Truncate strings that have no whitespace - javascript

I'm having an issue where some strings are overflowing their container. I can, of course use overflow:hidden, but it doesn't look that great as I would prefer text-overflow: ellipsis. However, the cross-platform support for that is iffy at best, and the existing solutions I've found don't allow the string to wrap if it contains spaces.
So, my workaround is to truncate the strings in Javascript if the string doesn't contain any spaces for the first N characters. Obviously it won't work as intended if the user doesn't have the correct font installed or if they're zoomed in, but in that case, overflow:hidden will kick in, so I'm okay with that.
Now my question is, how can I do this in as efficient a manner as possible? Will I have to loop through the first N characters and see if each one is a space, and if none of them are, do a string.substring(0, N-3) and then append an ellipsis to it?

Shouldn't have to loop to do simple "is there a space" detection:
var shortened = yourstring.substr(0,N);
if (shortened.indexOf(' ') == -1) {
var shortened = shortened.substr(0, N-3) + '...';
}

Related

How can I get the emoji character count as 1 text length? [duplicate]

I've a little problem.
I'm using NodeJS as backend. Now, an user has a field "biography", where the user can write something about himself.
Suppose that this field has 220 maxlength, and suppose this as input:
๐Ÿ‘ถ๐Ÿป๐Ÿ‘ฆ๐Ÿป๐Ÿ‘ง๐Ÿป๐Ÿ‘จ๐Ÿป๐Ÿ‘ฉ๐Ÿป๐Ÿ‘ฑ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฑ๐Ÿป๐Ÿ‘ด๐Ÿป๐Ÿ‘ต๐Ÿป๐Ÿ‘ฒ๐Ÿป๐Ÿ‘ณ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ณ๐Ÿป๐Ÿ‘ฎ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฎ๐Ÿป๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ๐Ÿ‘ท๐Ÿป๐Ÿ’‚๐Ÿปโ€โ™€๏ธ๐Ÿ’‚๐Ÿป๐Ÿ•ต๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฉ๐Ÿปโ€โš•๏ธ๐Ÿ‘จ๐Ÿปโ€โš•๏ธ๐Ÿ‘ฉ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ
As you can see there aren't 220 emojis (there are 37 emojis), but if I do in my nodejs server
console.log(bio.length)
where bio is the input text, I got 221. How could I "parse" the string input to get the correct length? Is it a problem about unicode?
SOLVED
I used this library: https://github.com/orling/grapheme-splitter
I tried that:
var Grapheme = require('grapheme-splitter');
var splitter = new Grapheme();
console.log(splitter.splitGraphemes(bio).length);
and the length is 37. It works very well!
str.length gives the count of UTF-16 units.
Unicode-proof way to get string length in codepoints (in characters) is [...str].length as iterable protocol splits the string to codepoints.
If we need the length in graphemes (grapheme clusters), we have these native ways:
a. Unicode property escapes in RegExp. See for example: Unicode-aware version of \w or Matching emoji.
b. Intl.Segmenter โ€” coming soon, probably in ES2021. Can be tested with a flag in the last V8 versions (realization was synced with the last spec in V8 86). Unflagged (shipped) in V8 87.
See also:
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)
What every JavaScript developer should know about Unicode
JavaScript has a Unicode problem
Unicode-aware regular expressions in ES2015
ES6 Strings (and Unicode, โค) in Depth
JavaScript for impatient programmers. Unicode โ€“ a brief introduction
TL;DR there are solutions, but they donโ€™t work in every case. Unicode can feel like a dark art.
There seems to be limitations in various solutions I have seen presented, with the issue going beyond emojis and covering other characters in the Unicode range. Consider รฉ can be stored as รฉ or e + โ€˜, if using combing characters. This can even lead to two strings that look the same not being equal. Also note, in certain cases a single emoji can be 11 characters when stored and as a result 22 bytes, assuming UTF16.
The way this is handled and how characters are combined, or displayed, can even vary between browsers and operating systems. So, while you may think you cracked it, there is a risk another environment breaks this. Be sure to test where it matters.
Now, there is the front-end vs back-end problem: you solved the character count problem so it works well for human users, now your single emoji blows right past the allocated field size in the database. Less of an issue with databases such as mongo, but can be one with SQL databases, where field allocation was conservative. This means how you solve your problem will depend where the hardest limitation comes in.
Note, that a basic solution does involve converting a string to an array and getting the length, accepting limitations:
Array.from(str)
This will fall apart when characters are combined and dealing with astral planes.
A few high level approaches, that take into account limitations:
use approaches that solve the front-end issue, as best as possible, and then ensure storage issues are resolved
be more conservative with the advertised front-end limits, if the database or other storage canโ€™t be adjusted
limit the character types that can be entered
clearly indicate limitations of the length calculation
Additionally, given the complexity of the issue it may be worth seeing if there is a popular JS library that already deals with this? I did not find one at the time of writing. Hopefully this is something that would become core to Javascript at some point.
Other pages to read:
https://blog.jonnew.com/posts/poo-dot-length-equals-two
https://mathiasbynens.be/notes/javascript-unicode
https://www.contentful.com/blog/2016/12/06/unicode-javascript-and-the-emoji-family/
https://dmitripavlutin.com/what-every-javascript-developer-should-know-about-unicode/
I answered to a similar question here
But basically, here it is :
'๐Ÿ‘'.match(/./gu).length == 1
As :
'๐Ÿ‘'.length == 2
More precision in my original post
function fancyCount2(str){
const joiner = "\u{200D}";
const split = str.split(joiner);
let count = 0;
for(const s of split){
//removing the variation selectors
const num = Array.from(s.split(/[\ufe00-\ufe0f]/).join("")).length;
count += num;
}
//assuming the joiners are used appropriately
return count / split.length;
}
With a regex that can parse emojis, this can be done easily and without the use of external libraries. Please see the code snippets for examples. ๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ
Note that grapheme-splitter as suggested in the question will overcount and split apart compound emojis that contain other emojis, such as this one: ๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿป. This is reported as three distinct "graphemes", ๐Ÿง‘๐Ÿปโ€ and ๐Ÿคโ€ and ๐Ÿง‘๐Ÿป
Here we are using the 'compact', literal version so it'll fit, but there's a safe, long version that uses Unicode escapes as well.
For more info on the regex see also this answer.
/*the pattern (compact version)*/
var emojiPattern = String.raw`(?:๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿด๓ ง๓ ข๓ ฅ๓ ฎ๓ ง๓ ฟ|๐Ÿด๓ ง๓ ข๓ ณ๓ ฃ๓ ด๓ ฟ|๐Ÿด๓ ง๓ ข๓ ท๓ ฌ๓ ณ๓ ฟ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘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๐Ÿ‘ถ๐Ÿผ|๐Ÿ‘ถ๐Ÿฝ|๐Ÿ‘ถ๐Ÿพ|๐Ÿ‘ถ๐Ÿฟ|๐Ÿง’๐Ÿป|๐Ÿง’๐Ÿผ|๐Ÿง’๐Ÿฝ|๐Ÿง’๐Ÿพ|๐Ÿง’๐Ÿฟ|๐Ÿ‘ฆ๐Ÿป|๐Ÿ‘ฆ๐Ÿผ|๐Ÿ‘ฆ๐Ÿฝ|๐Ÿ‘ฆ๐Ÿพ|๐Ÿ‘ฆ๐Ÿฟ|๐Ÿ‘ง๐Ÿป|๐Ÿ‘ง๐Ÿผ|๐Ÿ‘ง๐Ÿฝ|๐Ÿ‘ง๐Ÿพ|๐Ÿ‘ง๐Ÿฟ|๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฟ|๐Ÿ‘ฑ๐Ÿป|๐Ÿ‘ฑ๐Ÿผ|๐Ÿ‘ฑ๐Ÿฝ|๐Ÿ‘ฑ๐Ÿพ|๐Ÿ‘ฑ๐Ÿฟ|๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿฟ|๐Ÿง”๐Ÿป|๐Ÿง”๐Ÿผ|๐Ÿง”๐Ÿฝ|๐Ÿง”๐Ÿพ|๐Ÿง”๐Ÿฟ|๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฟ|๐Ÿง“๐Ÿป|๐Ÿง“๐Ÿผ|๐Ÿง“๐Ÿฝ|๐Ÿง“๐Ÿพ|๐Ÿง“๐Ÿฟ|๐Ÿ‘ด๐Ÿป|๐Ÿ‘ด๐Ÿผ|๐Ÿ‘ด๐Ÿฝ|๐Ÿ‘ด๐Ÿพ|๐Ÿ‘ด๐Ÿฟ|๐Ÿ‘ต๐Ÿป|๐Ÿ‘ต๐Ÿผ|๐Ÿ‘ต๐Ÿฝ|๐Ÿ‘ต๐Ÿพ|๐Ÿ‘ต๐Ÿฟ|๐Ÿ™๐Ÿป|๐Ÿ™๐Ÿผ|๐Ÿ™๐Ÿฝ|๐Ÿ™๐Ÿพ|๐Ÿ™๐Ÿฟ|๐Ÿ™Ž๐Ÿป|๐Ÿ™Ž๐Ÿผ|๐Ÿ™Ž๐Ÿฝ|๐Ÿ™Ž๐Ÿพ|๐Ÿ™Ž๐Ÿฟ|๐Ÿ™…๐Ÿป|๐Ÿ™…๐Ÿผ|๐Ÿ™…๐Ÿฝ|๐Ÿ™…๐Ÿพ|๐Ÿ™…๐Ÿฟ|๐Ÿ™†๐Ÿป|๐Ÿ™†๐Ÿผ|๐Ÿ™†๐Ÿฝ|๐Ÿ™†๐Ÿพ|๐Ÿ™†๐Ÿฟ|๐Ÿ’๐Ÿป|๐Ÿ’๐Ÿผ|๐Ÿ’๐Ÿฝ|๐Ÿ’๐Ÿพ|๐Ÿ’๐Ÿฟ|๐Ÿ™‹๐Ÿป|๐Ÿ™‹๐Ÿผ|๐Ÿ™‹๐Ÿฝ|๐Ÿ™‹๐Ÿพ|๐Ÿ™‹๐Ÿฟ|๐Ÿง๐Ÿป|๐Ÿง๐Ÿผ|๐Ÿง๐Ÿฝ|๐Ÿง๐Ÿพ|๐Ÿง๐Ÿฟ|๐Ÿ™‡๐Ÿป|๐Ÿ™‡๐Ÿผ|๐Ÿ™‡๐Ÿฝ|๐Ÿ™‡๐Ÿพ|๐Ÿ™‡๐Ÿฟ|๐Ÿคฆ๐Ÿป|๐Ÿคฆ๐Ÿผ|๐Ÿคฆ๐Ÿฝ|๐Ÿคฆ๐Ÿพ|๐Ÿคฆ๐Ÿฟ|๐Ÿคท๐Ÿป|๐Ÿคท๐Ÿผ|๐Ÿคท๐Ÿฝ|๐Ÿคท๐Ÿพ|๐Ÿคท๐Ÿฟ|๐Ÿ‘ฎ๐Ÿป|๐Ÿ‘ฎ๐Ÿผ|๐Ÿ‘ฎ๐Ÿฝ|๐Ÿ‘ฎ๐Ÿพ|๐Ÿ‘ฎ๐Ÿฟ|๐Ÿ•ต๐Ÿป|๐Ÿ•ต๐Ÿผ|๐Ÿ•ต๐Ÿฝ|๐Ÿ•ต๐Ÿพ|๐Ÿ•ต๐Ÿฟ|๐Ÿ’‚๐Ÿป|๐Ÿ’‚๐Ÿผ|๐Ÿ’‚๐Ÿฝ|๐Ÿ’‚๐Ÿพ|๐Ÿ’‚๐Ÿฟ|๐Ÿฅท๐Ÿป|๐Ÿฅท๐Ÿผ|๐Ÿฅท๐Ÿฝ|๐Ÿฅท๐Ÿพ|๐Ÿฅท๐Ÿฟ|๐Ÿ‘ท๐Ÿป|๐Ÿ‘ท๐Ÿผ|๐Ÿ‘ท๐Ÿฝ|๐Ÿ‘ท๐Ÿพ|๐Ÿ‘ท๐Ÿฟ|๐Ÿคด๐Ÿป|๐Ÿคด๐Ÿผ|๐Ÿคด๐Ÿฝ|๐Ÿคด๐Ÿพ|๐Ÿคด๐Ÿฟ|๐Ÿ‘ธ๐Ÿป|๐Ÿ‘ธ๐Ÿผ|๐Ÿ‘ธ๐Ÿฝ|๐Ÿ‘ธ๐Ÿพ|๐Ÿ‘ธ๐Ÿฟ|๐Ÿ‘ณ๐Ÿป|๐Ÿ‘ณ๐Ÿผ|๐Ÿ‘ณ๐Ÿฝ|๐Ÿ‘ณ๐Ÿพ|๐Ÿ‘ณ๐Ÿฟ|๐Ÿ‘ฒ๐Ÿป|๐Ÿ‘ฒ๐Ÿผ|๐Ÿ‘ฒ๐Ÿฝ|๐Ÿ‘ฒ๐Ÿพ|๐Ÿ‘ฒ๐Ÿฟ|๐Ÿง•๐Ÿป|๐Ÿง•๐Ÿผ|๐Ÿง•๐Ÿฝ|๐Ÿง•๐Ÿพ|๐Ÿง•๐Ÿฟ|๐Ÿคต๐Ÿป|๐Ÿคต๐Ÿผ|๐Ÿคต๐Ÿฝ|๐Ÿคต๐Ÿพ|๐Ÿคต๐Ÿฟ|๐Ÿ‘ฐ๐Ÿป|๐Ÿ‘ฐ๐Ÿผ|๐Ÿ‘ฐ๐Ÿฝ|๐Ÿ‘ฐ๐Ÿพ|๐Ÿ‘ฐ๐Ÿฟ|๐Ÿคฐ๐Ÿป|๐Ÿคฐ๐Ÿผ|๐Ÿคฐ๐Ÿฝ|๐Ÿคฐ๐Ÿพ|๐Ÿคฐ๐Ÿฟ|๐Ÿคฑ๐Ÿป|๐Ÿคฑ๐Ÿผ|๐Ÿคฑ๐Ÿฝ|๐Ÿคฑ๐Ÿพ|๐Ÿคฑ๐Ÿฟ|๐Ÿ‘ผ๐Ÿป|๐Ÿ‘ผ๐Ÿผ|๐Ÿ‘ผ๐Ÿฝ|๐Ÿ‘ผ๐Ÿพ|๐Ÿ‘ผ๐Ÿฟ|๐ŸŽ…๐Ÿป|๐ŸŽ…๐Ÿผ|๐ŸŽ…๐Ÿฝ|๐ŸŽ…๐Ÿพ|๐ŸŽ…๐Ÿฟ|๐Ÿคถ๐Ÿป|๐Ÿคถ๐Ÿผ|๐Ÿคถ๐Ÿฝ|๐Ÿคถ๐Ÿพ|๐Ÿคถ๐Ÿฟ|๐Ÿฆธ๐Ÿป|๐Ÿฆธ๐Ÿผ|๐Ÿฆธ๐Ÿฝ|๐Ÿฆธ๐Ÿพ|๐Ÿฆธ๐Ÿฟ|๐Ÿฆน๐Ÿป|๐Ÿฆน๐Ÿผ|๐Ÿฆน๐Ÿฝ|๐Ÿฆน๐Ÿพ|๐Ÿฆน๐Ÿฟ|๐Ÿง™๐Ÿป|๐Ÿง™๐Ÿผ|๐Ÿง™๐Ÿฝ|๐Ÿง™๐Ÿพ|๐Ÿง™๐Ÿฟ|๐Ÿงš๐Ÿป|๐Ÿงš๐Ÿผ|๐Ÿงš๐Ÿฝ|๐Ÿงš๐Ÿพ|๐Ÿงš๐Ÿฟ|๐Ÿง›๐Ÿป|๐Ÿง›๐Ÿผ|๐Ÿง›๐Ÿฝ|๐Ÿง›๐Ÿพ|๐Ÿง›๐Ÿฟ|๐Ÿงœ๐Ÿป|๐Ÿงœ๐Ÿผ|๐Ÿงœ๐Ÿฝ|๐Ÿงœ๐Ÿพ|๐Ÿงœ๐Ÿฟ|๐Ÿง๐Ÿป|๐Ÿง๐Ÿผ|๐Ÿง๐Ÿฝ|๐Ÿง๐Ÿพ|๐Ÿง๐Ÿฟ|๐Ÿ’†๐Ÿป|๐Ÿ’†๐Ÿผ|๐Ÿ’†๐Ÿฝ|๐Ÿ’†๐Ÿพ|๐Ÿ’†๐Ÿฟ|๐Ÿ’‡๐Ÿป|๐Ÿ’‡๐Ÿผ|๐Ÿ’‡๐Ÿฝ|๐Ÿ’‡๐Ÿพ|๐Ÿ’‡๐Ÿฟ|๐Ÿšถ๐Ÿป|๐Ÿšถ๐Ÿผ|๐Ÿšถ๐Ÿฝ|๐Ÿšถ๐Ÿพ|๐Ÿšถ๐Ÿฟ|๐Ÿง๐Ÿป|๐Ÿง๐Ÿผ|๐Ÿง๐Ÿฝ|๐Ÿง๐Ÿพ|๐Ÿง๐Ÿฟ|๐ŸงŽ๐Ÿป|๐ŸงŽ๐Ÿผ|๐ŸงŽ๐Ÿฝ|๐ŸงŽ๐Ÿพ|๐ŸงŽ๐Ÿฟ|๐Ÿƒ๐Ÿป|๐Ÿƒ๐Ÿผ|๐Ÿƒ๐Ÿฝ|๐Ÿƒ๐Ÿพ|๐Ÿƒ๐Ÿฟ|๐Ÿ’ƒ๐Ÿป|๐Ÿ’ƒ๐Ÿผ|๐Ÿ’ƒ๐Ÿฝ|๐Ÿ’ƒ๐Ÿพ|๐Ÿ’ƒ๐Ÿฟ|๐Ÿ•บ๐Ÿป|๐Ÿ•บ๐Ÿผ|๐Ÿ•บ๐Ÿฝ|๐Ÿ•บ๐Ÿพ|๐Ÿ•บ๐Ÿฟ|๐Ÿ•ด๐Ÿป|๐Ÿ•ด๐Ÿผ|๐Ÿ•ด๐Ÿฝ|๐Ÿ•ด๐Ÿพ|๐Ÿ•ด๐Ÿฟ|๐Ÿง–๐Ÿป|๐Ÿง–๐Ÿผ|๐Ÿง–๐Ÿฝ|๐Ÿง–๐Ÿพ|๐Ÿง–๐Ÿฟ|๐Ÿง—๐Ÿป|๐Ÿง—๐Ÿผ|๐Ÿง—๐Ÿฝ|๐Ÿง—๐Ÿพ|๐Ÿง—๐Ÿฟ|๐Ÿ‡๐Ÿป|๐Ÿ‡๐Ÿผ|๐Ÿ‡๐Ÿฝ|๐Ÿ‡๐Ÿพ|๐Ÿ‡๐Ÿฟ|๐Ÿ‚๐Ÿป|๐Ÿ‚๐Ÿผ|๐Ÿ‚๐Ÿฝ|๐Ÿ‚๐Ÿพ|๐Ÿ‚๐Ÿฟ|๐ŸŒ๐Ÿป|๐ŸŒ๐Ÿผ|๐ŸŒ๐Ÿฝ|๐ŸŒ๐Ÿพ|๐ŸŒ๐Ÿฟ|๐Ÿ„๐Ÿป|๐Ÿ„๐Ÿผ|๐Ÿ„๐Ÿฝ|๐Ÿ„๐Ÿพ|๐Ÿ„๐Ÿฟ|๐Ÿšฃ๐Ÿป|๐Ÿšฃ๐Ÿผ|๐Ÿšฃ๐Ÿฝ|๐Ÿšฃ๐Ÿพ|๐Ÿšฃ๐Ÿฟ|๐ŸŠ๐Ÿป|๐ŸŠ๐Ÿผ|๐ŸŠ๐Ÿฝ|๐ŸŠ๐Ÿพ|๐ŸŠ๐Ÿฟ|๐Ÿ‹๐Ÿป|๐Ÿ‹๐Ÿผ|๐Ÿ‹๐Ÿฝ|๐Ÿ‹๐Ÿพ|๐Ÿ‹๐Ÿฟ|๐Ÿšด๐Ÿป|๐Ÿšด๐Ÿผ|๐Ÿšด๐Ÿฝ|๐Ÿšด๐Ÿพ|๐Ÿšด๐Ÿฟ|๐Ÿšต๐Ÿป|๐Ÿšต๐Ÿผ|๐Ÿšต๐Ÿฝ|๐Ÿšต๐Ÿพ|๐Ÿšต๐Ÿฟ|๐Ÿคธ๐Ÿป|๐Ÿคธ๐Ÿผ|๐Ÿคธ๐Ÿฝ|๐Ÿคธ๐Ÿพ|๐Ÿคธ๐Ÿฟ|๐Ÿคฝ๐Ÿป|๐Ÿคฝ๐Ÿผ|๐Ÿคฝ๐Ÿฝ|๐Ÿคฝ๐Ÿพ|๐Ÿคฝ๐Ÿฟ|๐Ÿคพ๐Ÿป|๐Ÿคพ๐Ÿผ|๐Ÿคพ๐Ÿฝ|๐Ÿคพ๐Ÿพ|๐Ÿคพ๐Ÿฟ|๐Ÿคน๐Ÿป|๐Ÿคน๐Ÿผ|๐Ÿคน๐Ÿฝ|๐Ÿคน๐Ÿพ|๐Ÿคน๐Ÿฟ|๐Ÿง˜๐Ÿป|๐Ÿง˜๐Ÿผ|๐Ÿง˜๐Ÿฝ|๐Ÿง˜๐Ÿพ|๐Ÿง˜๐Ÿฟ|๐Ÿ›€๐Ÿป|๐Ÿ›€๐Ÿผ|๐Ÿ›€๐Ÿฝ|๐Ÿ›€๐Ÿพ|๐Ÿ›€๐Ÿฟ|๐Ÿ›Œ๐Ÿป|๐Ÿ›Œ๐Ÿผ|๐Ÿ›Œ๐Ÿฝ|๐Ÿ›Œ๐Ÿพ|๐Ÿ›Œ๐Ÿฟ|๐Ÿ‘ญ๐Ÿป|๐Ÿ‘ญ๐Ÿผ|๐Ÿ‘ญ๐Ÿฝ|๐Ÿ‘ญ๐Ÿพ|๐Ÿ‘ญ๐Ÿฟ|๐Ÿ‘ซ๐Ÿป|๐Ÿ‘ซ๐Ÿผ|๐Ÿ‘ซ๐Ÿฝ|๐Ÿ‘ซ๐Ÿพ|๐Ÿ‘ซ๐Ÿฟ|๐Ÿ‘ฌ๐Ÿป|๐Ÿ‘ฌ๐Ÿผ|๐Ÿ‘ฌ๐Ÿฝ|๐Ÿ‘ฌ๐Ÿพ|๐Ÿ‘ฌ๐Ÿฟ|๐Ÿ’๐Ÿป|๐Ÿ’๐Ÿผ|๐Ÿ’๐Ÿฝ|๐Ÿ’๐Ÿพ|๐Ÿ’๐Ÿฟ|๐Ÿ’‘๐Ÿป|๐Ÿ’‘๐Ÿผ|๐Ÿ’‘๐Ÿฝ|๐Ÿ’‘๐Ÿพ|๐Ÿ’‘๐Ÿฟ|#๏ธโƒฃ|0๏ธโƒฃ|1๏ธโƒฃ|2๏ธโƒฃ|3๏ธโƒฃ|4๏ธโƒฃ|5๏ธโƒฃ|6๏ธโƒฃ|7๏ธโƒฃ|8๏ธโƒฃ|9๏ธโƒฃ|โœ‹๐Ÿป|โœ‹๐Ÿผ|โœ‹๐Ÿฝ|โœ‹๐Ÿพ|โœ‹๐Ÿฟ|โœŒ๐Ÿป|โœŒ๐Ÿผ|โœŒ๐Ÿฝ|โœŒ๐Ÿพ|โœŒ๐Ÿฟ|โ˜๐Ÿป|โ˜๐Ÿผ|โ˜๐Ÿฝ|โ˜๐Ÿพ|โ˜๐Ÿฟ|โœŠ๐Ÿป|โœŠ๐Ÿผ|โœŠ๐Ÿฝ|โœŠ๐Ÿพ|โœŠ๐Ÿฟ|โœ๐Ÿป|โœ๐Ÿผ|โœ๐Ÿฝ|โœ๐Ÿพ|โœ๐Ÿฟ|โ›น๐Ÿป|โ›น๐Ÿผ|โ›น๐Ÿฝ|โ›น๐Ÿพ|โ›น๐Ÿฟ|๐Ÿ˜€|๐Ÿ˜ƒ|๐Ÿ˜„|๐Ÿ˜|๐Ÿ˜†|๐Ÿ˜…|๐Ÿคฃ|๐Ÿ˜‚|๐Ÿ™‚|๐Ÿ™ƒ|๐Ÿ˜‰|๐Ÿ˜Š|๐Ÿ˜‡|๐Ÿฅฐ|๐Ÿ˜|๐Ÿคฉ|๐Ÿ˜˜|๐Ÿ˜—|๐Ÿ˜š|๐Ÿ˜™|๐Ÿฅฒ|๐Ÿ˜‹|๐Ÿ˜›|๐Ÿ˜œ|๐Ÿคช|๐Ÿ˜|๐Ÿค‘|๐Ÿค—|๐Ÿคญ|๐Ÿคซ|๐Ÿค”|๐Ÿค|๐Ÿคจ|๐Ÿ˜|๐Ÿ˜‘|๐Ÿ˜ถ|๐Ÿ˜|๐Ÿ˜’|๐Ÿ™„|๐Ÿ˜ฌ|๐Ÿคฅ|๐Ÿ˜Œ|๐Ÿ˜”|๐Ÿ˜ช|๐Ÿคค|๐Ÿ˜ด|๐Ÿ˜ท|๐Ÿค’|๐Ÿค•|๐Ÿคข|๐Ÿคฎ|๐Ÿคง|๐Ÿฅต|๐Ÿฅถ|๐Ÿฅด|๐Ÿ˜ต|๐Ÿคฏ|๐Ÿค |๐Ÿฅณ|๐Ÿฅธ|๐Ÿ˜Ž|๐Ÿค“|๐Ÿง|๐Ÿ˜•|๐Ÿ˜Ÿ|๐Ÿ™|๐Ÿ˜ฎ|๐Ÿ˜ฏ|๐Ÿ˜ฒ|๐Ÿ˜ณ|๐Ÿฅบ|๐Ÿ˜ฆ|๐Ÿ˜ง|๐Ÿ˜จ|๐Ÿ˜ฐ|๐Ÿ˜ฅ|๐Ÿ˜ข|๐Ÿ˜ญ|๐Ÿ˜ฑ|๐Ÿ˜–|๐Ÿ˜ฃ|๐Ÿ˜ž|๐Ÿ˜“|๐Ÿ˜ฉ|๐Ÿ˜ซ|๐Ÿฅฑ|๐Ÿ˜ค|๐Ÿ˜ก|๐Ÿ˜ |๐Ÿคฌ|๐Ÿ˜ˆ|๐Ÿ‘ฟ|๐Ÿ’€|๐Ÿ’ฉ|๐Ÿคก|๐Ÿ‘น|๐Ÿ‘บ|๐Ÿ‘ป|๐Ÿ‘ฝ|๐Ÿ‘พ|๐Ÿค–|๐Ÿ˜บ|๐Ÿ˜ธ|๐Ÿ˜น|๐Ÿ˜ป|๐Ÿ˜ผ|๐Ÿ˜ฝ|๐Ÿ™€|๐Ÿ˜ฟ|๐Ÿ˜พ|๐Ÿ™ˆ|๐Ÿ™‰|๐Ÿ™Š|๐Ÿ’‹|๐Ÿ’Œ|๐Ÿ’˜|๐Ÿ’|๐Ÿ’–|๐Ÿ’—|๐Ÿ’“|๐Ÿ’ž|๐Ÿ’•|๐Ÿ’Ÿ|๐Ÿ’”|๐Ÿงก|๐Ÿ’›|๐Ÿ’š|๐Ÿ’™|๐Ÿ’œ|๐ŸคŽ|๐Ÿ–ค|๐Ÿค|๐Ÿ’ฏ|๐Ÿ’ข|๐Ÿ’ฅ|๐Ÿ’ซ|๐Ÿ’ฆ|๐Ÿ’จ|๐Ÿ•ณ|๐Ÿ’ฃ|๐Ÿ’ฌ|๐Ÿ—จ|๐Ÿ—ฏ|๐Ÿ’ญ|๐Ÿ’ค|๐Ÿ‘‹|๐Ÿคš|๐Ÿ–|๐Ÿ––|๐Ÿ‘Œ|๐ŸคŒ|๐Ÿค|๐Ÿคž|๐ŸคŸ|๐Ÿค˜|๐Ÿค™|๐Ÿ‘ˆ|๐Ÿ‘‰|๐Ÿ‘†|๐Ÿ–•|๐Ÿ‘‡|๐Ÿ‘|๐Ÿ‘Ž|๐Ÿ‘Š|๐Ÿค›|๐Ÿคœ|๐Ÿ‘|๐Ÿ™Œ|๐Ÿ‘|๐Ÿคฒ|๐Ÿค|๐Ÿ™|๐Ÿ’…|๐Ÿคณ|๐Ÿ’ช|๐Ÿฆพ|๐Ÿฆฟ|๐Ÿฆต|๐Ÿฆถ|๐Ÿ‘‚|๐Ÿฆป|๐Ÿ‘ƒ|๐Ÿง |๐Ÿซ€|๐Ÿซ|๐Ÿฆท|๐Ÿฆด|๐Ÿ‘€|๐Ÿ‘|๐Ÿ‘…|๐Ÿ‘„|๐Ÿ‘ถ|๐Ÿง’|๐Ÿ‘ฆ|๐Ÿ‘ง|๐Ÿง‘|๐Ÿ‘ฑ|๐Ÿ‘จ|๐Ÿง”|๐Ÿ‘ฉ|๐Ÿง“|๐Ÿ‘ด|๐Ÿ‘ต|๐Ÿ™|๐Ÿ™Ž|๐Ÿ™…|๐Ÿ™†|๐Ÿ’|๐Ÿ™‹|๐Ÿง|๐Ÿ™‡|๐Ÿคฆ|๐Ÿคท|๐Ÿ‘ฎ|๐Ÿ•ต|๐Ÿ’‚|๐Ÿฅท|๐Ÿ‘ท|๐Ÿคด|๐Ÿ‘ธ|๐Ÿ‘ณ|๐Ÿ‘ฒ|๐Ÿง•|๐Ÿคต|๐Ÿ‘ฐ|๐Ÿคฐ|๐Ÿคฑ|๐Ÿ‘ผ|๐ŸŽ…|๐Ÿคถ|๐Ÿฆธ|๐Ÿฆน|๐Ÿง™|๐Ÿงš|๐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โ˜ฆ|โ˜ช|โ˜ฎ|โ™ˆ|โ™‰|โ™Š|โ™‹|โ™Œ|โ™|โ™Ž|โ™|โ™|โ™‘|โ™’|โ™“|โ›Ž|โ–ถ|โฉ|โญ|โฏ|โ—€|โช|โฎ|โซ|โฌ|โธ|โน|โบ|โ|โ™€|โ™‚|โšง|โœ–|โž•|โž–|โž—|โ™พ|โ€ผ|โ‰|โ“|โ”|โ•|โ—|ใ€ฐ|โš•|โ™ป|โšœ|โญ•|โœ…|โ˜‘|โœ”|โŒ|โŽ|โžฐ|โžฟ|ใ€ฝ|โœณ|โœด|โ‡|ยฉ|ยฎ|โ„ข|โ„น|โ“‚|ใŠ—|ใŠ™|โšซ|โšช|โฌ›|โฌœ|โ—ผ|โ—ป|โ—พ|โ—ฝ|โ–ช|โ–ซ)`
/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g");
/*count of emojis*/
let emoCount = [..."๐Ÿ‘ถ๐Ÿป๐Ÿ‘ฆ๐Ÿป๐Ÿ‘ง๐Ÿป๐Ÿ‘จ๐Ÿป๐Ÿ‘ฉ๐Ÿป๐Ÿ‘ฑ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฑ๐Ÿป๐Ÿ‘ด๐Ÿป๐Ÿ‘ต๐Ÿป๐Ÿ‘ฒ๐Ÿป๐Ÿ‘ณ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ณ๐Ÿป๐Ÿ‘ฎ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฎ๐Ÿป๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ๐Ÿ‘ท๐Ÿป๐Ÿ’‚๐Ÿปโ€โ™€๏ธ๐Ÿ’‚๐Ÿป๐Ÿ•ต๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฉ๐Ÿปโ€โš•๏ธ๐Ÿ‘จ๐Ÿปโ€โš•๏ธ๐Ÿ‘ฉ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ".matchAll(emoRegex)].length
console.log(emoCount) //37
/*modifying the pattern to count other characters too*/
let generalCounter = new RegExp(emojiPattern+"|.", "g") //emoji or regular character
let allCount = [..."$%^ other stuff equalling 28๐Ÿ‘ถ๐Ÿ‘ฆ๐Ÿป๐Ÿ‘ง๐Ÿป๐Ÿ‘จ๐Ÿป๐Ÿ‘ฉ๐Ÿป๐Ÿ‘ฑ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฑ๐Ÿป๐Ÿ‘ด๐Ÿป๐Ÿ‘ต๐Ÿป๐Ÿ‘ฒ๐Ÿป๐Ÿ‘ณ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ณ๐Ÿป๐Ÿ‘ฎ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฎ๐Ÿป๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ๐Ÿ‘ท๐Ÿป๐Ÿ’‚๐Ÿปโ€โ™€๏ธ๐Ÿ’‚๐Ÿป๐Ÿ•ต๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฉ๐Ÿปโ€โš•๏ธ๐Ÿ‘จ๐Ÿปโ€โš•๏ธ๐Ÿ‘ฉ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ".matchAll(generalCounter)].length
console.log(allCount) //28+37 = 65
As you can see from the below example, this is to do with unicode encoding,
There's some great resources such as the one I took this example from.
https://blog.jonnew.com/posts/poo-dot-length-equals-two
console.log("๐Ÿ‘ฉโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ".length === 11);
For anyone interested, I had a similar problem where I wanted to count the length of an emoji at the end of a string.
This is the solution I came up with:
var emoji = new RegExp('(\\p{Extended_Pictographic})((\u200D\\p{Extended_Pictographic})*)$', 'u');
var testStrings = ['๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง', '๐Ÿ˜‚', '๐ŸŒฒ'];
for(var string = 0; string < testStrings.length; string++){
var match = testStrings[string].match(emoji);
var chars = match == null ? 0 : match[0].length;
console.log(testStrings[string] + ': ' + chars);
}
Explanation: \\p{Extended_Pictographic} matches an emoji like ๐Ÿ˜‚, consisting of two characters. Emojis like ๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง consists of 4 emojis (๐Ÿ‘จ, ๐Ÿ‘ฉ, ๐Ÿ‘ง,๐Ÿ‘ฆ) combined by a zero width joiner (\u200D).
The regex matches any emoji at the end ($). If there is a match the length is counted. I am sure it could be adopted for your use-case by matching all emojis in a given string and then subtracting the surplus. It's not a complete implementation for your particular question but I hope this gets you on the right track.
use lodash toArray method
console.log(_.toArray("๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง").length); // 1
console.log(_.toArray("๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง๐Ÿงโ€โ™‚๏ธ๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ง").length); // 3
Check here for Codesandbox
I suggest using the runes package to accomplish correct multi-byte string conversions cause else you will get more issues if using reducers and more to reverse strings for example.
Take a look at this great small package: runes

How to count the correct length of a string with emojis in javascript?

I've a little problem.
I'm using NodeJS as backend. Now, an user has a field "biography", where the user can write something about himself.
Suppose that this field has 220 maxlength, and suppose this as input:
๐Ÿ‘ถ๐Ÿป๐Ÿ‘ฆ๐Ÿป๐Ÿ‘ง๐Ÿป๐Ÿ‘จ๐Ÿป๐Ÿ‘ฉ๐Ÿป๐Ÿ‘ฑ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฑ๐Ÿป๐Ÿ‘ด๐Ÿป๐Ÿ‘ต๐Ÿป๐Ÿ‘ฒ๐Ÿป๐Ÿ‘ณ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ณ๐Ÿป๐Ÿ‘ฎ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฎ๐Ÿป๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ๐Ÿ‘ท๐Ÿป๐Ÿ’‚๐Ÿปโ€โ™€๏ธ๐Ÿ’‚๐Ÿป๐Ÿ•ต๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฉ๐Ÿปโ€โš•๏ธ๐Ÿ‘จ๐Ÿปโ€โš•๏ธ๐Ÿ‘ฉ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ
As you can see there aren't 220 emojis (there are 37 emojis), but if I do in my nodejs server
console.log(bio.length)
where bio is the input text, I got 221. How could I "parse" the string input to get the correct length? Is it a problem about unicode?
SOLVED
I used this library: https://github.com/orling/grapheme-splitter
I tried that:
var Grapheme = require('grapheme-splitter');
var splitter = new Grapheme();
console.log(splitter.splitGraphemes(bio).length);
and the length is 37. It works very well!
str.length gives the count of UTF-16 units.
Unicode-proof way to get string length in codepoints (in characters) is [...str].length as iterable protocol splits the string to codepoints.
If we need the length in graphemes (grapheme clusters), we have these native ways:
a. Unicode property escapes in RegExp. See for example: Unicode-aware version of \w or Matching emoji.
b. Intl.Segmenter โ€” coming soon, probably in ES2021. Can be tested with a flag in the last V8 versions (realization was synced with the last spec in V8 86). Unflagged (shipped) in V8 87.
See also:
The Absolute Minimum Every Software Developer Absolutely, Positively Must Know About Unicode and Character Sets (No Excuses!)
What every JavaScript developer should know about Unicode
JavaScript has a Unicode problem
Unicode-aware regular expressions in ES2015
ES6 Strings (and Unicode, โค) in Depth
JavaScript for impatient programmers. Unicode โ€“ a brief introduction
TL;DR there are solutions, but they donโ€™t work in every case. Unicode can feel like a dark art.
There seems to be limitations in various solutions I have seen presented, with the issue going beyond emojis and covering other characters in the Unicode range. Consider รฉ can be stored as รฉ or e + โ€˜, if using combing characters. This can even lead to two strings that look the same not being equal. Also note, in certain cases a single emoji can be 11 characters when stored and as a result 22 bytes, assuming UTF16.
The way this is handled and how characters are combined, or displayed, can even vary between browsers and operating systems. So, while you may think you cracked it, there is a risk another environment breaks this. Be sure to test where it matters.
Now, there is the front-end vs back-end problem: you solved the character count problem so it works well for human users, now your single emoji blows right past the allocated field size in the database. Less of an issue with databases such as mongo, but can be one with SQL databases, where field allocation was conservative. This means how you solve your problem will depend where the hardest limitation comes in.
Note, that a basic solution does involve converting a string to an array and getting the length, accepting limitations:
Array.from(str)
This will fall apart when characters are combined and dealing with astral planes.
A few high level approaches, that take into account limitations:
use approaches that solve the front-end issue, as best as possible, and then ensure storage issues are resolved
be more conservative with the advertised front-end limits, if the database or other storage canโ€™t be adjusted
limit the character types that can be entered
clearly indicate limitations of the length calculation
Additionally, given the complexity of the issue it may be worth seeing if there is a popular JS library that already deals with this? I did not find one at the time of writing. Hopefully this is something that would become core to Javascript at some point.
Other pages to read:
https://blog.jonnew.com/posts/poo-dot-length-equals-two
https://mathiasbynens.be/notes/javascript-unicode
https://www.contentful.com/blog/2016/12/06/unicode-javascript-and-the-emoji-family/
https://dmitripavlutin.com/what-every-javascript-developer-should-know-about-unicode/
I answered to a similar question here
But basically, here it is :
'๐Ÿ‘'.match(/./gu).length == 1
As :
'๐Ÿ‘'.length == 2
More precision in my original post
function fancyCount2(str){
const joiner = "\u{200D}";
const split = str.split(joiner);
let count = 0;
for(const s of split){
//removing the variation selectors
const num = Array.from(s.split(/[\ufe00-\ufe0f]/).join("")).length;
count += num;
}
//assuming the joiners are used appropriately
return count / split.length;
}
With a regex that can parse emojis, this can be done easily and without the use of external libraries. Please see the code snippets for examples. ๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ
Note that grapheme-splitter as suggested in the question will overcount and split apart compound emojis that contain other emojis, such as this one: ๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿป. This is reported as three distinct "graphemes", ๐Ÿง‘๐Ÿปโ€ and ๐Ÿคโ€ and ๐Ÿง‘๐Ÿป
Here we are using the 'compact', literal version so it'll fit, but there's a safe, long version that uses Unicode escapes as well.
For more info on the regex see also this answer.
/*the pattern (compact version)*/
var emojiPattern = String.raw`(?:๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿง‘๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฝโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿพโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฟโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿด๓ ง๓ ข๓ ฅ๓ ฎ๓ ง๓ ฟ|๐Ÿด๓ ง๓ ข๓ ณ๓ ฃ๓ ด๓ ฟ|๐Ÿด๓ ง๓ ข๓ ท๓ ฌ๓ ณ๓ ฟ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿปโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿผโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฝโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿพโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฟโ€๐Ÿคโ€๐Ÿง‘๐Ÿฟ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿฟโ€๐Ÿคโ€๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿผ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿปโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿพ|๐Ÿ‘ฉ๐Ÿผโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿฟ|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘จ๐Ÿป|๐Ÿ‘ฉ๐Ÿฝโ€๐Ÿคโ€๐Ÿ‘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๐Ÿ‘ถ๐Ÿผ|๐Ÿ‘ถ๐Ÿฝ|๐Ÿ‘ถ๐Ÿพ|๐Ÿ‘ถ๐Ÿฟ|๐Ÿง’๐Ÿป|๐Ÿง’๐Ÿผ|๐Ÿง’๐Ÿฝ|๐Ÿง’๐Ÿพ|๐Ÿง’๐Ÿฟ|๐Ÿ‘ฆ๐Ÿป|๐Ÿ‘ฆ๐Ÿผ|๐Ÿ‘ฆ๐Ÿฝ|๐Ÿ‘ฆ๐Ÿพ|๐Ÿ‘ฆ๐Ÿฟ|๐Ÿ‘ง๐Ÿป|๐Ÿ‘ง๐Ÿผ|๐Ÿ‘ง๐Ÿฝ|๐Ÿ‘ง๐Ÿพ|๐Ÿ‘ง๐Ÿฟ|๐Ÿง‘๐Ÿป|๐Ÿง‘๐Ÿผ|๐Ÿง‘๐Ÿฝ|๐Ÿง‘๐Ÿพ|๐Ÿง‘๐Ÿฟ|๐Ÿ‘ฑ๐Ÿป|๐Ÿ‘ฑ๐Ÿผ|๐Ÿ‘ฑ๐Ÿฝ|๐Ÿ‘ฑ๐Ÿพ|๐Ÿ‘ฑ๐Ÿฟ|๐Ÿ‘จ๐Ÿป|๐Ÿ‘จ๐Ÿผ|๐Ÿ‘จ๐Ÿฝ|๐Ÿ‘จ๐Ÿพ|๐Ÿ‘จ๐Ÿฟ|๐Ÿง”๐Ÿป|๐Ÿง”๐Ÿผ|๐Ÿง”๐Ÿฝ|๐Ÿง”๐Ÿพ|๐Ÿง”๐Ÿฟ|๐Ÿ‘ฉ๐Ÿป|๐Ÿ‘ฉ๐Ÿผ|๐Ÿ‘ฉ๐Ÿฝ|๐Ÿ‘ฉ๐Ÿพ|๐Ÿ‘ฉ๐Ÿฟ|๐Ÿง“๐Ÿป|๐Ÿง“๐Ÿผ|๐Ÿง“๐Ÿฝ|๐Ÿง“๐Ÿพ|๐Ÿง“๐Ÿฟ|๐Ÿ‘ด๐Ÿป|๐Ÿ‘ด๐Ÿผ|๐Ÿ‘ด๐Ÿฝ|๐Ÿ‘ด๐Ÿพ|๐Ÿ‘ด๐Ÿฟ|๐Ÿ‘ต๐Ÿป|๐Ÿ‘ต๐Ÿผ|๐Ÿ‘ต๐Ÿฝ|๐Ÿ‘ต๐Ÿพ|๐Ÿ‘ต๐Ÿฟ|๐Ÿ™๐Ÿป|๐Ÿ™๐Ÿผ|๐Ÿ™๐Ÿฝ|๐Ÿ™๐Ÿพ|๐Ÿ™๐Ÿฟ|๐Ÿ™Ž๐Ÿป|๐Ÿ™Ž๐Ÿผ|๐Ÿ™Ž๐Ÿฝ|๐Ÿ™Ž๐Ÿพ|๐Ÿ™Ž๐Ÿฟ|๐Ÿ™…๐Ÿป|๐Ÿ™…๐Ÿผ|๐Ÿ™…๐Ÿฝ|๐Ÿ™…๐Ÿพ|๐Ÿ™…๐Ÿฟ|๐Ÿ™†๐Ÿป|๐Ÿ™†๐Ÿผ|๐Ÿ™†๐Ÿฝ|๐Ÿ™†๐Ÿพ|๐Ÿ™†๐Ÿฟ|๐Ÿ’๐Ÿป|๐Ÿ’๐Ÿผ|๐Ÿ’๐Ÿฝ|๐Ÿ’๐Ÿพ|๐Ÿ’๐Ÿฟ|๐Ÿ™‹๐Ÿป|๐Ÿ™‹๐Ÿผ|๐Ÿ™‹๐Ÿฝ|๐Ÿ™‹๐Ÿพ|๐Ÿ™‹๐Ÿฟ|๐Ÿง๐Ÿป|๐Ÿง๐Ÿผ|๐Ÿง๐Ÿฝ|๐Ÿง๐Ÿพ|๐Ÿง๐Ÿฟ|๐Ÿ™‡๐Ÿป|๐Ÿ™‡๐Ÿผ|๐Ÿ™‡๐Ÿฝ|๐Ÿ™‡๐Ÿพ|๐Ÿ™‡๐Ÿฟ|๐Ÿคฆ๐Ÿป|๐Ÿคฆ๐Ÿผ|๐Ÿคฆ๐Ÿฝ|๐Ÿคฆ๐Ÿพ|๐Ÿคฆ๐Ÿฟ|๐Ÿคท๐Ÿป|๐Ÿคท๐Ÿผ|๐Ÿคท๐Ÿฝ|๐Ÿคท๐Ÿพ|๐Ÿคท๐Ÿฟ|๐Ÿ‘ฎ๐Ÿป|๐Ÿ‘ฎ๐Ÿผ|๐Ÿ‘ฎ๐Ÿฝ|๐Ÿ‘ฎ๐Ÿพ|๐Ÿ‘ฎ๐Ÿฟ|๐Ÿ•ต๐Ÿป|๐Ÿ•ต๐Ÿผ|๐Ÿ•ต๐Ÿฝ|๐Ÿ•ต๐Ÿพ|๐Ÿ•ต๐Ÿฟ|๐Ÿ’‚๐Ÿป|๐Ÿ’‚๐Ÿผ|๐Ÿ’‚๐Ÿฝ|๐Ÿ’‚๐Ÿพ|๐Ÿ’‚๐Ÿฟ|๐Ÿฅท๐Ÿป|๐Ÿฅท๐Ÿผ|๐Ÿฅท๐Ÿฝ|๐Ÿฅท๐Ÿพ|๐Ÿฅท๐Ÿฟ|๐Ÿ‘ท๐Ÿป|๐Ÿ‘ท๐Ÿผ|๐Ÿ‘ท๐Ÿฝ|๐Ÿ‘ท๐Ÿพ|๐Ÿ‘ท๐Ÿฟ|๐Ÿคด๐Ÿป|๐Ÿคด๐Ÿผ|๐Ÿคด๐Ÿฝ|๐Ÿคด๐Ÿพ|๐Ÿคด๐Ÿฟ|๐Ÿ‘ธ๐Ÿป|๐Ÿ‘ธ๐Ÿผ|๐Ÿ‘ธ๐Ÿฝ|๐Ÿ‘ธ๐Ÿพ|๐Ÿ‘ธ๐Ÿฟ|๐Ÿ‘ณ๐Ÿป|๐Ÿ‘ณ๐Ÿผ|๐Ÿ‘ณ๐Ÿฝ|๐Ÿ‘ณ๐Ÿพ|๐Ÿ‘ณ๐Ÿฟ|๐Ÿ‘ฒ๐Ÿป|๐Ÿ‘ฒ๐Ÿผ|๐Ÿ‘ฒ๐Ÿฝ|๐Ÿ‘ฒ๐Ÿพ|๐Ÿ‘ฒ๐Ÿฟ|๐Ÿง•๐Ÿป|๐Ÿง•๐Ÿผ|๐Ÿง•๐Ÿฝ|๐Ÿง•๐Ÿพ|๐Ÿง•๐Ÿฟ|๐Ÿคต๐Ÿป|๐Ÿคต๐Ÿผ|๐Ÿคต๐Ÿฝ|๐Ÿคต๐Ÿพ|๐Ÿคต๐Ÿฟ|๐Ÿ‘ฐ๐Ÿป|๐Ÿ‘ฐ๐Ÿผ|๐Ÿ‘ฐ๐Ÿฝ|๐Ÿ‘ฐ๐Ÿพ|๐Ÿ‘ฐ๐Ÿฟ|๐Ÿคฐ๐Ÿป|๐Ÿคฐ๐Ÿผ|๐Ÿคฐ๐Ÿฝ|๐Ÿคฐ๐Ÿพ|๐Ÿคฐ๐Ÿฟ|๐Ÿคฑ๐Ÿป|๐Ÿคฑ๐Ÿผ|๐Ÿคฑ๐Ÿฝ|๐Ÿคฑ๐Ÿพ|๐Ÿคฑ๐Ÿฟ|๐Ÿ‘ผ๐Ÿป|๐Ÿ‘ผ๐Ÿผ|๐Ÿ‘ผ๐Ÿฝ|๐Ÿ‘ผ๐Ÿพ|๐Ÿ‘ผ๐Ÿฟ|๐ŸŽ…๐Ÿป|๐ŸŽ…๐Ÿผ|๐ŸŽ…๐Ÿฝ|๐ŸŽ…๐Ÿพ|๐ŸŽ…๐Ÿฟ|๐Ÿคถ๐Ÿป|๐Ÿคถ๐Ÿผ|๐Ÿคถ๐Ÿฝ|๐Ÿคถ๐Ÿพ|๐Ÿคถ๐Ÿฟ|๐Ÿฆธ๐Ÿป|๐Ÿฆธ๐Ÿผ|๐Ÿฆธ๐Ÿฝ|๐Ÿฆธ๐Ÿพ|๐Ÿฆธ๐Ÿฟ|๐Ÿฆน๐Ÿป|๐Ÿฆน๐Ÿผ|๐Ÿฆน๐Ÿฝ|๐Ÿฆน๐Ÿพ|๐Ÿฆน๐Ÿฟ|๐Ÿง™๐Ÿป|๐Ÿง™๐Ÿผ|๐Ÿง™๐Ÿฝ|๐Ÿง™๐Ÿพ|๐Ÿง™๐Ÿฟ|๐Ÿงš๐Ÿป|๐Ÿงš๐Ÿผ|๐Ÿงš๐Ÿฝ|๐Ÿงš๐Ÿพ|๐Ÿงš๐Ÿฟ|๐Ÿง›๐Ÿป|๐Ÿง›๐Ÿผ|๐Ÿง›๐Ÿฝ|๐Ÿง›๐Ÿพ|๐Ÿง›๐Ÿฟ|๐Ÿงœ๐Ÿป|๐Ÿงœ๐Ÿผ|๐Ÿงœ๐Ÿฝ|๐Ÿงœ๐Ÿพ|๐Ÿงœ๐Ÿฟ|๐Ÿง๐Ÿป|๐Ÿง๐Ÿผ|๐Ÿง๐Ÿฝ|๐Ÿง๐Ÿพ|๐Ÿง๐Ÿฟ|๐Ÿ’†๐Ÿป|๐Ÿ’†๐Ÿผ|๐Ÿ’†๐Ÿฝ|๐Ÿ’†๐Ÿพ|๐Ÿ’†๐Ÿฟ|๐Ÿ’‡๐Ÿป|๐Ÿ’‡๐Ÿผ|๐Ÿ’‡๐Ÿฝ|๐Ÿ’‡๐Ÿพ|๐Ÿ’‡๐Ÿฟ|๐Ÿšถ๐Ÿป|๐Ÿšถ๐Ÿผ|๐Ÿšถ๐Ÿฝ|๐Ÿšถ๐Ÿพ|๐Ÿšถ๐Ÿฟ|๐Ÿง๐Ÿป|๐Ÿง๐Ÿผ|๐Ÿง๐Ÿฝ|๐Ÿง๐Ÿพ|๐Ÿง๐Ÿฟ|๐ŸงŽ๐Ÿป|๐ŸงŽ๐Ÿผ|๐ŸงŽ๐Ÿฝ|๐ŸงŽ๐Ÿพ|๐ŸงŽ๐Ÿฟ|๐Ÿƒ๐Ÿป|๐Ÿƒ๐Ÿผ|๐Ÿƒ๐Ÿฝ|๐Ÿƒ๐Ÿพ|๐Ÿƒ๐Ÿฟ|๐Ÿ’ƒ๐Ÿป|๐Ÿ’ƒ๐Ÿผ|๐Ÿ’ƒ๐Ÿฝ|๐Ÿ’ƒ๐Ÿพ|๐Ÿ’ƒ๐Ÿฟ|๐Ÿ•บ๐Ÿป|๐Ÿ•บ๐Ÿผ|๐Ÿ•บ๐Ÿฝ|๐Ÿ•บ๐Ÿพ|๐Ÿ•บ๐Ÿฟ|๐Ÿ•ด๐Ÿป|๐Ÿ•ด๐Ÿผ|๐Ÿ•ด๐Ÿฝ|๐Ÿ•ด๐Ÿพ|๐Ÿ•ด๐Ÿฟ|๐Ÿง–๐Ÿป|๐Ÿง–๐Ÿผ|๐Ÿง–๐Ÿฝ|๐Ÿง–๐Ÿพ|๐Ÿง–๐Ÿฟ|๐Ÿง—๐Ÿป|๐Ÿง—๐Ÿผ|๐Ÿง—๐Ÿฝ|๐Ÿง—๐Ÿพ|๐Ÿง—๐Ÿฟ|๐Ÿ‡๐Ÿป|๐Ÿ‡๐Ÿผ|๐Ÿ‡๐Ÿฝ|๐Ÿ‡๐Ÿพ|๐Ÿ‡๐Ÿฟ|๐Ÿ‚๐Ÿป|๐Ÿ‚๐Ÿผ|๐Ÿ‚๐Ÿฝ|๐Ÿ‚๐Ÿพ|๐Ÿ‚๐Ÿฟ|๐ŸŒ๐Ÿป|๐ŸŒ๐Ÿผ|๐ŸŒ๐Ÿฝ|๐ŸŒ๐Ÿพ|๐ŸŒ๐Ÿฟ|๐Ÿ„๐Ÿป|๐Ÿ„๐Ÿผ|๐Ÿ„๐Ÿฝ|๐Ÿ„๐Ÿพ|๐Ÿ„๐Ÿฟ|๐Ÿšฃ๐Ÿป|๐Ÿšฃ๐Ÿผ|๐Ÿšฃ๐Ÿฝ|๐Ÿšฃ๐Ÿพ|๐Ÿšฃ๐Ÿฟ|๐ŸŠ๐Ÿป|๐ŸŠ๐Ÿผ|๐ŸŠ๐Ÿฝ|๐ŸŠ๐Ÿพ|๐ŸŠ๐Ÿฟ|๐Ÿ‹๐Ÿป|๐Ÿ‹๐Ÿผ|๐Ÿ‹๐Ÿฝ|๐Ÿ‹๐Ÿพ|๐Ÿ‹๐Ÿฟ|๐Ÿšด๐Ÿป|๐Ÿšด๐Ÿผ|๐Ÿšด๐Ÿฝ|๐Ÿšด๐Ÿพ|๐Ÿšด๐Ÿฟ|๐Ÿšต๐Ÿป|๐Ÿšต๐Ÿผ|๐Ÿšต๐Ÿฝ|๐Ÿšต๐Ÿพ|๐Ÿšต๐Ÿฟ|๐Ÿคธ๐Ÿป|๐Ÿคธ๐Ÿผ|๐Ÿคธ๐Ÿฝ|๐Ÿคธ๐Ÿพ|๐Ÿคธ๐Ÿฟ|๐Ÿคฝ๐Ÿป|๐Ÿคฝ๐Ÿผ|๐Ÿคฝ๐Ÿฝ|๐Ÿคฝ๐Ÿพ|๐Ÿคฝ๐Ÿฟ|๐Ÿคพ๐Ÿป|๐Ÿคพ๐Ÿผ|๐Ÿคพ๐Ÿฝ|๐Ÿคพ๐Ÿพ|๐Ÿคพ๐Ÿฟ|๐Ÿคน๐Ÿป|๐Ÿคน๐Ÿผ|๐Ÿคน๐Ÿฝ|๐Ÿคน๐Ÿพ|๐Ÿคน๐Ÿฟ|๐Ÿง˜๐Ÿป|๐Ÿง˜๐Ÿผ|๐Ÿง˜๐Ÿฝ|๐Ÿง˜๐Ÿพ|๐Ÿง˜๐Ÿฟ|๐Ÿ›€๐Ÿป|๐Ÿ›€๐Ÿผ|๐Ÿ›€๐Ÿฝ|๐Ÿ›€๐Ÿพ|๐Ÿ›€๐Ÿฟ|๐Ÿ›Œ๐Ÿป|๐Ÿ›Œ๐Ÿผ|๐Ÿ›Œ๐Ÿฝ|๐Ÿ›Œ๐Ÿพ|๐Ÿ›Œ๐Ÿฟ|๐Ÿ‘ญ๐Ÿป|๐Ÿ‘ญ๐Ÿผ|๐Ÿ‘ญ๐Ÿฝ|๐Ÿ‘ญ๐Ÿพ|๐Ÿ‘ญ๐Ÿฟ|๐Ÿ‘ซ๐Ÿป|๐Ÿ‘ซ๐Ÿผ|๐Ÿ‘ซ๐Ÿฝ|๐Ÿ‘ซ๐Ÿพ|๐Ÿ‘ซ๐Ÿฟ|๐Ÿ‘ฌ๐Ÿป|๐Ÿ‘ฌ๐Ÿผ|๐Ÿ‘ฌ๐Ÿฝ|๐Ÿ‘ฌ๐Ÿพ|๐Ÿ‘ฌ๐Ÿฟ|๐Ÿ’๐Ÿป|๐Ÿ’๐Ÿผ|๐Ÿ’๐Ÿฝ|๐Ÿ’๐Ÿพ|๐Ÿ’๐Ÿฟ|๐Ÿ’‘๐Ÿป|๐Ÿ’‘๐Ÿผ|๐Ÿ’‘๐Ÿฝ|๐Ÿ’‘๐Ÿพ|๐Ÿ’‘๐Ÿฟ|#๏ธโƒฃ|0๏ธโƒฃ|1๏ธโƒฃ|2๏ธโƒฃ|3๏ธโƒฃ|4๏ธโƒฃ|5๏ธโƒฃ|6๏ธโƒฃ|7๏ธโƒฃ|8๏ธโƒฃ|9๏ธโƒฃ|โœ‹๐Ÿป|โœ‹๐Ÿผ|โœ‹๐Ÿฝ|โœ‹๐Ÿพ|โœ‹๐Ÿฟ|โœŒ๐Ÿป|โœŒ๐Ÿผ|โœŒ๐Ÿฝ|โœŒ๐Ÿพ|โœŒ๐Ÿฟ|โ˜๐Ÿป|โ˜๐Ÿผ|โ˜๐Ÿฝ|โ˜๐Ÿพ|โ˜๐Ÿฟ|โœŠ๐Ÿป|โœŠ๐Ÿผ|โœŠ๐Ÿฝ|โœŠ๐Ÿพ|โœŠ๐Ÿฟ|โœ๐Ÿป|โœ๐Ÿผ|โœ๐Ÿฝ|โœ๐Ÿพ|โœ๐Ÿฟ|โ›น๐Ÿป|โ›น๐Ÿผ|โ›น๐Ÿฝ|โ›น๐Ÿพ|โ›น๐Ÿฟ|๐Ÿ˜€|๐Ÿ˜ƒ|๐Ÿ˜„|๐Ÿ˜|๐Ÿ˜†|๐Ÿ˜…|๐Ÿคฃ|๐Ÿ˜‚|๐Ÿ™‚|๐Ÿ™ƒ|๐Ÿ˜‰|๐Ÿ˜Š|๐Ÿ˜‡|๐Ÿฅฐ|๐Ÿ˜|๐Ÿคฉ|๐Ÿ˜˜|๐Ÿ˜—|๐Ÿ˜š|๐Ÿ˜™|๐Ÿฅฒ|๐Ÿ˜‹|๐Ÿ˜›|๐Ÿ˜œ|๐Ÿคช|๐Ÿ˜|๐Ÿค‘|๐Ÿค—|๐Ÿคญ|๐Ÿคซ|๐Ÿค”|๐Ÿค|๐Ÿคจ|๐Ÿ˜|๐Ÿ˜‘|๐Ÿ˜ถ|๐Ÿ˜|๐Ÿ˜’|๐Ÿ™„|๐Ÿ˜ฌ|๐Ÿคฅ|๐Ÿ˜Œ|๐Ÿ˜”|๐Ÿ˜ช|๐Ÿคค|๐Ÿ˜ด|๐Ÿ˜ท|๐Ÿค’|๐Ÿค•|๐Ÿคข|๐Ÿคฎ|๐Ÿคง|๐Ÿฅต|๐Ÿฅถ|๐Ÿฅด|๐Ÿ˜ต|๐Ÿคฏ|๐Ÿค |๐Ÿฅณ|๐Ÿฅธ|๐Ÿ˜Ž|๐Ÿค“|๐Ÿง|๐Ÿ˜•|๐Ÿ˜Ÿ|๐Ÿ™|๐Ÿ˜ฎ|๐Ÿ˜ฏ|๐Ÿ˜ฒ|๐Ÿ˜ณ|๐Ÿฅบ|๐Ÿ˜ฆ|๐Ÿ˜ง|๐Ÿ˜จ|๐Ÿ˜ฐ|๐Ÿ˜ฅ|๐Ÿ˜ข|๐Ÿ˜ญ|๐Ÿ˜ฑ|๐Ÿ˜–|๐Ÿ˜ฃ|๐Ÿ˜ž|๐Ÿ˜“|๐Ÿ˜ฉ|๐Ÿ˜ซ|๐Ÿฅฑ|๐Ÿ˜ค|๐Ÿ˜ก|๐Ÿ˜ |๐Ÿคฌ|๐Ÿ˜ˆ|๐Ÿ‘ฟ|๐Ÿ’€|๐Ÿ’ฉ|๐Ÿคก|๐Ÿ‘น|๐Ÿ‘บ|๐Ÿ‘ป|๐Ÿ‘ฝ|๐Ÿ‘พ|๐Ÿค–|๐Ÿ˜บ|๐Ÿ˜ธ|๐Ÿ˜น|๐Ÿ˜ป|๐Ÿ˜ผ|๐Ÿ˜ฝ|๐Ÿ™€|๐Ÿ˜ฟ|๐Ÿ˜พ|๐Ÿ™ˆ|๐Ÿ™‰|๐Ÿ™Š|๐Ÿ’‹|๐Ÿ’Œ|๐Ÿ’˜|๐Ÿ’|๐Ÿ’–|๐Ÿ’—|๐Ÿ’“|๐Ÿ’ž|๐Ÿ’•|๐Ÿ’Ÿ|๐Ÿ’”|๐Ÿงก|๐Ÿ’›|๐Ÿ’š|๐Ÿ’™|๐Ÿ’œ|๐ŸคŽ|๐Ÿ–ค|๐Ÿค|๐Ÿ’ฏ|๐Ÿ’ข|๐Ÿ’ฅ|๐Ÿ’ซ|๐Ÿ’ฆ|๐Ÿ’จ|๐Ÿ•ณ|๐Ÿ’ฃ|๐Ÿ’ฌ|๐Ÿ—จ|๐Ÿ—ฏ|๐Ÿ’ญ|๐Ÿ’ค|๐Ÿ‘‹|๐Ÿคš|๐Ÿ–|๐Ÿ––|๐Ÿ‘Œ|๐ŸคŒ|๐Ÿค|๐Ÿคž|๐ŸคŸ|๐Ÿค˜|๐Ÿค™|๐Ÿ‘ˆ|๐Ÿ‘‰|๐Ÿ‘†|๐Ÿ–•|๐Ÿ‘‡|๐Ÿ‘|๐Ÿ‘Ž|๐Ÿ‘Š|๐Ÿค›|๐Ÿคœ|๐Ÿ‘|๐Ÿ™Œ|๐Ÿ‘|๐Ÿคฒ|๐Ÿค|๐Ÿ™|๐Ÿ’…|๐Ÿคณ|๐Ÿ’ช|๐Ÿฆพ|๐Ÿฆฟ|๐Ÿฆต|๐Ÿฆถ|๐Ÿ‘‚|๐Ÿฆป|๐Ÿ‘ƒ|๐Ÿง |๐Ÿซ€|๐Ÿซ|๐Ÿฆท|๐Ÿฆด|๐Ÿ‘€|๐Ÿ‘|๐Ÿ‘…|๐Ÿ‘„|๐Ÿ‘ถ|๐Ÿง’|๐Ÿ‘ฆ|๐Ÿ‘ง|๐Ÿง‘|๐Ÿ‘ฑ|๐Ÿ‘จ|๐Ÿง”|๐Ÿ‘ฉ|๐Ÿง“|๐Ÿ‘ด|๐Ÿ‘ต|๐Ÿ™|๐Ÿ™Ž|๐Ÿ™…|๐Ÿ™†|๐Ÿ’|๐Ÿ™‹|๐Ÿง|๐Ÿ™‡|๐Ÿคฆ|๐Ÿคท|๐Ÿ‘ฎ|๐Ÿ•ต|๐Ÿ’‚|๐Ÿฅท|๐Ÿ‘ท|๐Ÿคด|๐Ÿ‘ธ|๐Ÿ‘ณ|๐Ÿ‘ฒ|๐Ÿง•|๐Ÿคต|๐Ÿ‘ฐ|๐Ÿคฐ|๐Ÿคฑ|๐Ÿ‘ผ|๐ŸŽ…|๐Ÿคถ|๐Ÿฆธ|๐Ÿฆน|๐Ÿง™|๐Ÿงš|๐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โ˜ฆ|โ˜ช|โ˜ฎ|โ™ˆ|โ™‰|โ™Š|โ™‹|โ™Œ|โ™|โ™Ž|โ™|โ™|โ™‘|โ™’|โ™“|โ›Ž|โ–ถ|โฉ|โญ|โฏ|โ—€|โช|โฎ|โซ|โฌ|โธ|โน|โบ|โ|โ™€|โ™‚|โšง|โœ–|โž•|โž–|โž—|โ™พ|โ€ผ|โ‰|โ“|โ”|โ•|โ—|ใ€ฐ|โš•|โ™ป|โšœ|โญ•|โœ…|โ˜‘|โœ”|โŒ|โŽ|โžฐ|โžฟ|ใ€ฝ|โœณ|โœด|โ‡|ยฉ|ยฎ|โ„ข|โ„น|โ“‚|ใŠ—|ใŠ™|โšซ|โšช|โฌ›|โฌœ|โ—ผ|โ—ป|โ—พ|โ—ฝ|โ–ช|โ–ซ)`
/*compile the pattern string into a regex*/
let emoRegex = new RegExp(emojiPattern, "g");
/*count of emojis*/
let emoCount = [..."๐Ÿ‘ถ๐Ÿป๐Ÿ‘ฆ๐Ÿป๐Ÿ‘ง๐Ÿป๐Ÿ‘จ๐Ÿป๐Ÿ‘ฉ๐Ÿป๐Ÿ‘ฑ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฑ๐Ÿป๐Ÿ‘ด๐Ÿป๐Ÿ‘ต๐Ÿป๐Ÿ‘ฒ๐Ÿป๐Ÿ‘ณ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ณ๐Ÿป๐Ÿ‘ฎ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฎ๐Ÿป๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ๐Ÿ‘ท๐Ÿป๐Ÿ’‚๐Ÿปโ€โ™€๏ธ๐Ÿ’‚๐Ÿป๐Ÿ•ต๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฉ๐Ÿปโ€โš•๏ธ๐Ÿ‘จ๐Ÿปโ€โš•๏ธ๐Ÿ‘ฉ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ".matchAll(emoRegex)].length
console.log(emoCount) //37
/*modifying the pattern to count other characters too*/
let generalCounter = new RegExp(emojiPattern+"|.", "g") //emoji or regular character
let allCount = [..."$%^ other stuff equalling 28๐Ÿ‘ถ๐Ÿ‘ฆ๐Ÿป๐Ÿ‘ง๐Ÿป๐Ÿ‘จ๐Ÿป๐Ÿ‘ฉ๐Ÿป๐Ÿ‘ฑ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฑ๐Ÿป๐Ÿ‘ด๐Ÿป๐Ÿ‘ต๐Ÿป๐Ÿ‘ฒ๐Ÿป๐Ÿ‘ณ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ณ๐Ÿป๐Ÿ‘ฎ๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฎ๐Ÿป๐Ÿ‘ท๐Ÿปโ€โ™€๏ธ๐Ÿ‘ท๐Ÿป๐Ÿ’‚๐Ÿปโ€โ™€๏ธ๐Ÿ’‚๐Ÿป๐Ÿ•ต๐Ÿปโ€โ™€๏ธ๐Ÿ‘ฉ๐Ÿปโ€โš•๏ธ๐Ÿ‘จ๐Ÿปโ€โš•๏ธ๐Ÿ‘ฉ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ๐Ÿ‘จ๐Ÿปโ€๐ŸŒพ".matchAll(generalCounter)].length
console.log(allCount) //28+37 = 65
As you can see from the below example, this is to do with unicode encoding,
There's some great resources such as the one I took this example from.
https://blog.jonnew.com/posts/poo-dot-length-equals-two
console.log("๐Ÿ‘ฉโ€โค๏ธโ€๐Ÿ’‹โ€๐Ÿ‘ฉ".length === 11);
For anyone interested, I had a similar problem where I wanted to count the length of an emoji at the end of a string.
This is the solution I came up with:
var emoji = new RegExp('(\\p{Extended_Pictographic})((\u200D\\p{Extended_Pictographic})*)$', 'u');
var testStrings = ['๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง', '๐Ÿ˜‚', '๐ŸŒฒ'];
for(var string = 0; string < testStrings.length; string++){
var match = testStrings[string].match(emoji);
var chars = match == null ? 0 : match[0].length;
console.log(testStrings[string] + ': ' + chars);
}
Explanation: \\p{Extended_Pictographic} matches an emoji like ๐Ÿ˜‚, consisting of two characters. Emojis like ๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง consists of 4 emojis (๐Ÿ‘จ, ๐Ÿ‘ฉ, ๐Ÿ‘ง,๐Ÿ‘ฆ) combined by a zero width joiner (\u200D).
The regex matches any emoji at the end ($). If there is a match the length is counted. I am sure it could be adopted for your use-case by matching all emojis in a given string and then subtracting the surplus. It's not a complete implementation for your particular question but I hope this gets you on the right track.
use lodash toArray method
console.log(_.toArray("๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง").length); // 1
console.log(_.toArray("๐Ÿ‘จโ€๐Ÿ‘ฉโ€๐Ÿ‘ง๐Ÿงโ€โ™‚๏ธ๐Ÿ‘ฉโ€๐Ÿ‘งโ€๐Ÿ‘ง").length); // 3
Check here for Codesandbox
I suggest using the runes package to accomplish correct multi-byte string conversions cause else you will get more issues if using reducers and more to reverse strings for example.
Take a look at this great small package: runes

JavaScript + RegEx Complications- Searching Strings Not Containing SubString

I am trying to use a RegEx to search through a long string, and I am having trouble coming up with an expression. I am trying to search through some HTML for a set of tags beginning with a tag containing a certain value and ending with a different tag containing another value. The code I am currently using to attempt this is as follows:
matcher = new RegExp(".*(<[^>]+" + startText + "((?!" + endText + ").)*" + endText + ")", 'g');
data.replace(matcher, "$1");
The strangeness around the middle ( ((\\?\\!endText).)* ) is borrowed from another thread, found here, that seems to describe my problem. The issue I am facing is that the expression matches the beginning tag, but it does not find the ending tag and instead includes the remainder of the data. Also, the lookaround in the middle slowed the expression down a lot. Any suggestions as to how I can get this working?
EDIT: I understand that parsing HTML in RegEx isn't the best option (makes me feel dirty), but I'm in a time-crunch and any other alternative I can think of will take too long. It's hard to say what exactly the markup I will be parsing will look like, as I am creating it on the fly. The best I can do is to say that I am looking at a large table of data that is collected for a range of items on a range of dates. Both of these ranges can vary, and I am trying to select a certain range of dates from a single row. The approximate value of startText and endText are \\#\\#ASSET_ID\\#\\#_<YYYY_MM_DD>. The idea is to find the code that corresponds to this range of cells. (This edit could quite possibly have made this even more confusing, but I'm not sure how much more information I could really give without explaining the entire application).
EDIT: Well, this was a stupid question. Apparently, I just forgot to add .* after the last paren. Can't believe I spent so long on this! Thanks to those of you that tried to help!
First of all, why is there a .* Dot Asterisk in the beginning? If you have text like the following:
This is my Text
And you want "my Text" pulled out, you do my\sText. You don't have to do the .*.
That being said, since all you'll be matching now is what you need, you don't need the main Capture Group around "Everything". This: .*(xxx) is a huge no-no, and can almost always be replaced with this: xxx. In other words, your regex could be replaced with:
<[^>]+xxx((?!zzz).)*zzz
From there I examine what it's doing.
You are looking for an HTML opening Delimeter <. You consume it.
You consume at least one character that is NOT a Closing HTML Delimeter, but can consume many. This is important, because if your tag is <table border=2>, then you have, at minimum, so far consumed <t, if not more.
You are now looking for a StartText. If that StartText is table, you'll never find it, because you have consumed the t. So replace that + with a *.
The regex is still success if the following is NOT the closing text, but starts from the VERY END of the document, because the Asterisk is being Greedy. I suggest making it lazy by adding a ?.
When the backtracking fails, it will look for the closing text and gather it successfully.
The result of that logic:
<[^>]*xxx((?!zzz).)*?zzz
If you're going to use a dot anyway, which is okay for new Regex writers, but not suggested for seasoned, I'd go with this:
<[^>]*xxx.*?zzz
So for Javascript, your code would say:
matcher = new RegExp("<[^>]*" + startText + ".*?" + endText, 'gi');
I put the IgnoreCase "i" in there for good measure, but you may or may not want that.

Line length for lines with strings

Being obsessed with neatness in Javascript lately, I was curious about whether there is some type of common practice about how to deal with lines that span over 80 cols due to string length. With innerHTML I can mark line breaks with a backslash and indentation spaces won't show up in the content of the element, but that doesn't seem to go for eg. console.log().
Are there any conventions for this or should I just learn to live with lines longer than 80 cols? :)
There's no universal convention. With modern high-res monitors you can easily fit 160 columns and still have room for IDE toolbars without needing to scroll, so I wouldn't be concerned about sticking to 80 columns.
Some people go out of their way to never have any line of code go past n columns, where n might be 80, or 160, or some other arbitrary number based on what fits for their preferred font and screen resolution. Some people I work with don't care and have lines that go way off to the right regardless of whether it is due to a long string or a function with lots of parameters or whatever.
I try to avoid any horizontal scrolling but I don't obsess about it so if I have a string constant that is particularly long I will probably put it all on one line. If I have a string that is built up by concatenating constants and variables I will split it over several lines, because that statement will already have several + operators that are a natural place to add line breaks. If I have a function with lots of parameters, more than would fit without scrolling, I will put each parameter on a newline. For an if statement with a lot of conditions I'd probably break that over several lines.
Regarding what you mentioned about innerHTML versus console.log(): if you break a string constant across lines in your source code by including a backslash and newline then any indenting spaces you put on the second line will become part of the string:
var myString1 = "This has been broken\
into two lines.";
// equivalent to
var myString2 = "This has been broken into two lines.";
// NOT equivalent to
var myString3 = "This has been broken\
into two lines.";
If you use that string for innerHTML the spaces will be treated the same as spaces in your HTML source, i.e., the browser will display it with multiple spaces compressed down to a single space. But for any other uses of the string in your code including console.log() the space characters will all be included.
If horizontal scrolling really bothers you and you have a long string the following method lets you have indenting without extra spaces in the string:
var myString3 = "Hi there, this has been broken"
+ " into several lines by concatenating"
+ " a number of shorter strings.";

removing phpbb tag using regex javascript

I'm trying to remove a rectangular brackets(bbcode style) using javascript, this is for removing unwanted bbcode.
I try with this.
theString .replace(/\[quote[^\/]+\]*\[\/quote\]/, "")
it works with this string sample:
theString = "[quote=MyName;225]Test 123[/quote]";
it will fail within this sample:
theString = "[quote=MyName;225]Test [quote]inside quotes[/quote]123[/quote]";
if there any solution beside regex no problem
The other 2 solutions simply do not work (see my comments). To solve this problem you first need to craft a regex which matches the innermost matching quote elements (which contain neither [QUOTE..] nor [/QUOTE]). Next, you need to iterate, applying this regex over and over until there are no more QUOTE elements left. This tested function does what you want:
function filterQuotes(text)
{ // Regex matches inner [QUOTE]non-quote-stuff[/quote] tag.
var re = /\[quote[^\[]+(?:(?!\[\/?quote\b)\[[^\[]*)*\[\/quote\]/ig;
while (text.search(re) !== -1)
{ // Need to iterate removing QUOTEs from inside out.
text = text.replace(re, "");
}
return text;
}
Note that this regex employs Jeffrey Friedl's "Unrolling the loop" efficiency technique and is not only accurate, but is quite fast to boot.
See: Mastering Regular Expressions (3rd Edition) (highly recommended).
Try this one:
/\[quote[^\/]+\].*\[\/quote\]$/
The $ sign indicates that only the closing quote element at the end of the string should be used to determine the ending of the quote you're trying to remove.
And i added a "." before the asterisk so that this will match any sign in between. I tested this with your two strings and it worked.
edit: I don't exactly know how you are using that. But just as an addition. If you want the pattern also to match to a string where no attributes are added for example:
[quote]Hello[/quote]
You should change the "+" sign into an asterisk as well like this:
/\[quote[^\/]*\].*\[\/quote\]$/
This answer has flaws, see Ridgerunner's answer for a more correct one.
Here's my crack at it.
function filterQuotes(text)
{
return text.replace(/\[(\/)?quote([^\/]*)?\]/g,"");
}

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