Develop Reference

How would I go about changing the contents of a div after the user searches?

So I have this form:
<form method="post" action="index.php" id="searchform">
<input type="text" name="search" placeholder="Search...">
<input type="image" src="img/img1.png" alt="submit" onmouseover="hover(this);" onmouseout="unhover(this);" /></a>
</form>
When the user searches for something I want to change this div:
<div class = "mainText">
<h2>Today's Events: </h2>
</div>
To say this:
<div class = "mainText">
<h2>Results: </h2>
</div>
How can I do this?
EDIT: Is it possible to run this code from within a php if statement?

jquery .text() seems a better fit, so you can just change the text of the tag.
$(".mainText h2").text("Results:");
More on this here:
http://www.w3schools.com/jquery/html_text.asp

The action in your form is the destination of where your form ends up.
If you are looking to control the dom elements you need something like javascript or jquery to control the front end of your application.
You could use jquery to simply listen for when your user has clicked the button or submitted the form and parse the results (in this case, just switching html text). *Remove the the action destination otherwise the page will redirect to index.php
$('form').submit(function(){
$('.mainText').html('<h2>Results: </h2>');
return false;
});
Common usage is to put an ajax call in the submit function to retrieve some data from outside the page source. Hopefully that puts you on track :)

Submitting a Form using Selenium in Python

I need to scrape some data behind those hyperlinks from this Site. However, those hyperlinks are javascript function calls, which later submits a form using post method. After some search, selenium seems to be a candidate. So my question is that how should I properly set a value to an input tag and submit the form which does not a submit a button.
from selenium import webdriver
url = "http://www.echemportal.org/echemportal/propertysearch/treeselect_input.action?queryID=PROQ3h3n"
driver = webdriver.Firefox()
driver.get(url)
treePath_tag = driver.find_element_by_name("treePath")
Before submitting the form, I need to assign value to tag <input>. However, I got an error
Message: Element is not currently visible and so may not be interacted
with
treePath_tag.send_keys('/TR.SE00.00/QU.SE.DATA_ENV/QU.SE.ENV_ENVIRONMENT_DATA/QU.SE.EN_MONITORING')
IF above is correct, I would like to submit form this way. Is it correct?
selenium.find_element_by_name("add_form").submit()
Below are sources from the web page.
JavaScript function
<script type="text/javascript">
function AddBlock(path){
document.add_form.treePath.value=path;
document.add_form.submit();
}
</script>
form "add_form"
<form id="addblock_input" name="add_form" action="/echemportal/propertysearch/addblock_input.action" method="post" style="display:none;">
<table class="wwFormTable" style="display:none;"><tr style="display:none;">
<td colspan="2">
<input type="hidden" name="queryID" value="PROQ3h1w" id="addblock_input_queryID"/> </td>
</tr>
<tr style="display:none;">
<td colspan="2">
<input type="hidden" name="treePath" value="" id="addblock_input_treePath"/> </td>
</tr>
</table></form>
div with javascript call
<div id="querytree">
<h1>Property Search</h1>
<h2>Select Query Block Type</h2>
<p>Select a section for which to define query criteria.</p>
<div class="queryblocktools"><img style="vertical-align:top;" alt="Load" src="/echemportal/etc/img/load.gif"/> Load Query</div>
<ul class="listexpander">
<li>Physical and chemical properties<ul>
<li>Melting point/freezing point</li>
<li>Boiling point</li>
</ul>
</div>

You are trying to set value on hidden input is which not visible on the page, that's why error has occurred. If you want to set value on hidden field try using execute_script as below :-
treePath_tag = driver.find_element_by_name("treePath")
driver.execute_script('arguments[0].value = arguments[1]', treePath_tag, '/TR.SE00.00/QU.SE.DATA_ENV/QU.SE.ENV_ENVIRONMENT_DATA/QU.SE.EN_MONITORING')
After setting value on hidden field you can use following to submit the form :-
selenium.find_element_by_name("add_form").submit()
Hope it helps..:)

How to open Custom pop on click of Button?

I am having a scenario when I am clicking on a button then one pop-up must be opened asking "Do you want to perform this operation". There are two button OK and Cancel. And on pressing any of there button control must go i controller and do required task.
After doing google, I find one way using windows.open but i cannot apply my css on this and there is no particular url for this. So this did not worked.
I have tried that when the page load a div having this data should hide and after clicking it must shown but this is not giving felling of popup.
<body onload="hide()">
<center>
<script>
function hide() {
document.getElementById("show").style.visibility = "hidden";
}
function show() {
document.getElementById("show").style.visibility = "visible";
}
</script>
<div id="form">
<form method="get">
<div id="show">Demo</div>
<table>
<tr>
<td></td>
<td><a id="dialog-link" href="">
<button type="button" value="Show Pop up"
onclick="show()">Click</button>
</a></td>
</tr>
</table>
</form>
</div>
</center>
</body>

i think you need confirmation box:
function show() {
confirm("do your operation!");
}

My guess:
1. Add style "display:none", that will hide your element in DOM.
2. Change that attribute using JS.
<body onload="hide()">
<center>
<script>
function hide() {
document.getElementById("show").style.display = 'none';
}
function show() {
document.getElementById("show").style.display = 'block';
}
</script>
<div id="form">
<form method="get">
<div id="show" style="display: none;">Demo</div>
<table>
<tr>
<td></td>
<td><a id="dialog-link" href=""><button type="button"
value="Show Pop up" onclick="show()">Click</button></a></td>
</tr>
</table>
</form>
</div>
</center>
</body>
Here is a similar topic:
javascript hide/show element
If you want something more than a confirm modal, something with more css, I would go into bootstrap, because creating a modal window from scratch can be sometimes hard, and bootstrap gives you free API for that. But it will require jQuery in your app.

Cross browser solution for submit buttons outside form

I am basically trying to implement this
http://www.impressivewebs.com/html5-form-attribute/
I have a cart which is outputting and sandwiched by a html table. Below the table, I currently have my submit button.
<thead>
<tr>
<th>ITEM</th>
<th>PRICE</th>
<th>WEIGHT (Kg)</th>
<th>QTY</th>
<th>SUBTOTAL</th>
<th></th>
</tr>
</thead>
<tbody>
<form action='shop.php' id='cart' method='post'>
<?php echo $cartOutput; ?>
</form>
<tr>
<td class="totals"><strong>Total</strong></td>
<td class="totals"> </td>
<td class="totals"><?php if (isset($weightTotal)) { echo $weightTotal . 'kg';} ?> </td>
<td class="totals"><?php if (isset($quantityTotal)) { echo $quantityTotal; } ?></td>
<td class="totals"><strong><?php if (isset($cartTotal)) { echo '$' . $cartTotal; } ?></strong></td>
<td class="totals"></td>
</tr>
</tbody>
/* code finishing table here */
<div class="col-lg-12 col-md-12 col-xs-12 remove-padding">
<button type="submit" class="btn btn-default" form="cart" name="adjustButton" id="adjust-button">UPDATE CART</button>
<button type="button" class="btn btn-default" form="contact" name="order" id="order-button" onclick="confirmOrder()" >ORDER NOW</button>
</div>
So because of the way I want the layout to look.. I can't put the buttons inside the form. I want to have the ability to put the update button below the cart.
Right now the order button is not a submit button but just a button. I can put it beneath its own form section but right now I force it through javascript for a confirmation and then submit the request through JS if they say OK.
I want to keep that function while supporting browsers including IE 9 +10. From what I found form="" doesn't work in IE
Can I achieve this?

Put the form tag outside all 'relevant' content (including submit button(s)):
<body>
<form>
<table>
</table>
<div>
<button>
</button>
</div>
</form>
</body>
If the button cannot be inside the form, make the form outside the
button.

This should work in all browsers:
document.getElementById('cart').submit();
You can put that in the onClick, and wrap it in a function if needed.
Edit: Since the issue (per the comments below) is that you have inputs outside the form: Really the simplest solution, and one that involves no Javascript, is to put the </form> at the end of the page (so that all your inputs and buttons will be in the form). But of course this doesn't work if you need to have more than one form on the page, and it might not even be possible depending on how the page is layed out.

If your submit button is outside the form and you have some input elements outside the form then the simplest way to send this form (without using ajax) would be to make a form and put your submit button in it.
And since your input fields are outside the form you will make a copy of those input fields inside your form and hide them with display:none; and when user changes the value of your visible input fields you will use javascript to change the value of the hidden input field.
This way you get to send the form the usual way, without the input fields having to be inside the form itself.....

You could copy the outside form elements to inside the form and sync them using JS.
http://jsfiddle.net/rudiedirkx/y0cmda4o/
if ( !('fform' in document.createElement('input')) ) {
$('input[fform], textarea[fform], select[fform]').on('change', function(e) {
this.$hidden.val(this.value);
}).each(function(i, el) {
var formId = $(el).attr('fform'),
$form = $('#' + formId),
$hidden = $('<input name="' + el.name + '" type="hidden">');
$form.append($hidden);
el.$hidden = $hidden;
});
}
As you can see, I used the fform attribute, to trigger the if statement. Change it to form and try it in IE.
Disclaimer:
This won't work with multiple value elements (like select[multiple]), or you have to add some serious JS to fake those multiple values.
This won't send the triggered button value. Normal submit buttons send only their value, and not the other submit buttons'. You could maybe add an onclick to handle that... If you use it.

Is Wordpress hijacking my Ajax form post?

I'm new to Wordpress and new to JQuery, so let me start off explaining what I am trying to do.
I have an admin page, inside this page I'm giving the user the ability to upload an image. I want this done using Ajax (independent from the general form update).
Here is the code I have so far:
At top of page - script includes:
<script type="text/javascript"
src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script src="http://malsup.github.com/jquery.form.js">
I can confirm these scripts are "pingable" and work.
Now the HTML code :
<table width="100%">
<tr>
<td width="100" style="padding:10px" valign="top">Email Image (180x180):</td>
<td style="padding:10px"><img id="previewEmailImage" width=180 height=180>
</td>
</tr>
<tr>
<td></td>
<td>
<div id='emailpreviewloader'>
</div>
</td>
</tr>
<tr>
<td></td>
<td>
<form id="imageform" method="post" enctype="multipart/form-data" action="/ajaximage.php">
<input type="file" name="photoimg" id="photoimg" />
</form>
</td>
</tr>
</table>
The key things in the HTML is a) a form and b) The div emailpreviewloader.
Now just after the html table, inline I have the following js:
<script type="text/javascript">
$(document).ready(function()
{
$('#photoimg').live('change', function()
{
$("#emailpreviewloader").html('');
$("#emailpreviewloader").html('<img width="180" src="/loader.gif" alt="Uploading...."/>');
$("#imageform").ajaxForm(function(result)
{
alert("Thank you for your comment!");
});
});
});
</script>
for testing purposes ajaximage.php just contains 1 line: Echo "It worked";
So assuming I've done my job right, and the html + js above is correct, it would seem Wordpress might be hijacking the Ajax somehow and preventing it from working as expected. Is this possible?
All I want to do is have a regular Ajax post, how is this possible?
EDIT:
What is working:
The change event for the file upload control is firing. I've confirmed this with an alert, and the loader.gif is visible. But it would seem the form isn't firing, or not firing correctly. The inner alert, never fires.

If you don't want to use wordpress's functions for ajax calls, try sending the form to action="<?php bloginfo('template_url');?>/ajaximage.php" and make sure the file is in the root of your wordpress instalation.