I am cloning a HTML drop down list using jQuery, the problem I have now is that there is no limit to the amount of cloned sections, and I have to capture all of the sections into a mySQL database.
How can I get all of those different sections with different ID's into a mySQL table, since I am using POST, how will the receiving PHP file know what variables to get from the header, and how do I get each cloned section to be it's own entry in the mySQL table?
my Javascript/jQuery:
$("span.remove").live('click', function(){
$(this).closest("div.container").fadeOut(400, function(){
$(this).remove();
$('#button').attr('disabled','');
});
});
//initialize the button
$('#button').attr('disabled','');
$('#button').click(function(){
var count = $("#systems_wrapper > .container").size();
var lastID = $("#systems_wrapper > .container:last").attr('id');
var exploded = lastID.split("_");
var increment = Number(exploded[1])+1;
if(count >= 5){
$('#button').attr('disabled','disabled');
}else {
$('#button').attr('disabled','');
}
var test = $('#systems_0.container').clone().attr('id', 'system_' + increment).appendTo('#systems_wrapper');
test.children(':nth-child(2)').append('<span class="remove"></span>');
test.children(':nth-child(2)').children(':first').attr('id', 'mail_' + increment);
});
//get the JSON object returned from test_post.php and run the necessary functions on the returned data
$.getJSON("test_post.php", function(data){
//clean out the select list
$('#box').html('');
//run the for loop to populate the drop down list
$.each(data, function(i, products) {
$('#box').append(
$('<option></option>').html(products.products)
);
});
});
HTML:
<h3>System Information:</h3>
<!-- Systems -->
<div id="systems_wrapper">
<div class="container" id="systems_0">
<label for="systems">Systems: </label>
<div>
<select id="box">
<option>Select one</option>
</select>
</div>
</div>
</div>
<div class="container">
<input type="button" id="button" name="button" value="add a system" />
</div>
This one has really stumped me, any help would be appreciated!
Thanx in advance!
You could pass an object via $.post(). But first, when you are cloning let the clone has a variable(as a property) containing some kind of id.
$('#systems_0.container').clone().attr('id', 'system_' + increment).appendTo('#systems_wrapper')[0].myID=increment;
postData={},sections=$('div[id^=systems_]');
sections.each(function(i){
var id=this.myID,self=$(this);
//for example, choose what to store here.
postData[id]=$('select#box option',self).toArray();
});
//posting
$.post('yourServerSideScript.php', postData,function(data){ console.log(data); });
Now your php predefined $_POST should be an array of ['1'=>[...], '2'=>[...], ...] and so on.
Related
I have a row/column table with switches, unfortunately the script can't find
the switches in the new column, basically after the end of the cell .
I tried modifying some of the scripts that were posted in the similar posts but
none of them worked. I am pretty much stuck at this point.
Here's my HTML and the java script that does the calculation for the switches:
<div style="margin-left:-178px">
<form action="file:///Users/jason/Desktop/Temp/JACK010.txt" target="_blank">
<font color="white">JACK010</font>
<input type="submit" value="CHECK ADDRESS">
<div id="checkbox-container">
<div style="margin-left:178px">
<div style="margin-top:-18px">
<div>
<input type="checkbox" id="option170">
</div>
</form>
</td>
</tr>
I have a lot of those, within the cell, and finally the JavaScript:
var checkboxValues = JSON.parse(localStorage.getItem('checkboxValues')) || {};
var $checkboxes = $("#checkbox-container :checkbox");
$checkboxes.on("change", function() {
$checkboxes.each(function() {
checkboxValues[this.id] = this.checked;
});
localStorage.setItem("checkboxValues", JSON.stringify(checkboxValues));
});
$.each(checkboxValues, function(key, value) {
$("#" + key).prop('checked', value);
});
Thank you!
Using only $("#checkbox-container :checkbox"); results in only reading the first container with the ID checkbox-container.
If you want to fetch all checkboxes, you should either change the checkbox-container to a class or use the following selector within jQuery:
var $checkboxes = $("div#checkbox-container :checkbox");
It will then loop through all the checkboxes, even if an ID is used instead of a class.
Keep in mind, that the ID of your checkbox (<input type="checkbox" id="option170">) must however change in order to get valid data and all the values you want.
Side note: Please keep your HTML code clean and valid.
I am new to web development and javascript and jquery
I am working in auto created dynamic input field as much as user want and save that list in database , I already did that .
but I am facing 3 problem with that :
if the user want to reload the page I lose the already created list.
I had to show the same list from database in the same fields for update and
I don't know how to do it !!
The counter of the list works fine if i delete a row it decrement in right
way , but if i want to delete for example number 4 in list from 8 row the
counter doesn't work properly .
here is the list :
and here is the html code :
<div id="initRow" class="row">
<div class="form-group">
<div class="col-md-1">
<input class="form-control no-border text-center" id="count" value="1" readonly style="background-color:#FFFFFF">
</div>
<div class="col-md-6">
<input type="text" class="form-control" name="AssistantFactorsToSuccessProject[]" id="AssistantFactorsToSuccessProject" placeholder="Value" />
</div>
<div class="col-md-2">
<label class="control-label"><a class="rowDelete"><span class="glyphicon glyphicon-minus"></span></a></label>
</div>
</div>
</div>
and here is the javascript code :
var $counter = document.getElementById('count');
function addRow(section, initRow) {
var counter = 1;
var newRow = initRow.clone().removeAttr('id').addClass('new').insertBefore(initRow),
deleteRow = $('');
newRow.on('click', 'a.rowDelete', function() {
removeRow(newRow);
})
.slideDown(300, function() {
$(this)
.find('input').focus();
})
}
function removeRow(newRow) {
newRow
.slideUp(200, function() {
$(this)
.next('div:not(#initRow)')
.find('input').focus()
.end()
.end()
.remove();
$counter.value = parseInt($counter.value) - 1;
});
}
$("#FeasibiltyStudyDate").val( moment().format('YYYY-MM-DD') );
$(function () {
var initRow = $('#initRow'),
section = initRow.parent('section');
initRow.on('focus', 'input', function() {
addRow(section, initRow);
$counter.value = parseInt($counter.value) + 1;
}
});
});
and here is how I save it as array in db :
for ($i=0;$i<count($_POST['AssistantFactorsToSuccessProject']);$i++) {
$f = implode("</br>", $_POST['AssistantFactorsToSuccessProject']);
$AssistantFactorsToSuccessProject = $f;
}
answers for the mentioned points in the query.
1)if the user want to reload the page I lose the already created list.
Your not storing the data in database so on page refresh client side data will be cleared.
2)I had to show the same list from database in the same fields for update and I don't know how to do it !!
through ajax or form submit store the data in database.
refer to the below link: https://www.formget.com/insert-data-in-database-using-php/
3)The counter of the list works fine if i delete a row it decrement in right way , but if i want to delete for example number 4 in list from 8 row the counter doesn't work properly .
for delete you have to delete by id.
like. $('itemid').remove(); // it will remove html entity of that id.
I have the following form. Each time the users clicks add_accommodation I want to add to an array that I will return to the end point (http://server/end/point).
<form action="http://localhost:3000/a/b/c" method="post">
<div>
<input type="hidden" id="Accommodation" name="accommodation"><div>
</div>
</form>
<div id="accommodation_component">
<div>
<label for="AccommodationType">Type:</label>
<input type="number" step="1" id="accommodationType" name="accommodation_type" value="0">
</div>
<div>
<button type="button" id="add_accommodation">Add Accommodation</button>
</div>
</div>
<script>
$( document ).ready(function() {
$('#add_accommodation').click(function() {
make_accommodation(this);
});
});
function make_accommodation(input) {
var value = {
type : $("#AccommodationType").val(),
};
var accommodation = $('#Accommodation').attr('id', 'accommodation');
accommodation.push(value);
console.log(accommodation);
}
</script>
At my end point I want the result to be and array (accommodation = [{1},{2},{3},{4}]). How can I do this?
Give the form an id, and just append a new hidden(?) input that has a name that has [] at the end of it, it will send the values as an array to the server.
HTML
<form id="myform" ...>
Javascript
function make_accommodation(){
var newInput = $("<input>",{
type:"hidden",
name:"accommodation[]",
value: {
type: $("#AccommodationType").val()
}
});
$("#myform").append(newInput);
}
Also you list the output as [1,2,3,4] but your code shows you setting the value as an object with a property type and setting it to the value of the accommodation input, i am going to assume that was a mistake. If I am mistaken just modify the value property in the code above.
Also in your code you change the id of the input, not sure why you were doing that as it serves no purpose and would have made your code error out so i removed it.
EDIT
Since you are wanting to send an array of objects, you will have to JSON.stringify the array on the client end and decode it on the server end. In this one you do not need multiple inputs, but a single one to contain the stringified data.
var accommodationData = [];
function make_accommodation(){
accommodationData.push({
type: $("#AccommodationType").val()
});
$("#accommodation").val( JSON.stringify(accommodationData) );
}
Then on the server you have to decode, not sure what server language you are using so i am showing example in PHP
$data = json_decode( $_POST['accommodation'] );
If you are using jQuery's ajax method you could simplify this by sending the array data
jQuery.ajax({
url:"yourURLhere",
type:"post"
data:{
accomodation:accommodationData
},
success:function(response){
//whatever here
}
});
Add antorher hidden field in form
<input type="hidden" name="accommodation[]"> // click1
<input type="hidden" name="accommodation[]"> // click2
...
<input type="hidden" name="accommodation[]"> // clickn
Then when you submit form on server you will have array of accommodation.
JS part :
function make_accommodation() {
$(document.createElement('input'))
.attr('type', 'hidden')
.attr('name', 'accommodation[]')
.val($("#AccommodationType").val())
.appendTo('form');
}
on server(PHP) :
print_r($_POST['accommodation']);
Since you're using jQuery you can create a function which creates another hidden field, after clicking on the button
<div id='acommodation-wrapper'></div>
<button type="button" id="add_accommodation" onclick="addAnother()">Add Accommodation</button>
<script type="text/javascript">
function addAnother(){
var accWrapper = $('#accommodation-wrapper');
var count = accWrapper.children().length;
var div = "<input type=\"hidden\" class=\"accommodation-"+count+"\" name=\"accommodation["+count+"]\"></div>";
accWrapper.append(div);
}
</script>
I have an application (drag and drop using JqueryUI.GridSort) that allows the user to upload photos, and then sort the photos in the order that they would like using drag and drop.
On page load, the user is prompted to upload photos which are posted to the next page. When they arrive on the next page my php script creates a <ul id="sortable"> containing <li> for each of the files they uploaded. For each picture that they have uploaded to the site, a new <li> is created. Inside of that <li> is a <img> that sets the picture for <li> with the image they have uploaded.
My goal is to be able to "save" the order of the pictures after they have arranged them in the drag and drop interface. For example, once they have finished arranging and sorting the pictures in the order they want them in, I would like to be able to send them another page that creates an xml file ( I don't need help with the XML, only saving the order) with using the list that they created in the correct order.
After hours of tinkering with PHP, I have come to realization that because PHP is a serverside language, it cannot see what is sorted post render. So my question is, is there a way to have JavaScript or Ajax read the current order of the list, and post it to the next page? If you do know how, could you please provide an example of both the POST from one page, and the post receiving on the other? I am not very familiar with Ajax.
Thank you greatly for any assistance you could provide.
Sample Code (The contents of the foreach statement that creates a LI for each file uploaded)
$imgID++;
echo '<li class="ui-state-default"><img id="'.$imgID.'"'.' src="user_files/'.$file_name.'" draggable="true" height="90" width="95"></li>';
EDIT
main page :
<script>
$('#my_form').on('submit', function() {
var ordered_list = [];
$("#sortable li img").each(function() {
ordered_list.push($(this).attr('id'));
});
$("#ordered_list_data").val(JSON.stringify(ordered_list));
});
</script>
<div id="tesT">
<form id="my_form" action="update_data.php">
<!-- other fields -->
<input type="hidden" id="ordered_list_data"></input>
<input type="submit" value="Proceed to Step 2"></input>
</form>
</div>
update_data.php:
<?php
// process other fields as normal
if(isset($_POST['ordered_list_data'])) {
$img_ordering = json_decode($_POST['ordered_list_data']);
echo "1";
} else {
echo "nodata";
}
// do things with the data
?>
I built a JSFiddle doing basically the same thing that David posted.
I added a piece to write out the result to a div on the page, so you can see what's going on:
<input type="button" id="savebutton" value="save"/>
<div id="output"></div>
<form id="listsaveform" method="POST" action="script.php">
<input type="hidden" name="list" id="hiddenListInput" />
</form>
Javascript:
$(function() {
$( "#sortable" ).sortable();
$( "#sortable" ).disableSelection();
$( "#savebutton" ).click(function() { LISTOBJ.saveList(); });
});
var LISTOBJ = {
saveList: function() {
var listCSV = "";
$( "#sortable li" ).each(function() {
if (listCSV === "") {
listCSV = $(this).text();
} else {
listCSV += "," + $(this).text();
}
});
$("#output").text(listCSV);
$("#hiddenListInput").val(listCSV);
//$("#listsaveform").submit();
}
}
If you're using a <form> you can do something like this (assuming jQuery is being used):
$('#my_form').on('submit', function() {
var ordered_list = [];
$("#sortable li img").each(function() {
ordered_list.push($(this).attr('id'));
});
$("#ordered_list_data").val(JSON.stringify(ordered_list));
});
In essence, what you're doing is looping over the <ul>, fetching each <img> and appending the ids (in order of appearance) to an array. Arrays preserve ordering in JavaScript and JSON, so one can turn it into a JSON string using the JSON.stringify function, set it as the value of a <input type="hidden"> field and then submit the form.
If you want to use AJAX, the functionality is very similar. However, instead of using an onsubmit (or onclick) you'd use $.post.
Let's go with the <form> option since it's simpler. All told you'll have something similar to the above JS along with HTML like this:
<form id="my_form" method="post" action="./update_data.php">
<!-- other fields -->
<input type="hidden" name="ordered_list_data" id="ordered_list_data"></input>
<input type="submit" value="Submit"></input>
</form>
Then, in update_data.php (or whatever your script is named):
<?php
// process other fields as normal
if(isset($_POST['ordered_list_data'])) {
$img_ordering = json_decode($_POST['ordered_list_data']);
} else {
// handle case where there is no data
}
// do things with the data
?>
I am sure this is so easy and I'm just a huge huge noob. I have a form on a PHP page, and it has a few normal form elements (1 textarea, 1 text field).
I am also dynamically adding 100 small images to the page, which are random, and I am using JQuery to let someone select or deselect these images:
Here is the html that loops 100 times to display the images:
<div class='avatar'><img class='avatar_image' src='$this_profile_image' name='$thisfriend'></div>
and here is the Jquery:
<script type="text/javascript">
$(document).ready(function() {
$(".avatar_image").click(function() {
$(this).toggleClass("red");
});
});
</script>
What I want to do is, when the form is submitted, have the script that processes it be able to tell which of those 100 images is selected (so it's class will be "red" instead of "avatar_image"). I am blanking on this.
You'll need to add hidden inputs with some kind of identifiers for those images, and toggle the state of those inputs based on the image selected-ness. Something like this:
Change your image markup:
<div class='avatar'>
<img class='avatar_image' src='$this_profile_image' name='$thisfriend'>
<input type="hidden" name="avatar_image[]" value="$this_profile_image" disabled="disabled" />
</div>
Change jQuery binding (and use event delegation, maybe pick a better container than document.body):
<script type="text/javascript">
$(function() {
var selClass = 'red';
$(document.body).on('click', ".avatar_image", function() {
var $this = $(this);
var $inp = $this.siblings('input[type="hidden"]');
var isSelected = $this.hasClass(selClass), willBeSelected = !isSelected;
$this.toggleClass(selClass);
if(willBeSelected) {
$inp.removeAttr('disabled');
} else {
$inp.attr('disabled', 'disabled');
}
});
});
</script>
Read the submitted data in PHP (assuming you're submitting via a POST form):
$selectedImages = $_POST['avatar_image'];
Add a ID to each image, when its clicked grab the id and then inject it into a hidden textfield
<input type="hidden" name="avatar" id="avatar" value="" />
$(".avatar_image").click(function() {
$(this).toggleClass("red");
//assign its id to the hidden field value
$("input[name='avatar']").attr('value', $(this).attr('id'));
// pass that to your DB
});
I presume your using ajax to grab this data back
success : function(callback){
$("image[id*='"+callback.avatar+"']").addClass('red');
}
Try this
PHP: Add the id for the friend to the html you had
<div class='avatar'>
<img class='avatar_image' src='$this_profile_image' name='$thisfriend' data-id='$thisFriendsId>
</div>
JS: Create an empty array. Use each function to go through push the selected id into your array. Then use post to submit to your php.
selected = [];
$(function(){
$(".avatar_image").click(function() {
$(this).toggleClass("red");
});
$('.submit').click(function(){
$('.red').each(function(){
var selectedId = $(this).data('id');
selected.push(selectedId);
});
$.post ('http://mysite.com/process.php', selected, function() { alert('succes!'); });
});
});