Develop Reference

Submit checkbox value on form without page refresh AJAX PHP

I just started learning ajax and its really great and time saving i agree.
But i got stuck at this point sending form data without page reload.
Below is my html code.
<form id="form4" method="post">
<input type="checkbox" name="test" id="agreed" value="check">
<br>
<br>
<input type="submit" id="form-submit" name="submit" value="Send">
<p class="form-message"></p>
</form>
Below is my Ajax script
<script>
$(document).ready(function() {
$("#form4").submit(function(event) {
event.preventDefault();
var action = 'another_test';
var agreed = $("#agreed").val();
var submit = $("#form-submit").val();
$(".form-message").load("test3.php", {
test: agreed,
submit: submit,
action: action
});
});
});
</script>
Below is my php code
<?php
if (isset($_POST['action'])) {
if ($_POST['action'] == 'another_test') {
$test = $_POST["test"];
$errorEmpty = false;
if (!empty($test)) {
echo "<p>Click the checkbox pls</p>";
$errorEmpty = true;
}
else {
echo "<p>Checkbox clicked</p>";
}
} else {
echo "Error.. cant submit";
}
}
?>
<script>
var errorEmpty = "<?php echo $errorEmpty ?>";
</script>
The php file is on another page called test3.php
This particular code works if it was an input text but doesn't work for a checkbox.
Please help me so i can learn well.
Thanks in advance.

.load() (as per the documentation) performs a GET request, not a POST, but your PHP is (as shown by the $_POST references) expecting a POST request - and it usually makes sense to submit form data using POST.
So you'd be better to use $.post() - this will send a POST request. Then you can handle the response and load it into your "form-message" element in the "done" callback triggered by that request.
N.B. You could also make the code shorter by putting the "action" variable as a hidden field in the form, and then simply serialize the form in one command instead of pulling each value out separately.
Example:
HTML:
<form id="form4" method="post">
<input type="checkbox" name="test" id="agreed" value="check">
<br>
<br>
<input type="submit" id="form-submit" name="submit" value="Send">
<input type="hidden" action="another_test"/>
<p class="form-message"></p>
</form>
JavaScript
$(document).ready(function() {
$("#form4").submit(function(event) {
event.preventDefault();
$.post(
"test3.php",
$(this).serialize()
).done(function(data) {
$(".form-message").html(data);
});
});
});
Documentation:
jQuery Load
jQuery Post
jQuery Serialize

How to embed form data in the action link?

I have a form defined:
<form method="post">
<label for="phone_or_uid">Enter a phone number or uid:</label>
<input type="text" name="phone_or_uid" value=""></input>
<input type="submit" name="" value="Submit"></input>
</form>
Currently, when this form is submitted I am able to work with the data and add info to the page based on the value of phone_or_uid. However, what I'd like to do is something where the form redirects to the same page but with the value of phone_or_uid appended to the end. So, if the initial page is https://myhost.com/lookup then submitting the form should bring the user to https://myhost.com/lookup/16175431234 if the value of the phone_or_uid input box is 16175431234.
Essentially, my form should then look something like this:
<form action={some code that puts the value of phone_or_uid here}>
...
</form>
Is this possible? And if so, how could I accomplish this? I don't want to create or redirect to any extra files, if possible.

I would use JavaScript. Listen for the submit event and redirect to a custom url.

this is just a really general example:
<form method="post" onsubmit="submitFunction()">
<label for="phone_or_uid">Enter a phone number or uid:</label>
<input type="text" name="phone_or_uid" id="phone_or_uid" value=""></input>
<input type="submit" name="" value="Submit"></input>
</form>
<script>
submitFunction = (event) => {
event.preventDefault();
const phoneInfo = document.getElementById('phone_or_uid').value;
fetch('http://myhost.com/lookup/' + phoneInfo, {
method: 'post'
})
.then(response => {
window.location.href = "http://myhost.com/lookup/' + phoneInfo";
});
}
</script>

PHP 2 actions from a single Button

I am wondering how to get 2 actions in PHP from a single Button.
Attached here is an screenshot of the page:
I have the following code:
For the Submit button
<form method='POST'>
<div class="form-group">
<input type="text" name="s_amount" style='width:20%;' required>
<input type="submit" class="btn btn-primary" name="submit" value="Submit" />
</div>
</form>
<?php
$s_amount = $_POST['s_amount'];
echo $s_amount;
?>
AND for the Submit Code button
<button id="submitcode"type="button" class="btn btn-default">Submit Code</button>
<pre><code id="output">.../...</code></pre>
When the Submit code is pressed, this executes the following script
<script>
$(document).ready(function(){
$("#submitcode").on("click", function(){
ocpu.seturl("https://public.opencpu.org/ocpu/library/base/R")
//arguments
var mysnippet = new ocpu.Snippet("V_CT="+$('[name="CT"]:radio:checked').val()+"\r V_TP="+$('[name="LENGTH"]:radio:checked').val()+$('#input2').val());
//perform the request
var req = ocpu.call("identity", {
"x" : mysnippet
}, function(session){
session.getObject(function(data) {
//data is the object returned by the R function
$("#output").text(data);
});
});
})
});
</script>
What I would like to have is a single button, which not only gets the value next to the first submit button (here 12, see attached pciture) but also executes the script.
Many thanks !

try giving id to form tag and on click on submitcode button call the form using its id.
for ex.
<form method='POST'>
function(session){
session.getObject(function(data) {
//data is the object returned by the R function
$("#output").text(data);
// using form id call the form
$("#formdata").submit(); // it will simply submit the form.
});
});
<form method="post" id="formdata"> <!--assign id to form tag-->
</form>

Could finally do it very easily using js.
<input type="text" id="VTP" value="0">
and get the value in the javascript form
document.getElementById("VTP").value
# nikhil borikar: Thanks but it did not work

I have 1 form with 2 submit buttons

I am trying to set-up a form that has 2 buttons, accept and deny. It doesn't seem to be working. Any thoughts on what I should fix?
<form name="iform" method="post" onsubmit="" onreset="" enctype="multipart/form-data" action="formapprovedeny" class="iform">
Form content here.
<input type="button" onclick="submitForm('html_form_approve.php')" class="submit_button" value="Approved" name="Approved" />
<input type="button" class="submit_button" onclick="submitForm('html_form_deny.php')" value="Denied" name="Denied" />
</form>
Here is the script part.
<script>
function submitForm(action)
{
document.getElementById('formapprovedeny').action = action;
document.getElementById('formapprovedeny').submit();
}
</script>

Your Javscript is trying to submit a form with an id of formapprovedeny but your form does not have an id. Try adding id="formapprovedeny" to your form

It should id="formapprovedeny" not action="formapprovedeny"
<form name="iform" method="post" onsubmit="" onreset="" enctype="multipart/form-data" id="formapprovedeny" class="iform">

You have a problem with your naming.
You try to get the form by it's id, but it is not set. It's name is.
You should use either getElementByName or give your form an id.

The type of button must be 'submit' and the value whatever you want, look this:
<input type="submit" class="submit_button" value="Approved" name="Approved" />
<input type="submit" class="submit_button" value="Denied" name="Denied" />

What do you want to achieve using the 2 buttons? What do you expect?
http://jsfiddle.net/xaW5P/
<script>
function submitForm(action)
{
alert('hello submitForm '+action);
document.getElementById('formapprovedeny').action = action;
document.getElementById('formapprovedeny').submit();
}
</script>
if I use your code (added an alert) this seems to work...whatever it should be doing ;)

using javascript to modify form action submits form without doing submit

I have an HTML form that I submit after changing the action with some javascript. Two different buttons can do the submit.
The interesting thing is that I was trying to debug it and inserted an alert after changing the action and before submitting the form. The form is submitted without the alert ever being displayed. To make sure it's actually performing the javascript, I added an alert before changing the action. That alert displays; the alert after changing the action does not.
<form name='FormSelect' method='post' action='Undefined'>
...
<button onclick="SubmitForm('class')">Submit</button>
...
<button onclick="SubmitForm('student')">Submit</button>
...
</form>
<script type="text/javascript">
function SubmitForm(target){
alert("Action 1: " + document.FormSelect.action);
if (target=="class") {
document.FormSelect.action = "ClassAction.php";
} else {
document.FormSelect.action = "StudentAction.php";
}
alert("Action 2: " + document.FormSelect.action);
// document.FormSelect.submit();
}
</script>
Is that the expected sequence of events?

Any button placed inside form element will cause submit action. To prevent this you can add type="button" to button elements, or make you submit callback return false;
<button type="button" onclick="SubmitForm('class')">Submit</button
see http://jsfiddle.net/yD2Uu/

As the others have already pointed out the form will be submitted anyway if you don't cancle the event. I want to suggest a JavaScript free solution to your problem.
<button formaction="ClassAction.php">Submit</button>
<button formaction="StudentAction.php">Submit</button>
It's not supported in IE < 10 though. But you can still use your function as a fallback then, just a bit more elegant ;)
function SubmitForm(button){
button.form.action = button.formaction;
}

A better solution is to give the buttons a name each and submit to Action.php and let the server get the value of the named button
$student = filter_var($_POST["student"], FILTER_SANITIZE_STRING); // php5 cleaning
when you have
<form method="post" action="Actions.php">
<input type="submit" name="student" value="John Doe" />
<input type="submit" name="student" value="Jane Doe" />
<input type="submit" name="student" value="Whatever Doe" />
</form>
Otherwise if you must
Try this
<form method='post' action='Undefined'>
...
<input type="button" value="Class" onclick="SubmitForm(this)" />
...
<input type="button" value="Student" onclick="SubmitForm(this)"/>
...
</form>
<script type="text/javascript">
var actions = {
"class":"ClassAction.php",
"student":"StudentAction.php"
}
function SubmitForm(button){
button.form.action = actions[button.value];
button.form.submit();
}
</script>

Thanks to Yauhen Vasileusky's example, I started removing code between my 1st & 2nd alerts and found that the problem seems to be the following IF statement:
if (document.FormSelect.FormName.value.substr(0,19)=="ObservationRequest_" || document.FormSelect.FormName.value=="StudentReg2013rx" || document.FormSelect.FormName.value=="Toddler Update Form v3rx")
{
document.FormSelect.action = "GenerateXDP.php";
}
When I remove it, both alerts are displayed. So the answer to my question is that changing the action does not submit the form; it was some other error in my code that made it appear as if that was the case.