Develop Reference

Making a div change size with animate, addClass and RemoveClass

This is my first question here, feel free to tell me if I am not specific enough or whatever I do wrong!
I want a jquery method which change all divs with the class "passive" to height 500 px and passive-->active, so there would be another method which changes the height back to 100px. The first half is working, I got the class changed, but the second animation won't happen. All I have in html is one div with the class of passive.
$("document").ready(function(){
$(function() {
$(".passive").click(function(){
$(this).animate({height:'500px'});
$(this).addClass("active");
$(this).removeClass("passive");
});
$(".active").click(function(){
$(this).animate({height:'100px'});
$(this).addClass("passive");
$(this).removeClass("active");
});
});
});`

jQuery.animate() is costly and choppy. You will get a smoother transition by just toggling the class and using CSS to transition
.passive {
height:100px;
transition:height 1s;
}
.active {
height:300px;
}
Array
.from(document.querySelectorAll('.passive'))
.forEach(
e => e.addEventListener(
'click',
evnt => e.classList.toggle('active')
)
)
.container { display:flex; }
.container>div {
flex:1 auto;
}
.passive {
background-color:red;
margin:5px;
height:100px;
width:20px;
transition:height 1s;
}
.active {
height:300px;
}
<div class="container">
<div class="passive" tabindex=1></div>
<div class="passive" tabindex=2></div>
<div class="passive" tabindex=3></div>
</div>

You are trying to interact with a class added after the DOM loaded. By default, click functions will only work with elements that exist on load. You can either use event delegation or add a base class to the element. If you add a base class, you can simplify the click function.
You can do an if/else to check if the element has a certain class using hasClass. Also, you can chain together the $(this) methods inside the if/else blocks.
$("document").ready(function() {
$(function() {
$("baseclassname").click(function() {
if ($(this).hasClass('passive')) {
$(this).animate({ height: '500px' });
$(this).addClass("active");
$(this).removeClass("passive");
// $(this).animate({ height: '500px' }).addClass('active').removeClass('passive');
} else {
$(this).animate({ height: '100px' });
$(this).addClass("passive");
$(this).removeClass("active");
// $(this).animate({ height: '100px' }).addClass('passive').removeClass('active');
}
});
});
});

jQuery show/hide/mouseenter issues

I have four lines of text and I want to display a specific image on mouseenter on the right side of each line.
The problem I'm having right now is that all four images are beeing displayed at the same time.
What am I doing wrong?
http://jsfiddle.net/m97qebjr/10
jQuery:
$(".thumb").hide();
$(".text" ).mouseenter(function() {
$(".thumb").show();
}).mouseleave(function() {
$(".thumb").hide();
});

You don't need jQuery at all: http://jsfiddle.net/m97qebjr/16/
.thumb {
display:none; /* added line */
float:right;
overflow:hidden;
width:100px;
height:100px;
}
.wrap:hover .thumb{ /* added rule */
display:block;
}

$(".thumb") matches all elements with class thumb. Try this instead:
$(".thumb").hide();
$(".text").mouseenter(function () {
$(this).siblings(".thumb").show();
}).mouseleave(function () {
$(this).siblings(".thumb").hide();
});
Updated fiddle: http://jsfiddle.net/m97qebjr/13/

How to slide a div by hovering over another div with jquery?

I have some code here and cannot find out how to make this work because I am still really new to javascript and jquery. I will have a demo below so you can see what I have going on. In the demo there is div positioned left:-60px so it is hidden, this div also has class of 'show' which positions the div to left:0 There is also the long black box which is another div. I want to make it so when you hover over the long black box, it will activate the 'show' property of the other div. Here is my code:
var $showSidemenu = $('#sidemenu');
var $sidemenuShowButton = $('#sidemenuShowButton');
function(showSidemenu){
$showSidemenu.onmouseover($sidemenuShowButton).addclass('show');
}
#sidemenuShowButton {
width:60px;
height:100%;
background:#000000;
top:0;
left:0;
position:fixed;
}
#sidemenu {
width: 60px;
height:100%;
background-color: #383D3F;
position: fixed;
top: 0;
left:-60px;
float: left;
z-index:0;
}
#sidemenu.show {
left: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id="sidemenuShowButton"></div>
<div id="sidemenu"></div>

try this jQuery:
var $showSidemenu = $('#sidemenu');
var $sidemenuShowButton = $('#sidemenuShowButton');
$(document).ready(function(){
$sidemenuShowButton.on('mouseover',function(){
$('#sidemenu').addClass("show");
});
$sidemenuShowButton.on('mouseout',function(){
$('#sidemenu').removeClass("show");
});
// to make the showed div stay while the mouse is still over it
$('#sidemenu').on('mouseover',function(){
$(this).addClass("show");
});
$('#sidemenu').on('mouseout',function(){
$(this).removeClass("show");
});
});
if you want a little animation, you can use CSS3 Transition for that, like this one:
#sidemenu {
transition: 1s;
}
HERE'S A WORKING DEMO

Use JQuery's show and hide functions. If you set your #sidemenu to display: none;. And then use this this function it will work:
$('#sidemenu').mouseenter(function(){
$("#sidemenuShowButton").show();
}).mouseleave(function(){
$("#sidemenuShowButton").hide();
});
No classes are needed in this way.

Your JS should looks like this:
var $showSidemenu = $('#sidemenu');
var $sidemenuShowButton = $('#sidemenuShowButton');
$sidemenuShowButton.on('mouseover', function(){
$showSidemenu.addClass('show')
});
First of all you are using function which never used and cannot be used since it have no name. Second, there is no onmouseover method in jQuery (read the manual ;-). Third you have to pass there a callback function which will be involved when 'mouseover' event occurs.
And if you wanna hide your div when mouse leaves add
$showSidemenu.on('mouseleave', function(){
$showSidemenu.removeClass('show')
});
You should use $showSidemenu in this case instead of $sidemenuShowButton because when $showSidemenu apears mouse leaves $sidemenuShowButton and enters $showSidemenu. But if you wanna use css3 animation - it's better to make appearing div nested to control div and use event bobbling.
And jsfiddle

Solution:Use mouseover and mouseout events to add and remove class "show"
I have intentionally added mouseout event on showSidemenu as when it slides in it goes over sidemenuShowButton div and comes on top of it, so attaching mouseout to sidemenuShowButton will cause flickering effect.
http://api.jquery.com/category/events/mouse-events/
$sidemenuShowButton.mouseover(function(){
$showSidemenu.addClass("show");
}
);
$showSidemenu.mouseout(function(){
$showSidemenu.removeClass("show");
}
);
Working JS Fiddle Example: http://jsfiddle.net/2cjjdm7j/1/

Jquery effect - on mouse hover background color change;

I'm trying to create an effect that's, when the mouse over this change the background color from the left to the right.
I tried this:
http://jsfiddle.net/WVWKE/
$('#div1').mouseover(function(){
$('#back').animate({width: '200px'}, 1000);
});
$('#div1').mouseout(function (){
$('#back').animate({width: '0px'}, 1000).stop();
});
#div1{
height:200px;
width:200px;
background-color:green;
float:left;
}
#back {
width:0px;
height:200px;
background-color:Gray;
display: block;
}
<div id="div1">
<div style="position:absolute">That was amazing!</div>
<div id="back">
</div>
</div>
But, is not working correctly. If i put the mouse many times on the div, this do the effect many times and don't to.
Try to put the mouse and leave many times. The effect happens many times to.
Any help?

You are using stop incorrectly. Use it like this:
$('#div1').mouseover(function (){
$('#back').stop().animate({width: '200px'}, 1000);
});
$('#div1').mouseout(function (){
$('#back').stop().animate({width: '0px'}, 1000);
});
It's easy to understand if you think about it like it's English:
$('#back') // take "back"
.stop() // and stop it
.animate({width: '200px'}, 1000); // and animate it
Fiddle

jQuery animate movement left and right

Using jquery's .css() i am changing the left attributes value to move a div left or right. Im looking for a way to animate this change as it occurs. Nothing ive tried is working, ive tried jQueryUI's .show(slide) function, but this moves the whole div, rather than just the 120px movement i need.
This is my current function which is working without an animation:
$('#plrt').live("click",function(){
var lm=$('.plwid').css("left");
lm = (parseInt(lm) + 120);
$('.plwid').css("left", lm);
});
this is the slide function, it does not work properly as the whole div goes from display:hide to display:show, rather than just moving the pixel change

try animate()
$('#plrt').on("click",function(){
$('.plwid').animate({ left: '+=120' }, 400 );
});

I have whipped up a quick example of what I think you are trying to achieve.
You should check out jQuery Animate.
//note live is deprecated
$('#plrt').on("click", function() {
//perform custom animation to add 120px to current left CSS position
$('.plwid').animate({
left: '+=120'
});
});
#plrt{
position:relative;
background:red;
width:100px;
height:100px;
cursor:pointer;
}
.plwid{
position:absolute;
background:blue;
width:100px;
height:100px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div id="plrt"></div>
<div class="plwid"></div>

try this http://api.jquery.com/animate/
$('#plrt').on('click', function() {
$('.plwid').animate({ left: '+=120', 5000 });
});