Do while mouseover , do other thing while mouseout - javascript

I saw this code in another question , I thought I might make it work for an image too, but since I am a newbie in jquery, I didn't do much.
Here is the code:
$('someObject').bind('mouseover', function() {
//Do the following while mouseover
$('someOtherObject').css('margin-left',adjustedLeft + 'px');
setTimeout(/*do it again*/,25);
});
I saw it in this question right here:
An "if mouseover" or a "do while mouseover" in JavaScript/jQuery
There is an example below it also, but that one works for text fields.
I want mine to work for images, basically i have 2 images one over another and i want to make a fading effect, so something like
while mouseover , every 0,01sec , lower the opacity by 0.01 ,till 0,01
the moment the mouse leaves the image(button) , stop lowering the opacity and start heightening it again by 0.01 every 0.01sec till 0.99 opacity
Just to be clear again , i got 2 images(buttons) 1 above the other , i want to lower and then heighten the opacity of the upper button.
Also i saw another type of fade , but the 2 buttons were on 1 image , but for me(the newbie) its too advanced i guess, but i might look at that , its a nice way to use less images i guess.
Just in case , here is the link to the example too : http://jsfiddle.net/YjC6y/29/

$('someObject').mouseover(function() {
$('someOtherObject').animate({
opacity: 0
})
}).mouseout(function() {
$('someOtherObject').animate({
opacity: 0.99
})
});

Use jquery hover http://api.jquery.com/hover/someObject
$('someObject').hover(
function () {
// Set the effect you want when mouse is over the element
},
function () {
// Set the effect for mouse leave
}
);
Hope this help :)

Related

Creating a sliding image gallery that does not glitch on image change

I have created a sliding image gallery and when the button is pushed it slides the picture across and updates the image attribute for the relevant sections.
However this works perfectly like 50% of the time. The other times there is a second glitch and the images then go in place as expected.
I have attached the javascript methods for the animate method and the array change method. I have looked elsewhere and cannot see anyone else with a similar issue or where I am going wrong, especially when it doesn't happen often.
imageGallery.leftSelect.onclick = function () {
window.setTimeout(imageGallery.rightClick, 250);
imageGallery.animateImages('.image1', '.imageRight');
imageGallery.animateImages('.imageRight', '.imageNoneRight');
imageGallery.animateImages('.imageLeft', '.image1');
imageGallery.animateImages('.imageNoneLeft', '.imageLeft');
};
animateImages: function (classFrom, classTo) {
var classMoving = $(classFrom);
var classGoingTo = $(classTo);
classMoving.animate({
top: classGoingTo.css('top'),
left: classGoingTo.css('left'),
width: classGoingTo.css('width'),
opacity: classGoingTo.css('opacity'),
}, 258, function () {
console.log('Animated');
classMoving.css({"width":'', "opacity":'', "top":'', "left":'', });
});
},
rightClick: function () {
imageGallery.imagesDisplay.push(imageGallery.imagesDisplay.shift());
imageGallery.imageNoneLeft.setAttribute('src', imageGallery.imagesDisplay[2]);
imageGallery.imageLeft.setAttribute('src', imageGallery.imagesDisplay[1]);
imageGallery.imageMain.setAttribute('src', imageGallery.imagesDisplay[0]);
imageGallery.imageRight.setAttribute('src', imageGallery.imagesDisplay[10]);
imageGallery.imageNoneRight.setAttribute('src', imageGallery.imagesDisplay[9]);
},
Can someone assist, I really need this to work?
If there is anything not clear or you need more code let me know.
Thanks,
First things first, the culprit was the setAttribute of all images i.e. whatever you were doing inside the rightClick and leftClick functions were the reasons why you were seeing a glitch. Changing src of an img tag produces the glitch.
But then we cannot simply remove it because your approach relies heavily on this swapping of images.
I had to breakdown and really understand your approach first. The way it worked was that you would animate, for example, image1 (the centered one) to move to the position of imageLeft upon click on the rightCarousel button. On that same click, you had a setTimeout of almost the duration of the animation to call rightClick function. This rightClick function then swaps the images so that image1 can always remain at the center and only images can come and go after animation. This was the problem.
What I had to change was that all image tags i.e. imageNoneLeft, imageLeft, image1, imageRight & imageNoneRight would change each others classes such that their position remains changed after animations.
Also, I had to add another animateImages line inside your leftSelect and rightSelect callbacks to animate the furthest images i.e. imageNoneLeft & imageNoneRight to animate to each other's positions with respect to the click of the buttons.
Take a look at this jsFiddle. It will help you understand a lot better. And let me know if you have any questions.
JavaScript:
var imageGallery={
prefix:'https://dl.dropboxusercontent.com/u/45891870/Experiments/StackOverflow/1.5/',
imagesDisplay:['JS.jpg','PIXI.jpg','GSAP.jpg','JS.jpg','PIXI.jpg','GSAP.jpg','JS.jpg','PIXI.jpg','GSAP.jpg','JS.jpg','PIXI.jpg'],
rightSelect:document.querySelector('.rightCarousel'),
leftSelect:document.querySelector('.leftCarousel'),
imageMain:document.querySelector('.image1'),
imageLeft:document.querySelector('.imageLeft'),
imageRight:document.querySelector('.imageRight'),
imageNoneLeft:document.querySelector('.imageNoneLeft'),
imageNoneRight:document.querySelector('.imageNoneRight'),
init:function(){
imageGallery.imagesDisplay.push(imageGallery.imagesDisplay.shift());
imageGallery.imageNoneLeft.setAttribute('src',imageGallery.prefix+imageGallery.imagesDisplay[2]);
imageGallery.imageLeft.setAttribute('src',imageGallery.prefix+imageGallery.imagesDisplay[1]);
imageGallery.imageMain.setAttribute('src',imageGallery.prefix+imageGallery.imagesDisplay[0]);
imageGallery.imageRight.setAttribute('src',imageGallery.prefix+imageGallery.imagesDisplay[10]);
imageGallery.imageNoneRight.setAttribute('src',imageGallery.prefix+imageGallery.imagesDisplay[9]);
},
animateImages:function(classFrom,classTo){
var classMoving=$(classFrom);
var classGoingTo=$(classTo);
classMoving.animate({
top:classGoingTo.css('top'),
left:classGoingTo.css('left'),
width:classGoingTo.css('width'),
opacity:classGoingTo.css('opacity')
},258,function(){
$(this).removeClass(classFrom.substr(1));
$(this).addClass(classTo.substr(1));
$(this).removeAttr('style');
});
}
};
imageGallery.init();
imageGallery.leftSelect.onclick=function(){
imageGallery.animateImages('.imageNoneRight','.imageNoneLeft');
imageGallery.animateImages('.imageRight','.imageNoneRight');
imageGallery.animateImages('.image1','.imageRight');
imageGallery.animateImages('.imageLeft','.image1');
imageGallery.animateImages('.imageNoneLeft','.imageLeft');
};
imageGallery.rightSelect.onclick=function(){
imageGallery.animateImages('.imageNoneLeft','.imageNoneRight');
imageGallery.animateImages('.imageLeft','.imageNoneLeft');
imageGallery.animateImages('.image1','.imageLeft');
imageGallery.animateImages('.imageRight','.image1');
imageGallery.animateImages('.imageNoneRight','.imageRight');
};

Run two functions in the exact same time

I want to slideUp() a div, and when its sliding up, I want to move it down by animate() - in the exact same time .
what I have done so far :
ln = jQuery("Selector");
ln.slideUp(1500, function() {
ln.animate({top: '150px'}, 'slow');
var Html = jQuery('#last' + id1).html() + jQuery('#last' + id2).html();
ln.html(Html);
});
But it slides up first, and then moves down 150px.
I want to call these two functions (slideUp and animate ) in the exact same time, I want to know is it possible or not?
Or does my problem have an easier way to solve ?
P.S : I think this kind of questions has been asked before, like this, but Its not my answer if you read it completely.
You can do this by using .animate() for both operations and just specifying both changes with properties that you pass to animate. The slideup can be done by specifying a final height of 0 for animate. Using this single animation, jQuery will run both changes together as part of the same animation sequence.
ln.animate({top: '150px', height: 0}, 'slow');
Working demo: http://jsfiddle.net/jfriend00/kKsa4/

How do I stop a bouncy JQuery animation?

In a webapp I'm working on, I want to create some slider divs that will move up and down with mouseover & mouseout (respectively.) I currently have it implemented with JQuery's hover() function, by using animate() and reducing/increasing it's top css value as needed. This works fairly well, actually.
The problem is that it tends to get stuck. If you move the mouse over it (especially near the bottom), and quickly remove it, it will slide up & down continuously and won't stop until it's completed 3-5 cycles. To me, it seems that the issue might have to do with one animation starting before another is done (e.g. the two are trying to run, so they slide back and forth.)
Okay, now for the code. Here's the basic JQuery that I'm using:
$('.slider').hover(
/* mouseover */
function(){
$(this).animate({
top : '-=120'
}, 300);
},
/* mouseout*/
function(){
$(this).animate({
top : '+=120'
}, 300);
}
);
I've also recreated the behavior in a JSFiddle.
Any ideas on what's going on? :)
==EDIT== UPDATED JSFiddle
It isn't perfect, but adding .stop(true,true) will prevent most of what you are seeing.
http://jsfiddle.net/W5EsJ/18/
If you hover from bottom up quickly, it will still flicker because you are moving your mouse out of the div causing the mouseout event to fire, animating the div back down.
You can lessen the flicker by reducing the delay, however it will still be present until the delay is 0 (no animation)
Update
I thought about it and realized that there is an obvious solution to this. Hoverintent-like functionality!
http://jsfiddle.net/W5EsJ/20/
$(document).ready(function() {
var timer;
$('.slider').hover(
/* mouseover */
function(){
var self = this;
timer = setTimeout(function(){
$(self).stop(true,true).animate({
top : '-=120'
}, 300).addClass('visible');
},150)
},
/* mouseout*/
function(){
clearTimeout(timer);
$(this).filter(".visible").stop(true,true).animate({
top : '+=120'
}, 300).removeClass("visible");
}
);
});
You could use .stop() and also use the outer container position
$(document).ready(function() {
$('.slider').hover(
/* mouseover */
function(){
$(this).stop().animate({
top : $('.outer').position().top
}, 300);
},
/* mouseout*/
function(){
$(this).stop().animate({
top : $('.outer').position().top + 120
}, 300);
}
);
});
​
DEMO
Hope this helps
Couldn't reproduce your issue but I believe that hover is getting called multiple times. To work around this you can check if the div is already in animation. If yes, then don't run another animation again.
Add following piece of code to check if the div is already 'animating':
if ($(this).is(':animated')) {
return;
}
Code: http://jsfiddle.net/W5EsJ/2/
Reference:http://api.jquery.com/animated-selector/
I understand the problem and reproduced it, it happens when hovering from the bottom up. The hovering with the mouse is what's causing the problem since the animation function will be called when the mouse hovers over the image. You need to control what happens here by using mouse enter and mouse leave, check out a similar example: Jquery Animate on Hover
The reason it's like that is because the hover is getting queued up causing it to slide up and down multiple times. There's a plug-in called hoverIntent which fixes the issue. http://cherne.net/brian/resources/jquery.hoverIntent.html
If you do decide to use hoverIntent, the only thing you have to change in your code is .hover > .hoverIntent

Animate a div after scrolling away from the top of the webpage

I'm currently trying to make a div appear from behind another div after the user scrolls away from the top of the page.
I'm hoping to do this using animate so that it slides out. Like this...
http://jsfiddle.net/xaYTt/99/
But I can't figure out how to make the red box stay behind the blue box until the user scrolls away from the top of the page.
I also need to reverse this when the user scrolls back up to the top of the page, so the red box slides back under the blue box again.
Can anyone help me out?
This is not the most elegant solution, but it works nonetheless.
http://jsfiddle.net/37LZ5/
Components:
Use $(document).scroll as a trigger to know when scrolling
Use scrollTop() to know how far we're scrolling (0 = top)
Remember state to make sure animation doesn't get triggered a zillion times (var away)
Use .stop() to prevent weird behaviour when halfway through one animation, another animation gets triggered
I think you are looking for this take a look at this demo
Working demo
Code
$(document).ready(function(){
//$('#bottom-box').animate({'margin-top': '200px'}, 1500);
$('body').hover(function(){
$('#bottom-box').animate({'margin-top': '200px'}, 1500);
}, function(){
$('#bottom-box').animate({'margin-top': '50px'}, 1500);
});
});
If my understanding about your question is correct, this is what you are looking for
Since you said, "User scrolls away from the top of the page", I added a div to be at the top of the page.
var isAlreadyOut=false;
$("#divPageTop").mouseover(function(){
if( isAlreadyOut==true)
{
$('#bottom-box').animate({'margin-top': '60px'}, 1500);
isAlreadyOut=false;
}
else
{
$('#bottom-box').animate({'margin-top': '200px'}, 1500);
isAlreadyOut=true;
}
});
Here is the jsfiddle version
http://jsfiddle.net/xaYTt/103/
I did something with jsFiddle that might be what you are after, if I understood your question correctly.
Basically, the red box will animate when you scroll the window more than the distance of the blue box.
Not 100%, just a quick mock up to see if that's what you want.
(When you scroll, click on the scroll bar arrows for more accurate results)
Demo here: http://jsfiddle.net/peduarte/xaYTt/104/

Jquery - fadeIn/fadeOut flicker on rollover

I am using the following code to acheive a fadeIn/fadeOut effect on rollover/rollout of it's parent div.
$('.rollover-section').hover(function(){
$('.target', this).stop().fadeIn(250)
}, function() {
$('.target', this).stop().fadeOut(250)
})
It works correctly when I rollover the div and out slowly. However if I move my mouse over and then off the div quickly, it breaks the effect. The target div seems to get stuck at an opacity between 0 and 1.
What confuses me is that when I use the following code it works perfectly.
$('.rollover-section').hover(function(){
$('.target', this).stop().animate({
opacity: 1
}, 250);
}, function() {
$('.target', this).stop().animate({
opacity:0
}, 250);
})
So, I have two questions.
1 - why is my first code block behaving as it does?
2 - What is the difference between fadeIn()/fadeOut() and animating the opacity?
As it was stated already it's because those modify the css and change the display to none. By using fadeTo you can get the same effect, but it doesn't modify the css, so it should work correctly.
update example: http://jsfiddle.net/TFhzE/1/
you can also do
$('.rollover-section').hover(function() {
$('.target', this).stop().fadeTo(0,250);
}, function() {
$('.target', this).stop().fadeTo(250,0,function(){$(this).hide();});
});
to completely hide it yourself once it actually is complete.
I've put my answer from the comments here:
Just use the animate example you have there. Check here for an answer to why the fade animation behaves the way it does:
jQuery fade flickers

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