03FF]/gi, '*');
You have to use the XRegexp plugin, along with the Unicode add-on.
Once you have that, you can use modern regexes like /[\p{L}\p{Nl}]/, which necessarily also includes those \p{Greek} code points which are letters or letter-numbers. But you could also match /[\p{Latin}\p{Greek}]/ if you wanted.
Javascript’s own regexes are terrible. Use XRegexp.
So something like: /^[^?&\^"]*$/ (that means the string is composed only of characters outside the five you listed)...
But if you want to have the greek characters and the unicode characters (what are unicode characters? àèéìòù? Japanese?) perhaps you'll have to use http://xregexp.com/ It is a regex library for javascript that includes character classes for the various unicode character classes (I know I'm repeating myself) plus other "commands" for unicode handling.
Related
To detect if the string is composed of ASCII characters, I am using a regex that looks as follows:
"string".match(/^[\x00-\x7F]*$/gm)
This works fine in detecting the ASCII characters. But for this leaves the characters that are similar in meaning to ascii codes. For example a double quote that falls out of ASCII set and is included in unicode set. For example:
"see the difference in double quotes“
With the above regex, this string will fail the detection test because of “. How could I extend the above regex to include characters such as these that are very similar to meaning in ASCII set. For example, , [comma], "[double quote], etc.
Regex doesn't understand the meaning of anything, it only follows its rules to match the sequence of characters.
If you want to match a comma, you need to put a comma in your character set. If you are looking for "similar" characters, you need to identify each and every one of them and put them inside the character set.
[,"]
will match "comma" and "double quote".
I have a field in my application where users can enter a hashtag.
I want to validate their entry and make sure they enter what would be a proper HashTag.
It can be in any language and it should NOT precede with the # sign.
I am writing in JavaScript.
So the following are GOOD examples:
Abcde45454_fgfgfg (good because: only letters, numbers and _)
2014_is-the-year (good because: only letters, numbers, _ and -)
בר_רפאלי (good because: only letters and _)
арбуз (good because: only letters)
And the following are BAD examples:
Dan Brown (Bad because has a space)
OMG!!!!! (Bad because has !)
בר רפ#לי (Bad because has # and a space)
We had a regex that matched only a-zA-Z0-9, we needed to add language support so we changed it to ignore white spaces and forgot to ignore special characters, so here I am.
Some other StackOverflow examples I saw but didn't work for me:
Other languges don't work
Again, English only
[edit]
Added explanation why bad is bad and good is good
I don't want a preceding # character, but if I would to add a # in the beginning, it should be a valid hashtag
Basically I don't want to allow any special characters like !##$%^&*()=+./,[{]};:'"?><
If your disallowed characters list is thorough (!##$%^&*()=+./,[{]};:'"?><), then the regex is:
^#?[^\s!##$%^&*()=+./,\[{\]};:'"?><]+$
Demo
This allows an optional leading # sign: #?. It disallows the special characters using a negative character class. I just added \s to the list (spaces), and also I escaped [ and ].
Unfortunately, you can't use constructs like \p{P} (Unicode punctuation) in JavaScript's regexes, so you basically have to blacklist characters or take a different approach if the regex solution isn't good enough for your needs.
I don't understand why this question does not get more votes. Hashtag detection for multiple languages is a problem. The only working option I could find is posted by Lucas above (all other ones do not work so well).
It needs a modification though:
#[^\s!##$%^&*()=+.\/,\[{\]};:'"?><]+
DEMO
this detects all the hashtags, not only in the beginning of the string, fixes an unescaped character, and removes the unnecessary $ in the end.
First if we exclude all symbol it will not a handy solution. Because symbol depends on keyboard layout and there are hundreds of math symbols and so on. So use this..
[\p{sc=Bengali}|\p{L}_\p{N}]+
1. If you think if language need extra care include like \p{sc=Bengali}|\p{sc=Spanish} etc. Suppose bangla has surrogate alphabet like া, ে ৌ etc so codepoint need to recognize Bangla separately first by \p{sc=Bengali}
2. Than use \p{L} that matches anything that is a Unicode letter a-z and letters like é,ü,ğ,i,ç too or normal any alphabet without complex...matches a single code point in the category "letter"
3. _ underscore allowed
4. \p{N} matches any kind of numeric character in any script. (\d matches only a digit (equal to [0-9]) but for allowed Unicode digit \p{N} only option, because its works with any digit codepoint)
I want to delete from string all characters that are not letters.
I know that there is something like \W in regex, but it considers non-English characters as not letters. For example my script deletes all Polish letters (like "ą", "ć", "ó"), but I need them.
How to tell regex to do this?
Code:
var text = text.replace(/\W/g, ' ');
You can either use Steve Levithan's XRegExp library (with Unicode plugins), or you have to define the Unicode character range manually, since JavaScript doesn't support Unicode properties.
[^\u0041-\u005A\u0061-\u007A\u00AA\u00B5\u00BA\u00C0-\u00D6\u00D8-\u00F6\u00F8-\u02C1\u02C6-\u02D1\u02E0-\u02E4\u02EC\u02EE\u0345\u0370-\u0374\u0376\u0377\u037A-\u037D\u0386\u0388-\u038A\u038C\u038E-\u03A1\u03A3-\u03F5\u03F7-\u0481\u048A-\u0527\u0531-\u0556\u0559\u0561-\u0587\u05B0-\u05BD\u05BF\u05C1\u05C2\u05C4\u05C5\u05C7\u05D0-\u05EA\u05F0-\u05F2\u0610-\u061A\u0620-\u0657\u0659-\u065F\u066E-\u06D3\u06D5-\u06DC\u06E1-\u06E8\u06ED-\u06EF\u06FA-\u06FC\u06FF\u0710-\u073F\u074D-\u07B1\u07CA-\u07EA\u07F4\u07F5\u07FA\u0800-\u0817\u081A-\u082C\u0840-\u0858\u08A0\u08A2-\u08AC\u08E4-\u08E9\u08F0-\u08FE\u0900-\u093B\u093D-\u094C\u094E-\u0950\u0955-\u0963\u0971-\u0977\u0979-\u097F\u0981-\u0983\u0985-\u098C\u098F\u0990\u0993-\u09A8\u09AA-\u09B0\u09B2\u09B6-\u09B9\u09BD-\u09C4\u09C7\u09C8\u09CB\u09CC\u09CE\u09D7\u09DC\u09DD\u09DF-\u09E3\u09F0\u09F1\u0A01-\u0A03\u0A05-\u0A0A\u0A0F\u0A10\u0A13-\u0A28\u0A2A-\u0A30\u0A32\u0A33\u0A35\u0A36\u0A38\u0A39\u0A3E-\u0A42\u0A47\u0A48\u0A4B\u0A4C\u0A51\u0A59-\u0A5C\u0A5E\u0A70-\u0A75\u0A81-\u0A83\u0A85-\u0A8D\u0A8F-\u0A91\u0A93-\u0AA8\u0AAA-\u0AB0\u0AB2\u0AB3\u0AB5-\u0AB9\u0ABD-\u0AC5\u0AC7-\u0AC9\u0ACB\u0ACC\u0AD0\u0AE0-\u0AE3\u0B01-\u0B03\u0B05-\u0B0C\u0B0F\u0B10\u0B13-\u0B28\u0B2A-\u0B30\u0B32\u0B33\u0B35-\u0B39\u0B3D-\u0B44\u0B47\u0B48\u0B4B\u0B4C\u0B56\u0B57\u0B5C\u0B5D\u0B5F-\u0B63\u0B71\u0B82\u0B83\u0B85-\u0B8A\u0B8E-\u0B90\u0B92-\u0B95\u0B99\u0B9A\u0B9C\u0B9E\u0B9F\u0BA3\u0BA4\u0BA8-\u0BAA\u0BAE-\u0BB9\u0BBE-\u0BC2\u0BC6-\u0BC8\u0BCA-\u0BCC\u0BD0\u0BD7\u0C01-\u0C03\u0C05-\u0C0C\u0C0E-\u0C10\u0C12-\u0C28\u0C2A-\u0C33\u0C35-\u0C39\u0C3D-\u0C44\u0C46-\u0C48\u0C4A-\u0C4C\u0C55\u0C56\u0C58\u0C59\u0C60-\u0C63\u0C82\u0C83\u0C85-\u0C8C\u0C8E-\u0C90\u0C92-\u0CA8\u0CAA-\u0CB3\u0CB5-\u0CB9\u0CBD-\u0CC4\u0CC6-\u0CC8\u0CCA-\u0CCC\u0CD5\u0CD6\u0CDE\u0CE0-\u0CE3\u0CF1\u0CF2\u0D02\u0D03\u0D05-\u0D0C\u0D0E-\u0D10\u0D12-\u0D3A\u0D3D-\u0D44\u0D46-\u0D48\u0D4A-\u0D4C\u0D4E\u0D57\u0D60-\u0D63\u0D7A-\u0D7F\u0D82\u0D83\u0D85-\u0D96\u0D9A-\u0DB1\u0DB3-\u0DBB\u0DBD\u0DC0-\u0DC6\u0DCF-\u0DD4\u0DD6\u0DD8-\u0DDF\u0DF2\u0DF3\u0E01-\u0E3A\u0E40-\u0E46\u0E4D\u0E81\u0E82\u0E84\u0E87\u0E88\u0E8A\u0E8D\u0E94-\u0E97\u0E99-\u0E9F\u0EA1-\u0EA3\u0EA5\u0EA7\u0EAA\u0EAB\u0EAD-\u0EB9\u0EBB-\u0EBD\u0EC0-\u0EC4\u0EC6\u0ECD\u0EDC-\u0EDF\u0F00\u0F40-\u0F47\u0F49-\u0F6C\u0F71-\u0F81\u0F88-\u0F97\u0F99-\u0FBC\u1000-\u1036\u1038\u103B-\u103F\u1050-\u1062\u1065-\u1068\u106E-\u1086\u108E\u109C\u109D\u10A0-\u10C5\u10C7\u10CD\u10D0-\u10FA\u10FC-\u1248\u124A-\u124D\u1250-\u1256\u1258\u125A-\u125D\u1260-\u1288\u128A-\u128D\u1290-\u12B0\u12B2-\u12B5\u12B8-\u12BE\u12C0\u12C2-\u12C5\u12C8-\u12D6\u12D8-\u1310\u1312-\u1315\u1318-\u135A\u135F\u1380-\u138F\u13A0-\u13F4\u1401-\u166C\u166F-\u167F\u1681-\u169A\u16A0-\u16EA\u16EE-\u16F0\u1700-\u170C\u170E-\u1713\u1720-\u1733\u1740-\u1753\u1760-\u176C\u176E-\u1770\u1772\u1773\u1780-\u17B3\u17B6-\u17C8\u17D7\u17DC\u1820-\u1877\u1880-\u18AA\u18B0-\u18F5\u1900-\u191C\u1920-\u192B\u1930-\u1938\u1950-\u196D\u1970-\u1974\u1980-\u19AB\u19B0-\u19C9\u1A00-\u1A1B\u1A20-\u1A5E\u1A61-\u1A74\u1AA7\u1B00-\u1B33\u1B35-\u1B43\u1B45-\u1B4B\u1B80-\u1BA9\u1BAC-\u1BAF\u1BBA-\u1BE5\u1BE7-\u1BF1\u1C00-\u1C35\u1C4D-\u1C4F\u1C5A-\u1C7D\u1CE9-\u1CEC\u1CEE-\u1CF3\u1CF5\u1CF6\u1D00-\u1DBF\u1E00-\u1F15\u1F18-\u1F1D\u1F20-\u1F45\u1F48-\u1F4D\u1F50-\u1F57\u1F59\u1F5B\u1F5D\u1F5F-\u1F7D\u1F80-\u1FB4\u1FB6-\u1FBC\u1FBE\u1FC2-\u1FC4\u1FC6-\u1FCC\u1FD0-\u1FD3\u1FD6-\u1FDB\u1FE0-\u1FEC\u1FF2-\u1FF4\u1FF6-\u1FFC\u2071\u207F\u2090-\u209C\u2102\u2107\u210A-\u2113\u2115\u2119-\u211D\u2124\u2126\u2128\u212A-\u212D\u212F-\u2139\u213C-\u213F\u2145-\u2149\u214E\u2160-\u2188\u24B6-\u24E9\u2C00-\u2C2E\u2C30-\u2C5E\u2C60-\u2CE4\u2CEB-\u2CEE\u2CF2\u2CF3\u2D00-\u2D25\u2D27\u2D2D\u2D30-\u2D67\u2D6F\u2D80-\u2D96\u2DA0-\u2DA6\u2DA8-\u2DAE\u2DB0-\u2DB6\u2DB8-\u2DBE\u2DC0-\u2DC6\u2DC8-\u2DCE\u2DD0-\u2DD6\u2DD8-\u2DDE\u2DE0-\u2DFF\u2E2F\u3005-\u3007\u3021-\u3029\u3031-\u3035\u3038-\u303C\u3041-\u3096\u309D-\u309F\u30A1-\u30FA\u30FC-\u30FF\u3105-\u312D\u3131-\u318E\u31A0-\u31BA\u31F0-\u31FF\u3400-\u4DB5\u4E00-\u9FCC\uA000-\uA48C\uA4D0-\uA4FD\uA500-\uA60C\uA610-\uA61F\uA62A\uA62B\uA640-\uA66E\uA674-\uA67B\uA67F-\uA697\uA69F-\uA6EF\uA717-\uA71F\uA722-\uA788\uA78B-\uA78E\uA790-\uA793\uA7A0-\uA7AA\uA7F8-\uA801\uA803-\uA805\uA807-\uA80A\uA80C-\uA827\uA840-\uA873\uA880-\uA8C3\uA8F2-\uA8F7\uA8FB\uA90A-\uA92A\uA930-\uA952\uA960-\uA97C\uA980-\uA9B2\uA9B4-\uA9BF\uA9CF\uAA00-\uAA36\uAA40-\uAA4D\uAA60-\uAA76\uAA7A\uAA80-\uAABE\uAAC0\uAAC2\uAADB-\uAADD\uAAE0-\uAAEF\uAAF2-\uAAF5\uAB01-\uAB06\uAB09-\uAB0E\uAB11-\uAB16\uAB20-\uAB26\uAB28-\uAB2E\uABC0-\uABEA\uAC00-\uD7A3\uD7B0-\uD7C6\uD7CB-\uD7FB\uF900-\uFA6D\uFA70-\uFAD9\uFB00-\uFB06\uFB13-\uFB17\uFB1D-\uFB28\uFB2A-\uFB36\uFB38-\uFB3C\uFB3E\uFB40\uFB41\uFB43\uFB44\uFB46-\uFBB1\uFBD3-\uFD3D\uFD50-\uFD8F\uFD92-\uFDC7\uFDF0-\uFDFB\uFE70-\uFE74\uFE76-\uFEFC\uFF21-\uFF3A\uFF41-\uFF5A\uFF66-\uFFBE\uFFC2-\uFFC7\uFFCA-\uFFCF\uFFD2-\uFFD7\uFFDA-\uFFDC]
matches a character that isn't a Unicode letter.
It depends on what engine you are working with. It also depends on how your Unicode characters are encoded — are they encoded as a single character, or as a character+mark combination?
You can try the following: \p{L} to target character+mark combinations, and \P{M}\p{M}*+ for the single character encodings.
So, finally I decided to write my own regex condition, because it seems like it there isn't any fast&simple way to do that in javascript.
I added here all unnecessary characters that came to my mind, could be in typical website and aren't needed to understand single word (I left ' character because in English it is quite important ;) ). If you want you can edit my answer and add your own ones.
[:;.,\?!-()~\/"|®##$%^&*+-]
JS:
text = text.replace(/[:;\.,\?!\-\(\)~\\\/"|®##$%^&*+-]/, "");
I have this Regular Expression pattern, which is quite simple and it validates if the provided string is "alpha" (both uppercase and lowercase):
var pattern = /^[a-zA-Z]+$/gi;
When I trigger pattern.test('Zlatan Omerovic') it returns true, however if I:
pattern.test('Zlatan Omerović');
It returns false and it fails my validation.
In Bosnian language we have these specific characters:
š đ č ć ž
And uppercased:
Š Đ Č Ć Ž
Is it possible to validate these characters (both cases) with JavaScript regular expression?
Sure, you can just add those characters to the list of characters your matching. Also, since you're doing a case insensitive match (the i flag), you don't need the uppercase characters.
var pattern = /^[a-zšđčćž ]+$/gi;
Fiddle here: http://jsfiddle.net/ryanbrill/KB74b/
Here's an alternate pattern, which uses the unicode representation, which might be better (embedding the characters won't work if the file isn't saved with the proper encoding, for instance)
var pattern = /^[a-z\u0161\u0111\u010D\u0107\u017E ]+$/gi;
http://jsfiddle.net/ryanbrill/KB74b/2/
a-zA-Z means exactly that, and in an English-centric way: abcdefghijklmnopqrstuvwxyz. Sadly, with JavaScript's regular expressions, if you want to test other alphabetic characters, you have to specify them specifically. JavaScript doesn't have a locale-sensitive "alpha" definition. To include non-English alphabetic characters, you have to include them on purpose. You can either do that literally (for instance, by including š in the regular expression), or using Unicode escape sequences (such as \u0161). If the additional Bosnian alphabetic characters in question have a contiguous range, you can use the - notation with them as well, but it has to be separate from the a-z, which is defined in English terms.
To include in test result the first (S-based) symbol of your five I did:
var pattern = /^[a-zA-Z\u0160-\u0161]+$/g;
Try to add all the symbols you need this way ;)
I want to validate any string that contains çÇöÖİşŞüÜğĞ chars and starting at least 5 chars.String to validate can contain spaces.RegEx must validate like "asd Çğ ğT i" for example.
Any reply will helpful.
Thanks.
You can use escape sequences of the form
\uXXXX
where each "X" can be any hex digit. Thus:
\u0020
is the same as a plain space character, and
\u0041
is upper-case "A". Thus you can encode the Unicode values for the characters you're interested in and then include them in a regex character class. To make sure the string is at least five characters long, you can use a quantifier in the regex.
You'll end up with something like:
var regex = /^[A-Za-z\u00nn\u00nn\u00nn]{5,}$/;
where those "00nn" things would be the appropriate values. As to exactly what those values are, you should be able to find them on a reference site like this one or maybe this one. For example I think that "Ö" is \u00D6. (Some of your characters are in the Unicode Latin-1 Supplement, while others are in Latin Extended A.)