How would you go about finding a string constant that is not HTML-safe?
It appears the following searches for the individual characters.
var i = text.indexOf('»')
You'll first need to unescape the HTML in the pattern:
var i = text.indexOf(decodeHTML('»'));
function decodeHTML(s) { // e.g. using jQuery
return $('<div>' + s + '</div>').text();
}
var i = text.indexOf('\273')
would search for the actual character.
http://www.c-point.com/javascript_tutorial/special_characters.htm explains how to escape special characters in javascript.
Try looking at the html directly.
document.getElementById('search').innerHTML.indexOf('»')
Related
I found this snippet somewhere and it works like a charm:
var n = parseInt(e.find("span.favNum").text().replace(/./g, "")) + 1;
If I do it in a similar way it doesn't work anymore.
I do the following:
<div id ="test">6.987</div>
var test = $("#test");
var r = test.text().replace(/./g, "");
console.log("wrong ", r);
I know that I can replace it also like this:
var r = test.text().replace(".", "");
This works.
I would like to understand why the "stolen" snippet is working.
Any idea?
http://jsfiddle.net/nJZMf/3/
The original script is found here: http://wp-svbtle.themeskult.com/
You will find the snippet by viewing the source of index.html and searching for .replace.
You need to escape the "."
test.text().replace(/\./g, "");
The reason that the code in the page you linked to works, where yours doesn't, is that it's not the same regular expression. Here's what I found in that page (and similar code in several places)
r = n.text().replace( /,/g, "" )
where r is a jQuery object.
Note that the regular expression has a , inside the //, not a . like the code you had trouble with.
Comma is not a special character in regular expressions, so it needs no special treatment. Period has a special meaning. As the other answers pointed out, it matches all characters, and you need to prefix it with \ if you want to match . only.
Also note that .replace() is not jQuery code, it's JavaScript.
jQuery's .text() method returns a JavaScript String value. So anything you do with that string - such as the .replace() call - is actually a JavaScript String method.
The distinction is important when you want to research a problem: a search for "javascript string replace" will get you better information than "jquery replace".
It has to be var r = test.text().replace(/\./g, ""); instead of var r = test.text().replace(/./g, ""); because you need to escape the . in order for it to be replaced.
http://jsfiddle.net/mrk1989/nJZMf/4/
Solution because I add \ in var r = test.text().replace(/\./g, "");
The problem was that you did not escape dot.
But keep in mind that:
.replace(".", "");
.replace(/\./g, "");
are two different things.
For example: https://jsfiddle.net/rmhpkz9n/1/
I am trying to replace the string below with whitespaces using javascript
function replaceString()
{
var str = "ABC**EFG";
return str.replace(/\*/g, " ");
}
I received the result as ABC EFG but I expect the result to come with two whitespace.
I also tried the same thing using php str.replace but still get the same result.
Is there any other methods i can used to replace the individual asterisk with whitespace??
P/S: The return string will be used as part of the sql query
[UPDATE]
I ended up return the string without any replacement to sql, then I use sql replace function to perform replacement in the query.
If you're displaying the resulting string in an HTML element then two or more whitespaces will be displayed as only one whitespace. To workaround this fact, use instead:
return str.replace(/\*/g, ' ');
try this
return str.replace(/\*/g, ' ');
Buddy the problem is with the HTML compiler which has its own special rules of parsing
So it parses multiple spaces into one.This can work for HTML only.
Thats why use the GIFT tag .
<pre>
<p id="para"></p>
</pre>
<script> function replaceString()
{
var str = "ABC**EFG";
return str.replace(/\*/g," ");
}
document.getElementById("para").innerHTML=replaceString();
</script>
<script>
function replaceString()
{ var str1=String.fromCharCode(32,32);
var str = "ABC**EFG";
return str.replace(/\*/g,str1);
}
alert(replaceString());
</script>
return of function from above code can be used directly in mysql...
Finally found the best solution, I replace those special characters using percent-encoding (URL-encoding)
for my case: str.replace(/\*/g, "%20");
I am trying to extract a number from a string with regular expression as I am told this would be the best approach for what I am wanting to do.
Here is the string:
http://domain.com/uploads/2011/09/1142_GF-757-S-white.jpg&h=208&w=347&zc=1&q=90&a=c&s=&f=&cc=&ct=
and I am trying to extract 208 from (height) from the string. so I know I have to look for "&h=" in the expression but I don't know what to do after that. How can I match between that and the next "&" but not include them as well...
Thanks..
Regular expression to match an h url parameter containing an integer value.
[&?]h=(\d+)
The Javascript:
var match = /[&?]h=(\d+)/.exec(url_string);
alert(match[1]);
Learn more about Regular Expressions.
To get the entire h=xxxx parameter, you can use this generic function (which you can reuse elsewhere for other purposes) and pass it the desired key:
function getParameterFromURL(url, key) {
var re = new RegExp("[&?]" + key + "=([^&]*)");
var matches = url.match(re);
if (matches) {
return(matches[1]);
}
return(null);
}
var url = "http://domain.com/uploads/2011/09/1142_GF-757-S-white.jpg&h=208&w=347&zc=1&q=90&a=c&s=&f=&cc=&ct=";
var parm = getParameterFromURL(url, "h");
See http://jsfiddle.net/jfriend00/86MEy/ for a working demo.
I have some text content (read in from the HTML using jQuery) that looks like either of these examples:
<span>39.98</span><br />USD
or across multiple lines with an additional price, like:
<del>47.14</del>
<span>39.98</span><br />USD
The numbers could be formatted like
1,234.99
1239,99
1 239,99
etc (i.e. not just a normal decimal number). What I want to do is get just whatever value is inside the <span></span>.
This is what I've come up with so far, but I'm having problems with the multiline approach, and also the fact that there's potentially two numbers and I want to ignore the first one. I've tried variations of using ^ and $, and the "m" multiline modifier, but no luck.
var strRegex = new RegExp(".*<span>(.*?)</span>.*", "g");
var strPrice = strContent.replace(strRegex, '$1');
I could use jQuery here if there's a way to target the span tag inside a string (i.e. it's not the DOM we're dealing with at this point).
You could remove all line breaks from the string first and then run your regex:
strContent = strContent.replace(/(\r\n|\n|\r)/gm,"");
var strRegex = new RegExp(".*<span>(.*?)</span>.*", "g");
var strPrice = strContent.replace(strRegex, '$1');
This is pretty easy with jQuery. Simply wrap your HTML string inside a div and use jQuery as usual:
var myHTML = "<span>Span 1 HTML</span><span>Span 2 HTML</span><br />USD";
var $myHTML = $("<div>" + myHTML + "</div>");
$myHTML.find("span").each(function() {
alert($(this).html());
});
Here's a working fiddle.
try using
"[\s\S]*<span>(.*?)</span>[\s\S]*"
instead of
".*<span>(.*?)</span>.*"
EDIT: since you're using a string to define your regex don't forget to esacpe your backslashes, so
[\s\S]
would be
[\\s\\S]
You want this?
var str = "<span>39.98</span><br />USD\n<del>47.14</del>\n\n<span>40.00</span><br />USD";
var regex = /<span>([^<]*?)<\/span>/g;
var matches = str.match(regex);
for (var i = 0; i < matches.length; i++)
{
document.write(matches[i]);
document.write("<br>");
}
Test here: http://jsfiddle.net/9LQGK/
The matches array will contain the matches. But it isn't really clear what you want. What does there's potentially two numbers and I want to ignore the first one means?
I'm guessing this is a simple problem, but I'm just learning...
I have this:
var location = (jQuery.url.attr("host"))+(jQuery.url.attr("path"));
locationClean = location.replace('/',' ');
locationArray = locationClean.split(" ");
console.log(location);
console.log(locationClean);
console.log(locationArray);
And here is what I am getting in Firebug:
stormink.net/discussed/the-ideas-behind-my-redesign
stormink.net discussed/the-ideas-behind-my-redesign
["stormink.net", "discussed/the-ideas-behind-my-redesign"]
So for some reason, the replace is only happening once? Do I need to use Regex instead with "/g" to make it repeat? And if so, how would I specifiy a '/' in Regex? (I understand very little of how to use Regex).
Thanks all.
Use a pattern instead of a string, which you can use with the "global" modifier
locationClean = location.replace(/\//g,' ');
The replace method only replaces the first occurance when you use a string as the first parameter. You have to use a regular expression to replace all occurances:
locationClean = location.replace(/\//g,' ');
(As the slash characters are used to delimit the regular expression literal, you need to escape the slash inside the excpression with a backslash.)
Still, why are you not just splitting on the '/' character instead?
You could directly split using the / character as the separator:
var loc = location.host + location.pathname, // loc variable used for tesing
locationArray = loc.split("/");
This can be fixed from your javascript.
SYNTAX
stringObject.replace(findstring,newstring)
findstring: Required. Specifies a string value to find. To perform a global search add a 'g' flag to this parameter and to perform a case-insensitive search add an 'i' flag.
newstring: Required. Specifies the string to replace the found value from findstring
Here's what ur code shud look like:
locationClean = location.replace(new RegExp('/','g'),' ');
locationArray = locationClean.split(" ");
njoi'