Develop Reference

Image change on hover from a stitched image

I have a image that is created to have 4 images in one See this image
Now, what I am trying to do is get the css to load just the first square at the top. Then when a user hovers over that image it will switch between all four images.
So it will display black on load, then when a user hovers over it, the image changes to red, then blue, then green, then back to black. It then repeats over and over until the mouse is moved off the image area.
I know that I can do this by converting the png to a gif but the image is generated outside of my control so this method is needed.
If anyone can help I will be forever grateful.
Cheers.

You should use CSS sprites and to make the change happend when over use setInterval function to change position ( here the height of each block of your image mesures 300px , so we incerement by +300 ) every defined interval time ,
Below snippet I've used .hover() jquery function to set and clear annimation .
var interval;
$(function(){
$("#image").hover(
function() {
var bottom = 0;
$this = $(this);
interval = setInterval(function() {
bottom >= 900 ? bottom = 0 : bottom+=300;
$this.css({'background-position' : '0px -'+bottom+'px'});
} , 1000)
},
function(){
$this.css({'background-position' : '0 0'})
clearInterval(interval);
}
);
});
#image {
width:150px;
height:150px;
background: url('https://i.stack.imgur.com/h8h14.png') 0 0px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="image" ><div>

How can I animate a div to the right when it is pressed, and then, when it is pressed again, return it back to its first position with jQuery?

I have multiple clickable panels made with Bootstrap class panel, organized in this way:
Image of my website naoh
For example, when I click on the first panel, some other panels appear and cool stuff happens.
When you click a panel.
But I want that the panel that I clicked to be at the center. And then, when that same panel is clicked, I want to return everything to normal (which right now works with the specific panels per panel), including the main panel, so it should move to the left. The panels at the center doesn't require animation, and the right ones should animate to the left and back to the right.
Here is my jQuery code for the panels, lets say panel 2:
//Panel 2
if ($("#panel_2").data("clicked")) {
$(".navegadores").toggle(function () { });
} else {
$(".navegadores").hide();
}
$("#panel_2").click(function () {
$("#panel_2").data('clicked', true);
$(".navegadores").toggle(function () { });
console.log($("#panel_2").data("clicked"));
});
I feel I would need to use the .toggle method somehow, or the .slideToggle, but I'm quite confused atm.

Something like this should get you started:
$('#panel2').click(function(){
if ( $(this).data('clickstate') == 0 ){
$(this).animate({
marginLeft: '200px'
},1000, function(){
$(this).data('clickstate', '1');
});
}else{
$(this).animate({
marginLeft: '0'
},1000, function(){
$(this).data('clickstate', '0');
});
}
});
#panel2{position:relative;height:100px;width:100px;background:green;}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div id="panel2" data-clickstate="0"></div>

Make .delay() and .animate() function re-run everytime a classes div opens

So, I'm sure there is a simple answer to this, but after 2 days of research I cannot find a solution.
The Story:
I have a dynamic page. When you get to one section and click on one of the 6 options it pulls up some info (name, place, etc.). I have a jQuery function that makes that info hide about half way after a few seconds. When you hover over that section with the mouse it also will animate up and back down as the mouse leaves it.
The Problem:
How do I make the whole function run again if another of those 6 option is clicked? Each time an option is selected the class with that info comes up, but after this function runs once (the delay part and animate down part) it just stays minimized unless you hover over it. I want it to appear every time and then run through the function. I have tried a number of things, and I'm sure there is a simple solution, just not sure what it is.
Here is a link to my codepen with a sample: http://codepen.io/jsegarra/pen/GxByr
I have also tried to wrap that all in a click function, for clicking on one of those 6 options and thought that would do the trick, but still the same thing:
$(document).ready(function () {
$('.title').click(function () {
$('.bottomTab').delay(5000).animate({
height: '50px' // to 50px
}, 'slow');
$(".bottomTab").hover(
//on mouseover
function () {
$(this).stop().animate({
height: '+=100' //adds 50px
}, 'slow');
},
//on mouseout
function () {
$(this).stop().animate({
height: '50px' //back to 50px
}, 'slow');
});
});
});

Just reset the div css before re-running the function
$(document).ready(function () {
$('.title').click(function () {
$('.bottomTab').css('height', '100px').delay(500).animate({
height: '50px' // to 50px
}, 'slow');
$(".bottomTab").hover(
//on mouseover
function () {
$(this).stop().animate({
height: '+=100' //adds 50px
}, 'slow');
},
//on mouseout
function () {
$(this).stop().animate({
height: '50px' //back to 50px
}, 'slow');
});
});
});
Here is the html I used with that javascript
<div class="title">title</div>
<div class="bottomTab">This is going to move from just being about 50 pixels high to about 100 pixels high after i add in some mouseenter and mouse out events</div>
I used the same CSS of your code pen, and the result was a full reclickable option

I don't see the problem. Your code seems to works fine. You've just typed an error while transfering to CodePen. Replace $('this').hover( with $('.bottomTab').hover(.

jQuery show div on hover with image map

I have an image map that I want to show a new div when I hove over the hotspots. It starts with a default listing of text but once I mouseover the hotspots, I want that to change out to the corresponding div's. I'm using the following code and am getting no joy:
$(".office-default").mouseover(function () {
var elementId = "#office-" + $(this).attr("id").split("-")[1];
$(elementId).removeClass("hidden");
});
$(".office-default").mouseout(function () {
var elementId = "#office-" + $(this).attr("id").split("-")[1];
$(elementId).addClass("hidden");
});
Here's the entire code:
http://jsfiddle.net/leadbellydesign/jR6pa/1/
I've done tons of searches and have come up with nothing helpful. I don't want to change images, I just want to show div's.

You still need to fix the space below the divs, but this should work
DEMO
$("area").hover(function () {
$office = $(this).attr("href");
$(".office-default > div").addClass("hidden");
$($office).removeClass("hidden");
}, function(){
$(".office-default > div").addClass("hidden");
$("#office-1").removeClass("hidden");
});
UPDATE
To fix the spacing issue, update your .office-default CSS:
DEMO
.office-default {
background:#444;
padding:5px 15px 0;
width: 80%;
height:150px;
}

Slide boxes with margin-left check if overslided

I made a simple content/box slider which uses the following javascript:
$('#left').click(function () {
$('#videos').animate({
marginLeft: '-=800px'
}, 500);
});
$('#right').click(function () {
$('#videos').animate({
marginLeft: '+=800px'
}, 500);
});
Here is the demo: http://jsfiddle.net/tjset/2/
What I want to do and I can't figure out how to show and hide arrows(left and right box) as the all the boxes slided.
So I clicked 4 time to the LEFT and slided all the boxes! then hide "left" so that you can't give more -800px
What can I do?

What you can do is check after the animation completes to see if the margin-left property is smaller or larger than the bounds of the video <div>. If it is, depending on which navigation button was clicked, hide the appropriate navigation link.
Check out the code below:
$('#left').click(function () {
// reset the #right navigation button to show
$('#right').show();
$('#videos').animate({
marginLeft: '-=800px'
}, 500, 'linear', function(){
// grab the margin-left property
var mLeft = parseInt($('#videos').css('marginLeft'));
// store the width of the #video div
// invert the number since the margin left is a negative value
var videoWidth = $('#videos').width() * -1;
// if the left margin that is set is less than the videoWidth var,
// hide the #left navigation. Otherwise, keep it shown
if(mLeft < videoWidth){
$('#left').hide();
} else {
$('#left').show();
}
});
});
// do similar things if the right button is clicked
$('#right').click(function () {
$('#left').show();
$('#videos').animate({
marginLeft: '+=800px'
}, 500, 'linear', function(){
var mRight = parseInt($('#videos').css('marginLeft'));
if(mRight > 100){
$('#right').hide();
} else {
$('#right').show();
}
});
});
Check out the jsfiddle:
http://jsfiddle.net/dnVYW/1/

There are many jQuery plugins for this. First determine how many results there are, then determine how many you want visible, then use another variable to keep track with how many are hidden to the left and how many are hidden to the right. So...
var total = TOTAL_RESULTS;
var leftScrolled = 0;
var rightScrolled = total - 3; // minus 3, since you want 3 displayed at a time.
instead of using marginLeft I would wrap all of these inside of a wrapper and set the positions to absolute. Then animate using "left" property or "right". There's a lot of code required to do this, well not MUCH, but since there are many plugins, I think you'd be better off searching jquery.com for a plugin and look for examples on how to do this. marginLeft is just not the way to go, since it can cause many viewing problems depending on what version of browser you are using.