In my HTML a#navInnerMapR and a#navInnerMapL are contained within div#navTwo.
The following code is within a function. When called, I need the function to fadeOut any visible links in div#navTwo, pause for a moment, and then fadeIn a#navInnerMapR.
$('div#navTwo a').fadeOut(200, function() {
$('a#navInnerMapR').delay(100).fadeIn(200);
});
The code fades out the links but doesn't fade anything in. I thought that they delay would only start once the fadeOut finishes, however changing the delay value to 1000 makes it sometimes work but its very buggy. Thanks
UPDATE Here is a fiddle showing that the hidden link starts to be shown before the visible is hidden: http://jsfiddle.net/jamesbrighton/d9QKr/5/
UPDATE Apologies, my question doesnt include the full details of what I need to achieve. I simplified it as I thought I just had some sort of sytax issus that could be easily fixed.
div#navTwo actually contains 3 links. At any point (other than the delay before animations run) only 1 link is visible. I need to be able to call a function that will hide either of the other 2 links that are being shown, and then show a#navInnerMapR.
Different events will call this function, so either of the 2 links that arn't a#navInnerMapR may be visible. Thanks
UPDATE I think this fiddle illustrates the issue. Ive created 2 div.nav's to illustrate different states. Ive hidden different links with inline CSS in each one. JavaScript will be showing and hiding the links in my div repeatedly, so the same div will look like each example at different times.
Ive created 2 triggers to illustrate that different events will need to call the function. When you click on a trigger you can see the issue with both examples. The visible divs are not hidden before the a.one is shown. Thanks for your patience!
http://jsfiddle.net/jamesbrighton/dYvMS/24/
Interesting point, if I change $('.nav a.one').fadeIn(1000); to an alert, the alert fires multiple times! No idea why this would be the case!
Edit: Updated answer based on your below comment,
Yes this works as I need, but im not sure it will work for my actual
page. Sorry for my question not being detailed enough. The code
example I gave is simplified. In the actual page their are 3 links
within div#navTwo, at any time only one of them will be visible. I
need to be able to call a function that hides any links and shows a
specific one, but either one of the other 2 links in div#navTwo may be
visible. Thanks
DEMO
HTML: Added class to all links inside navTwo
<div id="navTwo">
Right
Left
Middle
Upper
Lower
</div>
JS:
$('.links').click(function() {
showHide($(this));
});
function showHide($this) {
$this.fadeOut(1000, function() {
$('#navTwo a').not($this).delay(1000).fadeIn(1000);
});
}
I think I understood what you need. Try below DEMO and let me know if that is what you want,
DEMO
$('#navInnerMapR').click(function() {
runMeR($(this));
});
$('#navInnerMapL').click(function() {
runMeL($(this));
});
function runMeR($this) {
$this.fadeOut(1000, function() {
$('a#navInnerMapL').delay(1000).fadeIn(1000);
});
}
function runMeL($this) {
$this.fadeOut(1000, function() {
$('a#navInnerMapR').delay(1000).fadeIn(1000);
});
}
As you said, You need the function to fadeOut any visible links in div#navTwo, pause for a moment, and then fadeIn a#navInnerMapR (not other links, only a#navInnerMapR).
$('#navTwo a').click(function(e) {
$(this).parent().children().each(function(i){
$(this).fadeOut('slow', function(){
$('a#navInnerMapR').delay(1000).fadeIn(1000);
});
});
});
A fiddle is here.
Related
To explain the situation ,I am using both jquery and animate.css combined in order to bring about some animation part that i want to apply to my website.
http://lifeto.cafe24.com/xe/
I have a couple of questions in this post, and it needs fairly thorough understanding of the site that i have built.
Fist, If you go to the webstie I linked above and click on the menu that says '공지사항' on the bottom, an iframe src gets triggered by jquery attr.
And if you click on any of the image you can see on the board after that, the board content (#window_frame) slidesout to left and the new div (.window_board) slides in from the leftside.
but when you click on the image, notice the content of the board AND the .window_board disappear and appear AT THE SAME TIME.
what i want to achieve here is to have the #window_frame slides out first, and THEN, after it is done, have .window_board slides in.
and SECONDLY, when i click on the menu button that says '공지사항' from the point when the .window_board is still opened, i want the .window_board to slides back in, and have the content(#window_frame) comes back out.
I wonder if it's possible to achieve this only by using simple jquery events, as it needs to calculate when the #window_frame is opened or not.
here is the complete js for the board (iframe)
jQuery(document).ready(function(){
jQuery(document).on('click', '.item', function() {
jQuery('.loader_container', parent.document.body).show();
var url = jQuery(this).data('url');
jQuery('#window_board', parent.document.body).attr('src', 'url',200);
jQuery('#window_frame', parent.document.body).addClass('animated slideOutLeft');
jQuery('.window_board', parent.document.body).addClass('open animated slideInLeft');
jQuery('.loader_container', parent.document.body).hide();
});
});
and the main menu:
<a onclick="jQuery('#window_frame').attr('src',
'http://lifeto.cafe24.com{$val1['href']}',200),
jQuery('#window_frame').removeClass('animated slideOutLeft')" class="menu_a">MENU</a>
Your question not clear so much, but if i consider only your main question:
how to execute jquery function after one another
you can use promise().done() or .when() to execute a jquery function after another.
Example:
$('div').click(function(){
$(this).addClass('blah').promise().done(function(){
alert('class added!');
});
});
You can read more about it:
https://api.jquery.com/promise/
I want to slideDown() a div when the appropriate radio is selected, and slideUp the active one.
However, as it is now, in some cases it's being pushed down, in other cases pushed up.
(Private -> Shop = Up, Shop -> Private = Down)
I want it to always be pushed down. What am I doing wrong?
Here's the current state on JSFiddle: http://jsfiddle.net/mfmU7/
And the raw Javascript code:
$(document).ready(function() {
$("#private").click(function() {
$('#registration-brand, #registration-shop').slideUp();
$('#registration-private').slideDown();
});
$("#shop").click(function() {
$('#registration-brand, #registration-private').slideUp();
$('#registration-shop').slideDown();
});
$("#brand").click(function() {
$('#registration-shop, #registration-private').slideUp();
$('#registration-brand').slideDown();
});
});
It's all about position in the DOM (or z-index):
$(document).ready(function() {
$('.btn').on('click', function() {
var that = $('#registration-'+this.id);
$('.registration-type:visible').not(that).slideUp().before(that.slideDown());
});
});
FIDDLE
I had same problem and I resolve it by adding:
position:absolute;
bottom:85%;
to CSS and it solves your isue here
but then u have to again place those divs
Here: http://jsfiddle.net/isair/mfmU7/4/
The problem (that some slide up visually and some slide down visually) is caused because, in your original code, all the animations are occurring at once and the divs are vertically placed one above the other. So the top one looks like it is sliding down but the other two, while sliding down, look like they are popping up from the bottom because of the one that is in the process of hiding.
I like doing it this way so one action doesn't start until the others are over:
$("#private").click(function() {
$('#registration-brand, #registration-shop').slideUp(function() {
$('#registration-private').slideDown();
});
});
FIDDLE HERE
The problem with doing that (like I usually do) is that the function gets called twice, once when the already hidden div finishes hiding, which is almost immediately, and once after the other div finishes hiding (4/10 sec later). The second one does nothing because the appearing div is already fully visible (or almost so).
So ... another solution is needed.
This one has a whole different look because it waits until both slide up actions are done (even though one div is already hidden) before starting the slide down. The 'promise()' creates something that will be finished when all the 'slideUp()' calls complete their animation and the 'always()' calls the function when that is done.
$("#private").click(function() {
$('#registration-brand, #registration-shop').slideUp().promise().always(function() {
$('#registration-private').slideDown();
});
});
ALTERNATE FIDDLE
I'm new to javascript so I'm struggling with the basics...
I'm using this delay to bring in a div but i want to fade the div in as part of this function (not just have the box appear)
function show() {
AB = document.getElementById('div_with_text');
AB.style.display = 'inline';
}
setTimeout("show()", 3000);
Can any one help with this?
I've tried adding things like:
$(function(){
$('#div_with_text').fadeIn('slow');
});
but I don't know the language well enough to get it to work...
Any help would be much appreciated!
Is your DIV hidden in the first place? If not, that is your problem. Your are trying to open an already opened door.
Your code is also incorrect, even if you hide the DIV, this will not work. It should have been setTimeout(show, 3000);
With the JavaScript code (setTimeout) you have provided, 3 seconds after the page loads, you are trying to display the DIV. Did you notice that the DIV was already there and never 'appeared' after 3 seconds as you expected?
Example - http://jsfiddle.net/BLPTq/2/ - just click run and see.
To make it work, hide the DIV first and then call the setTimeout or the jQuery method. Example - http://jsfiddle.net/zeXyG/ - just click run and see. Check the CSS display:none;
OR, if you don't want to hide it with CSS, just call hide() before calling fadeIn()
$('#div_with_text').hide().fadeIn('slow');
Example - http://jsfiddle.net/zeXyG/1/
As per your comment below. Add delay() to the call like shown below
$('#div_with_text').hide(); // this or use css to hide the div
$('#div_with_text').delay(2000).fadeIn('slow');
2 seconds after the page loads, this will hide the div and then fade in slowly. Look at this example carefully.
The fadeIn method will only work if you load the jQuery library on your page. Without that, the method will not work since it isn't part of native Javascript.
Once you have loaded jQuery, that method will work as your syntax is correct.
I am currently making a website that includes a menu navigation almost identical to the one found at fotopunch.com only instead of pointing down it points up. Anyways, I wrote the code using jquery/javascript for the menu and it works but I am wondering if there is a way to make it so that the hover function doesn't take effect for a specified amount of time. That way when you hover quickly over an item it doesn't cause the page to load unnecessarily. If anyone has any suggestions I would greatly appreciate it.
Below is a copy of part of my code to create the menu navigation. Another issue I am having is if you hover over too many navigation items in a row the arrow lags behind. I am hoping that by creating a wait time before the hover function takes effect that it would mostly correct this issue.
$("div#menu .reps").hover(function() {
if(current_slide != "reps"){
$(".arrow").animate({"left":"135px"});//move the arrow
if(current_slide == "clients"){
$(".clients_display").stop(true, true).fadeOut().hide();
$(".reps_display").fadeIn().show();
current_slide = "reps";
}
else if(current_slide == "services"){
$(".services_display").stop(true, true).fadeOut().hide();
$(".reps_display").fadeIn().show();
current_slide = "reps";
}
else{
$(".training_display").stop(true, true).fadeOut().hide();
$(".reps_display").fadeIn().show();
current_slide = "reps";
}
}
});
I think that something that you can do, although there is probably a better way is:
declare a function where you place all the code with a condition:
function hoverFunc(option)
{
if($(option).is(':hover'))
{
all the code to show the menu
}
}
And on the over function you do:
$("div#menu .reps").hover(function() {
setTimeout("hoverFunc('"+getOptionName+"')",milliseconds);
});
The idea is: when over, set a timeout and when the timeout is reached, check if the mouse is over and then do whatever you want, the hardest point is to pass the reference to the function, but you can pass the name of the item just getting it from html or a rel attribute.
But if you dont need the reference it is really ease, just call the function and check the element.
There is another option that maybe is more interesting for you. You can add a delay to the all the effects and add a stop(true) before, this way, if the user change the tag fast, the events will be cancelled, but it will change if the user goes through an option fast and goes out of the menu.
You an use the delay on some of your calls such as:
$(".reps_display").delay(100).fadeIn().show();
Or you can make some of the show and hide have a longer duration: show(2000) for instance.
I am trying to make a simple searcher/highlighter and I am running into difficulties with inconsistent results/nothing happening when I test it out.
I think the biggest gap is my understanding of how the callback functions should work and what the selectors are able to match.
Ideally when one clicks on the tag, everything should fade out and only the dives with the matching tags in them should reappear. If nothing matches then the nothing found div should appear and the reset should fade veryhtign out and make all the divs (sans nomatch div) reappear unhighlighted.
Anyone provide some clarification on where I can improve?
Edit: See the link in the comments to see my code.
More clarification on problems:
Click on a tag (old, photography, guide) and then click on reset. All three parts should reappear but only two do.
Randomly The no results found will show up.
If you select a tag, then search for a different one, the fade ins and outs will be asynchronous.
The problem is that the .fadeout() was on each .workshopentry so would really be 3 fade outs. Therefore the animation complete callback function was being called 3 times as well! So the logic to determine which new entries to show and hide was being executed 3 times and causing the strange multiple fading.
I have updated the jsfiddle with a more robust solution.
Let me know if you need any more explanation of what the JavaScript is doing.
You need to copy your following code
if (toFadeIn.length < 1) { //No results found
toFadeIn.push(noResults);
}
$(toFadeIn).each(function(index, div){
div.fadeIn(1000);
});
inside the callback function of the workshop.fadeout.. like this :
workshop.fadeOut(1000, function() {
var tags = $('.left ul li', this);
tags.removeClass('searchMatch'); //reset the search results
tags.each(function() {
if ($(this).text().toLowerCase() === searchTerm.toLowerCase()) {
$(this).addClass('searchMatch');
toFadeIn.push($(this).parent().parent().parent());
}
});
if (searchTerm === "") {
toFadeIn.push(workshop);
}
if (toFadeIn.length < 1) { //No results found
toFadeIn.push(noResults);
}
$(toFadeIn).each(function(index, div){
div.fadeIn(1000);
});
});
You see? The fadeout callback was not yet called but you already started going through the toFadeIn array to show the search results. At that time it hadn't even searched through the entries yet.
It's only down to because we are mostly used to sequential code so callbacks take a little bit of head around. But it does work like that. You just keep on putting the code inside the callback ..and then again inside another callback and so on.