I wrote a javascript function for Telerik RadTreeView as follows:
function CheckedNodeValues() {
var checkedNodes = $(this).get_checkedNodes();
for (var n in checkedNodes) {
checkedNodes[n].get_value();
}
}
I would like to be able to do myRadTreeView.CheckedNodeValues() as opposed to CheckedNodeValues(myRadTreeView);
Is there a way to add a function to a class in Javascript?
I hope what I'm asking is clear, ideally, I would like extend the methods available on a class.
You should extend the prototype of your object, like this:
myRadTreeView.prototype.CheckedNodeValues = function () {
// your code here
};
You can read more about the prototype concept here: http://www.javascriptkit.com/javatutors/proto.shtml or here: http://javascriptweblog.wordpress.com/2010/06/07/understanding-javascript-prototypes/
Something like this should do ..
Telerik.Web.UI.RadTreeView.prototype.CheckedNodeValues = function() {
var checkedNodes = $(this).get_checkedNodes();
for (var n in checkedNodes) {
checkedNodes[n].get_value();
}
}
Absolutely:
myRadTreeView.CheckedNodeValues = function () {
// do totally rad stuff here
};
To call it you would use:
myRadTreeView.CheckedNodeValues();
Related
The main reason why I want it is that I want to extend my initialize function.
Something like this:
// main.js
window.onload = init();
function init(){
doSomething();
}
// extend.js
function extends init(){
doSomethingHereToo();
}
So I want to extend a function like I extend a class in PHP.
And I would like to extend it from other files too, so for example I have the original init function in main.js and the extended function in extended.js.
With a wider view of what you're actually trying to do and the context in which you're doing it, I'm sure we could give you a better answer than the literal answer to your question.
But here's a literal answer:
If you're assigning these functions to some property somewhere, you can wrap the original function and put your replacement on the property instead:
// Original code in main.js
var theProperty = init;
function init(){
doSomething();
}
// Extending it by replacing and wrapping, in extended.js
theProperty = (function(old) {
function extendsInit() {
old();
doSomething();
}
return extendsInit;
})(theProperty);
If your functions aren't already on an object, you'd probably want to put them there to facilitate the above. For instance:
// In main.js
var MyLibrary = {
init: function init() {
}
};
// In extended.js
(function() {
var oldInit = MyLibrary.init;
MyLibrary.init = extendedInit;
function extendedInit() {
oldInit.call(MyLibrary); // Use #call in case `init` uses `this`
doSomething();
}
})();
But there are better ways to do that. Like for instance, providing a means of registering init functions.
// In main.js
var MyLibrary = (function() {
var initFunctions = [];
return {
init: function init() {
var fns = initFunctions;
initFunctions = undefined;
for (var index = 0; index < fns.length; ++index) {
try { fns[index](); } catch (e) { }
}
},
addInitFunction: function addInitFunction(fn) {
if (initFunctions) {
// Init hasn't run yet, remember it
initFunctions.push(fn);
} else {
// `init` has already run, call it almost immediately
// but *asynchronously* (so the caller never sees the
// call synchronously)
setTimeout(fn, 0);
}
}
};
})();
Here in 2020 (or really any time after ~2016), that can be written a bit more compactly:
// In main.js
const MyLibrary = (() => {
let initFunctions = [];
return {
init() {
const fns = initFunctions;
initFunctions = undefined;
for (const fn of fns) {
try { fn(); } catch (e) { }
}
},
addInitFunction(fn) {
if (initFunctions) {
// Init hasn't run yet, remember it
initFunctions.push(fn);
} else {
// `init` has already run, call it almost immediately
// but *asynchronously* (so the caller never sees the
// call synchronously)
setTimeout(fn, 0);
// Or: `Promise.resolve().then(() => fn());`
// (Not `.then(fn)` just to avoid passing it an argument)
}
}
};
})();
There are several ways to go about this, it depends what your purpose is, if you just want to execute the function as well and in the same context, you can use .apply():
function init(){
doSomething();
}
function myFunc(){
init.apply(this, arguments);
doSomethingHereToo();
}
If you want to replace it with a newer init, it'd look like this:
function init(){
doSomething();
}
//anytime later
var old_init = init;
init = function() {
old_init.apply(this, arguments);
doSomethingHereToo();
};
The other methods are great but they don't preserve any prototype functions attached to init. To get around that you can do the following (inspired by the post from Nick Craver).
(function () {
var old_prototype = init.prototype;
var old_init = init;
init = function () {
old_init.apply(this, arguments);
// Do something extra
};
init.prototype = old_prototype;
}) ();
Another option could be:
var initial = function() {
console.log( 'initial function!' );
}
var iWantToExecuteThisOneToo = function () {
console.log( 'the other function that i wanted to execute!' );
}
function extendFunction( oldOne, newOne ) {
return (function() {
oldOne();
newOne();
})();
}
var extendedFunction = extendFunction( initial, iWantToExecuteThisOneToo );
2017+ solution
The idea of function extensions comes from functional paradigm, which is natively supported since ES6:
function init(){
doSomething();
}
// extend.js
init = (f => u => { f(u)
doSomethingHereToo();
})(init);
init();
As per #TJCrowder's concern about stack dump, the browsers handle the situation much better today. If you save this code into test.html and run it, you get
test.html:3 Uncaught ReferenceError: doSomething is not defined
at init (test.html:3)
at test.html:8
at test.html:12
Line 12: the init call, Line 8: the init extension, Line 3: the undefined doSomething() call.
Note: Much respect to veteran T.J. Crowder, who kindly answered my question many years ago, when I was a newbie. After the years, I still remember the respectfull attitude and I try to follow the good example.
This is very simple and straight forward. Look at the code. Try to grasp the basic concept behind javascript extension.
First let us extend javascript function.
function Base(props) {
const _props = props
this.getProps = () => _props
// We can make method private by not binding it to this object.
// Hence it is not exposed when we return this.
const privateMethod = () => "do internal stuff"
return this
}
You can extend this function by creating child function in following way
function Child(props) {
const parent = Base(props)
this.getMessage = () => `Message is ${parent.getProps()}`;
// You can remove the line below to extend as in private inheritance,
// not exposing parent function properties and method.
this.prototype = parent
return this
}
Now you can use Child function as follows,
let childObject = Child("Secret Message")
console.log(childObject.getMessage()) // logs "Message is Secret Message"
console.log(childObject.getProps()) // logs "Secret Message"
We can also create Javascript Function by extending Javascript classes, like this.
class BaseClass {
constructor(props) {
this.props = props
// You can remove the line below to make getProps method private.
// As it will not be binded to this, but let it be
this.getProps = this.getProps.bind(this)
}
getProps() {
return this.props
}
}
Let us extend this class with Child function like this,
function Child(props) {
let parent = new BaseClass(props)
const getMessage = () => `Message is ${parent.getProps()}`;
return { ...parent, getMessage} // I have used spread operator.
}
Again you can use Child function as follows to get similar result,
let childObject = Child("Secret Message")
console.log(childObject.getMessage()) // logs "Message is Secret Message"
console.log(childObject.getProps()) // logs "Secret Message"
Javascript is very easy language. We can do almost anything. Happy JavaScripting... Hope I was able to give you an idea to use in your case.
Use extendFunction.js
init = extendFunction(init, function(args) {
doSomethingHereToo();
});
But in your specific case, it's easier to extend the global onload function:
extendFunction('onload', function(args) {
doSomethingHereToo();
});
I actually really like your question, it's making me think about different use cases.
For javascript events, you really want to add and remove handlers - but for extendFunction, how could you later remove functionality? I could easily add a .revert method to extended functions, so init = init.revert() would return the original function. Obviously this could lead to some pretty bad code, but perhaps it lets you get something done without touching a foreign part of the codebase.
In my case, I'm using the Phaser framework.
So in this example I'm extending the Group class of phaser. Every 'actor' class (Sprite, Group, ...) calls upon the update() prototype every few miliseconds.
My idea was to extend this function only when the application runs on a desktop (so not on a phone).
for example:
var MousePointer = function (game, parent, name) {
Phaser.Group.call(this, game, parent, name);
this.init();
};
MousePointer.prototype = Object.create(Phaser.Group.prototype);
MousePointer.prototype.constructor = MousePointer;
MousePointer.prototype.init = function () {
// ... init
};
MousePointer.prototype.update = function () {
// Do something when on desktop
};
I can't possibly use an if clausule in the update() function to check whether the player is on dekstop/tablet/phone. So is there a way to actually override the prototype on initialisation?
for example (pseudocode):
if(onPhone)
MousePointer.prototype.update = parent.prototype.update;
else
MousePointer.prototype.update = this.update;
Well, you've kind of already written the answer for yourself, haven't you? This code (not inside the init method).
if(onPhone) {
MousePointer.prototype.update = function(){//Phone implementation};
} else {
MousePointer.prototype.update = function(){//Other implementation};
}
I advise against starting off with the "regular" function and then potentially overriding it, since you're just declaring it for nothing.
I think a better way to do this would be to write two different classes that shares the same parent, and then write different update() implementations for them. Then you can just do something like:
if(phone) {
var obj = new PhoneMousePointerObject();
} else {
var obj = new DesktopMousePointerObject();
}
// ... later
obj.update()
This is some JS code
var methodArr = ['firstFunc','secondFunc','thirdFunc'];
for(var i in methodArr)
{
window[methodName] = function()
{
console.log(methodName);
}
}
My problem is that how to get the name of a function in JS.
In JS, use this.callee.name.toString() can get the function name. But in this situation, it is a null value. How can i get the 'funName' string?
Sorry, I didn't make it clear.
I want to create functions in a for loop, all these functions has almost the same implementation which need its name. But others can call these functions use different name.I want to know what methodName function is called.
it seems a scope problem.
Try this:
var methodArr = ['firstFunc','secondFunc','thirdFunc'];
for(var i in methodArr) {
var methodName = methodArr[i]; // <---- this line missed in your code?
window[methodName] = (function(methodName) {
return function() {
console.log(methodName);
}
})(methodName);
}
window['secondFunc'](); // output: secondFunc
well i'm confuse about the line witch says "$.Recup ..." I don't know why it is named the same as the plugin name and what it's for.
(function ($) {
$.fn.Recup = function () {
var parametros = {
};
var tsic = true;
$.Recup = function (opciones) {
var Metodos = {
};
return Metodos;
};
$.Recup.anterior = function () {
};
$.Recup.siguiente = function () {
}
})(jQuery);
I'm refering to this code, What does $.Recup exactly do?it would be perfect if someone gives me an example please
$.Recup = function (opciones) {
var Metodos = {
};
return Metodos;
};
In this case it appears to be a questionable plugin design - especially since $.Recup is not assigned until $.fn.Recup is first called.
However, if it is "appropriately and/or well written" is another question that requires context of (intended) usage. For what it is worth, I would reject this code as written as it smells of misunderstood design and widely scoped side-effects.
Anyway, the way the function is assigned determines how the method can be called.
// let $ be jQuery, then:
$.fn.foo = function () { console.log("foo") }
$.bar = function () { console.log("bar") }
$.foo() // TypeError: $.foo is not a function
$.bar() // -> "bar"
$("sel").foo() // -> "foo"
$("sel").bar() // TypeError: $(..).bar is not a function
That is, $.fn.foo is like .each() - it does something based on the currently selected elements (which are represented by this). On the other hand, $.bar is like jQuery.each() - it provides a way to iterate over a general collection but is not related to a specific set of (previously) selected elements.
In general, a plugin should only add a single entry to $.fn, but directly adding to $ may be useful to expose utility functions - it should definitely be done with care.
Here are two approaches that fix the issue of incorrectly leaked data:
$.fn.Recup = function () {
var parametros = ..
var tsic = true;
// Most trivial change; then use recup in this scope
// (or child scopes) only. There is no $.Recup - yay!
var recup = function (opciones) {
};
// ..
}
Or, just expose as local methods:
$.fn.Recup = function () {
var parametros = ..
var tsic = true;
function anterior () {
}
function siguiente () {
}
// Just use simple functions in scope
}
This is a jQuery plugin.
jQuery.fn is an alias to jQuery's prototype. So this line lets you call the Recup function on instances of jQuery :
$('#myid').Recup();
Here's the documentation on creating jQuery plugins.
I'm trying to create a simple, small and basic javascript framework just for learning purposes.
But the thing is that i'm allready stuck at the very basics.
I'm trying to do something like this:
$('testdiv').testFunction();
And the code i've written for that:
var elementID;
var smallFramework = {
$:function(id) {
this.elementID = id;
},
testFunction:function() {
alert(this.elementID);
}
};
window.$ = smallFramework.$;
But in return I get:
$('testdiv) is undefined
Can anyone help me with this small and hopefully easy question?
To get the behavior you're expecting, you need the $ function to return an object with a method named testFunction.
Try:
var smallFramework = // an object for namespacing
{
$:function(id) // the core function - returns an object wrapping the id
{
return { // return an object literal
elementID: id, // holding the id passed in
testFunction: function() // and a simple method
{
alert(this.elementID);
}
};
}
};
Of course, there are many other ways to achieve the behavior you desire.
If you're trying to add methods to an HTML element you could do something along these lines.
$ = function( elementId ) {
var element = document.getElementById( elementId );
element.testFunction = function(){
alert( this.id );
return this; // for chaining
}
return element;
}
$('test').testFunction();
Try
smallFramework.$('testdiv');
instead. According to the code you posted, that's where your $ function ended up.
Or alternatively, it looks like you're trying to replicate something like jQuery. You might want to try something like this.
var $ = smallFramework = (function () {
var f =
{
find:function(id) {
f.elementID = id;
return f; //every function should return f, for chaining to work
},
testFunction:function() {
alert(f.elementID);
return f;
}
}
return f.find //the find function will be assigned to $.
//and also assigned to smallFramework.
//the find function returns f, so you get access to testFunction via chaining
// like $("blah").testFunction()
})() //note this function gets called immediately.
this code may look confusing to someone new to JavaScript because it depends heavily on the concept of closures. I suggest that if this doesn't make sense, spend some time at Douglas Crockford's JavaScript website. This is important because the code above will bite if you happen to use this in the find function because this won't be bound to f, as you may expect it to be when you use it from $ or smallFramework.