Develop Reference

keep properties after jquery.load

I'm learning javascript/jquery on the go, I'm trying to reload a form but keeping its js properties (required and masked inputs), code and pictures attached.
First image: Masked inputs works like a charm
Second image: The form its fully filled, still working
Third image: The form it reloaded, but no properties applied
The html form (minmized, just the first field)
<div class="card-body" id="clientsAddFormContainer">
<form method="post" action="main/clients/addController.php">
<div class="form-group row" id="clientRutDiv">
<div class="col-lg-6">
<div class="form-group" id="clientRutInnerDiv">
<label class="col-form-label" for="clientRut">RUT <span class="required">*</span></label>
<input type="text" name="clientRut" id="clientRut" class="form-control" placeholder="Ej. 11.111.111-1" required="" data-plugin-masked-input="" data-input-mask="99.999.999-*" autofocus>
</div>
</div>
</div>
</div>
</form>
<footer class="card-footer">
<div class="switch switch-sm switch-primary">
<input type="checkbox" name="wannaStay" id="wannaStay" data-plugin-ios-switch checked="checked" />
</div> Mantenerme en esta página
<button type="button" style="float: right;" class="btn btn-primary" onclick="realizaProceso();">Enviar</button>
</footer>
The JS for realizaProceso()
function realizaProceso(){
var validator =0;
validator += validateRequiredField('clientRut');
if(validator == 0){
var parametros = {
"clientRut" : document.getElementById('clientRut').value,
"tableName" : 'clients'
};
$.ajax({
data: parametros,
url: 'route/to/addController.php',
type: 'post',
success: function (respText) {
if(respText == 1){
if(document.getElementById('wannaStay').checked){
$("#clientsAddFormContainer").load(location.href + " #clientsAddFormContainer");
}else{
window.location = "linkToOtherLocation";
}
}else{
showNotyErrorMsg();
}
},
error: function () {
showNotyErrorMsg();
}
});
}else{
showNotyValidationErrorMsg();
}
}
So my JS check all fields are validated, then prepare the array, and wait for the php binary response, 1 means the data has been inserted to db, if wannaStay is checked reload the div "clientsAddFormContainer" but as I said, it loose the properties.
Please sorry for my grammar or any other related english trouble, not a native english speaker.
Ps. I've removed some code so it could go different than the images.
Thanks in advance!
EDIT!
The original code is
<div class="card-body" id="clientsAddFormContainer">
<form method="post" action="main/clients/addController.php">
</form>
</div>
one the js exec I got
<div class="card-body" id="clientsAddFormContainer">
<div class="card-body" id="clientsAddFormContainer">
<form method="post" action="main/clients/addController.php">
</form>
</div>
</div>
2nd EDIT
I found the answer in other stackoverflow question

Ajax form not submitting form rails

I'm using a super basic google form on my website. I'm using this website to extract the HTML to display it on my website - http://stefano.brilli.me/google-forms-html-exporter/
Once I hit submit, nothing happens. The page is just locked. I'm trying to resubmit it to another page. Here is my code
<div class="row">
<form action="https://docs.google.com/forms/d/e/1FAIpQLSfJQ9EkDN8aggSL9AEB2PK4BGiZgBzLDbS1IPppfSkU1zy-oA/formResponse"target="_self" id="bootstrapForm" method="POST">
<div class="col-sm-6 col-md-3">
<input id="679075295" type="text" name="entry.679075295" class="form-control" >
</div>
<div class="col-sm-6 col-md-3">
<input id="897968244" type="text" name="entry.897968244" class="form-control" >
</div>
<div class="col-sm-6 col-md-3">
<input id="685661947" type="text" name="entry.685661947" class="form-control" >
</div>
<input id="503500083" type="hidden" name="entry.503500083" value="<%= #investment.id %>" >
<div class="col-sm-6 col-md-3">
<button type="submit" value"submit" class="btn btn--primary type--uppercase" >Get Started</button>
</div>
</form>
Here is the ajax script
<script>
$('#bootstrapForm').submit(function (event) {
event.preventDefault()
var extraData = {}
$('#bootstrapForm').ajaxSubmit({
data: extraData,
dataType: 'jsonp', // This won't really work. It's just to use a GET instead of a POST to allow cookies from different domain.
error: function () {
// Submit of form should be successful but JSONP callback will fail because Google Forms
// does not support it, so this is handled as a failure.
alert('Form Submitted. Thanks.')
// You can also redirect the user to a custom thank-you page:
window.location = 'http://reif.com.au/thankyou'
}
})
})
</script>
</div>

Feeling a little silly on this one. Essentially i didn't copy over all of the scripts. I was rushing through.. ALWAYS number 1 error!
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.2.1/jquery.min.js" integrity="sha256-hwg4gsxgFZhOsEEamdOYGBf13FyQuiTwlAQgxVSNgt4=" crossorigin="anonymous"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery.form/4.2.2/jquery.form.min.js" integrity="sha256-2Pjr1OlpZMY6qesJM68t2v39t+lMLvxwpa8QlRjJroA=" crossorigin="anonymous"></script>
This is what i needed to add, it now successfully submits and redirects!

How to make php content appear in a html div element

I am trying to create a search using ajax and mysql and placing the returned data into a div. I am following a tutorial on youtube and so far so good, however I am trying to pass in dummy data into the div but it isn't appearing.
This here is my jquery
$('#submit').on('click', function() {
var search = $('#search').val();
if ($.trim(search) != '') { //if search is not equal to nothing - using trim allows users to type in blank space and it won't return anything
$.post('searching.php', {search: search}, function(data) {
$('#search').text(data);
});
}
});
This is my html
<div class="container">
<div class="card card-container">
<p id="profile-name" class="profile-name-card"></p>
<form class="form-signin" method="POST">
<input type="text" name="search" id="search" class="form-control" placeholder="Search">
</form><!-- /form -->
<button class="btn btn-lg btn-primary btn-block btn-signin" value= "search" type="required" id="submit" name="submit">Search</button>
</div><!-- /card-container -->
<div class="row">
<div class="col-md-4">
<div id="search"></div>
<div class="caption">
<p></p>
</div>
</div>
When the user clicks search the content from the searching.php file should appear in the div. Currently in the searching.php file it just has echo"content";. It should have "content" in the div but it isn't appearing in the web browser and there are no errors. Within the network in inspect element the name is searching.php and the status is ok. Not sure where I am going wrong, any help would be grateful.

You have multiple id="search" elements in your HTML. So this isn't going to know which one you mean:
$('#search')
It's probably trying to set the "text" of the <input>, which doesn't have a "text" (it has a "value"). Correct the HTML. Either change the <input> or the <div> to have a unique id. (And, of course, update your jQuery selectors as well as anything else targeting these elements.)

don't use same id (search) for both input and div
change the id in html
<div class="container">
<div class="card card-container">
<p id="profile-name" class="profile-name-card"></p>
<form class="form-signin" method="POST">
<input type="text" name="search" id="search" class="form-control" placeholder="Search">
</form>
<button class="btn btn-lg btn-primary btn-block btn-signin" value= "search" type="required" id="submit" name="submit">Search</button>
</div><!-- /card-container -->
<div class="row">
<div class="col-md-4">
<div id="searchText"></div>
<div class="caption">
<p></p>
</div>
</div>
and javascript
$('#submit').on('click', function() {
var search = $('#search').val();
if ($.trim(search) != '') { //if search is not equal to nothing - using trim allows users to type in blank space and it won't return anything
$.post('searching.php', {search: search}, function(data) {
$('#searchText').text(data);
});
}
});

.text not work with input
use val() instead of text() for input
$('#search').val(data);
$("#btn1").click(function(){
$("#test1").text("Hello world!");
});
$("#btn2").click(function(){
$("#test2").html("<b>Hello world!</b>");
});
$("#btn3").click(function(){
$("#test3").val("Dolly Duck");
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p id="test1">This is a paragraph.</p>
<button id="btn1">Set Text</button>
<p id="test2">This is another paragraph.</p>
<button id="btn2">Set HTML</button>
<p>Input field: <input type="text" id="test3" value="Mickey Mouse"></p>
<button id="btn3">Set Value</button>

How to validate a form's input from ajax page using jquery

There are two inputs in my form. The first input can be validated before an ajax function. The second input can't be validated. The second input comes from a page using ajax and the submit button also comes from the page using ajax. I need to validate the second input which comes from the page using ajax. Also the submit button which comes from the page is not working. Please help me.
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("#form").submit(function(){
if ($('#Name1').val().length<3) {
alert ("please enter your first names");
$('#Name1').focus();
return false;
}
$.ajax({
url: "result.php",
method: "GET" // Either get or post
}).done(function(response) {
var splitted = response.split("|"); // RESULT
$("#Div1").html(splitted[0]); // The first name
$("#Div2").html(splitted[1]); // The first name
});
return (false);
if ($('#Name2').val().length<3) {
alert ("please enter your second names");
$('#Name2').focus();
return false;
}
});
});
</script>
</head>
<body>
<form id="form" action="Page.php">
<div style="float:left;">
<b>Name1:</b>
</div>
<input id="Name1" type="text">
<br><br><br><br>
<div style="clear:both;">
<div style="float:left;">
<b>Name2:</b>
</div>
<div id="Div1" style="float:left;">
</div>
<br><br><br>
<div style="clear:both;">
<div id="Div2">
<button>First Event</button>
</div>
</div>
</div>
</form>
</body>
</html>
This is result.php
<input type="text" id="Name2">
i need to validate this input. | <button>Second Event</button>

There's a few ways you can do this, however because I am on my phone I can't give you a detailed example.
What I recommend for you to look into is sending the AJAX request as JSON data to your PHP file, you can then validate the JSON data within the PHP file and return a response to the front end accordingly.
Within the PHP file you can return any value as a response, meaning that if you echo "success" or "true", you can see whether the data is what you are looking to receive from the user.
I would highly recommend doing as much validation possible in the back end. It is a good habit to get in to as anything can be manipulated on the front end of a website.

This code works well. i have solved myself.
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<script>
$(document).ready(function(){
$("#form").submit(function(){
if ($('#Name1').val().length<3) {
alert ("please enter your first names");
$('#Name1').focus();
return false;
}
if ($('#hidden').val().length<3) {
$.ajax({
url: "result.php",
method: "GET" // Either get or post
}).done(function(response) {
var splitted = response.split("|"); // RESULT
$("#Div1").html(splitted[0]); // The first name
$("#Div2").html(splitted[1]); // The first name
});
//alert ("please verify");
return false;
}
if ($('#Name2').val().length<3) {
alert ("please enter your second names");
$('#Name2').focus();
return false;
}
});
});
</script>
</head>
<body>
<form id="form" action="Page.php">
<div style="float:left;">
<b>Name1:</b>
</div>
<input id="Name1" type="text">
<br><br><br><br>
<div style="clear:both;">
<div style="float:left;">
<b>Name2:</b>
</div>
<div id="Div1" style="float:left;">
<input id="hidden" type="hidden">
</div>
<br><br><br>
<div style="clear:both;">
<div id="Div2">
<button>First Event</button>
</div>
</div>
</div>
</form>
</body>
</html>
result.php
<input type="hidden" id="hidden" value="something"> <input type="text" id="Name2"> | <input id="button" type="submit" value="Second Event">

Error sending a form via AJAX

I am very new to jQuery and I'm looking for an explanation as to why this code does not seem to work. I think it is something with the "action" not sure. Can someone help me understand my mistake here. thanks
<script src="/jquery.validationEngine.js"></script>
<script>
$("#contact_body").submit(function(e) {
e.preventDefault(); // Prevents the page from refreshing
var $this = $(this); // `this` refers to the current form element
if ($("#contact_body").validationEngine('validate')) {
//Post Data to Node Server
$.post(
$this.attr("action"), // Gets the URL to sent the post to
$this.serialize(), // Serializes form data in standard format
function(data) { /** code to handle response **/ },
"json" // The format the response should be in
);
//Notify User That the Email Was Sent to the Server & Thanks!
//$('#contactThanksModal').modal('show');
$('#contactModal').modal('hide');
alert("success");
}
else {
//handle Invalid Email Format Error
alert("error");
}
});
</script>
<!--pop up contact form -->
<div id="contact" class="modal hide fade in" style="display: none;">
<div class="modal-header">
<a class="close" data-dismiss="modal">x</a>
<h3>Send us a message</h3>
</div>
<div class="modal-body">
<form id="contact_body"class="contact_body" name="contact_body" action="/contact">
<label class="label" for="form_name">Your Name</label><br>
<input type="text" name="form_name" id="form_name" class="input-xlarge"><br>
<label class="label" for="form_email">Your E-mail</label><br>
<input type="form_email" name="form_email" class="input-xlarge"><br>
<label class="label" for="form_msg">Enter a Message</label><br>
<textarea name="form_msg" class="input-xlarge"></textarea>
</form>
</div>
<div class="modal-footer">
<input class="btn btn-success" type="submit" value="Send!" id="submit">
Nah.
</div>
<!-- <div id="thanks"><p><a data-toggle="modal" href="#contact" class="btn btn-primary btn-large">Modal powers, activate!</a></p></div> -->

You need to wrap your JQuery scripts in a
$(document).ready(function() {
...your_code_here...
});
This will then wait for the whole document to load before trying to attach events to objects.
Without this you may be trying to bind events to objects that have yet to be "created".

You need to put your code in a document ready handler:
<script src="/jquery.validationEngine.js"></script>
<script>
$(function() {
$("#contact_body").submit(function(e) {
// your code...
});
});
</script>
Your code is currently trying to add the submit() handler before the element exists in the DOM.