I want to create an Element, which is very thin, and very high. I want the element to be visible all time, even if you scroll to the right. It should be position:fixed to the right, and left, but it should be scrollable down and up.
I searched with google, but couldn't find an appropiate way to solve the problem.
I only found this site:
http://demo.rickyh.co.uk/css-position-x-and-position-y/
This is exactly, what I want to have, BUT I am using jQuery, and not MooTools. I am looking for the same function in jQuery. I do not really want to use 2 Frameworks. Does anyone know help? Anything? I have been looking several hours, but I can't find something that fit to my needs in jQuery.
Here's a solution with jquery
jsfiddle demo
the html
<div style="width:1000px;height:1000px;">
<div id="box1" class="box" style="left:20px;top:20px;">
My position-x is fixed but position-y is absolute.
</div>
<div id="box2" class="box" style="left:20px;top:120px;">
My position-x is absolute but position-y is fixed.
</div>
<div id="box3" class="box" style="left:20px;top:220px;">
Im positioned fixed on both axis.
</div>
</div>
the code
$(window).scroll(function(){
var $this = $(this);
$('#box1').css('top', 20 - $this.scrollTop());
$('#box2').css('left', 20 - $this.scrollLeft());
});
and some css
.box
{
width:400px;
height:80px;
background:gray;
position:fixed;
}
Depending on a previous answer that helped me with what I was trying to do, keeping a header div with position-y fixed, a left div with position-x fixed, and a content div which would scroll on both x and y.
Figured I would post my jsfiddle in case anyone finds it useful:
My jsfiddle demo
The HTML
<body>
<div style="width:5000px;height:1000px;">
<div id="box1" class="box">
My position-x is fixed but position-y is scrollable.
</div>
<div id="box2" class="box">
My position-y is scrollable but position-x is fixed.
</div>
<div id="box3" class="box">
My position-x and position-y are both scrollable.
</div>
</div>
The code
$(window).scroll(function(){
var $win = $(window);
$('#box2').css('top', 0 -$win.scrollTop());
$('#box1').css('left', 120 -$win.scrollLeft());
$('#box3').css('left', 120 -$win.scrollLeft());
$('#box3').css('top', 20 -$win.scrollTop());
});
The CSS
.box {
position:fixed;
}
#box1 {
top: 0px;
left: 120px;
width: 1000px;
height: 20px;
background-color: #FF0000;
z-index:150;
}
#box2 {
top: 0px;
left: 0px;
width: 120px;
height: 520px;
background-color: #00FF00;
z-index:200;
}
#box3 {
top: 20px;
left: 120px;
width: 1000px;
height: 500px;
background-color: #0000FF;
color: white;
z-index:100;
}
Related
Say I wanted an element to be positioned vertically absolutely, but horizontally relative. Is this possible with css/html/javascript?
Not sure which case could be fine to use this mix, but it is possible,
if you only define top/bottom properties in a position:absolute element.
The left/right position of the element will be "relative" if you leave it untouched.
In the following example, the second container has a mixed positioning.
.example{
margin: 30px;
position: relative;
border: 1px solid red;
}
.item1, .item2{
display: inline-block;
margin: 0;
}
#example2 .item2{
position: absolute;
top: 80px;
}
<div id="example1" class="example">
<div class="item1">Item1</div>
<div class="item2">Item2</div>
</div>
<div id="example2" class="example">
<div class="item1">Item1</div>
<div class="item2">Item2</div>
</div>
I have 3 questions about my jQuery study today.
Why my jQuery code not have the animation effect as it should be? for example, .slideUp() and .slideDown(), my code shows something strange instead of slideUp animation.
I understand, the .hide() or .slideUp() function is only to HIDE the div box, not DELETE them, however, in my code, why the position of other div boxes changed after a DIV .hide()? Shouldn't it stay at their original position as the DIV box is still there, just HIDED?
How can I achieve to let other DIVs stay at the original position, when one DIV box has been hided?
$(document).ready(function() {
$('#panel1').slideUp(1000).delay(1500).slideDown(1000);
});
.panel {
display: inline-block;
width: 80px;
height: 60px;
border: 1px solid green;
position: relative;
top: 20px;
margin-left: 45px;
border-radius: 5px;
}
.panelTop {
height: 30px;
background-color: blue;
color: white;
text-align: center;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="panels">
<div id="panel1" class="panel">
<div class="panelTop">#panel1</div>
<div class="panelBottom">content</div>
</div>
<div id="panel2" class="panel">
<div class="panelTop">#panel2</div>
<div class="panelBottom">content</div>
</div>
<div id="panel3" class="panel">
<div class="panelTop">#panel3</div>
<div class="panelBottom">content</div>
</div>
<div id="panel4" class="panel">
<div class="panelTop">#panel4</div>
<div class="panelBottom">content</div>
</div>
</div>
For your first question
Why my jQuery code not have the animation effect as it should be? for
example, .slideUp() and .slideDown(), my code shows something strange
instead of slideUp animation.
The .slideUp() method animates the height of the matched elements. Means it animates height so it reaches 0 (or, if set, to whatever the CSS min-height property is). See here for reference. That is exactly what is happening to your first box it is decreasing in height.
Afterwards the display style property is set to none to ensure that the element no longer affects the layout of the page.
What display none does ?
display:none means that the tag in question will not appear on the
page at all
Now for second and third question
I understand, the .hide() or .slideUp() function is only to HIDE the
div box, not DELETE them, however, in my code, why the position of
other div boxes changed after a DIV .hide()? Shouldn't it stay at
their original position as the DIV box is still there, just HIDED?
How can I achieve to let other DIVs stay at the original position,
when one DIV box has been hided?
The .hide() and .slideUp()function they both add display:none to your tag element. Means they are gone now
Now what can you do to let them stay there, But hidden from view ?
You can use visibility or opacity property instead rather than using display
property.
For example: visibility: hidden; will just hide it from the view.
Will update your fiddle in order to demonstrate it in a while. Hope this will help you. Please feel free to ask if not clear. Thank you.
$(document).ready(function() {
setInterval(function(){
$('#panel1').slideUp(1000).delay(500).slideDown(1000);
}, 3000);
});
.outer-div
{
position: relative;
display: inline-block;
min-height: 1px;
margin-right: 15px;
margin-left: 15px;
width: 130px;
height: 90px;
}
.panel {
border: 1px solid green;
margin-left: 45px;
border-radius: 5px;
position:absolute;
top:0;
width: 100%;
}
.panelTop {
height: 30px;
background-color: blue;
color: white;
text-align: center;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.4/jquery.min.js"></script>
<div class="panels">
<div class="outer-div">
<div id="panel1" class="panel">
<div class="panelTop">#panel1</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel2" class="panel">
<div class="panelTop">#panel2</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel3" class="panel">
<div class="panelTop">#panel3</div>
<div class="panelBottom">content</div>
</div>
</div>
<div class="outer-div">
<div id="panel4" class="panel">
<div class="panelTop">#panel4</div>
<div class="panelBottom">content</div>
</div>
</div>
</div>
You should use display:flex on .panels, that solves your first question.
For second question you should use visibility or opacity.
With current code you are removing it, although it is called hide() it is equivalent to CSS display:none; which doesn't keep space of element.
Although you actually don't need to set visibility in your case because sliding it up will hide element and down show.
Something like this:
$('#panel1').animate({
top: -62 // 60 is height of element plus 2px of borders
}, 1000).delay(1500).animate({
top: 0
}, 1000);
Also you have to change CSS a bit.
Add this to your CSS:
.panels {
display: flex;
overflow: hidden;
margin-top: 20px;
}
And from .panel remove top: 20px;
Full example is here https://jsfiddle.net/_jakob/cphptby3/1/
Is it possible to absolutely position elements inside a fixed position container? For example:
<div style="position:fixed; left:0; top:0">
<div style="position:fixed; left:0; top:0;"></div>
<div style="position:fixed; left:200px; top:120px;"></div>
</div>
I want to be able to move, using jQuery, the container div to the left and right (and it's children along with it), but this obviously doesn't work (moving the container's left property does not affect the children).
I tried something like this:
<div style="position:fixed; left:0; top:0">
<div style="position:relative; width:100%; height:100%;">
<div style="position:fixed; left:0; top:0;"></div>
<div style="position:fixed; left:200px; top:120px;"></div>
</div>
</div>
...but it doesn't work. I know I could ultimately just drop the container and animate each of the fixed position children at the same time, but I'd really prefer not to. I'll probably end up adding more children later, and that would mean managing the animations/movements of each one (now that I think of it, I could just add a class to each child, and have jQuery animate the left property of all occurances of that class, but I'd still prefer to resolve my initial problem if possible).
Hacks are welcome!
use relative for the children, not fixed.
<div style="position:fixed; left:0; top:0">
<div style="position:relative; left:0; top:0;"></div>
<div style="position:relative; left:200px; top:120px;"></div>
</div>
The children should be position absolute (because they are positioned absolutely within the fixed container).
See this demo:
http://jsfiddle.net/74dE7/2/
#fixed-box {
position: fixed;
height: 300px;
width: 300px;
background: red;
right: 10px;
top: 10px;
}
#absolute-box {
position: absolute;
left: 10px;
bottom: 10px;
background: blue;
height: 50px;
width: 50px;
}
<div id="fixed-box">
<div id="absolute-box">
</div>
</div>
what I'm trying to do is simple to tell. There is fixed div on my page on bottom. It must be always shown on bottom, so position fixed is used.
In this div there are 2divs, one small must be always on top of this fixed div, another must be scrollable.
The problem is small div, if I give him position fixed, it is position to top of window, not on top of this fixed div, as you can see in this fiddle
If small div is position absolute, it is on top of fixed div, but if it is scrolled, as you can see in this fiddle
HTML
<div class="bottom">
<div class="top"></div>
<div class="content"></div>
</div>
CSS
.bottom
{
padding:20px;
height: 253px;
position: fixed;
bottom:0px;
width:100%;
background-color: red;
overflow-x: hidden;
overflow-y: scroll;
}
.top
{
height:50px;
width:100%;
background-color: yellow;
position: fixed;
top: 0px;
}
.content
{
height: 1500px;
background: linear-gradient(green, blue);
}
Is is possible to make this work without watching scrolling by jvascript? By pure CSS?
You can use a wrapper <div> for the content and let it scroll - so that the absolutely positioned sibling does not scroll along with it, as follows:
HTML
<div class="bottom">
<div class="top"></div>
<div class='contentWrap'>
<div class="content"></div>
</div>
</div>
CSS
.contentWrap{
height:100%;
overflow-y:auto;
}
* {
margin: 0;
padding: 0;
}
.bottom {
padding: 20px;
height: 253px;
position: fixed;
bottom: 0px;
width: 100%;
background-color: red;
overflow: hidden;
}
.top {
height: 50px;
width: 100%;
background-color: yellow;
position: absolute;
top: 0px;
}
.contentWrap {
height: 100%;
padding-top: 30px; /* .top height - .bottom padding*/
overflow-y: auto;
}
.content {
height: 1500px;
background: linear-gradient(green, blue);
}
<div class="bottom">
<div class="top"></div>
<div class='contentWrap'>
<div class="content"></div>
</div>
</div>
JSFiddle Demo
Your approach using fixed -> absolute is absolutely correct since you can position an element absolute but relative to its parent by doing so. The problem is that the absolute .top always appears on top of .bottom - so if .bottom is scrolled, .top will follow.
My solution would be using position:fixed; on .top, but using bottom instead of top:
.top {
....
position:fixed;
bottom:253px; /*note sure how it should look at the end, try it yourself*/
}
Add div with class top inside div with class content and remove top:0 from .top class:
html
<div class="bottom">
<div class="content" >
<div class="top"></div>
</div>
<div>
css
.top
{
height:50px;
width:100%;
background-color: yellow;
position: fixed;
}
fiddle
Try this, it basically just puts a frame container around your scrollable div to keep everything in place. JSFiddle
<div class="bottom">
<div class="top"></div>
<div class="scroll-container">
<div class="content" ></div>
</div>
<div>
.scroll-container
{
height: 203px;
overflow-y: scroll;
}
Also, remove overflow-y: scroll; from the .bottom class
If you already dealing with fixed heights & positions, why not just position the 'top' section as fixed as well? check the Fiddle Demo
like so:
.top
{
height:50px;
bottom:243px;
width:100%;
background-color: yellow;
position: fixed;
}
At my Page there are tow sections, a header div and the contents div. I want JS or jquery solution to stick the header section at the top, so that when user scrolls the contents section would cross and cover the header section.
html:
<div id="header">
<h3>I'd like to stick here at the background, please! </h3>
</div>
<div id="content">
<h3>I'd like to cross over the header when user scrolls.</h3>
</div>
http://jsfiddle.net/KNh46/
Update: misunderstood, so you want the content to scroll over the header, not under. Then it should be like:
#header {
position: fixed;
height: 100px;
top: 0;
z-index: 100;
}
#content {
position: relative;
margin-top: 100px;
z-index: 101;
}
See an example here: http://jsfiddle.net/aorcsik/v7zav/
If your header is fixed height, say 100px, then:
#header {
position: fixed;
height: 100px;
top: 0;
}
#content {
margin-top: 100px;
}
This way when scrolled to the top, the header won't overlay the content, but when you start to scroll down, it will.
Something like this, if I understand your question:
<div id="content_wrapper" style="position:relative">
<div id="header" style="z-index:1; position:absolute; top:0px">
<h3>I'd like to stick here at the background, please! </h3>
</div>
<div id="content" style="z-index:5">
<h3>I'd like to cross over the header when user scrolls.</h3>
</div>
</div>
I'm using https://github.com/bigspotteddog/ScrollToFixed on my projects with no problems. ScrollToFixed allows you to set when the div will be fixed based on the scroll position.
fiddle with example: jsfiddle.net/ZczEt/167/
you should add css:
*{margin:0;padding:0}
#header{
position:fixed;
width:100%;
height:200px;
background:#ccc;
}
h3{
text-align:center;
}
#content{
background:#f1f1f1;
padding-top:200px;
min-height:500px;
}
jsfiddle
I myself came with another solution :
add another container div to the header and then position that div to fixed, and make the contents to be absolute. but this way you need to specify a min-height or height for the header:
http://jsfiddle.net/pna54/
<div id="header">
<div class="container">
<h3>I'd like to stick here at the background, please! </h3>
</div>
</div>
<div id="content">
<h3>I'd like to cross over the header when user scrolls.</h3>
</div>
css:
div{margin:0;padding:0}
h3{
padding:0;margin:0;
padding-top: 100px;
padding-bottom:100px;
text-align:center;
}
#header{
background:#ccc;
min-height:200px;
width:500px;
position:relative;
}
.container{
position:fixed;
width:100%;
max-width:500px;
}
#content{
background:#f1f1f1;
min-height: 500px;
position: absolute;
width:500px;
}
http://jsfiddle.net/pna54/