calculating average using for loop in javascript - javascript

function averageCalculator (numvalues) {
for(i=0, i <= numvalues, i++>) {
var score = prompt("input the score")
result1 += score;
}
alert(result1 / 3);
}
this function is later triggered by a button with onclick="averageCalculator (2)
<input type="button" value="Click for the average" onclick="averageCalculator (2)">
any ideas why its not working? it should prompt you for 2 values and then alert you with the average. not sure whats wrong.

Your code has multiple issues. The for loop is not well formatted and you need to terminate statements with a semi-colon. Also you need to declare variables. And your loop will run numvalues+1 times which is why i removed the = in your loop. Also if you want to calculate an average you want to divide by numvalues.
function averageCalculator (numvalues) {
var result1 = 0;
for(i=0; i < numvalues; i++) {
var score = prompt("input the score");
result1 += score;
}
alert(result1 / numvalues);
}
On top of the invalid syntax you will run into a common "problem" with javascript here. The inputs are treated as strings and instead of being added they will be concatenated. Providing 2 and 2 as scores will result in 11. 2 concatenated with 2 = 22 / 2 = 11. You need to cast the value to a number explicitly before adding them together:
function averageCalculator (numvalues) {
var result1 = 0;
for(i=0; i < numvalues; i++) {
var score = prompt("input the score");
result1 += Number(score);
}
alert(result1 / numvalues);
}
Above code will correctly return 2

The syntax of your for-loop is wrong:
for(i=0, i <= numvalues, i++>) {
should be
for(i=0; i <= numvalues; i++) {
Tip: Also, it's better to use
for(var i=0; i <= numvalues; i++) {
since then i will be a local variable instead of a global one.

Try like this
for(var i=0; i <= numvalues; i++){}

An alternative solution (using a functional programming libary, like Underscore.js):
function averageCalculator(numValues) {
var numbers = _.map(_.range(numValues), function(element) {
return +prompt('input the score');
});
var result = _.reduce(numbers, function(memo, number) {
return memo + number;
}, memo);
alert(result / 3);
}
While a little bit more complicated (and less efficient), you'll get rid of loops altogether.
EDIT
The +prompt('input the score') does effectivly the same as Number(prompt('input the score')).

Related

Luhn Check Javascript

I am attempting to have someone input there credit card number and validate if it is a valid number by doing the Luhn Check. I want to be able to check it if they input the whole card number as one big string or if they put spaces in it. In my function validate though I keep getting an error message that there is an illegal return statement for my total variable. Here is my current code.
<script type="text/javascript">
function validate(numbers) {
var sum;
var sum1;
var total;
for (i = 0; i < numbers.length; i++) {
if (numbers.length % 2 == 0) {
sum += numbers[i];
}
else
if ((numbers[i] * 2) >= 10) {
sum1 += numbers[i] - 9;
}
else
sum1 += numbers[i];
}
total = sum + sum1;
return total;
}
function cardnumber() {
var cardnumber = document.getElementById("input").value;
var numbers = cardnumber.split(" ");
var out = "";
for (i = 0; i < numbers.length; i++) {
out += validate(numbers[i]);
if (out % 10 == 0)
return true;
}
}
function getOutput() {
if (cardnumber()) {
alert("You card is valid.");
}
}
</script>
<body>
<h1>I will validate a credit card number</h1>
Card Type:
<input type="radio" id="c1" value="Visa">Visa</input>
Card number: <textarea id="input" style="vertical-align: middle;"></textarea></br>
<input type="button" value="Submit" onclick="getOutput()" /></br></br>
</body>
Your function validate is missing an opening curly brace after the for loop. This made your return statement outside of your function and since a return statement is invalid outside of a function it was an invalid return statement.
function validate(numbers){
var sum;
var sum1;
var total;
for (i=0; i<numbers.length; i++) { // this previous curly brace `{` was missing
if (numbers.length%2==0){
sum += numbers[i];
}
else
if ((numbers[i]*2)>=10){
sum1 += numbers[i] -9;
}
else
sum1 +=numbers[i];
}
total = sum + sum1;
return total;
}
EDIT WITH MORE CORRECTIONS:
There is quite a bit more wrong with the formatting of you functions you also need to include opening and closing curly braces around your other else statements. I would suggest getting a code editor like VS Code and downloading an extension similar to Bracket pair colorizer 2. It will highlight paired brackets together. This will help you with your formatting.
function validate(numbers){
var sum;
var sum1;
var total;
for (i=0; i<numbers.length; i++) {
if (numbers.length%2==0){
sum += numbers[i];
}
else {
if ((numbers[i] * 2) >= 10) {
sum1 += numbers[i] - 9;
}
else {
sum1 += numbers[i];
}
}
}
total = sum + sum1;
return total;
}
function cardnumber(){
var cardnumber= document.getElementById("input").value;
var numbers = cardnumber.split(" ");
var out ="";
for (i = 0; i < numbers.length; i++) {
out += validate(numbers[i]);
}
if (out %10==0)
return true;
}
function getOutput() {
if (cardnumber()) {
alert("You card is valid.");
}
}
These are all the changed lines (the left is new code and the right side is the old code):
Tips for completion
validate function
So, currently if you console.log your numbers are strings when they pass into the validate function. This is fine when they are sent into validate, but when you add the numbers at index i (i.e. numbers[i]) you should use parseInt(numbers[i], 10) to turn them into numbers, so for example sum += parseInt(numbers[i], 10); the same applies when adding to sum1. The other thing to note is that saying var sum will make sum equal the undefined value. When you add a number or string to an undefined value some unexpected things will probably happen, so since you need your sums and totals to be numbers you should instead initialize your sums and totals at 0. Like so:
var sum = 0;
var sum1 = 0;
var total = 0;
The only other thing wrong with your validate function is that your are checking if numbers.length%2==0 which instead you should be checking if i%2==0. You may have to think about why for a moment, but one thing you may notice is the length of numbers never changes during the iteration of the loop where as i does change at each step.
cardnumber function
Your out variable needs to be initialized to zero. Your cardnumber can instead be split by spaces and then joined by the empty string. This handles if the user accidentally types multiple spaces. Then since you join your split array you no longer would need a for loop.
var numbers = cardnumber.split(" ").join('');
var out =0;
out += validate(numbers);
Lines that need changing somehow
Here's a difference of the lines of the old code that where incorrect and need to be changed somehow. I'm not giving you the completed code, but hopefully this will be sufficient to help you figure out the rest on your own (I feel I shouldn't give you all of the solution due to some degree of academic integrity. I would feel I robbed you the opportunity to learn more if I don't at least let you think through and type it out on your own.). If you are wondering what needs to be changed on a specific line that is highlighted red all of it should be above, so best of luck.

Javascript Binary to Decimal Calculator

I have no idea why this code doesn't work, could anyone help:
toDecimal: function () {
var counter = 0;
var decimalValue = 0;
for (var i = 7; i > 0; i--){
var binaryValue = self.binaryArray[i];
decimalValue += binaryValue * Math.pow(2, counter);
counter++;
}
return decimalValue;
}
the code self.binaryArray is just an array of numbers (contains only 8, a byte, that's all i need to work with) something like this [0,0,0,0,1,1,1,1]
2nd'ly
Can you provide a slicker way of doing the counter, for the life of me I can't figure out how to calculate the counter from the i value, which shouldn't be too difficult, simple maths really.
Thanks
Your original loop never processes binaryArray[0]. As to a "slicker" way of doing things, assuming that binaryArray[0] is the most significant bit, I'd write your loop like this:
toDecimal: function () {
var decimalValue = 0;
for (var i = 0; i < 8; i++){
decimalValue = (decimalValue << 1) + self.binaryArray[i];
}
return decimalValue;
}
(The left shift is just a quick way of multiplying by 2.)
However, I like StephenH's suggestion:
toDecimal: function () {
return parseInt(self.binaryArray.join(''), 2);
}
Why not just use JavaScript's built in parseInt function?
Syntax: parseInt(string, radix);
var n = parseInt("10001",2);
n = 17

Javascript: Example of recursive function using for loops and substring - can't figure out where I'm going wrong

I'm currently working on coderbyte's medium challenge entitled "Permutation Step."
The goal is to take user input, num, and to return the next number greater than num using the same digits So, for example, if user input is 123, then the number 132 should be returned. If user input is 12453, then 12534 should be returned...
Anywho, I have a correct model answer created by someone (probably a genius, cuz this stuff is pretty hard) and I'm trying to figure out how the answer works, line for line by having an example play out (I'm keeping it simple and playing out the function with user input 123).
The answer has 2 functions, but the 1st function used is what I'm currently trying to work out...
The relevant code is:
var PermutationStep1 = function(num) {
var num1 = num.toString();
var ar = [];
//return num1;
if (num1.length < 2) {
return num;
} else {
for(var i = 0; i < num1.length; i++) {
var num2 = num1[i];
var num3 = num1.substr(0,i) + num1.substr(i+1, num1.length -1);
var numAr = PermutationStep1(num3);
for(var j = 0; j < numAr.length; j++) {
ar.push(numAr[j] + num2);
}
}
ar.sort(function(a,b) {return a-b});
return ar;
}
}
Again, I'm trying to work thru this function with the inputted num as 123 (num = 123).
I'm pretty sure that this function should output an array with multiple elements, because the 2nd function merely compares those array elements with the original user input (in our case, 123), and returns the next greatest value.
So in our case, we should probably get an array, named 'ar', returned with a host of 3 digit values. But for some reason, I'm getting an array of 2 digit values. I can't seem to isolate my mistake and where I'm going wrong. Any help with where, specifically, I'm going wrong (whether it be the recursion, the use of substring-method, or the concating of strings together, whatever my problem may be) would be appreciated...
Here's some of my work so far:
PS1(123) / num1 = 123
i = 0;
num2 = (num1[i]) = '1';
num3 = (num1.substr(0, 0) + num1.substr(1, 2)) = ('0' + '23') = '23'
PS1(23)
i = 0;
num2 = '2';
num3 = '3'
PS1(3) -> numAr = 3 (since num1 is less than 2 digits, which is the recursion base case?)
(So take 3 into the 2nd for loop)...
ar.push(numAr[j] + num2) = ar.push('3' + '1') = 31
ar = [31] at this point
And then I go through the initial for-loop a couple more times, where i = 1 and then i = 2, and I eventually get....
ar = [31, 32, 33]...
But I'm thinking I should have something like ar = [131, 132, 133]? I'm not sure where I'm going wrong so please help. Because the answer is correctly spit out by this function, the correct answer being 132.
Note: if you need the 2nd part of the model answer (i.e. the 2nd function), here it is:
var arr = [];
function PermutationStep(num1) {
arr.push(PermutationStep1(num1));
var arrStr = arr.toString();
var arrStrSpl = arrStr.split(",");
//return arrStrSpl;
for(var p = 0; p < arrStrSpl.length; p++) {
if(arrStrSpl[p] > num1) {
return arrStrSpl[p];
}
}
return -1;
}
I'm sorry the first function i posted was under a mathematical logical mistake and i was to overhasty
I thought about it again and now i have the following function which definitley works
function getNextNumber (num)
{
var numberStr=num.toString (), l=numberStr.length, i;
var digits=new Array (), lighterDigits, digitAtWeight;
var weight,lightWeight, lighterDigits_l, value=0;
for (i=l-1;i>-1;i--)
digits.push (parseInt(numberStr.charAt(i)));
lighterDigits=new Array ();
lighterDigits.push (digits[0]);
for (weight=1;weight<l;weight++)
{
digitAtWeight=digits[weight];
lighterDigits_l=lighterDigits.length;
for (lightWeight=0;lightWeight<lighterDigits_l;lightWeight++)
{
if (digitAtWeight<lighterDigits[lightWeight])
{
lighterDigits.unshift (lighterDigits.splice (lightWeight,1,digitAtWeight)[0]);
lighterDigits.reverse ();
digits=lighterDigits.concat (digits.slice (weight+1,l));
for (weight=0;weight>l;weight++)
value+=Math.pow (10,weight)*digits[weight];
return value;
}
}
lighterDigits.push (digitAtWeight);
}
return NaN;
}
okay here is my solution i found it in 20 minutes ;)
//---- num should be a Number Object and not a String
function getNextNumber (num)
{
var numberStr=num.toString (), l=numberStr.length, i;
var digits=new Array (), digitA, digitB;
var weight,lightWeight;
var valueDifference,biggerValue;
for (i=l-1;i>-1;i--)
digits.push (parseInt(numberStr.charAt(i))); // 345 becomes a0=5 a1=4 a2=3 and we can say that num= a0*10^0+ a1*10^1+ a2*10^2, so the index becomes the decimal weight
for (weight=1;weight<l;weight++)
{
digitA=digits[weight];
biggerValue=new Array ();
for (lightWeight=weight-1;lightWeight>-1;lightWeight--)
{
digitB=digits[lightWeight];
if (digitB==digitA) continue;
valueDifference=(digitA-digitB)*(-Math.pow(10,weight)+Math.pow (10,lightWeight));
if (valueDifference>0) biggerValue.push(valueDifference);
}
if (biggerValue.length>0)
{
biggerValue.sort();
return (biggerValue[0]+num);
}
}
}
this is the solution I figured out for the problem without using a recursive function. It's passed all the tests on coderbyte. I am still new to this so using recursion is not the first thing I look for. hope this can help anyone else looking for a solution.
function PermutationStep(num) {
var numArr = (num + '').split('').sort().reverse();
var numJoin = numArr.join('');
for (var i = (num + 1); i <= parseInt(numJoin); i++){
var aaa = (i + '').split('').sort().reverse();
if (aaa.join('') == numJoin){
return i;
}
}
return -1;
}

Javascript variable stays undefined

I have a problem with this script, something is going wrong.
Rnumer stays undefined.This script should return and write all uneven digits from the random number list. Can someone tell me what I do wrong. Thanks in advance
var Rnumber = new Array();
for (i = 0; i<= 100;i++)
{
Rnumber[i] = Math.ceil(Math.random()*101);
// document.write(Rnumber[i] + "<br/>");
}
function unevenAndDivisible(Rnumber)
{
var remainder = new Array();
for (i = 0; i<= 100; i++)
{
remainder = parseInt(Rnumber[i])%2;
}
return remainder;
}
document.write(unevenAndDivisible());
Changed to
var Rnumber = new Array();
for (i = 0; i<= 100;i++)
{
Rnumber[i] = Math.ceil(Math.random()*101);
// document.write(Rnumber[i] + "<br/>");
}
function unevenAndDivisible(Rnumber)
{
var remainder = new Array();
for (i = 0; i<= 100; i++)
{
remainder[i] = Rnumber[i]%2;
}
return remainder;
}
document.write(unevenAndDivisible(Rnumber));
but now i get the result :
0,1,0,0,1,0,0,0,1,1,0,0,1,0,1,1,1....
I simply want maybe I asked it wrong the first time, to write al uneven numbers from the random list of Rnumbers
Then I need to divide that through 7 and return that.
EDIT
Allmost all problems are clear , thanks everyone for that.
Their is still one question left:
In this code below it only take the first uneven value from remainder and I want that it takes all values that are uneven to the next if statement to check %7.
Maybe you see the problem better if you run it for youreself
var Rnumber = new Array();
for (i = 0; i<= 100;i++)
{
Rnumber[i] = Math.ceil(Math.random()*101);
}
function unevenAndDivisible()
{
var remainder = [];
var answer = [];
for (i = 0; i<= 100; i++)
{
if (Rnumber[i]%2 !== 0)
{
remainder.push(Rnumber[i]);
for (c = 0; c <= remainder.length;c++)
{
if (remainder[c]%7 == 0)
{
answer.push(remainder[c]);
}
}
}
}
return answer;
}
answer = unevenAndDivisible();
document.write(answer);
Problem solved , Thanks everyone
You don't need to pass Rnumber to the function, as it's already available in scope:
function unevenAndDivisible()
{
var remainder = [];
for (i = 0; i<= 100; i++)
{
if (Rnumber[i]%2 !== 0) {
remainder.push(Rnumber[i]);
}
}
return remainder;
}
remainder = unevenAndDivisible();
console.log(remainder);
JS Fiddle demo.
Edited in response to question from OP (in comments to question, above):
...can someone explain what this mean: var remainder = [];
Sure, it's array-literal notation, which is equal to: var remainder = new Array();, it's just a little more concise, and I prefer to save myself the typing. I get the impression, from JS Lint, whenever I use var x = new Array(); therein that the above version is generally preferred (since it complains otherwise), but I don't know why.
Either pass Rnumber to the function unevenAndDivisible or omit it from the argument list. Since it is an argument, it has more local scope than the initial declaration of Rnumber.
Your problem is the line
function unevenAndDivisible(Rnumber)
You are passing in Rnumber in as an argument, but when you call unevenAndDivisible()
you are not passing it it.
Consequently for the body of the function Rnumber is undefined (cause you passed nothing in)
The following snippet is equivalent to what you wrote nad might explain better
function unevenAndDivisible(xyz)
{
var remainder = new Array();
for (i = 0; i<= 100; i++)
{
remainder = parseInt(xyz[i])%2;
}
return remainder;
}
then called as
unevenAndDivisible(undefined)
to fix it remove the argument from the call definition
i.e. define it as
function unevenAndDivisible()
1 - you is not defining the Rnumber value that's function argument.
2 - in loop, you're defining remainder to divised value of ranumber and is not saving in array; try:
change:
remainder = parseInt(Rnumber[i])%2;
to
remainder[i] = parseInt(Rnumber[i])%2;
var array = [],
i = 100;
while (i--) {
var random = Math.random()*i|0;
if(random % 2)
array.unshift(random);
}
alert(array);

Using a round up JavaScript

I have this JavaScript below that add different fields. It works but does not round up the sum:
function Field2Value(aFields) {
var aValues = new Array(aFields.length);
for(i = 0; i < aFields.length; i++) {
aValues[i] = this.getField(aFields[i]).value;
}
return aValues;
} // end Field2Value
function SumArray(aValues) {
var sum = 0;
for(i = 0; i < aValues.length; i++) {
if(isNaN(aValues[i])) aValues[i] = 0;
sum += Number(aValues[i]);
}
return sum;
} // end SumArray
var myFields = new Array("AverageDiv", "AverageDiv1", "AverageDiv2",
"AverageDiv3", "AverageDiv4", "AverageDiv5", "AverageDiv6", "AverageDiv7",
"AverageDiv8", "AverageDiv9", "AverageDiv10", "AverageDiv11",
"AverageDiv12", "AverageDiv13");
event.value = SumArray( Field2Value(myFields) );
function Round(nValue, nDec) {
return Number(util.printf( "%,0 ." + Number(nDec) + "f", Number(nValue))) ;
}
I also have a script I want to use that will round up the sum of the average dividends but I do not know where to place this script in the script above.
Here is the rounding script:
function Round(nValue, nDec) {
return Number(util.printf( "%,0 ." + Number(nDec) + "f", Number(nValue))) ;
}
Please help.
The easiest way to round a number using Javascript is to use Math.round():
http://www.w3schools.com/jsref/jsref_round.asp
Edit - looking more closely, it looks like you're round to a set number of decimal places. You're using 'util.printf' - is that a library call? Does that function exist? That could be why your function is failing.
Put your code in a code block and it would be a lot easier to read.

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