HTML in nested DIV's does not change - javascript

I have something like this in my page:
<div id="test">
<div class="item">Test</div>
<div class="item">Test</div>
<div class="item">Test</div>
<div class="item">Test
<div class="container">
<div class="item">Test2</div>
<div class="item">Test2</div>
<div class="item">Test2</div>
</div>
</div>
</div>
Now I want to do something like this:
$.each(this.find(".item"), function(index, value) {
$(value).html("Test" + $(value).html());
});
Of course I want to do some more stuff inside the loop, but this is only an example. When I do this, all "Test" change into "TestTest", but "Test2" does not change into "TestTest2". Is there a way to select these items, even if there are inside another one? Btw: There could be a conatiner in every item. Even in those who are already nested.

The call to $(value).html("Test" + ...) actually removes and re-adds elements, so any descendent elements (with class item) that are iterated over have already been removed from the DOM.
Try the following:
this.find(".item").each(function(index, value) {
$(value).prepend("<span>Test</span>");
});

Related

jQuery: Appending multiple elements from .load() after the last occurrence of a specific class element on a page

I'm working on a listing page and I am trying to create a "Load More Items" functionality. I'm attempting to use .load() to append all ".vehicleListing" elements from another page url (the second listing page) and add them after the last occurrence of a a div with the class of "vehicleListing".
Page 1:
<div class="overview-feature-1">
<div class="vehicleListing">1</div>
<div class="vehicleListing">2</div>
<div class="vehicleListing">3</div>
<div class="vehicleListing">4</div>
<div class="vehicleListing">5</div>
<div class="vehicleListing">6</div>
<div class="controls"></div>
<div class="additional-controls"></div>
</div>
Page 2:
<div class="overview-feature-1">
<div class="vehicleListing">7</div>
<div class="vehicleListing">8</div>
<div class="vehicleListing">9</div>
<div class="vehicleListing">10</div>
<div class="vehicleListing">11</div>
<div class="vehicleListing">12</div>
<div class="controls"></div>
<div class="additional-controls"></div>
</div>
Desired Result:
Page 1 after "Load More" functionality is executed:
<div class="overview-feature-1">
<div class="vehicleListing">1</div>
<div class="vehicleListing">2</div>
<div class="vehicleListing">3</div>
<div class="vehicleListing">4</div>
<div class="vehicleListing">5</div>
<div class="vehicleListing">6</div>
<div class="vehicleListing">7</div>
<div class="vehicleListing">8</div>
<div class="vehicleListing">9</div>
<div class="vehicleListing">10</div>
<div class="vehicleListing">11</div>
<div class="vehicleListing">12</div>
<div class="controls"></div>
<div class="additional-controls"></div>
</div>
This is what I have so far, but it keeps adding it inside the last vehicleListing div instead of after it.
$(".vehicleListing").after().last().load('page2url' + ' .vehicleListing');
Can someone point out why it's inserting inside the last div instead of after it, and how I can correct this?
Here is what worked for me:
Add an empty div after the last vehicleListing in your first file
<div class="overview-feature-1">
<div class="vehicleListing">1</div>
<div class="vehicleListing">2</div>
<div class="vehicleListing">3</div>
<div class="vehicleListing">4</div>
<div class="vehicleListing">5</div>
<div class="vehicleListing">6</div>
<div id="container"></div>
<div class="controls"></div>
<div class="additional-controls"></div>
</div>
And change your JS
$("#container").load('http://aba.bbtj.dev/test2.html' + ' .vehicleListing', function(){
$('#container').replaceWith(function() {
return $('.vehicleListing', this);
});
$( '<div id="container"></div>' ).insertAfter( ".vehicleListing:last" );
});
This will load the new vehicles in the empty div, and then remove that div and keep the new vehicles (using the replaceWith function).
Then we re-add the empty div to be able to add more vehicule.
Load documntation:
Description: Load data from the server and place the returned HTML into the matched element.
$(".vehicleListing").after().last()
Targets the last vehicleListing div.
You can try smething like:
$.load('page2url' + ' .vehicleListing').insertAfter(".vehicleListing:last");
Your probably going to have to go about this differently. As mentioned, load() takes the response and loads it into the element it is operating upon. Since it replaces the contents, it doesn't really fit what you are trying to do which is to append additional content to an existing element. Your best bet is to probably use an ajax method instead.
$.get('page2url' + ' .vehicleListing', function(data){
$(".vehicleListing").last().after(data);
});

jquery clone a link (once per div)

I have a set of divs, and need to clone the link from the top and insert into the last div (mobile-link). It is either cloning the links from all of the divs, and then inserting all of them at once, or if I use :eq(0), it's putting the first link into all of the divs.
<div class="course">Accounting</div>
<div class="start-date">1-1-2017</div>
<div class="credits">4</div>
<div class="location">Online</div>
<div class="mobile-link"></div>
<div class="course">Business</div>
<div class="start-date">1-1-2017</div>
<div class="credits">3</div>
<div class="location">Online/Campus</div>
<div class="mobile-link"></div>
<script>
$(".course a:eq(0)").clone().appendTo(".mobile-link");
</script>
What do I need to change to make this work properly?
You need to process each anchor separately:
$(".course").each(function() {
var myLink = $(this).find('a').clone();
$(this).nextAll('.mobile-link').first().append(myLink);
});
Demo fiddle
Append method can take a function as argument, and here it is appending to the each .mobile-link first <a> from his previous .course div
$(".mobile-link").append(function(){
return $(this).prevAll('.course:first').find('a:first').clone();
});
Check the below snippet
$(".mobile-link").append(function(i) {
return $(this).prevAll('.course:first').find('a:first').clone();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="course">Accounting
</div>
<div class="start-date">1-1-2017</div>
<div class="credits">4</div>
<div class="location">Online</div>
<div class="mobile-link"></div>
<div class="course">Business
</div>
<div class="start-date">1-1-2017</div>
<div class="credits">3</div>
<div class="location">Online/Campus</div>
<div class="mobile-link"></div>
I beleive that you should use last (If I understood question correctly):
var lastDiv = $(".mobile-link").last();
$(".course a:eq(0)").clone().appendTo(lastDiv);
Here is jsfiddle: fiddle

jQuery hide and show when the data matches

I made a snippet and I am working a jQuery show/hide when the data attr matches.
HTML structure is like below
<div class="container">
<div class="item" data-item="1">1
<div class="inside" data-content="1">
</div>
</div>
<div class="item" data-item="2">2
<div class="inside" data-content="2">
</div>
</div>
<div class="item" data-item="2">3
<div class="inside" data-content="3">
</div>
</div>
</div>
the class class="item" will be append (ed) to outside div, I'd like to achieve that,
if content data-num is existing, do not "append()", show()instead, then the slides can be showed properly. I wanted to learn how to check if data-num existing?
so the concept is like that,
if click on class item if item 's data-item(e.g. data-item = "2") matches outside > content data-num (e.g data-num = "2" ), then show() that content class.
Hope I made it clear. Thanks a lot.
Here is online sample: http://jsfiddle.net/8VD9R/
You have to iterate over the content class.
I am writing the sample code here ,Please update it accordingly:
$('.item').click(function(){
$('.content').hide();
$('.content').each(function(i, obj) {
if($(this).attr('data-item')==$(obj).attr('data-num'))
{
$(obj).show();
return;
}
});
});

Check if n-th child exists, if not create and update

I have a div structure as
<div class="hours_logged">
<div class="time_item">
<div class="record_id"></div>
<div class="time_logged">0</div>
<div class="desc"></div>
</div>
</div>
I am adding new items dynamically. When I add new time I save that via AJAX call and update my DOM. The above is the DOM that I want to update. If user adds 2 new times I want to add another "time_item" DIV and populate values in that. I am already using jquery each function and I get the index number right for the DIV but how do I check like if index is 2 then
if(!$('.hours_logged').eq(index))
{
$('.hours_logged').append(' <div class="time_item">
<div class="record_id"></div>
<div class="time_logged">0</div>
<div class="desc"></div>
</div>');
}
try this:
if($('.hours_logged').length < 1)
{
$('.hours_logged').append(' <div class="time_item"><div class="record_id"></div><div class="time_logged">0</div><div class="desc"></div></div>');
}

Append a div to a new div

i am using IPB and i am going to put each category into a new tab the category div is something like this:
<div id='category_100'>
<div id='category_104'>
<div id='category_102'>
<div id='category_101'>
and my tabs content is like this:
<div class="content">
<div id="content-1" class="content-1">
</div>
</div>
and the categories divs is already showing but i want it to be moved to the content-1 div without duplicate so i want it to move from its div to this div with jjava script how?
<script>
document.getElementById('content-1').appendChild(
document.getElementById('category_100')
);
</script>
this worked for me but how can i add more than id to category_100
i want it to be like this in one script code so i would not repeart the scrip code four times:
<div class="content">
<div id="content-1" class="content-1">
<div id='category_100'>
<div id='category_104'>
<div id='category_102'>
<div id='category_101'>
</div>
</div>
using my two lines the suggested things here is not working!
Try this code :
$('div[id^="category_"]').appendTo('#content-1')
Have a look to this fiddle : http://jsfiddle.net/lulu3030/sjEPx/2/
"using my two lines the suggested things here is not working!"
You just get a single element with an ID and trying to append it...
Live Demo
If you want to append multiple elements, there are many ways...
Wrap those elements and then append...
<div id="categories">
<div id='category_100'></div>
<div id='category_104'></div>
<!-- etc. -->
</div>
document.getElementById('content-1').appendChild(document.getElementById('categories'));
or add same class to all elements that you want to append...
<div id='category_100' class="myClass"></div>
<div id='category_104' class="myClass"></div>
[].forEach.call(document.getElementsByClassName("myClass"), function (value, index, array) {
document.getElementById("content-1").appendChild(value);
});
or get elements with query selector that match some pattern...
[].forEach.call(document.querySelectorAll("div[id^='category_']"), function (value, index, array) {
document.getElementById("content-1").appendChild(value);
});
and etc.

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