In the following code why the variable 'a' refer to the index rather than the value ?
for (var a in Values) {
alert(Values[a]);
}
That's by design. It's trivial to get a value in an array when you know its key, but it's much harder to get a key given a value. Values can be duplicated, so how do you know which key should be used? But a key's unique, so given a key, there's only ever one value to retrieve. So, the for loop will iterate over the keys, and it's trivial to get the associated value.
Think of a JavaScript Array as a normal Object with a special property named length (actually, it a bit more complex). So the for..in loop behaviour is identical as for other objects:
var a = new Array();
a[1] = "a";
alert(a.length); // 2
alert(a[0]); // undefined
a[1000] = "b"
alert(a.length); // 1001
a[-1] = "c";
alert(a[-1]); // c
a.abc="why not";
for(var key in a)
{
alert(key+"="+a[key]);
}
// 1=a
// 1000=b
// -1=c
// abc=why not
Also note that you can have gaps within your array without having to pay the memory price.
There is a for each...in loop that does exactly that - enumerates only values. Coming soon to a browser near you.
for each(var a in Values) {
..
}
For arrays, there is a new function forEach which achieves the same.
someArray.forEach(function(value) {
..
});
Related
Why does this array have a length property of 0? And as a follow up to that question, why can't you access an item in this array with an index value?
Consider the following:
var box = [];
box['material'] = 'cardboard';
box['size'] = 'small';
box.length; //0
console.log(box);
//[ material: 'cardboard', size: 'small' ]
box[0]; //undefined
However, when I do the following:
var box = [];
box['0'] = true;
box['1'] = 'cardboard';
box['2'] = 'some value';
box.length; //3
box[0];// true
Why does it output the correct length in this case, since '0' is a string and not a number and access the correct item with the 0 index?
In JavaScript, the length of an array is always one more than the largest numeric (integer) property name. Arrays can have properties whose names are not numeric, but they don't count towards the length of the array (and they are ignored in some other important situations).
Object property names are always strings, but strings that are non-negative integer values when interpreted as numbers are special in arrays. Accessing properties with numeric values works because the numbers are first converted to strings; thus box[0] and box['0'] do exactly the same thing.
when setting box['material'] it creates a property called 'material' with value 'cardboard'. this doesn't add a element to the list!
you need to use .push() or asign the index you want.
also, the '0' string is cased to a number, so obj['0'] and obj[0] is the same (not just for 0, this happens for all numbers)
I think you’re confusing objects with arrays. While arrays are indeed objects in javascript, that doesn’t help us here.
What you are trying to instantiate is an associative array with key-value pairs “material”->“cardboard”, “size”->“small”. However, such a datastructure does not exist in javascript. Array must only have integers as indexes, as in
box = [];
box[0] = 'material';
box[1] = 'someValue';
The reason why your code (which only seems to be an associative array)
box = [];
box['0'] = true;
box['1'] = 'cardboard';
works is because of implicit type conversion. Because you’ve declared box to be an array, a string is not valid in this position, so javascript quietly converts it into an integer, so you again get a plain, boring, integer-indexed array as above.
What you can do, though, is create an object with attributes. So you might, for example, state
box = {}; // box is now an object
box.size = 'small'; // box now has an attribute called “size”
// which has the (string) value “'small'”
box.material = 'cardboard';
or at one go using the notation for object literals:
box = {
size: 'small',
material: 'cardboard'
};
This is the closest you can get to associative arrays in javascript. Note that objects do not have a length. If you want to access the number of attributes they have, you have to use Object.keys(box).length. To iterate over the keys, use
for(var key in box){
console.log('value of ' + key + ' is ' + box[key])
}
Note the array-like notation here, but remember: You’re dealing with objects, not arrays, though dealing with them looks similar. Since box is of type object, you will not only get the attributes you have defined yourself, but also any attributes which are defined for every object. To get only the keys you put in there yourself, use
for (var key in box) {
if (box.hasOwnProperty(key)) {
// do stuff
}
}
If you need to add keys, i.e. attributes at runtime, use (for example)
//supposing that box was instantiated as above
var listOfBoxAttributes = ['shape', 'color', 'weight'];
for(var i in listOfBoxAttributes)
box[listOfBoxAttributes[i]] = undefined;
So here's my problem:
So this is what my array looks like, I have shown a fragment of it here (from the console window).
It's overall pretty basic right? Except for it's indexing. As you see the first has value "1" and let's say the second has value "4". As for it's subarrays, these have custom indexes too.
Therefore, the old fashioned:
for(i=0; i<array.length; i++){
someVar = array[i];
//do something
}
won't work.
I get the 1 or 4 from iterating through another array, so don't need to get those.
I want to get all subArrays(not the further nested subArrays, only the second level).
So basicly what I want is something like this(is there something like this?):
array[someIndex].children.forEach(
//do something with **this**
)
To make it more practical for you:
So I know that the first array has index 1. How can I get the values of cat1 and cat2 without knowing it has index 2 (this could also be 6 or 42 for example). In this case, the first array only has one subArray but I would like to make it work for multiple subArrays. (to clarify, select cat1, cat2 from the second level subarray with, in this case, index 2)
Thanks in advance, any help is appreciated!
Evoc
Those aren't arrays. You have
[ { "1": { etc...
which is an array containing an object containing multiple other objects. You can't really use a for(i=...) loop for this, because your keys aren't sequential. You should use a for ... in loop instead:
arr = [{"1":{....}}];
for (i in arr[0]) {
for (j in arr[0][i]) {
console.log(arr[0][i][j]['msg']);
}
}
Use Object.getOwnPropertyNames to get the properties ordered with the integer indices first, from smallest to greatest. Iterate them to get msg1.
var array = {"1":{"3":{"5":{"data":"someData","moreData":"someMoreData"},"msg1":"hello world","msg2":"foo equals bar"},"5":{"8":{"data":"someData","moreData":"someMoreData"},"msg1":"world hello","msg2":"bar equals foo"},"your_name":"jimmy","your_msg":"hello world"},"4":{"3":{"5":{"data":"someData","moreData":"someMoreData"},"msg1":"hello world","msg2":"foo equals bar"},"5":{"8":{"data":"someData","moreData":"someMoreData"},"msg1":"world hello","msg2":"bar equals foo"},"your_name":"billy","your_msg":"foo equals bar"}};
for(let key of Object.getOwnPropertyNames(array[1])) {
if(Object(array[1][key]) !== array[1][key]) break;
console.log('msg1 of "'+key+'": ' + array[1][key].msg1);
}
console.log('your_msg: ' + array[1].your_msg);
The example you showed it's an array with only one index, inside of this index there are nested objects, you could iterate them using the property iterator (foreach). You have to go to the second level tho, since the values you need are there.
for (var key in object) {
for(var anotherKey in object[key]) {
//check for undefined
if(object[key][anotherKey].hasOwnProperty('msg')) {
//code
}
}
}
{ } - declaring objects (literal)
[ ] - declaring arrays
As per what I know, arrays in Javascript is nothing but the combination of methods and objects.
Now my task is to display the values of array (say y_array)
I have used for(x in y_array) and then displayed the value.
In mozilla and in IE its working fine, but in IE it displays the first element of array with index as indexOf and value is indexOf(obj, from) which i dont want.
I tried
if(x!='indexOf') { display the array value ; }
It worked and things were fine but there is extensive use of arrays been displayed and I am looking for some permanent fix rather than this hardcoded one.
Can anyone please help me?
You are not the first mixing up arrays and objects. SO should contain a FAQ for this kind of questions ;)
Let's try to explain things:
An array is a row of values, which can be retrieved using their position in the row. The order of the array values is fixed (and may be reordered).
An object is a variable that contains named properties in the form of key-value pairs. The order of the key-value pairs belonging to an object is arbitrary.
An array looks like: [ 'first', 'second', 'third', ..., 'nth' ]
An object looks like: { first:'firstvalue', second:'secondvalue', ..., nth:'nthvalue' }
The first element of an array is the element with index 0 (so the first position in the row has index value 0). You retrieve it using myArray[0]
An object is unordered, so it has no first element. You retrieve any element from it using myObject.somekey or myObject['somekey'].
For arrays you use a loop iterating through the numbered index until the end of the array is reached:
var i=0, len = myArray.length;
for ( i; i<len; i++ ) {
//do something with >>> myArray[i] <<<
}
For objects you use a loop using the key and the in operator (making sure you are only retrieving user defined properties of the object with the .hasOwnAttribute method):
for ( var key in myObject ){
if (myObject.hasOwnProperty(key)) {
// do something with >>> myObject[key] <<<
}
}
Basically, think of an array as a cupboard with drawers, each containing a value. An object can be imagined as a pile of boxes with stickers on the lid, describing the content of the box. Retrieving something from an object, you ask: is there a box with sticker y in pile x and if so, what's in it? Retrieving something from an array, you ask: please give me the contents of drawer nr x.
Now as to your question: the array you are retrieving values for with a for..in loop contains a user defined method, namely indexOf. Using the object style loop for it, the array is treated as object, and the indexOf key (with value like function(){...} I bet) is shown too. IE That's why it may be better to use a traditional for loop with a numeric index when iterating over arrays.
Why is this only in IE? In modern browsers indexOf is a native method of the Array prototype, and native methods are not shown (unless you loop through their prototype that is). IE < 9 doesn't have a native indexOf method for arrays. Somewhere in the scripting you use the method has been added to the Array prototype as a user defined extension.
Bottom line for your problem: don't use for ... in to loop through the values of an array.
For arrays you should use this for loop:
var y_array = [1,2,3,4];
for (var i = 0; i < y_array.length; i++) {
var value = y_array[i];
// do what you want
alert(i + ': ' + value);
}
For objects (objects are like associative arrays - property: value) use this loop:
var y_array = { prop_1 : "value a", prop_2: "value_2", prop_3: 333 }
for (var key in y_array) {
var value = y_array[key];
// do what you want
alert(key + ': ' + value);
}
if there is no value in your json Object like jsobObj = {}. Then you got the indexOf prototype function in side the empty object in IE < 9. (with value like function(){...} I bet) is shown too.
Your can check a condition in side your for Loop. and skip that indexOf.
if(key =='indexOf'){continue;}
E.g :
var jsonObj = { key_1 : "value a", key_2: "value_2", key_3: 333 }
for (var key in y_array) {
if(key == 'indexOf'){continue;} // check if the array contain indexOf
var value = y_array[key];
// do what you want
alert(key + ': ' + value);
}
Can anyone explain why the second alert says 0 ?
var pollData = new Array();
pollData['pollType'] = 2;
alert(pollData['pollType']); // This prints 2
alert(pollData.length); // This prints 0 ??
The length of the array is only changed when you add numeric indexes. For example,
pollData["randomString"] = 23;
has no effect on length, but
var pollData = [];
pollData["45"] = "Hello";
pollData.length; // 46
changes the length to 46. Note that it doesn't matter if the key was a number or a string, as long as it is a numeric integer.
Besides, you are not supposed to use arrays in this manner. Consider it more of a side effect, since arrays are objects too, and in JavaScript any object can hold arbitrary keys as strings.
Because you haven't put anything into the array yet. You've only been assigning to a dynamically-created pollType attribute on the array object.
If you use numeric indices, then the array automagically takes care of length. For example:
var arr = [ ]; // same as new Array()
arr[2] = 'Banana!';
alert(arr.length); // prints 3 (indexes 0 through 2 were created)
The length property takes into consideration only those members of the array which names are indexes (like '1', '2', '3', ... ).
Arrays in JavaScript have numeric indexes only.
Use an object, which is essentially what you are doing above, setting properties on that array object.
array.length returns how many values are stored in the array. The first alert is returning the value of the position 'pollType'.
The reference guide I always use when needing help with javascript arrays is this page http://www.hunlock.com/blogs/Mastering_Javascript_Arrays
I'd also read what it says under the heading Javascript Does Not Support Associative Arrays, as you may run into problems with this also.
var pollData = Array();
function test() {
pollData[0] = 2
alert(pollData[0]);
alert(pollData.length);
}
//[x] is the array position; hence ['polltype'] is causing issues
When I do something like this:
var o = new Array();
o[20] = true;
o[1000] = true;
o[4000] = true;
Is it reasonable to expect that only 3 elements will be allocated or can the implementation decide to suddenly allocate something with 4000 elements?
The reason I'm asking is that when I do this I see in firebug an indication that there are actually 4000 undefined in o. are they really there?
Now that we know that o is an Array, I can answer you precisely.
No, the elements will not be 'allocated' or 'created'.
When you make an assignment of an index property to an Array object, which is greater than the actual length of the array two things happen:
The index named property is created
The length property is incremented, to be the index + 1
For example:
var o = [];
o[4000] = true;
o.hasOwnProperty(0); // false, the property doesn't exist
o.hasOwnProperty(1); // false
o.hasOwnProperty(4000); // true, the property exist
As you can see, the hasOwnProperty method returns false when we test the presence of the 0 or 1 properties, because they don't exist physically on the object, whereas it returns true for 4000, the property that was created.
When Firebug detects that the object being printed in the console is an array-like object, it will simply make a loop, showing each of the index values from 0 to length - 1.
Firebug detects array-like objects simply by looking if they have a length property whose its value is an unsigned 32-bit integer (less than 2^32 - 1), and if they have a splice property that is a function, for example, the following object will be detected and printed as an Array on the Firebug's console:
console.log({length:3, splice:function(){}});
// Firebug will log: `[undefined, undefined, undefined]`
a) That code is not valid. You need either var o = {}; // object or var o = []; // array.
b) In the first case, the object is sparse. In the second, it may depend on the interpreter; in modern browsers it is also sparse. Try o[99999999] = "hi"; and see how much memory your browser does or does not allocate. If it does not go up by at least 10MB, your arrays are sparse.
I think this one answers the question.
Are Javascript arrays sparse?
And according to that one, arrays are spares, thats is, if you use for(item in array) you only get 3 items, not 4000 but if you use array.length it will take the larges integer value and return one larger, look here:
http://www.crockford.com/javascript/survey.html
Linkpad will use a for(item = 0; item < array.length; item++) and that one will return undefined for any index that is not present in the array.
/*
On the other hand, if you have a very large index any array manipulation will have to loop
through each index- it won't skip from one defined item to the the next defined item.
*/
var A= [];
A[0]= 'a';
A[10]= 'b';
A[4000000]= 'c';
alert(A.filter(function(itm){
return itm!= undefined;
}));
Javascript will generate all elements inbetween, always. You may want to use o.length to verify the length of the array. It will return 4000 and not 3.