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Regex after first sign [duplicate]

This question already has answers here:
How can I get query string values in JavaScript?
(73 answers)
Closed 5 years ago.
I'm gonna to write regex or other expression to get coordinates after '='.
My example:
var cords = https://maps.googleapis.com/maps/api/staticmap?center=50.082961,19.966860&zoom=13&size=300x300&sensor=false&markers=color:orange%7C50.082961,19.966860&client=gme-marktplaats&channel=bt_pl&signature=lPDQWiNQ2_mY8xgoVthZHLLYWac=
I want to get 50.082961,19.966860
I know that I could use slice but I think I could write it better with regex.
Simple base for this example: \=(.[0-9]) What's next?

Try this center\=(\d+\.\d+,\d+\.\d+)&
var val = 'https://maps.googleapis.com/maps/api/staticmap?center=50.082961,19.966860&zoom=13&size=300x300&sensor=false&markers=color:orange%7C50.082961,19.966860&client=gme-marktplaats&channel=bt_pl&signature=lPDQWiNQ2_mY8xgoVthZHLLYWac='.match(/center\=(\d+\.\d+,\d+\.\d+)&/)[1]
console.log(val)
But as other's have commented, you likely shouldn't be using regex for this purpose

How can '+myVar;' be a valid syntax [duplicate]

This question already has answers here:
Explain +var and -var unary operator in javascript
(7 answers)
Closed 6 years ago.
I just got a bug that took some of my time to spot my searching filters weren't working because of the following code :
queryObject.search='valid==true';+searchQuery;
The good syntax is to mive the ';' in the string :
queryObject.search='valid==true;'+searchQuery;
The reasn why i didn't spot that is because the earlier line of code didn't triggered any javascript console error. So it seems it's a valid syntax.
So here is my question, how can this be a valid syntax ?

+something is an expression using the plus unary operator.
Its general purpose is to convert a value, for example a string, to a number.

+ is unary operator, which tries to get numeric value from variable.
There is a thread about it.

javascript now to create two ways currency format? [duplicate]

This question already has answers here:
How to convert a currency string to a double with Javascript?
(23 answers)
Closed 8 years ago.
I have found this link have a simple and useable funciton to convert number to currency.
www.mredkj.com/javascript/nfbasic.html
but how to turn it back form currency to number...
I already try this :
[http://jsfiddle.net/vb2cb1tm/3/]...
But its failed...
I try to read a formatted string using javascript and make a counting on this valua...

I think something as simple as
function numbers(nStr){
return Number(nStr.replace(/[\$\,]/g,''));
}
might do the trick, though it's hard to tell without seeing your original code.

function cur2num(cur) {
return parseFloat(cur.replace(/,/g,"");
}
if currency signs try /[^0-9]\.\-]/g as first argument to the replace

Number format with regex javascript [duplicate]

This question already has answers here:
Javascript Thousand Separator / string format [duplicate]
(15 answers)
Closed 8 years ago.
I have a number is 1205000000, I want display at 1.205.000.000
number.toString().replace(/(\d{3})/g, "$1.").toString()
but result is 120.500.000.0
I don't want reverse a number.

For the sake of correcting your regular expression (obviously for integer values only):
number.toString().replace(/(\d)(?=(?:\d{3})+$)/g, '$1.');
» Detailed Regex Explanation

One way would be to reverse the string before your manipulation and ther reverse it again. Like so:
var number = 1205000000;
function reverse(s) {
return s.split("").reverse().join("");
}
var str = reverse(reverse(number.toString()).replace(/(\d{3})/g, "$1."));
alert(str);
See this working fiddle.
EDIT:
See the comments. Its a bit dirty but for that specific number it will work. The link posted by #Artyom Neustroev as a comment under you question seems a whole lot better than this here.

Regex for a decimal number [duplicate]

This question already has answers here:
Displaying a number in Indian format using Javascript
(15 answers)
Closed 9 years ago.
I used the following regex
var x=32423332.343;
var res= x.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",");
which gives an output of 32,423,332.343
How do I modify this regex (shortest way) to get the following output
3,24,23,332.343

Well, if you want that, you can modify your regex a bit:
\B(?=(?:\d{2})*\d{3}(?!\d))
regex101 demo
(?:\d{2})* will match even number of digits before the final \d{3}.
For PCRE engine, one that can handle integers and floating, with g enabled.
\G\d{1,2}\K\B(?=(?:\d{2})*\d{3}(?!\d))