Image Enlarger Script - javascript

I am looking for one of those scripts that when you click a Thumbnail, it makes the picture englarge. I tried searching Google using a lot of terms, but cant find any.
Where do I get these?

I believe one of these are what you are looking for.
http://leandrovieira.com/projects/jquery/lightbox/
http://jquery.com/demo/thickbox/

They're called lightboxes, if you search google again, I'm sure you'll find a lot.

i would use some very simple javascript:
your img tag in html file:
<img src="lala.alal" id="getbigger" onClick="grow()" />
your javascript:
function grow() {
width = document.getElementById('getbigger').width;
height = document.getElementById('getbigger').height;
width = width*[INSERT GROWTH RATIO HERE];
height = height*[INSERT GROWTH RATIO HERE];
document.getElementById('getbigger').height = height;
document.getElementById('getbigger').width = width;
}
of course you could just use jQuery animate tools
a good demo of jQuery animate with changing height and width is at this w3schools page.

Related

Canvas to be same height to left column

I am new to JavaScript and I found a codepen which allowed me to create a canvas with confettis falling with javascript. I added the javascript to my project but it seems that the canvas height to way too long. I want the canvas height to be the same as the column on the left (Body). It seems that the canvas' height is set using Javascript but I am still a beginner to the language and hence not sure how to modify it to the way I want. Would appreciate any help thanks.
<canvas id="confeti" class="active" width="100%" height="100%">
</canvas>
Codepen: https://codepen.io/anon/pen/gomLNV
one solution would be to call this onload :
function fixSize(){
var confeti = document.getElementById("confeti");
var leftSide = document.getElementById("leftSide");
confeti.style.height = leftSide.clientHeight + 'px';
}
Ofcourse you have to add the id leftSide to the element which you want to use as max height.
To be fair this is really ugly and simple.
code similar to what spaceninja posted.
i didn't mess with any of your css, its just three lines of js, close to what he responded with:
let b = document.getElementById('b');
let c = document.getElementById('confeti');
c.style.height = b.clientHeight+'px';
https://codepen.io/anon/pen/dJvNQb

How to find the height of the entire webpage?

I am working on a solution capturing screen-shots of websites. I am using the default example mentioned at slimerjs.org to get the job done.
Screen-shots are great with this tool, but I need to take full height screen-shots of websites. When capturing screens of websites like http://www.yellowpages.com, I can get full length screens without having to mention any height parameter.
But when I try this url: http://votingbecause.usatoday.com/
I only get screenshot of the set resolution (default: 1920x1080), I can't get full length images.
Since I am using slimerjs, I can manipulate the dom by using jQuery. I need to find complete website height so that I can take screenshot of that resolution
I tried
document.height()
document.body.scrollheight
screen.height
$(document).height()
(and many other which i found)
But all of these only gave the height of the viewport (website in view)
Question is, how to find the full scrollable height of the website?
To be more general and find the height of any page you could just find the highest DOM Node on current page with a simple recursion:
;(function() {
var pageHeight = 0;
function findHighestNode(nodesList) {
for (var i = nodesList.length - 1; i >= 0; i--) {
if (nodesList[i].scrollHeight && nodesList[i].clientHeight) {
var elHeight = Math.max(nodesList[i].scrollHeight, nodesList[i].clientHeight);
pageHeight = Math.max(elHeight, pageHeight);
}
if (nodesList[i].childNodes.length) findHighestNode(nodesList[i].childNodes);
}
}
findHighestNode(document.documentElement.childNodes);
// The entire page height is found
console.log('Page height is', pageHeight);
})();
You can test it on your sample site(http://votingbecause.usatoday.com/) with pasting this script to a DevTools Console.
Enjoy!
P.S. Supports iframe content.
The contents in the site are in the following div
<div class="site-wrapper flex column">
use this code to get it's height
document.querySelector(".site-wrapper").scrollHeight
Updated Answer for 2020:
You can just simply pass this below line to get the Height of the Webpage
Code:
console.log("Page height:",document.body.scrollHeight);
try windows.innerHeight to get browser viewport size
i think that is what you are loking for
$("body").height();
is what you need
$(window).height();
retrieve current window height..
Here is what I found that worked.
document.body.scrollHeight
was giving me a value of 0.
What worked was
document.documentElement.scrollHeight
https://minimul.com/getting-a-zero-with-document-body-scrollheight.html

Use plain javascript rather then Jquery

I am attempting to code the game breakout in javascript. Currently I have it working using JQuery in several locations. My professor does not want the class to use Jquery so I have to change the areas I use jquery to javascript.
function windowsize() {
WIDTH = $("#canvas")[0].width = ($(window).width()-20.5);
HEIGHT = $("#canvas")[0].height = ($(window).height()-20.5);
}
windowsize();
I am using this function to get reference to the canvas element and subtracting from the sides to remove the scrollbar. (on a side note if anyone knows how to remove the scroll bar without subtracting let me know!)
I attemped the following code to get reference to the canvas, but cannot get it to work?
var c=document.getElementById("canvas");
var ctx=c.getContext("2d");
Here is my fiddle: http://jsfiddle.net/Kinetic915/kURvf/29/
Any help is appreciated!
Thanks!
Assuming Chrome, document.documentElement.clientWidth seems to do it for you. Or, find a 100% width element on the page and get the width of that.

enlarge image and move it with the pointer on mouse over

Sorry if this might seem trivial for me to ask but..
I have some images and I need them to enlarge when I hover my mouse over them. But.. I want for the enlarged image to stick next to the pointer as I move it across the image. I don't know what to call it. I'm pretty sure it's only done with javascript, just css won't work here.
Something like this http://www.dynamicdrive.com/style/csslibrary/item/css-popup-image-viewer/ , but you know, it has to move with the pointer in motion.
What's the most effective way to do this?
The previous answers may be exactly what you're looking for, and you may already have this solved. But I note that you didn't mention jquery anywhere in your post and all of those answers dealt with that. So for a pure JS solution...
I'll assume from the way the question was phrased that you already know how to pop the image up? This can be done by coding an absolutely positioned hidden img tag in the html or generated on the fly with JS. The former may be easier if you are a JS novice. In my examples I'll assume you did something similar to the following:
<img src="" id="bigImg" style="position:absolute; display:none; visibility:hidden;">
Then you need an onMouseOver function for your thumbnail. This function must do three things:
1) Load the actual image file into the hidden image
//I'll leave it up to you to get the right image in there.
document.getElementById('bigImg').src = xxxxxxxx;
2) Position the hidden image
//See below for what to put in place of the xxxx's here.
document.getElementById('bigImg').style.top = xxxxxxxx;
document.getElementById('bigImg').style.left = xxxxxxxx;
3) Make the hidden image appear
document.getElementById('bigImg').style.display = 'block';
document.getElementById('bigImg').style.visibility = 'visible';
Then you'll need to capture the onMouseMove event and update the now un-hidden image's position accordingly using the same code you would have used in (2) above to position the image. This would be something like the following:
//Get the mouse position on IE and standards compliant browsers.
if (!e) var e = window.event;
if (e.pageX || e.pageY) {
var curCursorX = e.pageX;
var curCursorY = e.pageY;
} else {
var curCursorX = e.clientX + document.body.scrollLeft;
var curCursorY = e.clientY + document.body.scrollTop;
}
document.getElementById('bigImg').style.top = curCursorY + 1;
document.getElementById('bigImg').style.left = curCursorX + 1;
And that should just about do it. Just add an onMouseOut event to hide the bigImg image again. You can change the "+1" in the last two lines to whatever you like to place the image correctly in relation to the cursor.
Note that all of the code above was for demonstration purposes only; I haven't tested any of it, but it should get you on the right track. You may want to expand upon this idea further by preLoading the larger images. You could also forgoe capturing mousemove events by using setTimeout to update the position every 20 ms or so, though I think that approach is more complicated and less desirable. I only mention it because some developers (including me when I started) have an aversion to JS event handling.
I did something similar to this with a custom ColdFusion tag I wrote that would generate a floating div users could click and drag around the screen. Same principle. If you need me to I can dig that out to answer any additional questions in more depth.
Good luck!
Liece's solution is close, but won't achieve the desired effect of the large image following the cursor.
Here's a solution in jQuery:
$(document).ready(function() {
$("img.small").hover (function () {
$("img.large").show();
}, function () {
$("img.large").hide();
});
$("img.small").mousemove(function(e) {
$("img.large").css("top",e.pageY + 5);
$("img.large").css("left",e.pageX + 5);
});
});
The HTML is:
<img class="small" src="fu.jpg">
<img class="large" src="bar.jpg">
CSS:
img { position: absolute; }
Try this links [jquery with auto positioning]
1.Simple
http://jquery.bassistance.de/tooltip/demo/
2.Good with forum
http://flowplayer.org/tools/tooltip/index.html
if I understood you correctly you want to position your big image relatively to the cursor. One solution in jquery (i'm not 100% sure of the code here but the logic is there):
$('.thumb').hover(function(e){
var relativeX = e.pageX - 100;
var relativeY = e.pageY - 100;
$(.image).css("top", relativeY);
$(.image).css("left", relativeX);
$(.image).show();
}, function(){
$(.image).hide();
})
Jquery is the easiest route. position absolute is key.
^ In addition to the above, here is a working JS Fiddle. Visit: jsfiddle.net/hdwZ8/1/
It has been roughly edited so it isnt using just overall IMG css tags, easy for anyone to use with this now.
I am using this script instead of a Lightbox in my Wordpress client site, a quick zoomed in image with mouse over is much nicer IMO. It is very easy to make efficient galleries especially with AdvancedCustomFields plug-in & in the WP PHP repeater loops!

Programmatically Clip/Cut image using Javascript

Are there any documents/tutorials on how to clip or cut a large image so that the user only sees a small portion of this image? Let's say the source image is 10 frames of animation, stacked end-on-end so that it's really wide. What could I do with Javascript to only display 1 arbitrary frame of animation at a time?
I've looked into this "CSS Spriting" technique but I don't think I can use that here. The source image is produced dynamically from the server; I won't know the total length, or the size of each frame, until it comes back from the server. I'm hoping that I can do something like:
var image = getElementByID('some-id');
image.src = pathToReallyLongImage;
// Any way to do this?!
image.width = cellWidth;
image.offset = cellWidth * imageNumber;
This can be done by enclosing your image in a "viewport" div. Set a width and height on the div (according to your needs), then set position: relative and overflow: hidden on it. Absolutely position your image inside of it and change the position to change which portions are displayed.
To display a 30x40 section of an image starting at (10,20):
<style type="text/css">
div.viewport {
overflow: hidden;
position: relative;
}
img.clipped {
display: block;
position: absolute;
}
</style>
<script type="text/javascript">
function setViewport(img, x, y, width, height) {
img.style.left = "-" + x + "px";
img.style.top = "-" + y + "px";
if (width !== undefined) {
img.parentNode.style.width = width + "px";
img.parentNode.style.height = height + "px";
}
}
setViewport(document.getElementsByTagName("img")[0], 10, 20, 30, 40);
</script>
<div class="viewport">
<img class="clipped" src="/images/clipped.png" alt="Clipped image"/>
</div>
The common CSS properties are associated with classes so that you can have multiple viewports / clipped images on your page. The setViewport(…) function can be called at any time to change what part of the image is displayed.
In answer to :
Alas, JavaScript simply isn't capable of extracting the properties of the image you'd require to do something like this. However, there may be salvation in the form of the HTML element combined with a bit of server-side scripting.
...
< ? (open php)
$large_image = 'path/to/large_image';
$full_w = imagesx($large_image);
$full_h = imagesy($large_image);
(close php) ? >
This can be done in Javascript, just google a bit :
var newimage = new Image();
newimage.src = document.getElementById('background').src;
var height = newimage.height;
var width = newimage.width;
This generates a new image from an existing one and captures this way in java script the original height and width properties of the original image (not the one id'ed as background.
In answer to :
The width/height properties of the document's image object are read only. If you could change them, however, you would only squish the frames, not cut the frames up like you desire. The kind of image manipulation you want can not be done with client-side javascript. I suggest cutting the images up on the server, or overlay a div on the image to hide the parts you do not wish to display.
...
var newimage = new Image();
newimage.src = document.getElementById('background').src;
var height = newimage.height;
var width = newimage.width;
newimage.style.height = '200px';
newimage.style.width = '200px';
newimage.height = '200px';
newimage.width = '200px';
and if wanted :
newimage.setAttribute('height','200px');
The doubled newimage.style.height and newimage.height is needed in certain circumstances in order to make sure that a IE will understand in time that the image is resized (you are going to render the thing immediately after, and the internal IE processing is too slow for that.)
Thanks for the above script I altered and implemented on http://morethanvoice.net/m1/reader13.php (right click menu... mouseover zoom lent) correct even in IE , but as you will notice the on mousemove image processing is too fast for the old styled IE, renders the position but only once the image. In any case any good idea is welcome.
Thanks to all for your attention, hope that the above codes can help someone...
Claudio Klemp
http://morethanvoice.net/m1/reader13.php
CSS also defines a style for clipping. See the clip property in the CSS specs.
The width/height properties of the document's image object are read only. If you could change them, however, you would only squish the frames, not cut the frames up like you desire. The kind of image manipulation you want can not be done with client-side javascript. I suggest cutting the images up on the server, or overlay a div on the image to hide the parts you do not wish to display.
What spriting does is essentially position a absolutely-positioned DIV inside another DIV that has overflow:hidden. You can do the same, all you need to do is resize the outer DIV depending on the size of each frame of the larger image. You can do that in code easily.
You can just set the inner DIV's style:
left: (your x-position = 0 or a negative integer * frame width)px
Most JavaScript Frameworks make this quite easy.
Alas, JavaScript simply isn't capable of extracting the properties of the image you'd require to do something like this. However, there may be salvation in the form of the HTML <canvas> element combined with a bit of server-side scripting.
PHP code to go about extracting the width and height of the really large image:
<?php
$large_image = 'path/to/large_image';
$full_w = imagesx($large_image);
$full_h = imagesy($large_image);
?>
From here, you'd then load the image into a <canvas> element, an example of which is documented here. Now, my theory was that you may be able to extract pixel data from a <canvas> element; assuming that you can, you would simply make sure to have some form of definite divider between the frames of the large image and then search for it within the canvas. Let's say you found the divider 110 pixels from the left of the image; you would then know that each "frame" was 110 pixels wide, and you've already got the full width stored in a PHP variable, so deciphering how much image you're working with would be a breeze.
The only speculative aspect to this method is whether or not JavaScript is capable of extracting color data from a specified location within an image loaded into a <canvas> element; if this is possible, then what you're trying to accomplish is entirely feasible.
I suppose you want to take a thumbnail for your image. You can use ImageThumbnail.js that created from prototype library in this way:
<script type="text/javascript" src="prototype.js"></script>
<script type="text/javascript" src="ImageThumbnail.js"></script>
<input type="file" id="photo">
<img src="empty.gif" id="thumbnail" width="80" height="0">
<script type="text/javascript">
<!--
new Image.Thumbnail('thumbnail', 'photo');
//-->
</script>
for more information
try use haxcv library haxcv js by simple functions
go to https://docs.haxcv.org/Methods/cutImage to read more about his library
var Pixels = _("img").cutImage (x , y , width , height );
_("img").src (Pixels.src);
// return cut image
but try to include library first

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