Returning the method of a function - javascript

In the code below, I've got two objects declared, with one object inheriting the properties and functions of another.
I want to use the super variable to call the methods of the object I inherited from. When I trace out itemEditor, I can see the function and it's methods correctly. When I try to access the method of itemEditor, it returns undefined.
What am I doing wrong? Is there a better way to do this?
var myObject = {
itemEditor : function (vars) {
this.editItem = function () {
alert("Editing Item");
}
},
recurringItemEditor : function (vars) {
myObject .itemEditor.apply(this, [vars]);
this.prototype = myObject.itemEditor.prototype;
var super = myObject.itemEditor
this.editItem = function () {
console.log("fn.recurringItemEditor.editItem");
console.log(super);
console.log(super.editItem);
super.editItem.call(this);
}
}

Your code seems a little confused. On the one hand myObject.itemEditor is a constructor and therefore a function (myObject.itemEditor.apply(this, [vars])), and on the other you treat it like an object with a prototype (this.prototype = myObject.itemEditor.prototype;).
That's not even considering that super is a reserved keyword.
Your example may be simplifying something you are trying to do, but I don't see why you don't just use the usual prototype inheritance. That way you can still have a method in your local instance and call the prototype one within it if you want e.g.
recurringItemEditor : function (vars) {
this.prototype = new myObject.itemEditor(vars);
this.editItem = function () {
console.log("fn.recurringItemEditor.editItem");
console.log(this.prototype);
console.log(this.prototype.editItem);
this.prototype.editItem.call(this);
}
}

I used your advice and it works well now. In regards to treating it like a function and an object, myObject .itemEditor.apply(this, [vars]); was still required in order for the object to inherit the properties of itemEditor. I should have made that clear in the original code. If there's a better way to do this, let me know.
var myObject = {
itemEditor : function (vars) {
var myVars = vars + "foo";
this.editItem = function () {
alert(myVars);
}
},
recurringItemEditor : function (vars) {
myObject .itemEditor.apply(this, [vars]);
this.prototype = new myObject.itemEditor(vars);
this.editItem = function () {
console.log("fn.recurringItemEditor.editItem");
console.log(this.prototype);
console.log(this.prototype.editItem);
this.prototype.editItem.call(this);
}
}
}

Related

JS OOP outside prototype function call ( scope )

I'm new to OOP, and I'm writing a simple game script to learn the OOP principles.
//main game function
battleLevel.prototype =
{
battle:function () {
this.obj1 = {
enterMonsterMenu: function() {
return console.log('enterMonsterMenu');
}
};
},
} /* end OOP prototype */
//external contructor
var Hero = function (warpX, warpY, game, name, life, mana, speed) {
//some code
};
Hero.prototype.monsterSelectUp = function() {
console.log('monsterSelectUp');
//this.enterMonsterMenu();
battleLevel.prototype.battle.call(obj1);
};
I want to access enterMonsterMenu() method by calling the monsterSelectUp() but I can't call it properly. What I am doing wrong ?
It looks like you didn't get the concepts right, try to re-read at least this short intro.
Let's try to look what happens in the line where you are trying to call "enterMonsterMenu".
Here it is:
battleLevel.prototype.battle.call(obj1);
The battleLevel.prototype is an object you defined first.
The battleLevel.prototype.battle is a function and you execute it's "call" method (because functions are also objects in js and have functions like "call").
What does "function.call" method? It calls the function with given this value.
For example,
var myObject = { name: "Object 1" };
var yourObject = { name: "Object 2" };
function test() {
alert(this.name);
}
test.call(myObject); //alert Object 1
test.call(yourObject); //alert Object 2
In your code, you are trying to call the battleLevel.prototype.battle and passing the obj1 as this.
But at that point of code there is no obj1 variable defined, so you just call the battle method with undefined variable.
Moreover, even if you passed the defined variable, you would not call the enterMonsterMenu function anyway. Because your method only adds the obj1 property to the this object:
battleLevel = {}
battleLevel.prototype =
{
battle:function () {
this.obj1 = {
enterMonsterMenu: function() {
alert('enterMonsterMenu');
}
};
},
}
var myThis = {"property": "value"};
alert(JSON.stringify(myThis)); // {"property": "value"};
// This call will add "obj1" property to myThis
battleLevel.prototype.battle.call(myThis);
alert(JSON.stringify(myThis)); // {"property": "value", "obj1": {}};
// now call the 'enterMonsterMenu'
myThis.obj1.enterMonsterMenu();
You can see above how you can actually call your enterMonsterMenu, but to be honest, I see no point in doing things like this. And, as I said, you probably need to spend more time on learning the concepts.

Making JavaScript private methods accessible to its public methods

I understand there are couple of patterns to make JavaScript 'class-like'.
I would like to take the 'extending by prototype' way... simply because it looks more neat. I am not worried about performance much here...
In the below example I have a class (basically function) MetricsChart. I have couple of public methods and one private method (basically a reusable method).
Here from the public method (drawOrAdd) I can't access the private method (_convertArrayToTable), how can I do that?
function MetricsChart(containerId, chartType) {
this._container = document.getElementById(containerId);
this._chartType = chartType;
this._isChartDrawn = false;
this._chartData = null;
var _convertArrayToTable = function (data) {
return google.visualization.arrayToDataTable(data);
}
}
MetricsChart.prototype.drawOrAdd = function(data)
{
if (!this.isChartDrawn()) {
var chart = new google.visualization.LineChart(this._container);
if (chart) {
var table = _convertArrayToTable(data);
console.log(table);
this._isChartDrawn = true;
}
}
}
MetricsChart.prototype.isChartDrawn = function () {
return this._isChartDrawn;
}
MetricsChart.prototype.getChartData = function () {
}
One way I accidentally found was to enclose the public methods inside the MetricsChart class itself...
It works for me :): I can access the public methods outside and the public method can access the private method (serves the purpose).
Below code... Is this right? Am I doing anything wrong?
function MetricsChart(containerId, chartType) {
this._container = document.getElementById(containerId);
this._chartType = chartType;
this._isChartDrawn = false;
this._chartData = null;
var _convertArrayToTable = function (data) {
return google.visualization.arrayToDataTable(data);
}
MetricsChart.prototype.drawOrAdd = function (data) {
if (!this.isChartDrawn()) {
var chart = new google.visualization.LineChart(this._container);
if (chart) {
var table = _convertArrayToTable(data);
console.log(table);
this._isChartDrawn = true;
}
}
}
MetricsChart.prototype.isChartDrawn = function () {
return this._isChartDrawn;
}
MetricsChart.prototype.getChartData = function () {
}
}
So, here a couple of things, in order to understand what you have done precisely.
First of all:
function foo() {
var i = 0;
function bar() {
return true;
}
}
What's happening here: every time the function foo is called, it creates in its scope a new variable i, and a new function bar. The function bar and the variable i are in its scope, it means they're local: there is no way, with this code, to access to either i or bar outside the function foo. Also because, once the function foo is terminated, both i and bar are disposed.
So, this is why you cannot access from your "public" method to the "private" one, and I hope it's more clear now. The only way for a function to access to a function or variable is that there is a reference shared in the same scope. So, this is what you have done in your last example: you define your "public" methods in the same scope where you define your "private" method. In this way they can access each other. However, the way you have done, has a big downside. As I said previously, the function bar is created every time the function foo is called. In a "class" example, it means:
function MyClass() {
function myprivate() {}
MyClass.prototype.mypublic = function () { return myprivate() }
}
It means that every time you're creating an instance of MyClass, you're creating two new functions, and you're rewrite all the time the prototype of your "class". This is far from be a good approach. In fact, if you have something like:
var a = new MyClass();
var _mypublic = a.mypublic;
var b = new MyClass();
console.log(_mypublic === b.mypublic) // false
console.log(_mypublic === a.mypublic) // false too!
So, you guess right but you executed wrong. What you need here is a the "module pattern": nowadays you can use CommonJS module in nodejs or AMD in browser and so on, but the basic idea is defined a "scope" and exports from this scope only what you want. In your case, you could have:
// this is your "module"
;(function(exports) {
// your local (private) function
var _convertArrayToTable = function (data) {
return google.visualization.arrayToDataTable(data);
}
function MetricsChart(containerId, chartType) {
this._container = document.getElementById(containerId);
this._chartType = chartType;
this._isChartDrawn = false;
this._chartData = null;
}
MetricsChart.prototype.drawOrAdd = function(data) {
if (!this.isChartDrawn()) {
var chart = new google.visualization.LineChart(this._container);
if (chart) {
var table = _convertArrayToTable(data);
console.log(table);
this._isChartDrawn = true;
}
}
}
// you decided to exports to the main scope what you want
exports.MetricsChart = MetricsChart;
}(this)); // here `this` is the global object
And that's it. You have created a closure, using the "module pattern", and from the "public" method you can access to the "private" function, because they're defined in the same scope. But because you do not do that in the "class" constructor, you don't redefine them every time you instantiate a new object. Therefore, the previous example written in this way, will give the right result:
var a = new MyClass();
var _mypublic = a.mypublic;
var b = new MyClass();
console.log(_mypublic === b.mypublic) // true
console.log(_mypublic === a.mypublic) // true
What you've done isn't necessarily "wrong"...it just looks weird. Also, you won't be able to access "MetricsChart.prototype.*" until after you've created an instance of "MetricsChart". Depending on how you are using this object, it may not matter.
That being said, another way is to keep your original structure, but move the following outside of the constructor:
var _convertArrayToTable = function (data) {
return google.visualization.arrayToDataTable(data);
}
It would still be private to your module which should be good enough (you are using modules right?).
What you have done works perfectly.
You can't inherit private methods in any OOP language in terms of overriding them or accessing them directly. They are private. So it makes no sense to have them prototyped for inheritance purposes. You have wrapped them in function scope so they are as "private" as they need to be.
To access the private methods use privilege methods. Check this document: http://javascript.crockford.com/private.html.
About your code check this answer:
Setting javascript prototype function within object class declaration
p.s.
function Test()
{
var p = function(pv)
{
//
}
this.e = function (ap) { p(ap) }
}
var n = new Test();
n.e("e"); // It is legal call
n.p(); // will throw
But if you declare a private function in c-tor it will be executed on first creation of object of this type. When declare a methods in prototype this methods are add before any code execution. In general the browser first check the js file to collect all methods for prototype and than execute any code. So when you declare a prototype methods into c-tor this methods will be available only after first creation of the object of those type. ( Sorry for my English ).
Check this situation:
function Test()
{
alert(this.ST_A);//alert undefined
alert(this.ST_B);//alert 2
Test.prototype.ST_A = 1;
alert( this.ST_A)//alert 1
}
Test.prototype.ST_B = 2;
In first pass the browser will populate Test with ST_B and ST_B will be available anywhere any time. After than in second pass the browser will start to execute the code in this time ST_A will not be visible until the browser execute the Test.prototype.ST_A = 1;

javascript class inherit from Function class

I like that in javascript, I can create a function, and then add further methods and attributes to that function
myInstance = function() {return 5}
myInstance.attr = 10
I would like to create a class to generate these objects. I assume I have to inherit from the Function base class.
In other words, I would like to:
var myInstance = new myFunctionClass()
var x = myInstance()
// x == 5
But I don't know how to create the myFunctionClass. I have tried the following, but it does not work:
var myFunctionClass = function() {Function.call(this, "return 5")}
myFunctionClass.prototype = new Function()
myInstance = new myFunctionClass()
myInstance()
// I would hope this would return 5, but instead I get
// TypeError: Property 'myInstance' of object #<Object> is not a function
I also tried the more complicated (and more proper?) inheritance method found here: How to "properly" create a custom object in JavaScript?, with no more luck. I have also tried using the util.inherits(myFunctionClass, Function) found in node.js. Still no luck
I have exhausted Google, and therefore feel that I must be missing something fundamental or obvious. Help would be greatly appreciated.
Your trying to inherit from Function. This is a right pain to do. I suggest you do the following instead
Live Example
var Proto = Object.create(Function.prototype);
Object.extend(Proto, {
constructor: function (d) {
console.log("construct, argument : ", d);
this.d = d;
// this is your constructor logic
},
call: function () {
console.log("call", this.d);
// this get's called when you invoke the "function" that is the instance
return "from call";
},
method: function () {
console.log("method");
// some method
return "return from method";
},
// some attr
attr: 42
});
You want to create a prototype object that forms the basis of your "class". It has your generic methods/attributes. It also has a constructor that gets invoked on object construction and a call method that gets invoked when you call the function
var functionFactory = function (proto) {
return function () {
var f = function () {
return f.call.apply(f, arguments);
};
Object.keys(proto).forEach(function (key) {
f[key] = proto[key];
});
f.constructor.apply(f, arguments);
return f;
}
}
A function factory takes a prototype object and returns a factory for it. The returned function when called will give you a new function object that "inherits" from your prototype object.
var protoFactory = functionFactory(proto);
var instance = protoFactory();
Here you create your factory and then create your instance.
However this isn't proper prototypical OO. we are just shallow copying properties of a prototype into a new object. So changes to the prototype will not reflect back to the original object.
If you want real prototypical OO then you need to use a hack.
var f = function () {
// your logic here
};
f.__proto__ = Proto;
Notice how we use the non-standard deprecated .__proto__ and we are mutating the value of [[Prototype]] at run-time which is considered evil.
JS does not allow a constructor to return a function, even though functions are objects. So you cant have an instantiation of a prototype that is itself executable. (Am I right in this? please correct if I'm not, it's an interesting question).
Though you could do a factory function:
var makeCoolFunc = function() {
var f = function() { return 5 };
f.a = 123;
f.b = 'hell yes!'
return f;
};
var func = makeCoolFunc();
var x = func();
You can extend Function and pass the wanted function body as String to the super constructor. The context of the function can be accessed with arguments.callee.
Example for an observable Attribute class:
export default class Attribute extends Function {
constructor(defaultValue){
super("value", "return arguments.callee.apply(arguments);");
this.value = defaultValue;
this.defaultValue = defaultValue;
this.changeListeners = [];
}
apply([value]){
if(value!==undefined){
if(value!==this.value){
var oldValue = this.value;
this.value=value;
this.changeListeners.every((changeListener)=>changeListener(oldValue, value));
}
}
return this.value;
}
clear(){
this.value=undefined;
}
reset(){
this.value=this.defaultValue;
}
addChangeListener(listener){
this.changeListeners.push(listener);
}
removeChangeListener(listener){
this.changeListeners.remove(listener);
}
clearChangeListeners(){
this.changeListeners = [];
}
}
Example usage:
import Attribute from './attribute.js';
var name= new Attribute();
name('foo'); //set value of name to 'foo'
name.addChangeListener((oldValue, newValue)=>{
alert('value changed from ' +oldValue+ ' to ' +newValue);
});
alert(name()); //show value of name: 'foo'
name('baa'); //set value of name to new value 'baa' and trigger change listener

Javascript apply — Inheriting classes

The code below is adapted from this answer
function MessageClass() {
var self = this;
this.clickHander = function(e) { self.someoneClickedMe = true; };
var _private = 0;
this.getPrivate = function() { return _private; };
this.setPrivate = function(val) { _private = val; };
}
ErrorMessageClass.prototype = new MessageClass();
function ErrorMessageClass() {
MessageClass.apply(this, arguments);
}
var errorA = new ErrorMessageClass();
var errorB = new ErrorMessageClass();
errorA.setPrivate('A');
errorB.setPrivate('B');
console.log(errorA.getPrivate());
console.log(errorB.getPrivate());
The original post did not have the MessageClass.apply(this, arguments); since the purpose was to show how inheritance can go wrong in Javascript.
My question is, is saying: ErrorMessageClass.prototype = new MessageClass(); before the ErrorMessageClass constructor has even been declared bad practice? My understanding is that calling undeclared identifiers like that causes a silent declaration to occur, with the result being placed on the global window object, which I understand is bad.
Is this form:
function ErrorMessageClass() {
MessageClass.apply(this, arguments);
}
ErrorMessageClass.prototype = new MessageClass();
considered to be better practice? This link shows the code written as it was originally above, which is why I even tried it. Does this blogger know something I don't (quite likely)?
EDIT
Lots of great info in the answers below, but I did want to highlight this link which really explains things perfectly
Usually, to avoid this confusion, you would just attach the prototype after, but as Adam Rackis pointed out, function declarations are hoisted, like var statements.
However, you should not instantiate the base object as the prototype. If your base object takes arguments, what are you supposed to use? Use an empty "surrogate" constructor
// Used to setup inheritance
function surrogate () {};
function MessageClass() {
var self = this;
this.clickHander = function(e) { self.someoneClickedMe = true; };
var _private = 0;
this.getPrivate = function() { return _private; };
this.setPrivate = function(val) { _private = val; };
}
// The key steps to creating clean inheritance
surrogate.prototype = MessageClass;
// Sets up inheritance without instantiating a base class object
ErrorMessageClass.prototype = new surrogate();
// Fix the constructor property
ErrorMessageClass.prototype.constructor = ErrorMessageClass
function ErrorMessageClass() {
MessageClass.apply(this, arguments);
}
There's much more to be said. http://js-bits.blogspot.com/2010/08/javascript-inheritance-done-right.html
It works because function declarations are evaluated first. If you tried to move these classes under an object literal "namespace" the first version would fail.
I personally find the second method to be much easier to read - also, don't forget to set the sub-class' prototype.constructor property back to itself. Personally, I use an inherits() method on the Function prototype which wraps up essentially the type of code you're using here.

Encapsulation in javascript

I need to create simple reusable javascript object publishing several methods and parameterized constructor. After reading through several "OOP in JavaScript" guides I'm sitting here with an empty head. How on the Earth can I do this?
Here my last non-working code:
SomeClass = function(id) {
this._id = id;
}
(function() {
function intFun() {
return this._id;
}
SomeClass.prototype.extFun = function() {
return incFun();
}
})();
This is my usual approach:
MyClass = function(x, y, z) {
// This is the constructor. When you use it with "new MyClass(),"
// then "this" refers to the new object being constructed. So you can
// assign member variables to it.
this.x = x;
...
};
MyClass.prototype = {
doSomething: function() {
// Here we can use the member variable that
// we created in the constructor.
return this.x;
},
somethingElse: function(a) {
}
};
var myObj = new MyClass(1,2,3);
alert(myObj.doSomething()); // this will return the object's "x" member
alert(myObj.x); // this will do the same, by accessing the member directly
Normally the "this" keyword, when used in one of the object's methods, will refer to the object itself. When you use it in the constructor, it will refer to the new object that's being created. So in the above example, both alert statements will display "1".
An exception to this rule is when you pass one of your member functions somewhere else, and then call it. For example,
myDiv.onclick = myObj.doSomething;
In this case, JavaScript ignores the fact that "doSomething" belongs to "myObj". As a result, the "this" inside doSomething will point to another object, so the method won't work as expected. To get around this, you need to specify the object to which "this" should refer. You can do so with JavaScript's "call" function:
myDiv.onclick = function() {
myObj.doSomething.call(myObj);
}
It's weird, but you'll get used to it eventually. The bottom line is that, when passing around methods, you also need to pass around the object that they should be called on.
I usually don't worry too much about hiding the internals, although I do prefix them with underscores to mark them as not intended to be used outside the "class". Normally what I will do is:
var MyClass = function() {};
MyClass.prototype = {
_someVar : null,
_otherVar : null,
initialize: function( optionHash ) {
_someVar = optionsHash["varValue"];
_otherVar = optionsHash["otherValue"];
},
method: function( arg ) {
return _someVar + arg;
},
};
And use it as so...
var myClass = new MyClass( { varValue: -1, otherValue: 10 } );
var foo = myClass.method(6);
All vars are private:
SomeClass = function (id) {
var THIS = this; // unambiguous reference
THIS._id = id;
var intFun = function () { // private
return THIS._id;
}
this.extFun = function () { // public
return intFun();
}
}
Use THIS within private methods since this won't equal what you might expect.
From http://learn.jquery.com/code-organization/concepts/#the-module-pattern:
// The module pattern
var feature = (function() {
// private variables and functions
var privateThing = "secret";
var publicThing = "not secret";
var changePrivateThing = function() {
privateThing = "super secret";
};
var sayPrivateThing = function() {
console.log( privateThing );
changePrivateThing();
};
// public API
return {
publicThing: publicThing,
sayPrivateThing: sayPrivateThing
};
})();
feature.publicThing; // "not secret"
// logs "secret" and changes the value of privateThing
feature.sayPrivateThing();
So using returning an object that aliases its "methods" could be another way to do it.
I've read from http://www.amazon.com/Programming-Oracle-Press-Poornachandra-Sarang-ebook/dp/B0079GI6CW that it is always good practice to use getters and setters rather that accessing the variable directly from outside the object, so that would eliminate the need of returning variables by reference.
BTW you could just use this.variable to reference/declare a public variable and var variable to declare a private variable.
I know this is a late answer, but I hope it helps anyone who reads it in the future.

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