I load a html with ajax. I want to load the result in a jquery object. I tried that but it returns null. How can I do this? I got a complete page including doctype, head elements and body elements.
var test = $(result); //result contains html code
alert(test.html()); //returns null
I load the data with this function.
function ajaxLoadContent(element) {
$.ajax({
url: "url to the page",
type: "GET",
timeout: 5000,
datattype: "html",
success: function(result) {
//handler
},
});
return false;
It's a while ago, but maybe you're still interested in it..
The intern implementation of $(String) is not able to build an jQuery object that contains head or body tags. It will simply ignore them and move all elements inside on level up.
So if your string is for example
<html>
<head>
<meta ...>
</head>
<body>
<div id="a"/>
</body>
</html>
the resulting jQuery object will be an array of two elements
[<meta ...>, <div id="a" />]
to get a body-like jQuery object cut everything but the body content before passing it to jQuery:
body = '<div id="body-mock">' + html.replace(/^[\s\S]*<body.*?>|<\/body>[\s\S]*$/ig, '') + '</div>';
var $body = $(body);
now things work as expected.. for example
$body.find('#a')
Hope that helps..
test is just an html string, so you could simply do this to show the contents
alert(result);
and if you want to bind that to an element
$("#myDiv").html(result);
function ajaxLoadContent(element) {
$.ajax({
url: "url to the page",
type: "GET",
timeout: 5000,
datattype: "html",
success: function(data) {
var result = $(data);
},
});
return false;
You should now be able to call the result like this (remember it's not added to the DOM yet):
alert(result.html());
Add to the DOM
result.appendTo("body");
Let me know if this works for you.
Try the load method of jQuery object: http://api.jquery.com/load/
Load data from the server and place
the returned HTML into the matched
element.
Related
I'm so frustrated! As an ok PHP developer I can't get my head around the simplist of jquery problems!
I have recently moved my HTML jquery include to the end of the HTML body, instead of in the head to improve google pagespeed score.
This has broken some jquery which is used for simple comment voting. This was written badly as it repeats for every comment.
<div id="voterow-19907" class="commentfooter">UP</a> | <a id="comment-vote-down-19907" href="#" rel="nofollow">DOWN</a></div>
<script>
$("#comment-vote-up-19907").click(function() {
$.ajax({
type: "GET",
url: "/ajax.php",
data: "a=rv&v=19907&d=up",
success: function(data){
$("#voterow-19907").text("Thank you for your vote")
}
});
return false;
});
$("#comment-vote-down-19907").click(function() {
$.ajax({
type: "GET",
url: "/ajax.php",
data: "a=rv&v=19907&d=down",
success: function(data){
$("#voterow-19907").text("Thank you for your vote")
}
});
return false;
});
</script>
Since moving the jquery include to the bottom of the page this naturally doesn't work.
What I'm trying to do is turn the above code into a mini function I can include after the jquery include, then pass the ID and VOTE-DIRECTION to the function from the HTML a hrefs using the jquery DATA- attribute.
Any help would be greatly appreciated. I'm running out of hair!
I think, repeated codes will hurt your page than placement of JQuery file.
You can solve this problem using more general event listener. Remove all listeners inside code (all of them) and append the code below after Jquery include.
$('[id^=comment-vote]').click(function() {
var elementId = $(this).attr('id');
var elementIdParts = elementId.split("-");
var voteType = elementIdParts[2];
var id = elementIdParts[3];
$.ajax({
type: "GET",
url: "/ajax.php",
data: "a=rv&v="+id+"&d="+voteType,
success: function(data){
$("#voterow-"+id).text("Thank you for your vote")
}
});
return false;
});
$('[id^=comment-vote]") selects all elements which have id starting with "comment-vote". If user clicks one of these elements, event handler gets id of elements, split into parts like "comment", "vote", "up", "19900". 2nd part is voteType and 3rd part is ID of row. We can use these variables while generating/operating AJAX request.
I didn't try the code but the idea behind that would be beneficial for you.
To really give a great working answer, I would need to see your an example page / the exact structure of your html, but here's what I have for you.
In a script file that you include after jQuery, you can include something similar to the below code assuming your html is as follows:
<div id="voterow-1" class="voterow">
<p class="voteresult"></p>
<a class="upvote" href="#" rel="nofollow">UP</a>
<a class="downvote" href="#" rel="nofollow">DOWN</a>
</div>
<div id="voterow-2" class="voterow">
<p class="voteresult"></p>
<a class="upvote" href="#" rel="nofollow">UP</a>
<a class="downvote" href="#" rel="nofollow">DOWN</a>
</div>
Having the class of upvote and downvote makes it easy to target these elements in jQuery:
// After jQuery is loaded, the function passed to ready() will be called
$(document).ready(function () {
// bind a click event to every direct child with the upvote class of an element with the voterow class
$('.voterow > .upvote').click(function (event) {
// get the voterow parent element
var $parent = $(event.target).parent();
// use regex to strip the id number from the id attribute of the parent
var id = parseInt($parent.attr('id').match(/^voterow-(\d+)/)[1]);
// call your ajax function
vote(id, 'up', $parent.find('.voteresult');
});
$('.voterow > .downvote').click(function (event) {
var $parent = $(event.target).parent();
var id = parseInt($parent.attr('id').match(/^voterow-(\d+)/)[1]);
vote(id, 'down', $parent.find('.voteresult');
});
function vote(id, direction, $resultElement) {
$.ajax({
type: "GET",
url: "/ajax.php",
// here we have the id and the direction needed to make the ajax call
data: "a=rv&v=" + id + "&d=" + direction,
success: function(data){
$resultElement.text("Thank you for your vote")
}
});
}
});
Here is a demo: https://plnkr.co/edit/ECL376hZ3NOz8pBVpBMW?p=preview
I have a page that I have edited after load and what I want to do is get the pages current HTML and pass that off to a PHP script.
I first passed document.documentElement.innerHTML but that ended up including a bunch of computed style garbage at the top which I did not want. After googling around I found I could use ajax to get a copy of the current file on the server and then replace the edited part afterwards.
I can get the copy of the file using this:
var url = window.location.pathname;
var filename = url.substring(url.lastIndexOf('/')+1);
$.ajax({
url: filename,
async: false, // asynchronous request? (synchronous requests are discouraged...)
cache: false, // with this, you can force the browser to not make cache of the retrieved data
dataType: "text", // jQuery will infer this, but you can set explicitly
success: function( data, textStatus, jqXHR ) {
origPage = data; // can be a global variable too...
// process the content...
}
});
Which works fine and gets me the html I expected and see when viewing the page in notepad.
The next step is what I cannot figure out. All I want to do is swap out the innerHTML of a div with an id of 'editor' with what the current value is, so I have tried this:
origPage.getElementById('editor').innerHTML = e.html;
But I get the error "TypeError: undefined is not a function". I must be doing something simple wrong I feel but I don't know the proper formatting to do this. I have tried the following variations:
alert($(origPage).getElementById('editor').innerHTML);
//Different attempt
var newHtml = $.parseHTML( origPage );
alert($(newHtml).getElementById('editor').innerHTML);
//Different attempt
alert($(origPage).html().getElementById('editor').innerHTML);
But I always get "TypeError: undefined is not a function" or "TypeError: Cannot read property 'getElementById' of undefined". How can I do this properly?
EDIT:
Complete page html below:
<!DOCTYPE html>
<html>
<body>
<div id="editor">
<h1>This is editable.</h1>
<p>Click me to start editing.</p>
</div>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<script type="text/javascript" src="snapeditor.js"></script>
<script type="text/javascript">
var editor = new SnapEditor.InPlace("editor", {onSave: function (e) {
var isSuccess = true;
//var origPage = e.html;
var origPage;
var url = window.location.pathname;
var filename = url.substring(url.lastIndexOf('/')+1);
// Actually perform the save and update isSuccess.
// Javascript:
$.ajax({
url: filename,
async: false, // asynchronous request? (synchronous requests are discouraged...)
cache: false, // with this, you can force the browser to not make cache of the retrieved data
dataType: "text", // jQuery will infer this, but you can set explicitly
success: function( data, textStatus, jqXHR ) {
origPage = data; // can be a global variable too...
// process the content...
}
});
//origPage shows expected html as this point
//alert($(origPage).getElementById('editor').innerHTML);
//alert($(origPage).html().getElementById('editor').innerHTML);
$(origPage).getElementById('editor').innerHTML = e.html;//fails here
alert(origPage);
//alert(newHtml.getElementById('editor').innerHTML);
$.ajax({
data: {html: origPage, docName: 'example1.html'},
url: 'savePage.php',
method: 'POST', // or GET
success: function(msg) {
alert(msg);
isSuccess = true;
}
});
return isSuccess || "Error";
},
onUnsavedChanges: function (e) {
if(confirm("Save changes?")) {
if(e.api.execAction("save")){
//location.reload();
}
} else {
e.api.execAction("discard");
}
}});
</script>
</body>
</html>
It seems that you get the user's changes in a variable - you called the var e.html. That is not a good variable name, BTW. If you can, change it to something like htmlEdited
Question: If you add the command alert(e.html); what do you get? Do you see the HTML after user edits?
If yes, then what you need to do is send that variable to a PHP file, which will receive the data and stick it into the database.
Code to send the data:
javascript/jQuery:
alert(e.html); //you should see the user-edited HTML
$.ajax({
type: 'post',
url: 'another_php_file.php',
data: 'userStuff=' + e.html, //var_name = var_contents
success: function(d){
window.location.href = ''; //redisplay this page
}
});
another_php_file.php:
<?php
$user_edits = $_POST['userStuff']; //note exact same name as data statement above
mysql_query("UPDATE `your_table_name` SET `your_col_name` = '$user_edits' ") or die(mysql_error());
echo 'All donarino';
The AJAX javascript code will send the var contents to a PHP file called another_php_file.php.
The data is received as $user_edits, and then inserted into your MySQL db
Finally, I presume that if you redisplay that page it will once again grab the contents of the #editor div from the database?
This is where you haven't provided enough information, and why I wanted to see all your code.
ARE you populating that div from the database? If not, then how do you expect the page to be updated after refreshing the page?
You would benefit from doing some tutorials at phpacademy.org or a thenewboston.com. Do these two (free) courses and you'll be an expert:
https://phpacademy.org/videos/php-and-mysql-with-mysqli
https://phpacademy.org/videos/oop-loginregister-system
If all you need to do is insert the contents of e.html to replace the #editor div, then try this:
$('#editor').html(e.html);
HOWEVER, you need an event to trigger that code. Are you able to do this?
alert(e.html);
If so, then put the first bit of code at that same spot. If not, we need more information about when your code receives that variable -- that is where you put the $('#editor').html(e.html); statement.
I have two divs, each one should have a record name from a json result.
<div class="first"></div>
<div class="second"></div>
My json file is as follows :
[{"Name":"name1","Instruction":"instr"},
{"Name":"name2","Instruction":"instr again"}]
I want to put in the first div's value, the ‘Name‘ value of the first record, same for the second div but with the second record.
I'm using jQuery :
<script>
$(document).ready(function() {
$.post("data/result.php",
function(data) {
//alert("Data: " + data);
$('div.first').append(data.Name); //data.Name returns undefined
}
);
});
</script>
Any help would be appreciated.
as far as you are using post for you ajax call, the data returns as a json string, do this:
$(document).ready(function() {
$.post("data/result.php",
function(data) {
data = JSON.parse(data);
$('div.first').append(data[0].Name);
$('div.second').append(data[1].Name);
}
);
});
As previously mentioned you need to parse the result as json. You could use the built in parser in jquery. Like this:
<script>
$(document).ready(function() {
$.ajax({
url: 'data/result.php',
type: 'POST',
dataType: 'json',
success : function (data) {
$('div.first').append(data[0].Name);
}
});
});
</script>
First of all, you can give a datatype with a request:
$.post('data/result.php',function(data) { },'JSON');
If you are not posting any information, why not just use $.get ? (it's the same syntax btw)
$.post('data/result.php',function(data) {
var $first = $('div.first'),
$second = $('div.second');
$first.text(data[0].Name);
$second.text(data[1].Name);
},'JSON');
Also, if you use .append(..) it will be appended to whatever is already in the div. If that is your intention, use .append(...). However, if you want to replace the content of it, even if it is empty, use .text(...) or .html(...)
This code is supposed to run over to load.php and get some data in xml format, parse it, and load it in a div and display it. It works great, except the data from load.php is displayed twice. Is there another way to do this that won't cause the data to be shown twice? I've seen a number of posts related to the document ready function causing this problem, but can't seem to figure out how to apply any solutions to this case. I am putting this in the head tags on my page. I really want to keep this format, because eventually I'll POST some data to the load.php page.
SCRIPT
$(document).ready(function () {
$.ajax({
type: 'POST',
url: 'load.php',
success: loadReturn
});
function loadReturn(data) {
var xml = $.parseXML(data);
$xml = $(xml);
$errorcode = $xml.find('errorcode');
$data = $xml.find('data');
document.getElementById("defaultcode").innerHTML = $data.text();
$("#defaultcode").fadeIn(300);
}
});
</script>
HTML
<div id="defaultcode" style><h3>a title</h3><p>blah blah</p><h3>a title</h3><p>blah blah</p></div>
Thank you in advance for your time.
First of all I try to fixed your code to the right ways. but I dont think code is wrong. it should be you have send two data tag from load.php. please check your returned data.
$(document).ready(function () {
$.ajax({
type: 'POST',
url: 'load.php',
success: loadReturn
});
function loadReturn(data) {
// check your data
console.log(data);
// jQuery will parse for you automatically
var $xml = $(data);
var $errorcode = $xml.find('errorcode');
var $data = $xml.find('data');
// set html before fadeIn
$("#defaultcode").html($data.text()).fadeIn(300);
}
});
I'm trying to load an XML file with ajax and insert parts of this XML DOM document into the browsers HTML DOM.
This works so far, but when I try to get an inserted element with a class or id selector with jquery it returns the empty list.
I tried it only in firefox 10 so far. does anyone have a clue why this might be? is it just not safe to do so?
test.html:
<html><head>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
<title>dom test</title>
<script type="text/javascript">
$(function() {
var xml = null;
$.ajax({
type : "GET",
async : false,
url : 'test.xml',
dataType : "xml",
success : function(data) {
xml = data;
}
});
$('body').html($(xml).children().clone());
console.log($('h1')); // prints the h1 element
console.log($('.title')); // prints empty list
console.log($('p')); // prints the p element
console.log($('#content')); // prints empty list
});
</script>
</head><body></body></html>
test.xml:
<div id="root">
<h1 class="title">Blabla</h1>
<p id="content">
Lorem ipsum
</p>
</div>
It seems like you are just trying to grab HTML via AJAX and then insert it into your page. To do that you should be using dataType: "html" in your ajax request.
$(function() {
var html = null;
$.ajax({
type : "GET",
async : false,
url : 'test.xml',
dataType : "html",
success : function(data) {
html = data;
}
});
$('body').html(html);
});
It is doing as expected. Can verify by alerting the $(xnl).find("h1").text(). however can you please try with changing double quotes to single quotes in your xml. and disabling HTML5 support in your ff (that might be the issue too)?