I've got my form validation almost working but I can't seem to figure this last problem out.
I'm trying to send back error messages and position them in their own div next to their relevant form fields.
I've got an error message coming back in its own div, but when I try to send multiple messages back nothing happens, any thoughts?
Here's most of my ajax
function regForm(thisform) { //Reg user form check
xmlHttp=GetXmlHttpObject();
if (xmlHttp==null) {
alert ("Browser does not support HTTP Request");
return;
}
var formdata = "";
formdata = "lname=" + thisform.elements['lname'].value + "&fname=" + thisform.elements['fname'].value + "&email=" + thisform.elements['email'].value + "&username=" + thisform.elements['username'].value + "&pass=" + thisform.elements['pass'].value + "&pass2=" + thisform.elements['pass2'].value; //send the data through the url - frist is the name i want to call it... second grad the content from the form using its id
xmlHttp.onreadystatechange=formSubmitted;
xmlHttp.open("POST", "adduser.php",true);
xmlHttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
xmlHttp.setRequestHeader("Content-length", formdata.length);
xmlHttp.setRequestHeader("Connection", "close");
xmlHttp.send(formdata);
return false;
}
function formSubmitted() {
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete") {
xmlDoc=xmlHttp.responseXML;
//document.getElementById("feedback").innerHTML = xmlHttp.responseText;
document.getElementById("feedback1").innerHTML= xmlDoc.getElementsByTagName("lname")[0].childNodes[0].nodeValue;
document.getElementById("feedback2").innerHTML= xmlDoc.getElementsByTagName("fname")[0].childNodes[0].nodeValue;
}
}
and here is my simple adduser.php page so far
<?php
header('Content-Type: text/xml');
$lname = mysql_real_escape_string($_POST['lname']);
$fname = mysql_real_escape_string($_POST['fname']);
if($lname == NULL) {
echo "<lname>NEED TO FILL</lname>";
}
//if($fname == NULL) {
//echo "<fname>NEED TO FILL</fname>";
//}
else {
echo "<lname> </lname>";
//echo "<fname> </fname>";
}
?>
As you can see I've got the fname information commented out right now and my messaging is working for lname but as soon as I uncomment the fname stuff in hopes to send a message for both lname and fname nothing happens I don't understand why.
Any insight would be a big help! Thanks.
I don't entirely understand what you mean by "coming back in its own div" but you are aware that an element ID must be unique in the document? There doesn't happen to happen that you get two DIVs of the same ID if the error DIV comes back?
Try having only a single echo statement at the very end of the script (so have a variable to concatenate all your error messages and only echo it at the very end).
Also, I would very strongly recommend using a JS library (like jQuery) for all your ajax needs - will make your life a whole lot easier
ok I've got it figured out and like always it was stupid why it wasn't working.
in my adduser.php page I just need to wrap the error message in a xml tag.
echo "<errors>";
//error content
echo "</errors>";
Related
Working example below, hopefully this will help others learn!
I'm using AJAX in javascript to send a JSON string to PHP.
I'm not familiar with AJAX, javascript or php, so this is taking me a while to get started.
I have a html file with a username field, password field, and login button.
Then I have a javascript file that takes the username pass and sends it to a php file.
I know the php file is being accessed because I am seeing the test echo in console.
I just cant figure out how to access the data I'm sending to the php.
script.
function attemptLogin(){
var inputUserName = JSON.stringify(document.getElementById("userName").value);
var ajaxData = new XMLHttpRequest();
ajaxData.open('GET', 'ajax.php', true);
ajaxData.onreadystatechange = function(){
var DONE = 4;
var OK = 200;
if (ajaxData.readyState === DONE) {
if (ajaxData.status === OK) {
console.log(ajaxData.responseText);
}else{
console.log("ERROR : " + ajaxData.status);
}
}
};
ajaxData.send(inputUserName);
}
ajax.php
<?php
echo"TestInPHP";
?>
For now all I want to do is echo the username back to console, I'm sure the syntax is something simple, I just cant figure out what it is.
Here is an edit for the working code thanks to SuperKevin in the
comments below. This code will take the string in the username and
password fields in HTML by the JS, send it to PHP and then sent back
to the JS to output to the browser console window.
index.html
<input type="text" name="userID" id="userName" placeholder="UserID">
<input type="password" name="password" id = passW placeholder="Password">
<button type="button" id = "button" onclick="attemptLogin()">Click to Login</button>
script.js
function attemptLogin(){
var inputUserName =
JSON.stringify(document.getElementById("userName").value);
// console.log(inputUserName);
var inputPassword = JSON.stringify(document.getElementById("passW").value);
var cURL = 'ajax.php?fname='+inputUserName+'&pass='+inputPassword;
var ajaxData = new XMLHttpRequest();
ajaxData.open('GET', cURL, true);
ajaxData.onreadystatechange = function(){
var DONE = 4;
var OK = 200;
if (ajaxData.readyState === DONE) {
if (ajaxData.status === OK) {
console.log(ajaxData.responseText);
}else{
console.log("ERROR : " + ajaxData.status);
}
}
};
ajaxData.send();
}
ajax.php
<?php
echo $_GET['fname'];
echo $_GET['pass'];
?>
Here's a simple example of how you would make a vanilla call.
This is our main file, call it index.php.
<script>
var xhttp = new XMLHttpRequest();
xhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
document.getElementById("demo").innerHTML = this.responseText;
}
};
xhttp.open("GET", "delete.php", true);
xhttp.send();
</script>
Here's our server script. delete.php
<?php
echo "HELLO THERE";
Now, if you wanted to pass data to your script you can do the following:
xhttp.open("GET", "delete.php?fname=Henry&lname=Ford", true);
xhttp.send();
To access this data you can use the global $_GET array in php. Which would look like this:
$fname = $_GET['fname'];
$lname = $_GET['lname'];
Obviously, you have to sanitize the data, but that's the gist of it.
For a much more in depth tutorial visit W3Schools Tutorial PHP - AJAX.
You can see all the data sent to your php with :
<?php
print_r($_GET); //if it's send via the method GET
print_r($_POST); //if it's send via the method POST
?>
So, in your case it will be something like :
<?php
echo $_GET['username'];
?>
If you're not using jQuery then don't pay attention to my answer and stick to the pure javascript answers.
With jQuery you can do something like this:
First Page:
$.ajax({
url: 'sportsComparison.php',
type: 'post',
dataType: 'html',
data: {
BaseballNumber = 42,
SoccerNumber = 10
},
success: function(data) {
console.log(data);
});
which will send the value 42 and 10 to sportsComparison.php with variable names BaseballNumber and SoccerNumber. On the PHP page they can then be retrieved using POST (or GET if that's how they were sent originally), some calculations performed, and then sent back.
sportsComparison.php:
<?php
$BaseballValue = $_POST["BaseballNumber"];
$SoccerValue = $_POST["SoccerNumber"];
$TotalValue = $BaseballValue * $SoccerValue;
print "<span class='TotalValue'>".$TotalValue."</span>";
?>
This will return a span tag with the class of TotalValue and the value of 420 and print it in the console.
Just a simple way to do ajax using jQuery. Don't forget commas in the parameter list.
So i have written a function that is called onclick in my html file that uses AJAX, but i would like for this post to go to a specific table in mysql.
$('#submitIFC').click(function(e) {
var request;
if (window.XMLHttpRequest) {
request = new XMLHttpRequest();
} else {
request = new ActiveXObject("Microsoft.XMLHTTP");
}
var opinionIFC = $('ul.sort').sortable('toArray').join(',');
request.onreadystatechange = function() {
if ((request.readyState===4) &&(request.status===200)) {
var return_data = request.responseText;
document.getElementById('rank_ul').innerHTML= 'return_data';
// Preventing the default action triggered by clicking on the link
e.preventDefault();
e.preventDefault();
}//end of if
}//end of onreadystatechange function
//send requested movie to php file which will send to the external server
request.open("POST", "results.php", true);
request.send(opinionIFC);
document.getElementById('rank_ul').innerHTML='<img src="ajax-loader.gif">';
});
however there seems to be an issue with connecting this to my php if conditional, i tried copying the contents on my request.send(), like so
if($_POST['opinionIFC'])
{echo
// The data arrives as a comma-separated string,
// so we extract each post ids:
$data=explode(',',str_replace('li','',$_POST['sortdata']));
// Getting the number of objects
list($tot_objects) = mysql_fetch_array(mysql_query("SELECT COUNT(*) FROM sort_objects"));
if(count($data)!=$tot_objects) die("Wrong data!");
foreach($data as $k=>$v)
{
// Building the sql query:
$str[]='('.(int)$v.','.($tot_objects-$k).')';
}
$str = 'VALUES'.join(',',$str);
// This will limit voting to once a day per IP:
mysql_query(" INSERT INTO `sort_votes` (ip,date_submit,dt_submit)
VALUES ('".$_SERVER['REMOTE_ADDR']."',NOW(),NOW())");
// If the user has not voted before today:
if(mysql_affected_rows($link)==1)
{
mysql_query(' INSERT INTO `sort_objects` (id,votes) '.$str.'
ON DUPLICATE KEY UPDATE votes = votes+VALUES(votes)');
}
}
why isnt the ajax post request filtering through to my php file?
thank you so much, any help is much appreciated.
You're not sending opinionIFC parameter, try:
request.send('opinionIFC=' + opinionIFC);
You also need to set Content-type
request.setRequestHeader("Content-type","application/x-www-form-urlencoded");
I am trying to make a ajax call and validate a input html field. But, instead of getting simple echo message. I am getting complete source code in responseText.
JavaScript
function checkUsername() {
document.getElementById("username").className = "thinking";
usernameRequest = createRequest();
if (usernameRequest == null)
alert("Unable to create request");
else {
var theName = document.getElementById("username").value;
var username = escape(theName);
var url= "checkName.php?username=" + username;
usernameRequest.onreadystatechange = showUsernameStatus;
usernameRequest.open("GET", url, true);
usernameRequest.send(null);
}
}
function showUsernameStatus() {
alert(usernameRequest.responseText);
if (usernameRequest.readyState == 4)
{
if (usernameRequest.status == 200) {
if (usernameRequest.responseText == "okay") {
document.getElementById("username").className = "approved";
document.getElementById("register").disabled = false;
}
else {
document.getElementById("username").className = "denied";
document.getElementById("username").focus();
document.getElementById("username").select();
document.getElementById("register").disabled = true;
}
}
}
}
checkName.php
<?php
$takenUsernames = array('bill', 'ted');
sleep(2);
if (!in_array($_REQUEST['username'],$takenUsernames )) {
echo 'okay';
} else {
echo 'denied';
?>
Previously, I tried to integrate PHP into tomcat, but I was advice it was not a good practice. TRIAL TO INTEGRATE PHP
What I can make out of this situation is that Tomcat is not parsing PHP file and instead it is returning the source code. I believe there should be a means for me to let tomcat parse php files and send the right response.
I have also tried with simple php code, with one statment <?php echo 'HELLO'; ?> and I still get the source code.
Thanks in advance.
NOTE : I do not know php, I am working an example from HEAD FIRST AJAX
you need to install PHP for Tomcat & set its path to compile it.see the below link for php configuration settings.
http://php-java-bridge.sourceforge.net/doc/tomcat6.php
http://www.studytrails.com/blog/php-on-a-java-app-server-apache-tomcat-using-quercus/
To simplify the problem, all I want is passing 3 variable from javascript to PHP. So let say I have 4 varible : a,b,c,message.
I have tried the following ways:
1)The code below is in my javascript file
window.location.href="somewebsite.php?x=" + a + "&y=" + b + "&z=" + c + "&msg=" + message;
I saw that it actually passing the values to URL, it jump to the PHP website that specifies in the code above but somehow nothing is getting from $_POST['x'] ( I even try $_GET['x'] and $_REQUEST('x') but none of them works at all)
2) Then I tried with ajax
$.post("somewebsite.php",{x:a, y:b, z:c, msg:message})
And same as above nothing are passed to the PHP website.
3) I tried with form submit
I put everything into a form and submit it to the PHP website but what I get from $_POST is an empty array.
So I conclude that something is wrong with azurewebsites server. This is the first time I used window azure so I don't know how it even works. Any suggestion would be appreciated.
you can try out ajax function
$.ajax({
url:"url",
method:"post",
data:{x:a, y:b, z:c, msg:message},
success:function(data)
{
// success code
},
error:function(error)
{
// error code ;
}
});
Should work:
Your js file:
$(document).ready(function(){
var aval = "testas";
var bval = "testas2";
var cval = "testas3";
var msg = "testas4";
$.post('test.php',{a:aval,b:bval,c:cval,message:msg},function(resp){
alert(resp);
});
});
php file should look like:
<?php
$resp = "";
foreach($_POST as $key => $val){
$resp .= $key.":".$val." \n";
}
echo $resp;
?>
After post alert should give response of all sent post values.
I hope it helped you. If yes, don't forget resp. Thanks.
Try sending an array to your somewebsite.php write this inside a function on jquery code.
It must work if you place it on a good place on your code.
var x=new Array();
x[0]='field0';
x[1]='field1';
x[2]='fieldN';
$.post('somewebsite.php',x,function(x){
alert(x);
});
Your somewebsite.php could be like this.
<?php
if(!isset($_POST['x']))$x=array();else $x=#$_POST['x'];
for($i=0;$i<count($x);$i++)
echo "X ($i) = ".$x[$i];
?>
Happy codings!
Sorry for the really newbie question, just starting to learn AJAX.
I'd like to understand what exactly in the following causes the divMessage content to change continuously when "myName" text is changed.
1) It would seem that the Javascript function process is constantly "listening", is this normal Javscript behavior, or are there any triggers to call "process" repeatedly?
2) Is it true that any function that we assign to "body onload" will be executed repeatedly? How often is this repeated execution?
3) What if we want a single execution of the function process, how to do this?
4) I'm confused because I'm thinking the body will only load once. But is it because after "body onload" the function "process" is called, and the function process in turn modifies the "body" by changing the divMessage, essentially letting it go thru "body onload" again, then "process" again, etc.. ?
Thanks a lot in advance for your help!
<head>
<script type="text/javascript" src="quickstart.js"></script>
</head>
<body onload='process()'>
Server wants to know your name:
<input type="text" id="myName" />
<div id="divMessage" />
</body>
Here's quickstart.js processing parts
function process()
{
// proceed only if the xmlHttp object isn't busy
if (xmlHttp.readyState == 4 || xmlHttp.readyState == 0)
{
// retrieve the name typed by the user on the form
name = encodeURIComponent(
document.getElementById("myName").value);
// execute the quickstart.php page from the server
xmlHttp.open("GET", "quickstart.php?name=" + name, true);
// define the method to handle server responses
xmlHttp.onreadystatechange = handleServerResponse;
// make the server request
xmlHttp.send(null);
}
}
// callback function executed when a message is received from the server
function handleServerResponse()
{
// move forward only if the transaction has completed
if (xmlHttp.readyState == 4)
{
// status of 200 indicates the transaction completed successfully
if (xmlHttp.status == 200)
{
xmlResponse = xmlHttp.responseXML;
xmlDocumentElement = xmlResponse.documentElement;
helloMessage = xmlDocumentElement.firstChild.data;
// display the data received from the server
document.getElementById("divMessage").innerHTML =
'<i>' + helloMessage+ '</i>';
}
}
}
and the quickstart.php
<?php
header('Content-Type: text/xml');
echo '<?xml version="1.0" encoding="UTF-8" standalone="yes"?>';
echo '<response>';
$name = $_GET['name'];
// generate output depending on the user name received from client
$userNames = array('YODA', 'AUDRA', 'BOGDAN', 'CRISTIAN');
if (in_array(strtoupper($name), $userNames))
echo 'Hello, master ' . htmlentities($name) . '!';
else if (trim($name) == '')
echo 'Stranger, please tell me your name!';
else
echo htmlentities($name) . ', I don't know you!';
echo '</response>';
?>
Found the answer by shutting down and trying to run this again.
It turns out there was additional code that I commented out
but was cached that calls "process" every 1 second from handleServerResponse():
// display the data received from the server
document.getElementById("divMessage").innerHTML =
'<i>' + helloMessage+ '</i>';
setTimeout('process()', 1000);
Sorry about that. Lesson is to clear the browser cache before testing each code change :)
So I guess the advice to check if this function is called from any other place is correct.
Anyway, I read a great deal and learned a lot while trying to figure
this out. Thanks a lot #pst!