I am experimenting with animation in <canvas> and can't work out how to draw an image at an angle. The desired effect is a few images drawn as usual, with one image rotating slowly. (This image is not at the centre of the screen, if that makes any difference).
You need to modify the transformation matrix before drawing the image that you want rotated.
Assume image points to an HTMLImageElement object.
var x = canvas.width / 2;
var y = canvas.height / 2;
var width = image.width;
var height = image.height;
context.translate(x, y);
context.rotate(angleInRadians);
context.drawImage(image, -width / 2, -height / 2, width, height);
context.rotate(-angleInRadians);
context.translate(-x, -y);
The x, y coordinates is the center of the image on the canvas.
It is interesting that the first solution worked for so many people, it didn't give the result I needed.
In the end I had to do this:
ctx.save();
ctx.translate(positionX, positionY);
ctx.rotate(angle);
ctx.translate(-x,-y);
ctx.drawImage(image,0,0);
ctx.restore();
where (positionX, positionY) is the coordinates on the canvas that I want the image to be located at and (x, y) is the point on the image where I want the image to rotate.
I have written a function (based on Jakub's answer) that allows user to paint an image in a X,Y position based on a custom rotation in a custom rotation point:
function rotateAndPaintImage ( context, image, angleInRad , positionX, positionY, axisX, axisY ) {
context.translate( positionX, positionY );
context.rotate( angleInRad );
context.drawImage( image, -axisX, -axisY );
context.rotate( -angleInRad );
context.translate( -positionX, -positionY );
}
Then you can call it like this:
var TO_RADIANS = Math.PI/180;
ctx = document.getElementById("canvasDiv").getContext("2d");
var imgSprite = new Image();
imgSprite.src = "img/sprite.png";
// rotate 45º image "imgSprite", based on its rotation axis located at x=20,y=30 and draw it on context "ctx" of the canvas on coordinates x=200,y=100
rotateAndPaintImage ( ctx, imgSprite, 45*TO_RADIANS, 200, 100, 20, 30 );
Related
I am experimenting with animation in <canvas> and can't work out how to draw an image at an angle. The desired effect is a few images drawn as usual, with one image rotating slowly. (This image is not at the centre of the screen, if that makes any difference).
You need to modify the transformation matrix before drawing the image that you want rotated.
Assume image points to an HTMLImageElement object.
var x = canvas.width / 2;
var y = canvas.height / 2;
var width = image.width;
var height = image.height;
context.translate(x, y);
context.rotate(angleInRadians);
context.drawImage(image, -width / 2, -height / 2, width, height);
context.rotate(-angleInRadians);
context.translate(-x, -y);
The x, y coordinates is the center of the image on the canvas.
It is interesting that the first solution worked for so many people, it didn't give the result I needed.
In the end I had to do this:
ctx.save();
ctx.translate(positionX, positionY);
ctx.rotate(angle);
ctx.translate(-x,-y);
ctx.drawImage(image,0,0);
ctx.restore();
where (positionX, positionY) is the coordinates on the canvas that I want the image to be located at and (x, y) is the point on the image where I want the image to rotate.
I have written a function (based on Jakub's answer) that allows user to paint an image in a X,Y position based on a custom rotation in a custom rotation point:
function rotateAndPaintImage ( context, image, angleInRad , positionX, positionY, axisX, axisY ) {
context.translate( positionX, positionY );
context.rotate( angleInRad );
context.drawImage( image, -axisX, -axisY );
context.rotate( -angleInRad );
context.translate( -positionX, -positionY );
}
Then you can call it like this:
var TO_RADIANS = Math.PI/180;
ctx = document.getElementById("canvasDiv").getContext("2d");
var imgSprite = new Image();
imgSprite.src = "img/sprite.png";
// rotate 45º image "imgSprite", based on its rotation axis located at x=20,y=30 and draw it on context "ctx" of the canvas on coordinates x=200,y=100
rotateAndPaintImage ( ctx, imgSprite, 45*TO_RADIANS, 200, 100, 20, 30 );
I have a code sample where I am adjusting a large image to a smaller size with the canvas matching the size of the image. There is a rotate right functionality that will rotate the image inside of the canvas which will adjust the canvas size. I almost have it perfectly working but the image is perfect size only when original or upside down. I can't get the height to be right ratio when the image is rotated on left or right. Here is my jsfiddle and code which is modified code from a different fiddle. Image is just used as test.
var canvas=document.getElementById("canvas");
var ctx=canvas.getContext("2d");
var canvasWidth = 400;
var canvasHeight;
var degrees=0;
var image=document.createElement("img");
image.onload=function(){
canvas.width = canvasWidth;
canvasHeight = 400 / (image.width / image.height);
canvas.height = canvasHeight;
ctx.drawImage(image,0,0,canvas.width,canvas.height);
}
image.src="https://www.magezinepublishing.com/equipment/images/equipment/Lumix-DMCFZ330-5824/highres/Panasonic-Lumix-FZ330-Wide-P1010001_1438873612.jpg";
$("#clockwise").click(function(){
degrees+=90
if (degrees >= 360) degrees = 0;
if (degrees === 0 || degrees === 180 ) {
canvas.width = canvasWidth;
canvas.height = canvasHeight;
}
else {
// swap
canvas.width = canvasHeight;
canvas.height = canvasWidth;
}
ctx.save();
// you want to rotate around center of canvas
ctx.translate(canvas.width/2,canvas.height/2);
ctx.rotate(degrees*Math.PI/180);
ctx.drawImage(image, -canvas.width*0.5, -canvas.height*0.5, canvas.width, canvas.height);
ctx.restore();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<canvas id="canvas" ></canvas><br>
<button id="clockwise">Rotate right</button>
jsfiddle
Any help is appreciated.
Remember you rotate your image. You are changing the aspect ratio of the image when using the swapped canvas width/height in the image draw call. By your calculations, the original image, rotated, should already fit the canvas. The image you produce is also stretched because of this.
Use ctx.drawImage(image, -canvasWidth*0.5, -canvasHeight*0.5, canvasWidth, canvasHeight);.
Else said, you want to draw the same image, then rotate/translate it with canvas calls. But what you are doing is draw a different sized, stretched image when being rotated 90° or 270° and then rotate/translate that.
To rotate an image in 90deg steps.
Rather the use the translate and scale you can rotate the image by directly setting the tranformation matrix.
ctx.setTransform(a,b,c,d,e,f);
The arguments are as follows
a,b the vector describing the direction and size of a pixels x axis
c,d the vector describing the direction and size of a pixels y axis
e,f the coordinate of the origin (where 0,0 will be)
All these are in canvas pixel coordinates. The default is a = 1, b =0 x axis of a pixel is 1 pixel across, and 0 down, c = 0, d = 1 y axis 0 pixels across and one pixel down, e = 0, f = 0 origin at the top left.
To rotate the image 90 deg clockwise you want the xAxis to go down the canvas and the y axis to go from right to left. The origin is shifted to the top right of the canvas.
ctx.setTransform(
0,1, // x axis down
-1,0 // y axis from left to right
ctx.canvas.height, // origin x and y to top right
0,
)
ctx.drawimage(image,0,0);
As you are scaling by 0.5 this means the pixels will be half the size, and as you are drawing an image you want the origin so that the image fits the image.
// rotate image 90 deg and scale 0.5
ctx.setTransform(
0,0.5, // x axis down
-0.5,0 // y axis from left to right
image.height * 0.5, // origin x and y to top right
0,
)
ctx.drawimage(image,0,0);
You can do the same for each additional rotation
// rotate 180 scale 0.5
ctx.setTransform(-0.5,0,0,-0.5, image.width * 0.5,image.height * 0.5);
// rotate -90 scale 0.5
ctx.setTransform(0,-0.5,0.5,0, 0,image.width* 0.5);
The image dimensions for each rotation is as follows
// for 0deg and 180 deg rotation
canvas.width = image.width * 0.5;
canvas.width = image.height * 0.5;
// for 90deg and -90 deg rotation
canvas.width = image.height * 0.5;
canvas.width = image.width * 0.5;
To restore the transform to the default just set the transform to the identity matrix
ctx.setTransform(1,0,0,1,0,0);
I have a canvas tag:
<canvas width="321" height="240" id="img_source"></canvas>
I want to add a crop functionality, so I made a resizeable div that can identify the borders of cropped image through dragging the corners of the div using the mouse. It looks like the image below:
I'm currently using "toDataURL()" to convert the data from the canvass to an image that can be displayed by an <img> tag. My question is, How will I convert to an image only part of the canvas that was identified by the resizeable div?
Use the method getImageData with the selected rectangle coordinates. For example:
let imageData = ctx.getImageData(65, 60, 100, 100);
Then create a secondary canvas with the desired sizes and use putImageData to set the pixels:
let canvas1 = document.createElement("canvas");
canvas1.width = 100;
canvas1.height = 100;
let ctx1 = canvas1.getContext("2d");
ctx1.rect(0, 0, 100, 100);
ctx1.fillStyle = 'white';
ctx1.fill();
ctx1.putImageData(imageData, 0, 0);
Finally use toDataURL to update the image:
dstImg.src = canvas1.toDataURL("image/png");
See the full sample I've prepared for you in CodePen
Create a new canvas at destination size, draw in the cropped image using drawImage() and insert that canvas into the DOM avoiding using img and data-uri:
var ccanvas = document.createElement("canvas"),
cctx = ccanvas.getContext("2d");
ccanvas.width = w;
ccanvas.height = h;
// draw with crop arguments
cctx.drawImage(image_src, x, y, w, h, 0, 0, w, h);
// ^^^^^^^^^^ source region
// ^^^^^^^^^^ dest. region
// insert cropped image somewhere in the DOM tree:
document.body.appendChild(ccanvas);
window.onload = function() {
var img = document.getElementById("image_src");
document.body.appendChild(region2canvas(img, 150, 60, 220, 200));
}
function region2canvas(img, x, y, w, h) {
var ccanvas = document.createElement("canvas"),
cctx = ccanvas.getContext("2d");
ccanvas.width = w;
ccanvas.height = h;
// draw with crop arguments
cctx.drawImage(img, x, y, w, h, 0, 0, w, h);
return ccanvas;
}
<img src="http://i.imgur.com/kWI4Cmz.png" id="image_src">
The key to cropping from one image is that the context's drawImage method allows us to render a cropped section of the source image to the canvas.
context.drawImage(img, sx, sy, sw, sh, dx, dy, dw, dh);
img - Source image object
sx - Source x
sy - Source y
sw - Source width
sh - Source height
dx - Destination x
dy - Destination y
dw - Destination width
dh - Destination height
Create a new canvas, and copy the selected portion to that new canvas, and then get the toDataURL() from that new canvas.
I want to achive the following:
Draw a bg-image to the canvas (once or if needed repeatedly)
The image should not be visible at the beginning
While i "paint" shapes to the canvas the bg-image should get visible where the shapes were drawn
The parts of the image that will be revealed shall be "painted" (like with a brush) so i want to use strokes.
What i tried:
- Do not clear the canvas
- Paint rects to the canvas with globalCompositeOperation = 'destination-in'
This works, the rectangles reveal the image but i need strokes
If i use strokes they are ignored with 'destination-in' while i see them with normal globalCompositeOperation.
Is this intended that the strokes are ignored? Is there a workaround like somehow converting the stroke/shape to a bitmap? Or do i have have to use two canvas elements?
In OpenGL i would first draw the image with its rgb values and with a = 0 and then only "paint" the alpha in.
You can solve it by these steps:
Set the image as a pattern
Set the pattern as fillStyle or strokeStyle
When you now fill/stroke your shapes the image will be revealed. Just make sure the initial image fits the area you want to reveal.
Example showing the principle, you should be able to adopt this to your needs:
var ctx = canvas.getContext("2d"),
img = new Image,
radius = 40;
img.onload = setup;
img.src = "http://i.imgur.com/bnAEEXq.jpg";
function setup() {
// set image as pattern for fillStyle
ctx.fillStyle = ctx.createPattern(this, "no-repeat");
// for demo only, reveals image while mousing over canvas
canvas.onmousemove = function(e) {
var r = this.getBoundingClientRect(),
x = e.clientX - r.left,
y = e.clientY - r.top;
ctx.beginPath();
ctx.moveTo(x + radius, y);
ctx.arc(x, y, radius, 0, 2*Math.PI);
ctx.fill();
};
}
<canvas id=canvas width=900 height=600></canvas>
Hope this helps!
Alternative solution:
Put the image as a normal image on your website
add a canvas and use CSS positioning to place it right above the image
Fill the canvas with the color you use as the page background
have your paint tools erase the canvas when you draw. By the way, you can set context.globalCompositionOperation = 'destination-out' to turn all drawing operations into an eraser.
Here is an example. As you can see, the alpha properties of your tools are respected.
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');
//prepare canvas
ctx.fillStyle = '#ffffff'
ctx.fillRect(0, 0, 120, 120);
//prepare a 30% opacity eraser
ctx.globalCompositeOperation = 'destination-out';
ctx.lineWidth = 5;
ctx.strokeStyle = 'rgba(0, 0, 0, 0.3)';
// make random strokes around cursor while mouse moves
canvas.onmousemove = function(e) {
var rect = this.getBoundingClientRect();
var x = e.clientX - rect.left;
var y = e.clientY - rect.top;
ctx.beginPath();
ctx.moveTo(x + Math.random() * 33 - 16, y + Math.random() * 33 - 16);
ctx.lineTo(x + Math.random() * 33 - 16, y + Math.random() * 33 - 16);
ctx.stroke();
}
<span>Move your mouse:</span>
<div>
<img src='https://upload.wikimedia.org/wikipedia/commons/thumb/6/61/HTML5_logo_and_wordmark.svg/120px-HTML5_logo_and_wordmark.svg.png' style='position:absolute'>
<canvas id='canvas' width=120 height=120 style='position:absolute'></canvas>
</div>
I've created a basic HTML5 image slider where images move from top to bottom in a canvas.
I want all the images rotated at angle of 5 degrees. When I tried it out there seems to be some
distortion to the canvas and the image is not properly rotated.
I've tried the method for rotation mentioned in the below post
How do I rotate a single object on an html 5 canvas?
Fiddle - http://jsfiddle.net/DS2Sb/
Code
this.createImage = function (image, width, height) {
var fbWallImageCanvas = document.createElement('canvas');
var fbWallImageCanvasContext = fbWallImageCanvas.getContext('2d');
fbWallImageCanvas.width = width;
fbWallImageCanvas.height = height;
fbWallImageCanvasContext.save();
fbWallImageCanvasContext.globalAlpha = 0.7;
this.rotateImage(image, 0, 0, width, height, 5, fbWallImageCanvasContext);
fbWallImageCanvasContext.drawImage(image, width, height);
fbWallImageCanvasContext.restore();
return fbWallImageCanvas;
};
this.rotateImage = function (image, x, y, width, height, angle, context) {
var radian = angle * Math.PI / 180;
context.translate(x + width / 2, y + height / 2);
context.rotate(radian);
context.drawImage(image, width / 2 * (-1), height / 2 * (-1), width, height);
context.rotate(radian * (-1));
context.translate((x + width / 2) * (-1), (y + height / 2) * (-1));
};
The distortion you see is due to the fact that a rotated image will only fit in a larger canvas. So what we see is a rectangle view on a rotated image.
The computations are not that easy to get things done properly, but instead of pre-computing the rotated image, you might rotate them just when you draw them, which lets you also change the angle whenever you want (and opacity also btw).
So i simplified createImage, so that it just stores the image in a canvas (drawing a canvas is faster than drawing an image) :
this.createImage = function(image , width, height) {
var fbWallImageCanvas = document.createElement('canvas');
fbWallImageCanvas.width = width;
fbWallImageCanvas.height = height;
var fbWallImageCanvasContext = fbWallImageCanvas.getContext('2d');
fbWallImageCanvasContext.drawImage(image,0,0);
return fbWallImageCanvas;
};
And i changed drawItem so it draws the image rotated :
this.drawItem = function(ct) {
var angle = 5;
var radian = angle * Math.PI/180;
ct.save();
ct.translate(this.x + this.width/2 , this.y + this.height/2);
ct.rotate(radian);
ct.globalAlpha = 0.7;
ct.drawImage(fbc, - this.width/2, -this.height/2 , this.width, this.height);
ct.restore();
this.animate();
};
You'll probably want to refactor this, but you see the idea.
fiddle is here :
http://jsfiddle.net/DS2Sb/1/
Here is a link to a small html5 tutorial I created a while ago:
https://bitbucket.org/Garlov/html5-sidescroller-game-source
And here is the rotate code:
// save old coordinate system
ctx.save();
// move to the middle of where we want to draw our image
ctx.translate(canvas.width/2, canvas.height-64);
// rotate around that point
ctx.rotate(0.02 * (playerPosition.x));
//draw playerImage
ctx.drawImage(playerImage, -playerImage.width/2, -playerImage.height/2);
//and restore coordniate system to default
ctx.restore();