I have lots of HTML generated on $(document).ready(). I have a simple window system. But not only it is generated on $(document).ready() - also some HTML elements (different JS files put stuff into $(document).ready() ). I want my window system to be generated after $(document).ready() is called. So how do I handle a function to be called after all the code registered in $(document).ready() is completed?
$(window).load(function(){
//some code after ready
});
There is another event which is fired later. it's $(window).load(); This is fired after all resources are loaded.
But perhaps you want this:
function loadWindowSystem(){
// load window system here
}
$(document).ready(function(){
// do some html stuff here
loadWindowSystem();
})
This way you can separate your code in functions.
I usually don't advocate using setTimeout, but you can build on top of #jfriend00's answer to create a more abstract approach:
$(document).ready(function() {
setTimeout(function() {
$(document).trigger('afterready');
}, 1);
});
$(document).bind('afterready', function() {
// call your code here that you want to run after all $(document).ready() calls have run
});
If you want something to fire right after all $(document).ready() calls, you can put this once anywhere in your page:
$(document).ready(function() {
setTimeout(function() {
// call your code here that you want to run after all $(document).ready() calls have run
}, 1);
});
This will get called along with all the other document.ready calls, but it sets a short timeout that will execute after all the other document.ready calls have finished.
By adding another handler function ones the document is ready, the
handler will almost certainly be last one in the ready event queue. Effectively giving you an instant "post" ready handler function.
$(document).ready(function() {
$(document).ready(function() {
// code to run "after" ready
});
});
$(document).ready
When multiple functions are added via successive calls to this method, they run when the DOM is ready in the order in which they are added.
Note that this will only work as long as no ones else uses this "trick".
there is nothing after this function , so if you have some ajax loaders, only think you can do is to wait for all of them and then start rendering
EDIT But i wonder why you dont just structuralize your code to eliminate this.
$(document).ready() is called just after the DOM has finished loading.
pageLoad() is called next on a 0 timer, but beware it is run after every partial postback.
Edit: Added side note - this will only count if using ASP.NET, the pageLoad functionality mentioned is separate from jQuery. See more info Here
You can use
$(window).on('load', function () {
alert("Window Loaded");
});
$(window).load(function(){
alert("Window Loaded");
}
has been removed from jQuery.
Related
The live function of jQuery is triggered with an event
The api documentation is here
http://api.jquery.com/live/
$(".xyz").live('event', function(){
});
I want the above function to run without an event , i.e as soon as the class xyz is dynamically created.
I have tried this without the event parameter
$(".xyz").live( function(){
});
but it doesn't work !!
adding
I don't know exactly what you want to do, but I'll make assumptions.
Scenario 1
In order to execute a function inside jQuery, you need to tell jQuery when to execute the function, otherwise it cannot know. One way to do this is:
$(document).ready(function () {
$('.xyz').css('color', 'red');
// more code, anything, functions, calculations, etc.
});
The code inside that function will be executed as soon as your DOM is ready (is safe to manipulate).
You can put $('.xyz').css('color', 'red'); also outside the ready() event and it will also be executed. The "event" this time is when the executions of the page reaches that line of code. For example, if you put this line before your HTML, you don't have guarantee it will work.
Scenario 2 - onClassChange event
If you are looking for an event called something like onClassChange, it does not exits on jQuery. An approach to that problem could be this:
Create a timer which runs infinitely
On each run, check if that object has your class ( $(obj).hasClass('xyz') )
If yes, do whatever you want to do inside the if ()
Also, since you said the class xyz is created dynamically, you can try to run your function immediately after you create your class in your code.
For more about onClassChange event, there are long discussions you can check on this site.
If I have some code like this:
jQuery(document).ready(function() {
jQuery('body').on('mouseup', '.some-div', function(e){
});
});
Is it possible to trigger the mouseup event outside the (document).ready()
with
jQuery('.some-div').mouseup();
or should I write this code
jQuery('body').on('mouseup', '.some-div', function(e){
});
as a function outside the (document).ready()?
I don't think dependency matters as much as loading order of the whole file. $(document).ready ensures that jQuery waits to execute the main function until
the page Document Object Model (DOM) is ready for JavaScript code to
execute.
Code outside this ready block might (be tried to) run before the page is actually ready. For instance, let's say this is code that's in the head of your page:
<script>
jQuery(document).ready(function() {
jQuery('body').on('mouseup', '.some-div', function(e){
});
});
jQuery('.some-div').mouseup();
</script>
The ready block will wait, as described above, but the mouseup trigger will try to fire, but it can't. The DOM isn't ready yet, which means .some-div can't be found yet - and thus, the trigger can't be activated.
To improve the chances that DOM is ready, you can try to load your jQuery before the closing </body> tag. The ready block can stay in the head, but the trigger should then move to the end of the document to improve the likelihood that the DOM is ready (which it normally should at that stage). For an interesting read on where to place script tags, also see this highly popular post.
jQuery('.some-div').mouseup(callback); writing this outside of document ready does not ensure document is ready before event is being attached to a document element. It may happen jQuery('.some-div') is not there before we are trying to access and attach an event listener.
jQuery(function() {
jQuery('body').on('mouseup', '.some-div', function(e){
});
is equivalent to
jQuery(document).ready(function() {
jQuery('body').on('mouseup', '.some-div', function(e){
});
});
Both the ways are good to ensure availability of dom elements before access.
Once the event is attached you can trigger any time. But you should always make sure document is ready.
Once .ready() is executed and event is binded, you can call it outside of that function.
Yes it's possible to trigger mouseup outside $.ready() using
jQuery('.some-div').mouseup();
But remember to call it after $.ready gets executed. In practice it requires another $.ready handler or just the invocation in the same one at the end.
Try this :
$(document).on('mouseup','.some-div',function(){
//code there
});
What are differences between
$(document).ready(function(){
//my code here
});
and
$(window).load(function(){
//my code here
});
And I want to make sure that:
$(document).ready(function(){
})
and
$(function(){
});
and
jQuery(document).ready(function(){
});
are the same.
Can you tell me what differences and similarities between them?
$(document).ready(function() {
// executes when HTML-Document is loaded and DOM is ready
console.log("document is ready");
});
$(window).load(function() {
// executes when complete page is fully loaded, including all frames, objects and images
console.log("window is loaded");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Query 3.0 version
Breaking change: .load(), .unload(), and .error() removed
These methods are shortcuts for event operations, but had several API
limitations. The event .load() method conflicted with the ajax .load()
method. The .error() method could not be used with window.onerror
because of the way the DOM method is defined. If you need to attach
events by these names, use the .on() method, e.g. change
$("img").load(fn) to $(img).on("load", fn).1
$(window).load(function() {});
Should be changed to
$(window).on('load', function (e) {})
These are all equivalent:
$(function(){
});
jQuery(document).ready(function(){
});
$(document).ready(function(){
});
$(document).on('ready', function(){
})
document.ready is a jQuery event, it runs when the DOM is ready, e.g. all elements are there to be found/used, but not necessarily all the content.
window.onload fires later (or at the same time in the worst/failing cases) when images and such are loaded. So, if you're using image dimensions for example, you often want to use this instead.
Also read a related question:
Difference between $(window).load() and $(document).ready() functions
These three functions are the same:
$(document).ready(function(){
})
and
$(function(){
});
and
jQuery(document).ready(function(){
});
here $ is used for define jQuery like $ = jQuery.
Now difference is that
$(document).ready is jQuery event that is fired when DOM is loaded, so it’s fired when the document structure is ready.
$(window).load event is fired after whole content is loaded like page contain images,css etc.
From the jQuery API Document
While JavaScript provides the load event for executing code when a
page is rendered, this event does not get triggered until all assets
such as images have been completely received. In most cases, the
script can be run as soon as the DOM hierarchy has been fully
constructed. The handler passed to .ready() is guaranteed to be
executed after the DOM is ready, so this is usually the best place to
attach all other event handlers and run other jQuery code. When using
scripts that rely on the value of CSS style properties, it's important
to reference external stylesheets or embed style elements before
referencing the scripts.
In cases where code relies on loaded assets (for example, if the
dimensions of an image are required), the code should be placed in a
handler for the load event instead.
Answer to the second question -
No, they are identical as long as you are not using jQuery in no conflict mode.
The Difference between $(document).ready() and $(window).load() functions is that the code included inside $(window).load() will run once the entire page(images, iframes, stylesheets,etc) are loaded whereas the document ready event fires before all images,iframes etc. are loaded, but after the whole DOM itself is ready.
$(document).ready(function(){
})
and
$(function(){
});
and
jQuery(document).ready(function(){
});
There are not difference between the above 3 codes.
They are equivalent,but you may face conflict if any other JavaScript Frameworks uses the same dollar symbol $ as a shortcut name.
jQuery.noConflict();
jQuery.ready(function($){
//Code using $ as alias to jQuery
});
$(document).ready(function(e) {
// executes when HTML-Document is loaded and DOM is ready
console.log("page is loading now");
});
$(document).load(function(e) {
//when html page complete loaded
console.log("completely loaded");
});
The ready event is always execute at the only html page is loaded to the browser and the functions are executed....
But the load event is executed at the time of all the page contents are loaded to the browser for the page.....
we can use $ or jQuery when we use the noconflict() method in jquery scripts...
$(window).load is an event that fires when the DOM and all the content (everything) on the page is fully loaded like CSS, images and frames. One best example is if we want to get the actual image size or to get the details of anything we use it.
$(document).ready() indicates that code in it need to be executed once the DOM got loaded and ready to be manipulated by script. It won't wait for the images to load for executing the jQuery script.
<script type = "text/javascript">
//$(window).load was deprecated in 1.8, and removed in jquery 3.0
// $(window).load(function() {
// alert("$(window).load fired");
// });
$(document).ready(function() {
alert("$(document).ready fired");
});
</script>
$(window).load fired after the $(document).ready().
$(document).ready(function(){
})
//and
$(function(){
});
//and
jQuery(document).ready(function(){
});
Above 3 are same, $ is the alias name of jQuery, you may face conflict if any other JavaScript Frameworks uses the same dollar symbol $. If u face conflict jQuery team provide a solution no-conflict read more.
$(window).load was deprecated in 1.8, and removed in jquery 3.0
I've my jQuery code as
$('#tarea').click(function() {
// Do stuffs
});
This works fine for the button #tarea loaded along with this script. If the button #tarea had been loaded using ajax in future, than the above code doesn't work.
Now I changed the code to
$('#tarea').live('click', function() {
// Do stuffs
});
This time, the button #tarea if loaded along with the script doesn't work. But the script works with the button if generated using ajax.
How do I write the script so that in both cases, it works??
.live() works in both cases without doing anything additional to what you have already done. I would check for some other problems in your code that might be preventing this from happening.
Important: One thing to check is to make sure that your .live() event is being bound and that it doesn't rely on some other event happening. It might help to post the important parts of you JavaScript file. Personally I like to declare my .live() events globally.
I do something like this:
// this is what I mean by global because it is outside the document.ready
$("#test").live("click", function() {
// do stuff
});
$(function() {
// do stuff when document is ready
});
If you want to prove what I said above, you only need to put the button and the .live() JavaScript code in a new HTML file.
You put :
$('#tarea').click(function() {
// Do stuffs
});
in a function.
And when you load via ajax, you add a callback function (the one above) in second parameter of .load()
For example :
.load(target_url, function() { $('#tarea').click(function() { blablabla; }})
I'm using some external jQuery with $(document).ready() to insert adverts after the document ready event has fired, something like:
$(document).ready( function() {
$('#leaderboard').html("<strong>ad code</strong>");
});
This is to prevent the UI being blocked by the slow loading of the adverts. So far it's been working well.
Now I need to insert some more ads though our CMS system, this can't be part of the external JS file, so I'm wondering can I use a second document ready event and insert it using an inline script tag? If so, what will be the order of execution the external JS document ready event first or the inline script?
You can use as many event methods as you want, jquery joins them in a queue. Order of method call is same as definition order - last added is last called.
A useful thing may be also that, you can load html code with script using ajax and when code is loaded into DOM $().ready() also will be called, so you can load ads dynamically.
Yes, adding multiple $(documents).ready()s is not a problem. All will be executed on the ready event.
Note however that your code sample is wrong. $(document).ready() takes a function, not an expression. So you should feed it a function like this:
$(document).ready( function() {
$('#leaderboard').html("<strong>ad code</strong>");
});
That function will be executed when the document is ready.
Here's a little tutorial on Multiple Document Ready
An added bonus of the jQuery way is
that you can have multiple ready()
definitions. This is the case with all
jQuery events.
$(document).ready(function () {
alert("Number One"); });
$(document).ready(function () {
alert("Number Two");
JQuery calls the ready functions in the order they are defined.
If you want to load some data first and deleay execution use holdReady().