I followed a tutorial to create a simple javascript slideshow but I am having a strange bug... The first 2 cycles work perfectly, but once the counter resets the slideshow begins showing the previous slide quickly then trying to fade in the correct slide. Any idea what is causing this?
I have 3 images (named Image1.png, Image2.png, and Image3.png) in a folder for my simple slideshow and 3 divs set up like this:
<div id="SlideshowFeature">
<div id="counter">
3
</div>
<div class="behind">
<img src="SlideShow/image1.png" alt="IMAGE" />
</div>
<div class="infront">
<img src="SlideShow/image1.png" alt="IMAGE" />
</div>
</div>
My javascript looks like this
var nextImage;
var imagesInShow;
var currentImage;
var currentSrc
var nextSrc
function changeImage() {
imagesInShow = "3";
currentImage = $("#counter").html();
currentImage = parseInt(currentImage);
if (currentImage == imagesInShow) {
nextImage = 1;
}
else {
nextImage = currentImage + 1;
}
currentSrc = $(".infront img").attr("src");
nextSrc = "SlideShow/image" + nextImage + ".png";
$(".behind img").attr("src", currentSrc);
$(".infront").css("display", "none");
$(".infront img").attr("src", nextSrc);
$(".infront").fadeIn(1000);
$("#counter").html(nextImage);
setTimeout('changeImage()', 5000);
}
$(document).ready(function () {
changeImage();
});
EDIT:
Also here is my CSS
#SlideshowFeature
{
text-align:center;
margin: 0 auto;
width:800px;
background: #02183B;
height:300px;
float: left;
overflow:hidden;
display:inline;
}
#SlideshowFeature div
{
width: 800px;
height:300px;
position:absolute;
}
#counter
{
display:none;
}
The problem seem to be in your HTML structure (and not in your JS):
...
<img src="SlideShow/image1.png" alt="IMAGE" />
...
<img src="SlideShow/image1.png" alt="IMAGE" />
...
I think you meant to put image1.png and then image2.png
.infront must be in front and .behind must be behind
.behind {
z-index: 1;
}
.infront {
z-index: 255;
}
And I also moved re-scheduling logic to fadeIn callback:
$(".infront").fadeIn(1000, function(){setTimeout('changeImage()', 2500)});
$("#counter").html(nextImage);
//setTimeout('changeImage()', 2500);
Looks good for me now.
Related
I want to change an image to some other image when i click on the object. the code is stacked in the following order:
<li><img><some text></img></li>
<li><img><some text></img></li>
<li><img><some text></img></li>
<li><img><some text></img></li>
<li><img><some text></img></li>
What I wish to do is, when I click on the <li> i want to change the image to a coloured version of the image, i.e. some other image. Now, I know I can use JQuery/JS to accomplish it. But I don't want a huge amount of JS code to accomplish something so simple.
Can it be done using something simpler? Like pseudo selectors? .active class?
I cannot seem to think of it.
To change image onclik with javascript you need to have image with id:
<p>
<img alt="" src="http://www.userinterfaceicons.com/80x80/minimize.png"
style="height: 85px; width: 198px" id="imgClickAndChange" onclick="changeImage()"/>
</p>
Then you could call the javascript function when the image is clicked:
function changeImage() {
if (document.getElementById("imgClickAndChange").src == "http://www.userinterfaceicons.com/80x80/minimize.png"){
document.getElementById("imgClickAndChange").src = "http://www.userinterfaceicons.com/80x80/maximize.png";
} else {
document.getElementById("imgClickAndChange").src = "http://www.userinterfaceicons.com/80x80/minimize.png";
}
}
This code will set the image to maximize.png if the current img.src is set to minimize.png and vice versa.
For more details visit:
Change image onclick with javascript link
Or maybe
and that is prob it
<img src="path" onclick="this.src='path'">
How about this? It doesn't require so much coding.
$(".plus").click(function(){
$(this).toggleClass("minus") ;
})
.plus{
background-image: url("https://cdn0.iconfinder.com/data/icons/ie_Bright/128/plus_add_blue.png");
width:130px;
height:130px;
background-repeat:no-repeat;
}
.plus.minus{
background-image: url("https://cdn0.iconfinder.com/data/icons/ie_Bright/128/plus_add_minus.png");
width:130px;
height:130px;
background-repeat:no-repeat;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="plus">CHANGE</div>
If your images are named you can reference them through the DOM and change the source.
document["imgName"].src="../newImgSrc.jpg";
or
document.getElementById("imgName").src="../newImgSrc.jpg";
The most you could do is to trigger a background image change when hovering the LI. If you want something to happen upon clicking an LI and then staying that way, then you'll need to use some JS.
I would name the images starting with bw_ and clr_ and just use JS to swap between them.
example:
$("#images").find('img').bind("click", function() {
var src = $(this).attr("src"),
state = (src.indexOf("bw_") === 0) ? 'bw' : 'clr';
(state === 'bw') ? src = src.replace('bw_','clr_') : src = src.replace('clr_','bw_');
$(this).attr("src", src);
});
link to fiddle: http://jsfiddle.net/felcom/J2ucD/
Here, when clicking next or previous, the src attribute of an img tag is changed to the next or previous value in an array.
<div id="imageGallery">
<img id="image" src="http://adamyost.com/images/wasatch_thumb.gif" />
<div id="previous">Previous</div>
<div id="next">Next</div>
</div>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<script>
$( document ).ready(function() {
var images = [
"http://placehold.it/350x150",
"http://placehold.it/150x150",
"http://placehold.it/50x150"
];
var imageIndex = 0;
$("#previous").on("click", function(){
imageIndex = (imageIndex + images.length -1) % (images.length);
$("#image").attr('src', images[imageIndex]);
});
$("#next").on("click", function(){
imageIndex = (imageIndex+1) % (images.length);
$("#image").attr('src', images[imageIndex]);
});
$("#image").attr(images[0]);
});
</script>
I was able to implement this by modifying this answer: jQuery array with next and previous buttons to scroll through entries
If you don't want use js, I think, you can use instead of img and then use css like
a {
background: url('oldImage.png');
}
a:visited {
background: url('newImage.png');
}
EDIT: Nope. Sorry it works only for :hover
You can try something like this:
CSS
div {
width:200px;
height:200px;
background: url(img1.png) center center no-repeat;
}
.visited {
background: url(img2.png) center center no-repeat;
}
HTML
<div href="#" onclick="this.className='visited'">
<p>Content</p>
</div>
Fiddle
This script helps to change the image on click the text:
<script>
$(document).ready(function(){
$('li').click(function(){
var imgpath = $(this).attr('dir');
$('#image').html('<img src='+imgpath+'>');
});
$('.btn').click(function(){
$('#thumbs').fadeIn(500);
$('#image').animate({marginTop:'10px'},200);
$(this).hide();
$('#hide').fadeIn('slow');
});
$('#hide').click(function(){
$('#thumbs').fadeOut(500,function (){
$('#image').animate({marginTop:'50px'},200);
});
$(this).hide();
$('#show').fadeIn('slow');
});
});
</script>
<div class="sandiv">
<h1 style="text-align:center;">The Human Body Parts :</h1>
<div id="thumbs">
<div class="sanl">
<ul>
<li dir="5.png">Human-body-organ-diag-1</li>
<li dir="4.png">Human-body-organ-diag-2</li>
<li dir="3.png">Human-body-organ-diag-3</li>
<li dir="2.png">Human-body-organ-diag-4</li>
<li dir="1.png">Human-body-organ-diag-5</li>
</ul>
</div>
</div>
<div class="man">
<div id="image">
<img src="2.png" width="348" height="375"></div>
</div>
<div id="thumbs">
<div class="sanr" >
<ul>
<li dir="5.png">Human-body-organ-diag-6</li>
<li dir="4.png">Human-body-organ-diag-7</li>
<li dir="3.png">Human-body-organ-diag-8</li>
<li dir="2.png">Human-body-organ-diag-9</li>
<li dir="1.png">Human-body-organ-diag-10</li>
</ul>
</div>
</div>
<h2><a style="color:#333;" href="http://www.sanwebcorner.com/">sanwebcorner.com</a></h2>
</div>
function chkicon(num,allsize) {
var flagicon = document.getElementById("flagicon"+num).value;
if(flagicon=="plus"){
//alert("P== "+flagicon);
for (var i = 0; i < allsize; i++) {
if(document.getElementById("flagicon"+i).value !=""){
document.getElementById("flagicon"+i).value = "plus";
document.images["pic"+i].src = "../images/plus.gif";
}
}
document.images["pic"+num].src = "../images/minus.gif";
document.getElementById("flagicon"+num).value = "minus";
}else if(flagicon=="minus"){
//alert("M== "+flagicon);
document.images["pic"+num].src = "../images/plus.gif";
document.getElementById("flagicon"+num).value = "plus";
}else{
for (var i = 0; i < allsize; i++) {
if(document.getElementById("flagicon"+i).value !=""){
document.getElementById("flagicon"+i).value = "plus";
document.images["pic"+i].src = "../images/plus.gif";
}
}
}
}
<body>
<div id = "SiteContainer">
<div id = "NavigationButtons"></div>
<div id = "ShowReelContainer">
<div id= "NavigationBackward" name = "back" onclick="setPosition();">x</div>
<div id= "NavigationForward" name = "forward" onclick="setPosition();">y</div>
<div id = "VideoWrapper">
<div id = "SlideShowItem">
<img src="Images/A.png" alt="A"></img>
</div>
<div id = "SlideShowItem">
<img src="Images/B.png" alt="B"></img>
</div>
<div id = "SlideShowItem">
<img src="Images/C.png" alt="C" ></img>
</div>
</div>
</div>
</div>
<script>
var wrapper = document.querySelector("#VideoWrapper");
function setPosition(e)
{
if(e.target.name = "forward")
{
if!(wrapper.style.left = "-200%")
{
wrapper.style.left = wrapper.style.left - 100%;
}
}
else
{
if(e.target.name = "back")
{
if!(wrapper.style.left = "0%")
{
wrapper.style.left = wrapper.style.left + 100%;
}
}
}
}
</script>
</body>
Hi, I am very new to javascript. What I am trying to do, is change the x-position of a div when another div (NavigationForward or NavigationBackward) is clicked. However it does not appear to do anything at all. Basically if the div with name forward is clicked, I want to translate the VideoWrapper -100% from it's current position and +100% when "back". The css div itself VideoWrapper has a width of 300%. Inside this div as you can see is a SlideShowItem which is what will change. Perhaps I am adding and subtracting 100% the wrong way?
EDIT:
Thanks everyone for helping me out with this...I had just one more query, I am trying to hide the arrows based on whether the wrapper is at the first slide or the last slide. If its on the first slide, then I'd hide the left arrow div and if it's on the last, I'd hide the right arrow, otherwise display both of em. Ive tried several ways to achieve this, but none of em work, so Ive resorted to using copies of variables from the function that works. Even then it does not work. It appears that my if and else if statements always evaluate to false, so perhaps I am not retrieving the position properly?
function HideArrows()
{
var wrapper2 = document.getElementById("VideoWrapper");
var offset_x2 = wrapper2.style.left;
if(parseInt(offset_x2,10) == max_x)
{
document.getElementById("NavigationForward").display = 'none';
}
else if(parseInt(offset_x2,10) == min_x)
{
document.getElementById("NavigationBackward").display = 'none';
}
else
{
document.getElementById("NavigationForward").display = 'inline-block';
document.getElementById("NavigationBackward").display = 'inline-block';
}
}
//html is the same except that I added a mouseover = "HideArrows();"
<div id = "ShowReelContainer" onmouseover="HideArrows();">
To achieve this type o slider functionality your div VideoWrapper must have overflow:hidden style, and your SlideShowItemdivs must have a position:relative style.
Then to move the slides forward or backward you can use the style left which allows you to move the divs SlideShowItem relative to it's parent VideoWrapper.
I've tested this here on JSFiddle.
It seems to work as you described in your question, although you may need to do some adjustments, like defining the width of your slides, how many they are and so on.
For the sake of simplicity, I defined them as "constants" on the top of the code, but I think you can work from that point on.
CSS
#VideoWrapper{
position:relative; height:100px; white-space:nowrap;width:500px;
margin-left:0px; border:1px solid #000; overflow:hidden; }
.SlideShowItem{
width:500px; height:100px;display:inline-block;position:relative; }
#NavigationForward, #NavigationBackward{
cursor:pointer;float:left; background-color:silver;margin-right:5px;
margin-bottom:10px; text-align:center; padding:10px; }
HTML
<div id = "SiteContainer">
<div id = "NavigationButtons">
</div>
<div id = "ShowReelContainer">
<div id= "NavigationBackward" name = "back" onclick="setPosition('back');">prev</div>
<div id= "NavigationForward" name = "forward" onclick="setPosition('forward');">next</div>
<div style="clear:both;"></div>
<div id = "VideoWrapper">
<div class= "SlideShowItem" style="background-color:blue;">
Slide 1
</div>
<div class = "SlideShowItem" style="background-color:yellow;">
Slide 2
</div>
<div class = "SlideShowItem" style="background-color:pink;">
Slide 3
</div>
</div>
</div>
</div>
JavaScript
var unit = 'px'; var margin = 4; var itemSize = 500 + margin; var itemCount = 3; var min_x = 0; var max_x = -(itemCount-1) * itemSize;
function setPosition(e) {
var wrapper = document.getElementById("VideoWrapper");
var slides = wrapper.getElementsByTagName('div');
var offset_x = slides[0].style.left.replace(unit, '');
var curr_x = parseInt(offset_x.length == 0 ? 0 : offset_x);
if(e == "forward")
{
if(curr_x <= max_x)
return;
for(var i=0; i<slides.length; i++)
slides[i].style.left= (curr_x + -itemSize) + unit;
}
else if(e == "back")
{
if(curr_x >= min_x)
return;
for(var i=0; i<slides.length; i++)
slides[i].style.left= (curr_x + itemSize) + unit;
} }
After you analyze and test the code, I don't really know what's your purpose with this, I mean, you maybe just playing around or trying to develop something for a personal project, but if you are looking for something more professional avoid to create things like sliders on your own, as there are tons of plugins like this available and well tested out there on the web.
Consider using jQuery with NivoSlider, it works like a charm and is cross browser.
I would recommend using jQuery, this will reduce your coding by quite a bit. Can read more here: http://api.jquery.com/animate/
I've created a simple fiddle for you to take a look at. This example uses the .animate() method to reposition two div elements based on the CSS 'left' property.
CSS:
#container {
position: absolute;
left: 1em;
top: 1em;
right: 1em;
bottom: 1em;
overflow: hidden;
}
#one, #two {
position: absolute;
color: white;
}
#one {
background: pink;
width: 100%;
top:0;
bottom:0;
}
#two {
background: blue;
width: 100%;
left: 100%;
top:0;
bottom:0;
}
HTML:
<div id="container">
<div id="one">Div One</div>
<div id="two">Div Two</div>
</div>
JavaScript/jQuery:
var one, two, container;
function animateSlides(){
one.animate({
left : '-100%'
}, 1000, function(){
one.animate({
left : 0
}, 1000);
});
two.animate({
left : 0
}, 1000, function(){
two.animate({
left:'100%'
}, 1000);
});
};
$(function(){
one = $('#one');
two = $('#two');
container = $('#container');
setInterval(animateSlides, 2000);
});
JSFiddle Example: http://jsfiddle.net/adamfullen/vSSK8/3/
I am working on an image slideshow, and the fadeOut() functionality working with every image change, but the next image appears abruptly. I want it to fade in. I can't seem to get it working.
Here is the code without any fadeIn():
HTML:
<div id="backgroundChanger">
<img class="active" src="background1.jpg"/>
<img src="background2.jpg"/>
<img src="background3.jpg"/>
CSS:
#backgroundChanger{
position:relative;
}
#backgroundChanger img{
position:absolute;
z-index:-3
}
#backgroundChanger img.active{
z-index:-1;
}
Javascript:
function cycleImages(){
var $active = $('#backgroundChanger .active');
var $next = ($active.next().length > 0) ? $active.next() : $('#backgroundChanger img:first');
$next.css('z-index',-2);
$active.fadeOut(1500,function(){
$active.css('z-index',-3).show().removeClass('active');
$next.css('z-index',-1).addClass('active');
});
}
$(document).ready(function(){
setInterval('cycleImages()', 7000);
})
I'd recommend something like this for your interval function:
window.setInterval(function (){
var images = $('#backgroundChanger img');
var active, next;
images.each(function(index, img) {
if($(img).hasClass('active')) {
active = index;
next = (index === images.length - 1) ? 0 : index + 1;
}
});
$(images[active]).fadeOut(1000, function() {
$(images[next]).fadeIn(1000);
});
$(images[next]).addClass('active');
$(images[active]).removeClass('active');
}, 3000);
And this is all you'd need for your css:
#backgroundChanger img:first-child {
display: block;
}
#backgroundChanger img {
display: none;
}
And keep the same HTML and you should be good to go!
You can fadeIn() the next image in the callback of fadeOut() as shown below:
$(window).load(function() {
var $slider = $("#backgroundChanger"),
$slides = $slider.find("img"),
$firstSlide = $slides.first();
function cycleImages() {
var $active = $('#backgroundChanger .active'),
$next = ($active.next().length > 0) ? $active.next() : $firstSlide;
$active.fadeOut(1000, function() {
$active.removeClass('active');
$next.fadeIn(1000).addClass('active');
});
}
setInterval(cycleImages, 3000);
})
#backgroundChanger img {
position: absolute;
width: 150px;
height: 100px;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="backgroundChanger">
<img class="active" src="http://i46.tinypic.com/2epim8j.jpg" />
<img src="http://i49.tinypic.com/28vepvr.jpg" />
<img src="http://i50.tinypic.com/f0ud01.jpg" />
</div>
Notes:
Since we're dealing with images, It's better to use load() handler than ready() to make sure the slide show starts after the images are loaded
You can slightly improve the performance by caching the elements accessed frequently
You don't have to play with z-index property at all since both fadeIn() and fadeOut() changes the elements `display property itself
I was working with responsive web design and I wanted to slide some images in to a page. I tried some plugins but the problem with the plugin is it uses width and height property and also assigns position: absolute. So I thought of changing the src of the image myself using js and it worked fine, but can I give some transition effect to it?
Demo fiddle
What I have done is:
var i = 0;
var total = 2;
window.setInterval(function() {
show_hide();
}, 1000);
function show_hide() {
var img = $('.image-holder img, .image-holder2 img');
//alert(img.length);
if (i % 2 == 0) {
img[0].src = 'http://digimind.com/blog/wp-content/uploads/2012/02/number2c.png';
img[1].src = 'http://digimind.com/blog/wp-content/uploads/2012/02/number2c.png';
i = 0;
}
else {
img[0].src = 'http://healthystartups.com/storage/600px-MA_Route_1.png?__SQUARESPACE_CACHEVERSION=1319542839834';
img[1].src = 'http://healthystartups.com/storage/600px-MA_Route_1.png?__SQUARESPACE_CACHEVERSION=1319542839834';
}
i++;
}
My HTML is as follows:
<div class="image-holder" >
<img src="http://healthystartups.com/storage/600px-MA_Route_1.png?__SQUARESPACE_CACHEVERSION=1319542839834" />
</div>
<div class="image-holder2" >
<img src="http://healthystartups.com/storage/600px-MA_Route_1.png?__SQUARESPACE_CACHEVERSION=1319542839834" />
</div>
Here's what I put together. jsFiddle
javascript
var img = $(".image-holder img")
var i = 0;
var count = img.length - 1;
setInterval(function() {
showImage(i);
i++;
if (i > count) i = 0;
}, 2000);
function showImage(i) {
img.eq(i - 1).animate({
"opacity": "0"
}, 1000);
img.eq(i).animate({
"opacity": "1"
}, 1000);
}
HTML
<div class="image-holder" >
<img src="http://healthystartups.com/storage/600px-MA_Route_1.png?__SQUARESPACE_CACHEVERSION=1319542839834" />
</div>
<div class="image-holder" >
<img src="http://digimind.com/blog/wp-content/uploads/2012/02/number2c.png" />
</div>
CSS
.image-holder img{ opacity: 0;}
.image-holder { position: absolute; }
I am new person in Front End Development and i am facing one major problem is that i have 3 images placed on each others and now i want to move one image so the other image comes up and then it goes and third image comes up after some interval of time.
I want three images on same position in my site but only wants to see these three images one after one after some interval of time.
Please help how i can do this??
May i use marquee property or javascript???
Non-jQuery Option
If you don't want to go down the jquery route, you can try http://www.menucool.com/javascript-image-slider. The setup is just as easy, you just have to make sure that your images are in a div with id of slider and that div has the same dimensions as one of your images.
jQuery Option
The jQuery cycle plugin will help you achieve this. It requires jquery to work but it doesn't need much setting up to create a simple sliple slideshow.
Have a look at the 'super basic' demo:
$(document).ready(function() {
$('.slideshow').cycle({
fx: 'fade' // choose your transition type, ex: fade, scrollUp, shuffle, etc...
});
});
It has many options if you want something a bit fancier.
Here you go PURE JavaScript solution:
EDIT I have added image rotation... Check out live example (link below)
<script>
var current = 0;
var rotator_obj = null;
var images_array = new Array();
images_array[0] = "rotator_1";
images_array[1] = "rotator_2";
images_array[2] = "rotator_3";
var rotate_them = setInterval(function(){rotating()},4000);
function rotating(){
rotator_obj = document.getElementById(images_array[current]);
if(current != 0) {
var rotator_obj_pass = document.getElementById(images_array[current-1]);
rotator_obj_pass.style.left = "-320px";
}
else {
rotator_obj.style.left = "-320px";
}
var slideit = setInterval(function(){change_position(rotator_obj)},30);
current++;
if (current == images_array.length+1) {
var rotator_obj_passed = document.getElementById(images_array[current-2]);
rotator_obj_passed.style.left = "-320px";
current = 0;
rotating();
}
}
function change_position(rotator_obj, type) {
var intleft = parseInt(rotator_obj.style.left);
if (intleft != 0) {
rotator_obj.style.left = intleft + 32 + "px";
}
else if (intleft == 0) {
clearInterval(slideit);
}
}
</script>
<style>
#rotate_outer {
position: absolute;
top: 50%;
left: 50%;
width: 320px;
height: 240px;
margin-top: -120px;
margin-left: -160px;
overflow: hidden;
}
#rotate_outer img {
position: absolute;
top: 0px;
left: 0px;
}
</style>
<html>
<head>
</head>
<body onload="rotating();">
<div id="rotate_outer">
<img src="0.jpg" id="rotator_1" style="left: -320px;" />
<img src="1.jpg" id="rotator_2" style="left: -320px;" />
<img src="2.jpg" id="rotator_3" style="left: -320px;" />
</div>
</body>
</html>
And a working example:
http://simplestudio.rs/yard/rotate/rotate.html
If you aim for good transition and effect, I suggest an image slider called "jqFancyTransitions"
<html>
<head>
<script type="text/javascript">
window.onload = function(){
window.displayImgCount = 0;
function cycleImage(){
if (displayImgCount !== 0) {
document.getElementById("img" + displayImgCount).style.display = "none";
}
displayImgCount = displayImgCount === 3 ? 1 : displayImgCount + 1;
document.getElementById("img" + displayImgCount).style.display = "block";
setTimeout(cycleImage, 1000);
}
cycleImage();
}
</script>
</head>
<body>
<img id="img1" src="./img1.png" style="display: none">
<img id="img2" src="./img2.png" style="display: none">
<img id="img3" src="./img3.png" style="display: none">
</body>
</html>
Fiddle: http://jsfiddle.net/SReject/F7haV/
arrayImageSource= ["Image1","Image2","Image3"];
setInterval(cycle, 2000);
var count = 0;
function cycle()
{
image.src = arrayImageSource[count]
count = (count === 2) ? 0 : count + 1;
}
Maybe something like this?